Number of results: 192,720
Statistics
MathGuru, /**** statistic. Otherwise, check a z-table for a one-tailed test at .05 level of significance. Compare to your test statistic. If the test statistic exceeds the value from the table, reject the null and conclude p < .90. If the test statistic does not exceed ...
Friday, April 20, 2012 at 7:20pm by Srinivas
statistics
Try a one-sample t-test to determine your test statistic. Once you have the test statistic, compare the test value to the critical value from a t-table using degrees of freedom along with the significance level. If the test statistic exceeds the critical value from the table, ...
Tuesday, August 2, 2011 at 1:01pm by MathGuru
statistic
You can probably use a one-sample proportional test for your data. (Test sample proportion = 20/55 or .36) Find the appropriate table for your critical value at .10 level of significance for a one-tailed test. Compare the test statistic you calculate to the critical value from...
Tuesday, August 2, 2011 at 12:40am by MathGuru
statistics
Here are a few hints: 1. Try an independent groups t-test to calculate the t-test statistic. 2. Degrees of freedom for an independent groups t-test is this: n1 + n2 - 2 3. Compare your test statistic to the critical values listed. If the test statistic exceeds the critical ...
Thursday, January 17, 2013 at 7:03pm by MathGuru
Statistic
You can use a one-sample proportional z-test for your data. (Test sample proportion = 39/90 and sample size = 90) Convert fractions to decimals to use in the z-test. Find the critical value in the appropriate table at .05 level of significance for a two-tailed test. Compare ...
Monday, July 9, 2012 at 10:41pm by MathGuru
statistics
Use the appropriate statistical formula for this type of 2-sample test. Calculate the test statistic using the information in the problem. Find your critical value using the appropriate table at .05 level of significance for a one-tailed test. Compare your test statistic to ...
Thursday, February 16, 2012 at 8:18pm by MathGuru
Statistics
Use the z-test formula to find the test statistic: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) Plug the values given into the formula to calculate your z-test statistic. Since the H1 shows a specific direction, this ...
Saturday, March 13, 2010 at 8:59pm by MathGuru
statistic
how a t Test for a dependent variable can be of great value in applying a new approach to the treatment of aggressive behavior to a small group of students. Why would this t Test be preferred to using another test statistic?
Wednesday, December 15, 2010 at 12:42am by smith
Statistics
You can use a one-sample proportional z-test for your data. (Test sample proportion = .58 and sample size = 150) Find the critical value in the appropriate table at .01 level of significance for a two-tailed test. Compare the test statistic you calculate to the critical value ...
Friday, May 11, 2012 at 3:28pm by MathGuru
statistics
You can use a one-sample proportional z-test for your data. (Test sample proportion = 76/120 or .63) Find the critical value in the appropriate table at .05 level of significance for a one-tailed test. Compare the test statistic you calculate to the critical value from the ...
Tuesday, August 2, 2011 at 12:32am by MathGuru
statistics
You can probably use a one-sample proportional test for your data. (Test sample proportion = 65/80 or .8125) Find the appropriate table for your critical value at .10 level of significance for a one-tailed test. Compare the test statistic you calculate to the critical value ...
Friday, February 17, 2012 at 12:47am by MathGuru
Statistics
You can use a one-sample proportional z-test for your data. (Test sample proportion = 24/200 and sample size = 200) Convert all fractions to decimals. Find the critical value in the appropriate table at .01 level of significance for a two-tailed test. Compare the test ...
Thursday, July 19, 2012 at 10:57am by MathGuru
Math-Statistics
Suppose you want to test the claim that mean is not equal 3.5. Given a sample size of n = 45 and a level of significance of a = 0.10, when should you reject H0 ? A) Reject H0 if the standardized test statistic is greater than 1.96 or less than -1.96 B) Reject H0 if the ...
Saturday, December 12, 2009 at 2:43pm by Jenny
Statistics
A few hints to get you started: 1. If H1 shows a specific direction, the test is one-tailed. If H1 does not show a specific direction (could be in either tail of the distribution curve), the test is two-tailed. 2. Use a one-sample z-test formula to determine the test statistic...
