April 20, 2014

Search: pr

Number of results: 583

Pr(three heads)= 1/2*1/2*1/2 Pr(one head in three flips)= Pr(HTT)+Pr(HHT) + Pr(HHH)+ Pr(THT)+Pr(TTH)+ Pr(THH)+Pr(HTH) = oddly enough 1/2*1/2*1/2 * 7 check me to make certain I included all the ways to get at least one head. think on that one.
Friday, October 9, 2009 at 10:11pm by bobpursley

College Finite Math
Suppose for this problem that Pr[E]=13/24 and Pr[F]=5/8 and Pr[(E U F)'] = 0. Finding Pr[E/F] and Pr[F/E]. For this problem I added 13/24 + 5/8 and got 1.17, therefore, I assumed that .17 is the intersection between Pr(E) and Pr(F). I know that to solve these problems I have ...
Monday, March 16, 2009 at 3:09pm by Rory

Draw your Venn Diagram My drawing shows that Note: Pr(Junior or Psy)= Pr(Jun)+ Pr(Psy)-Pr(Junior AND Psy) But you are given Pr (NOT(Junior Or Psy), so Pr(Junior or Psy)=1-Pr( Not(junior or Psy). Finally, then Pr(Junior ANd Psy)=Pr(Jun)+Pr(Psy)-Pr(Jun or Psy) = Pr(Jun)+ Pr(Psy...
Monday, February 1, 2010 at 8:08am by bobpursley

Choices are AB, AC, BC, None Pr(A and B)= Pr(A)Pr(B)= 1/4*1/3= 1/12 Pr(B and C)= Pr(B)Pr(C)= 1/3*5/12=5/36 Pr(A and C)= 1/4 * 5/12=5/48 Pr(None)=1- sum of the three other choices above.
Monday, February 1, 2010 at 8:31pm by bobpursley

Okay Last Q's For today Ms. Sue MAth
2. Pr(equal or greater than 3)=Pr(3)+pr(4)+pr(5)+pr(6)=4/6 3. 1/5
Wednesday, April 3, 2013 at 9:46pm by bobpursley

math probability
It looks like a Venn diagram problem to me - which is a pity because I can't draw a Venn diagram here. Never mind: I'll try to manage with just the numbers. Pr(EuF) = P(E) + P(F) - P(EnF) = 0.55 + 0.55 - Pr(EnF) = 0.85, so Pr(EnF) = 1.10 - 0.85 = 0.25. Likewise Pr(EuG) = Pr(E...
Saturday, September 15, 2012 at 6:10pm by David Q/R

In the equation A=p+prt, t is equilvalent to... (1)A-pr (3)A - p _________ ___ p pr (2)A-p (4)A - pr ________ ___ pr p t is time. Your answers are difficult to interpret. Solving for t, t = (A-p)/pr
Tuesday, February 27, 2007 at 8:01pm by megan

P(6) given as .2 P(3<x<5)=Pr(4)=.15 Pr(x>2)=1-Pr(1 or 2or 0)=1-Pr(o)-Pr(1)-Pr(2)
Saturday, September 17, 2011 at 11:01am by bobpursley

Math Probability dice roll
you can get it with a 5,4; 6,3 pr= 2*pr(5,4)+ 2*pr(6,3)= 4*1/6*1/6=1/9 against a 12, that is the same as 1-pr(12) pr= 1-1/6*1/6= 35/36
Monday, April 16, 2012 at 3:57pm by bobpursley

math probability
Assume that Pr[E]=0.55,Pr[F]=0.55,Pr[G]=0.55,Pr[E∪F]=0.85,Pr[E∪G]=0.8, and Pr[F∪G]=0.75. Find: Pr[E' U F]; Pr[F' ∩ G]; and Pr[E ∩ G]
Saturday, September 15, 2012 at 6:10pm by alex

A) PR(B,B)=Pr(b)*Pr(b)=1/2*1/2 B) Pr(g)Pr(b)=1/2*1/2 C) you can get at least one girl these ways: gb bg gg Pr(at least one g)= 1/2*1/2*3
Wednesday, November 18, 2009 at 5:32pm by bobpursley

Use the same formula as the other post: For an annual payment P for n years at interest rate r, the value of the investment is A=Pr^n+Pr^(n-1)+....Pr =Pr(1+r+r˛+...+rn-1) =Pr(rn-1)/(r-1) Here A=122000 n=22 r has not been supplied. Solve for P. Note: Please do not switch screen...
Wednesday, September 22, 2010 at 1:46pm by MathMate

