Wednesday

November 26, 2014

November 26, 2014

Number of results: 1,539

**calc asap!**

can you help me get started on this integral by parts? 4 S sqrt(t) ln(t) dt 1 please help! thanks! Integral t^(1/2)Ln(t)dt = 2/3 t^(3/2)Ln(t)- 2/3 Integral t^(1/2) dt = 2/3 t^(3/2)Ln(t) - 4/9 t^(3/2) Simpler method: Integral t^(a)dt = t^(a+1)/(a+1) Integral d/da [t^(a)]dt = d/...
*June 7, 2007 by Woof*

**calc**

how do you start this problem: integral of xe^(-2x) There are two ways: 1) Integration by parts. 2) Differentiation w.r.t. a suitably chosen parameter. Lets do 1) first. This is the "standard method", but it is often more tedious than 2) You first write the integral as: ...
*May 15, 2007 by walex*

**Calculus**

Find the volume of the solid whose base is the region in the xy-plane bounded by the given curves and whose cross-sections perpendicular to the x-axis are (a) squares, (b) semicircles, and (c) equilateral triangles. for y=x^2, x=0, and y=0 (a) integral (x^2)^2 from 0 to 2=32/5...
*December 15, 2007 by Anonymous*

**Integral**

That's the same as the integral of sin^2 x dx. Use integration by parts. Let sin x = u and sin x dx = dv v = -cos x du = cos x dx The integral is u v - integral of v du = -sinx cosx + integral of cos^2 dx which can be rewritten integral of sin^2 x = -sinx cos x + integral of (...
*February 20, 2007 by drwls*

**Calculus II/III**

A. Find the integral of the following function. Integral of (x√(x+1)) dx. B. Set up and evaluate the integral of (2√x) for the area of the surface generated by revolving the curve about the x-axis from 4 to 9. For part B of our question , the surface of revolution ...
*February 19, 2007 by Ryoma*

**Math/Calculus**

How would I solve the following integral with the substitution rule? Integral of: [(x^3)*(1-x^4)^5]dx Put 1-x^4 = y Then -4x^3 dx = dy Integral is then becomes: Integral of -1/4 y^5 dy ok, thanks a lot! I got it now.
*May 28, 2007 by COFFEE*

**Calculus II**

Integrate using integration by parts (integral) (5-x) e^3x u = 5-x du = -dx dv = e^3x v = 3e^3x I wonder if this is right so far. = uv - (integral) v du = (5-x)(3e^3x) - (integral) (-3e^3x) =(5-x)(3e^3x) + (integral) (3e^3x) = (5-x)(3e^3x) + 9e^3x + C
*December 30, 2012 by Katie*

**Calc 121**

How do you integrate using substitution: the integral from 1 to 3 of: ((3x^2)+(2))/((x^3)+(2x)) There is a trick to this one that grealy simplifies the integral. Let u = x^3 + 2x. Then du = (3x^2 + 2)dx The integral then bemoces just the integral of du/u, which is ln u = ln (x...
*April 21, 2007 by Me*

**Calculus**

integral -oo, oo [(2x)/(x^2+1)^2] dx (a) state why the integral is improper or involves improper integral *infinite limit of integration (b) determine whether the integral converges or diverges converges? (c) evaluate the integral if it converges I know f(x)=arctan->f'(x)=1...
*February 8, 2008 by Anonymous*

**calc**

find integral using table of integrals ) integral sin^4xdx this the formula i used integral sin^n xdx =-1/n sin^n-1xcosx +n-1/n integral sin^n-2 using the formula this is what i got: integral sin^4xdx=-1/4sin^3xcosx+3/4 integral sin^2xdx= -1/2sinxcosx+1/2 integral 1 dx can ...
*February 20, 2011 by tom*

**calculus**

8). Part 1 of 2: In the solid the base is a circle x^2+y^2=16 and the cross-section perpendicular to the y-axis is a square. Set up a definite integral expressing the volume of the solid. Answer choices: integral from -4 to 4 of 4(16-y^2)dy, integral from -4 to 4 of (16+y^2)dy...
*April 14, 2013 by Sally*

