Monday
March 17, 2014

Number of results: 985

Algebra HELP
2X^3 + 3X^2 + 2X + 3 = 0. First, we reduce the cubic Eq to a guadratic Eq by finding a value of x that satisfies the Eq. This was done by trial and error. However, the task was made a lot easier by the use of EXCEL Spread sheets. It was determined x = -1.5 satisfies the cubic ...
Sunday, November 14, 2010 at 8:59pm by Henry

Math
Monday, February 25, 2008 at 4:31pm by Austin

Geometry
Monday, February 25, 2008 at 4:37pm by Austin

Math
OOPS! Draw a pair of quads. where the angles of the 1st quad. are congruent to the angles of the 2nd quad. No side of one quad. is to be congruent to any side of the other quad. THIS is straight out of the workbook SORRY!
Monday, February 25, 2008 at 4:46pm by Austin

math anaylsis
Y = X^2 + 54X + 800. Vertex form: y = a(x - h)^2 + k, h = Xv = -b/2a = -54/2 = -27, Substitute -27 for x in quad. Eq: k = Yv = (-27)^2 + 54*(-27) + 800 = 71. a = 1 = coefficient of x^2. Eq: y = (x + 27)^2 + 71.
Monday, October 11, 2010 at 10:38pm by Henry

trig
find the exact value given that cosA=(1/3) in quad I, sin B=(-1/2) in quad 4, and sin C=(1/4) in quad 2 tan(B+C)
Friday, March 26, 2010 at 9:24am by stacey graham

Math
Use the CAST rule to determine the sign of the functions cosine and tangent: C-quad.4, Cosine >0 A-quad.1, All functions >0 S-quad.2, sin>0 T-quad.3, tan>0 From the given values, cos(θ)>0 and tan(θ)<0 Only θ in quad.4 will satisfy both ...
Sunday, July 17, 2011 at 10:29am by MathMate

trig
find the exact value given that cosA=(1/3) in quad I, sin B=(-1/2) in quad 4, and sin C=(1/4) in quad 2 sin(A-B)?
Friday, March 26, 2010 at 12:24am by stacey graham

trig
Tuesday, June 11, 2013 at 7:59pm by bobpursley

trig
find the exact value given that cosA=(1/3) in quad I, sin B=(-1/2) in quad 4, and sin C=(1/4) in quad 2 tan(B+C) ? At the end of my equation I had (sqrt45/15) over (1-sqrt15/15) , how do I rationalize or did I make an error in calculation
Saturday, March 27, 2010 at 5:58pm by stacey graham

MatHHH
a. sec(225) = 1/cos(225) = -sqrt(2), 3rd QUAD. b. sin(-15) = sin(345) = -0.2588,4th QUAD. c. sin(75) = 0.9659,1st QUAD
Wednesday, January 19, 2011 at 4:51pm by Henry

Algebra
Check the given Eq. Should it be y = x + 4 ? (6 , 7). m1 = 1 = Slope of given Eq y = mx + b 7 = 1*6 + b, Solve for b: 7 = 6 + b, Subtract 6 from eaqch side: 1 = b or b = 1. Eq: y = 1x + 1 If your given Eq is different, use this as a guide or Repost it.
Tuesday, September 7, 2010 at 7:52pm by Henry

Chemistry/lab math
A stock standard contains 140 Eq/L of sodium and 5 Eq/L of potassium. How would the working standard of 140 m Eq/L and 5 m Eq/L be prepared?
Wednesday, August 7, 2013 at 10:06pm by Anonymous

math
x + 6y = 12 --- eq 1 -x + 7y = 1 --- eq 2 ------------ 13y = 13 y = 13/13 y = 1 Sub y = 1 in eq 1 or eq 2 and find for x
Monday, July 25, 2011 at 9:37pm by Mithra

Physics
If you draw the FBD for both object separately. Then, Positive being up and right, T=m1a Eq 1 T-m2g=-m2a Eq 2 T= -m2a+m2g Eq 3 Eq 3 = Eq 1 m1a= -m2a+m2g a=m2g/(m1+m2) since, a=x then, T=m1x
Wednesday, October 20, 2010 at 12:20am by Gharib

