Wednesday
April 23, 2014

Number of results: 4,024

calc help
Take the derivative: v=3t^2 -8t -7 put v=10 and rearrange it to have a quadratic in standard format, solve the quadratic with the quadratic formula.
Saturday, April 26, 2008 at 6:16pm by bobpursley

You are referring to the discriminant, which is part of the quadratic formula in the RADICAND section. Here is how the discriminant works: Given a quadratic equation in the forn ax^2 + bx + c = 0, plug the coefficients into the expression b^2 - 4ac to see what happens. The ...
Wednesday, February 13, 2008 at 7:31am by Guido

Please explain to me how to do the following problems, I dont understand them. Thanks! Find the x-intercepts (if any) for the graph of the quadratic function. 1.f(x) = (x + 2)2 - 4 Find the y-intercept for the graph of the quadratic function. 5.y + 9 = (x + 3)2 Find the domain...
Saturday, October 13, 2007 at 11:46pm by Carmen

If your expressions mean : x ^ 2 - 9 x = 0 x ^ 2 +8 x = 0 x ^ 2 = 6 x x ^ 2 = - 3 x Then in google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open in rectangle type your ...
Wednesday, February 15, 2012 at 2:17pm by Bosnian

math
Sunday, February 13, 2011 at 9:54pm by Anonymous

Algebra 2
how can you possibly think that those are the same? Quadratic form means you want a quadratic expression of the form az^2 + bz + c Now, since m^8 = (m^4)^2, you have 13(m^4)^2 - 3(m^4) + 4 which is a quadratic if you let z=m^4. Then you have 13z^2-3z+4
Saturday, May 18, 2013 at 9:16am by Steve

chemistry
You have two choices. 1)The simple choice, and one which doesn't always work, is to assume x is very small in comparison with 0.001 so that 0.001 - x = 0.001. That way you don't have a quadratic equation. You can try that, then see if 0.001 - x = about 0.001 or not. If x is ...
Sunday, April 6, 2008 at 10:42pm by DrBob222

algebra II
I'm quite clueless as to how to solve this. I know the quadratic equation but am not sure how to get this equation into the format to plug in to the quadratic... Solve the quadratic equation using the formula [1/(1+x)]-[1/(3-x)]=(6/35) Show your work
Sunday, May 24, 2009 at 11:36am by maddie

algebra II
How do you know if a quadratic equation will have one, two, or no solutions? How do you find a quadratic equation if you are only given the solution? Is it possible to have different quadratic equations with the same solution? Explain. Provide your classmates with one or two ...
Tuesday, October 7, 2008 at 1:33am by Nadia

algebra II
How do you know if a quadratic equation will have one, two, or no solutions? How do you find a quadratic equation if you are only given the solution? Is it possible to have different quadratic equations with the same solution? Explain. Provide your classmates with one or two ...
Tuesday, June 15, 2010 at 2:29pm by hollywood

math
(4.35E-2 - x)(7.56E-2 -x ) ============================ (0.324 + 2x)2 Rearrange to get an expression of the form ax2 + bx + c = 0 and use the quadratic formula (solve for x. This gives: x = 1.05E-2, 0.143 basically i understand they use the quadratic equation but how did they...
Saturday, March 10, 2012 at 3:27pm by bob

math,algebra,help
Is this right: Solve: x^2+16x+60=0 this is what i did: i used the quadratic formula and this is what i ended up with. x = -8 +- (sqrt(16))/(2) Which is -8 +-2 Or you could have factored the quadratic (x+10)(x+6) Which is -8 +-2 Or you could have factored the quadratic (x+10)(x+6)
Saturday, April 14, 2007 at 3:41pm by jasmine20

ALGEBRA-MAT117
How do you know if a quadratic equation will have one, two, or no solutions? How do you find a quadratic equation if you are only given the solution? Is it possible to have different quadratic equations with the same solution?
Monday, January 12, 2009 at 10:59pm by Paradise

ALGEBRA-MAT117
How do you know if a quadratic equation will have one, two, or no solutions? How do you find a quadratic equation if you are only given the solution? Is it possible to have different quadratic equations with the same solution?
Monday, January 12, 2009 at 10:59pm by shauna

Algebra
How do you know if a quadratic equation will have one, two, or no solutions? How do you find a quadratic equation if you are only given the solution? Is it possible to have different quadratic equations with the same solution?
Tuesday, September 30, 2008 at 5:14pm by Laura

