Friday
May 24, 2013

Search: fd

Number of results: 188

Calculus
I draw the figure, labeling the distance the plane flies on its path as Flightdistance(FD), d is the distance from radar to plane, 8km is the initial vertical altitude. FD=time*24km/min Using law of cosines d=sqrt(FD^2+8^2-2*8*FD cos 110) taking the derivative d'= 1/2*1/...
Monday, March 1, 2010 at 9:26pm by bobpursley

Quantiative Methods
rfdf d fd fd f
Saturday, November 10, 2007 at 7:13pm by Rick

geometry
If FD=4x-27, and SG is congruent to FD and SG=2x-3, Then whais the length of SG?
Monday, November 14, 2011 at 3:39pm by KC

Physics
1. Since work equals force times distance(W = F*d), and the force or weights and distance were equal, the amount of work was also equal. 2. We can use the horsepower(hp) Eq to compare their power outputs: hp = f*d / 550t = f*d / 550*30, hp = f*d / 16500 = 6.06x10^(-5)*fd. hp...
Monday, November 15, 2010 at 7:50pm by Henry

math
since AF is the perpendicular bisector of BD, therefore BF=FD. since DF=FD=13, BF=13 now, if you draw this figure, you will see that you form a right triangle (AFD) when you connect A and D,, connecting A and B, you form another right triangle,, since they share a common ...
Monday, March 28, 2011 at 10:31pm by Jai

AP Physics
a. a = (Vf - Vi)/t, a = (4.65 - 0) / 2.6 = = 1.788m/s^2. d = 0.5at^2, d = 0.5 * 1.788 (2.6)^2 = 6.04m. F = ma = 1260 * 1.788 = 2252.88N. W = Fd = 2252.88 * 6.04 = 13607J. b. P = Fd/t=2252.88 * 6.04/1.768=7696.
Saturday, February 26, 2011 at 9:45pm by Henry

College Chemistry Lab
Determine the molarity of FD&C Yellow #5 in the following solution that's prepared by mixing the dye solution with water and alcohol. None of the solutes react with one another. 6.35x10^-5M FD&C Yellow #5 = 6.50mL deionized water = 6.50mL ethyl alcohol = 6.80mL
Tuesday, March 16, 2010 at 7:32pm by L**

Physics
First, take the mass. It has weight mg. break that into components, normal to the plane, and down the plane. fn=mgcosTheta fd=mgsinTheta You I hope remember friction is dependent on the normal force. Pulling force-fd-friction=mass*a This problem is standard fore for physics ...
Saturday, December 5, 2009 at 8:35pm by bobpursley

physics
two people push in opposite directions on a block that sits atop a frictionless surface. The soles of their shoes are glued to the surface. if the block originally at rest moves to the right a distance of d. Describe qualitatively how much work is done by the person on the ...
Monday, October 30, 2006 at 9:44pm by joseph

geometry
this one is just like the one with bearings. Use law of cosines: DE2 = FD2 + FE2 - 2*FD*FE*cosF DE2 = 225 + 784 - 2*15*28*cos(73.666666) DE2 = 773 DE = 28
Thursday, February 16, 2012 at 10:54pm by Steve

physics
also I was always told to use this equation when the velocity is small through the medium Fd = -bv were this is just a proportion also that other formula that is suppose to be used when there is a high velocity Fd = 2^-1 p v^2 A Cd v Ok what is exactly meant by high and low ...
Friday, July 31, 2009 at 10:56pm by physics

Physics
What work is required to stretch a spring of spring constant 500N/m from x1=.2m to x2=.25m? Assume the unstreched position is at x=0. W=Fd so w=(500)(.25-.2) =500(.05) =25J is this correct? Calculate the work required to compress an initially uncompressed spring with a spring ...
Wednesday, October 17, 2007 at 5:07pm by Andrea

Math
5
Thursday, January 8, 2009 at 4:16pm by fd

fs
fd
Wednesday, March 7, 2012 at 10:30am by De

physics
W=Fd
Friday, October 12, 2012 at 12:15am by Anonymous

English 2
fd
Monday, January 16, 2012 at 5:07pm by debra

physics
6ytguyhjiui fd,
Tuesday, October 26, 2010 at 7:37pm by ertyu

physics
W = Fd = 5 * 0.5 = 2.5 Joules.
Tuesday, November 8, 2011 at 8:45am by Henry