Trig
find (s+t) given that cos s=1/3 with s in quad I and sin T=-1/2 with t in quad IV
Friday, February 18, 2011 at 1:43pm by Paige

natural log
I need to solve for k'eq: -13.8= -2.479 ln k'eq -11.321= ln k'eq How do I get the ln out of the way in order to solve for k'eq? thanks!
Friday, March 28, 2008 at 11:25pm by stew

trig
well, cos is 1/sec so if one is + the other is + In quadrant 4 in fact the cos is + and also in quadrant 1 the cos is + but in quad one they are all plus. It can not be quad 2 or quad 3 because cos is - there. So I think you are correct.
Wednesday, March 17, 2010 at 9:58pm by Damon

Math
Any value 0f X that gives zero output when inserted in the given Eq is a solution (root). A 7 degree Eq has a maximum of 7 solutions(roots). These roots can be written as factors of the Eq. It can be found by trial and error that the following values of X satisfies the Eq: X...
Monday, February 14, 2011 at 1:40pm by Henry

5x-3y=23...............equation (1) 3x+5y=7.................equation (2) Eq. (1) x 5: 25x-15y=115......Equation (3) Eq. (2) x 3: 9x + 15y=21........Equation (4) Eq (3)+Eq. (4): 34x = 136 (eliminating y) Therefore, x = 4
Tuesday, March 16, 2010 at 6:50pm by Math?

math
if a quad is equilateral the quad is a square true right? or is it false? kindda stupid question but i gotta b sure of it
Wednesday, November 14, 2007 at 9:06pm by Anonymous

Math
Help I use S|A --- T|C First quad: All trigs. positive Sec. quad: Only sin and csc Third quad: Only tan and cot Fourth quad: Only cos and sec So, in the second quadrant makes sin positive. Therefor, I think it should be sin2x=2*(3/4) I may be wrong though. I know if I was ...
Sunday, May 9, 2010 at 2:17am by John

math
6x + 5y = -4 3x - 3y = 9 Multiply each side of 1st Eq by -3 and 2nd Eq by 6 and add the 2 Eq: -18x - 15y = 12 18x - 15y = 54 0 - 33y = 66 y = -2 Substitute -2 for y in fhe 2nd Eq: 3x -3 * -2 = 9 x = 1 (1 , -2).
Tuesday, August 24, 2010 at 3:30pm by Henry

acollege algebra
F(x) = Y = 2(x-3)^22(-5 Y = 2(x^2--6x+9)-5 Y = 2x^2-12x+18-5 Y = 2x^2-12x+13 h = -B/2A = 12/4 = 3 k = 2(3-3)^2-5 = -5 V(h,k) = (3,-5) Use Quad. Formula and get: X = 4.5,and 1.5. = X- Intercepts To find Y-int.,replace x in given Eq with 0 and solve for y. Y-int = 4.
Tuesday, April 30, 2013 at 5:46pm by Henry

algebra
2r - 5s = -22 5r + 2s = 32 Multiply 1st Eq by 5 and 2nd Eq by -2. 10r - 25s = -160 -10r -4s = -64 Add the 2 Eq -29s = -174 5 = 6 Substitute 6 for s in original Eq and solve rfor r. 2r - 5*6 = -22 2r = -22 + 30 = 8 r = 4.
Friday, August 20, 2010 at 4:14pm by Henry

Algebra
a=3b+7...eq (1) 4a+9b=70 or 4a=-9b+70...eq (2) multiplying equation i by 3 3(a)=3(3b+7)...eq (1) 3a=9b+21...eq (3) subtracting equation (2) from eq(3) 4a=-9b+70...eq(2) 3a=9b+21...eq (3) a = 49 this is the value of a
Sunday, March 31, 2013 at 10:04pm by Riana

Math
Let the 1st # = x And the 2nd # = y Difference between the two # is = 72 x - y = 72 ---- Equation 1 Then, one of the # divided by the other # which = 4 x/y = 4 ----Equation 1 x - y = 72 -- eq 1 x / y = 4 -- eq 2 x = 72 + y -- eq 3 Sub eq 3 in eq 2 we get, [(72 + y) / y] = 4 72...
Monday, July 25, 2011 at 6:25am by Mithra

Trig
Use "All Students Take Calculus" to find which of the functions are positive in which quadrant. The positive quadrants are for: S|A ---- T|C To find which quadrant will have sec<0 and cot<0, you look up the quadrant where cos<0 and tan<0. For cos<0, it will be ...
Thursday, October 29, 2009 at 4:31pm by MathMate

