Wednesday

April 16, 2014

April 16, 2014

Number of results: 952

**integrate**

integrate du/3u and integrate x/x^2 dx it might be simple...i just need a head start...tnx
*Wednesday, October 8, 2008 at 6:38pm by allison*

**calculus**

1) Integrate Cos^n(x) dx 2) Integrate e^(ax)Sinbx dx 3) Integrate (5xCos3x) dx I Will be happy to critique your thinking on these. 1) Derive a recursive relation. 2) Simplest by replacing sin(bx) by Exp[i b x] and taking imaginary part at the end. 3) First integrate sin(yx) ...
*Friday, April 13, 2007 at 11:24am by Febby*

**Integral calculus**

Please do help solve the followings 1) Integrate e^4 dx 2) Integrate dx/sqrt(90^2-4x^2) 3) Integrate (e^x+x)^2(e^x+1) dx 4) Integrate xe^x2 dx e^4 is a constant. 3) let u= e^x + x du= (e^x + 1)dx 4) let u= x du=dx v= e^x dv= e^x dx
*Friday, April 13, 2007 at 9:09am by Febby-1*

**Calculus**

6.] Replace the integral in exercise 5 (int. (1/ 1 – t) dt a = 0, b = 1/2with ?1/(1+t) dt with a = 0, b = 1, and repeat the four steps. a. integrate using a graphing utility b. integrate exactly c. integrate by replacing the integrand with a Taylor series and integrate term by...
*Sunday, October 16, 2011 at 9:10am by Rajeev*

**Calc 1**

integrate from 0 to pi/4 (sec^2x)/((1+7tanx)^2)^1/3 integrate form pi^2/36 to pi^2/4 (cos(x^1/2))/(xsin(x^1/2))^1/2 integrate from 0 to pi/3 (tanx)/(2secx)^1/2
*Friday, November 30, 2012 at 2:34pm by Frank*

**calculus 2 **

Justify, with a written explanation or a mathematical reasoning and with a sketch of at least two different cases, the following properties of integrals: a) If f(x) is less than or equal to g(x) for a<=x<=b then integrate from a to b of f(x)dx is less than or equal to ...
*Wednesday, September 12, 2012 at 8:07am by bobby*

**plz integrate**

how do u integrate 1+u/3u+2u^2 please help me get started ...tnk u
*Wednesday, October 8, 2008 at 7:22pm by allison*

**PLZ integrate**

integrate cos^3x dx tnk U
*Wednesday, November 19, 2008 at 3:16pm by mary*

**Need help in math**

Integrate x+1 from -1 to 2, and integrate -x-1 from -3 to -1. Add the results. [x^2/2 +x]@2 - [x^2/2 +x]@-1 = 4 + 1/2 = 9/2 That's the first part. You finish it
*Sunday, December 19, 2010 at 7:11pm by drwls*

**Calculus**

How do you integrate [(x^2)(cos(2(x^3)))]? I tried to integrate by parts but I'm going in circles yet again...
*Friday, February 13, 2009 at 1:49am by Hannah*

**calculus**

wait...dont u have to integrate it from 0 to 21 or something?? n how would you integrate this equation?
*Saturday, January 5, 2013 at 1:22am by Anon*

**PLZ integrate**

wow thank u.... what about integrate -sinx*cos^(2)x dx is that 1/3cos^3x?? rigth?
*Wednesday, November 19, 2008 at 3:16pm by mary*

**calculus I**

I used wolframalpha.c o m and plugged integrate √(cotx)/sinx dx And it seems to integrate sorry, don't know how to.
*Monday, May 10, 2010 at 9:36pm by Do*

**Calculus AB**

Please help me integrate this equation using partial fractions: Integrate [(x^2+5)/(x^3-x^2+x+3)]dx. Thank you very much.
*Sunday, June 5, 2011 at 11:58pm by JAE92*

**maths**

integrate by parts integrate (4+x^2)^1/2
*Saturday, December 29, 2012 at 8:16am by laura*

**maths**

integrate by parts integrate (4+x^2)^1/2
*Saturday, December 29, 2012 at 12:34pm by Jess*