Summary of The Necklace?
fd
Thursday, October 18, 2007 at 10:29pm by Ebony

Social Studies
fd
Monday, October 15, 2007 at 11:40pm by Allie

PHYSICS
Efinal= 1/2mvi^2+fd
Tuesday, March 26, 2013 at 7:58am by Brandon

physics
W=FD 300/2 = 150 N
Tuesday, February 8, 2011 at 7:07pm by Tiffany

physics
W=Fd or W=FnetCOS(theta)
Tuesday, November 2, 2010 at 6:44pm by Asim

fd
if y=36 when x=9 find x when y=52
Tuesday, June 17, 2008 at 12:54pm by df

Physics
recall that speed is distance traveled per unit time, or v = d/t also recall that work is force exerted times distance, or W = Fd since in the problem we are only given the force, we calculate for the distance first. substituting the given speed and time to formula for speed: ...
Friday, April 8, 2011 at 11:04pm by Jai

science
287J=W=Fd=F(2.5m), solve for F
Monday, February 25, 2013 at 8:33pm by Devron

Physical science
W = fd W also = change in K
Monday, February 4, 2013 at 3:26pm by Emmi

PreAp Physics
W = Fd = 112 * 4.5 = 504J.
Wednesday, November 23, 2011 at 7:21pm by Henry

Physics
W = Fd/t = F * d/(t/3) = F * d * 3/t. Wo = 3 Times the usual.
Wednesday, March 2, 2011 at 11:38pm by Henry

Physics
W = FD Given m = 2.0-kg d = 0.050 m W = ?
Thursday, January 7, 2010 at 5:06pm by Priscilla

Physics
please check these: In which of the following sentences is WORK used in the scientific sense of the word? a. holding a heavy box requires a lot of work b. a scientist works on an experiment in the laboratory c. sam and rachel pushed hard, but they could do no work on the car d...
Monday, February 9, 2009 at 5:27pm by y912f

physics
W = Fd = 463 * 0.12m = 55.56J.
Tuesday, November 8, 2011 at 11:56pm by Henry

physics
W = Fd, F = W/d = 1470 / 20 = 73.5N.
Thursday, June 30, 2011 at 6:16pm by Henry

physics
W=Fd 1250=F*2 Power to lift it=625
Thursday, November 4, 2010 at 7:30pm by Judy

Physics
Given F = 450 N m = 20 kg d = 2 m W = Fd
Sunday, January 2, 2011 at 3:53pm by Anonymous

physics
W = Fd = 80 * 15 = 1200 Joules.
Tuesday, November 23, 2010 at 9:33pm by Henry

fd
Cross-multiply and then solve for x: 36/9 = 52/x
Tuesday, June 17, 2008 at 12:54pm by Writeacher

intergrated physics and chemistry
Work is expressed by- Fd
Thursday, November 29, 2007 at 7:18pm by scott

calculate work done
W = Fd F = ma a = (15-6)/2 = 4.5 d = 1/2 at^2 = 2.25*4 = 9 W = 2*4.5*9 = 81
Friday, November 11, 2011 at 12:28pm by Steve

physics
Work = Fd = 30N * 6m = 180 Joules.
Wednesday, August 3, 2011 at 4:32am by Henry

physics
W e Fd = 1470J, 20F = 1470, F = 73.5N.
Wednesday, June 29, 2011 at 1:24pm by Henry

Physics
F = mg = 260kg * 9.8 = 2548N. P=W/t = FD/t = 2548 * 1.9 / 1.8 = 2690.
Thursday, February 3, 2011 at 9:00pm by Henry

geometry
If CFD=12a+45, find a so that FC is perpendicular to FD
Saturday, September 6, 2008 at 12:17pm by Mary

Physics
A beam which is fixed to a wall by bolting or which is extended from inside the building, the free other end of which is freely hanging in the air is called a cantilever. This may make for easier search if you intend to do so. The torque caused by weights on the beam is called...
Saturday, December 4, 2010 at 11:37pm by MathMate

PHUSICS
W = Fd = 700 * 10 assuming a weightless bucket :-) or, Jill carried it.
Tuesday, March 12, 2013 at 2:01am by Steve

Physics
F = mg = 50kg * 9.8N/kg = 490N. W = Fd = 490 * 3 = 1470Nm.
Wednesday, March 2, 2011 at 11:37pm by Henry

physics
Wb = mg = 50kg * 9.8N/kg = 490N. = Weight of block. Fb = 490N @ odeg. Fh=490sin(0) = 0 = Hor. force of block Fv = 490cos(0) = 490N. = Force perpendicular to surface = Normal. a. Fap*cos30 - Fh - Ff = 0, Fap*cos30 - 0 - 0 = 0, Fap*cos30 = 0, Fap = 0 = Force applied. Work = Fd...
Monday, November 28, 2011 at 5:41pm by Henry

geometry
looks like 4x-27 = 2x-3 so, x=12 and SG = FD = 21
Monday, November 14, 2011 at 3:39pm by Steve