Let E and F be events such that the following is true. Pr (E) = 0.26, Pr (F ' ) = 0.61, Pr (E F) = 0.61 What is Pr (E ∩ F)?
Friday, March 16, 2012 at 11:59pm by Emma

weekly demand data have been analyzed yielding the probability mass fnc. for weekly demad D as follows Pr{D=0}=0.05, Pr{D=1}=0.1, Pr{D=2}=0.2,Pr{D=3}=0.4, Pr{D=4}=0.1,Pr{D=5}=0.1,Pr{D=6}=0.05. Let X be the Markov chain where Xn is the inventory at the end of week n. a) find ...
Thursday, February 26, 2009 at 1:41pm by John

Assumptions: 1. ABCDE is also a pentagon 2. PR is the corresponding diagonal in the 2nd pentagon In that case, the areas of similar figures are proportional to the square of their sides (or their diagonals) PR^2/6^2 = 18/32 PR^2 = 648/32 = 81/4 PR = 9/2
Saturday, October 19, 2013 at 5:24am by Reiny

This is a response to bobpursley's answer of Pr(0) = .3; Pr(1) = 7*.3; Pr(2) = 7*.7. Can you show me how you arrived at the above answers? Also, what does * mean? Thanks.
Sunday, January 2, 2011 at 2:47pm by bree

This is a hydrolysis problem. The sodium propionate ion (which I'll call Pr^-) hydrolyzes. Pr^- + HOH ==> HPr + OH^- Set up an ICE chart and substitute into the Kb expression for Pr^-. (HPr is propionic acid). Kb = (Kw/Ka) = (HPr)(OH^-)/(Pr^-). (HPr_ = x = (OH^-). (Pr^-) = ...
Monday, August 8, 2011 at 7:57pm by DrBob222

It is the product of the two independent probabilities: Pr(4)=1/6 (if it is six sided die) Pr(heads)=1/2 Pr(4 and head)=1/12
Thursday, September 4, 2008 at 4:47pm by bobpursley

Pr (E) = 0.26, Pr (F ' ) = 0.61, Pr (E∪F) = 0.61. What is Pr (E ∩ F)? Hint: use P(F)=1-P(F') P(E∪F)=P(E)+P(F)-P(E∩F)
Friday, March 16, 2012 at 11:59pm by MathMate

Given Pr(a)= 0.9, Pr(C|A)= 0.78 and Pr(D|B) = 0.38. find a. (A|C) = b. (A|D) = c. (B|C) = d. (B|D) =
Monday, October 22, 2012 at 9:54pm by Katie

AP Statistics
a) NNNNY NNNYN NNYNN NYNNN YNNNN so, there are five ways to sort the fourth graders Pr(one)=5*.71*.29^4=.0251 check that. b)Pr(none)=.29^5 c) Pr(at least one)=1-Pr(none)
Sunday, January 3, 2010 at 4:41pm by bobpursley

Pr(1 defective)=1/10*(9/10)^9*10!/(1!9!) = .1(.387)10=.387 Pr(more than two)=1-Pr(two)-Pr(one)-Pr(zero) = 1-.1^2*.9^8 * 10!/(2!8!)-.387-.9^10 = 1-.193-.397-.349=.061 check all this.
Thursday, October 20, 2011 at 2:20pm by bobpursley

I will do two: b) Pr= 13/52 * 13/52 d)Pr(one a queen)= pr(two queens)+pr(one queen) Pr(QQ)+Pr(QN)+Pr(NQ) 4/52*4/52 + 4/52*48/52 + 4/52*48/52 = (16+2*4*48)/52*52=.148 check it.
Saturday, March 13, 2010 at 5:22pm by bobpursley

AP Chem
I'm lazy so let's call sodium propanoate NaPr. The Pr anion is hydrolyzed. Pr^- + HOH ==> HPr + OH^- Kb= (Kw/Ka) = (HPr)(OH^-)/(Pr^-) Substitute for Kw and Ka (for propionic acid) and (Pr^-). Let X = HPr and OH. Solve for x, convert to pOH, then to pH.
Wednesday, March 9, 2011 at 10:16pm by DrBob222

