Wednesday

April 23, 2014

April 23, 2014

Number of results: 3,367

**Applied Calculus**

This is a chain rule. (the derivative of the whole thing times the derivative of what is in the parenth.) first derivative: (1/2)(5) (5t+4)^-1/2 Take the derivative of the above for the second derivative. Take the derivative of that answer again and you will have the 3rd ...
*Wednesday, February 20, 2013 at 6:24pm by JJ*

**math**

Let f be a real value function and x Df then 0 lim ( ) ( ) h f x h f x h + - when it exists is called A) The derivative of f at a B) The derivative of f at h C) The derivative of f at x D) The derivative of f at x = h
*Friday, November 2, 2012 at 12:26am by Zaheer*

**math**

If I understand your notation correctly, you want the 725th derivative of sin x ?? 1st derivative of sin x = cosx 2nd derivative = -sinx 3rd derivative = -cosx 4th derivative = sinx Ahhh, we are back where we started from. so the 5th derivative = cos x ,etc. 725 4 = 181 with...
*Thursday, October 15, 2009 at 5:37pm by Reiny*

**Calculus**

second derivative is derivative of first derivative on wolframalpha dot com type : derivative 4 ( x - 3 ) / [ 2 x ^ 2 - 12 x + ( y -10 ) y ] and click option = then Show steps
*Friday, May 4, 2012 at 8:27am by Bosnian*

**calc arc length**

You need to integrate sqrt[1+f'(x)^2] from x = 0 to pi/3. Computing the derivative of f(x) is not difficult, you can use the chain rule, substitute u = x^3 for the upper limit and use that the derivative w.r.t. x is the derivative w.r.t u times the derivative of of u w.r.t. x...
*Wednesday, December 19, 2012 at 5:36pm by Count Iblis*

**Calculus Derivative- Taylor Series?**

your first derivative should have been: y' = -1(x-1)^-2 then y'' = 2(x-1)^-3 y''' = -6(x-1)^-4 ----> the third derivativ y'''' = 24(x-1)^-5 ----> the 4th derivative y''''' = -120(x-1)^-6 ---> the 5th derivative did you notice that the numbers 1 , 2, 6, 24 , 120 are ...
*Sunday, March 10, 2013 at 5:37pm by Reiny*

**Calculus**

Differentiate f(x) to get f'(x), then substitute a for x. Let u = 1 + x Then you want the derivative of ( (2u-1)/u. That is the derivative of -1/u (since the derivative of 2u/u is 0). The derivative is therefore is u^-2 = 1/(1+x)^2 That becomes 1/(1+a^2)when a is substituted ...
*Monday, February 15, 2010 at 12:25am by drwls*

**math derivative please help**

the derivative of 2x^e is zero right or no? do i have to use the log formula 2 x^e is x to the power 2.718.. It is not a constant and therefore the derivative is not zero. Use the formula for the derivative of x to a power that is constant (x^a). The formula for that may ...
*Sunday, September 24, 2006 at 10:26pm by Anonymous*

**Calculus**

The derivative of a product. The rule is: the first times the derivative of the second PLUS the second times the derivative of the first. simplify your answer. The derivative of the first: 4x-2 The derivative of the second -3x^-4 -8x^-5 Can you finish with these hints?
*Friday, February 22, 2013 at 10:38am by JJ*

**calculus **

The derivative of -x^2 is -2x. The derivative of x is 1. Add the two terms. In general, the derivative of any term that can be written a*x^n, where a and n are constants, is n*a*x^(n-1)
*Thursday, December 30, 2010 at 12:29am by drwls*

**calc**

derivative of (x^3/6)+(1/2x)? i got (x^2/2)-(1/2x^2) is that correct? and then wut is the (F'(x))2?...meaning the derivative squred? if you meant (1/2)x^2 - 1/(2x^2) you are correct I don't think they are looking for the square of the derivative, but rather the second ...
*Sunday, May 6, 2007 at 1:09pm by MARY*

**Calculus Derivative**

I'm still not quite sure how that works out, if you can explain it please? Isn't the derivative of v dv/dt and the derivative of m (since it's a constant) 0?
*Wednesday, March 6, 2013 at 3:38pm by Mary*

**Calculus**

You were given: Find the derivative of f 0f x. f(x) = x^2 - 8x - 17 at x = 4 We first find the derivative of the given function and then replace x with 4 in the derivative we will find. I will use the power rule to find the derivative of your function. The Power Rule: The ...
*Monday, January 7, 2008 at 5:56pm by Guido*