**calculus**

1. integral -oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta) d(theta) (a) state why the integral is improper or involves improper integral (b) determine whether the integral converges or diverges converges? (c) evaluate the integral if it converges CONFUSE: how would...
*February 10, 2008 by Anonymous*

**Calculus**

Use the symmetry of the graphs of the sine and cosine functions as an aid in evaluating each definite integral. (a) Integral of sinx*dx from -pi/4 to pi/4 (b) Integral of cosx*dx from -pi/4 to pi/4 (c) Integral of cosx*dx from -pi/2 to pi/2 (d) Integral of sinx*cosx*dx from -...
*November 15, 2009 by John*

**Math**

Find the integrals. (show steps) (integral sign) xe^(4x^2) I think this how is how its done: (integral sign) xe^(4x^2) it's a u du problem let u=4x^2 so, du=8x dx now you have an x already so all u need is 8 inside and and 1/8 outside the integral [1/8] (integral sign) [8]xe^(...
*December 11, 2006 by Jay*

**Integral Help**

I need to find the integral of (sin x)/ cos^3 x I let u= cos x, then got -du= sin x (Is this right correct?) I then rewrote the integral as the integral of -du/ u^3 and then rewrote that as the integral of - du(u^-3). For this part, I wasn't sure how to finish. I was hoping to...
*November 14, 2013 by Anonymous*

**double integral**

1. Sketch the region of integration & reverse the order of integration. Double integral y dydz... 1st (top=1, bottom =0)... 2nd(inner) integral (top=cos(piex), bottom=(x-2)... 2. Evaluate the integral by reversing the order of integration. double integral sqrt(2+x^3) dxdy... ...
*March 11, 2011 by Michelle*

**integration by parts**

s- integral s ln (2x+1)dx ? = ln(2x+1)x - s x d( ln (2x+1)) = ln(2x+1)x- s x [(2x+1)'/ (2x+1)] dx = ln(2x+1)x- s x [(2)/ (2x+1)] ?... then i'm confused... "ln(2x+1)x- s x [(2)/ (2x+1)] ?... then i'm confused..." x [(2)/ (2x+1)] = 2x/(2x+1) = (2x+1-1)/(2x+1) = 1-1/(2x+1) B.t.w...
*February 17, 2007 by nicholas*

**calculus **

LEt f and g be continous functions with the following properties i. g(x) = A-f(x) where A is a constant ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx iii. for the integral from 2 to 3 f(x)dx = -3A a find the integral from 1 to 3 of f(x)dx in terms of ...
*February 13, 2011 by Little*

**calculus **

LEt f and g be continous functions with the following properties i. g(x) = A-f(x) where A is a constant ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx iii. for the integral from 2 to 3 f(x)dx = -3A a find the integral from 1 to 3 of f(x)dx in terms of ...
*February 13, 2011 by alex *

**math**

LEt f and g be continous functions with the following properties i. g(x) = A-f(x) where A is a constant ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx iii. for the integral from 2 to 3 f(x)dx = -3A a find the integral from 1 to 3 of f(x)dx in terms of...
*February 14, 2011 by jimbo*

**Calc BC**

1. Find the indefinite integral. Indefinite integral tan^3(pix/7)sec^2(pix/7)dx 2. Find the indefinite integral by making the substitution x=3tan(theta). Indefinite integral x*sqrt(9+x^2)dx 3. Find the indefinite integral. Indefinite integral cos(x)sin^3(x)dx
*September 27, 2011 by Zooey*

**Integral calculus**

You have not proved to me that the Integral of lnsinx w.r.t.x from 0 to pi/2 is equal to:Integral of lnsinx w.r.t.x from 0 to pi/4 plus Integral of lncosx w.r.t.x from 0 to pi/4.
*June 13, 2012 by alsa*

**calculus**

consider the function f(x) = e^x(sinNx) on the interval [0,1] where N is a positive integer. a) Compute the integral from 0 to 1 of f(x). Evaluate this integral when N=5, N=10, and N=100. B) What happens to the graph and to the value of the integral as N-->infinity? Does ...
*February 23, 2010 by Lindsay*

