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April 16, 2014

Search: physics-Moment of Inertia

Number of results: 109,976

physics
M = 110 m = 50 r = 4 The moment of inertia of the disk about the axis is .5 M r^2 The moment of inertia of the woman about the axis is m r^2 Total moment of inertia I = .5 Mr^2 + m r^2 angular velocity w = 2 pi * .5 radians/second angular momentum = I w = [.5 M + m] r^2* (2 pi...
Saturday, April 12, 2008 at 8:48pm by Damon

Physics
angular acceleration = (Torque)/(Moment of inertia) For a solid disc, Moment of Inertia = (1/2) M R^2 The answer will be in radians/second^2
Saturday, December 11, 2010 at 4:23pm by drwls

Physics
r = .19 meter I = (1/2) m r^2 is moment of inertia of disk I = (1/2)(45)(.19)^2 That is the rotational moment of inertia, I suspect what you want. If you really want the rotational inertia you must multiply that by omega, the angular velocity in radians per second.
Sunday, November 13, 2011 at 3:54pm by Damon

physics
It may have asked for the moment of inertia, I. In this case it would be (1/12)(0.58 kg)*(1.67 m)^2 The moment of inertia measured the intertial resistance to rotation, and the energy associated with rotary motion.
Wednesday, December 16, 2009 at 10:38pm by drwls

physics
I can't see your Fig. 2, but all you have to do is subract the moment of inertia of cavity, treating it as if it were a mass with the same density. Subtract it from the moment of inertia of the larger disc, treating it as having no hole. You may have to use the parallel axis ...
Thursday, December 29, 2011 at 12:09pm by drwls

physics
Angular momentum (I*w) is conserved. However the moment of inertia (I) increases and the angular velocity (w) decreases. The initial moment of inertia is I1 = (1/2)md*R^2 = 4950 g*cm^2 The final moment of inertia is I2 = (1/2)md*R^2 + mb*R^2 = 4950 + 900 = 5850 g*cm^2 new rpm/...
Sunday, March 25, 2012 at 9:45pm by drwls

physics
The moment of inertia of the disc before the hole is drilled is I0 = (1/2) M R0^2. From that, SUBTRACT the moment of inertia of what the hole would be, if it were solid and displaced h from the center. Its mass would be m = M(R1/R2)^2 Using the parallel axis theorem, its ...
Saturday, April 12, 2008 at 4:13am by drwls

Physic Moment of inertia
Determine the moment of inertia of a 11.1kg sphere of radius 0.794m when the axis of rotation is through its center.
Saturday, March 29, 2014 at 11:17am by David

Physics
What is the moment of inertia of an object that rolls without slipping down a 2.00-m-high incline starting from rest, and has a final velocity of 6.00 m/s? Express the moment of inertia as a multiple of MR2, where M is the mass of the object and R is its radius.
Sunday, July 14, 2013 at 5:15pm by Justin

Physics
. (a) Calculate the angular momentum of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.400 kg ⋅ m2. (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of ...
Sunday, July 14, 2013 at 5:15pm by Justin

physics
(a) Calculate the angular momentum of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.490 kgm2. (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia if ...
Wednesday, July 17, 2013 at 11:24pm by Wendy

physics please help me
angular acceleration = (Torque)/(moment of inertia) The units will be radians/s^2 if torque and moment of inertia are in the units given.
Saturday, November 27, 2010 at 6:09pm by drwls

physics
A toy consisting of two balls, each m = 0.56 kg, at the ends of a l = 0.73 m long, thin light-weight rod is shown below. Find the moment of inertia of the toy. The moment of inertia is to be found about the center of the rod.
Thursday, January 10, 2013 at 7:29pm by Anonymous

Classical Mechanics Physics - Urgent help please
You used moment of inertia about center of the ruler. But in your calcs you assume that it is rotating about its end. Shouldn't you use instead moment of inertia bout the end, when calculating KE of rotation?
Saturday, December 7, 2013 at 5:46pm by Damon

Classical Mechanics Physics - Urgent help please
@Damon You used moment of inertia about center of the ruler. But in your calcs you assume that it is rotating about its end. Shouldn't you use instead moment of inertia bout the end, when calculating KE of rotation?
Saturday, December 7, 2013 at 5:46pm by C_P

