Wednesday

April 16, 2014

April 16, 2014

Number of results: 214,135

**Math**

Logs are stacked up in apile as shown in the figure. The top row has 15 logs and the bottom row has 21 logs. How many logs are in the stack? a1= 1+14=15 an= 7+14=21 s1=(n/2)(a1+an) (n/2)(15+21) = 18 How do I figure out the n?
*Tuesday, May 4, 2010 at 4:37pm by Abbey(Please help)*

**math - natural logs**

Find the EXACT solution to e^(1-x) = 4^x You must use logs, not just a calculator.
*Monday, October 31, 2011 at 10:10pm by BJ*

**Math**

you will have to use logs 4( 7^(x-2) ) = 8 divide both sides by 4 7^(x-2) = 2 take logs of both sides log (7^(x-2) ) = log 2 by rules of logs (x-2)(log 7) = log 2 x-2 = log 2/log 7 x = 2 + log2/log7 = appr 2.3562
*Thursday, January 23, 2014 at 10:06am by Reiny*

**Math**

Well I know that a product law of logs is log(a) + log(b) = log(ab) and the quotient law of logs is log(a)-log(b)=log(a/b) But how do I change those laws, or relate it to prove the law of exponents. I know what the law of exponents are, but I just need help proving it IN ...
*Saturday, May 23, 2009 at 5:07pm by Jus*

**math logs**

solve 3^(2x+1) = 9^(2x-1) using base 3 logs
*Saturday, November 12, 2011 at 9:03pm by Sejul*

**Nautical/Maths**

By the way, in the old days like when I went sailboat racing, we had to use logs of trig functions to do these products by adding and subtracting logs because we did not have calculators. This was a total mess and resulted in complicated things like using half the angles so ...
*Friday, January 4, 2008 at 3:49am by Damon*

**Precalculus**

.5=e^(-20t) I am assuming this involves logs but we did't really learn logs. Anyone care to walk me thru with a calculator. Have the Ti-83
*Thursday, March 13, 2008 at 7:08pm by Trevor*

**precalculus**

start by collecting logs: log5 (x+3) + log5(x-1) = 1 now recall that sum of logs is log of product log5 [(x+3)(x-1)] = 1 raise 5 to the power of both sides: (x+3)(x-1) = 5 x^2 + 2x - 3 = 5 x^2 + 2x - 8 = 0 (x+4)(x-2) = 0 x = 2 or -4 Since logs of negative numbers do not exist...
*Monday, January 9, 2012 at 11:07am by Steve*

**another pre cal (logs)**

according to your basic laws of logs your expression is log3 ((3x-6)(x^2 - 4)/81)
*Monday, March 31, 2008 at 1:14am by Reiny*

**math**

the base doesn't really matter. All logs follow the same rules. (a) log(x^2-9) - 9log(x) but your parentheses are not balanced, so that's a guess. Could also be 3(log(x^2-9) - 3log(x)) (b) log(5) + 4log(a) Now, it helps to know that we're using logs base a, since then we have ...
*Monday, April 8, 2013 at 12:25am by Steve*

**chem**

"Yule logs are simulated wood logs make of compressed paper that burn with a red and green flame.How would you produce a similar yule log?"
*Wednesday, July 9, 2008 at 1:11am by jennifer*

**Pre Cal (logs)**

I need help with these logs 1: Log underscore4 16X 2: 2 Ln ( X(sqr. root)e 3:5^[2logUnderscore5(3x)] 4:log underscore2 ^[1280-logunderscore2 5) I don't understand how to do them thanks
*Sunday, March 30, 2008 at 11:25pm by Deb*

**Math**

You will have to know the basic rules of logs log(A/B) = logA - logB comes into play here log6 7 - log6 x = 4 log6 (7/x) = 4 by definition of logs 6^4 = 7/x 1296 = 7/x x = 7/1296
*Sunday, December 6, 2009 at 11:11am by Reiny*