**MATHS...PLEASE HELP**

what do you get when you: integrate 10sin^4xcosx dx when you integrate 9x^2e^6x^3 dx
*Sunday, September 12, 2010 at 1:39pm by adil ahmed*

**ap calculus**

how did you integrate (1+√x)^2 ? I would suggest you expand it first to get 1 + 2√x + x when you integrate that you get x + (4/3)x^(3/2) + (1/2)x^2 so my arithmetic shows vol = pi(9 + (4/3)(27) + 81/2) = .....
*Tuesday, March 10, 2009 at 7:15pm by Reiny*

**Integral calculus**

Please can anyone help with the following problems - thanks. 1) Integrate X^4 e^x dx 2) Integrate Cos^5(x) dx 3) Integrate Cos^n(x) dx 4) Integrate e^(ax)Sinbx dx 5) Integrate 5xCos3x dx The standard way to solve most of these integrals is using partial integration. So, look ...
*Friday, April 13, 2007 at 9:05am by Febby*

**math**

Draw graph of y= x^(1/2) to help you understand solution. Rotation about y-axis means that the radius of the solid (length being swung around the axis is the x-value). it helps to solve for x-value rather than try to substitute everything. x=y^2 where y>0 each disk or x-...
*Saturday, September 1, 2012 at 7:31pm by Anu*

**why won't anybody help me**

a) Integrate [(1+y^2)^(1/2) - 5/3 y ] dy from y = 0 to y = 3/4. You can substitute y = sinh(t) to make the maths a bit easier. b) Looks trivial c) Integrate r dr dtheta from r = 0 to r(theta) and theta = the desired interval = Integral 1/2 r(heta)^2dtheta
*Sunday, March 2, 2008 at 8:29pm by Count Iblis*

**math, calculus 2 **

Consider the area between the graphs x+y=16 and x+4= (y^2). This area can be computed in two different ways using integrals. First of all it can be computed as a sum of two integrals integrate from a to b of f(x)dx + integrate from b to c of g(x)dx What is the value of a, b, c...
*Wednesday, September 12, 2012 at 8:03am by bobby*

**integrate**

how do i integrate 2u du /u-2+2u^2 so i used subsitution rule? or can i used integration by parts and how? thanks in adnvace
*Wednesday, October 8, 2008 at 6:15pm by allison*

**calculus help please**

dy/dx = 2y^2 Integrating...y=2/3 y^3 + C put 1,-1 into the equation, and solve for C. Then find the y for x=2 if y= a^uhttp://math2.org/math/integrals/tableof.htm see exponential functions. dy/dx=2y^2 and if y=-1 when x=1, then when x=2, y=? how do i get x in the equation. do ...
*Sunday, December 10, 2006 at 5:58pm by bobpursley*

**CALCULUS WXMAXIMA !!PLEASE!**

the log and exp curves intersect at x=0.919387 above them, the atan curve intersects exp at x=0.363949 log at x=2.02510 so, break the integral into two intervals, [.363949,.919387] and [.919387,2.02510] the first interval integrate atan-exp, the second integrate atan-log How ...
*Wednesday, March 7, 2012 at 4:39pm by Steve*

**Calculus AB**

I had to integrate [(x^2+1)/(x^2-x)]dx with partial fractions. My answer was 2ln abs(x-1) -ln abs(x)+C. But the answer on the answer sheet has an extra +x that I did not account for. Is that a typo or did I integrate incorrectly?
*Monday, June 6, 2011 at 2:28am by JAE92*

**calcus**

Sketch the regions enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle and label its height and width. integrate with either respect to x or y, then find area S of the region given that y=sqrt(x), y=x/2, and ...
*Thursday, October 21, 2010 at 12:56am by helpplease*

**Calculus**

Sketch the regions enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle and label its height and width. integrate with either respect to x or y, then find area S of the region given that y=sqrt(x), y=x/2, and ...
*Thursday, October 21, 2010 at 12:57am by saywhat*

