Saturday

April 19, 2014

April 19, 2014

Number of results: 226

**maths**

2=1(1+i)^20 take the log of each side log2=20(log(1+i) log(1+i)=log2/20=.01505 now take the antilog 1+i=10^(.01505)=1.03526 so i=3.526 percent triple? 3=(1.03526)^t take the log of each side log3=t*log(1.03526) t= log3/log(1.03526)= .4771 /.01505 almost 32 years check that
*Saturday, May 7, 2011 at 4:52am by bobpursley*

**pre calc**

3000(1.02)^n = 8000 , where n is the number of quarter years 1.02^n = 8/3 take log of both sides log 1.02^n = log (8/3) using log rules ... n log1.02 = log8 - log3 n = (log8 - log3)/log1.02 = 49.53 it will take appr 49.53 quarter years or 12.4 years
*Monday, February 11, 2013 at 9:07pm by Reiny*

**Algebra 2**

log5 (log3³)
*Wednesday, June 13, 2012 at 1:22pm by Jackie*

**algebra**

Since this is not my area of expertise, I searched Google under the key words "exponent rules" to get these possible sources: http://www.purplemath.com/modules/exponent.htm http://www.sosmath.com/algebra/logs/log3/log3.html http://www.mathwords.com/e/exponent_rules.htm http://...
*Tuesday, April 15, 2008 at 2:38pm by PsyDAG*

**precal (log)**

3^(log3(4x)) thank u
*Tuesday, April 8, 2008 at 1:32am by Deb*

**trig**

evaluate log3 27
*Wednesday, October 29, 2008 at 9:00pm by jerson*

**Trigonometry**

log3(x^2)=2log3(4)-4log3(5)
*Friday, July 8, 2011 at 11:02am by Kali*

**Math**

Transform: log3^4= log(3/4)=
*Monday, February 20, 2012 at 8:27pm by Harry*

**calculus**

Logarithmics: Ie: log3 3^11 : Evaluate? Thanks.
*Sunday, April 20, 2008 at 4:33am by Pam*

**Calculus**

s(x)=log3(x^2+6x) find derivative?
*Friday, October 14, 2011 at 2:21pm by Beth*

**precalculus**

find the component f and g so that fog =H H(x)=log3 e^x
*Tuesday, November 8, 2011 at 11:29pm by tina*

**precalculus**

find the component f and g so that fog =H H(x)=log3 e^x
*Wednesday, November 9, 2011 at 9:52pm by tiona*

**Math- Alg 2**

x log3 = log28 x = 3.0331
*Friday, January 27, 2012 at 12:44am by drwls*

**Math**

Evaluate the logarithm log3 729
*Thursday, May 24, 2012 at 5:32pm by Neil*

**math equations**

Solve x = log3 15
*Tuesday, June 12, 2012 at 1:52pm by jess*

**Pre Cal**

f(x) = log3(93 x + 3 815 x + 3)
*Tuesday, October 2, 2012 at 11:29pm by Sally*

**Math**

since 243 = 3^5, that would be 5 log3
*Friday, November 16, 2012 at 10:22am by Steve*

**math**

Solve this equation for x Log3^2x+5 =1
*Saturday, March 29, 2014 at 6:14pm by Lindsay*

**Math**

I need help solving this logarithmic function: x = log3(4^3).
*Thursday, January 31, 2008 at 9:39pm by Danielle*

**Math - logs**

3^log_3(2x - 1) = 3^2 but 3^log3 a = a for any a so 2 x - 1 = 3^2 = 9 2 x = 10 x = 5
*Saturday, January 24, 2009 at 5:49pm by Damon*

**Pre Cal**

75=3*5^2 log75=log3+ 2log5
*Tuesday, December 22, 2009 at 6:02pm by bobpursley*

**pre-calculus**

since log3(x+8) = 4, x+8 = 3^4 x+8 = 81 x = 73
*Saturday, October 6, 2012 at 2:05pm by Steve*

