Number of results: 13,004
how many grams of CaCl2 must be dissolved to make 2.15 L of 0.05020 M Cl
Tuesday, December 14, 2010 at 11:20pm by Julia
Chemistry!! Please Help
How many grams of chloride are present in 1.00 liter of a 1.5 M solution of CaCl2?
Thursday, December 16, 2010 at 1:29pm by margrav2
You need to know the grams (or moles) of CaCl2 needed to produce a change of x joules.
Monday, March 7, 2011 at 8:47am by DrBob222
First, calcium chloride is CaCl2. Second, 0.500 g is not very much H2O to be using to prepare any kine of solution. Check your problem and your post. You want 1.5 m solution. The definition is m = mols/kg solvent 1.5m=moles/kg. I don't know if that is 0.5 grams or 0.5 kg. You ...
Wednesday, March 24, 2010 at 10:46pm by DrBob222
Calculate the concentration in ppm if 8 grams of CaCl2 is dissolved in 250 ml of water.
Wednesday, February 22, 2012 at 1:48am by Emmee
How do you sole this problem: how many grams of CaCl2 are needed to prepare 7.25 L of .015M solution?
Friday, March 15, 2013 at 1:30pm by Brittany jones
OMG! HELP! 1. How many grams of CaCl2 would be required to produce a 3.5 M (molar) solution with a volume of 2.0 L?
Saturday, August 17, 2013 at 5:03pm by Victoria
How many moles of CaCl2 are produced when this reaction is started with 4.70 grams of chlorine gas?
Tuesday, November 19, 2013 at 9:41pm by Elizabeth
No. The dilution formula is c1v1 = c2v2 where c = concn v = volume 8*v1 = 0.750*175 Solve for v1 = approximately 16 mL. 3CaCl2 + 2Na3PO4 ==> Ca3(PO4)2 + 6NaCl mols CaCl2 = grams/molar mass = estimated 0.002 mols Na3PO4 = M x L = estimated 0.0012. Now convert mols Na3PO4 and...
Sunday, July 14, 2013 at 1:35pm by DrBob222
If 33.6 grams of KCl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass? AND if 2.1 moles of CaCl2 are dissolved in enough water to make a .92 liter solution what is the resulting molarity? Please help and explain or anything?!
Tuesday, March 27, 2012 at 7:05pm by Dr. David
1.Calculate the Theoretical and % Yields of the following equation: 2.What is the limiting and excess reactant? 3.How much excess remains? 2AgNO3 + CaCl2 -> 2AgCl + Ca(NO3)2 mass of 2AgNO3= 1.5g mass of CaCl2= 1.1g (What I have so far): AgNO3: 1.5g(AgNO3) 2mol/170g = 0....
Thursday, January 19, 2012 at 12:50pm by Feloniz
From the valences or the oxidation states. Na in NaCl is +1. Cl is -1. CaCl2 will have Ca+2 and 2 Cl^- so CaCl2 will be more effective than NaCl. (NaCl will cause coagulation, too, but it won't be as effective as CaCl2). K3PO4 is 3K+ and 1 PO4^-3. I will leave Fe2(SO4)3 for ...
Monday, February 11, 2008 at 6:42pm by DrBob222
What's the density of 10%CaCl2? You would want 30 g CaCl2/300 g soln but that isn't 300 mL. That would be 300 g CaCl2 in 270 g H2O and that will produce a volume that is probably about 280 mL.
Tuesday, November 29, 2011 at 12:34pm by DrBob222
CaCO3(s)+2HCl(aq)>CaCl2(aq)+H2O(l)+CO2(g) how many grams of calcium chloride will be produced when 30 g of calcium carbonate are combined with 13 g of hydrochloric acid? Which reactant is in excess and how many grams of this reactant will remain after the reaction is complete?
Thursday, March 20, 2014 at 2:37pm by YOLANDA
How many grams of CaCl2 would be required to produce a 3.5M(molar) solution with a volume of 2.0L?