Math 209
My Eq for surface area(excluding top and bottom) does not agree with yours. My Eq: S = 2pi*rh. r = radius. h = height. Please check your Eq. a. S = 2*3.14*0.5*h = 3.14h. b. The surface ara increases with r. ;
Saturday, July 9, 2011 at 6:14am by Henry

Trig
No it is to find the exact value of the expression using the provided information. Find Tan (S+T) given that cos s=1/3 with s in quad I and sin T= -1/2 with T in quad IV
Friday, February 18, 2011 at 1:43pm by Paige

Trig
find the exact value of the expression using the provided information. Find Tan (S+T) given that cos s=1/3 with s in quad I and sin T= -1/2 with T in quad IV
Friday, February 18, 2011 at 10:36pm by Paige

Trig
find the exact value of the expression using the provided information. Find Tan (S+T) given that cos s=1/3 with s in quad I and sin T= -1/2 with T in quad IV
Saturday, February 19, 2011 at 11:21pm by Patti

Precalculus
Quad III and IV? May I know how you got 3.86132? and value for quad IV?
Tuesday, January 31, 2012 at 8:48pm by jake

square of a certain number decreased by 9 times the number is 36 . what is the number Goodness. You have to start to try these, and let us critique. There is nothing like the mind working on its own. N^2-9= what bob, appreciate the sentiment, but if i could figure it out, i ...
Wednesday, January 31, 2007 at 8:48pm by sandy d

Math
I can't for the life of me solve this! 6x^2-23x+15=0 6x^2-23x+15 = (a x + b) (c x + d) --> a c = 6 (1) a d + b c = -23 (2) b d = 15 (3) You could write down all possibilities for a and c (Eq. 1) and all possibilites for b and d (Eq. 3) and see which one satisfies Eq. 2 But ...
Thursday, May 24, 2007 at 6:08pm by Sandra

Algebra
elimination method means to eliminate one of the variables.let us eliminate s. 3r - 5s = 6 ---I 5r + 3s = 44 --II as a thumb rule multily eq I by 3 (coef. of s in eq II) and multiply eq II by 5 (coef. of s in eq II) 9r - 15s = 18 ---I 25r +15s = 220 --II By vertical addition ...
Monday, November 23, 2009 at 9:28pm by Anonymous

algebra
(1) 9x + 8y = 21 (2) x + 6y = 13 Multiply both sides of Eq. (2) by 9: (3) 9x + 54 y = 117 Subtract Eq. (1) from Eq. (3) 46 y = 96 Solve for y and take it from there. It looks like the solutions are not integers. Check my work.
Saturday, January 23, 2010 at 4:47pm by drwls

math
1. Multiply both sides of Eq. by 6. 2.Subtract 2a from both sides of Eq. 3. Add 30 to each side of Eq. 4. Solve for a.
Monday, July 19, 2010 at 3:58pm by Henry

algebra
1. b^2 < 4ac: 2 imaginary solutions. b^2 = 4ac: 1 real solution. b^2 > 4ac: 2 real soutions. 2. Let's take a given Eq and solution sets and use the solutions to derive the Eq. Eq: y = 2x^2 + 5x + 2. Solution set: x = -1/2, and x = -2. x = -1/2, x + 1/2 = 0. x = -2, x + 2...
Monday, November 15, 2010 at 7:07pm by Henry

algebra
1. X = -3. x+3 = 0. Using synthetic division, divide the given expression by x+3. You will get x^3 - 5x^2 + 15x - 49. + 151 Remainder. The fact that we got a remainder, means that x+3 is not a factor of the given expression and -3 is not a zero. Which means it will not give ...
Sunday, November 25, 2012 at 3:15pm by Henry

Chemistry
Of course it is but that's what I wrote in a different form. liters x normality x eq wt = grams. liters x normality = # equiv so #eq x eq wt = grams and eq wt = grams/#equivalents I like liters x normality x equivalent weight = grams BECAUSE it solve one equation instead of ...
Monday, March 5, 2012 at 2:40pm by DrBob222

algebra
Write 1st Eq in STD form: x - 4y = 13 2x + 16y = 20 Multiply 1st Eq by -2: -2x + 8y = -26 2x + 16y = 20 Add the 2 Eq: 24y = -6 y = -1/4 Substitute -1/4 for y in the 1st Eq and solve for x: x - 4(-1/4) 13 x = 12. (12 , -1/4).
Tuesday, August 24, 2010 at 5:58pm by Henry

