Saturday

April 19, 2014

April 19, 2014

Number of results: 47,340

**Pre-Cal**

Yes I am, but I don't understand it. I don't have a teacher to teach me. I do my work online, and I just need 2nd semester of pre-cal to graduate.
*Saturday, March 17, 2012 at 9:29pm by Adrianna*

**pre cal**

eh? plug in 6 for x. What do you get? If you're taking pre-cal, this should be a no-brainer.
*Wednesday, June 19, 2013 at 3:19pm by Steve*

**Pre-cal**

start with f(z) = i as directed then f(i) = -1 +i - i = -1 check f(-1) =+1 -1 - i = -i do not check f(-i) =-1 -i - i = -1 -2i
*Saturday, January 3, 2009 at 12:09pm by Damon*

**pre cal **

does anyone take pre-cal online ?
*Monday, April 16, 2012 at 6:44pm by Mecie *

**Pre. Cal.**

coefs of row 4 1 4 6 4 1 so a^4 + 4 a^3 b + 6 a^2 b^2 + 4 a b^3 + b^4 (3p+r^3)^4 a = 3p b = r^3 a^4 = 81 p^4 check 4 a^3 b = 4*27 or 108 p^3 r^3 check 6 a^2 b^2 = 6*9 or 54 p^2 r^6 check etc
*Thursday, May 14, 2009 at 10:43pm by Damon*

**pre cal--check**

yes
*Tuesday, March 31, 2009 at 8:27pm by Reiny*

**pre-cal**

pre-cal? more like algebra I must be the review section for the x-intercept, set y=0: x=1 for the y-intercept, set x=0: y = -2
*Sunday, December 9, 2012 at 11:59am by Steve*

**pre-cal/trig**

if you get to cosx+sinx=1/square root of 2, well we are doing identities in my pre-cal class and cosx+sinx always equals 1, so it would be 1/square root of 2.
*Tuesday, March 4, 2008 at 7:44pm by emily*

**PRE-CALC still stuck**

Pre-cal? V=kT V=kr^2 I=V(1/R)
*Sunday, October 18, 2009 at 5:55pm by bobpursley*

**Pre-Cal(Please check)**

i did -2/3 divided by 15, 10, -6, 0 and 14 I got 15, 0, -6 , 4 ,11.4 Is this correct?
*Saturday, March 27, 2010 at 5:38pm by Abbey*

**Integrated Physics and Chemistry**

The specific heat capacity of copper is 0.09 cal/g°C. How much energy is needed to flow into a 10-gram sample to change its temperature from 20°C to 21°C? A)0.009 cal B)0.09 cal C)0.9 cal D)9 cal
*Thursday, April 21, 2011 at 10:29am by Ashley!!*

**pre cal--check**

Name all the values of x that are not in the domain of f(x) = (2–x^2)/ (x+ 5) I got only x= -5 because that's the only value that would make the denominator zero.
*Tuesday, March 31, 2009 at 8:27pm by Jason*

**math**

80 cal/g x 5 g 400g/cal or 400 cal/g not sure can any one help Neither. 80 cal/g x 5g = 400 cal. The unit g cancels to leave calories. x2+2x-15
*Monday, December 11, 2006 at 10:45pm by rena*

**chemistry**

How many calories are required to heat 25.0 g of platinum from 24.5 °C to 75°C (specific heat of platinum = 0.139 J/gK)? 1. 47 cal 2. 42 cal 3. 48 cal 4. 20 cal 5. 80 cal Thank you.
*Sunday, November 22, 2009 at 5:30pm by Danny*

**science**

the conversion factor for calories (cal) and joules (J) is: 1 cal = 4.184 J now to convert calories to joules, we multiply 4000 cal by 4.184 J / 1 cal so that the cal unit will be canceled, and the numerator will have the unit J: 4000 cal * 4.184 J / cal = 16736 J hope this ...
*Wednesday, October 26, 2011 at 3:09am by Jai*

**Pre Cal Check**

focus: (0,p) vertex: if not given, then it is assumed (0,0) Directrix: k+p or k-p, i'm not sure I think these are the general equations for the focus, vertex, and directrix of a parabola, but i'm not sure. could someone please check this? thanks.
*Sunday, February 25, 2007 at 8:33pm by Marie*

**Lauren**

memorize the conversion units. 1000J=1kJ 1 cal= 4.1868 J 1k=1000 units so as an example, then on the second 2970kcal(4.1868J/cal) Then immediately check the units, to make certain the units cancel out to leave what you want. In this case... kcal*J/(cal) leaves kJ do the math.
*Thursday, December 5, 2013 at 3:07pm by bobpursley*

