Sunday
April 20, 2014

Search: dilution create 500 ml of 1.5M HCl from a stock solution with a concentration of 12M

Number of results: 23,968

chemistry
It looks ok to me but there is an easier way to do it. If you use the dilution formula you don't need to change the units; just keep everything in mL. The dilution formula is mL1 x M1 = mL2 x M2 15 x 8.00 = 500 x M2 and M2 = 15*8/500 = ? Usually I don't use the dilution ...
Monday, April 22, 2013 at 5:55am by DrBob222

chemistry
The general dilution equation is: C1V1 = C2V2, where C = concentration and V = volume 3.0 M x V1 = 1.0 M x 500 mL V1 = 1.0 M x 500 mL / 3.0 M = 167 mL Add 167 mL of 3.0 M HCl to enough water to make 500 mL of solution
Tuesday, March 15, 2011 at 8:57pm by sharice

Chemistry
What are the units for crying out loud? Are all of them 100 mL. I will assume that is what you meant except for the dilution which I assume is 0.500 L or 500 mL. 14 g/100 = 0.14 g/mL You took 55 mL of that so you have in the aliquot of 55 mL exactly 0.14 g/mL x 55 mL = 7.70 g...
Monday, February 8, 2010 at 10:54pm by DrBob222

chemistry
Can't you use the dilution formula of mL x % = mL x % mL x 25 = 500 x 10 Solve for mL.
Tuesday, February 15, 2011 at 4:32pm by DrBob222

Calculating Dilutions
1. 1 ml serum added to 5 ml saline. 1:2 dilution is made. What is the dilution of serum in tube 6? So the serum + saline would make a 1:6 dilution. Multiply that by serial dilution of 1:2 which would give: (1/6) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) = (1/192). Is that ...
Sunday, February 3, 2013 at 5:22pm by Anonymous

College Chemistry
SURELY you have a typo. I don't know how you can dilute a 35.0 mL sample to 0.500 mL. You might dilute it to 0.500 L but not mL. I will assume you intended to write "A 35.0 mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100 mL of ...
Sunday, February 21, 2010 at 11:06pm by DrBob222

Describe how you would make 250 mL of 0.500 M HCI
Using the dilution formula M1V1 = M2V2 you would use the following calculations. ((250 mL)x(0.500 M HCl))/12.1 M HCl = 10.3 mL This means you want to add 10.3 mL of the 12.1 M HCl into a 250-mL volumetric flask and then fill the rest with distilled water up to the etch line in...
Monday, April 4, 2011 at 10:20pm by John Wheeler

analytical chemistry
What is the pH of a solution formed by mixing 14.35 mL of 0.200 F HCl with 0.322 g of Na3PO4, followed by dilution to 500.00 mL?
Tuesday, December 4, 2007 at 10:51am by Jonny

chemistry
I believe this question needs work. A dilution from 78.7 mL to 12.0 mL is a dilution?
Sunday, December 4, 2011 at 4:56pm by DrBob222

AP Chemistry
c1v1 = c2v2 6M*350 mL = c2*4.2 c2 = 500? Check that. Then 500-350 = 150 mL added. Note: That is not exact because volumes are almost never additive. The 500 total volume is correct as is the 350 mL (it was measured) but we assume that 350 mL + 500 mL = 500 mL and that isn't ...
Wednesday, September 11, 2013 at 6:19pm by DrBob222

analytical chemistry
and what would you do with the 500 mL dilution after everything?
Tuesday, December 4, 2007 at 10:51am by Jonny

Honors Chemistry
M = mols/L a. If some solvent (L) has evaporated then L is a smaller number and M goes up and it is more concentrated. b. new concn = I would use 0.500M x (35/20) = ? BUT YOU may prefer to use the dilution formula. c1v1 = c2v2 c = concentration v = volume 35 mL x 0.500 = 20 mL...
Friday, May 4, 2012 at 1:13am by DrBob222

