Sunday

April 20, 2014

April 20, 2014

Number of results: 248,181

**mathematics**

The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2.1.1 equation of new circle which is the rotation of original circle through 180 degree around the origin...2.1.2 find equation of another circle which is the translation (x;y)-(x-8;y-6) of the points of the ...
*Thursday, March 21, 2013 at 4:46am by Jossie*

**math**

can u help this the qustion is : A circle passes through the points (1,4)&(5,0) and its centre lies on the line x+y-3=0.Find (i) the equation of the circle and it parametric equations . (ii) the centre,diameter and area of the circle . (iii) the equation of the tangent at (1,4...
*Wednesday, December 28, 2011 at 12:34am by steev*

**mathematics**

The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2.1.1 equation of new circle which is the rotation of original circle through 180 degree around the origin...2.1.2 find equation of another circle which is the translation (x;y)-(x-8;y-6) of the points of the ...
*Thursday, March 21, 2013 at 4:42am by Jossie*

**mathematics**

The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2.1.1 equation of new circle which is the rotation of original circle through 180 degree around the origin...2.1.2 find equation of another circle which is the translation (x;y)-(x-8;y-6) of the points of the ...
*Thursday, March 21, 2013 at 4:42am by Jossie*

**mathematics**

The circle x2-2x+y2-4y-4=0 lies on the cartesian plane,question 2.1.1 equation of new circle which is the rotation of original circle through 180 degree around the origin...2.1.2 find equation of another circle which is the translation (x;y)-(x-8;y-6) of the points of the ...
*Thursday, March 21, 2013 at 4:44am by Jossie*

**maths**

1) Circle centre (7,-2) passes through (-2,10). Calculate radius and find equation of circle. 2) AB is diameter of circle A(9,5) B(-1,-7). Find equation of circle mid point. I know i have to use the eqn (x1+x2)/2 and (y1+y2)/2 3) Find the equation of circle with centre (-8,5...
*Sunday, February 24, 2008 at 10:38am by Anonymous*

**steev**

can u help this the qustion is : A circle passes through the points (1,4)&(5,0) and its centre lies on the line x+y-3=0.Find (i) the equation of the circle and it parametric equations . (ii) the centre,diameter and area of the circle . (iii) the equation of the tangent at (1,4...
*Wednesday, December 28, 2011 at 12:33am by math *

**Math**

Hi guys, In the question "It is given that P (0, 3), Q(7, 5), R(9, -2) and S are vertices of a square. A circle A passes through the points P, Q, R and S. Find the equation of this circle. Hence or otherwise find the equation of circle B which is the image of A under the ...
*Friday, October 17, 2008 at 6:41am by Joshua*

**Math grade 10**

a) When x = -2, in order to be on the circle, y must satisfy the equation 4 + y^2 = 40. That means y^2 = 36. y can be either 6 or -6. Therefore the point (-2,-6) IS on the circle. b) The origin of the circle is (0,0). The equation of the circle tells you that. A line passing ...
*Wednesday, December 23, 2009 at 11:06am by drwls*

**math**

-a circle with center at the point O(0,0) also has the point P(-2,3) on it. The equation of this circle is? and a second question: -A circle has a center of square root 5. The equation of this circle is? Please help me.
*Thursday, October 9, 2008 at 9:52pm by Garrick*

**math**

Write an equation of a circle with the center (-5,-4) and radius 6. The general equation for a circle is (x-a)^2 + (y-b)^2 = r^2, where r is the radius of the circle and (a,b) are the (x,y) coordinates of the center. Make the appropriate substitutions and you will have the ...
*Monday, May 7, 2007 at 1:46am by James*

**NEED MAJOR HELP! *QUADRATIC EQUATIONS***

Write the equation for the circle with center at (- 8, - 6) and radius of 10. (x+8)² + (y + 6)² = 10 (x+8)² + (y + 6)² = 100 (x-8)² + (y - 6)² = 100 Find the standard equation for the circle with center on the positive x-axis and passing through the origin with radius of 2. x...
*Tuesday, March 20, 2012 at 2:56pm by Adrianna*

**math**

From the given circle equation you would have to know that its centre is (0,0) and its radius is √40 Notice that both A and B satisfy the equation of the circle, so A and B lie on the circle and AB is indeed a chord. In a) you are probably expected to illustrate the ...
*Thursday, October 9, 2008 at 5:11pm by Reiny*