Physics
(a) (earth's velocity in orbit)x(distance from sun) (b) This requires the moment of inertia about its axis, I. Assume mass is uniformly distributed and use I = (2/5)M*R^2 which applied to solid spheres. The moment of inertia of rotation is I*w where w is the angular velocity ...
Friday, March 18, 2011 at 6:46pm by drwls

Physics
The center of mass goes down by the radius r the change in potential energy is m g r that is the kinetic energy (1/2) I w^2 I is the moment of inertia about the pivot point which is the moment of inertia about the center + m r^2 the velocity v = w r
Saturday, March 19, 2011 at 9:13pm by Damon

physics
Yes, that is correct. (1/2) I w^2 I = 7.24 * 10^-3 kilograms m^2 is called the moment of inertia, not the inertia rotation.
Friday, April 10, 2009 at 11:38pm by drwls

Physics
The system moment of inertia will be the sum of all three. If the masses are the same, and the lengths the same, 3/2mr^2 will be total. Remember, when you derived the moment of inertia, you integrated (summed) all point masses at some distance r from the rotation.
Wednesday, July 28, 2010 at 11:09am by bobpursley

Physics review
So I've already found/ was given the radius, hanging mass, and acceleration for three objects but I need to find the moment of inertia using all those three. What equation do I use or how do I incorporate all of them to find the moment of inertia?
Thursday, July 12, 2012 at 5:21pm by hayley

Physics
Consider the angular moment of inertia to be I. Then the moment of inertia due to m at some r is 1/2 m r^2 conservation of momentum: Iinitial wi= Ifinal * Wf (I+1/2mr^2)w=(I + 1/2 m 0^2)wf (I+1/2 45*2).5=(I wf) you are given I as 360 405*.5=360 wf wf=.563 rad/sec check me.
Wednesday, December 15, 2010 at 7:41pm by bobpursley

Physics
The mass or moment of the axle must be specified because its moment of inertia affects the answer.
Saturday, March 17, 2012 at 5:22pm by drwls

Physics
The moment of inertia (rotational inertia) of the rectangular plate about the axis passing along the axis is Iₒ=ma²/3, where a= 1.5 m. Moment of inertia of the whole door is I=4Iₒ=4ma²/3 =439.51.5²/3=117.9 kgm². f=1/10.5=0.095 Hz KE=Iω&#...
Thursday, July 5, 2012 at 11:33pm by Elena

physics
Suppose that you measured the moment of inertia of the system as I = 5.05 kg-m2. Assume the diameter of the pulley around which you wrap the string is d = 2.5 cm. a) suppose the system is initially spinning at angular speed ωo = 2.05 rad/s. After you drop a cube of mass ...
Tuesday, November 30, 2010 at 12:50am by dan

Physics review
Goodness. If they are spinning about the same axis, add the three moments of inertia to get the total moment of inertia. Now each one individually, torque=momentinertia*acceleration force*distance=momentinertia*acceleration solve for moment of inertia. I am a little confused ...
Thursday, July 12, 2012 at 5:21pm by bobpursley

Physics
a) Convert revolutions per minute to radians per second. Surely you can do that. b) The moment of inertia of a disc of radius R and mass M is I = (1/2)M*R^2 c) Convert 800 rev/min to w = ___ radians/sec, and divide that by 8.0 seconds for the angular acceleration, ____rad/s^2...
Sunday, July 29, 2012 at 6:28pm by drwls

Physics
A cylinder with moment of inertia 22.1 kg m2 rotates with angular velocity 5.71 rad/s on a frictionless vertical axle. A second cylinder, with moment of inertia 28.3 kgm2, initially not rotating, drops onto the first cylinder and remains in contact. Since the surfaces are ...
Thursday, June 27, 2013 at 10:38am by Wolves

physics
A 90kg stuntman falls from a building that is 80 meters tall. (Vo = 0) Fortunately, the stuntman is attached to a cable that is wrapped around a flywheel (massive spool), with a radius of 0.5m. If the man takes 8 seconds to reach the ground, (a) what is the moment of inertia ...
Thursday, March 7, 2013 at 7:34pm by Sam

Physics
A 90kg stuntman falls from a building that is 80 meters tall. (Vo = 0)Fortunately, the stuntman is attached to a cable that is wrapped around a flywheel (massive spool), with a radius of 0.5m. If the man takes 8 seconds to reach the ground: (a) what is the moment of inertia of...
Thursday, March 7, 2013 at 8:13pm by Sam

physics
torque= momentInertia*angacceleration 210*.330= moment Inertia*1.161 look up the momentu of inertia here:http://www.physics.uoguelph.ca/tutorials/torque/Q.torque.inertia.html and solve for mass
Wednesday, November 9, 2011 at 9:02pm by bobpursley