Chemistry
c1v1 = c2v2 c = concn v = volume For example. You have 2M NaOH and you want to make 500 mL of 0.25M. How much of the 2M stuff do you take? 2M*x mL = 0.25M*500 mL mL = (0.25*500/2) = 62.5 mL So you take 62.5 mL of 2M NaOH, add to 500 mL volumetric flask and make to the mark. ...
Wednesday, January 16, 2013 at 10:41pm by DrBob222

pharmacy calculations
500 ml of a 1:5 solution contains 500*(1/5)=100 ml. of the concentrate. So if x is the volume of 1:4, then 500-x is the volume of 1:10. Hence x(1/4)+(500-x)(1/10)=500*(1/5) Solve for x to get x=333.33 ml.
Friday, August 3, 2012 at 1:08pm by MathMate

Chemistry: Dilution
mL x M = mL x M. 250mL x 0.20 M = mL x 1.0 M solve for mL of 1.0 M NaCl. Then ? mL of 1.0 M NaCl in a 250 mL volumetric flask, and make to the mark with water.
Thursday, June 4, 2009 at 7:08pm by DrBob222

chemistry
mL x M = mL x M mL x 12.0 = 500 x 3.5 mL = you can do it---about 60 mL or so. The reason I worked it through is to show you what NOT to do. You DON'T use 60 mL of the concd soln (or whatever the number turns out to be) and add 500 mL of water. Instead, you take 60 (or whatever...
Thursday, March 11, 2010 at 11:00pm by DrBob222

Chemistry
c1v1 = c2v2 50*?mL = 0.5 x 500 mL Solve for ?mL. Add ?ml stock to a 500 mL volumetric flask and make to the mark.
Friday, October 12, 2012 at 5:15pm by DrBob222

Chemistry-Please help
11.0 g/100 mL = ?? g/mL. You took 50.0 mL of this solution and diluted to 500 mL. So the final concn is 0.11 g/mL x (50 mL/500 mL) = ?? g/mL. g glucose in 100 mL = ?? g/mL x 100 mL = xx g/100 mL.
Monday, October 5, 2009 at 7:48pm by DrBob222

Chemistry
17.0 g in 100 mL. 55 mL taken diluted to 500 mL. So the glucose placed in the 500 mL flask is 17.0 x (55/100) = ?? Therefore, the concn (grams/mL) in the 500 mL flask is ??/500 mL. Multiply by 100 if you want the grams/100 mL.
Wednesday, July 7, 2010 at 8:31pm by DrBob222

chemistry
Use the dilution formula. mL x M = mL x M mL x 1M = 100 mL x 0.400 M
Wednesday, March 23, 2011 at 5:24pm by DrBob222

chemistry
Your question isn't stated very well. Do you mean something like this? Prepare 100 mL of a 500 mM HCl solution using HCl with a purity of 37% HCl and a density of 1.18 g/mL. If so, the first thing to do is to calculate the molarity of the 37% HCl solution. That will be 1000 mL...
Wednesday, March 30, 2011 at 11:26pm by DrBob222

chemistry
10.0mL of solution containing 20.0 mL of 1.0 M NaX (unknown base) and 10.0 mL of 1.0 M HX (unknown acid) was diluted with 50.0 ml water. The pH is 4.92. What is the concentration of HX after dilution and X- after dilution? What is the equilibrium concentration of HX, X-, and ...
Saturday, February 27, 2010 at 7:53pm by kelly

chemistry
The dilution formula is c1v1 = c2v2 c = concn v = volume 12.0M x 60mL = 1.85M x ?mL Solve for ? mL Actually, I think it is easier to remember mL x M = mL x M
Tuesday, April 8, 2014 at 11:36pm by DrBob222