Friday, October 3, 2008 at 3:08pm by MathGuru
Psychological Statistics
Null: Ho: µ = 75 Alternate: Ha: µ ≠ 75 Test would be two-tailed because the alternate hypothesis does not show a specific direction (results could be in either tail of the distribution curve). Do a z-test using the data listed in the problem. Check a z-...
Monday, February 20, 2012 at 6:46pm by MathGuru
Stats
2 samples were collected to determine whether there was a difference between two weight loss methods targeting men. The average weight loss method is provided for the 2 samples along with the respective standard deviations. Is the second method - with an average weight loss of...
Friday, February 23, 2007 at 4:33pm by Jason L
statistics
Null hypothesis: p = .40 Alternate hypothesis: p does not equal .40 You can use a one-sample proportional z-test for your data. (Test sample proportion = .37 and sample size = 100) Find the critical value in the appropriate table at .01 level of significance for a two-tailed ...
Thursday, July 19, 2012 at 9:31pm by MathGuru
Statistics
Use a one-sample z-test. z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: z = (522.3 - 530)/(29/√85) = ? Finish the calculation. Check a z-table at .01 level of significance for a two-tailed test (...
Friday, March 8, 2013 at 9:35pm by MathGuru
Statistics
Try a t-test since your sample size is rather small. Formula: t = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) sample mean = 8.2 population mean = 7.3 standard deviation = 1.4 sample size = 20 Plug in the values and ...
Sunday, March 10, 2013 at 1:30pm by MathGuru
statistics
This looks like an independent groups t-test. Here are a few hints: 1. d.f. for an independent groups t-test is this: n1 + n2 - 2 2. Use the denominator of the appropriate t-test as the standard error of the difference between the two means. 3. Use the appropriate t-test to ...
Thursday, April 29, 2010 at 3:35pm by MathGuru
statistics
Try a t-test since your sample size is rather small. Formula: t = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) sample mean = 12 population mean = 10 standard deviation = 3 sample size = 26 Plug in the values and calculate ...
Tuesday, May 3, 2011 at 11:11pm by MathGuru
Statistics
Try a one-sample z-test for your problem. Using the z-test formula to find the test statistic: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) z = (3.69 - 3.65)/(.24/√45) Finish the calculation. Use a z-table to ...
Thursday, September 11, 2008 at 1:29am by MathGuru
stats
1. FOR A ONE-TAILED TEST with alpha .01 = 2.33 (round accordingly) 2. Use a z-test to determine your test statistic. z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) Your data: sample mean = 55 population mean = 35 standard...
Tuesday, October 23, 2012 at 4:46pm by MathGuru
statistics
Suppose you want to test the claim that mu is not equal to 3.5. Given a sample size of n = 31 and a level of significance of alpha = 0.10 when should you reject Ho? A) Reject Ho if the standardized test statistic is greater than 2.575 or less than -2.575. B) Reject Ho if the ...
Tuesday, June 21, 2011 at 9:05pm by Brittany
statistics
The p-value is the actual level of the test statistic. It represents the probability of getting a result as extreme as the test statistic itself. To determine this probability, use a z-table with the z-values given.
Monday, September 13, 2010 at 1:41pm by MathGuru
math-Statistics
Ho: µ ≤ 10 -->null hypothesis Ha: µ > 10 -->alternative hypothesis Using the z-test formula to find the test statistic: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) z = (14.44...
Sunday, June 8, 2008 at 7:33pm by MathGuru
college Math
Ho: µ = 40 --->meaning the population mean is equal to 40. H1: µ < 40 ---> meaning the population mean is less than 40. This will be a one-tailed test because the alternative hypothesis is showing a specific direction. Use a z-test. Find the ...
Monday, December 7, 2009 at 8:30pm by MathGuru
statistics
Try a binomial proportion 2-sample test using proportions. Hypotheses: Ho: p1 = p2 Ha: p1 does not equal p2 -->this is a two-tailed test (the alternate hypothesis does not show a specific direction). Remember you are using proportions; therefore, convert all fractions ...
Monday, April 16, 2012 at 7:41am by MathGuru
math - stats
It is believed that at least 60% of voters from a certain region in Canada favor the free trade agreement (FTA). A recent poll indicated that out of 400 randomly selected individuals, 250 favored the FTA. If we wished to perform a test to determine whether the proportion of ...