**Chem**

I wish teachers would get away from Calories vs calories. A Calorie (with a capital C, sometimes called a "big calorie" actually is a kilocalorie and should be addressed as such. So 1 Cal = 1000 calories. There are 4.184 joules in 1 calorie. You can convert from anything to ...
*Sunday, October 16, 2011 at 8:13pm by DrBob222*

**Physics**

Fp=440 - 15/5 = 437Hz = Freq. of piano. Brent, check your 3-28-11, 11:57am post for solution to your Pre-cal prob.
*Wednesday, March 30, 2011 at 1:02pm by Henry*

**Pre-Cal**

Find the standard form of the equation of the ellipse. (Remember center is midpoint between either foci or vertices) (1) 9x^2+4y^2+36x-24y+36=0 (2) Vertices: (0,5)(0,-5) Passes through the point (4,2) Centered at the origin
*Sunday, April 19, 2009 at 6:33pm by Cal*

**Pre-Cal(Please check)**

-(-2) + sqrt 4 - (-2)^2 = 2 + sqrt 4 + 4 No 2 + sqrt 4 - 4
*Tuesday, March 16, 2010 at 1:47am by Damon*

**Pre-Cal(Please check)**

sqrt2 /10 Do I just leave this as sqrt2/10 or can I reduce it to sqrt1/5?
*Thursday, March 11, 2010 at 3:04pm by Abbey*

**Pre-Cal(Please check)**

1)f(x) = -x + sqrt 4 - x^2 Find f(-2) -(-2) + sqrt 4 - (-2)^2 = 2 + sqrt 4 + 4 2 + sqrt 8 = 4.828 Is this correct?
*Tuesday, March 16, 2010 at 1:47am by Hannah*

**Pre-Cal**

the centre is clearly (0,1), the midpoint of these two vertices. and a = 2 so x^2/4 - (y-1)^2/b^2 = 1 but it passes through the point (5,4), so 25/4 - 9/b^2 = 1 -9/b^2= 1-24/4 -9/b^2 = -20/4 b^2/9 = 4/20 = 1/5 b^2 = 9/5 so the hyperbola is x^2/25 - 5(y-1)^2/9 = 1 (check my ...
*Saturday, May 2, 2009 at 7:37pm by Reiny*

**Pre-Cal**

For the given f(x), you will need to use synthetic to find the quotient q(x) and the remainder, r. Since you already figured out how to do synthetic division, you should have no problem tackling this one. Post your answer for a check if you wish.
*Saturday, March 27, 2010 at 5:38pm by MathMate*

**Pre-Calculus**

I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
*Saturday, September 17, 2011 at 2:40pm by Cristina*

**Pre-Calculus**

I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
*Saturday, September 17, 2011 at 3:48pm by Cristina*

**Science**

A 50 gram ice cube is cooled to -10oC in the freezer. How many calories of heat are required to heat it until it becomes liquid water at 20oC? (The specific heat of ice is 0.5 cal/goC.) Answer A) 1250 cal. B) 4000 cal. C) 5000 cal. D) 5250 cal. Can someone please help me solve...
*Monday, September 26, 2011 at 1:29am by Anonymous*

**physics **

A 50 gram ice cube is cooled to -10oC in the freezer. How many calories of heat are required to heat it until it becomes liquid water at 20oC? (The specific heat of ice is 0.5 cal/goC.) Answer A) 1250 cal. B) 4000 cal. C) 5000 cal. D) 5250 cal. Can someone please help me solve...
*Monday, September 26, 2011 at 5:17pm by Allison*

**Pre-Cal(Please check!!!)**

are you solving for r? In an isoceleses right triangle, of angles 45-45-90, the hypontense is side*sqrt2 In your case, r=20*1.41=28.2 Your tangent of 45 degrees is wrong, it is tangent45=1
*Tuesday, March 23, 2010 at 4:09pm by bobpursley*

**Chemistry**

You don't need the heat of vaporization to do that calculation. It takes 10g*1Cal/C g*10C = 100 Cal heat release to reduce the temperature ot 0C, and another 80 Cal/g*10 g = 800 Cal to freeze it. The sum is 900 Cal
*Saturday, April 17, 2010 at 12:35am by drwls*