**math**

Mr Logan can saw 8 logs in 3 hours. How many logs can Mr Logan saw in one hour?
*Wednesday, August 15, 2012 at 1:15pm by Andrea*

**maths**

5^(logx) + x^(log5) = 50 Note that log(5^logx)) = logx * log5 log(x^log5)) = log5 * logx So, the two are equal. That means 2*5^logx = 50 5^logx = 25 = 5^2 logx = 2 x = b^2 where logs are base b. So, if natural logs, x = e^2 if common logs, x = 10^2 = 100 check (common logs): 5...
*Wednesday, March 19, 2014 at 3:21pm by Steve*

**Maths (Logs)**

1.Write the following equation without logs log y = mx+ c This would be y = 10^(mx+c) right? 2. Explain why this fits the exponential model (in other words, it can be written in the form y = a x b^x where a and b are real numbers).
*Monday, April 7, 2008 at 10:23pm by BP*

**misplaced modifier**

Were you hunting behind a pile of logs? -- or Was the fire extinguisher behind a pile of logs? We can't tell from this sentence.
*Saturday, September 24, 2011 at 4:32pm by Ms. Sue*

**math**

Take logs of both sides. I'll use logs to base 10, but it doesn't matter what base is used as long as it is consistent. log 14 = n log 1.4 n = log 14/log 1.4 = 1.14613/.14613 = 7.843
*Tuesday, February 26, 2008 at 2:01am by drwls*

**Math**

n/2(26) = 18 26n = 36 n = 36/26 something very wrong with your equation, since n has to a whole number where does the 18 come from? you seem to be using the formula S(n) = n/2(first + last) so 18 would be the sum of the logs ???? that makes no sense, since the bottom row alone...
*Tuesday, May 4, 2010 at 4:37pm by Reiny*

**math logs**

3^(2x+1) = 3^2(2x-1) easy way 2x+1 = 4x-2 2z=3 x= 3/2 using logs base 3 2x+1 = (2x-1)log3(9) 2x+1 = (2x-1)log3(3^2) 2x+1 = (2x-1)(2) log3(3) 2x+1 = 2(2x-1) same as above
*Saturday, November 12, 2011 at 9:03pm by Damon*

**math**

Hmmm... it may require some knowledge of how some functions work. Take 1/x. You can plug any value into x and it will be defined unless x is 0. You cannot divide something by 0. 0 no matter how many times will not be equal to 1. Another common one is sqrt(x). It's no longer a ...
*Wednesday, April 2, 2008 at 8:19pm by Anonymous*

**math**

what's ln vs lg? Assuming all logs are the same, and taking powers of e, e^(ln 4x) = e^(ln3 * ln5) (e^ln3)^(ln5) 4x = 3^(ln5) x = 1/4 * 3^(ln5) = 1.46 If the logs are different bases, then adjust the powers accordingly
*Saturday, July 6, 2013 at 11:59pm by Steve*

**Alegbra (logs)**

if logs are the same, the arguments are the same, so x-16 = 9x x = -2 But, log(x) is not defined for x<0, regardless of the base if you mean the entire exponents is 1+ln(7), then e^(1+ln(7)) = e^1 * e^ln(7) = 7e by definition, e^ln(n) = n
*Monday, April 22, 2013 at 3:39pm by Steve*

**precalculus**

for the first you don't even need logs 3^(x^3)=9^x 3^(x^3)=(3^2)^x 3^(x^3) = 3^(2x) so x^3 = 2x x^3 - 2x = 0 x(x^2 - 2) = 0 x = 0 or x = ±√2 for second, take logs of both sides log(2^x) = log 10 xlog2 = 1 x = 1/log2 for the last 4^x = 2^x 2^(2x) = 2^x 2x = x x = 0
*Monday, December 1, 2008 at 3:50pm by Reiny*