Physics. Speed of electron...
I would find the voltage on the capacitor, or Electric field first. Using Gauss Law, then E= sigma/2epsilion Force/q= E Force=Eq force*distance=Eq*distance 1/2 m v^2=Eq*distance solve for velocity v.
Tuesday, February 10, 2009 at 10:29pm by bobpursley

math
0 - pi/2 quad 1 pi/2 to pi quad 2 pi to 3 pi/2 guad 3 3 pi/2 to 2 pi quad 4
Saturday, July 9, 2011 at 10:24pm by Damon

precalc
What are parametric equations? How would you find the rectangular eq's when given parametric eq's? and how would you find parametric eq's when given rectangular eq's? for example, given x=cos4t and y=sin4t (t is between 0 and 2pi) what is the retangular equation? given y=2x^(2...
Thursday, April 7, 2011 at 1:01am by Haley

college chemistry
The base dissociation equilibrium constant (Kb) for C5H5N is 1.40×10-9 (eq. 1). (eq. 1): C5H5N(aq) + H2O(l) = OH-(aq) + C5H5NH+(aq) Calculate the value of the equilibrium constant (Ka) for the hydrolysis of C5H5NH+ as shown in the reaction (eq. 2). (eq. 2): C5H5NH+(aq) + H2O(l...
Thursday, November 4, 2010 at 1:03pm by sparkle

Algebra 1
In the 1st Eq, solve for Y; substitute this value in the 2nd Eq and xolve for X.
Tuesday, June 28, 2011 at 6:07pm by Henry

algebra2
(3 , -5), (3 , -3), (3 , 2). Eq: x = 3. x is constant and remains at 3 for all values of y. Use the 3 points to graph the Eq.
Sunday, November 21, 2010 at 3:05pm by Henry

Geometry
1. C(6,-4), m = -1. (X,Y). m = y-(-4)/(X-6) = -1, Eq: Y+4 = -1(X-6). 2. A(1,5), B(-2,-4), m = (-4-5)/(-2-2) = -9/-4 = 9/4. A(1,5), X,Y), m = (Y-5/(X-1) = (9/4)/1, Cross multiply: Eq: Y-5 = 9/4(X-1). 3. Similar to 1 and 2.
Sunday, February 20, 2011 at 7:51pm by Henry

Precal
Y = X^4 - 6X^3 + 9X^2 -6X + 8 = 0, It was determined by trial and error that when X = 2, Y = 0. Therefore, 2 is a real solution. X = 2, X - 2 = 0, Using synthetic division, divide the 4th degree Eq by X - 2 and get: X^3 -4X^2 + X - 4. Now we have: Y = (X - 2)(X^3 - 4X^2 + X - ...
Thursday, January 13, 2011 at 12:41pm by Henry

help plz
Thursday, April 1, 2010 at 5:34pm by catherine

Chemistry
Can somone please explain this problem to me? The hydrolysis equilibrium constant (Ka) for NH2NH3+ is 5.88E-9 (eq. 1). (eq. 1): NH2NH3+(aq) + H2O(l) = H3O+(aq) + NH2NH2(aq) Calculate the value of the base dissociation constant (Kb) for NH2NH2 as shown in the reaction (eq. 2...
Wednesday, May 5, 2010 at 12:28am by John

Math
Given: Ints 2 + sqrt(3) , 2 - sqrt(3). x = 2 + sqrt(3), x - 2 = sqrt(3), Square both sides: x^2 - 4x + 4 = 3, Set Eq = 0: x^2 - 4x + 1 = 0, EQ: Y = X^2 - 4X + 1. h = Xv = -a/b =4/2 = 2, K = Yv = 2^2 - 4*2 + 1 - -3 V(2 , -3). CHECK: y = (2 - sqrt(3)^2 -4(2 - sqrt(3)) + 1, y = 4...
Monday, August 23, 2010 at 12:26pm by Henry

chem- electrochem-HELP
right then, numbers are- Br2 + 2e- = 2Br E=1.065V I2(s)+ 2e- = 2I- E=0.536V i have placed both these numbers into eq- Ecell= Ered(cathode)-Ered(anode) but for every combination, using the before mentioned eq, i cannot get any answers that they offer. If E i get either +/- 1....
Saturday, September 18, 2010 at 9:36pm by lucylu