**Pre. Cal.**

yes
*Thursday, May 14, 2009 at 10:43pm by Reiny*

**Pre cal**

OK. Thanks. =]
*Saturday, August 29, 2009 at 6:12pm by Anonymous*

**Pre-Cal**

Thank You
*Saturday, March 27, 2010 at 5:38pm by Abbey*

**Pre-Cal**

Thank You!!
*Sunday, March 28, 2010 at 12:54pm by Hannah*

**Pre-Cal**

Thank You
*Sunday, April 4, 2010 at 5:30pm by Abbey*

**Pre Cal**

b)
*Monday, July 25, 2011 at 3:04pm by Anonymous*

**Pre Cal**

why and how do you know
*Monday, July 25, 2011 at 3:04pm by Ashley*

**Pre Cal**

Thank you!!!
*Monday, February 13, 2012 at 11:06pm by Anonymous*

**Pre-Cal**

thanks
*Saturday, March 17, 2012 at 9:29pm by Adrianna*

**Pre-cal**

thank you
*Wednesday, April 18, 2012 at 10:10am by sandra*

**Pre-cal**

to do what?
*Thursday, December 13, 2012 at 5:57pm by Steve*

**Pre-Cal**

y-2=3^x take the log base 3 of each side. log3(y-2)=x x= log3(y-2) y= log3(x-2) is the inverse. check: f(inverse)= 3^(log3(x-2)) + 2 = (x-2)+ 2 = x
*Friday, March 19, 2010 at 3:22pm by bobpursley*

**college maths**

Mathematically, you can set up the problem as follow: 232 Cal/1.5 Cup = x Cal/1 cup 1x = 232/1.5 x = 154.7 Cal Another way, this is a no brainer question given the choices below. With 1.5 cup, you know it has 232 Cal, so with only 1 cup, you know the answer should be less than...
*Wednesday, December 15, 2010 at 2:16pm by Terry*

**Chemistry**

1.24E7 J x (1 cal/4.184J) = 2.98E6 cal. 12 oz x 2.98E6 cal/80,000 cal = ?oz Gatorade.
*Saturday, April 20, 2013 at 7:55pm by DrBob222*

**Pre-Cal**

What are bearings??
*Tuesday, February 5, 2008 at 12:34pm by Daisy M.*

**Pre Cal**

thanks so much!
*Tuesday, February 19, 2008 at 1:01pm by Kindell*

**another pre cal (logs)**

Thank you
*Monday, March 31, 2008 at 1:14am by Deb*

**Pre-Cal**

xy=2 {{x^2=3+y^2}}
*Tuesday, October 21, 2008 at 6:16pm by Ash*

**Pre Cal.**

correct.
*Tuesday, March 31, 2009 at 9:28am by bobpursley*

**Pre Cal.**

è is theta.
*Tuesday, April 21, 2009 at 3:12pm by Jamie*

**Pre Cal.**

correct!
*Tuesday, April 21, 2009 at 3:12pm by Reiny*

**Pre-Cal**

(-2,1) and (2,1) are the vertices.
*Saturday, May 2, 2009 at 7:37pm by Hal*

**Pre Cal**

Solve for x 2^x=8^x-3
*Tuesday, December 22, 2009 at 2:53am by Raina*

**Pre-Cal**

Everywhere BUT 0
*Thursday, March 25, 2010 at 10:22pm by Damon*

**Pre-Cal :)**

You're very welcome!
*Saturday, March 27, 2010 at 5:38pm by MathMate*

**Pre-cal**

I agree
*Saturday, May 8, 2010 at 12:23am by Reiny*

**Pre Cal**

What is the inverse of g(x)= 1/2(x-1)^3-4
*Monday, October 25, 2010 at 1:17am by Katie*

**Pre Cal**

40
*Saturday, January 9, 2010 at 5:50pm by Anonymous*

**Pre Cal**

this is wrong
*Sunday, July 24, 2011 at 8:20pm by Dalidah*

**pre-cal**

no "t" in formula
*Monday, January 16, 2012 at 8:07pm by Steve*

**Translation**

It is pre-cal
*Friday, March 23, 2012 at 4:25pm by Sebastian*

**Pre-cal**

123694587
*Thursday, May 6, 2010 at 7:21pm by Anonymous*

**Pre-Cal**

#3 = B 95
*Saturday, March 17, 2012 at 10:21pm by Ryan*

**pre cal**

what is the question?
*Wednesday, February 13, 2013 at 5:08pm by bobpursley*

**Pre cal**

second
*Thursday, January 30, 2014 at 8:42pm by shelly *

**Pre cal**

how do you find A?
*Thursday, January 30, 2014 at 8:42pm by shelly *

**pre cal**

mmmhhh? (0+3)^2 = 3^2 = 9
*Thursday, January 30, 2014 at 8:53pm by Reiny*

**pre cal**

zero
*Thursday, March 6, 2014 at 9:43am by Damon*

**pre cal**

s400
*Sunday, September 4, 2011 at 11:14pm by Halib*

**Chemistry**

Do you know the conversion factor? 1 cal = 4.184 joules and I get 4565 cal. Is that a capital C for cal. In nutrition, especially in the old days, there was a big calorie (actually a kilocalorie or Calorie) and a small calorie (a calorie). If we round the 5 to the even number...
*Friday, October 30, 2009 at 7:22pm by DrBob222*