**calculus**

1) Integrate (e^x+x)^2(e^x+1) dx 2) Integrate xe^x2 dx Let u=(e^x+x) du=(e^x +1) dx I will be happy to critique your work or thinking. You are posting work for me to do, and I am not inclined to do that, it will not help you for me to do it. I think I gave you strong hints on ...
*Friday, April 13, 2007 at 11:22am by Febby*

**calculus**

Integrate sqrt(x^2 + 1) dx over [0,2*pi] I can substitute u=arctan x to get: Integrate (sec u)^3 du over [0,arctan(2*pi)] From there, I'm stuck. (thanks Count Iblis for your last help)
*Friday, July 6, 2012 at 9:46am by Parker*

**math**

Find the area bounded by the parabola y^2=4x and the line y=2x-4. Use vertical representative rectangles (integrate with respect to x) and horizontal representative rectangles (integrate with respect to y). the answer is 9 square units ... i just need to know how to get to that.
*Wednesday, December 15, 2010 at 4:51pm by ashton*

**Physics- Mechanics**

r(t) = x(t) i + y(t) j r(0) = 0 i + 4 j r' = x' i + y' j r'(0) = 92 i + 0 j r'' = x" i + y" j = -2 i - 2 j always integrate acceleration velocity = r' = [-2 t + x'(0) ] i +[-2 t + y'(0)] j = [ -2 t +92 ] i - 2 t j integrate velocity r = [-t^2 +92 t ] i +[-t^2 +4 ] j when is -t...
*Friday, September 17, 2010 at 3:27pm by Damon*

**College Calc 1**

Find the area bounded by the parabola y^2=4x and the line y=2x-4. Use vertical representative rectangles (integrate with respect to x) and horizontal representative rectangles (integrate with respect to y). the answer is 9 square units ... i just need to know how to get to that.
*Wednesday, December 15, 2010 at 3:20pm by Ashton*

**Calc**

Calculate the area bounded by the x-axis and the function f(x)= -(x-a)(x-b), where a<b and a and b are constants. Please do it out in steps so I can understand it, and try to simplify the final answer and leave it in factored form. Frankly, I would multiply out the ...
*Monday, November 27, 2006 at 6:15pm by Tezuka*

**math**

First define the x limits of the enclosed region. They are between the two roots of x^2 -6x +10 = x x^2 -7x +10 = 0 (x - 5)(x -2)= 0 You want to integrate between x = 2 and 5. The function that you integrate is f(x) = pi*{-[x^2 -6x +10]^2 + x^2} dx. The y = x curve lies above ...
*Wednesday, April 6, 2011 at 11:45am by drwls*

**calculus**

The region bounded by the two curves is between x = -1 and x = +1. Plot the two curves and you will see why. 1) Integrate (x^2 - x^4)dx from x = -1 to x = 1 2) Integrate pi*y1^2 - pi*y2^2 dx = pi*(x^4 - x^8)dx from x = -1 to x = 1. y1(x) = x^2 y2(x) = x^4 3) Integrate pi[(1 - ...
*Thursday, June 9, 2011 at 8:46pm by drwls*

**math**

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. 2y=5x , y=3 and 2y+1x=6 It is easier to integrate with respect to the variable Area = Help!!!!
*Saturday, January 25, 2014 at 4:42am by kitor*

**Matimaticaaaaas Help?**

First multiply the two terms. Then integrate the terms 3 x^3 and -x^2 separately, and add the results. Use the rule that the indefinite integral of a*x^n is [a/(n+1)]*x^(n+1), where a is any constant. The first term will be (3/4)*x^4. Now integrate -x^2 for the other term. An ...
*Wednesday, May 14, 2008 at 9:43pm by drwls*

**calculus**

You wrote << f(0)=4 and f(0)=3,>> but both cannot be true. One of the f(x) functions must be the derivative, f'(x). Which is it? Anyway, all you have to do is integrate your f''(x) once and use the value of f'(x) at x=0 to get the first cosntant, and then integrate...
*Tuesday, March 10, 2009 at 5:11pm by drwls*

**physics**

You know the formula for E from any segment dL (dL contains dq). You have to integrate around the semicircle to get E. Actually, it is easy as a vector, because you use arguments of symettry to just integrate the components of E directed along the axis of symettry, as the E ...
*Wednesday, February 20, 2008 at 3:04am by bobpursley*