Physics
Sir Steve I got the ans 46 but the correct ans is 48 S=vt+1/2at^2 in 1st gear S=v*2+1/2*20*2^2 S=2v+40..........eq 1 in second gear S=vt+1/2at^2 s=v*2+1/2*40*2^2 S=v+80.........eq 2 in third gear S=vt+1/2at^2 S=v*6=1/2*60*6^2 S=6v+1080.......eq 3 substituting eq 3 in eq 2 we ...
Friday, September 14, 2012 at 2:08pm by Mariam

algebra
I will derive an Eq passing through the given point with a slope = to that of given Eq. (-7 , 2), 3x = 2y + 9 3x - 2y = 9, STD Form, Slope = -A/B = -3/-2 = 3/2, Y = mx + b, Substitute x,y from given point into new Eq: 2 = (3/2)(-7) + b, Solve for b: 2 = -21/2 + b, 21/2 + 2 = b...
Wednesday, September 8, 2010 at 4:00pm by Henry

Chemistry
Can you explain what you don't understand here? The first thing you do is calculate where the equivalence point is. A is just calculation of pH of a weak acid. Then you have all of the calculations leading up to the eq. pt, all of the calculations after the eq. pt. and finally...
Sunday, February 10, 2013 at 5:35pm by DrBob222

Physics
You have to make two FBD; 1st for the force being applied to the leg, and 2nd for the mass hanging from cable. Positive being up and right. Y direction for FBD #2: T= mg Eq 1 x direction for FBD #1: -F+2Tcos(60)=0 Eq 2 T= F/2cos(60) T=x From Eq 1, m=x/g that's your answer.
Wednesday, October 14, 2009 at 9:03pm by Gharib

math
Determine whether the graphs of lines with the given Equations are Parallel, Perpendicular or neither. Eq#1 2X + 3Y = 4 and Eq#2 Y = - 2/3 X + 8
Thursday, April 16, 2009 at 5:32pm by mark

Math(Equation Writing)
1. X = The # of trees planted in March. 2x + 3=The # of trees planted in April. Eq: 2x + 3 = 73. 2. X = The # of minutes used. C = the total charges. Eq: C = 0.1x + 4.99. 3. X = Cost of each pair of socks. C = Total cost. Eq: C = 8x + 7.50.
Wednesday, August 24, 2011 at 3:26pm by Henry

AP Chemistry
I got 1054.9 as my answer. I reversed the first eq and did (1/K1^(1/2)) added it to reverse of second eq (1/K2) then added that to the 3rd eq times 2 (K3^2). This got me the right equation. Do I just multiply the new Kc values together to get the final Kc of the new equation?
Wednesday, August 17, 2011 at 10:00pm by Matt

mth
We have a fraction in which a cubic Eq is the numerator and a Quadratic Eq is the denominator. Let's factor both. Find a value of X that gives 0 out when plugged into the cubic Eq. It was found by trial and error that -2 will give an output of 0 and,therefore, satisfies the Eq...
Tuesday, March 1, 2011 at 12:47pm by Henry

algebra
2x - 4y =-10 8x - 3y = -14 Multiply each side of the 1st Eq by -4 and add the 2 Eq: -8x + 16y = 40 8x - 3y = -14 0 + 13y - 26 y = 2 Substitute 2 for y in Eq 1: 2x - 4*2 = -10 x = -1 (-1 , 2).
Tuesday, August 24, 2010 at 5:55pm by Henry

Math
Derive an Eq for the 1st prob. If it does not match, set-up the next problem. Continue until you find the Eq that matches. F. Amt requested = X dollars, Amt ea gave = (X + 20) dollars, Eq: 5(X + 20) = 500. Not a match. G. 1st acc. inv. X dollers. 2nd acc. inv. (X + 20) dollars...
Sunday, January 9, 2011 at 5:47pm by Henry

math
Multiply I eq by 2 and II by 3 6x+8y=58 6x-15y=-57. Subtract II eq from I. Signs of II eq will change:-6x+15y=57. Thus, 8y+15y=58+57 Or 23y=115 or y=115/23=5. Now substitute this in any original eq: 3x-4x5=29 or 3x=29-20=9, hence x=9/3=3
Wednesday, July 24, 2013 at 11:03pm by Anonymous