**calc**

a circle is tangent to the y-axis at y=3 and has one x-intercept at x=1 1. determine the other x-intercept 2. find an equation for the circle so i know two points on the circle are (0,3) and (1,0) and the equation for a circle is (x-a)^2 + (y-b)^2 = r^2 but i don't know how to...
*Saturday, September 1, 2007 at 5:07pm by sammy*

**Math (Pre Cal)**

Hi, I am studying for a precalculus quiz and I do not understand this hw problem: "The tangent line to a circle may be defined as the point that intersects a circle in a single point... If the equation of the circle is x^2+y^2=r^2 and the equation of the tangent line is y=mx+b...
*Saturday, August 28, 2010 at 11:57pm by Dealie*

**MATH grade 10**

so basically you have a circle, right? and the equation of a circle is x^2+y^2 = r^2 so in this case your r, or radius is root of 64, or 8 if the radius of the circle is 8, use the formula for circumference of a circle (c=2pi(r)) to find the length of fencing so... c=2pi(8) so...
*Tuesday, October 6, 2009 at 9:25pm by brandon*

**Math**

This question makes reference to an orthonormal basis (i,j), and an origin O. 1. Consider the triangle ABC, with vertices A(0,-2), B(9,1), C(-1,11). Find: a) a cartesian equation of the altitude from C; b) a cartesian equation of the circle which has BC as a diameter; c) a ...
*Wednesday, February 27, 2008 at 11:08am by Anonymous*

**8th grade math**

circle A has a raduis that is twice the length og the raduis of circle B. Which is an accurate statement about the relationship of these areas of circle A and B and y? a.the area of circle A is 4 times the area of circle B b. the area of circle A is twice the area of circle B...
*Thursday, December 16, 2010 at 10:18pm by Court*

**Math**

Answer check please: Consider the circle (x-3)^2 + (y+1)^2 = 169. The point (15,4) is on the circle. Find an equation for the line that is tangent to the circle at this point. I got y= 5/12x-9/4.
*Sunday, August 26, 2012 at 2:44pm by KC*

**Advanced Math**

In general: (x-a)^2 + (y-b)^2 = r^2 Center point in 8x + 5y = 8, meaning: 8a + 5b = 8. ..(1) Circle passing (2,1): (2-a)^2 + (1-b)^2 = r^2. ..(2) Circle passing (3,5): (3-a)^2 + (5-b)^2 = r^2. ..(3) Use equations (2) and (3) to eliminate r, we now have a new equation with a ...
*Monday, February 28, 2011 at 3:36am by agrin04*

**geometry**

the center of the circle is at O(6,10) OX = 5 So, the equation of the circle with diameter XY and center O is (x-6)^2 + (y-10)^2 = 25 OZ = 5, so Z is on that circle. Any triangle with the circle's diameter as one side, and a point on the circle is a right triangle. Since Z is ...
*Wednesday, July 11, 2012 at 10:18pm by Steve*

**Algebra..**

The standard form equation of a circle: ( x - h ) ^ 2 + ( y - k ) ^ 2 = r ^ 2 h are the x coordinate of the center of the circle. k are the y coordinate of the center of the circle. r = radius In this case: h = - 2 k = 0 r = 3 So equation of a circle : ( x + 2 ) ^ 2 + y ^ 2 = 9
*Friday, September 14, 2012 at 3:52pm by Bosnian*

**geometry**

I guess you have not read this on Sunday: Standard equation of a circle with a radius of r and centre (x0,y0) is: (x-x0)²+(y-y0)²=r² Centre of circle: ((5-1)/2, (4+(-4))/2)=(2,0) Out of the four choices, there is only one that has a centre positioned at (2,0). (hint: refer to ...
*Sunday, May 13, 2012 at 7:11pm by MathMate*

**Math**

Cinnamon, that is so wrong. Samanth, the equation is a circle at the origin with radius 3. You need to memorize this equation (x-h)^2 + (y-j)^2=r^2 a circle at (h,j) with radius r.
*Sunday, September 30, 2007 at 3:48pm by bobpursley*

**Math**

Cinnamon, that is so wrong. Samanth, the equation is a circle at the origin with radius 3. You need to memorize this equation (x-h)^2 + (y-j)^2=r^2 a circle at (h,j) with radius r.
*Sunday, September 30, 2007 at 3:48pm by bobpursley*