ALGEBRA
How do you know if a quadratic equation will have one, two, or no solutions? How do you find a quadratic equation if you are only given the solution? Is it possible to have different quadratic equations with the same solution?
Sunday, March 28, 2010 at 5:39pm by GGIFT

I am trying to define the different appraoches to solving quadratic equations. My book says using quadratic formula, completing the sqaure and factoring. I thought completing the square would be by facotring? How are these two different?
Tuesday, February 5, 2008 at 11:33am by Marysvoice

calculus
The x-intercept on a quadratic expression is essentially solving for the roots of a quadratic equation. For the above, the intercepts can be found by solving for x when y=0, i.e. -0.01x^2+0.7x+6.1 = 0 You can solve by completing the squares, or by the quadratic equation. ...
Thursday, November 11, 2010 at 7:59pm by MathMate

In google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open in rectangle type: 15t^2+7t=2 and click option: solve it You will see solution step-by step
Sunday, June 19, 2011 at 11:34am by Bosnian

algebra
Solve the quadratic equation: 2x(squared)+6x+12=0 I know you have to find two numbers that =24 (2 times 12) and have a sum of 6. But I can't think of any! Can someone please help? Use the quadratic. And this problem has no real answers, they are imaginary. Oh, the quadratic ...
Saturday, December 9, 2006 at 5:19pm by Sir Galahad

Math
Have you ever heard of the quadratic formula? It's the easiest solution here. In the quadratic formula, for any quadratic equation in the for ax^2+bx+c=0 x=(-b}ć(b^2-4ac))/2a In this case: 4.905=a 2.93=b -10=c Think you can solve it from here? The rest is some simple ...
Sunday, February 28, 2010 at 7:48pm by anonymous

If you are looking at a graph of a quadratic equation, how do you determine where the solutions are?
Thursday, January 22, 2009 at 10:18pm by Paradise

univ-phys
F=G(m)(4.5-m)/.22^2 solve for m, then 4.5-m notice it is a quadratic, use the quadratic equation.
Friday, October 2, 2009 at 12:57pm by bobpursley

Physics
multiply it all out, you will get a quadratic equation. Use the quadratic formula.
Friday, November 6, 2009 at 10:19am by bobpursley

Algebra I
When it hits the ground, h=0 solve for that time. It is a quadratic, use the quadratic equation.
Thursday, February 4, 2010 at 10:27am by bobpursley

algebra
I don't know that you did anything wrong. How did you solve the quadratic? Did you use the quadratic formula?
Saturday, July 5, 2008 at 7:14pm by DrBob 222

ALGEBRA
yes, it is a quadratic. When your highest power is of degree 2, such as ?x^2, you have a quadratic.
Thursday, September 10, 2009 at 8:31pm by Reiny

algebra
Solve this quadratic equation using the quadratic formula. x^2 + 8x - 5 = 0
Thursday, January 21, 2010 at 3:48pm by yelena

Algebra
Monday, August 9, 2010 at 5:13pm by Tammy

If I were looking at a graph of a quadratic equation, how do I determine where the solutions are?
Thursday, September 2, 2010 at 9:49am by Lynn

The solutions are the x values where y = 0. (Where the curve crosses the x axis). y is the quadratic function.
Saturday, February 16, 2008 at 7:24pm by drwls

Physics
Friday, November 12, 2010 at 6:37pm by bobpursley

Physics
Tuesday, October 4, 2011 at 5:22pm by bobpursley

the statement of the quadratic formula would be the solution x = (-b ± √(b^2 - 4ac)/(2a)
Monday, January 16, 2012 at 9:54pm by Reiny

Maths
Show proof of deriving the Quadratic Formula from the Quadratic Equation ax^2 + bx + c = )
Monday, April 1, 2013 at 11:09pm by Jeconiah

Maths
Show proof of deriving the Quadratic Formula from the Quadratic Equation ax^2 + bx + c = O
Monday, April 1, 2013 at 11:10pm by Jeconiah

Physics
The first is a quadratic. Either factor it, or use the quadratic equation. On the second, you cannot get 9.8 m/s as a distance, that is a velocity.
Sunday, September 9, 2007 at 6:44pm by bobpursley

ALGEBRA--MAT 117
i prefer using the quadratic formula it better in solving quadratic eqations
Monday, January 12, 2009 at 11:00pm by nonkonzo

Math
multiply both sides by .858-x, then put in quadratic form, and use the quadratic equation.
Monday, June 1, 2009 at 10:58am by bobpursley

algebra
Look where it crosses the x-axis. the x-intercepts of the quadratic function are the solutions to the corresponding quadratic equation
Thursday, June 24, 2010 at 10:01am by Reiny