**calculus**

consider the function f(x) = e^x(sinNx) on the interval [0,1] where N is a positive integer. a) Compute the integral from 0 to 1 of f(x). Evaluate this integral when N=5, N=10, and N=100. B) What happens to the graph and to the value of the integral as N-->infinity? Does ...
*February 23, 2010 by anonymous*

**Calc 2**

a. Integral (x^2)/(sqrt(1+(x^2))) Would I separate these two into 2 separate integrals? Like: Integral of x^2 and the other integral of 1/sqrt(1+(x^2)) b. Integral (x^7)/(ln(x^4))dx Do I use integration by parts for this? I put u= lnx du = 1/x dv = x^7 v = (x^8)/8 It doesn't ...
*May 3, 2014 by Bae*

**Math(Please check)**

evaluate the integral integral of 3 to 2 x/(x^2-2)^2 dx u=x^2-2 du=2x dx 1/2 du = x dx integral of 1/u^2 du -1/(x^2-2) Then I plug in 3 and 2 and subtract them form each other -1/(3^2-2) - (-1/(2^2-2) Is this correct?
*April 30, 2011 by Hannah*

**Calculus 2**

The question is: Evaluate the improper integral for a>0. The integral is: the integral from 0 to infinity, of e^(-y/a)dy Can anyone help me solve this? When I try I get 'a', which apparently is incorrect. Thank you!
*September 25, 2011 by Sara*

**math**

evaluate the double integral and reverse order of integration [(first integral 0 to 1)(second integral 9y to 9)e^(x^2)dx)dy
*May 9, 2010 by college*

**math**

Evaluate the following indefinite integral by using the given substitution to reduce the integral to standard form integral 2(2x+6)^5 dx, u=2x+6
*September 10, 2013 by vishal*

**Calculus**

Can someone look over my work and tell me if my steps look correct? I'm trying to correct some problems that looked wrong. Instructions: Find the total areas between the given curves. 1. x= (y^3) and x=(y^2) on the interval [0,1] (integral from 0 to 1 of) ((y^3)-(y^2))dy = (...
*September 10, 2009 by Jenna*

**Calculus**

Which of the following is a step in evaluating. (Integral) cos^2 5x dx A. (Integral) 1+cos10x/2 dx B. (Integral) 1-cos10x/2 dx C. (Integral) 1+cos10x/20 dx D. (Integral) 1-cos10x/20 dx
*August 4, 2012 by Cynthia*

**Calculus**

evaluate the integral or state that it diverges. Check if I did it correctly. integral 0,1 dr/r^.999 lim b->0+ integral b, 1 1000r^.001 =-1000
*February 8, 2008 by Anonymous*

**math**

Evaluate the following indefinite integral by using the given substitution to reduce the integral to standard form integral cos(9x) dx, u=9x
*September 10, 2013 by vishal*

**math**

How do I derive the secant reduction rule? Integral (sec x)^n dx = Integral (sec x)^(n-2) * (sec x)^2 dx = Integral ((tan x)^2 + 1)^(n/2-1) * (sec x)^2 dx Doing a substitution with: u = tax x du = (sec x)^2 dx = Integral (u^2 + 1)^(n/2-1) * du At this point I'm stuck. Any ...
*November 7, 2007 by mathstudent*

**Calculus - Integrals**

I have 3 questions, and I cannot find method that actually solves them. 1) Integral [(4s+4)/([s^2+1]*([S-1]^3))] 2) Integral [ 2*sqrt[(1+cosx)/2]] 3) Integral [ 20*(sec(x))^4 Thanks in advance.
*March 23, 2008 by David*

**Calculus - Integrals**

I have 3 questions, and I cannot find method that actually solves them. 1) Integral [(4s+4)/([s^2+1]*([S-1]^3))] 2) Integral [ 2*sqrt[(1+cosx)/2]] 3) Integral [ 20*(sec(x))^4 Thanks in advance.
*March 24, 2008 by David*