Chemistry
What about 25 mL of 0.01M and dilute to 100. You now have 0.01M x (25/100) = 0.0025. Now dilute that by 10; 10 mL of that to 100. 0.0025M x (10/100) = 0.00025M Note: The problem doesn't say that you have TWO 100 mL volumetric flasks; if you have only one 100 mL volumetric ...
Monday, June 17, 2013 at 9:46pm by DrBob222

chemistry! URGENT
We need the molarity so we will need to be working in moles and therefore need the molar mass of the steroid. I make this C. 12 x 20 = 240 H. 29 x 1 = 29 F. 19 x 1 = 19 O. 3 x 16 = 48 total = 336 i.e. 336 g mol^-1 If 10.0 mg is dissolved taken then this is 0.0100 g /336 g mol...
Wednesday, December 7, 2011 at 1:39am by Dr Russ

see this too---chemistry
If you substitute 500 g and 0.500 L the density will be in units of g/L. If you want g/mL or g/cc, you need to substitute 500 g/500 mL = ? g/mL.
Thursday, September 6, 2012 at 7:57am by DrBob222

Chem Lab Math!
What's the molarity of the solution? 1,000 mL x 1.037 g/mL x 0.37 = ?g HCHO. ?g HCHO/molar mass = moles and that is the molarity since the solution is 1 L.Abut 13M but you need to do that more accurately than I. final M = about 13M x (1.00/500) x (1.00/5.00) = ? (Note: ...
Sunday, March 18, 2012 at 9:41pm by DrBob222

chem
I don't think your question is worded properly. I think you have 12 M HCl and want to prepare 500 mL of 0.4M. c1v1 = c2v2 12*mL = 0.4*500 Solve for mL of the 12 M material. Place that in the 500 mL volumetric flask and make to the mark. Shake thoroughly.
Tuesday, October 16, 2012 at 5:21pm by DrBob222

Chemistry 151
Use the dilution formula for these. c1v1 = c2v2 c = concn v = volume for a. 100 mL x 0.1M = ? mL x 1M Solve for ?mL of the 1M. b. 250 mL x 0.5M = ? mL x 1 M Solve for ?mL of 1 M.
Sunday, March 16, 2014 at 5:18pm by DrBob222

science
3ml of 2M NaOH is added to 27 ml of destilled water. what dilution is made? what is the concetration of Naoh in the dilution?
Thursday, August 16, 2012 at 10:02pm by alen

chemistry
The dilution formula, which works for M, m, and N (perhaps others) is mL x % = mL x %. Substitute and solve for mL.
Sunday, December 5, 2010 at 8:04pm by DrBob222

math
You are a lab technician and must create 250 ml of a 17% salt-solution. a. If you have 500 ml of 28% salt-solution, how many milliliters of it should you mix with water in order to create 250 ml of a 17% salt-solution? b. If you have 400 ml of 40% salt-solution, how many ...
Wednesday, February 15, 2012 at 8:45am by Fatih

Calc
You are a lab technician and must create 250 ml of a 17% salt-solution. a. If you have 500 ml of 28% salt-solution, how many milliliters of it should you mix with water in order to create 250 ml of a 17% salt-solution? b. If you have 400 ml of 40% salt-solution, how many ...
Thursday, February 16, 2012 at 10:16am by Fatih

Chemistry-need help ASAP
15 ml of 3.0 M NaOH are added to the following: 500.0 ml of pure water 500.0 ml of 0.1 M formic acid 500.0 ml of 0.1 M formate of potassium 500.0 ml of a solution containing 0.1 M formic acid and 0.1 M formate of potassium. Calculate the difference of pH resulting from the ...
Monday, April 14, 2014 at 8:40pm by Sam

chemistry dilution
Typos Add 6.67 x 10^1 mL of solvent to 1mL of stock. Converting everything to ug/mL, 200/3 =6.67 x 10^1 mL 200ug/(6.67 x 10^1 mL +1 mL)= 2.96ug/mL
Wednesday, February 27, 2013 at 8:54pm by Devron