Math check answer
a. what is .13^5 * .87^(31-5) > Put .13^5 * .87^(31-5)= in your google search window. b. at most four students... add the probabliliy of one, two, three, four, and none are left handed. Pr=.13^0*.87^31+.13^1*.87^30 + ... c. at least six? that is the same as 1- ...
Sunday, June 2, 2013 at 7:32pm by bobpursley

Two independent events, A and B, satisfy Pr(A) = 0.6 and Pr(B) = 0.3. In the case of Pr(A or B), why isn't the answer 0.3? We are looking at the probability of A or B. I choose B. Thank you!
Tuesday, February 24, 2009 at 2:56pm by David

pr(H,H)=.6*.6= .36 pr(T,H)= .4*.6=.24 Pr(H,T)=.24 Pr(T,T)=.16 so the likelyhood of one head and one tail is .48, the probablity of both the same is .36+.16=.52
Thursday, July 15, 2010 at 8:21pm by bobpursley

An experiment consists of rolling a weighted die. The probability of rolling each number is: Pr[1]=0.2 , Pr[2]=0.15 , Pr[3]=0.25 , Pr[4]=0.15 , Pr[5]=0.05 , and Pr[6]=0.2 . On the first roll, you record if the number is Small (1,2) or Large (3,4,5,6). If the first number is ...
Friday, March 27, 2009 at 6:40pm by Nahla

a: Pr= .4*.05 b: Pr=.4*.95+ .05*.6=.. c: Pr= 1-Pr(a)-Pr(b)
Friday, October 2, 2009 at 6:52pm by bobpursley

Public Relations
after I wrote this, I realized you are in a PR class. PR folks are addicted to fluff, not data. So my objective above suits management, but PR is much more fluff, and much less dates, cost, and performance. PR is a land I seldom visit, about as often as I visit Neverland. My ...
Sunday, April 6, 2008 at 2:56pm by bobpursley

You can do it this way: Pr(either m or P or both)=1-Pr(neither M or P) Pr(neither)=6/8*5/7*4/6= 120/336=40/112=20/56=10/28= 5/14 Pr(either m or P or both)=1-5/14=9/14
Wednesday, December 16, 2009 at 7:37pm by bobpursley

Am I to assume one candy is selected at random from each bowl? If so, then c) Pr=4/20*8/20 d) pr=1-pr(same)=1=4/20*8/20-5/20*5/20 - 6/20*4/20-5/20*3/20 e. pr=5/20*4/20
Monday, March 4, 2013 at 8:08pm by bobpursley

assume 100 folks. Those numbers as percents are now real humans. Pr(ulcers)=(1+3+3+4)/100 Pr(ulcer:no drink)=1/(22+1) pr(no drink:ulcer)=1/(1+3+3+4) Pr(two drinks: no ulcer)=32/(22+19+32+16) check me.
Thursday, October 21, 2010 at 3:38pm by bobpursley

computer science
calculate the steady state probability of source emitting a "0" from "Applied coding and information theory for engineers" page 70, chapter 2, example 2.4.4 pi0=1/9 pi1=pi2=2/9 pi3=4/9 For Pr(0) how are the values for Pr(0/Sn) found, by my observation, Pr(0/S3) should be 0 but...
Tuesday, July 13, 2010 at 3:36pm by Olla

Call propionic acid HPr. HPr ==> H^+ + Pr^- Ka = (H^+)(Pr^-)/(HPr) initial: HPr = 0.1994 M H^+ 0 Pr^- = 0 final: pH = 2.795. Convert to (H^+) by pH = -log(H^+) = ?? Pr^- = same as H^+. HPr = 0.1994-(H^+) Substitute into Ka expression and solve for Ka.
Monday, May 10, 2010 at 9:48pm by DrBob222

Not certain of the finalanswer? Pr(pass)=.51 Pr(fail)=1-pr(pass)=1-.51 Use your calculator, if you need, to solve that.
Friday, July 30, 2010 at 5:36pm by bobpursley

at least four make a purchase? pr(at least four)=Pr(4)+pr(5)+... = p^4q^6+P^5q^5+p^6q^4+p^7q^3+...p^10q^0 where p=.4, q=.6
Wednesday, October 24, 2012 at 7:31pm by bobpursley