**Calculus**

First, I think Reiny dropped a factor of 1/2 in his integral (-x/2, not -x), but that's not a big worry (except that the answer is wrong!) :-) To integrate x√(1-x^2), substitute u=1-x^2 Then you have du = 2x dx x√(1-x^2) = √u du/2 = 1/2 u^(1/2) du integrate ...
*Tuesday, September 11, 2012 at 1:00pm by Steve*

**Calc**

Problems, once again. 1. Compute the average value of: f(x} = x/(x+3) over the interval [-a,a] 2. Find the area of the region bounded by the graph of: y = 2√(x^2 + 1) X axis Y axis Line x = 1 On the first, integrate, then divide the integral by 2a. On the second, ...
*Saturday, March 17, 2007 at 6:18pm by Tezuka*

**Math**

dz =(−sinx + 2xy^2)dx +(2x^2 y)dy Integrate the differential to find the function z. Would I say that z was equal to two separate differentials and integrate the first part of the function with respect to x and the second part with respect to y? z = cosx + x^2 y^2 + x^2 ...
*Sunday, May 17, 2009 at 9:52am by Clare*

**calculus**

for (6x+7)/(x^(2)-8x+25) the denominator does not have rational factors, so complete squares to get into the form (x^2+a^2) and integrate using atan. Hints: 1. x^2-8x+25=(x-4)^2+3^2 2. you will need to split the expression into partial fractions, one of which will integrate ...
*Tuesday, November 29, 2011 at 8:22am by MathMate*

**Calculus**

You can separate the variables and integrate. dy/dx = xy dy/y = xdx Integrate to get log(y)+c = x²/2 (C=constant) elog(y)+c = ex^2/2 ecy = ex^2/2 y = kex^2/2 where k=e-c Now you can plot a family of curves for the solution y=f(x).
*Tuesday, October 13, 2009 at 1:43am by MathMate*

**Calculus **

integrate x/(x^4+x^2+1) | = integrate symbol u = x^2 du = 2x dx 1/2 du = x dx 1/2 | du/(u^2 + u + 1) Complete the square u^2 + u = -1 u^2 + u + 1/4 = -1 + 1/4 (u + 1/2)^2 + 3/4 1/2 | du/((u + 1/2)^2 + 3/4) w = u + 1/2 dw = du 1/2 | dw/(w^2 + 3/4) 1/2 | dw/(3/4 + w^2) And, ...
*Saturday, January 22, 2011 at 8:11pm by helper*

**Physics**

Use symettry as you integrate across. Starting from one side, all you want to add is the horizontal component (the vertical component will be oposite direction when you get to the other side). So integrate the cosine/sine Theta part of the angle only (theta equals an angle ...
*Friday, April 4, 2014 at 7:27pm by bobpursley*

**Calculus**

all three of us had chosen let dv = e^(2t)dt or dv/dt = e^(2t) wouldn't you have to integrate that to get v ? v = (1/2)e^(2t) I hope you recognized that we used a method called integration by parts in choosing the "u" and "dv" let u be something that you can differentiate, and...
*Monday, February 16, 2009 at 7:51pm by Reiny*

**AP Calculus**

well, from t = 0 to t = 3 sin(pi t/3 ) is positive and from t = 3 to t = 4, sin (pi t/3) is negative but the distance is still a positive quantity even if movingbackwards so integrate from t = 0 to t = 3 sin(pi t/3)dt then integrate from t = 3 to t = 4 sin (pi t/3) dt add the ...
*Wednesday, March 9, 2011 at 7:46am by Damon*

**Calculus**

integrate t*(t^2 - 1)^(1/3) dt over (0,3) I substitute u = t^2 - 1 du = 2t dt which leads to integrate (1/2) u^(1/3) du over(-1,8) = (3/8) * u^(4/3) over (-1/8) = 3/8 * [8^(4/3) - (-1)^(4/3)] I would guess that (-1)^(4/3) is +1, since the cube root of -1 is -1 and taking that...
*Saturday, February 5, 2011 at 12:34am by Sean*