Chemistry
Use the dilution relationship (Mi x Vi = Mf x Vf) to calculate the volume of 0.500 M NaOH needed to prepare 500 mL of .250 M NaOH. This is my work ? L Solution = 500mL x (1L/1000mL) = .500L ? mol NaOH = .500 L Solution x (0.250 M NaOH/1 L Solution) = .125 mol NaOH ? L solution...
Saturday, February 28, 2009 at 9:35pm by Bob

Chemistry
500 mL x 0.1M = ?mL x 2.0M Solve for mL, measure that quantity of 2.0M NaOH and make up to 500 mL with DI water.
Wednesday, March 28, 2012 at 1:39pm by DrBob222

Chemistry
You didn't follow the instructions and I don't see that you used MxV= MxV ?? mL x 0.500 M = 500 mL x 0.250 M ?? mL = 500 x 0.250/0.500 = 250 mL.
Saturday, February 28, 2009 at 9:35pm by DrBob222

Chemistry
1.8 g glucose/180 = 0.01 mole. So 0.01 mole/L is the stock soln. a. 0.01M x (50 mL/500 mL) = ?M b. ?M x (1.0 mL/100 mL) = x M or x*1000 uM. Technically, one cannot calculate values for a or b because volumes are not additive; however, since the concn is so low the difference ...
Monday, August 29, 2011 at 1:24pm by DrBob222

CHM 152
1.06 g/mL x 1000 = 1060g is mass 1000 mL soln. This 1000 mL soln consists of 500 mL ethylene glycol and 500 mL H2O(equal volumes of ethylene glycol and H2O). The mass of 500 mL ethylene glycol is 500 x 1.114 g/mL = 557 grams or 557/62.07 = 8.97 moles ethylene glycol per 1000 ...
Tuesday, June 8, 2010 at 12:06am by DrBob222

Chemistry
1. mL x M = mL x M 500 x 4.5 = mL x 18.0 Solve for mL of the 18.0. Remember volumes are not additive; therefore, you can't use 125 mL of the 18.0 M stuff and add 375 mL water. The way you do it is to place 125 mL of the 18.0 stuff in a 500 mL volumetric flask and add water to ...
Tuesday, August 17, 2010 at 11:14pm by DrBob222

chemistry
What volume of 2.00 M HCl must you use to prepare 100. mL of 0.500 M HCl? (Hint: Just use the dilution equation! MiVi = MfVf)
Tuesday, December 6, 2011 at 2:23pm by kathy

Chemistry - %v/v
I think #1 needs more work. %v/v = [(mL solute/mL SOLUTION)]*100 = ? 50 mL acetone + 500 mL methanol is more than 500 mL total volume. Assuming the volumes are additive (probably they are not), then [(50/550)]*100 = 9.1%
Sunday, June 2, 2013 at 2:00pm by DrBob222

Chemistry Lab
5.00 mL x 0.005 M = 0.025 millimoles Fe^+3. What is the volume? I see 5 mL + 5 mL + 10 mL = 20 mL. So the initial concn is 0.025 millimoles/20 mL = ?? M If you would rather work as a dilution, it can be done this way: 0.005 M has been diluted by a factor of 5.00 mL/20.00 mL...
Monday, February 22, 2010 at 9:01am by DrBob222

Chemistry
What mass of NaOH is required to create 500 mL of a .4 M solution of Sodium Hydroxide(aq)?
Thursday, February 13, 2014 at 8:30pm by Scott

chemistry dilution
Add 6.67 x 10^1 mL of solvent to 1mL of stock. Converting everything to ug/mL, 200/3 =6.67 x 10^5 uL or 6.67 x 10^1 mL 200ug/(6.67 x 10^5 mL +1 mL)= 2.96ug/mL
Wednesday, February 27, 2013 at 8:54pm by Devron

lab procedures
After reconstitution with 1.5 ml diluent, a 500 mg vial of ceftazidime injection yeilds an approximate volume of 1.8 ml.Each ml contains approximately 280 mg.If 500 mg IM are ordered, how many ml should be administered?
Thursday, September 13, 2007 at 6:50pm by GENE