**Precalculus**

log3 [(x+1)/(x-3)] = 2 (x+1)/(x-3) = 3^2 = 9 x+1 = 9x-27 8x = 28 x = 7/2
*Tuesday, December 11, 2012 at 5:55pm by Steve*

**Math**

Eq1: Pt = Po(1+r)^n. Eq2: Pt = 3Po. r = (3mo./12mo.) * 4% = 1% = 0.01 = Quarterly int rate expressed as a decimal. n=4 comp./yr * t yrs.=4tcomp. periods. In Eq1,substitute 3Po for Pt: 3Po = Po(1.01)^4t, Divide both sides by Po: (1.01)^4t = 3, Take Log of both sides: 4t*Log(1....
*Friday, July 22, 2011 at 11:34am by Henry*

**math... precalculus**

how do i solve this equation? log3x+log3(x-24)=4
*Sunday, November 15, 2009 at 1:54pm by alexa*

**calculus**

Suppose that log2 = a and log3 = b Solve for x in terms of a and b: 6^x = 10/3 - 6^-x
*Monday, December 6, 2010 at 10:33pm by Jenny*

**calculus**

what is the derivative of log3(x+X^2) log with base 3 i cant figure it out
*Monday, December 5, 2011 at 6:09pm by ann*

**math log**

log3 (x-9)=3 x-9=3^3 x= 9+27 second one is correct.
*Thursday, May 3, 2012 at 6:17pm by bobpursley*

**math 12**

log6=x and log8=y, determine an expression for log3 in terms of x an y.
*Sunday, October 3, 2010 at 10:13pm by nat*

**trig**

solve for x log4 64+ log2 2 ________________ =x log3 81
*Tuesday, February 28, 2012 at 1:49pm by Beth*

**math**

express the following as a single logarithm log2+log3+log4
*Monday, April 15, 2013 at 7:55pm by kathrine*

**maths**

solve the equation log3 (2-3x) = log9 (6x^2-19x+2)
*Tuesday, October 8, 2013 at 7:33pm by gibbons1*

**algebra 2 trig**

if log3=a then log300 can be expressed as? 1) 100a 2)a+2 3)100+a 4)3a
*Saturday, January 4, 2014 at 4:54pm by nikki*

**Math**

Solve for x: 3^(x+1)=2^x This is what I have so far... (x+1)log3 = xlog2 ...and now I'm stuck. Help plz? Thanks!
*Sunday, April 11, 2010 at 1:58pm by Nikki*

**math**

Given the fuction y = log3(x+3)+2, calculate the zero of the function. GIve an exact answer.
*Saturday, December 12, 2009 at 7:43pm by Cyn*

**college algebra**

use logarithms.ie log3^x-2=log11 and solve for x using the exponent rule
*Monday, April 5, 2010 at 1:27pm by fe*

**math**

Make into one log function: 2logx-log4-log3+logx
*Monday, January 10, 2011 at 6:03pm by matt*

**Math**

Make into one log function: 2logx-log4-log3+logx
*Monday, January 10, 2011 at 6:54pm by matt*

**Math**

Make into one log function: 2logx-log4-log3+logx
*Monday, January 10, 2011 at 7:00pm by matt*

**Precalculus**

Write 4log2+log6-log3 as a single logarithm. Explain with steps please!~~
*Monday, January 30, 2012 at 3:32am by Jake*

**college algebra**

solve the equation below. Please show all work. log3(x/2-9)=4
*Sunday, March 4, 2012 at 4:29pm by Tammy*

**Algebra 2**

-5=log2X -5 = log2x 2^-5 = x x = 1/32 3^(5x+1)= 40 let's take the log of both sides log(3^(5x+1)) = log40 (5x + 1) log3 = log40 5x+1 = log40/log3 etc. log6X+(log6)7=(log6)35 log6(7x) = log6 35 "antilog" both sides 7x = 35 etc.
*Friday, April 18, 2008 at 1:11pm by Reiny*