Physics
m(hole)= m, M(plate)=M We must treat the holes as the objects of negative mass. The moment of inertia is I=I(plate) 3I(hole). The plate is disk => I(plate)=MR²/2. The moment of inertia of the hole using the parallel axis theorem is I(hole)= mr²/2 + m (R/2)&#...
Friday, November 2, 2012 at 6:29pm by Elena

12th grade
A bicycle wheel has a radius of 0.330 m and a rim whose mass is 1.20 kg. The wheel has 50 spokes, each with a mass of 0.010 kg. a.) Calculate the moment of inertia of the rim about the axle. b.) Determine the moment of inertia of any one spoke, assuming it to be a long, thin ...
Wednesday, March 10, 2010 at 12:22am by Janelle

Physics Inertia : Merry-go-round
A playground merry-go-round of radius 1.96 m has a moment of inertia 335 kg m2 and is rotating at 12.3 rev/min. A child with mass 43.1 kg jumps on the edge of the merry-go-round. What is the new moment of inertia of the merry-go-round and child, together? Answer in units of kg...
Monday, April 19, 2010 at 11:08pm by HELP ME!!

Physics. PLEASE HELP!!
The moment of inertia of each spoke (of the length R) respectively its end is I(sp) = I(o) + mx^2 = mR^2/12 + m(R/2)^2 = mR^2/3 = . The wheel rim is a hoop with I(rim) = MR^2. The moment of inertia of the wheel is I = I(rim) + 6I(spoke) = MR^2 + 6mR^2/3
Friday, April 20, 2012 at 12:35pm by Elena

physics
Four objects are held in position at the corners of a rectangle by light rods . m1 2.90(kg) m2 1.90(kg) m3 4.50(kg) m41.90 (kg) (a) Find the moment of inertia of the system about the x-axis. Answer in kg m2 (b) Find the moment of inertia of the system about the y-axis. ...
Wednesday, October 26, 2011 at 4:30pm by Allie

physics
A uniform brass disk of radius R and mass M with a moment of inertia I about its cylindrical axis of symmetry is at a temperature T = 45 C. Determine the fractional change in its moment of inertia if it is heated to a temperature of 125 C. (The linear expansion coefficient ...
Friday, July 20, 2012 at 10:32am by Bruce

College Physics
Check your units (are they meters?) and your decimal point. The center of the stick is at the 0.50 m mark and the moment of inertia about that point is (1/12)ML^2 = 0.0483 kg m^2. (L = 1.0 m and M = 0.4833 kg) Using the parallel axis theorem, the moment of inertia about an ...
Tuesday, December 1, 2009 at 9:29pm by drwls

Physics
Torque = (Moment of Inertia)*(Angular deceleration) The moment of inertia is I = (1/2)*M*R^2 = 3*(0.2)^2 = 0.12 kg*m^2 Angular deceleration = (4 rad/s)/2s = 2 rad/s^2 Torque = 0.12 * 2 = 0.24 Newton-meter
Tuesday, February 5, 2013 at 12:36am by drwls

Physics hw question mistake
Hello, I didn't post the correct questions correctly so here they are: Hello, I have some questions: 1. Do you think the calculated moment of inertia is larger or smaller than the true moment of inertia? Explain. for static moment of inertia I have:.0202kgm^2 for dynamic " ":....
Thursday, November 16, 2006 at 12:34pm by Teenesha

physics
A diver in midair has an angular velocity of 6.0 rad/s and a moment of inertia of 1.2 kgm2. He then pulls is arms and legs into a tuck position and his angular velocity increases to 12 rad/s. The net external torque acting on the diver is zero. What is his moment of inertia ...
Tuesday, November 1, 2011 at 7:15pm by jason

physics
Angular acceleration = Torque/(moment of inertia) The moment of inertia is (1/2) M R^2 for a disk. After 10 seconds, the number of radians turned is theta = (1/2)(angular acceleration)*(10 s)^2 Divide that by 2 pi for the number of revolutions. Rotational work done is (torque...
Saturday, December 4, 2010 at 8:46am by drwls