chemistry!
[blank] mL of 6.0 M H2SO4 are needed to prepare 300 mL of 1.0 M H2SO4 solution. 50 mL x M = mL x M (works for dilution problems but not for all stoichiometry problems.)
Sunday, April 29, 2007 at 11:48pm by Emi

chemistry
There is a simple dilution formula you can use for all of these. c1v1 = c2v2 c = concentration v = volume 1M x ?mL = 0.1M x 100 mL ?mL = (0.1M x 100 mL)/1M = 10 mL
Saturday, March 29, 2014 at 12:21am by DrBob222

Chemistry
You want 10% m/v. That means 10 g Mg2SO4 per 100 mL soln. Convert that to 500 mL. 10g x (500/100) = ? g/500 mL.
Monday, February 18, 2013 at 8:39pm by DrBob222

dilution please help
How to use serial dilution to dilute a stock solution at 15000 fold dilution?
Saturday, February 16, 2013 at 12:11pm by John

Chemistry- dilution
51.0 mL of a 1.20 M solution is diluted to a total volume of 248 mL. A 124-mL portion of that solution is diluted by adding 125 mL of water. What is the final concentration? Assume the volumes are additive.
Sunday, October 13, 2013 at 1:51pm by Chelsea

chemistry dilution
This is a confusing problem. Here is another approach. We have a soln that is 200 ug/mL. We want 3 ug/100 uL. That is 0.003 ug/uL = 3 ug/mL Say we want to make 100 mL of this solution, then 3 ug/mL x 100 mL = 300 ug we need. 200 ug/mL x ?mL =300 ug ?mL = 300/200 = 1.5 mL; ...
Wednesday, February 27, 2013 at 8:54pm by DrBo222

chemistry
I have an easier way to understand. you want 18M to 3M? that is a dilution of 6 times. So you want 1 part original, 5 parts water. so, what is one part: in this case it is given: 25ml so what is five parts: 125 ml. to give a new total volume of acid at 3M of 150ml. Try my ...
Saturday, December 11, 2010 at 8:29pm by bobpursley

microbiology
This is an inverse proportion problem: 5*10^8*1 = 1*10^3*V V=5*10^8 / (1*10^3) =5*10^5 times the initial volume. So the dilution is 1 ml of the initial solution and 5*10^5-1 = 499999 litres diluent (water?) to make a total volume of 500000 ml, or 500 litres of diluted "solution".
Sunday, May 8, 2011 at 8:16pm by MathMate

Chem
1.5% w/v means 1.5 g HCl in 100 mL soln. You want 500 mL; therefore you will need 1.5 x (500/100) = g KCl in 500 mL soln.
Thursday, October 11, 2012 at 5:04pm by DrBob222

chemistry
0.500 WHAT? liters? 11.5 g/100 = 0.115 g/mL original. 25 mL x that = grams in 500 mL. Divide by 5 to find grams in 100 mL.
Sunday, January 31, 2010 at 8:42am by DrBob222

chemistry
Same two formulas. Or you could use the dilution formula of mL x M = mL x M
Thursday, January 14, 2010 at 4:16pm by DrBob222

lab math
If 0.5 ml of serum is added to 1.5 ml of saline, what is the dilution
Thursday, November 3, 2011 at 6:51pm by Shaquilla

Please Help Fast
10.5 g/100 mL = 0.105 g/mL. You took 20 mL which contains 20 x 0.105 g/mL. Now you diluted that 20 to 500 so the 500 now contains 20 x 0.105 g/mL = 2.10 g so you now have 2.10/500 mL = 0.00420 g/mL. How much is in 100 mL of that solution?
Thursday, February 12, 2009 at 12:29am by DrBob222

chemistry
10.5 g is in a 100; therefore, 10.5/100 = 0.105 g/mL. Now take 60.0 of that solution is diluted to 500 mL. So we have 10.5 g/mL x 60 mL = xx grams and that divided by 500 = yy g/mL. Now multiply that by 100 to know how much is in 100 mL. Check my thinking.
Tuesday, October 6, 2009 at 7:13pm by DrBob222