Wednesday, December 19, 2012 at 12:05am by barbra
statistics
Try a two-sample test. Hypothesis: Ho: µ1 = µ2 Ha: µ1 does not equal µ2 This is a two-tailed test because the problem is just asking if there is a difference (no specific direction in the alternate hypothesis). Find the critical or cutoff value using ...
Monday, April 16, 2012 at 7:33am by MathGuru
Statistics
Try a two-sample z-test. Hypotheses: Ho: µ1 = µ2 Ha: µ1 > µ2 Use a z-table to determine the critical or cutoff value to reject or fail to reject the null hypothesis at .01 level of significance. This will be a one-tailed test because the ...
Wednesday, November 7, 2012 at 3:20am by MathGuru
statistical psychology
You might try a one-way ANOVA on this data. Use the appropriate table to compare your test statistic to the critical value from the table at .05 level of significance. If the test statistic exceeds the critical value from the table, reject the null and conclude a difference. ...
Tuesday, August 17, 2010 at 12:46pm by MathGuru
Statistics
Your calculations look correct, as well as your conclusion. Part a) might be looking for the p-value, which is the actual level of the test statistic (z = -0.5873). If that is the case, then you can look up the p-value using the test statistic and a z-table. Good job!
Tuesday, March 31, 2009 at 11:34pm by MathGuru
statistics
Try a two-sample independent groups t-test since your sample sizes are small. Hypothesis: Ho: µ1 = µ2 Ha: µ1 does not equal µ2 This is a two-tailed test because the problem is just asking if there is a difference (no specific direction in the alternate ...
Friday, February 26, 2010 at 6:39pm by MathGuru
Statistics
In a study that was highly published doctors discovered that aspirin helps prevent heart attacks. The research project which was scheduled to last 5 years employed 22,000 american physicians (all male). Half took an aspirin tablet 3 times a week while the other half took a ...
Friday, February 23, 2007 at 4:24pm by Jason L
statistics
Try a t-test since your sample size is rather small. Ho: µ = 60 -->null hypothesis Ha: µ > 60 -->alternative hypothesis Formula: t = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) sample mean...
Thursday, May 10, 2012 at 3:18pm by MathGuru
Statistics
Try a proportional one-sample z-test for this one since this problem is using proportions. Here's a few hints to get you started: Null hypothesis: Ho: p ≥ .90 -->meaning: population proportion is greater than or equal to .90 Alternate hypothesis: Ha: p &...
Friday, April 20, 2012 at 7:20pm by MathGuru
Statistics
If you are asked to do a t-test on this data, see the following: t = 5.15/(11.45/√322) You can probably get away with doing a z-test for this problem because the sample size is so large. However, the formulas are the same for a t or z test. If you use a z-table for a...
Thursday, March 18, 2010 at 9:27pm by MathGuru
stats
I'll give a few hints and let you take it from there. Hypotheses: Ho: µ ≥ 26 Ha: µ < 26 Try a z-test to determine the test statistic. Formula: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size...
Wednesday, July 13, 2011 at 10:11am by MathGuru
statistics
You can use a one-sample z-test on this data. Null hypothesis: Ho: µ = 3 -->meaning: population mean is equal to 3 minutes Alternate hypothesis: Ha: µ < 3 -->meaning: population mean is less than 3 minutes Using the z-test formula to find the ...
Monday, June 23, 2008 at 1:09pm by MathGuru
URGENT Statistics
In performing two-tailed hypothesis test with v=20, you obtain a t-statistic of 2.41. The p-value is: Between 2% and 5%. I need help understanding how this range was gotten. I know that the t-statistic is between t.025 and t.01 and since this is a 2-tailed test these t-values ...
Friday, December 10, 2010 at 1:19pm by Rhea
statistics
There are t-tables that show values for one-tailed and two-tailed tests. Since the test is right-tailed, this is a one-tailed test. If n = 21, degrees of freedom would be n - 1, which is 20. (I'm assuming this was a one-sample t-test. If not, the degrees of freedom would ...
Friday, May 21, 2010 at 6:26pm by MathGuru
Statistics
This appears to be a hypothesis test involving inferences concerning two variances (standard deviation is the square root of the variance). Sample 1: n = 25; variance = sd^2; df = n - 1 = 24 Sample 2: n = 25; variance = sd^2; df = n - 1 = 24 Note: sd = standard deviation. Test...