physics
Interestingly, there have been several studies using cadavers to determine the moment of inertia of human body parts by letting them swing as a pendulum about a joint. In one study, the center of gravity of a 5.0 kg lower leg was found to be 18 cm from the knee. When pivoted ...
Tuesday, April 13, 2010 at 12:12pm by zidd

momentum
Convert rpm to rad/s to do the problem using conservation of angular momentum. Covert back to rpm when you get the answer. The child increases the moment of inertia by walking to the outer edge of the disk. I assume you know the formula for the moment of inertia of the disk
Friday, November 20, 2009 at 1:07am by drwls

physics
An ice skater has a moment of inertia of 2.3 kg * m^2 when his arms are outstretched and a moment of inertia of 1.0 kg * m^2 when his arms are tucked in close to his chest. If he starts to spin at an angular speed of 2.0 rps (revolutions per second) with his arms outstretched...
Monday, April 11, 2011 at 9:08pm by Dorian

Physics
ah, it turns out I took this course in 1955 and have had lots of practice since. I do not need to do your homework. However you do. Try the problems then comeback to us with specific things you are stuck on. The first part is moment or torque = moment of inertia * angular ...
Monday, April 23, 2012 at 7:57pm by Damon

Physics
A woman stands at the center of a platform. The woman and the platform rotate with an angular speed of 4.00 rad/s. Friction is negligible. Her arms are outstreched, and she is holding a dumbbell in each hand. In this position the total moment of inertia of the rotating system...
Wednesday, March 21, 2007 at 12:28pm by CJ

physics
A wheel is roatating freely at an angular speed of 800 rev/min on a Shaft of negligible moment of inertia. A second wheel initially at rest and with twice the moment of inertia of the first, is suddenly coupled to the same shaft. (a) what is the angular speed of the resultant...
Friday, December 3, 2010 at 3:38pm by kwaku

physics
A wheel is roatating freely at an angular speed of 800 rev/min on a shaft of negligible moment of inertia. A second wheel initially at rest and with twice the moment of inertia of the first, is suddenly coupled to the same shaft. (a) what is the angular speed of the resultant...
Sunday, December 5, 2010 at 4:01pm by Ama

Physics
A 10 m platform diver during his diving can increase his rotation rate from an initial rate of 0.8 rev/s to a maximum of 3.3 rev/s. If his initial moment of inertia was 10 kgm2, what is his moment of inertia at his maximum rotation rate?
Friday, April 26, 2013 at 10:44am by Derrick

moments of inertia
The area moment of inertia can be verified with a beam deflection experiment. Load the beam at the middle with freely supported edges, or cantilevered from one wall with a clamped edge, for example. For the polar moment of inertia about a perpendicular axis through the ...
Wednesday, April 7, 2010 at 9:55am by drwls

physics
A student opens a 12.0 kg door If the door is 2.00 m in height and 1.00 m wide what is the moment of inertia of the door about its hinges. The equation for moment of inertia about the hinges is I =1/3 mr^2 should i use the the width or the height as my r i think it should be ...
Sunday, April 19, 2009 at 12:50am by seth

Physics
Torque = (moment of inertia)*(angular acceleration) alpha = angular acceleration = 150 N m/0.6kg/m^2 = 250 rad/s^2 w = angular velocity at release = (angular acceleratio)*0.15 s = 37.5 rad/s Ball release velocity V = w*R = 33.8 m/s = 111 ft/s = 75.5 mph The mass of the ball ...
Wednesday, April 6, 2011 at 6:26pm by drwls

physics
The rotational energy of each astronaut is 1/2 * I * omega^2 where I is the moment of inertia, and omega is the angular speed. The moment inertia of the astronaut is m*r^2 r = 12.0 / 2 = 6 m v = 5 m/s = omega*r The total rotational energy is 1/2 * I * omega^2 + 1/2 * I * omega...
Sunday, November 11, 2012 at 7:48pm by Jennifer

physics
a circular disc rotates on a thin air film with a period of 0.3s. its moment of inertia about its axis of rotation is 0.06kgm^2. a small mass is dropped onto th disc and rotates with it . the moment of inertia of the mass about the axis of rotation is 0.04kgm^2.determine the ...
Saturday, February 11, 2012 at 10:14am by ashely

Physics
a circular disc rotates on a thin air film with a period of 0.3s. its moment of inertia about its axis of rotation is 0.06kgm^2. a small mass is dropped onto th disc and rotates with it . the moment of inertia of the mass about the axis of rotation is 0.04kgm^2.determine the ...
Wednesday, January 9, 2013 at 3:40am by Suroj