**Calculus**

That is the derivative. d/dt (t^3/3) = t^2 Since you asked for the derivative, I derived the derivative.
*Sunday, December 9, 2007 at 3:11pm by Damon*

**Calculus**

is that ln (x^2) or (ln x)^2 ? anyway, in any case, it is not differentiable at x = 0 because if you get the derivative, for ln (x^2): ln (x^2) = 2*ln x derivative of 2*ln x = 2/x for (ln x)^2: derivative (ln x)^2 = 2*(ln x)/x if you substitute x=0 to the derivative, the ...
*Friday, October 29, 2010 at 12:42am by jai*

**Derivatives- Math**

Can someone explain how to find the derivative of : 1. y= 5^x / x And the second derivative of: y= xe^10x For this question I got up to the first derivative and got this y = e^10x + 10xe^10x but I can't seem to get the correct answer for the second derivative.
*Monday, April 19, 2010 at 8:38pm by Mae*

**Calculus**

The zeros of the derivative or the zeros of the function ? I will assume you want the zeros of the derivative. factor it first = x^2(x-1)^3[4x + 3(x-1)] = x^2(x-1)^3(7x-3) we set this equal to zero to get x = 0, x = 1 and x = 3/7 remember that the function increases when the ...
*Sunday, December 13, 2009 at 9:56pm by Reiny*

**calculus**

Do you mean e^(2x)? The first derivative is 2 e^2x, and its value at x = 0 is 2. The second derivative is 4 e^2x, and its value at x=0 is 4. You should be able to figure out the nth derivative, and apply the Taylor series formula. If you don't know it, now is a time to learn ...
*Thursday, October 7, 2010 at 3:42am by drwls*

**cal**

Recall the chain rule. If two expressions which are functions of x are multiplied, we do the following: h(x) = f(x)*g(x) h'(x) = f'(x)*g(x) + f(x)*g'(x) As we can see, the derivative of h(x) is the derivative of f(x) multiplied by the original g(x), plus the derivative of g(x...
*Thursday, October 24, 2013 at 2:23pm by Jai*

**Calculus**

I need to find the second derivative of y=x(x-1)^1/2. I found the first derivative is 2x-1/2(x-1)^1/2, if someone could check, but I am miserably stuck on the second derivative.
*Monday, April 18, 2011 at 1:28am by Amie*

**calculus**

when you take the derivative of something for exaple y = 3x^3 +2x^2+3 it's y' = 9x^2 + 4x the equation y' is the derivative of the original equation- which was cubic- the derivative becomes quadratic.
*Friday, November 2, 2012 at 7:24pm by Sanya *

**Calc**

f(x) = e^(−3x) + 5e^(4x) Note that the derivative of e^x is equal to e^x times the derivative of the exponent with variable x: d/dx (e^x) = e^x dx applying this, f'(x) = -3e^(-3x) + 20e^(4x) : First derivative f''(x) = 9e^(-3x) + 80e^(4x) : Second derivative
*Tuesday, July 17, 2012 at 3:51pm by Jai*

**Calculus derivatives**

The derivative f'(a) is the sum of the derivative of a and the derivative of sqrt a. In this case, a is treated as a variable, not a constant. The answer is 1 + 1/(sqrt a)
*Monday, October 27, 2008 at 5:27am by drwls*

**Calculus**

Well the Sqrt(4sin(x)+2) is the same thing as saying (4sin(x)+2)^(1/2)....sooo take the derivative using the chain rule. So first you would take the derivative of the outside by bringing the (1/2) and subtracting one from the exponent. Then take the derivative of the inside. 4...
*Wednesday, December 8, 2010 at 9:01pm by Nisa*

**calculus**

The maximum is where the first derivative is zero, provided the second derivative is negative there. Solve the equation f'(x) = -x^2 +6x -5 = 0 -(x-5)(x-1) = 0 x = 5 and x = 1 are either maxima or minima. Use the second derivative test to see which is which.
*Tuesday, June 16, 2009 at 2:00pm by drwls*

**Calc-please help!**

What is the second derivative of (x^3)/(x^2-1)? And how would I accurately graph both the derivative and the second derivative of this function?
*Tuesday, November 1, 2011 at 4:59pm by Haley*