Thursday, June 19, 2008 at 5:22am by MathGuru
statistics
Try a two-sample test. Hypothesis: Ho: µ1 = µ2 Ha: µ1 does not equal µ2 This is a two-tailed test because the problem is just asking if there is a difference (no specific direction in the alternate hypothesis). P-value is the actual level of the test ...
Thursday, March 15, 2012 at 8:44pm by MathGuru
P Value Math Statistics
Find the P-value for the indicated hypothesis test with the given standardized test statistics, z. Decide whether to reject H0 for the given level of significance a. two-tailed test with test statistic z= -1.57 and a=0.04
Sunday, February 24, 2013 at 11:23pm by Katie
statistics
Yes, you are correct. This will be a one-tailed test (the alternate hypothesis shows a specific direction on a one-tailed test). Use a z-test. See your other post for an example on calculating the z-test statistic using a z-test. Your hypotheses for this problem: Ho: µ...
Thursday, April 19, 2012 at 4:44pm by MathGuru
statistics
Use a) for your hypotheses. You can try a proportional one-sample z-test since this problem is using proportions. Using a formula for a proportional one-sample z-test with your data included, we have: z = .16 - .15 -->test value (150/940) is .16) minus population value...
Monday, December 10, 2012 at 3:57pm by MathGuru
statistics please
H0: µ = 80 -->null hypothesis H1: µ < 80 -->alternative hypothesis Critical value for a one-tailed test (the alternative hypothesis shows a specific direction) can be found using a z-table at .05 level of significance. Calculate the test ...
Wednesday, December 12, 2012 at 6:59pm by MathGuru
statistics
Usually you use z-tests when sample sizes are large (n is greater than or equal to 30) whether or not you know the population standard deviation. If you do not know the population standard deviation and have a small sample (n < 30), then you can use t-tests. Therefore, ...
Monday, August 9, 2010 at 5:05pm by MathGuru
statistics
This level .05 determines where to reject the null (H0). If the test statistic for a hypothesis test is calculated and ends up exceeding the level .05, the null will be rejected in favor of the alternate hypothesis (H1). If the test statistic does not exceed the level .05, the...
Sunday, May 2, 2010 at 12:14pm by MathGuru
statistics
Use an independent groups t-test for your two samples. n1 + n2 - 2 degrees of freedom is used for this test. Use a t-table to determine your cutoff or critical value to reject the null (you should have a significance level set for the test). If your test statistic exceeds the ...
Saturday, November 6, 2010 at 10:40am by MathGuru
Statistic
A restaurant that bills its house account monthly is concerned that the average monthly bill exceeds $200 per account. A random sample of twelve accounts is selected, resulting in the sample mean of $220 and a sample standard deviation of $12. The researchers have determined ...
Monday, October 20, 2008 at 12:22am by Marilyn
statistics
Formula: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: z = (12 - 10)/(3/√36) Once you have the z-test statistic, check a z-table for a one-tailed test (H1 is showing a specific direction) at .02...
Thursday, July 21, 2011 at 10:44pm by MathGuru
statistics
5. A teacher wishes to compare two different groups of students with respect to their mean time to complete a standardized test. The time required is determined for each group. The data summary is given below. Test the claim at = 0.10, that there is no difference in variance. ...
Thursday, May 6, 2010 at 1:52pm by Ima
Statistics
This is a hypothesis test involving variances. Sample size for paper shredders = 7 Variance = ? (you will need to calculate the variance from the data given) degrees of freedom = 6 (df = n - 1) Sample size for calculators = 7 Variance = ? (you will need to calculate the ...
Wednesday, November 10, 2010 at 8:20pm by MathGuru
statistics
Use the z-test formula to find the test statistic since you know the population standard deviation: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With the data given in the problem: z = (190 - 200)/(50/√9) ...
Friday, March 19, 2010 at 7:15am by MathGuru
Statistics
If you use a one-sample z-test, here is the formula: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: z = (132.3 - 128)/(15/√50) = ? Finish the calculation. Check a z-table at 0.05 level of ...