Physics
A cord is wrapped around the rim of a wheel .250 m in radius, and a steady pull of 40.0 N is exerted on the cord. The wheel is mounted on frictionless bearings on a horizontal shaft through its center. The moment of inertia of the wheel about this shaft is 5.00kg*m^2. Compute ...
Tuesday, March 27, 2007 at 12:00pm by Karla

physics-Moment of Inertia
Two equal masses m are place at positions r1= (L, 2L, 3L) and r2= (3L, L ,2L). Calculate the moments of inertia Ix, Iy, Iz of the system with respect to the x, y, and z axes.
Wednesday, May 4, 2011 at 7:10am by Sandhya

Physics
What are the units of what you call "the inertia"? Is that supposed to be the MOMENT OF inertia of the wheel? Do you know what that means? If you know the acceleration rate of the mass going dwn the incline, you should be able to say how fast the wheel is turning after 2.0 ...
Friday, March 26, 2010 at 12:16pm by drwls

physics
Think of this as a torsional spring, with a torsional stiffness coefficient k = (0.37/0.93) = 0.398 N*m/radian The equation of motion is I*x" = -kx, where x is the angular deflection in radians and I is the moment of inertia of the sphere. x" is the second derivative of x, ...
Sunday, January 9, 2011 at 4:29pm by drwls

AP Physics
After falling a distance h, Potential energy m g h is converted to kinetic energy of the rotating shell, the falling mass, and the pulley. Let V be the velcoity of the mass at time t. The angular velocity of the shell is ws= V/R and its moment of inertia is Is = (2/3)MR^2 The ...
Sunday, January 27, 2008 at 5:18pm by drwls

Physics
F*r = I * a Where F is the force on the merry-go-round, r is the radius, I is the moment of inertia of the merry-go-round, and a is the angular acceleration for a solid, horizontal disk, the moment of inertia is: 1/2*m*r^2 F*r = 1/2*m*r^2*a F = 1/2*m*r*a w = w0 + a*t where w ...
Thursday, November 1, 2012 at 1:29pm by Jennifer

moments of inertia
I determined the area moment of inertia and the product of inertia of the cross-section of a beam about the centroidal axes using equations. I am now asked to design an experiment to verify the results that I obtained through equations. Can someone please suggest an experiment...
Wednesday, April 7, 2010 at 9:55am by Claire

Physics Please help!
In each of the following cases, the mass is 7.99 kg and the radius is 7.50 cm. (a) What is the moment of inertia (kg/m2 ) of a solid cylinder rotating about an axis parallel to the symmetry axis but passing through the edge of the cylinder? (b) What is the moment of inertia (...
Saturday, March 17, 2012 at 11:20pm by john

Physics
Step One: Convert rpm to radians per second (12 rpm)(2pi rad/1rev)(1min/60s) = 1.26 rad/s = w Step Two: Determine the Angular Acceleration w = alpha t + w 1.26 rad/s = alpha (9.0 s) + 0 Alpha = 0.140 Step Three: Determine the moment of inertia of the disk and children Moment ...
Tuesday, April 19, 2011 at 4:32pm by Sara

Physics
Step One: Convert rpm to radians per second (12 rpm)(2pi rad/1rev)(1min/60s) = 1.26 rad/s = w Step Two: Determine the Angular Acceleration w = alpha t + w 1.26 rad/s = alpha (9.0 s) + 0 Alpha = 0.140 Step Three: Determine the moment of inertia of the disk and children Moment ...
Tuesday, April 19, 2011 at 4:32pm by Sara

Physics
Step One: Convert rpm to radians per second (12 rpm)(2pi rad/1rev)(1min/60s) = 1.26 rad/s = w Step Two: Determine the Angular Acceleration w = alpha t + w 1.26 rad/s = alpha (9.0 s) + 0 Alpha = 0.140 Step Three: Determine the moment of inertia of the disk and children Moment ...
Tuesday, April 19, 2011 at 4:32pm by Sara

Physics please check
A rotating door is made from four rectangular glass panes, as shown in the drawing. The mass of each pane is 88 kg. A person pushes on the outer edge of one pane with a force of F = 53 N that is directed perpendicular to the pane. Determine the magnitude of the door's angular ...
Monday, March 26, 2007 at 12:53am by Jim