**math**

The derivative of a function tells you the instantaneous rate of change of the function at every point. The first derivative tells you the slopes of the function The second derivative tells you the slope of the slope (aka. the concavity) First derivative = 0 or undefined =>...
*Thursday, May 19, 2011 at 6:32pm by Anonymous*

**Calculus (Continuity and Differentiability)**

If they form a corner, there are two values of the derivative at that point, the different slopes on each side of the corner. By the way, the second derivative is undefined there since the first derivative changes instantly.
*Saturday, November 12, 2011 at 3:43pm by Damon*

**math**

Find the derivative of y=3x-2(4^x) Here is my attempt: Derivative of 3x is 3 Derivative of 2 is 0 derivative of 4^x is 4^x(ln(4)) Answer: 12^x(ln(4)) Is this correct? If not please explain what I did wrong and what the correct answer is and why. Thanks!
*Tuesday, October 15, 2013 at 2:40pm by Anonymous*

**calculus**

Please help with this. I need the first derivative of f(x)=4(x+squareroot (x(8-x)) and then the second derivative of this to show by the second derivative test that it is a local maximum. This is difficult to put into form here and I hope I have got it right. Many thanks.
*Thursday, February 24, 2011 at 3:08pm by Frank*

**Calculus**

You can find the slope of the tangent line by setting the first derivative equal to zero and solving for x. rewrite sqrt x as x^1/2 This becomes the derivative of a quotient. The denominator times the derivative of the numerator minus the numerator times the derivative of the ...
*Monday, March 11, 2013 at 2:52pm by Dr. Jane*

**Calculus**

The answer to question 1) is indeed sqrt( 1 + X^6) * 3x. You can put x^3 = y and differentiate w.r.t. y and then multiply by the derivative of y w.r.t. x (chain rule). The derivative w.r.t. y is sqrt(1+y^2) =sqrt(1+x^6) and the derivative of y w.r.t. x is 3 x^2.
*Wednesday, December 5, 2007 at 3:16am by Count Iblis*

**Calculus**

he was starting from where you left off with your derivative. the first time you wrote "so far I know how to find the derivative which is 4x^3-2x now I am stuck... Please help " that derivative is wrong. it is simply the one he used, hence the wrong answer.
*Friday, March 9, 2007 at 10:51am by joey*

**high school calculas**

h'(x) = -2/x^2 a function is increasing when its first derivative is positive, and a function is decreasing when its first derivative is negative. now look at our derivative, notice the bottom is a square of x, so no matter what you put in, the result will be positive, and ...
*Thursday, November 6, 2008 at 8:27pm by Reiny*

**calculus**

What I did was for the first derivative. You can proceed in a similar way for the second derivative, but I guess substitution is out. Take the derivative of what you've got as a product. u=(t^2 + 5)^7 v=16t d(uv)/dt = udv/dt + vdu/dt
*Wednesday, June 29, 2011 at 4:28pm by MathMate*

**Calculus--> bobpursley**

How do you get m=0? from taking the second derivative? does c=1? Can you check my work on how I get the derivative of R=M^2(c/2-m/3) NEXT R=1/2(CM^2)-1/3(M^3) NEXT dR/dM=CM-M^2. I checked in the back, and that was the answer for the first part of the equation. Isn't the ...
*Wednesday, May 30, 2007 at 6:34pm by Anonymous*

**Calculus (Continuity and Differentiability)**

In that case, the derivative is continuous. The 2nd derivative will not be continuous at the cusp. The function whose derivative is the v-shaped graph, will also be continuous, but display a sharp corner where the two parabolas intersect.
*Saturday, November 12, 2011 at 3:43pm by Steve*

**Math (Calculus)**

y=x2x+1 Find the derivative of the expression. (2x+1) To find the derivative of 2x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term. 1 Since 1 does not contain x, the derivative ...
*Wednesday, May 7, 2008 at 1:19pm by Anonymous*

**Differentiation**

Again, that all makes sense. Thank you very much. Thank you very much. I did get the derivative you show, but then divided thru by 6 to get at the stationary points. Was that wrong? I'm only looking for a critique please, not answers! given: f(x)= −2x 3 +21x 2 − ...
*Wednesday, June 20, 2007 at 7:02am by CharlieGolf*

**calculus**

Okay but now I'm confused because when I find the derivative of the volume I get dv/dt=2s(ds/dt) then I don't know the rest because I have to find the derivative for 108/4s -s/4 which equals to h but what would be its derivative?
*Saturday, January 3, 2009 at 4:25pm by Barbara*