**Logs.**

Can you please help me with the following log. problems? thanxs! Solve the exponential equation. Use a calculator to obtain a decimal approximation, correct to two decimal places, for the solution. 7^x = 6^(x + 7) this is how far I got: x log 7/x log 7= x+7 log 6/log 7, I am ...
*Friday, October 26, 2007 at 10:33pm by Ang*

**Math+Log**

log3(3^x) The first 3 is a subscript Would that = x? Also with log15(15^x) = x ? log221(221^x)= x?
*Monday, February 23, 2009 at 4:56pm by Chopsticks*

**Pre-Calc**

Make into one log function: 2logx-log4-log3+logx
*Monday, January 10, 2011 at 6:27pm by matt*

**College Algebra**

and your question? If it is to solve for x, take the log base 3 of each side. 2x=log3 14=2.40
*Wednesday, August 5, 2009 at 6:34pm by bobpursley*

**PreCalc**

Write the following expression as one logarithm: 2logx-log4-log3+logx. Simplify your answer.
*Monday, January 10, 2011 at 7:19pm by matt*

**Advanced Functions/ Precalculus Log**

By definition, blogbN = N #1. 64+100 = 164 #2. 1 = log2, so you have log2+log(x^3) = log(2x^3) #3. 1/2 (3logx + logy + 6logz) #4. supressing the "base 2" for readability, we have logx - log6 = log5+2log3 log(x/6) = log(5*3^2) x/6 = 45 x = 270 Actually, since all the logs are ...
*Thursday, December 19, 2013 at 11:42pm by Steve*

**math.**

Suppose h(x) = 3x and k(x) = log3(x). What is k(h(x))? What about h(k(x))? Start with a few numbers to convince yourself. Explain completely why this is true.
*Wednesday, March 17, 2010 at 9:48pm by Alyssa Pacheco*

**Precalculus **

a) log(log10) = log 1 = 0 b) √log100 - log(√100) = √2 - log10 =√2 - 1 c) log(√10^3√10^5√10) = log √10^9 = log 10^(9/2) = (9/2)log10 = (9/1)(1) = 9/2 d) 1000^log3 = ((10)^3)^log3 = 10 ^(3log3) = 10^(log27) = 27 e) log (1/log(10&#...
*Monday, March 1, 2010 at 12:43am by Reiny*

**Precalc**

let 2^x = u , then your equation becomes u^2 - u - 6 = 0 (u-3)(u+2) = 0 u=3 or u=-2 then 2^x = 3 x = log3/log2 = 1.58496 or 2^x = -2 which is not defined. so x = 1.58496
*Monday, January 26, 2009 at 10:19pm by Reiny*

**Math**

It's pretty much like this: log3 729= x 3^x= 729 3^x= 3^6 x= 6
*Thursday, May 24, 2012 at 5:32pm by Neil*

**math**

log2+log3+log4 = log(2*3*4) = log(24)
*Monday, April 15, 2013 at 7:55pm by Reiny*

**claculus**

graph Y=log3(x+1) graph Y<log2 ^X We can't draw graphs for you here.
*Friday, April 27, 2007 at 12:25am by Anonymous*

**oops Math**

why did I not see that -log3 in there ?? correct answer .... log ((x^2)(x)/((4)(3)) = log (x^3/12)
*Monday, January 10, 2011 at 7:00pm by Reiny*

**Calculus**

I am not certain what this is: IF it is 2^(-x)=3^(2x+2) then take the log of each side -xlog2=(2x+2)log3 and solve for x.
*Monday, January 17, 2011 at 10:09am by bobpursley*

**algebra 2**

Here are some examples to help you. log2 32 = ? 2^? = 32 ? = 5 log3 1/9 = ? 3^? = 1/9 ? = -2 As you can see, if y = logb x, then b^y = x.
*Friday, July 15, 2011 at 10:09pm by Max*