**calculus**

evaluate integral or state that it is diverges integral -oo, -2 [2/(x^2-1)] dx ----------------------------------- integral -oo, -2 [2/(x^2-1)] dx Through partial fractions, I came up with lim [ln(x-1)-ln(x+1)] b, -2 b->-oo I get (ln(3)-0)-(oo-oo)). The answer in the back ...
*February 11, 2008 by Anonymous*

**Calculus integral**

evaluate the integral: integral from -pi/4 to 0 for the function 6sec^3x dx. it has to be an exact answer and i did it and keep getting it wrong. I got 4sqrt(2)-4ln(-sqrt(2)+1)
*October 16, 2012 by kajri*

**calc check**

<<y=(1/A)*integral from a to b of: (1/2)[f(x)]^2 dx >> If that is the y value of the center of mass, I don't know why the factor (1/2) is there I also don't agree with your calculation of the x value, which should be 1/(ln 2). I agree with you that the area is ln 2...
*June 29, 2007 by drwls*

**Math**

Identify u and du for the integral. 1. The integral of [(cosx)/(sin^(2)x)]dx 2. The integral of sec2xtan2xdx
*November 30, 2010 by Jess*

**calc**

also: integral of tan^(-1)y dy how is integration of parts used in that? You write: arctan(y)dy = d[y arctan(y)] - y d[arctan(y)] Here we again have used the product rule: d(fg) = f dg + g df You then use that: d[arctan(y)] = 1/(1+y^2) dy So, the integral becomes: y arctan(y...
*May 23, 2007 by marsha*

**Calc**

Evaluate the integral using any method: (Integral)sec^3x/tanx dx I started it out and got secx(1tan^2x)/tanx. I know I just have to continue simplifying and finding the integral, but I'm stuck on the next couple of steps. Also, I have another question witht he same directions...
*October 1, 2012 by H*

**integral confusion**

integral of Sec[2x]Tan[2x] i know u is sec 2x du=2sec2xtan2x dx what would i have to multiply with du so it would equal tan 2x dx? if my question is confusing, then here's another example of what i'm talking about: integral of (3x-2)^30 dx u=3x-2 du=3 dx 1/3 du=dx (i need help...
*November 26, 2007 by julie*

**Math/Calculus**

How would I evaluate the following integral by using integration by parts? Integral of: (t^3)(e^x)? You mean (x^3)(e^x)? x^3 exp(x) dx = x^3 d[exp(x)] = d[x^3 exp(x)] - exp(x) d[x^3] = d[x^3 exp(x)] - 3 x^2 exp(x) dx So, if you integrate this you get x^3 exp(x) - 3 Integral of...
*May 28, 2007 by COFFEE*

**Calculus**

In the interval (0 is less than or equal to x which is less than or equal to 5), the graphs of y=cos(2x) and y=sin(3x) intersect four times. Let A, B, C, and D be the x-coordinates of these points so that 0<A<B<C<D<5. Which of the definite integrals below ...
*December 5, 2013 by Rasheda*

**Calc**

Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u substitution u = secx du = secxtanx dx (dx = ...
*May 30, 2012 by UCI Student*

**Calc**

Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u substitution u = secx du = secxtanx dx (dx = ...
*May 30, 2012 by ***UCI Student****

**intergrals**

find value of def integral with a=-2 and b=2sqrt(3) definite integral is : x^3 * sqrt(x^2+4) dx for integral i get 1/15 *((4+x^2)^(3/2)) (-8+3x^2) for value i get [1536- 64sqrt(2)]/15 but its' wrong. help please
*May 26, 2013 by Mikey*

**Calculus**

I need help with this integral. w= the integral from 0 to 5 24e^-6t cos(2t) dt. i found the the integration in the integral table. (e^ax/a^2 + b^2) (a cos bx + b sin bx) im having trouble finishing the problem from here.
*August 30, 2009 by Bobby Smith*

**definite integral**

Use the Riemann Sums corresponding to 5 inscribed rectangles of equal width to approximate the integral a= 1, b= 3, (1/x)dx this is all for definite integral i just know x1=1.4, x2=1.8, x3=2.2, x4=2.6, x5=3.0 how do i continue
*May 15, 2013 by Eric*