Tuesday, April 16, 2013 at 6:18pm by MathGuru
statistics
Using a formula for a binomial proportion one-sample z-test with your data included, we have: z = .55 - .50 / √[(.50)(.50)/500] Finish the calculation. Use a z-table to find the critical or cutoff value at 0.05 for a one-tailed test. If the z-test statistic ...
Wednesday, May 12, 2010 at 9:15pm by MathGuru
Statistics
Use a one-sample z-test. z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: z = (43.5 - 40)/(8/√100) = ? Finish the calculation. Check a z-table at .05 level of significance for a one-tailed test. If...
Friday, April 27, 2012 at 7:55am by MathGuru
statistics
Use a one-sample z-test. z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: z = (38.7 - 40)/(12.5/√50) = ? Finish the calculation. Check a z-table at .05 level of significance for a one-tailed test. ...
Sunday, February 24, 2013 at 1:15pm by MathGuru
statistics
Use a one-sample z-test. z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: z = (38250 - 39000)/(1200/√18) = ? Finish the calculation. Check a z-table at .05 level of significance for a one-tailed ...
Tuesday, June 8, 2010 at 1:45pm by MathGuru
STATISTICS
Using a formula for a binomial proportion one-sample z-test with your data included, we have: z = .62 - .50 / √[(.50)(.50)/50] Finish the calculation. Use a z-table to find the critical or cutoff value at 0.01 for a one-tailed test. If the z-test statistic calculated...
Tuesday, April 16, 2013 at 6:54pm by MathGuru
INTRO TO STATISTICS HYPOTHESIS TESTING
I would consider this a one-tailed test (state Ha as µ > 49600). When using a "does not equal" with Ha, you are just looking for a difference and the test would be two-tailed (either direction). Your test statistic calculation looks correct. This test ...
Friday, March 19, 2010 at 11:01pm by MathGuru
statistics
A two-tailed test means that the results could be in either tail of the distribution curve. For example, if you are doing a two-tailed z-test at .05 level of significance, the critical or cutoff values to reject the null would be z = + or - 1.96. If the test statistic exceeds ...
Thursday, May 13, 2010 at 11:33am by MathGuru
Statistics
Use a one-sample z-test. z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: z = (5.25 - 4.75)/(1.15/√52) = ? Finish the calculation. Check a z-table at .01 level of significance for a one-tailed test...
Sunday, May 5, 2013 at 4:51pm by MathGuru
statistics
Try a one-sample t-test since the sample size is fairly small. This will be a one-tailed test (the alternate hypothesis will show a specific direction). Formula for a one-sample t-test is the following: z = (sample mean - population mean)/(standard deviation divided by the ...
Tuesday, March 5, 2013 at 9:47pm by MathGuru
Statistics
Try an independent groups t-test. Hypotheses: Ho: µ1 = µ2 -->null hypothesis Ha: µ1 < µ2 -->alternate hypothesis Use (n1 + n2 - 2) degrees of freedom for this test. Use a t-table to determine your cutoff or critical value to reject ...
Wednesday, April 4, 2012 at 4:50pm by MathGuru
Prob and Stat
Use a one-sample z-test. Formula: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With the data in your problem: z = (58000 - 60000)/(7000/√49) Finish the calculation. If the test statistic exceeds the critical ...
Tuesday, May 17, 2011 at 2:15pm by MathGuru
statistics
You can use a t-test for this problem since the sample size is small. Using your data in the formula: t = (18 - 20)/(5/√8) = ? Finish the calculation. Using a t-table at 0.05 level of significance for a two-tailed test (the test is two-tailed because the alternative ...
Wednesday, May 5, 2010 at 6:53pm by MathGuru
psychology
how a t Test for a dependent variable can be of great value in applying a new approach to the treatment of aggressive behavior to a small group of students. Why would this t Test be preferred to using another test statistic?
Wednesday, March 16, 2011 at 9:34pm by Anonymous
statistics
You can probably use a chi-square for this kind of problem. Hypotheses: Ho: There was equal distribution of viewers across the channels. Ha: There was unequal distribution of viewers across the channels. If there was equal distribution across the channels, you would expect 50 ...