For an annual payment P for n years at interest rate r, the value of the investment is A=Pr^n+Pr^(n-1)+....Pr =Pr(1+r+r²+...+rn-1) =Pr(rn-1)/(r-1) After 8 years P=5000 r=1.0615 n=8 A=5000*1.0615*(1.0615^8-1)/(.0615) =52814.48 For the next 4 years A=52814.48*1.0615^4 =...
Wednesday, September 22, 2010 at 1:48pm by MathMate

If one considers each day independent of the day before (it is not), pr(rainanyday)=5/7 Pr(rainonly one day)= 5/7 * 2/7 * 2ways what can it happen on the weekend? RR RN NR NN so of the possibilities, RN or nR are what we focus on. Pr(rain only one day)=20/49 Lets check Pr(rain...
Saturday, January 31, 2009 at 9:06pm by bobpursley

ap chemistry
Propanoic acid = HPr HPr ==> H^+ + Pr^- Set up an ICE chart and substitute into the below equation. Ka = (H^+)Pr^-)/(HPr) Solve for (H^+) and convert to pH. (Pr^-) = (H^+) You can find OH^- from (H^+)(OH^-) = 1E-14 %diss = (H^+)/(HPr)*100 = ??
Wednesday, April 6, 2011 at 8:16pm by DrBob222

even sum 2, 4, 6, 8 , 10, 12 ways 1,1 one way 3,1;2,2; 1,3 three ways 5,1;4,2;3,3;3,3;1,5;2;4 six ways and continue... So for the pr (2)=1/6*1/6 pr(4)=1/6*1/6*3 pr(6)=1/6*1/6*6 and continue
Tuesday, February 15, 2011 at 8:35am by bobpursley

The pH is determined by the hydrolysis of the propionate ion, which I will call Pr^- Pr^- + HOH ==> HPr + OH^- Set up an ICE chart and substitute into the following Kb expression. Kb = (Kw/Ka) = (HPr)(OH^-)/(Pr^-) Kw you know Ka you know (HPr) = (OH^-) = x (Pr^-) = you don'...
Tuesday, May 3, 2011 at 4:16pm by DrBob222

Let HPr = propionic acid. HPr ==> H^ + Pr^- Set up an ICE chart. Ka = (H^+)(Pr^-)/(HPr) You know (H^+) from the problem. (Pr^-) is the same as (H^+). (HPr) = moles/L and you have the information to calculate that. Solve for Ka.
Monday, April 11, 2011 at 4:55am by DrBob222

Pr= get to school|didnt ring * pr didn't ring + get to school|did ring * pr did ring Pr= .8*.9 + .3*.2= .72+.06
Friday, October 2, 2009 at 6:56pm by bobpursley

In the U.S. 42% of the population has type A blood. Consider taking a sample size 4. Let y denote the number of persons in the sample with type A blood. a)Pr(y=O) b)Pr(y=1) C)Pr(y=2)
Tuesday, February 5, 2008 at 7:32pm by alice

Math is this right
Solve for t: I= Prt I/pr = prt/pr I/pr=t
Monday, January 7, 2008 at 10:39pm by Ronique

Pr(woman)=4/10 Pr(man)=6/10 or 1-Pr(woman) Pr(president)=1/10
Saturday, June 25, 2011 at 7:10am by bobpursley

Pr(NOT arm)=.98 Pr(NOT arm NOR leg)= 1-Pr(leg)-pr(arm)
Friday, May 18, 2012 at 10:40am by bobpursley

pr(marcadores)=3/10 pr(bolígrafros)=5/10 pr(lápices)=2/10
Monday, November 15, 2010 at 11:52am by bobpursley

larger than 9? that means 10,11, 12 Well, to get a 12, you can do it one way: Pr=1/6*1/6 To get an 11, you can do it two ways (5,6, or6,5) Pr= 2*1/6*1/6 To get a 10, you can do it 64,46,5,5 three ways Pr=3*1/6*1/6 add the probabilities of all the combinations.
Sunday, September 19, 2010 at 9:37pm by bobpursley

I will do one b) Pr(at most two heads)=1-Pr(three heads)-Pr(no heads) Pr(at most two heads)=1-(1/2)^3 - (1/2)^3 = 1-2/8= .75 Lets do it the other way.. Pr(at most two heads)=Pr(one head) + Pr(two heads) Now note, there are three ways one can get one head, and three ways one ...
Thursday, October 23, 2008 at 2:09pm by bobpursley