Saturday, April 27, 2013 at 1:27pm by Sunny
chemistry quick help!
Looking at my equation, I see i could have factored out a 2: 3CaCl2 + Al2(SO4)3 = 3CaSO4 + 2AlCl3 that does not affect the relative amounts, however. 4.19/111 = .0377 moles CaCl2 .0377 moles CaSO4 = .0377*136 = 5.13g Did you forget to calculate the grams, as they asked? You ...
Friday, January 25, 2013 at 2:03pm by Steve
How many moles of CaCl2 are in 32cm cube of 0.2M solution of CaCl2?
Thursday, October 4, 2012 at 10:56pm by desperate
moles = grams/molar mass. Solve for moles CaCl2. (You have a typo in the formula for CaCl2.) molality = moles/kg solvent. Solve for molality delta T = iKf*molality Solve for delta T; i = 3 Convert delta T to freezing point remembering the normal freezing point for water is 0 ...
Monday, April 25, 2011 at 1:06am by DrBob222
A 2.00 M solution of CaCl2 in water has a density of 1.17 g/mL. What is the mole fraction of CaCl2?
Monday, March 1, 2010 at 1:03pm by gaby
Only one question, it would be greatly appreciated if you would help me Thanx In an experiment, Na2CO3(aq) was added to 25.0 mL of CaCl2(aq) solution until no more precipitate was formed. The mass of precipitate produced was 2.50 g. Some statements about the experiment follows...
Thursday, September 28, 2006 at 1:24pm by Brittany Rusk
Determine the volume (in mL) of a 0.184 M CaCl2 solution that would be required to obtain 73.4 g of CaCl2.
Friday, April 23, 2010 at 3:05pm by jessica
How many moles of CaCl2 are in 250mL of a 3.0M of CaCl2? Ca=40.08 -- Cl=35.45 X 2 ?? Thanks
Friday, October 14, 2011 at 10:28am by Emily
Chemistry - DrBob222
About these: NaCl + Zn No reaction CaCl2 + NaOH No reaction CaCl2 + Zn No reaction CaCl2 + Na2SO4 No reaction How would these give no reaction. NaCl + Zn ==> ZnCl + Na CaCl2 + NaOH ==> Ca(OH)2 + NaCl CaCl2 + Zn ==> ZnCl + Ca CaCl2 + Na2SO4 ==> CaSO4 + Na
Sunday, November 11, 2007 at 8:34pm by Raj
2AgNO3 + CaCl2 ==> 2AgCl + Ca(NO3)2 moles CaCl2 = M x L = ?? moles AgCl produced is 2x moles CaCl2 = ?? g AgCl = moles AgCl x molar mass AgCl.
Wednesday, September 29, 2010 at 2:22am by DrBob222
calculate the value of water that is needed to dissolve 1.11 g of CaCl2 in order to prepare a 0.0250 M CaCl2 solution?
Tuesday, July 15, 2008 at 8:26pm by shanta
Most limiting reagent problems are done the same way. 1. Write the equation and balance it. 2a. Convert 1 g Na2CO3 to moles. moles = grams/molar mass. 2b. Convert 1 g CaCl2.2H2O to moles. same procedure. 3a. Using the coefficients in the balanced equation, convert moles Na2CO3...
Thursday, May 6, 2010 at 12:43pm by DrBob222
No, the result is CaCl2 and H2O. The CaCl2 does not decompose.
Monday, June 14, 2010 at 2:47pm by DrBob222
How do I convert 10 g CaCl2 to CaCl2.10H2O?
Sunday, September 5, 2010 at 11:00pm by j
Remember the definitions. Molarity = # mols/L. and # mols = g/molar mass. How many moles CaCl2 do you have in 11.1 g CaCl2. That will be 11.1 g CaCl2/molar mass CaCl2. Then #mols = M x L. You have M and you have mols, calculate L.