**Physics**

Isn't this Amperes law? Assume all current is at the center, so distance for B is one radius. Another approximation is uniform current density, you integrate current density, another approximation is that all the current is one the skin, you have to integrate dB. But having ...
*Thursday, December 12, 2013 at 8:28am by bobpursley*

**Integration of exponents with absolute values**

I cannot for the life of me figure this out. Please help me. How do I integrate the function f(x) = 0.1 * e ^ (-0.2 * |x|) from neg. Infinity to pos. Infinity? I seem to only be able to get 0, but the answer is 1. I think it is the |x| that is throwing me off. Please Hlep! ...
*Wednesday, January 24, 2007 at 11:24pm by Tyler*

**Calculus**

I assume you have no trouble with the definition of the average value, easily found by using a) your textbook b) google Just integrate over the interval, then divide by the interval length. So, how do we integrate? Recall that d/dx (sec x) = sec x * tan x Look familiar? So, ...
*Wednesday, September 14, 2011 at 5:44pm by Steve*

**math**

I'll show you how to do one of them. i) For the x coordinate of the centroid, integrate (Integral of) x(x^2+1) dx from x=0 to x=1 = [x^4/4 +x^2/2]@x=1 - [x^4/4 -x^2/2]@x=0 = 1/4 + 1/2 = 3/4 For the y coordinate of the centroid, integrate (Integral of) (y/2)(x^2+1) dx from x=0 ...
*Monday, May 3, 2010 at 2:35am by drwls*

**Math**

The graph crosses the x-axis at (6,0) integrate 36-x^2 from -1:6 to get the positive area integrate -(36-x^2) from 6:13 to add the area below the axis instead of subtracting it ∫[-1,6](36-x^2) + ∫[6,13](x^2-36) = (36x - x^3/3)[-1:6] + (x^3/3 - 36x)[6,13] 539/3 + ...
*Thursday, June 14, 2012 at 12:10pm by Steve*

**math, calculus 2 **

Consider the function f(x)=-((x^2)/2)-9. In this problem you will calculate integrate from 0 to 3 of ((-x^2)/2)-9)dx by using the definition integrate from a to b of (f(x))dx= lim as n approaches infinity of sum_(i=1)^n of (f(x_i))(delta x) The summation inside the brackets is...
*Wednesday, August 29, 2012 at 7:36am by bobby*

**calculus ab**

s=int v(t) dt do the integral. b. Now net change: you have some positive displacement, and negative displcement. You can 1) find where the velocity changes sign, then integrate those portions separately (negative distance), then change the sign, and add abs values. 2) square ...
*Sunday, January 8, 2012 at 4:45pm by bobpursley*

**Calculus HELP plz**

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. 2y=4x^1/2,y=5,2y+1x=5 Do you really mean "2y+1x=5" ? It is not customary to use the coefficient 1 in front of a variable. It is unnecessary. ...
*Saturday, May 5, 2007 at 10:50pm by jimmy*

**calculus**

The local extrema correspond to zeroes of the derivative. That derivative is a wauadratic function. So, you should write down a quadratic function that has its zeroes at x = -2 and x = 1. Then integrate that function. This function is fixed up to an overall factor. Then you ...
*Tuesday, April 7, 2009 at 10:01am by Count Iblis*

**integral**

here, click on "show steps" http://www.wolframalpha.com/input/?i=integrate+e^x^%281%2F3%29
*Sunday, July 31, 2011 at 3:24pm by Damon*

**calculus-integration**

integrate -2/xln^4(x)...plz help me..give me an idea on how to start..plz The derivative of the ln(x) function is 1/x and this is multiplying the ln^4(x). You can thus write the integral as: -2 * 1/5 ln^5(x) + constant. is that the answer? wut about the x infront of ln^(x)......
*Monday, May 7, 2007 at 1:03pm by Maria*

**Calculus**

For the total displacement during that interval, Integrate the velocity function vs time, for -1 < t < 5 s. Note that v starts out negative at t = -1, and then becomes 0 at t = 2 and 4 s. Those are "turnaround times". To get the distance travelled (in either direction), ...
*Friday, December 11, 2009 at 4:26am by drwls*