What is the difference between Keq and the term of [prod]pr / [react]pr?
Monday, September 1, 2008 at 8:29pm by chemistry

Algebra 1
Bobpursley told you to divide both sides by PR. I = Prt I/Pr = t
Monday, November 9, 2009 at 4:15pm by Ms. Sue

pr(3 makes)=.877^3 pr(missingone)= 3*.123*.87^2
Sunday, July 10, 2011 at 10:27pm by bobpursley

Algebra 2
Pr(winning) = sum of prob of the ways to win... Pr= 1/2 * .65 + 1/2 * .32= you do it.
Sunday, February 9, 2014 at 3:43pm by bobpursley

basic Algebra
Value = P + Pr + Pr^2/4 Plug in the numbers.
Friday, November 26, 2010 at 11:05pm by drwls

pr(at least one)=1-pr(none)=1-.86^8
Tuesday, April 2, 2013 at 3:40pm by bobpursley

Not too sure just what you're after, but the expression is P(1+r/2)^2 P + Pr + Pr^2/4
Saturday, August 10, 2013 at 5:27pm by Steve

in the equation A=p+ pr, t is equivalent to? is the answer A-P/pr
Saturday, January 10, 2009 at 3:11pm by Anonymous

One comment. On the at least on head in three flips should equal the 1-Pr(no heads)0r 1=Pr(TTT) or 1-1/2*1/2*1/2= 7/8
Friday, October 9, 2009 at 10:11pm by bobpursley

Decision Sciences
What is the expected value of each outcome, that is the point of the assignment. EV=Pr(favorable)*valuefavorable-Pr(unfavor)*velueunfavorable
Monday, November 18, 2013 at 4:08pm by bobpursley

Pr(h,qh)=1-pr(nohearts, not qhearts)= 1-(39/52)(50/51) Pr(qH,h)=(1/52)(12/51) check my thinking
Sunday, January 9, 2011 at 2:42pm by bobpursley

oops. Pr(NOT arm NOR leg)=1-Pr(arm or leg) = 1-Pr(arm)-Pr(leg)+pr(arm AND leg) = 1-.02-.03+.02*.03
Friday, May 18, 2012 at 10:40am by bobpursley

Of course they are not independent. The ways to get six total on both die are 5,1 1,5 4,2 2,4 3,3 or five ways. If the first three is secluded, there are only four ways to get six. Pr(E)=1/6 Pr(F)=5/36 Pr(F|E)= 1/6 Two events, E and F, are independent if the fact that E occurs...
Sunday, August 15, 2010 at 1:35pm by bobpursley

ok, then the question is what is the probability of all 17 wanting seats? Pr(all)=.89^17 Pr not enough seats=Pr(all)
Wednesday, June 12, 2013 at 3:27pm by bobpursley

Credit Policies and Procedures
P = principal r = interest rate per period n = number of periods M = monthly payment M = Pr/[1 - (1+r)^-n] So, start out with principal P. The 1st payment will have interest Pr So, Pr will go to interest, M-Pr will go to principal. For the next payment, use the reduced ...
Thursday, September 22, 2011 at 10:59pm by Steve

Pr=1-prwinning=1=- 1*1/3*2/3=1-2/9=7/9 is probablility of no one winning each game Pr this happening four games= that to the 4th power, or (7/9)^4 = about .366
Sunday, November 25, 2012 at 3:45pm by bobpursley

propionic acid = HPr = 0.085M KPr = potassium priopionate = 0.06 ........HPr ==> H^+ + Pr^- I.......0.085....0.....0 C........-x.......x....x E......0.085-x....x....x Ka = (H^+)(Pr^-)/(HPr) Substitute Ka. (H^+) = x (Pr^-) = x + 0.06 (HPr) = 0.085 Solve for H^+ and convert ...
Saturday, February 23, 2013 at 12:22pm by DrBob222

No, you did the probability of drawing two spades. As I read the question, you want the probabilitiy of one spade or one heart, Pr= Pr(one spade and one club/diamond)+pr(heart and one club/diamond). Pr=13/52* 26/51 + 13/52*26/51 check my thinking.
Thursday, August 13, 2009 at 12:02pm by bobpursley