**Calculus: Integral**

I don't understand how to do this one integral problem that involves secant. I'm asked to find the integral of sec^4 (4x). I'm not really sure how to go about solving this problem.
*March 31, 2014 by Anonymous*

**math, calculus**

if f(1)=12 and f' is continuous, what is the value of f(4)? integral from 1 to 4 of f'(x)dx = 17 IF the integral of f'(x) dx from 1 to 4 is 17, as you say, then the function f(x), which is the integral with an arbitrary constant, changes by 17 from 1 to 4. Then the value of f(...
*November 27, 2006 by Nicole*

**Calculus**

Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if it is convergent or divergent). I know how to find the indefinite integral of csc(x) dx, but I do not know how to evaluate the improper integral.
*June 4, 2012 by Sam*

**Calculus Help Please Urgent!!!**

Prove that the integral on the interval [a,b] of x is equal (b^2-a^2)/2 integral a to be (x)dx = (b^2-a^2)/2 using the definition of a Definite Integral. This is the limit of a sum approach. show steps please!!! Thank you!!!
*April 30, 2014 by Anonymous*

**Calc II**

Perform long division on the integrand, write the proper fraction as a sum of partial fractions, and evaluate the integral: (integral of) 2y^4dy/y^3 - y^2 + y - 1 After long divison I get: (integral of)2ydy + 2(integral of)dy + (integral of) 2/y^3 - y^2 + y - 1 I keep getting ...
*December 6, 2009 by Jenna*

**calc II**

Express the integrals as the sum of partial fractions and evaluate the integral: (integral of) (x^2)dx/(x-1)(x^2 +2x+1) My work: The above integral is equal to x^2dx/(x+1)^2 (A/x-1) + (B/x+1) + (Cx+D)/(x+1)^2 = x^2 A(x+1)^2 + B(x-1)(x+1) + (Cx+d)(x-1) = x^2 Ax^2 + 2Ax + A + Bx...
*December 6, 2009 by Jenna*

**Calculus**

F(x) = cos(x) • the integral from 2 to x² + 1 of e^(u² +5)du Find F'(x). When i did this, i got: -2xsin(x)e^((x²+1)² + 5) But my teacher got: -sin(x) • the integral from x² + 1 of e^(u² +5)du + 2xcos(x)e^((x²+1)² + 5) Do you know why the integral is in his answer? I'm not sure...
*October 17, 2011 by Erica*

**Is this how you derive the formula for arc length?**

For a smal change in x, dx: ds² = dx² + dy² ds = sqrt [(dx² + dy²)] s = INTEGRAL of sqrt [(dx² + dy²)] s = INTEGRAL of sqrt [(dx² + dy² * dx²/dx²)] s = INTEGRAL of sqrt[(1 + dy² * 1/dx²)] dx s = INTEGRAL of sqrt[(1 + (dy/dx)²)] dx
*December 4, 2007 by Rob*

**Calculus II**

Evaluate using u-substitution: Integral of: 4x(tan(x^2))dx Integral of: (1/(sqrt(x)*x^(sqrt(x))))dx Integral of: (cos(lnx)/x)dx
*February 24, 2009 by RuggedChild*

**Calculus**

Evaluate the Integral 1. integral of (x^9+7x^6-1)/x^8 dx 2. integral of x^(1/3)*(42-x)^2 dx 3. integral of 9x+5/7x^3 dx
*July 25, 2010 by Mely*

**calculus **

Evaluate the Integral 1. integral of (x^9+7x^6-1)/x^8 dx 2. integral of x^(1/3)*(42-x)^2 dx 3. integral of 9x+5/7x^3 dx
*July 25, 2010 by Mely*

**calc 2**

Determine whether the integral converges or diverges. Find the value of the integral if it converges. The integral where b=2 and a=0 (x/x^2-1 dx).
*September 23, 2010 by Pete*