**pre-cal**

(576^1/2+512^1/3)^1/3 =(√(24*24) + (8³)^(1/3) )^(1/3) =(24+8)^(1/3) =32^(1/3) (Note: check if the question by any chance reads (576^1/2+512^1/3)^1/5)
*Monday, May 31, 2010 at 7:53pm by MathMate*

**Pre-Cal(please check)**

From what I am reading into the diagram, you have a distance down the riverbank of 100ft, then w across the river. The angle to the end of w from the start of the 100ft length is 54deg tangent54=w/100 w= 100 tangent54.
*Tuesday, March 23, 2010 at 4:31pm by bobpursley*

**Pre-Cal (again)**

If: f(x)= 3/x^2-1 g(x)= x+1 What is the domain of f, g, and f o g?
*Saturday, September 20, 2008 at 9:19pm by Crystal*

**Trig/Pre-Cal**

1 - - x > 0 x
*Sunday, September 7, 2008 at 11:18pm by Brooke*

**pre cal**

What would cos2theta=-1/2 be???
*Saturday, November 15, 2008 at 2:45pm by becca*

**pre cal**

what is the sum of e or 1n
*Sunday, January 11, 2009 at 6:07pm by ash*

**Pre-Cal**

Find f X g 3 sqrt of x+1 X x^3+1
*Thursday, February 26, 2009 at 11:32pm by Dan*

**Pre-Cal**

if 2^x=3 whats does 4^-x equal
*Thursday, February 26, 2009 at 11:32pm by Dominique*

**Pre-Cal.**

Graph it on your calculator.
*Thursday, March 26, 2009 at 9:16am by bobpursley*

**Pre Cal.**

all 3 are correct.
*Monday, June 15, 2009 at 6:29pm by Reiny*

**Pre Cal.**

All correct!
*Thursday, August 13, 2009 at 12:45am by MathMate*

**Pre Cal.**

Both correct!
*Thursday, August 13, 2009 at 12:49am by MathMate*

**Pre Cal.**

none of them are correct.
*Saturday, August 15, 2009 at 4:31pm by bobpursley*

**Pre-Cal**

Simplify e^3ln2-1
*Saturday, January 9, 2010 at 11:02pm by jamie*

**Pre-Cal**

1/sec = cos
*Friday, March 5, 2010 at 5:42pm by bobpursley*

**Pre-Cal**

yes, to your second part
*Wednesday, March 10, 2010 at 11:12pm by Reiny*

**Pre-Cal(Please help)**

Error
*Tuesday, March 23, 2010 at 1:05pm by Mark*

**Pre-Cal(urgent)**

Nevermind.
*Wednesday, March 31, 2010 at 11:06pm by Hannah*

**Pre-cal**

both are right.
*Sunday, May 9, 2010 at 7:59pm by bobpursley*

**pre-cal**

(576^1/2+512^1/3)^1/3
*Monday, May 31, 2010 at 7:53pm by Soto*

**pre-cal**

16
*Thursday, September 2, 2010 at 6:06pm by Ms. Sue*

**L Pre-Cal**

yes that was a typo, my bad!
*Wednesday, January 26, 2011 at 7:43pm by Norah*

**Pre Cal**

please explain your b and a.
*Monday, July 25, 2011 at 3:04pm by Ashley*

**Pre cal**

Thank you sooooo much !!!
*Sunday, October 23, 2011 at 8:28pm by Basim*

**Pre Cal**

cos^2+tan^2=1
*Sunday, March 25, 2012 at 7:56pm by Trevion*

**pre-cal**

thank you very much
*Wednesday, April 18, 2012 at 10:52am by sandra*

**Pre-Cal**

YOU SHOULD KNOW HOW TO DO THIS!
*Wednesday, March 25, 2009 at 2:29pm by YOU'RE BAD AT MATH*

**pre cal**

7tan^2(pheta)-2=3
*Thursday, June 28, 2012 at 10:48pm by Maria*

**pre cal**

(y^2)^-4y^8 simplify
*Thursday, August 30, 2012 at 11:20pm by jennifer*

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