In a triangle ABC, AB = 2 cm, BC = 3 cm and AC = 4 cm. Choose the two options which give a triangle PQR which is similar to triangle ABC. Options: A. PQ = 1 cm, QR = 2 cm and PR = 3 cm. B. PQ = 1 cm, QR = 1.5 cm and PR = 2 cm C.PQ = 2.5 cm, QR = 1.5 cm and PR = 3 cm. D. PQ = ...
Friday, April 20, 2007 at 7:36pm by katie

make a sketch with O the origin OP = 480 and south along the y-axis. draw OR as the resultant of length 528 and angle POR = 15° Complete the parallogram with OQ =PR and QR = OP by cosine law: PR^2 = 480^2 + 528^2 + 2(480)(528)cos15° PR = 139.9125 So the wind speed is 139.9 km/h
Monday, May 2, 2011 at 4:07pm by Reiny

consider the Pr of two letters the same: 1/26 Now consider the Pr of two numbers: 1/10*9/10*8/10 Now the Pr of three numbers the same: 1/10*1/10*9/10 now the Pr of four numbers the same: 1/10*1/10*1/10 now the pr of having two pairs of numbers the same: 1/10*9/10*1/9 Pr(at ...
Friday, July 30, 2010 at 9:35pm by bobpursley

Pr(zero men)=4/7*3/6=12/42 pr (one man)=3/7*4/6+4/7*3/6=24/42 Pr(two men)= 3/7*2/6= 6/42 Now if you mean by "expected" value, then one man is expected.
Wednesday, November 9, 2011 at 4:24pm by bobpursley

Pr(one)=.02 pr(both)=.02*.02 Pr(neither)=.98*.98 pr(one or other)=.02*.98+.98*.02
Friday, October 9, 2009 at 1:14pm by bobpursley

Suppose the cordinate of P is 2, PQ = 8, and PR = 12. What are the possible cordinates of the midpoint of the given segment? PQ PR QR
Wednesday, January 23, 2013 at 10:45pm by Renee

Getting 5 or 10? 1,4 4,1 3,2 2,3 5,5 6,4 4,6 7 ways to get the event, so Pr=7/36 Then the complement Pr= 1-Preventg= 29/36
Thursday, May 20, 2010 at 7:04pm by bobpursley

Pr(Cash or check)=Pr(cash)+Pr(check)-Pr(cash AND check) pr(Cash AND check)=(.51+.54-.71) cash, check are not mutually exclusive
Saturday, October 22, 2011 at 9:54am by bobpursley

Alegbra 1
S=P+Prt for T Subtract P from both sides. S-P = P-P+Prt Combine terms. S-P = Prt. Divide both sides by Pr (S-P)/Pr = (Prt)/Pr etc.
Tuesday, September 15, 2009 at 2:35pm by DrBob222

Pr(less=4)=1-Pr(a 5 or 6)= 1-2/6=4/6
Sunday, February 21, 2010 at 11:32am by bobpursley

Pr(E) = 5/8 Pr(~E) = 3/8 Odds are 5:3
Tuesday, July 10, 2012 at 12:05pm by Steve

I would figure the prob of getting 25 or less first. You cant choose three of those bill to get 25 or less. So the probablility of getting an average of 26 dollars is 1. Now, if you mean by average value getting a total amount on the three bills of 26*3 or more, Pr(78dollars)=...
Thursday, October 16, 2008 at 1:47pm by bobpursley

Pr(0)=.3 Pr(1)= .7*.3 pr(2)=.7*.7
Sunday, January 2, 2011 at 12:35pm by bobpursley

HPr ==> H^+ + Pr^- Set up an ICE chart. Ka = (H^+)(Pr^-)/(HPr) Solve for (H^+) and convert to pH. Post your work if you get stuck.
Saturday, April 18, 2009 at 5:11pm by DrBob222

Pr(red|bag1)=3/8 pr(red|bag2)=5/20 which is the higher probability?
Thursday, December 2, 2010 at 7:48pm by bobpursley

pr(1 or more red)=1-pr(no red) = 1-(6/13)(5/12)(4/11)(3/10)(2/9)
Wednesday, August 17, 2011 at 9:54pm by bobpursley

Propanol = pr Methanol = me Pure pr = 44.6 Pure me = 303 The difference between pure pr and pure me is 303-44.6 = 258.4 delta P from pure pr = 131-44.6 = 86.4 delta P from pure me = 303-131 = 172.0 86.4/258.4 = mole fraction me. 172.0/258.4 = mole fraction pr. The best way to ...
Saturday, April 23, 2011 at 4:50pm by DrBob222