Instrumental Chem Lab
I didn't plot the data and I can't verify the equation you have for the line; however, just looking at the data suggests that unknown 2 must have a concn of about 7 mg/100 mL [I used 5 mg/100 x (about 15/about 8) = about 9 mg/100 mL) and 10 mg/100 mL x (about 8/about 15) = ...
Saturday, April 16, 2011 at 4:09pm by DrBob222

Chemistry
A chemist wants to be a supercook and wants to create 8%(m/v) acetic acud solution to be "extra strength" vinegar. if pure acetic acid Is a liquid density of 1.049 g/ml. how many ml of acetic acid should be dissolved to male 500 ml of 8% acetic acid? Calculate grams of acetic ...
Sunday, April 22, 2012 at 9:43am by Kate

Chemistry
I think your post is stated awkwardly. I assume you want to dilute 30% H2O2 to make 20 mL of a 3% solution. If that is true, use the dilution formula. c1v1 = c2v2. 30% x mL = 3% x 20 mL. Solve for mL of 30% stuff you need to take
Friday, September 28, 2012 at 11:26pm by DrBob222

chemistry
The question as posed makes little sense in terms of significant figures and practicalities. You would not use glassware of 500.00 ml +/- 0.01 ml (5 sig figs) to prepare a solution of 0.25 M (2 sig figs). Incidently a standard 500 ml class A volumetric glassware has an ...
Monday, October 4, 2010 at 1:39am by Dr Russ

Chemistry
I would use the dilution formula. c1v1 = c2v2 1M x V1 = 0.600 x 1000 mL Solve for V1 in mL; place that # mL in a 1 L volumetric flask, make to the mark, shake thoroughly.
Friday, October 19, 2012 at 1:04pm by DrBob222

chemistry
Are you asking how to dilute the HCl? If you are intending to dilute using a volumetric flask then it is a good idea to add acid to water than water to acid, although it is not as crucial with conc HCl (Cf H2SO4). The dilution will still get warm. My sequence would be to place...
Monday, October 11, 2010 at 5:57am by Dr Russ

chemistry
100 grams H2O x (500/37.5) = about 1330 mL. Or look at it this way. 37.5 g NaCl/100 mL = 0.375 g NaCl/1 mL. So (0.375 g NaCl/mL) x ??mL = 500 g Solve for ??mL.
Monday, January 17, 2011 at 6:56pm by DrBob222

chemistry
First you determine the molarity of te H2SO4 (and note that you made a typo). The density of conc H2SO4 is 1.80 g/mL (not 1.80 g/L). mass H2SO4 in 1L = 1000 mL x 1.80 x 0.98 = ? Then mols = grams/molar mass and since that's the mols in 1L soln that is the molarity. For the ...
Wednesday, July 31, 2013 at 7:31am by DrBob222

Chemistry
dilution problems can be solved with this. M x mL = M x mL.
Wednesday, March 10, 2010 at 3:11pm by DrBob222

Chemistry
mL x M = mL x M or L x M = L x M There aren't many dilution problems this one can't do.
Thursday, December 9, 2010 at 9:45pm by DrBob222

Chemistry-Confused by titration!!
mL x M = mL x M (Technically this is the dilution equation but you may use it in titrations in which the ratio of the titrant to the unknown solution is 1:1).
Monday, December 13, 2010 at 2:20pm by DrBob222

Chemistry
Calculate the pOH of an aqueous solution of 146.6 ml of 0.000625 M HBr(aq) after dilution to 850 ml.
Thursday, March 21, 2013 at 1:37am by Mary Ann

Chemistry
Calculate the pOH of an aqueous solution of 146.6 ml of 0.000625 M HBr(aq) after dilution to 850 ml.
Thursday, March 21, 2013 at 1:37am by Mary Ann