Tuesday, July 15, 2008 at 8:26pm by DrBob 222
If this is 10% by mass (w/w) you can't do it unless you know the density. Is this 10% w/w or 10% w/v? If 10% w/v, which I suspect, convert 10 g CaCl2 to CaCl2.10H2O and that many g in 100 mL will be 10% CaCl2. You need 250 mL; therefore, you will need 2.5 times that amount.
Sunday, September 5, 2010 at 11:00pm by DrBob222
Molarity=moles/volume (L)=0.015= x moles/7.25 L Solve for moles, 0.015*7.25L= moles of CaCl2 in solution moles of CaCl2 in solution*(110.98 g/mol)= mass of CaCl2 in g.
Friday, March 15, 2013 at 1:30pm by Devron
What you know to do, and very well I might add, is to calculate Ag and Cl in a saturated solution of AgCl. These two problems are slightly different. Basically they illustate the common ion effect. The first one has CaCl2 in the solution (the common ion is Cl^-) and the second...
Sunday, May 1, 2011 at 3:58pm by DrBob222
6.6g AgCl = .046 moles each mole CaCl2 yields 2 moles AgCl, so only 0.023 moles CaCl2 are needed. .023 moles CaCl2 = 2.55g
Monday, November 5, 2012 at 1:10pm by Steve
(a) When 300.0 milliliters of a solution of 0.200 molar AgNO3 is mixed with 100.0 milliliters of a 0.0500 molar CaCl2 solution, what is the concentration of silver ion after the reaction has gone to completion? 2AgNO3 + CaCl2 ==> 2AgCl + Ca(NO3)2 initial: AgNO3 = M x L = 0....
Monday, April 5, 2010 at 6:16pm by DrBob222
chemistry homework help!!
CaCo3(s)+2HCl(aq)---->CaCl2(aq)+H2O(l)+CO2 How many grams of calcium chloride will be produced when 27.0g of calcium carbonate are combined with 14.0g of hydrochloric acid? Which reactant is in excess and how many grams of this reactant will remain after the reaction is ...
Wednesday, February 15, 2012 at 1:33am by danielle
Consider the dissolution of CaCl2. CaCl2(s) Ca2+(aq) + 2 Cl-(aq) ΔH = -81.5 kJ A 13.0 g sample of CaCl2 is dissolved in 134 g of water, with both substances at 25.0°C. Calculate the final temperature of the solution assuming no heat lost to the surroundings and assuming ...
Sunday, November 13, 2011 at 2:20pm by william
Consider the dissolution of CaCl2. CaCl2(s) Ca2+(aq) + 2 Cl-(aq) ÄH = -81.5 kJ A 12.4 g sample of CaCl2 is dissolved in 100. g of water, with both substances at 25.0°C. Calculate the final temperature of the solution assuming no heat lost to the surroundings and assuming the ...
Sunday, November 13, 2011 at 4:03pm by Bill
When using the van't Hoff factor, I multiply the number of moles of CaCl2 by the factor right? So when finding the mole fraction of CaCl2 in the solution, it would be 3(1.22 mol CaCl2)/[3(1.22) + 12.2] which equals about .231. So then it would be dP = .231 * 239 = 55.2 mm Hg. ...
Wednesday, December 12, 2012 at 6:20pm by Brad
Consider the dissolution of CaCl2. CaCl2(s) Ca2+(aq) + 2 Cl-(aq) ÄH = -81.5 kJ A 10.4-g sample of CaCl2 is dissolved in 102 g of water, with both substances at 25.0°C. Calculate the final temperature of the solution assuming no heat lost to the surroundings and assuming the ...
Thursday, April 18, 2013 at 11:51pm by Mike
Setting up an ICE chart is a great move; however, I don't get the answers you have (perhaps I just can't red the spacing since the board doesn't recognize anything over one space). At any rate, the equation is right but the Ksp is wrong. CaCl2 + K2SO4 ==> CaSO4 Since I can'...