**Integrating Factors**

I've been working on this hw problem for a while now, but I'm stuck in the integration process. I'm pretty sure I made an error, cause I can't seem to be able to integrate the right side of the equation. Q: (1/(x^(2)+1))y' + xy = 3 using the equation d/dx(ry)=f(x)r(x) I found ...
*Monday, January 20, 2014 at 2:19am by Student*

**Calculus**

y = 2/x (The is the integrand). The derivative is -2/x^2 When calculating the length of a line, you have to integrate sqrt[1 + (dy/dx)^2], which in this case is sqrt[1 + 4/x^4]. That function is the integrand. Your last step is wrong. The line length from a to b is the ...
*Friday, March 13, 2009 at 12:01am by drwls*

**Calculus**

First you need to integrate y"(x). This looks like a situation where "integration by parts" can be used. Let u(v) = x and dv = e^-2x dx du = dx v = (-1/2)*e^-2x Integral of u dv = uv - integral of v du = (-x/2)e(-2x) + Integral of(1/2)*e^-2x dx Finish that off and use the y'(0...
*Thursday, May 15, 2008 at 7:55pm by drwls*

**Math Integration**

Integrate: f (x)/(2x + 1) dx let f represent integrate sign let u = x, du = dx => dx = du = f (u)/(2u + 1) du = f u (2u + 1)^(-1) du = (1/2)u^2 (ln|2u + 1|) + c = (1/2)x^2 (ln|2x + 1|) + c ...what did I do wrong? The correct answer is (1/2)x - (1/4)ln|2x + 1| + c
*Wednesday, February 11, 2009 at 4:40pm by Anonymous*

**math**

We have to integrate sqrt[1+y'2] from 0 to pi/4 1+y'^2 = 1+tan^2(x) = 1/cos^2(x) So, the arc length is: Integral from 0 to pi/4 of 1/cos(x) = Integral from pi/4 to p1/2 of 1/sin(x) We can write: 1/sin(x) = 1/[2sin(1/2 x) cos(1/2 x)] = [sin^2(1/2x) + cos^2(1/2x)] /[2sin(1/2 x) ...
*Monday, December 3, 2007 at 4:25pm by Count Iblis*

**CALC URGENT**

There are two regions between the curves, from (0,0) to (2 sqrt 2, sqrt 2) and the same in the third quadrant, So do the integral in quadrant 1 and double. We could do little vertical cylinders and integrate over x or horizontal rings and integrate over y. For the rings; ...
*Thursday, February 5, 2009 at 4:35am by Damon*

**Calculus**

Calc length of arc of y=ln(x) from x=1 to x=2 ---- So far: Definite Integral over x=(1,2) of sqrt(1 + 1/x) dx 1/x = tan^2 t x = 1/tan^2 t sqrt(1+1/x) = sqrt(1+tan^2 t) = sec t dx = -2 * tan^-3 t * sec^2 t dt Integrate over x=(1,2): sec^3 t / tan^3 t dt Integrate over x=(1,2): ...
*Wednesday, January 2, 2008 at 12:43am by mathstudent*

**Calculus**

Since we are considering negative areas, all we have to do is simple integration from 0 to a, without worrying about absolute value, etc. So, the question is just how to integrate x^2 cos(x/4). The answer is: use integration by parts. Huh? How's that work? Remember the product...
*Wednesday, September 14, 2011 at 9:16pm by Steve*

**Calculus**

Draw the three curves y1 = 4, y2 = -3/2 x +3 and y3 = (3/2)x^1/2 on the same graph to see what kind of a region you are dealing with. The top border of the region is the horizontal y = 4 line extending from x = -2/3 to x = 64/9 There are two other bordering lines. One is a ...
*Tuesday, July 10, 2012 at 3:37am by drwls*

**physics (mechanics)**

Practice problem: A rocket sled for testing equipment under large accelerations starts at rest and accelerates according to the expression: a= (2.8 m/s^3)t + (3.9 m/s^2) How far does the rocket move in the time interval t=0 to t=0.81 s? This is just a practice problem to help ...
*Saturday, August 28, 2010 at 6:11pm by John*