**Calculus**

Take the derivative of the function because the derivative is equal to the slope of the tangent line. a horizontal line has a slope of zero. Set you derivative = 0 and solve for x. That should give you the correct value of x.
*Thursday, February 21, 2013 at 4:38pm by JJ*

**calculus**

Please help with this. I submitted it below and was asked to clarify by Henry (hope this is clearer and thank you). I need the first derivative of f(x)=4(x+ sqrt (x(8-x)).And then the second derivative of this to show by the second derivative test that it is a local maximum. ...
*Friday, March 4, 2011 at 1:48pm by Frank*

**12th Calculus**

I will assume you really meant to write the derivative y' and not the function y although I would have thought the book would ask you to find that derivative. Wherever that derivative, y', is zero, the curve is horizontal This is twice at x = 1 and at x =2 and at x = 4 Look at...
*Tuesday, November 11, 2008 at 7:35pm by Damon*

**caluculus**

Multiply it out and differentiate it term by term. You will end up with four terms. The derivative of your polynomial is the sum of the derivatives of the individual terms Use the rule that the derivative of a*x^n is a*n*x^(n-1) The derivative of a constant is zero
*Friday, October 10, 2008 at 3:47pm by drwls*

**calculus**

Find the derivative of the function using the definition of derivative. g(t)= 9/sqrt(t) g'(t)= state the domain of the function and the domain of the derivative (use interval notation)
*Wednesday, September 19, 2012 at 10:07pm by maura urgent!!*

**calculus**

Differentiate both sides of the double angle identify sin 2x= 2 sin x cos x to determine an identify for cos x. Find the first derivative, second derivative, third fourth, fifth, sixth, seventh and eighth derivative. Use the results to find the twelfth and fifteenth derivative...
*Tuesday, February 21, 2012 at 7:42pm by john *

**Applied Calculus**

The derivative of a constant is 0 The derivative of 340 = 0 The derivative of 340x would be 340 The derivative of 340x^2 would be 680x.
*Monday, February 11, 2013 at 1:05pm by JJ*

**Calculus**

Any help would be much appreciated with the steps involved in each problem given. Thank you. 1) Find derivative if y =cot x + sin x 2) Find derivative if y = (3x+5)^8 3) Find derivative if y = x csc x 4) Find derivative if y = x 3x + 1 (3x + 1 is under the square root) 5) ( ...
*Sunday, September 30, 2007 at 9:03pm by Matt*

**Chain Rule**

Any help would be much appreciated with the steps involved in each problem given. Thank you. 1) Find derivative if y =cot x + sin x 2) Find derivative if y = (3x+5)^8 3) Find derivative if y = x csc x 4) Find derivative if y = x 3x + 1 (3x + 1 is under the square root) 5) ( ...
*Wednesday, September 26, 2007 at 5:47pm by Matt*

**Calculus**

If I have a function f(x), and am given its derivative, f'(x): may I take it as a given that f(x) is an integral of f'(x). My reasoning is that 'undoing' the derivative gives me the derivative. Eg is 1/3x^3 an integral of x^2? Thanks.
*Saturday, September 15, 2007 at 7:52am by charlie*

**calculus**

Find the first and second derivative - simplify your answer. y=x/4x+1 I solved the first derivative and got 1/(4x+1)^2 Not sure if I did the first derivative right and not sure how to do the second derivative.
*Wednesday, March 16, 2011 at 11:56pm by Janet*

**Math - derivative of a rational function**

find the 1st derivative of f(x) = x/(x-1)2 Is the 1st derivative f'(x)= -x-1/(x-1)^3
*Friday, October 29, 2010 at 6:48am by Farah*

**Math I'm so confused**

Set the derivative equal to zero and see if there is a solution in that interval. 2x - 1 = 0 x = 1/2 Now plot it (or take the second derivative f''(x) = 2) to see if that is a maximum or a minimum. If you have not learned what a derivative is, complete the square of the f(x) ...
*Wednesday, March 30, 2011 at 11:38am by drwls*

**Math - derivative of sinusoidal (check)**

a) Find a function y=f(x) that satisfies the differential equation dy/dx = fifth derivative. This is one of the questions in my practice test, I tried the basic equation of the trig function such as f(x)= sin(x) or f(x)=-sin(x) however in the fourth derivative they reach the ...
*Monday, November 29, 2010 at 5:53am by Farah*

