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April 18, 2014

Search: mathURGENT!!!!!!!

Number of results: 20

mathURGENT!!!!!!
3
Wednesday, March 20, 2013 at 4:44pm by Ms. Sue

mathURGENT!!!!!!
how did you get that ms sue?
Wednesday, March 20, 2013 at 4:44pm by don

mathURGENT!!!!
check for typos. I bet the original was supposed to be a right triangle.
Monday, October 22, 2012 at 5:27pm by Damon

mathURGENT!!!!!!!
Your question doesn't make any sense to me. The greatest number of candies it would be impossible to buy????
Saturday, January 26, 2013 at 9:12pm by Ms. Sue

mathURGENT!!!!!!!!!!
find all ordered pairs of positive integers (x,y) that satisfy the following equation: x^y=2^64. please answer and explain how you got it!!!!
Thursday, February 14, 2013 at 10:12pm by don

mathURGENT!!!!!!
the lines satisfying the equations x+2y=3 and 3y+ax=2 are perpendicular to each other. find the value of 'a'. please answer and explain how you got, please!!
Tuesday, February 5, 2013 at 7:42pm by don

mathURGENT!!!!!!
what is the greatest value of m such that 25!/5^m is an integer? hint: the exclamation point means "factorial". 3!=3*2*1=6 4!=4*3*2*1=24 etc. please answer and explain how you got it!!!!please???
Friday, March 8, 2013 at 3:47pm by don

mathURGENT!!!!!!!
let u = 4^x then u - u/4 = 24 3u = 96 u = 32 so, 4^x = 2^5 but 4^x = 2^(2x), so 2x = 5 x = 5/2 (2x)^x = 5^(5/2) = 25√5
Saturday, April 20, 2013 at 12:21am by Steve

mathURGENT!!!!!!
determine the smallest prime number that divides the following sum: 3^12+5^13+7^14+11^15? please answer and explain step by step how u got it!!!!
Monday, February 4, 2013 at 8:25pm by don

mathURGENT!!!!
the midpoints of the sides of a triangle are (1,1),(4,3),and (3,5). find the area of the triangle. what is the answer and can u explain how u got it step by step? please...
Monday, October 22, 2012 at 5:27pm by dan

mathURGENT!!!!!!
slope of first line = -1/2 slope of 2nd line = -a/3 to be perpendicular, they must be negative reciprocals of each other, or, when multiplied we should get -1 (-1/2)(-a/3) = -1 a/6 = -1 a = -6
Tuesday, February 5, 2013 at 7:42pm by Reiny

mathURGENT!!!!!!!
if (4^x)-(4^x-1)=24 what is the value of (2x)^x? please answer and explain step by step how u got it... PLEASE?????
Saturday, April 20, 2013 at 12:21am by don

mathURGENT!!!!!!!!!!
if 4^(x)-4^(x-1)=24 what is the value of (2x)^x? please answer and explain step by step how u got it... PLEASE?????
Saturday, April 20, 2013 at 9:48pm by don

mathURGENT!!!!!!
Trial and error -- but it didn't take long. 2^2 = 4 4 - 4 = 0 >> Nope. It's not 2. 3^2 = 9 9 - 6 = 3 >> Yep! That works. Obviously 4 is not the answer either.
Wednesday, March 20, 2013 at 4:44pm by Ms. Sue

mathURGENT!!!!!!
for which integers will the square of the integer decreased by twice the integer produce a difference of less than 4? please answer and explain how you got the answer...please????!!
Wednesday, March 20, 2013 at 4:44pm by don

mathURGENT!!!!
The triangle formed by connecting the midpoints is similar to the original triangle but with all lengths half the original. Therefore the area of the triangle is four times the area of the little one inside (1/2) b h = 4 (1/2)(b/2)(h/2)
Monday, October 22, 2012 at 5:27pm by Damon

mathURGENT!!!!!!
25! 25...........1 The question is how many numbers between 25 and 1 are divisble by 5 25 = 5 times 5 20 = 5 times 4 15 = 5 times 3 10 = 5 times 2 5 = 5 times 1 5^6 so, I think m = 6 is the answer.
Friday, March 8, 2013 at 3:47pm by Dr. Jane

mathURGENT!!!!!!!!!!
4^(x)-4^(x-1)=24 4^(x-1) (4 - 1) = 24 4^(x-1) = 8 (2^2)^(x-1) = 2^3 2^(2x-2) = 2^3 then 2x-2 = 3 2x = 5 and x = 5/2 thus: (2x)^x = (5)^(5/2) = (√5)^5 = 25√5
Saturday, April 20, 2013 at 9:48pm by Reiny

mathURGENT!!!!!!!
a certain type of candy is sold in small boxes of 8 and large boxes of 15. notice it would be impossible to buy exactly 12 candies without breaking up a box. it would also be impossible to buy 17 candies without breaking up a box. what is the greatest number of candies that it...
Saturday, January 26, 2013 at 9:12pm by don

mathURGENT!!!!!!!!!!
2^64 can be written as a power in the following ways 2^64 , 4^32 , 16^16, 256^8 , 65536^4, 4294967296^2 and (4294967296^2 )^1 2^64 = 2x2x2x2...x2x2 --- 64 of them (2x2)x(2x2)x2...x2)x(2x2) --- 32 pairs of 2's = 4^32 (2x2x2x2)x(2x2...x2x(2x2x2x2) --- 16 groups of 4 2's = 16^16 ...
Thursday, February 14, 2013 at 10:12pm by Reiny

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