Chemistry
Calculate the pOH of an aqueous solution of 146.6 ml of 0.000625 M HBr(aq) after dilution to 850 ml.
Thursday, March 21, 2013 at 1:37am by Mary Ann

chemistry
Use the dilution formula c1v1 = c2v2 c = concn v = volume. 0.015M x 10mL = 0.10M x ?mL. Solve for ?mL.
Tuesday, May 21, 2013 at 5:40pm by DrBob222

Chemistry
You are a lab technician and must create 250 ml of a 17% salt solution. You have available three stock solutions. You have a one liter container of a 5% salt, a 500 ml container of a 28% salt solution, and a 400 ml container of a 40% salt solution. Discuss and explain the ...
Monday, March 5, 2012 at 11:35am by Fatih

chemistry
Use the dilution formula of c1v1 = c2v2 c = concn v = volume 300mL x 2M = 50M x mL Solve for mL of stock.
Friday, February 1, 2013 at 12:17pm by DrBob222

chemistry
So we have prepared 19.0 g glucose in 100 mL. We now have a 19/100 = 0.19 g/mL (that is, 0.19 g glucose per mL solution). We take a 20 mL sample of that and place a container. How many g glucose did we transfer? We transferred 0.19 g/mL x 20 mL = 3.8 g to the container. Now we...
Sunday, February 28, 2010 at 2:08pm by DrBob222

Chemistry-Repost for DrBob222
Well, it's this way. If you read the problem, as I did, the first line says you want to prepare 500 mL of a buffer. When I read that I quit reading and wrote instructions for preparing 500 mL of said buffer. You read the whole problem, which I should have done, and saw the 3L...
Friday, March 21, 2014 at 2:34pm by DrBob222

chemistry
mL x M = mL x M is the dilution formula.
Monday, April 12, 2010 at 11:02pm by DrBob222

Chemistry
The dilution formula is mL x M = mL x M
Thursday, October 7, 2010 at 5:34pm by DrBob222

chemistry
The dilution formula is mL x M = mL x M
Monday, January 3, 2011 at 4:42pm by DrBob222

Chemistry
The dilution formula is mL x % = mL x %
Monday, February 21, 2011 at 10:26am by DrBob222

Chemistry (URGENT)
The problem is giving you 0.150M as the molarity and it tells you the new molarity will be the old one (0.160) x the dilution factor). After diluting, the first one will be 0.160 x (12mL/16mL) The next one is 0.160 x (8 mL/16 mL). However, from the way the problem is states I ...
Wednesday, December 15, 2010 at 8:18pm by DrBob222

chemistry
Please help me with this dilution. Given a very concentrated tube of virus. Apply serial dilution to make 1:7500 dilution. Dilute virus in PBS
Saturday, February 16, 2013 at 10:26am by Jen

chemistry dilution
Did it again, Add 5.67mL of solvent to 1mL of stock to get a total volume of 6.67mL. Converting everything to ug/mL, 200/30 =6.67mL 200ug/(5.67mL +1 mL)= 29.9ug/mL
Wednesday, February 27, 2013 at 8:54pm by Devron

Chemistry 12
The original 10 ml (KIO3) solution is 0.020M is mixed with 10 mL of 0.0020M NaHSO3 which give a total volume of 20 mL. Calculate the concentration of KIO3 in the final mixture of the dilution.
Wednesday, October 2, 2013 at 9:19pm by Raj

chemistry
500.0 mL x 0.200M = xmL x 15.0M(although you didn't write M). Solve for x and I get 6.667 mL. In practice you add 6.667 ml of the 15.0M NaOH to a 500.0 mL volumetric flask and add water to the mark on the flask. Note that you DO NOT add 6.667 mL NaOH to 493.3 mL H2O.
Sunday, November 6, 2011 at 7:43am by DrBob222