**math**

The given equation follows the general equation for circles, which is (x - a)^2 + (y - b)^2 = r^2 where (a,b) = the point where the center of the circle lies r = radius From the equation, (x + 3)^2 + (y + 5)^2 = 16 r^2 = 16 r = 4 units Recall that the circumference of a circle...
*Wednesday, August 14, 2013 at 11:34pm by Jai*

**Alg2**

The tangent to a circle may be defined as the line that intersects the circle in a single point, called the point of tangency. If the equation of the circle is x^2 + y^2 = r^2 and the equation of the tangent line is y = mx + b, show r^2(1 + m^2) = b^2 Hint: The quadratic ...
*Thursday, October 22, 2009 at 11:17pm by Allen*

**Math**

Not all Cartesian equations are straight lines. It is any equation that uses the variables x and y. For example, b) and c) are circles. For (a), they want the equation of a line through C that is perpendicular to the side c (from A to B) The line from A to B has slope m = (1+2...
*Wednesday, February 27, 2008 at 11:08am by drwls*

**geometry**

The equation of a circle is(x-3)squared plus (y+2)squared.The point (8,-2)is on the circle.What is the equation of the line that is tangent to the circle at (8,-2)? y=8 x=8 x=3 y=3
*Wednesday, January 18, 2012 at 10:45pm by Dana*

**Pre-Calc**

The general equation of a circle is (x-x0)² + (y-y0)² = r² where (x0,y0) represent the centre of the circle, and r = radius. The given equation of the circle: (u-5)^2 + y^2 =9 can be rewritten as: (u-5)² + (y-0)² = 3² which tells us that the ...
*Tuesday, December 7, 2010 at 8:59pm by MathMate*

**Algebra 2**

Consider a circle centered at (2,4). What are the coordinates of the center of the translated circle if we replace x with x-3 and y with y+5 in the equation of the circle?
*Sunday, January 15, 2012 at 10:54pm by Peter*

**Math**

The points (4, –5) and (– 4, 1) are endpoints of a diameter of a circle. (a) Find the center of the circle. (b) Find the length of the radius of the circle. (Note that this is a distance.) Give the exact answer. Show work. (c) State the equation of the circle (in standard form...
*Wednesday, June 24, 2009 at 1:52am by Kate*

**equation for circle**

find the equation of a circle. the endpoints of the diameter of a circle are (3,-2) and (7,-6).
*Sunday, February 5, 2012 at 6:44am by Declan*

**math**

a circle is tangent to the y-axis at y=3 and has one x-intercept at x=1 a) what's the other x-intercept b) what's the equation i have no clue how to solve this! You know that the center of the circle is somewhere in the line y = 3, denote the x-coordinate by rx. Then the ...
*Saturday, August 4, 2007 at 4:07pm by Anonymous*

**Geometry**

Within an orthonormal system consider points A(1,4) B(5,1) C(4,8) (a)Calculate the angle ABC (b)Show that 3x+4y-19=0 is an equation for line L which passes through A and B (c)Find a vector equation for line L (d)(i)give an equation for the circle with the line segment AB as ...
*Sunday, May 4, 2008 at 2:12pm by Anonymous*

**Math**

The point (-4.3) lies on a circle whose center is at (2,1). Find an equation of this circle.
*Saturday, February 5, 2011 at 6:41am by Adam*

**math**

circle has a center at (-8,-4) and circumference of 32.determine equation of the circle
*Tuesday, March 29, 2011 at 10:30pm by Anonymous*

**College Algebra**

using the knowledge of systems of equations, and that the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center and r is the radius. Find the equation of a circle that contains the following points: (6,2), (4,6), and (-3,5). (These 3 points each create an ...
*Thursday, December 15, 2011 at 12:27am by Kevin*

**College Algebra**

using the knowledge of systems of equations, and that the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center and r is the radius. Find the equation of a circle that contains the following points: (6,2), (4,6), and (-3,5). (These 3 points each create an ...
*Thursday, December 15, 2011 at 12:27am by Kevin*

**geometry**

Circle O is defined by the equation x2 + (y - 2)2 = 25. Plot the center of Circle O and type in the coordinates of one point with integral values that lies on Circle O.
*Sunday, August 5, 2012 at 4:33pm by sara*

**Math**

If the coordinates of the center of a circle are (-3,1) and the radius is 4, what is an equation of the circle
*Saturday, September 7, 2013 at 2:47am by Kiki*