**Logarithums?**

I don't see why you have to convert it; they are indeed the same thing. I want to draw a graph for this, but I can't :-) In general, you can use the rule that ln(1/x) = -ln(x), so you can simply declare that and be done. I'll try to show an equivalence so it might make a bit ...
*Sunday, September 20, 2009 at 4:59am by jim*

**physics**

The fraction (1/6) that remains after 70 years satisfies the relation: 1/6 = 2^(-t/T), where T is the half life and t = 70 years. Take logs of both sides to solve for T. I'll use logs to base e but it doesn't matter -1.7918 = -70/T ln 2 = -48.52/T T = 27.1 years
*Wednesday, May 21, 2008 at 5:51am by drwls*

**Logs-Algebra**

How do you graph the following logs? f(x)=log5 (x-2) f(x)=log5 x-2 f(x)= log5 x f(x)=log5 (x+2)
*Tuesday, October 23, 2007 at 11:11pm by Jayme*

**College Algebra**

The purpose of logs is that when multiplying, logs add. Thence the slide rule, and a mydrid of mechanical computing devices. The other use, is that many natural processes in nature are logarithimic in nature (population growth, interest, radioactiveity, in fact, anything whose...
*Thursday, October 21, 2010 at 10:54am by bobpursley*

**Quantative Method**

Generate your Unit transportation costs (in excel) 1. Ship construction logs from 8 provinces in Canada to 50 states in the U.S. Minimize total shipping cost. 2. Set up the demand in each state of the U.S. 3. Set up availability of logs in the 8 provinces of Canada
*Friday, June 14, 2013 at 10:36pm by Anita*

**more pre cal logs**

sorry I am so lost I missed the class that talked about logs since my sister was in the hospital giving birth to a still born baby.... now I am all lost... Expand the log Ln 3sqrootx^2y/x+3 (the 3 is part of the sqroot not infront like the 3rd power) I hope that makes since
*Monday, March 31, 2008 at 1:52am by Deb*

**Math+Growth/Decay**

By the way, at the vertical asymptote where x = -1/3, the value for y gets infinitely negative as you get closer and closer to that line (since the values in the parenthesis are getting smaller and smaller as you approach the minimum value for x, -1/3). Remember that it's ...
*Wednesday, March 11, 2009 at 9:57pm by Toothpicks*

**Math: Calculus**

changing the base of a log: Alg II http://www.sosmath.com/algebra/logs/log4/log43/log43.html
*Monday, October 17, 2011 at 7:37pm by bobpursley*

**Math - logs**

yep
*Saturday, January 24, 2009 at 5:49pm by Damon*

**Math-LOGS**

duplicate
*Monday, December 21, 2009 at 4:32pm by Anonymous*

**Math (logs)**

correct.
*Sunday, December 8, 2013 at 8:40pm by Steve*

**math**

solve with logs 3^(1-2x)=4^(x)
*Monday, November 24, 2008 at 8:38pm by kayla*

**Alg 2 (HS)**

take logs of both sides (x+2) log 4 = log 160 x+2 = log160/log4 x = log160/log4 - 2 that is also log4160 - 2 but most calculators don't do logs to various bases, but do have log
*Saturday, September 22, 2012 at 1:15am by Steve*

**math**

how do i solve these logs? log1/2 (3x+1)^1/3= -2 3^(x^3)= 9^x
*Thursday, January 8, 2009 at 6:15pm by kayla*

**Math**

hint - take logs
*Monday, November 29, 2010 at 8:36am by Dr Russ*

**math**

take the log base 5 of each side x-1=log5 9=log10 9 /( log10 5) http://www.sosmath.com/algebra/logs/log4/log43/log43.html
*Sunday, October 5, 2008 at 5:12pm by bobpursley*

**more pre cal logs**

In your text or in your notes you should find 3 main rules for logs. 1. log(AB) = logA + logB 2. log (A/B) = logA - logB 3. log (A^n) = nlogA use them in this question. You did not use brackets to establish the correct order of operations here, so I will let you finish it. You...
*Monday, March 31, 2008 at 1:52am by Reiny*