**Physics, Calculus(alot of stuff together)= HELP!!**

A rod extending between x=0 and x= 14.0cm has a uniform cross- sectional area A= 9.00cm^2. It is made from a continuously changing alloy of metals so that along it's length it's density changes steadily from 2.70g/cm^3 to 19.3g/cm^3. a) Identify the constants B and C required ...
*September 16, 2007 by ~christina~*

**calc: arc length**

find the exact length of this curve: y = ( x^3/6 ) + ( 1/2x ) 1/2 <or= x <or= 1 im looking over my notes, but i'm getting stuck. here's my work so far: A ( 1 , 2/3 ) B ( 1/2 , 49/48 ) y' = [1/6 (3x^2)] + [1/2 (-1x^-2)] y' = ( x^2 / 2 ) - ( x^-2 / 2 ) (y')^2 = [( x^2 / 2...
*June 11, 2007 by COFFEE*

**Math**

Calculate the integrals if they converge. 10.) Integral from 1 to infinity of X/4+X^2 dx 14.) integral from Pi/2 to Pi/4 of Sin X / sqrt cos x dx 22.) integral from 0 to 1 of ln x/x dx I'm having problems with working these out to figure out if they converge or not. Any help ...
*April 21, 2008 by Jessica*

**math**

Note: You can get full credit for this problem by just answering the last question correctly. The initial questions are meant as hints towards the final answer and also allow you the opportunity to get partial credit. Consider the definite integral from pi/6 to pi/2 cos(z)/...
*January 25, 2014 by kitor*

**Calculus**

I don't know if I did these problems correctly. Can you check them? Use Integration by parts to solve problems. integral x^3(lnx)dx u=lnx dv=x^3dx du=1/x v=x^4/4 Answer:(x^3)(lnx)-(x^4/16) integral xcosxdx x cosx 1 sinx 0 -cosx Answer: xcosx+cosx integral e^2x(sinx)dx u=e^2x ...
*November 18, 2007 by Anonymous*

**math **

Sorry I posted this question earlier with a error. Can anyone help me solve this now? Can someone help me answer this? If a < 5 the define integral [a, 4] 2.4e^(1.4x)dx = 44 Find the value a Define integral = integral sign a = lower limit 5 = upper limit
*May 19, 2013 by mark *

**Calc**

If we know that the definite integral from -6 to -3 of f(x) equals 6, the definite integral from -6 to -5 equals 2 and the definite integral from -4 to -3 equals 4 then: What is the definite integral from -5 to -4? I know that this is zero. But then what can we say about the ...
*September 27, 2013 by Anonymous*

**math**

Generalize this to fine a formula for the integral: sin(ax)cos(bx)dx Could someone tell me what they got for an answer so I can check it to see if my answer is right. My answer: -1/2sinasinbx^2-1/3acosaxcosbx^3+ integral 1/3 a^2cosbx^3sinax..I'm not sure hot to find the ...
*February 25, 2008 by Jessica*

**calculus**

how do you determine the convergence of : definite integral from 1--> infinity of lnx/(x^3)? i set the problem as lim (R--->infinity) of the integral of lnx/(x^3) from 1--->R, but i can't compute the integral.
*March 16, 2008 by mika*

**Math**

1. Evaluate the indefinite integral integral symbol[6x5+2sec(x) tan(x)]dx. 2. Integral symbol 8 at the top, 5 at the bottom 3x2+3x2 dx = Thanks
*September 19, 2011 by Sara*

**math **

Can someone help me answer this? If a < 5 the define integral [a, 4] 2.4e^(1.4x)dx = 44 Find the value a Define integral = integral sign a = lower limit 4 = upper limit
*May 19, 2013 by mark *

**please help me calc. have test tom**

d/dx integral from o to x of function cos(2*pi*x) du is first i do the integral and i find the derivative right. by the fundamental theorem of calculus, if there is an integral from o to x, don't i just plug the x in the function. the integral of the problem is cos*2*pi*) is ...
*December 13, 2006 by david*

**Integral question**

1) find the integral from 1to -1 if(5sinx-2tanx+3x^5)dx 2) find the integral of x^3/(x^4+1)dx
*June 26, 2014 by Sarah*