calculus
This graph is a v shape with vertex at (0,0) with a ray in the first quad with slope 1 and a ray in the second quad with slope -1 The +1 sends this graph up one It does not change the curve. The -flip the v downward The 3 changes the curve. Instead of the slope begin +/- 1, it...
Wednesday, December 12, 2012 at 12:12am by Mac

algebra
0.3X -0.27Y = 4.Iassumed you mean-.27Y 0.2X +0.3Y = -37/17. Multiply the 1st. Eq by 2 and the 2nd. Eq by -3: 0.6X -0.54Y = 8 -0.6X -0.9Y = 111/17 = 6 9/17. Add the 2 Eq: -0.63y = 14 9/17 = 14.53. Y = -23.06 Substitute -23.06 for Y in 1st Eq: 0.3X -0.27(-23.06) = 4. 0.3X +6.226...
Saturday, August 7, 2010 at 1:33pm by Henry

Calculus
You don't need Calculus to do this. The outer circle has centre at (0,0) and has radius 8 The other circle has centre (4,0) and radius 4, so the touch at (8,0) The big circle has area 64π, so the area in the first quad is 16π The smaller circle has area 16π and ...
Saturday, April 17, 2010 at 2:05pm by Reiny

physics
isolate N1 for the first eq: N1 = Fg - N2 eq 2: N1 x L1 - N2 x L2 = 0 sub N1 from eq 1 to eq 2. (Fg - N2)L2 - N2 x L2=0 (Fg - N2 x L2) - N2 x L2 = 0 Fg = N2 x L2 + N2 x L1 Fg = N2(L2+L1) since we already know Fg = mg, we isolate for N2 N2 = Fg/(L2+L1) Thus the normal for N2 is...
Thursday, November 4, 2010 at 9:26pm by Anonymous

Physics
1/R(eq)=3/R R(eq)=R/3
Monday, October 22, 2012 at 4:16pm by Elena

math
take the first eq. and solve for x. (x=6-2y). plug into second eq. and solve for y. you should be able to figure it out
Tuesday, September 4, 2007 at 10:22pm by Anonymous

math
Mary, you forgot to include the Eq; so i'll use a different Eq. The procedure will be the same. y = 2x + 2, (-6,),(-3,),(3,). y = 2(-6) + 2 = -12 + 2 = 10. y = 2(-3) + 2 = -6 + 2 = -4. y = 2*3 + 2 = 6 + 2 =8. Solution Sets: (-6,10),(-3,-4),(3,8).
Sunday, July 17, 2011 at 4:41pm by Henry

substitution method
1. 2m + n = 9 m - 6n = 50 Using Eq.1, solve for n: n = 9 - 2m Substitute 9 - 2m for n in Eq. 2: m -6(9 -2m) = 50 Solve for m: m - 54 + 12m = 50 m = 8 Substitute 8 for m in Eq. 1: 2(8) + n = 9 n = -7. Solution: m = 8, and n = -7.
Tuesday, July 20, 2010 at 12:35pm by Henry

algebra
Mult 1st eq by 3; x-2y+3z = 0 Mult 2nd eq by 4: 2x - 3y + 4z = 1 Add 2nd and 3rd: -4y+5z = 2 Mut 1st by 2: 2x-4y + 6z = 0 Add that answer and 3rd eq: -5y + 7z = 1 5(-4y + 5z = 2) + -4(-5y + 7z = 1) -20y + 25z = 10 + 20y - 28z = -4 -3z =6 z = -2 Sub into the 1st eq: x - 2y -6 =...
Monday, April 2, 2012 at 8:31pm by Charlie