Physics
I believe the answer is 1/2kx^2=Fd=10N(0.2m)=2J. Hopefully someone checks this.
Wednesday, January 23, 2013 at 5:08pm by Devron

phsyics
d = 1.8km * 1000m/km = 1800m. W = Fd = 470 * 1800 = 846,000 Joules.
Tuesday, November 1, 2011 at 7:04pm by Henry

geometry
ABC is congruent to DEF AB = 11, BC = 14, CA = 20, FD = 4x - 12 Find x
Sunday, November 20, 2011 at 6:01pm by T

AP Physics
but i solved for the force and it did not come out as the right anser i did Fd=mgh then said F(.6)=(48)(9.8)(3) but its wrong???
Thursday, November 13, 2008 at 10:00pm by Corey

Physics
A luggage handler pulls a 20kg suitcase up a ramp inclined at 25 degrees above teh horizontal by a force F of magnigutde 145N that acts parallel to the ramp. The coefficient of kinetic friction between teh ramp and the incline is .30. If the suitcase travels 4.6 m along the ...
Thursday, January 18, 2007 at 4:19pm by Jamie

Science
W=FD where W is work, F is force, and D is displacement. Find F and you will be able to get work.
Thursday, December 8, 2011 at 2:42pm by Anonymous

Physics
How do you use this equation? mgh+1/2mvh=mgh+1/2mv^2+Fd
Sunday, January 27, 2008 at 11:26pm by Cassidy

Physics
W = Fd = 5.89*10^5 * 520 = 30.63*10^7J.
Sunday, February 27, 2011 at 9:47am by Henry

Physics
Vo=0 7.80g=.0078kg V=590m/s d=.048m W/d W=Fd =1/2mV^2 - 1/2m(Vo)^2
Thursday, March 24, 2011 at 6:36pm by NinaCC

Physics
Fd=0.5mv^2 F(4.5)=0.5(75)(6.0)^2 F=0.5(75)(6.0)^2/4.5 F=300N
Thursday, January 10, 2013 at 11:16am by Anonymous

fd - Math
Math help needed here.
Tuesday, June 17, 2008 at 12:54pm by Ms. Sue

geometry
Since the triangles are congruent, FD = CA 4x-12 = 20 4x=32 x=8
Sunday, November 20, 2011 at 6:01pm by Steve

physics
F = mg = 10kg * 10N/kg = 100N. W = Fd = 100 * 100 = 10,000 J.
Sunday, October 30, 2011 at 2:58am by Henry

physics
convert 145 km/h into m/s 145 × 1000 ÷ 3600= 40.3 then use this equation: W=Fd
Wednesday, March 3, 2010 at 2:29pm by Diamond

physics
F = mg = 50kg * 9.8N/kg = 490N. W = Fd = 490N * 300m = 147,000 Joules.
Wednesday, August 3, 2011 at 4:37am by Henry

physics
In your "C" answer, second line, you should have used 0.08m, not 0.0888m (that was the K constant). Therfore, the result is W=Fd= 71*0.08= 5.68 Joules
Sunday, November 6, 2011 at 2:41pm by Moses

physics
a) F = ma |F| = 84kg*-3.5m/s^2 b)v=0 x= -(41m/s)^2/(2(-3.5m/s^2)) c)W is going in the -x direction because it's decelerating W= -Fd Then you just apply these equations to d,e, and f.
Thursday, October 28, 2010 at 10:18pm by Granger

physical science 101
Fn = ma = 7 * 4 = 28N. d=Vo*t + 0.5*at^2. d = 0 + 0.5*4*5^2 = 50m. W = Fd = 28 * 50m = 1400 Joules.
Thursday, August 11, 2011 at 9:58am by Henry

physics
Fe = 454kg * 9.8N/kg = 4449.2N. Pe Fd/t = FV = 4449.2 * 0.180m/s = 801W
Tuesday, March 8, 2011 at 4:46pm by Henry

fd - correction
Oops. I was considering the 17 as the length of the edges, not the diagonals. The height h is given by 15^2 + h^2 = 17^2 h=8 A = (8+22)/2 * 8 = 120
Wednesday, October 3, 2012 at 1:23am by Steve

Physics
Thanks. Is this the only way to calculate because in our lesson we only learned the formula for work =fd? We've haven't done KE yet.
Monday, April 6, 2009 at 11:51pm by KC

fd
a trapezoid abcd has parallel sides ab and dc of lengths 8 and 22. If both diagonals AC and BD are of length 17, what is the area of the trapezoid
Wednesday, October 3, 2012 at 1:23am by Anonymous