**Math**

Solve the logarithmic equation for x. Log3(x^2 − 5x − 9) = 3 I Have no idea
*Tuesday, November 22, 2011 at 12:12pm by Anonymous*

**Precalculus**

Take log on both sides to get: (3x+1)log2 = (x-2)log3 Solve for x. Log can be to any base.
*Sunday, November 14, 2010 at 12:19pm by MathMate*

**precal (log)**

When 3 is raised to the log3(4x) power, the result is 4x. That follows from the definition of a logarithm and its base.
*Tuesday, April 8, 2008 at 1:32am by drwls*

**Algebra 2**

NO, it is x=5 I verified it Here is yours: if x=3 LS= log3 + log1 = log(3x1) = log 3 which is not equal to the RS of 1
*Wednesday, February 25, 2009 at 8:08pm by Reiny*

**Math - Solving Logarithms equation**

Solve the equation below. Please show all of your work. Log3((x/2)-9) = 4
*Monday, June 6, 2011 at 1:46pm by CheezyReezy*

**Math**

since 3^6 = 729, log3 729 = 6
*Thursday, May 24, 2012 at 5:32pm by Steve*

**math**

I am supposed solve these SYMBOLICALLY but i don't know how since i was never taught in school. Could someone help me solve these? 1. 7(e^(2x))^3 = 35 2. 7^(x^2-x)=7^6 3. log3(5x)=4 Thank YOU very much!!
*Tuesday, August 24, 2010 at 9:04pm by Jamie*

**math**

simplify each expression by using properties of logarithms or definitions. check your results using the change of base formula a.) log3 27= b.) log5 (1/5)= c.) if f(x)= ln (x), find f(e^x)
*Thursday, March 3, 2011 at 1:29am by anonymous*

**Pre-Cal**

Solve the following logarithmic equation. Exact words only: log 3(x+4) = 2+log3(x-20) the 3 in the part of log (3)should be lower just didn't know how to type it in here
*Tuesday, January 1, 2013 at 9:02pm by phyllys*

**more math**

Are the following statements true ? log(-3) + log(-4) = log12 -log3 - log4 = -log12 Explain why or why not
*Sunday, December 13, 2009 at 11:58pm by Anonymous*

**more math**

Are the following statements true ? log(-3) + log(-4) = log12 -log3 - log4 = -log12 Explain why or why not
*Monday, December 14, 2009 at 1:36am by Anonymous*

**Math - Properties of Logarithms**

Use properties of logarithms to find the exact value of the expression. (log3(81)^4
*Monday, June 6, 2011 at 1:45pm by CheezyReezy*

**Algebra 2**

Simplify: 1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4. log4^3-log4^48 I need to see all of the steps. Thanks
*Thursday, May 12, 2011 at 5:38pm by Brandon*

**Trigonometry**

You must have meant log (√(3/5) = log 3^(1/2) - log 5^(1/2) = (1/2)( log3 - log 5) = (1/2)(x - y)
*Saturday, February 11, 2012 at 1:35pm by Reiny*

**Functions**

are we solving for x ? let 3^x = y then (3^x)^2 - 5(3^x) + 6 = 0 y^2 - 5y + 6 = 0 (y-2)(y-3) = 0 y = 2 or y = 3 then 3^x = 2 log both sides log 3^x = log 2 x log 3 = log 2 x = log2/log3 = approx .631 or 3^x = 3 by observation, x = 1
*Thursday, January 6, 2011 at 9:16pm by Reiny*

**algebra 2**

93log3.1+65 can be readily evaluated using a scientific calculator. Make sure you understand from the context of the question if log3.1 is to the base 10 or to the base e (natural log). Post your answer if you want it checked.
*Monday, May 23, 2011 at 10:13am by MathMate*