Desperate need of Help for Physics.
Moment of inertia of a flywheel disk question: Do you think the calculated moment of inertia is larger or smaller than the "true" moment of inertial of the actual disk? question: calculate the percent difference between the static and the dynamic moment. I got .0195kgm^2 for ...
Wednesday, November 15, 2006 at 11:15am by Teesha

physics help!
A small 520-gram ball on the end of a thin, light rod is rotated in a horizontal circle of radius 1.5 m. Calculate the moment of inertia of the ball about the center of the circle. Then calculate the torque needed to keep the ball rotating at constant angular velocity if air ...
Thursday, March 25, 2010 at 10:39am by Anonymous

Physics please check
A uniform solid disk with a mass of 32.3 kg and a radius of 0.414 m is free to rotate about a frictionless axle. Forces of 90.0 N and 125 N are applied to the disk. (a) What is the net torque produced by the two forces? (Assume counterclockwise is the positive direction.) (b) ...
Tuesday, April 24, 2007 at 8:24pm by Mary

physics
A spinning flywheel has rotational inertia I = 402.9 kgm2. Its angular velocity decreases from 20.3 rad/s to zero in 266.6 s due to friction. What is the frictional torque acting? Torque= MomentofInertia*angularacceleration. You are given the moment of inertia (you named it ...
Monday, October 23, 2006 at 7:06pm by Anonymous

college physics
Interestingly, there have been several studies using cadavers to determine the moment of inertia of human body parts by letting them swing as a pendulum about a joint. In one study, the center of gravity of a 5.0 kg lower leg was found to be 18 cm from the knee. When pivoted ...
Wednesday, April 14, 2010 at 9:34am by zidd

Physics
The moment of inertia of the platform with block will decrease as the block is pushed toward the center. This will cause the angular velocity of the platform to increase. When calculating the moment of inertia and angular velocity of block distance R, ignore the I of the ...
Wednesday, May 5, 2010 at 10:54pm by drwls

physics
Find moment of inertia of a disc?
Wednesday, October 10, 2012 at 12:41pm by Purnima

College Physics
College Physics- Inertia? Find the moment of inertia about each of the following axes for a rod that is 0.300 in diameter and 1.60 long, with a mass of 5.0010−2 . How do you find this ? I know how to find the perpendicular and end . but this? About an axis along the ...
Wednesday, October 10, 2012 at 11:39pm by Herosugar

physics
The moment of inertia of the empty merry-go-round, assuming it to be a uniform circular platform, is I = (1/2)MR^2 = 194.4 kg*m^2 Angular momentum is conserved when the child gets on, but the new moment of inertia becomes (with the boy's contribution added), I' = I + mR^2 = ...
Monday, January 16, 2012 at 10:28pm by drwls

physics
The rotational kinetic energy of a spinning sphere is given by K = (1/2)Iω² where K=kinetic energy due to rotation I=moment of inertia about the rotation axis ω = angular velocity The moment of inertia of a sphere spinning about an axis passing through its ...
Saturday, November 28, 2009 at 2:34pm by MathMate

Physics Please help!
In each of the following cases, the mass is 7.99 kg and the radius is 7.50 cm. (a) What is the moment of inertia (kg/m2 ) of a solid cylinder rotating about an axis parallel to the symmetry axis but passing through the edge of the cylinder? (b) What is the moment of inertia (...
Sunday, March 18, 2012 at 12:40am by john

physics
My immediate thought is what is the moment of inertia for the cylinder
Thursday, May 28, 2009 at 12:32pm by bobpursley

Physics
do i use I center = M L^2/ 12 for moment of inertia??
Thursday, June 25, 2009 at 8:56pm by Sarah

physics
Moment of inertia M(i) = 2WR^2/5 about any axis.
Tuesday, April 17, 2012 at 4:18pm by tchrwill

Physics :)
Angular acceleration= torque/moment of inertia
Saturday, April 13, 2013 at 3:39pm by Elena

Physics
Angular momentum is conserved. That means, in this case, I1*w1 = I2*w2 where w is the angular velocity and i is the moment of inertia. The moment of inertia of a solid sphere of uniform density with mass M and radius R1 is I1 = (2/5)M*R1^2 The moment of inertia of a thin ...
Tuesday, January 29, 2013 at 8:33pm by drwls