Physical Science
W=FD W=(400N)(3.0m) W=1200N I dont really get the 1250N car thing. Unless you also need friction, but i need the coefficent for that.
Monday, December 7, 2009 at 10:47pm by ALan

Physics
A spring has a force constant of 100N/m and an unstretched lenght of .07 m. One end is attached to a post taht is free to rotate in the center of a smooth table. The other end is attatched to a 1 kg disc moving in uniform circular motion on the table, which stretches the ...
Monday, March 26, 2007 at 6:40pm by Tammy

physics
A speeding car is pulling away from a police car. The police car is moving at 30 m/s. The radar gun in the police car emits an electromagnetic wave with a frequency of 20.0 x 10^9 Hz. The wave reflects from the speeding car and returns to the police car where the frequency is ...
Saturday, August 21, 2010 at 1:57pm by Liz

physics
you do Fd=.5m*vfinal^2-.5m*vinitial^2 solve for vfinal and that is the correct answer.
Wednesday, November 16, 2011 at 5:58pm by JM

Math solid mensurations
rhombus ABCD has diagonals that intersect at E. DF is drawn perpendicular to DC and AD at D. With AB = 10cm, &lt;BCD = 60 degrees and FD = 4cm, Find the length of FE
Thursday, February 23, 2012 at 6:56am by Anonymous

I don't quite get the formula "w=(fd)" i understand what to do once you get the data, but i can't seem to ever get the data from the six basic machines, and converting the measurement units. I really need help, please
Tuesday, December 16, 2008 at 10:26pm by Anonmymous

physics
A 1.00 kg hollow ball with a radius of 2.2^10^-1 m, filled with air, is released from rest at the bottom of a 1.50 m deep pool of water. How high above the water does the ball shoot upward if the upward force exerted by the fluid on the ball 40 N? Neglect all frictional ...
Monday, October 27, 2008 at 11:30pm by Sandhya

Physics Disaster
Had The Same Teacher For Physics And Ughh I Am Stuck. Notes Help Me A Lot So If Anyone Could Write A Few Or A Bunch Out That Would Be Awesome. I Am Not The Type Of A Person Who Minds Writing Down Notes;) Teacher Told Us About Work And That The Formula For It Is W = Fd. IS It? ...
Wednesday, November 16, 2011 at 9:16pm by Fizzylicous

physics
a.) the force exerted by the man is found by doing: Fnormal= mass(gravity)(sin30) - u(mass)(gravity)(cos30) ...the u is the coefficient of friction. b.) the work done by the man is found by using the force we found in the question above and putting it into: W=Fd My coeffiecent...
Monday, April 27, 2009 at 7:14am by Anonymous

Physics Disaster XXP
Had The Same Teacher For Physics And Ughh I Am Stuck. Notes Help Me A Lot So If Anyone Could Write A Few Or A Bunch Out That Would Be Awesome. I Am Not The Type Of A Person Who Minds Writing Down Notes;) Teacher Told Us About Work And That The Formula For It Is W = Fd. IS It? ...
Wednesday, November 16, 2011 at 10:39pm by Fizzylicous

Physics
You almost have it. Netforce*distance= changeinKE (20-mu*1*9.8)*5=change in ke or, you could calculate work in (your Fd) and subtract friction work. You forgot the distance on your fricion calcs.
Wednesday, October 17, 2007 at 6:02pm by bobpursley

geometry
Shape is a trapezoid: LINE AC = 12dm LINE FD = 13dm LINE BE = 14dm LINE CG = 10dm This line makes the right angle of the triangle What is the area?
Sunday, May 19, 2013 at 9:01pm by beck

physics 11
if you have the formula W=Fd, where W=work, F=force, and d=displacement, how do you find W if you don't have F, but you have a mass and displacement?
Tuesday, January 11, 2011 at 10:05pm by sierra

Physics
A 1000kg car accelerates from 0 to 25m/s in 8s. What is the average power delivered by the engine? (1hp=746W) P=W/t p=Fd/t P=Fv p=mav =1000(25/8)(25) =78125W which is about 104.725 hp Is this correct?
Wednesday, October 17, 2007 at 5:53pm by Andrea

Physics
A 15 N force is needed to move an object with constant velocity of 5 m/s. What power must be delivered to the object by the force? I konw that P=W/t and W=Fd But other than that I am confused . I am not sure how i would solve this problem.
Tuesday, October 16, 2007 at 8:59pm by Andrea