Wednesday, April 21, 2010 at 10:06pm by DrBob222
a)Water b)CaCl2 c)CaCl2 d)Water e)CaCl2
Wednesday, November 24, 2010 at 12:50am by Sean
a)CaCl2 b)water c)CaCl2 d)water e)CaCl2
Wednesday, November 24, 2010 at 12:50am by Anonymous
How do i convert g CaCl2 to g CaCl2*H2O?
Sunday, September 5, 2010 at 10:54pm by j
A laboratory assistant needs to prepare 325 mL of 0.110 M CaCl2 solution. How many grams of calcium chloride will she need?
Tuesday, November 9, 2010 at 9:57pm by Jasmin
Calcium chloride, CaCl2, has been used to melt ice from roadways. Given that a solution is 25% CaCl2 by mass, estimate the freezing point.
Monday, December 20, 2010 at 9:33am by Akkam
chemistry quick help!
In the balanced double replacement reaction of calcium chloride CaCl2 and aluminum sulfate Al2(SO4)3, how many grams of calcium sulfate can be produced if you start the reaction with 4.19 grams of calcium chloride and the reaction goes to completion?
Friday, January 25, 2013 at 2:03pm by thad
In the balanced double replacement reaction of calcium chloride CaCl2 and aluminum sulfate Al2(SO4)3, how many grams of calcium sulfate can be produced if you start the reaction with 18.97 grams of calcium chloride and the reaction goes to completion?
Monday, January 28, 2013 at 2:58pm by Thad
A solution contains 15 g of CaCl2 in a total volume of 190 mL. Express the concentration in terms of grams/liter, % w/v, molars, and milimolars.
Friday, February 1, 2008 at 10:00pm by Alex
mols CaCl2 = grams/molar mass Then M = mols/L solution
Saturday, April 5, 2014 at 8:43am by DrBob222
It would have helped if you had posted your work. That way I could find the error. As it is I'm slogging around in the dark. If CaCl2 is exothermic you know the temperature should go up and ot down. 3.80g/molar mass CaCl2 = mols. mols CaCl2 x 82800 = ? Joules. ?J = mass H2O x ...
Thursday, June 21, 2012 at 6:56pm by DrBob222
what will be the law of conversion of a) 65 grams 70 grams b) magnesium + oxygen = magnesium oxide 45 grams ? grams 80 grams c) sodium hydroxide + hydrochoride acid 40 grams 36.5 grams sodium chloride + water ? grams 18 grams
Saturday, August 4, 2012 at 12:35pm by Magaly
I assume you meant hydrochloric acid or aqueous hydrogen chloride (hydrogen chloride is a gas and there would be little to no reaction between the gas and solid CaCO3). Here is a step by step. Print this out so you can keep it. It will work all of your stoichiometry problems ...
Wednesday, August 15, 2012 at 7:26pm by DrBob222
Consider the dissolution of CaCl2: CaCl2(s) -----------> Ca2+(aq) + 2Cl-(aq) ΔH=-81.5 kJ/mol An 11.0 gram sample of CaCl2 is dissolved in 125 g water with both substances at 25.0 °C. Calculate the final temperature of the solution assuming the solution has no heat loss...
Wednesday, November 2, 2011 at 9:05pm by Bob
Calculate the number of moles and number of grams of solute in 250 mL of a 0.10M CaCl2.
Monday, April 21, 2008 at 12:37pm by Shaun
How would I go about doing this question, can someone explain it step by step please, my answer I keep getting is 1.17m CaCl2, but the answer is 1.35m CaCl2? A 1.30M solution of CaCl2 in water has a density of 1.1g/mL/ What is the MOLALITY? Also, when for questions with ...
Tuesday, June 16, 2009 at 4:56pm by DrFunk
How many grams of CaCO3 can be precipitated if 50.0 ml of 0.10 M CaCl2 are mixed with 30 ml of 0.2 M KCO3?