**Calculus**

take the first derivative .... a) f is increasing for all values of x for which f '(x) is positive f is decreasing for all values of x for which f '(x) is negative take the second derivative c) if the second derivative is positive, f is concave up d) if the second derivative ...
*Monday, November 29, 2010 at 9:53pm by Reiny*

**Calculus**

Any help would be much appreciated with the steps involved in each problem given. Thank you. 1) Find derivative if y =cot x + sin x 2) Find derivative if y = (3x+5)^8 3) Find derivative if y = x csc x 4) Find derivative if y = x /3x + 1 (3x + 1 is under a square root(/) 5) ( f...
*Sunday, September 30, 2007 at 9:28pm by Matt*

**calculus**

the velocity at time t is the derivative. the derivative of s(t) with respect to t = -A*sin(t + )(t) assuming that everything but t and s(t) are constent. to find out when the velocity is 0 we just have to set the derivative = to 0 and solve for t so it looks like the ...
*Tuesday, September 27, 2011 at 12:22am by johnathon*

**calculus**

Please help with this. I submitted it below but no one responded. I need the first derivative of f(x)=4(x+ then the square root to include (x(8-x)), then close bracket.And then the second derivative of this to show by the second derivative test that it is a local maximum. This...
*Tuesday, March 1, 2011 at 12:45pm by Frank*

**derivative**

Is that the 5th root of (3+5x+x^3)? If so, you can rewrite it as (3+5x+x^3)^(1/5). You have to use the chain rule to find this derivative. First set (3+5x+x^3)=z. You know have z^(1/5). Take the derivative of this. (1/5)z^(1/5-1)=(1/5)z^(-4/5). Now substitute (3+5x+x^3) back ...
*Thursday, November 4, 2010 at 9:41pm by Jack*

**math**

I have the same project as Jill down there... -What is the definition of a derivative? -What does the derivative of a function tell you (in english) ? Then I need an example of the power rule, quotient rule, and chain rule. -What information does the FIRST derivative tell you ...
*Thursday, May 19, 2011 at 6:32pm by Teenie*

**Calculus**

Use a symbolic differentiation utility to find the derivative of the function g(x)=x((x^2)+1). Use the utility to graph the function and is derivative on the same set of coordinate axes. Describe the behavior of the function that corresponds to any zeroes of the graph of the...
*Sunday, November 11, 2007 at 5:51pm by Jon*

**Calculus - derivatives**

Okay, I want to find the derivative of (x^x)^(x^x)... Well, I already went through the process of finding the derivative of just x^x (I used ln to do this). This is what I found... dy/dx = x^x(lnx+1) So now I want to find the derivative of (x^x)^(x^x) (using ln). This is what ...
*Sunday, November 29, 2009 at 3:58am by Lucy X*

**Calculus**

R=M^2(c/2-m/3) dR/dM=CM-M^2 I found the derivative. Now how would I find the vale of M that maximize the derivative dR/dM? set it to zero, and solve for m. You get two solutions. Use the second derivative to see which one is the max. I get M=C. How do I go from there? What do ...
*Tuesday, May 29, 2007 at 9:11pm by Anonymous*

**calculus**

Steeve you are right - I shouldn't have set denominator to zero but not because of your reasoning. No. But because it's a second derivative. When it comes to first derivative you CAN set (and have to sometimes) denominator to zero if you want to find vertical asymptotes! But ...
*Tuesday, June 11, 2013 at 9:02am by JuliaB*

**Calculus**

This is derivative of a division (fraction. the rule is the denominator times the derivative of the numerator - the numerator times the derivative of the denominator. ALL OVER the denominator squared. The denominator of the derivative is the easy part. It is just (t^4 -2)^2 ...
*Friday, February 22, 2013 at 9:16am by JJ*

**calc**

when dealing with rational functions, the value is undefined when the denominator is zero. So, f' and f" are undefined at x=0 f is the anti-derivative of f'. So, f(x) = 1/3 x^3 - 8ln(x) + c If you take the derivative of that, you'll get f' as given. Note that the value of c ...
*Tuesday, December 3, 2013 at 12:11pm by Steve*

**Math(Please check)**

π^2 is a constant just like the derivative of 5x would be 5 so the derivative of (π^2)x is simply π^2 (think of (π^2) as 3.14^2 or appr. 9.86 so what would be the derivative of 9.86x ? )
*Friday, April 29, 2011 at 3:08pm by Reiny*