**Trigonometry**

1) Find the coordinates of the point (-1,3) after the transformation T (to the -3,2 power) 2) What are the coordinates of point (-3,4) under D (to the 3rd power)? 3) Which of the following transformations could map the point (1,2) onto the point (3,6)? a)T (to the 2,3 power) b...
*Wednesday, February 24, 2010 at 9:44pm by Tyler*

**calculus**

The general equation for a circle is: (x-a)^2 + (y-b)^2 = R^2 R is the radius of the circle and the point (a,b) is the center. To solve the problem you just insert the coordinates of the three points that are known to be on the circle in the equation and solve for a, b and R: ...
*Friday, August 31, 2007 at 5:40pm by Count Iblis*

**geometry**

Standard equation of a circle with a radius of r and centre (x0,y0) is: (x-x0)²+(y-y0)²=r² Centre of circle: ((5-1)/2, (4+(-4))/2)=(2,0) Out of the four choices, there is only one that has a centre positioned at (2,0). (hint: refer to the standard equation of ...
*Sunday, May 13, 2012 at 7:11pm by MathMate*

**Math**

Find the equation for the following circle: The circle that passes through the origin and has intercepts equal to 1 and 2 on the x- and y-axes, respectively.
*Friday, August 8, 2008 at 12:12am by fishbowl*

**Math**

Write the standard for of the equation of the circle that passes through the points at (0,8),(8,0),and (16,8). Then identify the center and radius of the circle.
*Thursday, July 2, 2009 at 6:01pm by Sally*

**Math**

The endpoints of a diameter of a circle are (3, 4) and (7, –2). What is an equation of the circle?
*Sunday, February 16, 2014 at 6:51pm by Kiki*

**math**

sorry, i could not understand #15. #16. you have to plot this. But if you already know some properties of circle (in terms of its equation), you can skip plotting. The equation is a graph of circle, with center at (-6,-4) and radius = 6. The center is the position of source, ...
*Wednesday, May 23, 2012 at 11:36am by Jai*

**calculus**

#1. Have you tried plugging x=3 and y=2 into the equation? Do it and verify that the equation is satisfied there. Then get the circle's slope dy/dx at (3,2) by implicit differentiation. Once you know one point on the line (3,2), and the slope at that point, the equation of the...
*Saturday, June 28, 2008 at 9:36pm by drwls*

**Maths**

The center of the circle is at x=a, y = b. It is also on a line that is perpendicular to the tangent line. That line has slope -1 and its equation is (y-1) = -(x+4) y = -x -3, so since (a,b) is on that line, b = -a -3 Another equation that relates a to be is (-12-a)^2 + (9-b)^...
*Monday, March 17, 2008 at 5:12am by drwls*

**MATH**

The standard equation of a circle is (x-h)^2+(y-k)^2 = r^2 where the centre is at (h,k) and radius r. The given equation can be rewritten as: (x-(-2))^2 + (y-0)^2 = 8^2 Compare the above equation with the standard equation to find the centre and radius of the given circle.
*Sunday, February 13, 2011 at 1:21pm by MathMate*

**Algebra II**

In this set of eight problems, we have to match each equation with the correct description of its graph. However, these are test corrections I'm doing and I do not have the previous multiple choice answers so I can deduct from it, but can someone help me? The equation is xy = ...
*Wednesday, February 4, 2009 at 11:52pm by Emily*

**Pre-Calc**

Can someone please be kind and show me the steps on this? Thanks Find the equation of the circle centered at the origin in the uv-plane that has twice the circumference of the circle whose equation equals (u-5)^2 + y^2 =9
*Tuesday, December 7, 2010 at 8:59pm by Ann*

**Algebra 2**

"Solving" means finding ordered pairs that satisfy the equation. Your equation is a circle, and there are an infinite number of ordered pairs that will work. Did you mean to put it in the standard form of a circle equation?
*Thursday, April 8, 2010 at 2:44pm by Reiny*

**algebra 1**

recall that the equation of a circle is given by (x-h)^2 + (y-k)^2 = r^2 where h = x-coordinate of center of circle k = y-coordinate of center of circle r = radius thus from the given equation, (x-2)^2 + (y+4)^2 = 9 the radius is sqrt(9) = 3 also, recall that area of circle is...
*Sunday, April 24, 2011 at 10:05am by Jai*

**equation for circle**

Those are endpoints of A diameter which is neither horizontal nor vertical. There are other possible diameter endpoint pairs for the same circle. The midpoint of the given diameter is at (5,-4). You get that by averaging the two x's and the two y's, separately. The length of ...
*Sunday, February 5, 2012 at 6:44am by drwls*