**CALC**

Now on this one I am not sure what you mean. log base 2 (x) or log (2x) I will assume base 2 then log x + log (4-x) = 0 where logs are base 2 adding logs is multiplying log (x(4-x)) = 0 x(4-x) = 2^0 which is one 4x - x^2 = 1 x^2 -4x +1 = 0 solve for x
*Wednesday, July 22, 2009 at 4:59pm by Damon*

**college algebra**

log(a^b) = b log(a) log(ab) = log(a) + log(b) since 1/b = b^-1, log(a/b) = log(a) - log(b) since √a = a^(1/2), log √a = 1/2 log a log x^4y^7/4 = 4logx + 7logy - log4 so you should be able to do the other if these problems involve logs base 4, that doesn't matter. ...
*Wednesday, April 17, 2013 at 4:36pm by Steve*

**math**

Do you need to solve for t? Hint - take logs.
*Tuesday, March 11, 2008 at 2:29pm by DrRuss*

**math- logarithms**

how do i solve these logs? log1/2 (3x+1)^1/3= -2 3^(x^3)= 9^x
*Thursday, January 8, 2009 at 7:16pm by kayla*

**Math - logs**

3^log_3(2x - 1) = 3^2 but 3^log3 a = a for any a so 2 x - 1 = 3^2 = 9 2 x = 10 x = 5
*Saturday, January 24, 2009 at 5:49pm by Damon*

**math**

how do you solve for x using logs: [(a + b)^x]/b^x I am not sure of the steps to get there.
*Tuesday, January 19, 2010 at 8:59pm by David*

**Math 12 (Logs)**

Solve: 3^(2a+3)=7^(a-4) Please Help and Thank you
*Sunday, April 15, 2012 at 7:34pm by Anonymous*

**math- exponents and logs**

Yes, I am getting 2.063664032
*Monday, March 4, 2013 at 5:07pm by Dr. Jane*

**chemistry**

help required in calculating the pH value of a .84 mols per litre solution of sulfuric acid. I understand that pH = -log 10 (2x 0.84), I am not very experienced with logs and need assistance as to which keys to press on the scientific calculator in relation to the logs. thank ...
*Tuesday, March 6, 2007 at 5:45am by ruby*

**math - logs**

if logx3 = a and logx25 = b, determine an expression for logx(9/5).
*Thursday, December 10, 2009 at 10:36pm by Cyn*

**Math Repost (Logs)**

No. 10^.704=100/x solve for x
*Sunday, February 21, 2010 at 4:54pm by bobpursley*

**math**

Require that X*(1.025)^16 = 15,000. X is the initial amount that you will need to invest. The 1.025 is the factor by which balance increases by every 3 months. It does this 16 times in 4 years. You can use logs to get the answer. I will use base 10 logs. (The base does not ...
*Sunday, November 15, 2009 at 12:56pm by drwls*

**Science**

Which of the following materials will burn the fastest in open air? A. a log, two feet in diameter B. two logs, each one foot in diameter C. a pile of small splinters made from a two-foot diameter log D. Both logs and the splinters will burn at the same rate.
*Thursday, March 8, 2012 at 11:41am by Samantha*

**Science**

Which of the following materials will burn the fastest in open air? A. a log, two feet in diameter B. two logs, each one foot in diameter C. a pile of small splinters made from a two-foot diameter log D. Both logs and the splinters will burn at the same rate.
*Monday, March 12, 2012 at 4:47pm by Samantha*

**Calculus**

I see y = (2x+1)(x-2)^.5 / [(x-3)^(2/3)] There are many ways to do this to find dy/dx one is to use the quotient rule and just slug it out. If you know logs, there is a nice way: using the rules of logs we get ln y = (1/2)ln(x-2) + ln(2x+1) - (2/3)ln(x-3) then (dy/dx) / y = 1...
*Thursday, November 8, 2007 at 6:33pm by Reiny*