Friday, January 13, 2012 at 9:52pm by Eric
Hydrochloric acid reacts with calcium to form hydrogen and calcium chloride. If 100 grams of hydrochloric acid reacts with 100 grams of calcium, what is the limiting reactant? 2HCl + Ca --> CaCl2 + H2
Monday, June 18, 2012 at 10:15am by tyler
4.5% CaCl2 m/m means 4.5 g CaCl2/100 g soln. That is 4.5 g CaCl2 in a soln of (4.5 g CaCl2 + 95.5 g H2O). You have 60 g of this soln; therefore, you have g H2O = 60 x (95.5/100) = ? g H2O. 60 x (4.5/100) = ? g CaCl2.
Friday, April 27, 2012 at 10:09pm by DrBob222
what volume of 0.1 moldm-3 HCL acid would be required to dissolve 2.3 grams of calcium carbonate equation CaCO3+2HCL----------=CaCl2+CO2+H20 (WATER)
Sunday, September 25, 2011 at 10:43am by aisha
Calculate how many grams of the product(s) would be produced by complete reaction of 0.125 mole of the first reactant. CaCO3 + 2HCl --> CaCl2 + CO2 + H2O
Sunday, April 22, 2012 at 11:30pm by Lindsey
moles acid used = M x L. Moles CaCO3 is 1/2 that because CaCO3 + 2HCl ==> CaCl2 + H2O + CO2 moles CaCO3 = grams/molar mass. You have moles and molar mass. Solve for grams.
Sunday, March 14, 2010 at 3:50pm by DrBob222
If 60.0 mL of 0.150 M CaCl2 is added to 50.0 mL of 0.100 M AgNO3, what is the mass in grams of AgCl precipitate?
Monday, March 2, 2009 at 1:15pm by ash
You need to find and use the caps key on your keyboard. mols CaCl2 = grams/molar mass M = mols/L soln.
Saturday, May 25, 2013 at 3:03pm by DrBob222
There are two atoms of Cl in 1 mole of CaCl2; therefore, 2.7 mol CaCl2 must have 2*2.7 moles Cl.
Tuesday, March 8, 2011 at 6:03pm by DrBob222
(CaCl2) = M = moles/L soln. 0.075 mols/0.425 L = ? Since there are two Cl^- in a mol of CaCl2, the (Cl^-) = twice that.
Monday, April 23, 2012 at 9:30pm by DrBob222
how do you calculate the molaarity of a water solution of CaCl2, given that 5.04 L of the solution contains 612 g of CaCl2.
Sunday, June 13, 2010 at 6:40pm by denise
a chemist wants to make 5.5L of a .3M Cacl2 solution. What mass of CaCl2 should the chemist use?
Sunday, February 9, 2014 at 4:35pm by Charessa
What is the mass of 0.425 moles of CaCl2? The molar mass of CaCl2 is 110.98 g/mol.
Friday, February 19, 2010 at 12:09am by Jessica
A chemist wants to make 4.5 L of a 0.310 M CaCl2 solution what mass of CaCl2 (in g) should the chemist use
Monday, November 1, 2010 at 7:40pm by Lisa
A chemist wants to make 5.5 L of a 0.250 M CaCl2 solution, what mass of CaCl2 (in g) should the chemist use?
Saturday, November 20, 2010 at 1:07pm by Lisa
A solution of CaCl2 is prepared by dissolving 1.004 g of the solid in approximately 30 mL of water. How many moles of CaCl2 does this solution contain?
Sunday, March 3, 2013 at 9:04pm by KRIS
Ca(OH)2+ HCl <> CaCl2 + H20 + energy you add more HCl, Keq= [CaCl2]/[Ca(OH)2][HCl] you add more HCl, to reestablish equilibrium, more CaCl2 is made, and less Ca(OH)2 is left.
Sunday, October 9, 2011 at 5:00pm by bobpursley
First we get the amount (the mass, specifically) of calcium chloride needed. Mass is related to number of moles. Recall that molarity (M) is just number of moles (n) divided by the volume (V) in liters: M = n/V Therefore, n = MV n = (0.15 M)(0.2 L) n = 0.03 moles Now, to get ...