**Math**

write the equation of the circle in standard form. find the center, radius, intercepts, and graph the circle. x^2+y^2-6x-8y+25=36
*Sunday, May 27, 2012 at 9:08pm by Rachel*

**Math**

Circle O is centered at the origin and has a radius of 5. Circle O' is the image of circle O after a translation of T1,2. What is the center of circle O'? What is the radius of circle O'?
*Wednesday, March 3, 2010 at 10:48pm by Collin*

**math - Line+circle**

Rewrite x^2+y^2-4x+2y=20 as (x-2)^2+(y+1)^2=25=5^2 ...(1) represents a circle of radius 5 with centre (2,-1). which intersects with the line 4x+3y=5 ...(2) So write y=(5-4x)/3 and substitute in the circle equation (1) to get (x-2)^2+(((5-4x)/3)+1)^2=5^2 Solve for x in the ...
*Thursday, March 1, 2012 at 9:43am by MathMate*

**algebra 2**

It is a circle because the coeffients of the x terms and the y terms are the same. Note that it could be rewritten in the standard circle equation form: [(x-2)/3]^2 + [(y-4)/3]^2 = 1 The radius of the circle is 3 and the center is at (x,y) = (2,4).
*Tuesday, June 10, 2008 at 5:14pm by drwls*

**maths-urgently needed**

find the equation of circle if the line 2x - y +1 = 0 touches the circle at the point (2,5) and the center of the circle lies on the line x+y -9 =0
*Thursday, February 14, 2013 at 11:24am by Anonymous*

**Equations of a Circle**

Write the standard for of the equation of the circle that passes through the points at (0,8),(8,0),and (16,8). Then identify the center and radius of the circle. I have r=8, center=(8,8). What now?
*Saturday, April 21, 2012 at 5:27pm by Some1 Help Me Plz*

**maths**

Given that the equation of the circle is x^2 + y^2 +2x -8y+5 =0 (i)Find the centre and radius of the circle (ii)Determine whether the line x-3y=8 is tangent to the given circle
*Monday, February 27, 2012 at 3:50am by mazoe*

**maths**

Given that the equation of the circle is x^2+y^2+2x-8y+5=0 (i)find the centre and radius of the circle (ii)Determine whether the line x-3y=8 is tangent to the given circle
*Wednesday, March 14, 2012 at 10:49am by tembo*

**GEOMETRY**

The diameter of a circle has endpoints P(–10, –2) and Q(4, 6). a.Find the center of the circle. b.Find the radius. If your answer is not an integer, express it in radical form. c.Write an equation for the circle.
*Wednesday, May 30, 2012 at 1:15am by HELP PLEASE!*

**Math**

A circle has a radius that increases at a rate of 10cm/s. Find the equation of the outermost circle 6 seconds after it starts to expand. Using x2 +y2=r2
*Saturday, March 30, 2013 at 6:36pm by Amjs*

**Math**

A circle has a radius that increases at a rate of 10cm/s. Find the equation of the outermost circle 6 seconds after it starts to expand. Using x2 +y2=r2
*Saturday, March 30, 2013 at 6:36pm by Amjs*

**math (pre clac)**

so its this picture of a rectangle inscribed in a circle. the circle has a radius of 2. the vertexes of the circle are present in every quadrant, but you cant tell exactly whgat point they represent. point Q (x,y) is the vertex of the rectangle in Quadrant I and is on the ...
*Friday, April 25, 2008 at 4:55pm by Alexis*

**geometry**

This one is confusing me. please help The diameter of a circle has endpoints P(–10, –2) and Q(4, 6).Find the center of the circle.Find the radius. If your answer is not an integer, express it in radical form. Write an equation for the circle. Thanks
*Thursday, January 12, 2012 at 1:17am by ryan*

**Math (geometry)**

Line l is tangent to circle O at point P(3,4) where the center is located at (0,0). a. Find the radius of the circle. (I got 4) b. Give an equation of the circle. (I got x^2+y^2=16) c. Find the slope of line l. d. Give an equation of line l...
*Wednesday, April 30, 2008 at 7:09pm by Emily*