The pH will be determined by the hydrolysis of the salt, sodium propionate. If we abbreviate propanoic acid as HPr, then the titration is HPr + NaOH ==> NaPr + H2O The salt is NaPr and it's the Pr^- that is hydrolyzed. Pr^- + HOH ==> HPr + OH^- Set up an ICE chart and ...
Sunday, April 3, 2011 at 5:10pm by DrBob222

Statistics - Probability
Pr(at least one false)=1-pr(gettingnofalse)=1-.83^10 .83^10=.155, so pr(getting at least one false in 10) is 1-.155=.845 Hmmm. So, the thought of annual mammograms is comforting?
Thursday, July 14, 2011 at 10:11am by bobpursley

showing a circle with centre 0. 0M and 0N meet the chords PR and RS perpendicularly at M and N respectively Given that PR=12cm and RS=16cm find the radius
Tuesday, January 25, 2011 at 10:11am by Lola

Can anyone help me solve this : Assume that you have a disc-system with 300 256-byte sectors pr. track and assume that the disc rotates with 800 rpm. How long time does it take to read a sector? The answer should be in microseconds. Search time isnt needed. Solved it myself. ...
Friday, November 24, 2006 at 11:15am by Magnus

PR~=QR, PQ=x+3, QR=x+6. The perimeter is 93. Find x and PR.
Tuesday, October 9, 2012 at 10:52am by Anonymous

1) For each of the following partial diploids, give the cellular phenotypes for A and B. Explain. A B a. for a negatively regulated gene: F’pR- poA-B/ pR po-AB- F’p-R p-oA-B/ pR- poAB- b. for a positively regulated gene: F’pR- poA-B/ pR po-AB- F’p-R p-oA-B/ pR- poAB- 2) Would ...
Friday, November 18, 2011 at 2:11pm by Tommy

In Drosophila melanogaster, the genes for purple eyes (pr) and curved wings (c) are on the same chromosome. The recombination frequency between pr and c is roughly 20%. Both the purple eyed and curly winged phenotypes are recessive to the wild-type (+) phenotypes (red-eyed and...
Thursday, March 21, 2013 at 2:39am by qwerty

Because the probabilities add to greater than 1.0, some of them must be joint events (too much enamel and uneven, for instance) Prob (paint defect)=1-Pr(nodefects)=.58 Pr(improper)=.45/.58
Wednesday, September 29, 2010 at 6:57pm by bobpursley

Your numbers are nuts, so I assume it should read 0.110, 0.210, 0.310 as the probabilities of Head. pr(at least once)=1-pr(no heads) = 1- (.890)(.790)(.690)=.515 1000p=515
Sunday, February 10, 2013 at 4:10am by bobpursley

PR/QR = sin(Q) PR/120 = sin(10.5)
Tuesday, April 15, 2014 at 8:07pm by Steve

Algebra 1/Geometry
1. |-5 1/4 - 2/3| |-5 3/12 - 8/12| I forgot how to subtract fractions like the one above, can anyone refresh my memory? 2. Q bisects segment PR, PQ = 3y, and PR = 42. Find y and QR. Don't know how to do this. Explain to me please?
Wednesday, September 10, 2008 at 11:14pm by Jay

Not quite. Let's call propionic acid (Propanoic acid) HPr to avoid all that typing. HPr ==> H^+ + Pr^- K = (H^+)(Pr^-)/(HPr) Now, we have 37 g HPr/L which is 37/74 = 0.50 mole/L = 0.50 M. Set up an ICE chart. (H^+) = x (Pr^-) = x (HPr) = 0.5-x Substitute into Ka expression ...
Tuesday, July 27, 2010 at 9:45pm by DrBob222

Suppose the coordinate of P is 2, PQ = 8, and PR = 12. What are the possible coordinates of the midpoint of the given segment? The coordinates are PQ, PR, and QR.
Sunday, August 28, 2011 at 2:50pm by Terry

Kevin has 11 CDs in his glove compartment. Six are rock and 5 are rap. He selects 3 cds at random. What is the probability that he picks at least 2 rap cds? Pr (two)=5/11 * 4/10 * 6/9 Pr (three ) =5/11 * 4/10 * 3/9 add those. Not quite bobpursley. There are 3 ways to pick 2 ...
Tuesday, December 12, 2006 at 7:00pm by matt

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