The solutions to a quadratic equation occur where the graph of the parabola crosses the x-axis
Thursday, January 22, 2009 at 10:18pm by Cindy

math
Wednesday, March 26, 2008 at 12:35pm by DBob222

physics
d=vi*t+at^2 it will be a quadratic in time, use the quadratic equation.
Wednesday, September 16, 2009 at 10:04pm by bobpursley

Algebra
Which is the easiest way to figure a quadratic equation; graphing, quadratic formula, completing a square and factoring?
Monday, February 4, 2008 at 8:13am by Marysvoice

Rearrange this expression into quadratic form, ax2 bx c = 0 .2= ((x^2)/(55-x)) where a = 1, and identify the values of b and c.
Tuesday, February 19, 2013 at 12:15pm by Anonymous

complete the square factor by grouping use the quadratic equation what? study? try that too.
Tuesday, March 19, 2013 at 10:19am by Steve

Alg
d=65ft=.04v^2+.05v put this into quadratic form, and use the quadratic equation, solve for v.
Wednesday, April 16, 2014 at 8:41am by bobpursley

Algebra
Saturday, March 19, 2011 at 7:52pm by Damon

physics
expand the square on the right, gather terms, put it in the standard quadratic form, and use the quadratic formula.
Wednesday, April 23, 2008 at 6:00pm by bobpursley

where the graph of the corresponding quadratic function crosses or touches the x-axis, in other words, the x-intercepts
Thursday, January 22, 2009 at 10:18pm by Reiny

Math
make it a quadratic equation.. x^2+3x+4=0 Now, use the quadratic formula. I think it will have complex roots.
Wednesday, May 6, 2009 at 9:29pm by bobpursley

can you solve the equation using the quadratic formula x2 + 3x = 7? Explain and provide an exact answer.
Tuesday, January 17, 2012 at 10:01pm by becca

math
Friday, October 26, 2012 at 2:54pm by danica

how do you know if a quadratic equation will have 1,2 or no solutions
Sunday, January 4, 2009 at 1:33pm by Anonymous

Algebra
Thursday, August 23, 2012 at 2:43am by Liz

Algebra
The quadratic equation yields two solutions: x = 2 and x = -1 But that quadratic equation is not equivalent to the original equation. What you know for sure is that any solution of the original equation will also satisfy the quadratic equation. That means that the quadratic ...
Tuesday, July 7, 2009 at 9:37pm by Count Iblis

Algebra II
Wednesday, November 28, 2007 at 1:53pm by bobpursley

geometry
arrange it to look like the standard quadratic 2x^2 - 7x + 2 = 0 now use the quadratic formula x = (7 ± √33)/4
Monday, September 22, 2008 at 10:37pm by Reiny

College Math II
I would multiply all out, rearrange into a quadratic, then factor or use the quadratic equation.
Saturday, November 21, 2009 at 11:50am by bobpursley

Factoring Trinomials
I never heard of the criss cross method. I used the quadratic equation to solve for zeros of the quadratic expression.
Monday, October 31, 2011 at 6:40pm by Damon

math
Saturday, October 6, 2012 at 3:06am by bobpursley

algebra
which quadratic formula would be used to solve the following quadratic equation? 4x^2 - 5x = -2 can you show me the correct answer and how do it please
Tuesday, June 8, 2010 at 8:42am by gabriel

MATH
In google type: quadratic equation online When you see list of results click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open in rectangle type 2x^2+5x+3=0 and click option: solve it!
Sunday, March 9, 2014 at 10:16pm by Bosnian

Algebra II
If you are currently studying the quadratic function and its graph, then these are fundamental questions that you should know. If you are not studying the quadratic function then these pages are an excellent source http://www.uncwil.edu/courses/mat111hb/Pandr/quadratic/...
Tuesday, November 27, 2007 at 5:07pm by Reiny

Chemistry
I solved the quadratic and obtained 0.0064 which is appreciably different than 6.62 x 10^-3 so %ion = 6.40 Why don't you solve it by the quadratic and see if you get the same thing?
Sunday, February 15, 2009 at 9:39pm by DrBob222

math
expand the two binomials, combine like terms, then put it in the form of a quadratic...you can then use the quadratic equation, or perhaps factor to find x.
Tuesday, March 10, 2009 at 2:00pm by bobpursley

algebra
Quadratic equations can be solved by graphing,using the quadratic formula, completing the square, and factoring. What are the pros and cons of the methods. when would each be appropriate?
Tuesday, February 7, 2012 at 6:53pm by debby