**math**

If you mean the rate of change with respect to a change in x, that is the called the derivative. For y = x, the derivative is 1 For y = x^2, the derivative is 2x (which is 4 when x = 2) For y = 7, the derivative is 0. Y does not change and is independent of x. If you mean the ...
*Tuesday, February 9, 2010 at 11:26pm by drwls*

**CALCULUS HELP**

Find the second derivative for the function 5x^3+60x^2-36x-41 and solve the equation F(X)=0 i got to the second derivative but what do we do next to be able to get one of these answers.. F(x) = 5x3+60x2−36x−41 1. derivative of F(x) with respect to x = 15x2+120x&#...
*Wednesday, September 26, 2012 at 12:19am by Herosugar*

**calculus**

Could someone check my reasoning? thanx Find the derivative of the function. sin(sin[sinx]) I need to use the chain rule to solve. So I take the derivative sin(sin[sinx) first. Then multiply that by the inside which is the derivative of sin[sinx]. And multiply that by ...
*Thursday, May 7, 2009 at 10:43am by XCS*

**local min**

f(x) = x^4 + ax^2 What is a if f(x) has a local minimum at x=5. How do I justify the answer. The first derivative has to be zero at x = 5. You then check what the second derivative is at x = 5. If it is positive then that's ok. In this case you find that a = -50 and that the ...
*Sunday, November 19, 2006 at 5:11pm by Jen*

**Calculus (Help)**

Also I would like to know how to set this problem up in finding the answer: Find the second derivative. y= sqrt(3x+4) Thanks, P.S. I tried taking 3x+4 and squaring it to the 1/2. I thought that might've been the same, then I took the derivative of that and got 1/2(3x+4)^(-1/2...
*Wednesday, February 21, 2007 at 1:42am by Confused*

**calculus**

rewrite the square root of x as x^1/2 This is the quotient rule. demoninator times the derivative of the numerator minus the numerator times the derivative of the denominator all over the denominator squared. So... We know the derivative will have an x^2 in the denomoniator. ...
*Thursday, February 21, 2013 at 12:15pm by JJ*

**Math - Derivative of a polynomial function**

The way to solve this is explained in your subject title. Compute the derivative of the function, which is the speed, and calculate its value at t = 5.0803 s. The derivative is V(t) = dh/dt = -9.8t + 24.5 Plug in the value of t that you got (which was correct) and compute V
*Monday, October 11, 2010 at 7:16am by drwls*

**Math: partial derivative**

z=u(v+w)^(1/2) find ∂^3z/(∂u∂v∂w) what partial derivative am I suppose to be finding exactly? Do I take the derivative of z three times? Please help. Thank you.
*Sunday, July 11, 2010 at 11:42pm by C*

**Calculus**

Look in the index of your calculus book for derivative, definition of derivative. They may explain it better or search on google for "definition of derivative" calculus
*Sunday, December 9, 2007 at 3:11pm by Damon*

**maths**

The first derivative is 2 e^2x*sin2x + 2e^2x*cos2x The second derivative is 2(2 e^2x*sin2x + 2e^2x*cos2x) + 2(2e^2x*cos2x -2e^2xsin2x) = 8 e^2x*cos2x Look for a pattern. The fourth derivative might be 8^4 times the original function. Then that would repeat after the eighth ...
*Sunday, September 19, 2010 at 2:20am by drwls*

**Calculus**

Explain the global optimization process for a continuous function over a closed interval. Be sure to identify all steps involved and clearly explain how the derivative is utilized in this process. Does this have to do with the first derivative rule or second derivative rule ...
*Saturday, October 25, 2008 at 2:40pm by George*

**Calculus**

Explain the global optimization process for a continuous function over a closed interval. Be sure to identify all steps involved and clearly explain how the derivative is utilized in this process. Does this have to do with the first derivative rule or second derivative rule ...
*Monday, October 27, 2008 at 9:58am by George*

**Calculus**

The derivative of a^x is a^x*ln a The numerator's derivative is 1n 10*10^x - ln 5*5^x which at x = 0 equals ln 10 - 1n 5 = ln 2 = 0.693 Th derivative of the denominator is a= 1. L'Hopital's rule gives you a limit of 0.693/1 = 0.693 for the derivative
*Saturday, November 8, 2008 at 3:34pm by drwls*