Physics
W = FD Given F = 4.5 x 10^3 N D = 0.25 m W = (4.5 x 10^3 N) (0.25 m)
Thursday, January 7, 2010 at 5:08pm by Priscilla

Math
4ft = 48in Work is the same on both sides, and W = Fd W1 = W2 F1*d1 = F2*d2 150lbs*48in = F2*2in F2 = 3600lbs
Monday, July 13, 2009 at 12:22pm by Marth

phys
for a) w= 1/2 (m)(v^2) so just plug in the work that is given and the mass, and solve for v. for b) w=fd so f=w/d so plug in work and distance, convert as needed, and you're set. Hope I helped, even though I answered your question almost 3 years late!
Wednesday, October 27, 2010 at 6:18pm by Mario

Physics
in the equation w= fd it is assumed that the force varies and is exerted in the direction of displacement... true or false? Yes. Force is measured in the direction of displacement.
Wednesday, February 7, 2007 at 10:29pm by Shelley

precalculus
Find the focus, directrix, and focal diameter of the parabola. 9x + 7y2 = 0 my answers were focus = -9/28,0 fd =9/7 directrix= -9/28 (this ans. is incorrect) what am I missing? pls help
Saturday, December 1, 2012 at 11:09pm by amaa

A spring has stiffness of 100Nmm, the initial compression of the spring is 15mm, and it is then compressed to 65mm. 1Nmm = 0.001Nm 100Nmm = 100 X 0.001 = 0.1Nm Comp.1 = 15 mm = 0.015m Comp.2 = 65 mm = 0.065m a) i-Find potential energy at 15mm. ii- Find potential energy at 65mm...
Saturday, March 21, 2009 at 6:23pm by Henri

A spring has stiffness of 100Nmm, the initial compression of the spring is 15mm, and it is then compressed to 65mm. 1Nmm = 0.001Nm 100Nmm = 100 X 0.001 = 0.1Nm Comp.1 = 15 mm = 0.015m Comp.2 = 65 mm = 0.065m a) i-Find potential energy at 15mm. ii- Find potential energy at 65mm...
Saturday, March 21, 2009 at 6:52am by Henri

Physics
Calculate the work done by the applied force accelerating a 2 kg object at 3 m/s/s over 4 m if there is a 2.5 frictional force of resistance. I calculated using F=ma=6N; then net force = 6N-2.5N=3.5 N so W=fd=14J. Did I do this correctly? Thanks
Monday, April 6, 2009 at 4:10pm by KC

physics
Wb = mg = 50*12.3kg * 9.8N/kg = 6027N. = Weight of 50 boxes. Work = Fd = 6027 * 2.3 = 13,862 Joules. 31W. = 31Joules/s. t = 13,862J. * (1/31)s/J. = 447.2s
Tuesday, November 8, 2011 at 8:59am by Henry

Physics
Distance DC = FE = HG = AB = 2.7m FH = FD = GE = EC = CB = 2 m Find the supporting reaction of H, Member BD (Tension Force), Member CE, and Member CF? Figure Links: freeimagehosting 72dje
Thursday, June 7, 2012 at 8:32pm by ToT_Alex

Physics
I have a follow-up to my question at 4:10 about work because I still can't figure it out. F-F(friction)=ma F-F(friction)=2*3 F-2.5=2*3 F=2*3 + 2.5 W=Fd W=(2*3 + 2.5)4 Distributing the "4" I get W=2*3*4 +2.5*4 Please help in pointing out where I have gone wrong. ...
Monday, April 6, 2009 at 6:32pm by KC

Chemistry
Robby if you need more help,type ur question ino the search bar on your computor and a site titled chap15 fd.valenciacollege.edu will come up and it will break down complete indtructions on how to go about figuring out this question.I hope this helps.
Monday, February 18, 2013 at 1:03pm by Jeff

AP PHYSICS
Work done by friction= forcefriction*distance=mu(fn)*distance where fnormal= mg-2.3E2Sin21 Fd= (.200)(.700X9.8X-2.3E2Xsin21)X(7)= Work done by friction=19790.15328.. thats what I got and it is wrong i believe
Sunday, November 14, 2010 at 8:44am by Ashley

physics
F=85*cos20 N work=fd= 85*cos20*30 work =2,4 kNm
Saturday, December 4, 2010 at 5:39pm by bark

Physics
you can find the force doen through W=Fd, where W is work done,F is force applied, and D is the displacement(79m) Work done also equlals change in kinetic energy, which is -521360J, sp the force applied is -6599.5 N.
Wednesday, December 5, 2012 at 7:40pm by eintstein

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