Use the quadratic formula. You be able to do work of this nature you MUST have learned how to solve a quadratic equation.
Monday, September 17, 2012 at 10:53pm by Reiny

algebra 2
I will do number 2 only. We have this: (x-3)^2 = -4 The left side becomes x^2 - 6x + 9. We now have this: x^2 - 6x + 9 = -4 Add 4 to both sides and then equate to zero. x^2 - 6x + 9 + 4 = 0 x^2 - 6x + 13 = 0 This quadratic equation cannot be solved by factoring. In that case, ...
Tuesday, February 12, 2008 at 2:25pm by Guido

Mat/117 DQ1
How do you know if a quadratic equation will have one, two, or no solutions?Please give examples. How do you find a quadratic equation if you are only given the solution? Please give an example.Is it possible to have different quadratic equations with the same solution? ...
Monday, February 27, 2012 at 5:23pm by Rose

Algebra
I do not know what your problem is. That is sort of the quadratic equation: x = [-b +/- sqrt(b^2-4ac)]/2a and you would get the two answers but I did not see the original quadratic so do not know if right or not (although I can do it backwards).
Wednesday, March 19, 2008 at 7:21pm by Damon

math
multiply out both sides. Then, gather like terms into quadratic form. ax^2 +bx +c=0 Then, factor, or use the quadratic formula.
Wednesday, August 27, 2008 at 8:33pm by bobpursley

Algebra
Can someone help me with this question. I thought it was quadratic but now I am not sure. State whether the equation represents a linear, quadratic, exponential function or none of the above. x^2+ 6 = -8 x
Thursday, January 14, 2010 at 1:44pm by Kate

math
C '(x) = .6x^2 - 50x + 1531 = 0 for a max/min of C solve using the quadratic formula This quadratic has no real roots, I will leave it up to you to interpret that result.
Saturday, February 12, 2011 at 1:08am by Reiny

math,algebra
can someone help me out factor out this 0=16t^2-122t+180 i have so far this but the last one i am not sure 8(2t^2-14t + ?) you need to use the quadratic formula: -b(+or-)[sqrt(b^2-4ac)/2a] so you are saying that i don't have to factor it out any further i can just continue to ...
Friday, April 6, 2007 at 9:26pm by jasmin20

college geomrtry
What are the differences between linear and quadratic equations? How are these differences displayed in a graph? Write a brief scenario that can be modeled with a linear equation. Summarize a situation modeled by a quadratic equation. Are there equations that are neither ...
Sunday, February 28, 2010 at 10:56pm by Anonymous

College Algebra
By factoring, a quadratic equation with known zeroes can be expressed as: (x-x1)(x-x2)=0 where x1 and x2 are the solutions to the quadratic equation. Substitute the zeroes in the above equation and expand to give the quadratic equation.
Wednesday, April 13, 2011 at 8:28pm by MathMate

Math
What are the differences between linear and quadratic equations? How are these differences displayed in a graph? Write a brief scenario that can be modeled with a linear equation. Summarize a situation modeled by a quadratic equation. Are there equations that are neither ...
Sunday, January 17, 2010 at 4:09pm by Michelle

A little technicality : A quadratic equation does not have an axis of symmetry, a quadratic function does. the corresponding quadratic function would be f(x) = (x+1)(x-7), which would have zeros of -1 and 7 the axis of symmetry would be half-way between these two values, or x = 4
Wednesday, July 3, 2013 at 2:49pm by Reiny

chem
In one of your earlier posts, you asked if this was the correct quadratic equation and it was. X^2 + 0.022X - 1.2E-4 = 0 Using the quadratic formula, which is X=(-b +/- sqrt[b^2-4ac])/2a solve for X. What is that value?
Wednesday, March 26, 2008 at 12:42pm by DBob222

algebra
Quadratic equations are usually written with all terms on one side equal to zero so ... 2x^2 + 5x - 1 = 0 we used to call this the general form of a quadratic.
Friday, May 14, 2010 at 6:08pm by Reiny

math
Factoring a quadratic and solving the corresponding quadratic equation are closely related. in the first case I would consider solving it as x^2 + 8x + 53 = 0 since the only factors of 53 are 1 and 53 itself, there is no way we can get that 8 in the middle. using the formula ...
Monday, November 1, 2010 at 9:36pm by Reiny