Thursday, September 26, 2013 at 10:08am by Jai
Please note the correct spelling of Celsius. How much heat does the CaCl2 add to the water? That is 7.2 g (1 mol/molar mass CaCl2) x (82,800 Joules/mol). Then q = mass water x specific heat water x (Tf-Ti) where Tf is the final T and Ti is the initial T. Most dilute solutions ...
Friday, October 3, 2008 at 11:23pm by DrBob222
A 0.972g sample of a CaCl2*2H2O/K2C2O4*H2O solid salt mixture is dissolved in ~ 150ml of deionized water, previously adjusted to a pH that is basic. The precipitate, after having been filtered and air-dried, has a mass of 0.375 g. The limiting reactant in the salt mixture was ...
Friday, February 19, 2010 at 1:42pm by Maria
23.7/molar mass CaCl2 = moles CaCl2 moles Cl^- = 2 times that. Convert 3675 g water to liters using the density. Then M = mols/L.
Sunday, September 26, 2010 at 12:53pm by DrBob222
First, you made an error before you get to that part. grams O = 2.00-grams C - grams H. You subtracted grams CO2 and grams H2O. Your grams C (and moles) is ok as is the grams H (and moles H) but the oxygen must be redone.
Monday, October 17, 2011 at 9:21pm by DrBob222
M = mols/L of solution. You can calculate mols from mols = grams/ molar mass. You know molar mass CaCl2 and you know grams. Calculate mols from equation 2, and substitute in equation 1 to calculate molarity. Post your work if you need more help. I left a message for you on the...
Wednesday, May 7, 2008 at 9:02pm by DrBob222
If 17.0 mL of 0.590 M CaCl2 are mixed with 46.6 mL of 0.480 M CaCl2, calculate the molarity of each ion in the final solution? Assume the volumes are additive.
Sunday, April 3, 2011 at 7:44pm by Pob
What mass (in grams) of calcium carbonate is needed to react completely with 73 mL of 0.10 M HCl according to 2HCl + CaCO3 --> CaCl2 + H20 + CO2?
Thursday, November 11, 2010 at 3:29pm by Brenna
A solution is made by dissolving 10.9 g of calcium chloride, CaCl2,in enough water to make exactly 500 mL of solution. What is the concentration (molarity) of CaCl2 in mol/L?
Saturday, July 24, 2010 at 5:04pm by Shelia
GK is correct; the problem could have been worded more correctly. I assumed you were asking for the solution. Also, I note that I made an error in typing. It isn't 11.1 g CaCl2 but 1.11 g CaCl2.
Tuesday, July 15, 2008 at 8:26pm by DrBob 222
CaCl2 absorbs H2O (H2O comes from the H); the difference in mass is grams H2O. Convert that to grams hydrogen. Carbon is converted to CO2 then to H2CO3 and titrated. From the titration data yu obtain grams C. Use PV = nRT to solve for n for nitrogen and convert to grams. ...
Sunday, April 24, 2011 at 5:02pm by DrBob222
CHEM! (SCIENCE) NEED HELP
Look at the your other posts for explanations. 1 mol of HCl*(CaCl2/2 mol of HCl)= 0.5 mol of CaCl2 5.5 mol of CaCO3*(1 mol of CaCl2/1 mol of CaCO3)= 5.5 mol of CaCO3
Thursday, January 24, 2013 at 5:51pm by Devron
What am i supose to do here? A chemist performs the following experiment: 2FeCl3 + 3CaCO3 ---> Fe2(CO3)3 + 3CaCl If he starts with 105g FeCl3 and excess CaCO3 how many grams of CaCl2 will he obtain? Thanks, ~Nick
Sunday, January 18, 2009 at 7:11pm by Nick
I don't understand the question. There IS no ppt between CaCl2 and NaCl. You may have exceeded the solubility of NaCl or CaCl2. By the way, sodium chloride is NaCl, not NaCl2.
Monday, November 5, 2012 at 3:13pm by DrBob222
A solution is prepared by dissolving 23.7 g of CaCl2 in 375 g of water. The density of the resulting solution? is 1.05 g/ml. the concentration of CaCl2 is ________% by mass. answer: 5.94 can someone tell me the steps?