**Gradient of circle?**

A circle has the equation x^2+y^2-4x+6y-12=0 and i have already found that the centre has a coordinate of (2,-3), and a radius of 5 units. But i need to find points on the circle that has the gradient of -4/3 when a tangent is drawn on the point. How do i do that???
*Saturday, September 26, 2009 at 4:00am by Marrion*

**Pre Calc**

To me that doesn't seem like a complete question. You have 1 equation with 2 unknowns. You need a minimum of 2 equations to find 2 unknowns. Another way of looking at it is that the above equation is the equation for a circle with center (2,-3) and radius 3. So asking for two ...
*Sunday, March 15, 2009 at 9:01pm by GanonTEK*

**math**

A circle is tangent to the y-axis at y=3 and has one intercept at x=1. a) Determine the other x-intercept. b) Find the equation of the circle. Thanks for helping!
*Sunday, August 3, 2008 at 11:30am by alk*

**math**

If a circle of radius r has center at (h,k) the equation of the circle is (x-h)² + (y-k)² = r² So, plug and chug: x² + (y-(120+9))² = 120² x² + (y-129)² = 14400
*Wednesday, October 5, 2011 at 11:13am by Steve*

**Math**

Did you draw a diagram? Most people are "visual" and it will make the question easier to see. a) the altitude must meet AB and must be perpendicular to AB so slope of AB = 3/9 = 1/3 which makes the slope of the altitude -3 we know the altitude has slope -3 and must pass ...
*Wednesday, February 27, 2008 at 11:08am by Reiny*

**Math**

A circle is tangent to the y-axis at y=3 and has one x-intercept at x=1, find the other x-intercept and the equation of the circle. ...And if it's not any trouble, could you please explain how to do get there alongside showing me what to do? Thanks (:
*Monday, February 8, 2010 at 9:25pm by Leslie*

**math**

the general equation of a circle with centre at (0,0) is x^2 + y^2 = r^2 sub in your given point to find r^2 and you are done. your second question makes no sense the centre of a circle is a position, not a value.
*Thursday, October 9, 2008 at 9:52pm by Reiny*

**math**

Start with the equation of circumference of a circle: c = pi x d. The diamter is 2 x radius. So, the diameter of the first cirlce is 18cm. You know the diameter of the second circle. So, how do the circumferences compare?
*Wednesday, November 26, 2008 at 9:52pm by DanH*

**Pre-Calc (Circles)**

Describe the conditions necessary, where circle A has a larger radius than circle B, for the two circle to have no points of intersection, while circle B is entirely in the interior of circle A.
*Tuesday, November 17, 2009 at 6:44pm by Anonymous*

**math**

x^2 + y^2 -6x + 4y +2 = 0 can be rewritten as the equation of a circle, as follows. (x-3)^2 + (y+2)^2 -9 -4 +2 = 0 (x-3)^2 + (y+2)^2 = 11 The center of the circle is (3,-2) and the radius is sqrt(11). The other equation can be rewritten (x+4)^2 + (y+1)^2 = 22 -17 = 5 Its ...
*Friday, July 9, 2010 at 6:02am by drwls*

**math**

recall that the equation of a circle is given by (x-h)^2 + (y-k)^2 = r^2 where h = x-coordinate of the center k = y-coordinate of the center r = radius since in the problem, the center lies at (-8, -4) we have h = -8 k = -4 also, we need to solve for the radius from the ...
*Tuesday, March 29, 2011 at 10:30pm by Jai*

**math**

HELP!! the area A of the circle in the figure can be represented by A(r)=pi,r^2 where r is the radius what are the resonable domain and range for each function? explain the problme before this made me make a equation of B(r)=5^2-pi,r^2 im not sure if there asking this or A(r)=...
*Wednesday, November 3, 2010 at 9:03pm by paul*

**Check!!!**

okay so the question is: A unit circle center at the origin undergoes a series of transformations. The equation of the resulting graph is (x-3)^2+ (y+4)^2= 25 describe the transformation the unit circle underwnt Answer: The original circle was centered at the origin and had ...
*Wednesday, February 14, 2007 at 3:54pm by math*

**Math**

Consider a circle with centre A and B any point on the circle. let A be (0,4) , the y-intercept of y = 2x+4 the B must be both on y = 2x+4 and the circle the equation of the circle would be x^2 + (y-4)^2 = 25 sub in y = 2x+4 x^2 + (2x+4 - 4)^2 = 25 x^2 + 4x^2 = 25 5x^2 = 25 x^...
*Thursday, March 29, 2012 at 4:21pm by Reiny*