Math
F(x) = y = -3(x + 3)^2 + k. Vertex Form: y = a(x - h)^2 + k. V(h , k) = V(-3 , 0), Line of sym = h = -3 = Xv. h is positive in your Eq because you are subtracting a negative 3. If you gave me the complete Eq, k = 0. The graph opens downward since a is negative(-3).
Monday, August 30, 2010 at 10:43pm by Henry

trig
you should know that between 0 and (1/2)π is quad I (between 0 and 90°) between (1/2)π and 1 π is quad II (between 90 and 180°) etc. isn't (5/7) greater than 1/2 but less than 1 ?
Saturday, January 21, 2012 at 6:07pm by Reiny

math
[y + 2] = X. The Eq is an absolute value function. It is a function , because it passes the vertical line test: If you draw a vertical line through the graph of an Eq and it intersects the graph only once, the Eq is a function. [Y + 2] = X, +-(Y + 2) = X, +(Y + 2) = X, Y + 2...
Wednesday, February 2, 2011 at 12:26am by Henry

algebra
Eq 1 y = 2x + 3 Eq 2 y = 2x + 1 How can you determine these are parallel? Can you graph both equations? Is it possible the lines do intersect somewhere away from the coordinates you are plotting?
Friday, March 18, 2011 at 12:49pm by bianca, pleeease help i'm lost

algebra
Eq 1 y = 2x + 3 Eq 2 y = 2x + 1 How can you determine these are parallel? Can you graph both equations? Is it possible the lines do intersect somewhere away from the coordinates you are plotting?
Friday, March 18, 2011 at 6:51pm by bianca, pleeease help i'm lost

physics
M=0.393kg m=0.181kg Draw the FBD, you will see that T1+T2-W(of M)=0 Eq 1 T2-W(of m)=0 Eq 2 (T2 is what we need) now, Eq1-Eq2 => T1+Wm-WM=0 T1= -g(m-M) T1= x Newtons now, plug in T1 in Eq 1, T2=WM-T1 *Reminder W=mass*9.8 Ans: T2=1.77N
Sunday, September 27, 2009 at 1:02pm by Gharib

find 3 consecutive integers such that the product of the second and third integer is 20 Take three integers x, y, and z. The for xyz, we want y*z = 20 The factors of 20 are 20*1 10*2 5*4. 20*1 are not consecutive. 10*2 are not consecutive. But 5 and 4 are consecutive; ...
Wednesday, January 31, 2007 at 7:15pm by chrisw

Math
a+9b=19 ; a=19-9b--->eq 1 a+2b=-2 --->eq 2 subs eq1 into eq 2 19-9b+2b=-2 19-7b=-2 19+2=7b 21/7=b b=3 subs b=3 into eq 1 a=19-9(3) a=19-27 a=-8
Sunday, July 28, 2013 at 11:05am by Lola

Multiply both sides of the 1st Eq by -6. Multiply both sides of the 2nd Eq by 3. Then add the Eqs. -18a - 30b = -420 +18a + 27b = 405 -3b = -15 b = 5. in the 1st Eq, replace b by 5: 3a + 5*5 = 70 3a = 70-25 = 45 a = 15
Monday, April 1, 2013 at 5:44pm by Henry

math
a. Given: m = 3, P(0,0). Y = mx + b. 0 = 3*0 + b b = 0. Eq: Y = 3x. b. m = -1/3, P(0,2). Y = mx + b. 2 = (-1/3)*0 + b b = 2. Eq: Y = (-1/3)x + 2.
Sunday, May 27, 2012 at 3:55pm by Henry

Diff eq
y'(x)=sqrt2y(x)+7, y(4)=1 Solve the seperable diff eq
Sunday, February 24, 2013 at 2:07pm by Melissa

Algebra
-5 and-2 write a quad equation. -√5,6√5 write quad equation Tick, tick..I'm doomed..
Saturday, April 21, 2012 at 9:41am by Jean

math116
Trudy, based on the answer you gave; you want to find the Eq of a line that passes through the given point with a slope = to the given Eq. Given: (-4 , 9) ,2X = 5Y + 6. 2X - 5Y = 6, Slope = -A / B = -2 /-5 2 / 5 Y = mX + B Plug in the gtven point to find b: 9 = 2 / 5(-4) + b ...
Monday, July 26, 2010 at 1:55pm by Henry

math
let the no. be x and y... x - y = 7.........i 1/3 x- 1/4 y =7..........ii eq ii x 12 4x - 3y = 84.....iii subtracting i and iii y=40 substituting in any eq x=51
Monday, October 1, 2012 at 10:22am by Anonymous

math
Multiply both sides of the 1st Eq by -3, and multiply the 2nd Eq by 2. Then add the Eqs. -6s + 9t = 3 +6s - 8t = 0 t = 3.
Tuesday, April 2, 2013 at 6:22pm by Henry