Wednesday, September 15, 2010 at 5:39pm by john
If 10.0g of CaCl2 and 10.0g of NaCl are dissolved in 100.0mL of solution, what is the concentration of chloride ions? I found the molar mass of CaCl2 is 111.0g/mol; the molar mass of NaCl is 58.44g/mol. I divided 10g CaCl2/111.0g CaCl2 I divided 10g NaCl/588.44g NaCl and added...
Monday, July 12, 2010 at 9:33am by Casey
moles soln 1 = M x L = ?? moles soln 2 = M x L = ?? M CaCl2 = total moles/total L. M Ca^+2 = M CaCl2 M Cl^- = 2 x M CaCl2.
Sunday, April 3, 2011 at 7:44pm by DrBob222
How many milliters of 1.80M HCl are required to react with 30.0 grams of calcium hydroxide according to the given equation: CA(OH)2(s) + 2HCl(aq)> CaCl2(aq) + 2H2O(l)
Sunday, April 3, 2011 at 7:31pm by Elaine
An aqueous solution contains 4.50 g of calcium chloride, CaCl2, per liter. What is the molarity of CaCl2? When calcium chloride dissolves in water, the calcium ions, Ca^+2, and chloride ions, Cl^-, in the crystal go into the solution. What is the molar concentration of each ...
Monday, November 3, 2008 at 8:08pm by Anna
Just a step or two. molarity = moles/L. So convert 612 g CaCl2 to moles. moles = grams/molar mass. Then moles/L (L is 5.04) will get it.
Sunday, June 13, 2010 at 6:40pm by DrBob222
2 M CaCl2 = 2 mols CaCl2/L soln. 2 mol = 111 x 2 = 222 g (but that's an estimate--you recalculate it). Use density to calculate mass of 1L soln. That will be 1145grams. mass solvent = 1145g-222g = ?g and convert to kg. Then mols Cl in CaCl2 = 4 (2*2) mols Cl in MgCl2 = 10 (2*5...
Friday, May 10, 2013 at 4:54am by DrBob222
15 g CaCl2/molar mass = mols CaCl2. mols/L = molarity. millimolarity is 1000 times that. % W/V is mass in 100 mL solution.
Friday, February 1, 2008 at 10:00pm by DrBob222
If 20g of Ca(0H)2 took part in the following reaction, how much CaCl2 would be formed. Ca(0H)2 + 2HCl to CaCl2 +2H20
Monday, January 2, 2012 at 11:06pm by tracey
There are 6.02E23 molecules in 1 mol CaCl2. So there must be 6.02E23 x 2.35 = ? molecules in 2.35 instead of 1 mol of CaCl2. Then the formula tells you that there are 2 Cl ions in 1 molecule so the number of Cl^- must be twice the number of molecules of CaCl2.
Thursday, November 14, 2013 at 8:39pm by DrBob222
According to your balanced equation, each mole of CaCl2 needs one mole of NaF. Moles of CaCl2: .0246*.216 volume of NaF=that/.355 in liters.
Friday, July 8, 2011 at 3:06pm by bobpursley
When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO3 +2HCl yields CaCl2 +H2O +CO2 How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate are combined with 13.0 g of hydrochloric acid...
Sunday, September 22, 2013 at 7:09pm by Lori
Note the typo I made in the dissolution of CaCl2 It should be CaCl2 ==>Ca^+2 + 2Cl^- I didn't write the one for NaCl. NaCl ==> Na^+ + Cl^-
Tuesday, January 6, 2009 at 7:54pm by DrBob222
chemistry quick help!
6CaCl2 + 2Al2(SO4)3 = 6CaSO4 + 4AlCl3 So, now you know that each mole of CaCl2 produces one mole of CaSO4 How many moles in 4.19g of CaCl2? How many g in that much CaSO4?
Friday, January 25, 2013 at 2:03pm by Steve