Monday, August 9, 2010 at 7:49am by MathGuru
Statistics
You can probably use an independent groups t-test for this data. Ho: µ1 = µ2 H1: µ1 does not equal µ2 Group 1 (Women) mean = 538.82 standard deviation = 114.16 sample size = 18 Group 2 (Men) mean = 525.23 standard deviation = 97.23 sample size = 12 ...
Wednesday, February 1, 2012 at 5:30pm by MathGuru
statistics
a random sample of 80 college students was selected to participate in a experiment. the mean of the sample is 317 points, the standard deviation of 37 there are 310 students that didn't complete the experiment 1. compute the appropriate test statistic? 2. what is the ...
Wednesday, July 11, 2012 at 2:40pm by Anonymous
Stats.
If the test statistic exceeds the critical value from the chi-square table, then the null is rejected. Also, if the test statistic does not exceed the critical value from the table, then the null cannot be rejected. The above corrects the last few sentences. Sorry for any ...
Monday, March 28, 2011 at 11:43am by MathGuru
stats.& Prob
Null hypothesis: Ho: p = .50 -->meaning: population proportion is equal to .50 Alternative hypothesis: Ha: p does not equal .50 -->meaning: population proportion does not equal .50 Using a formula for a binomial proportion one-sample z-test with your data ...
Monday, August 15, 2011 at 1:52pm by MathGuru
statistics
Use Excel to find the p-value for each test statistic.a. Right-tailed test, t = +1.677, n = 13 b. Left-tailed test, t = −2.107, n = 5 c. Two-tailed test,t = −1.865, n = 34
Monday, September 13, 2010 at 1:58pm by kim
statistics/ Help!-thanks!
I would phrase the hypotheses this way: Ho: µ ≥ 1.73 Ha: µ < 1.73 This would be a one-tailed test since Ha is showing a specific direction (less than). Use a z-test: z = (sample mean - population mean)/(standard deviation divided by the square root...
Saturday, August 25, 2012 at 4:28pm by MathGuru
Statistics
Try an independent groups t-test. Hypotheses: Ho: µ1 = µ2 -->population means are equal Ha: µ1 does not equal µ2 -->population means are not equal Use (n1 + n2 - 2) degrees of freedom for this test. Use a t-table to determine your cutoff ...
Wednesday, April 4, 2012 at 5:07pm by MathGuru
biostatistic
Use a one-sample z-test. z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: z = (38 - 60)/(19/√50) = ? Finish the calculation. Check a z-table at .05 level of significance for a one-tailed test. If ...
Tuesday, November 20, 2012 at 1:37pm by MathGuru
statistics
Find the p-value for each test statistic. a. Right-tailed test, z=+1.34 b. Left-tailed test, z=−2.07 c. Two-tailed test, z=−1.69
Monday, September 13, 2010 at 1:41pm by kim
math
use technology to find the P-value for a two tailed test with n=28 and a test statistic t=2.032 P-value =???? Help please! i dont understand this
Sunday, May 8, 2011 at 10:58pm by jessica
statistics
Using a formula for a binomial proportion one-sample z-test with your data included, we have: z = .55 - .50 / √[(.50)(.50)/500] -->note: .55 is 275/500 in decimal form. Finish the calculation. Use a z-table to find the critical or cutoff value at 0.05 for a ...
Monday, May 10, 2010 at 12:56pm by MathGuru
statistic
a restaurant that bills its house account monthly is concerned that the average monthly bill exceeds $200 per account. A random sample of twelve account is selected, resulting in a sample mean of $220 and a standard deviation of $12. Use a= 0.05. what is the critical value for...
Tuesday, December 11, 2012 at 1:28am by HN
statistics
Since the sample size is small, you can use a t-test: t = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: t = (6.91 - 7.48)/(1.21/√24) Finish the calculation. Check a t-table using n - 1 for degrees ...
Tuesday, April 19, 2011 at 11:57pm by MathGuru
Statistics
It is believed that at least 60% of voters from a certain region in Canada favor the free trade agreement (FTA). A recent poll indicated that out of 400 randomly selected individuals, 250 favored the FTA. If we wished to perform a test to determine whether the proportion of ...
Thursday, January 24, 2013 at 11:13pm by Stanley
Statistics Question
For a test of Ho: p = 0.5, the z test statistic equals 1.52. Find the p-value for Ha: p > 0.5.