**Math**

The log button provides the logarithm (base 10) of any number punched into the calculator. (There is also an ln button on most calculators that provides the logarithm (base e) of any number punched into the calculator. There is probably a way of solving that equation without ...
*Saturday, November 29, 2008 at 3:51pm by DrBob222*

**Math - Working with Logs!!**

So, you don't use the equation: M = log(I_i / I_o) ?
*Tuesday, December 11, 2007 at 10:30pm by Anonymous*

**math**

How would I simplify this problem using logs? (25/16) -3/2
*Monday, June 2, 2008 at 7:26pm by Jenna*

**math**

solve for n ... 2000 = 1000(1.035)^n YOu will have to use logs
*Tuesday, November 9, 2010 at 10:49pm by Reiny*

**Algebra 2 ..**

256^2 = (4^4)^2 = 4^8 so, you are correct. But, you can't be smart IF YOU SHOUT IN CAPS!! log 45^x = x log45, so you are correct again. log 12^(x+1) = (x+1) log 12/log 6, so you are right again. Don't know whether you're smart, but you seem to understand logs. Better than I ...
*Friday, February 22, 2013 at 10:19pm by Steve*

**Math**

Could you check these pleas? Firewood usually sold by a measure known as a cord. A full cord may be a stack 8x4x4ft or a stack 8x8x2ft 10. what is the volume of a full cord? 8*4*4=(128ft) 11. A short cord or a face cord of wood is 8x4xThe lenght of the logs. What is the volume...
*Tuesday, September 7, 2010 at 8:19pm by TiffanyJ*

**Math**

just as powers of products add (6^2 * 6^3 = 6^5) and subtract (6^8 / 6^3 = 6^5) log of a product is the sum of the logs, and log of a quotient is difference of logs. That's because of the definition of log: log6N is the power of 6 needed to get N. Even though it looks weird, a...
*Thursday, March 1, 2012 at 4:00am by Steve*

**Pre calculus**

Usually you take logs to the base of the number having exponents. In your example, you have e^(3x-7), so take logs base e. If you had written 2^(x+3) * 2^(x-7) = 32 then you'd take logs base 2. As for graphing, just recall the all exponent/log graphs look the same, except for ...
*Tuesday, November 20, 2012 at 10:48am by Steve*

**math**

This is an exponential function of the form y=ae^x Substituting x,y values (20,45)into the equation, 20=160*e^(45k) take logs on both sides and solve for k k=-(1/45)ln(8) =-0.04621 So the mathematical model becomes: y(t)=y0*e^(-0.04621t) t=time in hours y0=initial mass y(t)=...
*Sunday, June 23, 2013 at 12:30pm by MathMate*

**Math - logs**

thank you! so if I get a problem like that, all I do is raise the base to the power of the log?
*Saturday, January 24, 2009 at 5:49pm by Anonymous*

**math**

also a problem that i cant figure out is how to do inverses of logs f(x)= 2log(base2)X
*Friday, March 2, 2012 at 10:16am by Diana*

**math**

3hours=8 logs 1hour =? if less, more will divide. 1/3 multiplys 8logs =8/3 =2 2/3
*Wednesday, August 15, 2012 at 1:15pm by Vanessa*

**math**

I need to use logs, sorry. 1.0275^n = 50,000/6250
*Monday, January 14, 2013 at 6:56pm by Damon*

**Math (logs)**

In x = -3 find x. I worked it out like this e^inx= e^-3 then I got x = 1/e^3. Is that correct?
*Sunday, December 8, 2013 at 8:40pm by Wilson*

**LOGARITHMS**

HI THE QUESTION STATES THAT ONE SHOULD CALCULATE THE LOGS WITHOUT THE USE OF A CALCULATOR...OKAY MY PROBLEM IS THIS... 2 3 2log 8 + 2log 8 what should i do? i had come to the piont of... 4 5 log 8 + log 8 But what's to do now i dont know..Think u can help?... cheers michelle ...
*Wednesday, October 25, 2006 at 8:15am by TIGGER*