**calculus**

how do you solve the integral of 1/[(square root of x)(lnx)] from 2 to infinity? i did the p- integral theorem with 1/square root of x and got it to be a divergent integral. however i was told this was the wrong way and that i should do it by integration by parts. but i can't ...
*August 25, 2009 by kathryn*

**Calculus**

Use the shell method to set up, but do not evaluate, an integral representing the volume of the solid generated by revolving the region bounded by the graphs of y=x^2 and y=4x-x^2 about the line x=6. I had the shell radius as (6-x) and the shell height as (4x-2x^2). My final ...
*March 7, 2011 by Ryan*

**Integral calculus**

Is it the integral of lnsinx w.r.t x from 0 to pi/2 = integral lnsinx w.r.t x from 0 to pi/4 + integral lncosx w.r.t x from 0 to pi/4 ?
*June 13, 2012 by alsa*

**calc 3**

1. Evaluate the given integral by making an appropriate change of variables, where R is the region in the first quadrant bounded by the ellipse 36x^2+25y^2=1. L= double integral R (4sin(144x^2+100y^2) dA. 2. Use the given transformation to evaluate the given integral, where R ...
*November 4, 2014 by lala*

**Calculus**

Find the exact coordinates of the centroid. y = sqrt[x], y = 0, x = 9. -------------- Is this basically 1/4 of an oval/ellipse? If so then the area would be: pi*9*3, correct? So the X coordinate would equal: 1/Area * Integral from 0 to 9 of (x*f(x))*dx Which equals: (4/(27*pi...
*June 17, 2007 by COFFEE*

**calc**

d/dx integral from o to x of function cos(2*pi*x) du is first i do the integral and i find the derivative right. by the fundamental theorem of calculus, if there is an integral from o to x, don't i just plug the x in the function. the integral of the problem is cos*2*pi*) is ...
*December 12, 2006 by david*

**calculus**

There are four integrals: 1) definite integral x/(1+x^4)dx b/w 0_infinity 2) definite integral (x^2)/(1+x^4)dx b/w 0_infinity 3) definite integral (x^3)/(1+x^4)dx b/w 0_infinity 4) definite integral (x^4)/(1+x^4)dx b/w 0_infinity Which of these integrals converge. First of all...
*March 3, 2010 by Carmen*

**calculus**

There are four integrals: 1) definite integral x/(1+x^4)dx b/w 0_infinity 2) definite integral (x^2)/(1+x^4)dx b/w 0_infinity 3) definite integral (x^3)/(1+x^4)dx b/w 0_infinity 4) definite integral (x^4)/(1+x^4)dx b/w 0_infinity Which of these integrals converge. First of all...
*March 4, 2010 by Carmen*

**Calc**

Recall that the acceleration a(t) of a particle moving along a straight line is the instantaneous rate of change of the velocity v(t); that is, a(t) = d/dt v(t) Assume that a(t) = 32 ft/s². Express the cumulative change in velocity during the interval [0, t] as a definite ...
*October 10, 2011 by Erica*

**Integral calculus**

Is Integral of f(x) w.r.t.x from 0 to a;equal to Integral of f(x-a) w.r.t.x from 0 to a?
*June 16, 2012 by alsa*

**calculus (integral)**

evaluate the integral: integral of 13/(x^3 - 27) dx
*September 13, 2013 by Anonymous*

**Calculus**

This is a definite integral question. Evaluate the following integral: (0)S(a)((x)((a^2 - x^2)^(1/2)))dx with a being a constant and the (0) being at the bottom of the integral notation and (a) at the top. S is the integral notation. I firstly checked whether the function was ...
*November 15, 2014 by Joshua*

**Calculus - Center of Mass**

Find the exact coordinates of the centroid given the curves: y = 1/x, y = 0, x = 1, x = 2. X = 1/Area*Integral from a to b: x*f(x)dx Y = 1/Area*Integral from a to b: [(1/2)*(f(x))^2]dx How do I find the area for this? Once I know that, is this the correct set up? X = 1/Area*...
*June 26, 2007 by COFFEE*