**Math**

(x+4)log3 = (x+2)log5 (x+4)(0.47712) = (x+2)(0.69897) 0.47712x + 1.90848 = 0.69897x + 1.39794 0.22185x = 0.51054 x=2.301 Checking you will probably find a small rounding error. If you carry the calculations to a lot of decimal places it will be more exact.
*Wednesday, July 23, 2008 at 12:09am by Quidditch*

**grade 12 math**

x= 2*3^y +1 (1/2)(x-1)=3^y take the log of each side log (1/2)+log(x-1)=ylog3 y= (log 1/2 + log(x-1)/log3
*Friday, July 30, 2010 at 11:13pm by bobpursley*

**math**

There is a vertical asymptote at x=-3 for y-intercept, let x = 0 y = log3 for x-intercept , let y = 0 log(x+3) = 0 log(x+3) = log 1 x+3 = 1 x = -2 domain: x > -3 range, y is any real number.
*Thursday, May 31, 2012 at 6:00pm by Reiny*

**Logs-check my anwers**

log10 sqrt of 10 i got 1 log3 3^11 i got 11 log5^5 i got 1
*Tuesday, October 23, 2007 at 11:37pm by Jayme*

**Math**

I think they want you to show the two values as 9=3^2 and 300=3x10^2 so you have log 3^2 - log(3x10^2) =2 log 3 - (log3 + 2log10) can you take it from here?
*Tuesday, July 28, 2009 at 10:17pm by Dr Russ*

**pre-calc**

right on a,b. 50 2^t = 20 3^t take the log of each side log50 + t*log2 = log 20 + t log3 solve for t log to any base, your calculator is your friend on this.
*Tuesday, May 19, 2009 at 6:25pm by bobpursley*

**Pre-Cal**

1) it is not correct. The second term would be log3(-2) and you can't take the log of a negative number. 2) it is not correct. The base angle would be 45 degrees, so the cotangent would be 1.
*Wednesday, March 10, 2010 at 5:14pm by FredR*

**pre-calculus**

solve the following logarithmic equation. Be sure to reject any value of x that is not in thedomain of the orginal logarithmic expression. Give the exact answer. log3(x+8)=4 The three actually drops down a little below the g. Can someone tell me how to do this?
*Saturday, October 6, 2012 at 2:05pm by ladybug*

**Algebra check**

Convert to exponential equations. 12.) m=log3 9 I have the answer as 3^m =9 13.) log2 64=6 I have the answer as 2^6 =64 Are these answers right?
*Monday, December 1, 2008 at 12:02am by Shawn*

**math**

e^2x + 1 = 74 e^2x = 73 2x = ln73 x = ln73/2 log3(x) = 4 x = 3^4 = 81
*Thursday, April 26, 2012 at 3:02am by Steve*

**Pre-Calc**

2logx-log4-log3+logx 3 log x - log 4 - log 3 log x^3 - log 4/3 log (x^3 / 4/3) log (3x^3/4) or log (3/4 x^3) not a tutor
*Monday, January 10, 2011 at 6:27pm by Anonymous*

**math**

a) corrrect b) 10^(-10log3) = 10^(log3^-10 = 3^-10 ...... using the property a^logak = k
*Sunday, April 7, 2013 at 10:13pm by Reiny*

**pre-calculus**

What is the domain and range of log3 (1-x)? I will be happy to critique your thinking. To assist you, consider log (-4) log (0) log 25 Those are to the base 10, changing to another base just changes the numbers, not the function.
*Saturday, January 13, 2007 at 12:45am by emma*

**math**

Find the value of each of the following. Leave your answers as fractions where appropriate. Do not change bases. a) log4 (1/8) B)10^(-10log3)<---superscript in brackets c.2log3<-----subscript.9 d.log3<---subscript.3^2x
*Thursday, March 15, 2012 at 6:15pm by james*

**maths**

how wod i solve the following two eqautions? either exactly or to 3 significant a)2^x = 5 b)3^x+1 = 7 i know a) is 2.32 and b) is 0.771 but i dont know how to show it out step by step in how i worked it out . can sum1 plz help me You have to use logs, and learn how to do that ...
*Tuesday, August 14, 2007 at 2:33pm by k*