**Math**

Mr.Reiny, We don't use logs yet, so how do I find it without using log?
*Thursday, April 18, 2013 at 7:48pm by Nancy*

**college algebra**

You are going to use 3 man rules of logs 1. log(A/B) = logA - logB 2. Log(AB) = logA + logB 3. log A^n = nlogA log 3√x + log x^4 - log x^3 = log 3 + log x^(1/2) + 4logx - 3logx = log3 + (1/2)logs + logx = log3 + (3/2)logx 2. 4 log (x+3) - 5 log (x^2+4) + 1/3 log y = log...
*Wednesday, April 17, 2013 at 8:57am by Reiny*

**Algebra 2**

Addition/subtraction of logs means product/division of numbers, while product of logs means power of numbers.Log m to the base b x Log n to the base b=log m^n. On keyboard,select the character to be subscripted, press Cntrl+=. Or else select the character, go to Fonts Menu-...
*Sunday, July 21, 2013 at 5:58pm by Anonymous*

**math**

5 divided by (3-e to the -x power)=4 5/(3- e^-x) = 4 5 = 12 - 4 e^-x 4 e^-x = 7 e^-x = 7/4 e^x = 4/7 Take natural logs of both sides, x = ln (4/7) = -0.5596
*Friday, December 8, 2006 at 1:00am by Anonymous*

**Logarithms**

OMG!! THANKS!!! I totally kept adding in logs where I shouldn't have!! AWESOME!! Thanks!
*Wednesday, January 9, 2008 at 10:55pm by Math genius! Urgent!*

**Math**

4^2.3 = 24.251... Multiply that by 3 for the answer. I used a hand calculator to get 4^2.3 You could also use logs.
*Wednesday, May 28, 2008 at 11:28pm by drwls*

**Math**

solve for x without using a calculator: log5(3^x) = log25(9^(1-2x)) I don't know how to get rid of the logs for this one. Help? Thank you!
*Sunday, November 15, 2009 at 6:18pm by Momo*

**Math (check please)**

Could you check these please? Firewood is usually sold by a measure known as a cord. A full cord may be a stack 8x4x4ft or a stack 8x8x2ft 10. what is the volume of a full cord? 8*4*4=(128ft) 11. A short cord or a face cord of wood is 8x4xThe lenght of the logs. What is the ...
*Tuesday, September 7, 2010 at 8:51pm by TiffanyJ*

**math**

How would you condense a logarithm expression into a single quantity if the logs have different bases?
*Tuesday, November 20, 2012 at 1:20am by Jamie*

**Logarithms**

How do I solve this using logs? I am having a total math meltdown tonight! 10=2^10/n Thanks again!
*Wednesday, January 9, 2008 at 10:55pm by Math genius! Urgent!*

**Algebra II**

If 4^x = 4+√19, then take logs, recalling that log(x^n) = n*log(x) x*log(4) = log(4+√19) and so on log(x^2) = (log x)^2 2 logx = (logx)^2 logx(2-logx) = 0 logx = 2 or 0 x = b^2 or 1 to whatever base b you are using for the logs.
*Saturday, February 15, 2014 at 9:17pm by Steve*

**College Algebra**

#1. assuming base 8, just for ease of readability, 2logx = log(4x+12) log(x^2) = log(4x+12) so, if the logs are equal, so are the numbers: x^2 = 4x+12 x^2-4x-12=0 (x-6)(x+2)=0 x=6 only, since log(-2) is not real. #2. so far, so good. Recall that adding/subtracting logs means ...
*Wednesday, December 4, 2013 at 1:17pm by Steve*

**Algebra**

domain is your choice of x's that you can use in your equation For logs, one of the main properties is that I can only take the log of a positive number so for y = 4 + lnx , the domain is x > 0 however, the result of taking such logs results in any real number, so the range...
*Sunday, April 7, 2013 at 10:17pm by Reiny*