**algebra**

1)Write an equation for the parabola with focus (1,3)and vertex(0,3) answer= x= 1/4(y-3)^2 2)Write an equation for a circle if the endpoints of a diameter are at (1,1)and(1,-9) answer= (x-1)^2+(y+4)^2=25 3)Which is the equation of a circle with center (0,1)and radius 2 units? ...
*Tuesday, August 21, 2007 at 5:09pm by Marissa*

**Math**

The roots of the parabola are known (-3 and 6), so the equation of the parabola is in the form: k(x+3)(x-6)=0 or k(x²-3x-18)=0 ...(1) where k is a constant to be determined. Since the y-intercept is negative, k>0. If ∠ABC is a right angle, then a circle with AB as ...
*Sunday, May 29, 2011 at 12:46am by MathMate*

**Math**

how an I tell if this is a circle or an ellipse? also, how am I supposed to solve it? -x^2+2y^2+8x+3=0 I answered a similar question for Jordan last night at 11:20 divide your equation by -1 to make it start with a positive x^2 term. At this point you should realize that it is...
*Wednesday, April 4, 2007 at 2:01am by Darrin*

**math - geometry**

Austin wants to sketch the graph of a circle represented by the given equation. (x - 4)2 + (y + 7)2 = 64 Using complete sentences, describe the steps used to sketch the circle on a coordinate grid
*Monday, August 19, 2013 at 9:39pm by kris*

**Pre-Calc**

Looks like the first one is intended to be the equation of a circle. (x^2 + ax) + (y^2 + by) = 0 Unfortunately, if a or b is not zero, there is no real graph. If a=b=0, then the graph is just the point (0,0). If there was a typo, giving a "d" on the right-hand side, then given...
*Tuesday, January 10, 2012 at 12:15pm by Steve*

**Algebra**

The point (-1,0) lies on a circle whose center is at (-6,5). Find an equation of this circle
*Tuesday, May 17, 2011 at 8:46pm by Jennifer*

**geometry**

Given the equation of the circle (x – 9)2 + y2 = 484 , where is the center of the circle located at?
*Tuesday, November 12, 2013 at 9:51am by jose*

**Algebra**

Write the equation of the circle. Center at (4,2) and the circle passes through the point (-1,-1). Please help!
*Wednesday, September 23, 2009 at 7:41pm by Bree*

**Calculus**

Points (–1, 6) and (–3, 2) are endpoints of the diameter of a circle. (a) What is the exact length of the diameter? (Simplify as much as possible) Answer: ________ (b) What is the center of the circle? Answer: ____________ (c) What is the equation of the circle? Answer: ...
*Saturday, March 10, 2012 at 2:47pm by Brian*

**math**

A circle with the equation (x + 4)2 + (y - 3)2 = 9 is reflected over the line y = -1. What is the equation of the image?
*Sunday, January 22, 2012 at 8:42pm by Callie*

**Math**

I have a series of questions that I did. They lead up to the last question I can't solve. Could you check my math and help me with the last question? Thanks! a) Let a be the point (2,3). Compute the distance from Origin 0 to A answer: a^2 + b^2 = c^2 3^2 + 2^2 = c^2 c=sqrt(13...
*Thursday, October 14, 2010 at 2:21pm by Shane*

**Algebra**

If a circle of radius 5 is made to roll along the x-axis, what is the equation for the path of the center of the circle?
*Tuesday, August 11, 2009 at 6:01pm by coried*

**Algebra**

The circumference,y, of a circle varies directly with the diameter,x, of the circle. Write an equation if y=44cm when x=14cm.
*Monday, May 17, 2010 at 10:44pm by Austin*

**maths**

the equation of the circle is x^2+y^2+2x-8y-1=0. Find the coordinates of the point where the circle crosses the x-axis
*Friday, March 30, 2012 at 2:48am by mumba*

**math **

I am supposed to find the area of a segment of a circle. The circle is cut with two radi with an angle of 90 degrees. Then where the radi touch the circle another line is drawn to connect them. The triangle and the small section between the triangle and the edge of the circle ...
*Saturday, May 4, 2013 at 10:21pm by Ed*

**math**

I am supposed to find the area of a segment of a circle. The circle is cut with two radi with an angle of 90 degrees. Then where the radi touch the circle another line is drawn to connect them. The triangle and the small section between the triangle and the edge of the circle ...
*Sunday, May 5, 2013 at 7:57pm by Hannah*

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