**calc check: curve length**

Find the length of the curve y=(1/(x^2)) from ( 1, 1 ) to ( 2, 1/4 ) [set up the problem only, don't integrate/evaluate] this is what i did.. let me know asap if i did it right.. y = (1/(x^2)) dy/dx = (-2/(x^3)) L = integral from a to b for: sqrt(1+(dy/dx)^2)dx L = integral ...
*July 2, 2007 by COFFEE*

**Calculus**

Hello, I have some calculus homework that I can't seem to get started..at least not on the right track? I have 3 questions 1. integral of [(p^5)*(lnp)dp] I'm using the uv-integral v du formula So first, I'm finding u and I think it's lnp.......so du is 1/p Then, I think dv = p...
*January 23, 2007 by Shelley*

**Calculus**

Hello, I'm having trouble with this exercise. Can you help me? Integral of (x* (csc x)^2)dx I'm using the uv - integral v du formula. I tried with u= (csc x)^2 and used some trigonometric formulas, but the expression became too complicated, I couldn't continue working. Then I ...
*March 15, 2007 by Maria*

**trig integration**

s- integral endpoints are 0 and pi/2 i need to find the integral of sin^2 (2x) dx. i know that the answer is pi/4, but im not sure how to get to it. i know: s sin^2(2x)dx= 1/2 [1-cos (4x)] dx, but then i'm confused. The indefinite integral of (1/2) [1-cos (4x)] is (x/2) - (1/2...
*February 18, 2007 by christine*

**Math/Calculus**

How would I integrate the following by parts: Integral of: (x^2)(sin (ax))dx, where a is any constant. Just like you did x^2 exp(x) below. Also partial integration is not the easiest way to do this integral. You can also use this method. Evaluate first: integral of sin(ax)dx...
*May 28, 2007 by COFFEE*

**calculus**

h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du= ? -> using u=1/x, we can write h(x)= integral from (1, 1/x) arctan (2t)dt as h(u)= integral from (1,u) arctan(2t)dt and h'(u)= arctan (2) Part 2: By the chain Rule, for functions h(u) and u(x), we have: -&...
*July 14, 2011 by Anonymous*

**calculus**

h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du= ? -> using u=1/x, we can write h(x)= integral from (1, 1/x) arctan (2t)dt as h(u)= integral from (1,u) arctan(2t)dt and h'(u)= arctan (2) Part 2: By the chain Rule, for functions h(u) and u(x), we have...
*July 14, 2011 by Anonymous*

**Calculus**

Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if it is convergent or divergent). I know how to find the indefinite integral of csc(x) dx, but I do not know how to evaluate the improper integral, at the following particular step. I know I need to take the ...
*June 5, 2012 by Sam*

**Calc 2, Series/Sequences**

Explain clearly in detail the difference of the summation of n=1 to infinity of 1/n^2; and the integral of 1/x^2dx with the limit of 1 to infinity, as well. Part 2: Explain the natures of the two expressions and explain why the summation is greater than the integral test. The ...
*April 1, 2010 by Alex*

**PLEASE HELP!**

Let integral f(x)dx=9 from -6 to -1.5 integral f(x)dx=7 from -6 to -4.5 integral f(x)dx=4 from -3 to -1.5 A. Find integral f(x)dx from -4.5 to -3 B. Find integral (9f(x)-7)dx from from -4.5 to -3
*April 19, 2014 by Jay*

**calculus**

evaluate the following integrals by any means possible: b. integral from -1 to 1 (w/ (w^2+1)) (dw) c. integral from -3 to 0 sqrt(9-x^2)dx
*July 3, 2009 by Dora*

**math**

integral x/(x+5)^1/2 (u-5)/u^1/2 du giving u^1/2 du -5u^-1/2 du and integral will be now 2/3 u^3/2 -10u^1/2 +c =2/3(x+5)^3/2 -10(x+5)^1/2 +c =2/3(x+5)^1/2{(x+5) -30} +c =2/3(x+5)^1/2{(x -25} +c have i done something wrong??
*November 19, 2009 by atif*

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