**Math**

1. Given the product law of logarithms, prove the product law of exponents. 2. Given the quotient law of logarithms, prove the quotient law of exponents. 3. Apply algebraic reasoning to show that a=b^(loga/logb) for any a,b>0 Please explain these to me. All I know is that ...
*Monday, May 25, 2009 at 5:38pm by Jus*

**MATH please help!**

adding logs is same as multplying log((2^3)/x)=log32 take the antilog of each side. 8/x=32 solve for x
*Thursday, December 16, 2010 at 4:41pm by bobpursley*

**math**

Thank you, Ms. Sue and Vanessa! I thought this might be a trick question, and that perhaps the correct answer was 2 (keeping logs whole).
*Wednesday, August 15, 2012 at 1:15pm by Andrea*

**misplaced nodifier**

Modifiers (adjectives and adjective phrases mostly) need to be placed as close as possible to whatever they're describing/modifying. Which one, do you think, is the corrected version of what you posted? ~~> We had been hunting for the fire extinguisher behind a pile of logs...
*Saturday, September 24, 2011 at 4:32pm by Writeacher*

**Math**

Subtracting logs is the equivalent of dividing. log 9 - log 300 = ??
*Tuesday, July 28, 2009 at 10:17pm by DrBob222*

**d**

change logs to numbers. 1E6(1+-.02) now, go to logs. remember that log(ab)=log a+logb Intensity=6 +log.98 to 6 +log(1.02) The error is the difference, so error=log1.02-log.98= .009+.009=.018 You can work it more accurately. Now differentials: Error=highentensity-lowintensity ...
*Wednesday, November 7, 2012 at 5:24pm by bobpursley*

**Math - logs**

the log(10^ -1)of 3.66 = of 9.86 = of -2.8 = thank you
*Saturday, January 19, 2013 at 12:57pm by Needs log help*

**Math**

thanks so much! i was sure it had logs involved but wasn't sure. thanks drwls and quidditch!
*Wednesday, July 23, 2008 at 12:09am by Miley*

**Math**

solve for n 8000 = 4000(1.0785)^n 2 = (1.0785)^n you will have to use logs
*Wednesday, April 21, 2010 at 4:53pm by Reiny*

**math. logs**

anyone know how to solve this step by step? e^(3ln2)
*Sunday, September 28, 2008 at 9:50pm by Kay*

**Math**

Thank you so much for your detailed reply. My problem is that we haven't done logs or "e" yet. Is there any other way arrive at an answer without knowing these? I really appreciate your help.
*Tuesday, December 1, 2009 at 12:47am by Jim*

**Math logs**

Solve the system of equations: y= (lnx)^2 + 2 (lnx^2) y = 3ln(1/x^2)+24 Im not sure what to do..
*Wednesday, October 14, 2009 at 12:53am by Mike*

**math - logs**

2 ln (x) = ln (20-x)
*Monday, October 31, 2011 at 10:34pm by Sebastian*

**Please help me!!!! maths**

I am not sure if the 5 , 8 , and 6 are bases of the logs or just multipliers. Let's hope they are just multipliers, or else it would be a terrible terrible mess by the laws of logs log5(x-2)+log8(x-4) = log6(x-1) log [40(x-2)(x-4)] = log 6(x-1) anti-log it 40(x^2 - 6x + 8) = ...
*Wednesday, April 3, 2013 at 5:33am by Reiny*

**Pre Calculus**

Major Error ! How did you mathemagically change 5^x to 20^4x ? Did you do something like (5^x)(4^4) = 20^4x ?? If so then something like this should work : (3^5)(4^2) = 12^10 which is certainly false You can only do this type of question if you know logs. take the log of both ...
*Sunday, July 26, 2009 at 11:22am by Reiny*

**Math**

ln (24/6) using the law of logs or lns where subtraction becomes division. so you have ln 4
*Tuesday, March 5, 2013 at 4:56pm by Dr. Jane*

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