Chemistry
You want 5.9 g CuCl2 in 52.0 mL. The molar mass CuCl2 is 134.451 so 5.9/134.451 = 0.0439 moles. That in 52.0 mL = 0.0439 moles/0.052 L = 0.844 M is the concn of the solution you want to end up with. 124 mL x 8.10M = ?? mL x 0.844M Solve for ?? mL and that will be the volume ...
Wednesday, August 4, 2010 at 6:02pm by DrBob222

chemistry
What volume of WATER MUST BE ADDED to 10.0 mL of 6.0 M NaOH to make a solution that is 0.30 M in NaOH? Assume that the volumes are additive. a. 10 mL b. 190 mL c. 200 mL d. 210 mL e. 500 mL
Monday, March 29, 2010 at 6:30am by lawrence

chemistry
Serial dilution is starting with a stock solution, then diluting it, for example, 10 times. If we dilute the first dilution 10 times, we get a second dilution which is 100 times more dilute than the stock solution. We can continue to dilute the last dilution and achieve a ...
Monday, May 4, 2009 at 8:10pm by GK

Chemistry
mL x M = mL x M 500 mL x 0.200 M = mL x 12 M solve for mL.
Tuesday, June 8, 2010 at 1:42am by DrBob222

pharmaceutical calculation
We ignore the dilution of the dextrose. Assume the volume of injection is x ml, which contains 300mg/2ml, or 150mg/ml, or 0.15 g/ml Volume of injection required = 2/0.15 = 13.3 ml Volume of D5W = 1000-x = 983.7 ml Total volume = 1000 ml total antibiotic = 13.3*0.15 = 2 g
Saturday, January 8, 2011 at 10:47pm by MathMate

Chemistry
A solution is prepared by adding 300 mL of 0.500 M NH3 and 100 mL of 0.500 M HCl. Assuming that the volumes are additive, what is the pH of the resulting mixture? Kb for ammonia is 1.8 x10 -5
Monday, October 4, 2010 at 10:11pm by Taylor

chem
I can't remember the details of the problem and my answer. I think the alcoholic beverage was 100 proof which means 50% v/v (volume/volume). That means we have 500 mL ethanol + 500 mL water (assuming water and alcohol volumes are additive and they are not), so you convert 500 ...
Wednesday, February 13, 2008 at 4:33pm by DrBob222

Chemistry
12.0 g/100 mL 0riginal. Take a 50.0 mL aliquot so now you have 6.0 g in the 50.0 mL. That is diluted to 500 mL so now you have 6.0 g in 500 mL. If you take 100 mL of that solution you will have 1/5 of 6.0 = ??
Wednesday, September 29, 2010 at 2:54am by DrBob222

chemsitry
I usually do too much work to do these dilution problems but I go about it this way. The first one. 1000 ug/mL x 100 mL = 100,000 ug in the 100 mL flask. We want 30 ug/mL x 50 mL = 1500 ug in the 50 mL flask. (100,000/100 mL) x ? = 1500 and ? = 1500 x 100/100,000 = 1.5 mL. To ...
Sunday, January 31, 2010 at 12:10pm by DrBob222

Chemistry help!!
A chemist wants to be a supercook and wants to create 8%(m/v) acetic acud solution to be "extra strength" vinegar. if pure acetic acid Is a liquid density of 1.049 g/ml. how many ml of acetic acid should be dissolved to male 500 ml of 8% acetic acid? It says to first calculate...
Sunday, April 22, 2012 at 12:42pm by Kate

Dilution
What volume of H2O should be added to 500 ML of a 1.0 mol/L CuSO4 solution to dilute it to 0.5 mol/L? This is what I have so far... H20 + CuSO4 --------> H2SO4 + CuO So you use the formula M1V1 = M2V2 so its (0.500)(1.0) = (0.5)(V) Solve for V, I got 1.0 L. HOWEVER, the ...
Monday, January 29, 2007 at 12:28pm by Rienna

Pages: 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | Next>>

Search
Members