Math
Use the quadratic formula to solve each of the following quadratic equations... 1. 2x^2-5x=3 2. 3x^2-2x+1=0 Rearrange the equation in quadratic formula form. 2x^2 -5x -3 = 0 Then use the formula. Tell me what you don't understand about it if you don't know what to do next. I ...
Wednesday, June 13, 2007 at 3:43pm by Tomika

Math
In google type: quadratic equation online When you see list of result click on: Free Online Quadratic Equation Solver:Solve by Quadratic Formula When page be open in rectangle type: (x^2)+3x-4=14 and cilck option: solve it! You will see solutions step-by step.
Friday, August 19, 2011 at 10:03am by Bosnian

algebra2
This looks like a "prime" quadratic. With trial and error trying: (-4t )(t ) or (-2t )(t ) you cannot get it to work. So there are no "interger" solutions. You can use the famous "quadratic equation" to get an approximation. ARe you familiar with this?
Tuesday, January 29, 2008 at 9:21pm by DanH

calculus
from the second,y=15-3x then square it... 225-90x+9x^2 check that, and put it in for y^2 in the first equation, rearrange it in quadratic form, and solve for x using the quadratic formula.
Tuesday, January 20, 2009 at 5:28pm by bobpursley

algebra
I would multiply by 10 and re-arrange into a standard quadratic equation. t^2 + 500t - 11000 = 0 now use the quadratic formula to find the two real roots.
Monday, August 24, 2009 at 10:11pm by Reiny

math
Does 3x^2=5 represent a linear equation or a quadratic equation? Does y=10^2 represent a linear or quadratic equation? does y=2x=23-14x repesent a linear or quadratic equation?
Wednesday, December 9, 2009 at 3:00pm by Kay Kay

Algebra II
Wednesday, November 28, 2007 at 1:53pm by JaneLee

Math (Trig)
put it in quadratic form. 2 (sinX)^2 + sinX-1=0 now solve for sin x using the quadratic equation a=2 b=1 c=-1
Sunday, December 16, 2007 at 6:55pm by bobpursley

physics
Put t=4.5/Vcos45 into the second equation, you only have V as the unknown. It is a quadratic, use the quadratic equation.
Friday, October 8, 2010 at 7:05pm by bobpursley

y = 2x^2 I am to decide if this is a linear, quadratic or exponential function. I chose that the above function is quadratic. Am I right?
Sunday, June 13, 2010 at 4:32pm by bart

physics
h=ho+vi*t-1/2 g t^2 15=0+20t-4.9t^2 Put it in the form of a quadratic equation at^2+bt+c=0 and use the quadratic equation.
Wednesday, July 20, 2011 at 8:30pm by bobpursley

College Algebra
hint x = 2 and x = -3 are roots so either do long division by x-2 and x+3 to get a quadratic or do it by synthetic division. Solve that quadratic using the formula.
Monday, January 2, 2012 at 11:42pm by Reiny

Suppose p(x)=ax^2+bx+c is a quadratic polynomial satisfying p(7)−p(3)=214. Determine the value of p(9)−p(1).
Sunday, April 28, 2013 at 9:49am by Bob

The quadratic formula tells you that the solutions are: t = [-b +/-sqrt(b^2 - 4ac]/(2a) In this case, a = 15, b = 7 and c = -2 See what you get.
Sunday, June 19, 2011 at 11:34am by drwls

Math
* By equation, I meant quadratic formula. Sorry for being vague. ** As well, I typed the quadratic formula wrong. It's: x = [-b (+ or -) [sqroot](b^2 -4ac)] / [2a]
Thursday, June 10, 2010 at 4:28pm by Anonymous

it actually say to use quadratic formula so i subtract 4 from both sides to get an equation by itself so i plug it in?
Tuesday, January 17, 2012 at 11:49pm by Shreya

Math
n*ln(a)=ln(a^n) 0.5*ln(x+3)=ln[(x+3)^0.5]= ln[sqroot(x+3)] ln(a)-ln(b)=ln(a/b) 5ln(x+3)-ln(x)=ln(sqroot(x+3)/x]=0 ln(1)=0 That mean: sqroot(x+3)/x=1 sqroot(x+3)=x Square that x+3=x^2 -x^2+x+3=0 Now you must solve this quadratic equation. In google type: quadratic equation ...
Tuesday, March 29, 2011 at 7:29pm by Anonymous

math
I seriously doubt if any basket ball player works out quadratic solutions when playing, or a sniper, or a diver. I would apply quadratic equations when designing fire fighting equipment.
Friday, February 17, 2012 at 7:26pm by bobpursley

Pages: 1

Search
Members