**calculus**

how do you integrate x^2/(9+x^6)
*Tuesday, February 12, 2008 at 11:21pm by sarah*

**calculus**

how do you integrate x^2/(9+x^6)
*Tuesday, February 12, 2008 at 11:32pm by sarah*

**physics**

How would you integrate them?
*Sunday, September 13, 2009 at 6:18pm by How do you do this?*

**physics**

How would you integrate them?
*Sunday, September 13, 2009 at 6:18pm by How do you do this?*

**calc**

Integrate 2(x^2)e^g(x) where g(x)=4^(x^3)
*Wednesday, May 1, 2013 at 10:36pm by Sunny*

**math**

how do you integrate 3-e^1?
*Saturday, February 8, 2014 at 5:32pm by Hannah*

**Calculus**

Integrate each of the three terms separately, using what you call the "power integration formula", and add up the results. The formula you are probably refering to is: Integral of (a*x^n) = a*n*x^(n+1)/(n+1) where a is the constant coefficient and n is the constant exponent. 1...
*Sunday, May 22, 2011 at 10:22pm by drwls*

**Calculus**

Integrate: x/(9+x^4)dx
*Tuesday, January 22, 2013 at 6:26pm by Bella*

**Calculus**

integrate: (x^2 + 1)^k dx
*Tuesday, November 6, 2007 at 5:45pm by mathstudent*

**math**

integrate: (x^2 + 1)^k dx
*Wednesday, November 7, 2007 at 4:40pm by mathstudent*

**Calculus**

How do we integrate xlne^x .
*Tuesday, March 18, 2008 at 11:09pm by RJ*

**Calculus**

How do we integrate 1/lnx.
*Tuesday, March 18, 2008 at 11:43pm by RJ*

**math**

how do you integrate dx/(x^2*(x^2+4)^1/2)?
*Sunday, February 15, 2009 at 4:19pm by Lauren*

**calculus**

how do you integrate dx/(x^2*(x^2+4)^1/2)
*Monday, February 16, 2009 at 12:48pm by Lauren*

**calculus**

how do you integrate 30x^2/(x-2)(x+3)(x-5)
*Monday, February 16, 2009 at 12:49pm by Lauren*

**calculus**

how do you integrate 30x^2/(x-2)(x+3)(x-5)
*Tuesday, February 17, 2009 at 12:19am by Lauren*

**calculus**

integrate (2/3x^5)
*Thursday, January 28, 2010 at 11:35pm by Anonymous*

**Calculus**

From 2 to 3, integrate ((x^3)+5)dx/x.
*Friday, February 5, 2010 at 1:39am by <3*

**calculus**

How do I integrate 1-e^-kt from 0 to infinity?
*Tuesday, March 2, 2010 at 9:14pm by will*

**calculus**

How do I integrate [1/(x^2+1)] Thx
*Tuesday, January 25, 2011 at 7:03pm by Priscilla*

**Calc**

How do you integrate sin²x?
*Wednesday, February 2, 2011 at 12:37am by Erica*

**Calculus**

How would you integrate x^2/x^2+9 ?
*Thursday, May 26, 2011 at 8:21pm by Athene*

**calculus**

integrate 2/((2x-7)^2) from x=4 to 6
*Friday, June 24, 2011 at 11:15am by cyn*

**Calculus**

integrate: (x^2-3)sqrt (x+5)
*Wednesday, December 14, 2011 at 8:45pm by Ashley*

**Calculus**

Integrate tan^6(x)
*Sunday, January 8, 2012 at 5:56pm by Shayna*

**math**

Integrate x^2/rootx-1..
*Friday, October 5, 2012 at 12:30pm by abhi*

**maths**

integrate x^2/(x^4+a^4) dx
*Friday, December 21, 2012 at 7:55am by sapna*

**Calculus**

How do you integrate: 1/(x^2-1) dx ?
*Wednesday, January 9, 2013 at 7:48pm by Kyle*

Pages: **1** | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | Next>>