**Calculus - Maths**

Yes, you can... The product rule is "first, derivative of the second + second, derivative of the first." The quotient rule is "bottom, derivative of the top minus top, derivative of the bottom all over the bottom squared." (The commas are multiplication.) Say those statements ...
*Monday, November 26, 2007 at 7:00am by Michael*

**calculus**

PS - derivative of a constant is 0, not 1. Reason 1: derivative is rate of change. constants do not change. Reason 2: since 1 = x^0, a constant k = kx^0 the derivative is thus 0*k*x^(-1) = 0
*Tuesday, November 13, 2012 at 11:16pm by Steve*

**Is this f'(x) or partial derivative?**

Find d VC/ d y = ((y/240)^2)(w) = 2yw/240^2 + 0 + y^2/240^2 but final answer is.... = 2yw/240^2 So, is the question asking for partial derivative or first derivative? I think partial because the final answer only took the derivative with respect to y.
*Wednesday, October 14, 2009 at 3:42pm by Anonymous*

**Math-Calculus (check please)**

The "concavity" of the function comes from the second derivative, where there is a critical point. If the second derivative is positive at a point where the first derivative is zero, the function is "concave upward" there. If it is negative, it is concave downward.
*Saturday, November 1, 2008 at 8:32pm by drwls*

**Calculus derivatives**

f(a) = a + √a (a) Find the derivative of the function using the definition of derivative.
*Monday, October 27, 2008 at 5:27am by Ben*

**Calculus**

You have already written the correct value of the derivative of y(x). That is y' = m x^(m-1) . The second derivative is y" = m(m-1)y^(m-2)
*Saturday, September 5, 2009 at 2:37am by drwls*

**Math**

Find the derivative of f(x)= 2 sqrt x at x=4. i thought that the derivative would be 2 x^1/2 but I guess this is wrong.
*Saturday, February 5, 2011 at 11:31am by Hannah*

**Calculus**

Sorry I don't understand how to get the second derivative, I gsolved the first derivative already
*Sunday, March 20, 2011 at 7:47pm by Janet*

**derivative **

Find the derivative. 11) f(t)=(1)/(sqrt(8t-3)) 12) g(t)= ((4t-3)^2)/ ((5t+1)^4) Thanks.
*Wednesday, June 15, 2011 at 5:15pm by Ben*

**Math**

How would I find the derivative of x^2 + 3x using the definition of the derivative?
*Wednesday, December 5, 2007 at 3:44am by Jessica*

**calculus**

Calculate the derivative of the function. Then find the value of the derivative as specified. f(x) = 8/(x+2); f '(0)
*Sunday, July 4, 2010 at 8:45pm by theo*

**Calc**

Set the first derivative and second derivative of x^2/x-2 equal to 0. Solve for 0.
*Monday, October 22, 2012 at 12:01pm by Anonymous*

**Calculus**

first, it's derivative. since 217^(1/2) is a constant, the derivative is zero.
*Wednesday, December 5, 2012 at 9:31pm by Steve*

**CALCULUS**

The derivative of e^x is e^x. To determine the derivative apply the constant multiple rule
*Wednesday, February 20, 2013 at 2:50pm by Anon*

**Math**

You should know how to take the derivative of x^2 -3x. The derivative of that function is 2x -3. Plug in x=0 for the answer
*Friday, July 25, 2008 at 6:52pm by drwls*

**calculus**

Um I still don't get it because that hint was the derivative and I asked for the anti-derivative of square root x
*Wednesday, January 14, 2009 at 9:20pm by Barbara*

**Dear Stuck - Calculus**

Did you get f'(x) = 2 by simply taking the derivative of the top over the derivative of the bottom ?? my oh my !!
*Monday, February 15, 2010 at 12:25am by Reiny*

**Math**

The rules of the derivative of x^n is nx^(n-1). The anti-derivative is the reverse process: ∫x^ndx = (1/(n+1))x^(n+1) + C
*Thursday, July 1, 2010 at 10:31am by MathMate*

**calc**

I am guessing you want the derivative of the piecewise-continuous function f(x) = 2(x^2 + 3|x|) , but what does the "1" represent? If you want the derivative at x=1, you can remove the | | signs
*Monday, March 7, 2011 at 2:56am by drwls*

**Calculus**

She found the derivative of the equation, and then simply plugged in a one for the (x) after it was in its derivative form.
*Sunday, October 2, 2011 at 7:20pm by Ed*

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