Thursday, March 22, 2012 at 9:37pm by M
Stastics
Use a one-sample z-test. z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) Note: Standard deviation is the square root of the variance. Check a z-table at .05 level of significance for a one-tailed test. If the z-test ...
Wednesday, April 3, 2013 at 1:40pm by MathGuru
statistics
You may want to check this with a statistics text, but here is one way you might approach this problem. This looks like a hypothesis test involving two variances (standard deviation is the square root of the variance). The null hypothesis would be the ratio of the two ...
Monday, August 18, 2008 at 11:40am by MathGuru
math-test statistic
If we have a sample of 12 drawn from a normal population, then we would use as our test statistic A) z0 with 11 degrees of freedom B) t0 with 12 degrees of freedom C) z0 with 12 degrees of freedom D) t0 with 11 degrees of freedom
Saturday, December 5, 2009 at 8:35pm by jason
stats
Here are a few steps to get you started: Null hypothesis: Ho: p = .20 -->meaning: population proportion is equal to .20 Alternative hypothesis: Ha: p > .20 -->meaning: population proportion is greater than .20 Using a formula for a binomial proportion one-...
Wednesday, May 11, 2011 at 2:18am by MathGuru
math Statistics
I'll give you a few hints. The null hypothesis ALWAYS uses an equals sign. It could be greater than or equal to or less than or equal to or just equals some value. An alternate hypothesis can be greater than, less than, or does not equal some value. If no direction is ...
Sunday, February 19, 2012 at 12:56pm by MathGuru
Business Statistics
1- When the necessary conditions are met, a two-tail test is being conducted to test the difference between two population proportions. The two sample proportions are p1= 0.25 and p2 = 0.20 , and the standard error of the sampling distribution of p1 − p2 is 0.04. The...
Tuesday, August 11, 2009 at 12:13pm by Lesliam
Statistics
Try an independent groups t-test. This will be a two-tailed test because the problem is asking if there is a difference, which could be in either direction. Hypotheses: Ho: µ1 = µ2 (1 = females; 2 = males) Ha: µ1 ≠ µ2 Compare the test ...
Wednesday, November 7, 2012 at 3:23am by MathGuru
business statistics
Using the z-test formula to find the test statistic: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) z = (230.8 - 220)/(17/√12) Finish the calculation. Since this sample is from a normally distributed population...
Wednesday, July 29, 2009 at 4:47pm by MathGuru
Stats
Try a one-sample z-test or t-test, depending on the size of your sample. Check the appropriate table at 0.01 level of significance for a two-tailed test. Once you calculate the test statistic, compare to the critical or cutoff value(s) from the table to reject or fail to ...
Monday, May 20, 2013 at 12:34pm by MathGuru
Statistics
Here are a few hints: 1. Use a one-sample z-test for both A and B, which is: z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) 2. Find the critical or cutoff value to reject the null using a z-table for .05 level of ...
Monday, November 15, 2010 at 5:34pm by MathGuru
Statistics
Use a one-sample z-test. Hypotheses: Ho: µ = 124 -->null hypothesis Ha: µ > 124 -->alternate hypothesis z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size) With your data: z = (125.50 - 124)/(2...
Thursday, April 19, 2012 at 5:13pm by MathGuru
business statistics
1. Use an ANOVA table to determine your table value using 0.05 level of significance. If the test statistic exceeds the critical value from the table, you reject the null. If the test statistic does not exceed the critical value from the table, you do not reject the null. 2. ...
Tuesday, August 11, 2009 at 12:14pm by MathGuru
Statistics
You can use a one-sample t-test since this sample size is fairly small. Calculating: t = (275.66 - 250)/(78.11/√25) = ? I'll let you finish the calculation. Use a t-table at .05 level of significance for a one-tailed test (the alternate hypothesis will show a ...
Sunday, June 6, 2010 at 3:37pm by MathGuru
STATS
Determine the p–value associated with the values of the standardized test statistic z = 1.05 for one-tail test. (1) 0.3531 (2) 0.1469 (3) 0.8531 (4) 0.0146 (5) 0.2938
Wednesday, March 31, 2010 at 1:30pm by SAM
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