**maths**

i will be greatful to you if you help in solving the below problems: 1.)Prove that log15=log5+log3 2.)Show that log10800=4log2+3log3+2log5 3.)show that log108/605=2log2+3log3-log5-2log11.
*Friday, April 27, 2012 at 10:52pm by srikar*

**Math(Please help)**

log3 (8x) = 4 by definition ... 8x = 3^4 8x = 81 x = 81/8
*Sunday, March 14, 2010 at 4:56pm by Reiny*

**RESPONSE**

hmmm how did you go from this a(log3+logn)=b(log4+logn) to this? logn(a-b)=blog4-alog3 logn=( )/(a-b)
*Monday, April 26, 2010 at 8:08pm by RESPONSE*

**algebra**

Rewrite the following as an equivalent logarithmic equation.Do not solve. y^t = x answer logy+logt=logx-is this right also Express as an equivalent expression that is a sum of logt (3ab) the t is at the bottom of the g answer log3+loga+logb logarithms.
*Wednesday, May 5, 2010 at 2:13am by dani*

**Algebra 1**

by definition log3(x - 1) = 4 is 3^4 = x-1 x= 82 for the second, (I will assume you meant log3(x - 1) = log34 ) anti-log it x-1 = 4 x = 5
*Tuesday, February 8, 2011 at 8:50am by Reiny*

**calculus**

log3 3^11 = 11log3 3 = 11*1 = 11
*Sunday, April 20, 2008 at 4:33am by Reiny*

**maths**

since 9=3^2, log3 = 2*log9 and we have, using base 9 logs, 2log(2-3x) = log(6x^2-19x+2) (2-3x)^2 = 6x^2 - 19x + 2 3x^2 + 7x + 2 = 0 (3x+1)(x+2) = 0 x = -2 or -1/3
*Tuesday, October 8, 2013 at 7:33pm by Steve*

**Math**

Let log 2 = a, log 3 = b and log 7 = c. Express the indicated logarithm in terms of a, b, and c. 1-log3 5 (3 is the subscript of the log) ans:(1-a)/b, i need someone to show me the step bcus my ans is different from the given ans. my ans=(1/a)-b.
*Thursday, March 28, 2013 at 8:33pm by ifi*

**math- precalculus**

9^(-x)=1/3 (3^2)^(-x) = 3^-1 3^(-2x) = 3^-1 so -2x = -1 x = 1/2 2^(2x)+ 2^(x) -12 = 0 (2^x)^2 + 2^x - 12 = 0 let y = 2^x y^2 + y - 12 = 0 (y+4)(y-3) = 0 y = -4 or y = 3 2^x = -4, no solution , or 2^x = 3 --- x = log3/log2
*Monday, December 1, 2008 at 8:27pm by Reiny*

**Math**

2logx-log4-log3+logx = log (x^2) - log4 + logx = log( x^3/4)
*Monday, January 10, 2011 at 7:00pm by Reiny*

**Algebra**

Evaluate the logarithmic equation for three values of x that are greater than 2, three values of x that are between 1 and 2, and at x=2. Show your work. Use the resulting ordered pairs to plot the graph. State the equation of the line asymptotic to the graph. y = log3 (x - 1)
*Tuesday, June 15, 2010 at 7:21pm by Bobby*

**Algebra 2**

Express as a logarithm of a single number or expression: 1. 5log4^p+log4^q 2. log10^x-4 log10^y 3. 4log3^A-1/2 log3^B 4. log5^M+1/4 log5^N 5. log2^M+log2^N+3 6. log5^x-log5^y+2 7. 1-3 log5^x 8. (1+log9^x)/2 I need to see all of the steps. Thanks
*Thursday, May 12, 2011 at 5:35pm by Brandon*

Pages: <<Prev | 1 | **2** | 3 | Next>>