math
30, 60, 90 triangle 1, sqrt 3, 2 sin 30 = 1/2 cos 30 = sqrt 3/2 cos is negative in quad 2 and quad 3 so 180 - 30 = 150 degrees 180 + 30 = 210 degrees
Monday, March 18, 2013 at 7:05pm by Damon

math
2x+y=2 or 8x+4y=8 7x+4y=7. Subtracting one eq from other, we get x=1. Substituting this in given eq, 2x1+y=2 or y=0. Check:0=-2x1+2 ok, 7x1+4x0=7 ok.
Friday, July 26, 2013 at 6:21am by Anonymous

algebra
(X+3)/(X^2-X-12) + 2/(X+3) = 1/(X-4). (X+3)/(X-4)(X+3) + 2/(X+3) = 1/(X-4) Multlply both sides by (X-4)(X+3) and get: X+3+2(X-4) = X+3, X+3 + 2X-8 = X+3, X+2X-X = 3-3+8, 2X = 8, X = 4. Julie, there's something wrong with your Eq; because when I plug 4 into your Eq,the 1st and ...
Sunday, February 20, 2011 at 4:09pm by Henry

math116
9 = 2/5 (-4) + b 9 = -8/5 + b add 8/5 to each side of Eq 8/5 + 9 = 8/5 - 8/5 + b 8/5 +9 = b To add 8/5 and 9 , they should have a common denominator which is 5. 8/5 +45/5 = b 53/5 = b, or b = 53/5 Trudy, you are having problems with solving basic Eq and fractions.
Monday, July 26, 2010 at 1:55pm by Henry

MATHS
When x = 2, y = 0. Therefore, x = 2 is a solution. I'm going to derive the Eq with the assumption that 2 is the only solution. If my assumption is correct, all given points will satisfy the derived Eq. x = 2, x - 2 =0, (x - 2)^2 = x^2 - 4x + 4 = 0. CHECK: F(2) = 2^2 - 4*2 + 4...
Tuesday, September 28, 2010 at 5:51pm by Henry

Physics
Wouldn't you use Gauss Law for this? Inside, zero, no charge is contained. Pressure=force/area=Eq/area=E*surface charge density. = Eq/areabubble
Friday, October 11, 2013 at 11:48pm by bobpursley

Math
y = -4x^3 + 15x^2 - 1. First, we find a number that gives a zero when plugged into the cubic Eq. This is normally done by trial and error. but the use of EXCEL Spread sheet made the task a lot easier. It determined that -1/4 gives the zero that we need: y = -4(-1/4)^3 + 15(-1/...
Sunday, November 7, 2010 at 1:50pm by Henry

Chem
How many grams of nickel can be produced by passing a current of 15.0A through aqueous nickel(II) chloride for 80.0 minutes? I'm not sure if I'm on the right path... All I know is that 1 coloumb= amperes x seconds 1F=96485c/eq eq=molar mass/charge Since MM of Ni= 58.69g/mol ...
Monday, March 31, 2008 at 7:42pm by Ginger

Chemistry Solubility help!!!!!!!!!
INFORMATION: [HCl] = 0.1388 M We placed 0.5 g Ca(OH)2 in 100 mL of the following solutions: Flask A: Distilled Water (7.4 mL of HCl needed to titrate) Flask B: 0.05 NaOH (12.1 mL of HCl needed to titrate) Flask C: 0.025 NaOH (10.8 mL of HCl needed to titrate) Flask D: 0.0125 ...
Tuesday, March 26, 2013 at 5:51pm by Sally

chemistry
eq pt. mL acid x M acid = mL KOH x M KOH Solve for mL KOH. 0 mL: .........HPr ==> H^+ + Pr^- I......0.165.....0.....0 C.........-x......x....x E.......0.165-x...x....x Ka = (H^+)(Pr^-)/(HPr). Substitute from the E line and solve for x = (H^+), then convert to pH. For ...
Wednesday, October 23, 2013 at 11:03pm by DrBob222

physics
Given: x = -86, y = 75. tanA = 75/-86 = -0.8721, A = -41.09 deg. -41.09 is in 4th quad., but our vectors are in 2nd quad. so we add 180 deg: -41.09 + 180 = 138.9 deg.
Sunday, October 24, 2010 at 7:01pm by Henry

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