Physics: Moment of Inertia
A yo-yo has a rotational inertia of 760 gcm2 and a mass of 200 g. Its axle radius is 4.0 mm, and its string is 100 cm long. The yo-yo rolls from rest down to the end of the string. (a) What is the magnitude of its linear acceleration?
Wednesday, October 27, 2010 at 12:22am by Xavier Hernandez

physics
an ice skater spins about a vertical axis at an angular speed of 15 rad/s when her arms are outstreched . she then quickly pulls her arms into her sides in a very small time interval so that the frictional force due to ice are negligible.her initial moment of inertia about the...
Saturday, February 11, 2012 at 10:19am by ashely

physics
(1/2) I w^2 = 1822.5 J w = 110 rad/s Solve for I, the moment of inertia
Friday, October 21, 2011 at 7:46pm by drwls

physics
moment inertia= sume of momentus= 1/2 3*.3^2+1/2*.1*.7^2 KE= 1/2 I w^2 solve for W
Sunday, June 24, 2012 at 7:09pm by bobpursley

physics
moment of inertia of a ring perpendicular to tangent and its plane
Thursday, November 1, 2012 at 12:15pm by sara

physics
The total moment of inertia with arms outstretched is: I1 = Ibody + Iarms = 0.450 + (1/12) m L^2 = 0.450 + (1/12)*8.5*(1.8)^2 = 2.75 kg m^2 The total moment of inertia with arms rapped aound the body is: I2 = Ibody + Iarms = 0.450 + m R^2 = 0.45 + 0.53 = 0.98 kg m^2 Use the ...
Saturday, April 12, 2008 at 4:52pm by drwls

Physics
Torque = (moment of inertia) x (angular acceleration) = 50 N*m The moment of inertia is I = (1/2) M*R^2 = 281.25 kg*m^2 The maximum angular velocity you want to achieve is w = 1200 rev/min * (2 pi/60) = 125.66 rad/s The angular acceleration rate is alpha = 125.66 rad/s / t ...
Saturday, July 23, 2011 at 5:45pm by drwls

Physics
She has increased her moment of inertia. Angular momentum is conserved; angular momentum = inertia*angular velocity if inertia is increased, angular velocity....
Thursday, October 7, 2010 at 3:48pm by bobpursley

Applied Machanics (Physics)
I thought the moment of inertia would be 1/12 ml^2
Sunday, May 3, 2009 at 7:20pm by bobpursley

Physics
The moment of inertia of a solid cylinder or disc is (1/2) M R^2, and does not depend upon the thickness.
Thursday, October 13, 2011 at 12:30am by drwls

physics
a. Look this up, flat disk, moment of inertia table. b. KE= 1/2 I w^2
Thursday, March 22, 2012 at 3:26pm by bobpursley

physics
PERIOD OF THE LEG The period of the leg can be approximated by treating the leg as a physical pendulum, with a period of 2pi*sqrt(I/mgh), where I is the moment of inertia, m is the mass, and h is the distance from the pivot point to the center of mass. The leg can be ...
Friday, February 26, 2010 at 9:33pm by Jennifer

Physics Classical Mechanics
remember that the sum of the torques is equal to I*alpha so sigma(t) = r1xF1 + r2xF2 +... +rnxFn = I*alpha where I is the moment of inertia through the axis of rotation. look for I in a table, easily found on google. notice the similarity to the application of Newtons second ...
Friday, December 6, 2013 at 5:54pm by Batman

Physics
A solid circular disk has a mass of 1.67 kg and a radius of 0.144 m. Each of three identical thin rods has a mass of 0.351 kg. The rods are attached perpendicularly to the plane of the disk at its outer edge to form a three-legged stool (see the figure). Find the moment of ...
Saturday, November 3, 2012 at 9:44pm by StressedStudent

Physics
I need help with this problem. A ceiling fan is turned on and a net torque of 2.0 Nm is applied to the blades. The blades have a total moment of inertia of 0.24 kgm2. What is the angular acceleration of the blades in rad/s2? The formula is well known: Torque= momentof inertia...
Wednesday, March 21, 2007 at 7:06pm by Jim

physics
You are correct. moment of inertia is not in the picture, acceleration tangential is zero. Good point.
Thursday, October 30, 2008 at 6:30am by bobpursley

physics
Look up the moment of inertia for a hoop. torque=momeninertia)angular acceleration
Friday, November 25, 2011 at 10:55am by bobpursley

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