Number of results: 18,476
-3 + 4i in polar form in pi the magnitude is 5 from pyth theorm. Now the angle. Using i the positive real as the reference axis, the angle from it is PI/2 + arctan4/3
Friday, November 3, 2006 at 5:26pm by kevin
-2-2i in polar form = 2.8 cis 2.35?? -3+4i polar form = 5 cis 2.2??? 1 - sqaureroot(3i) polar form = 2 cis 1.04?? What is cis? never mind I have the right answers. polar form z = r (cos O + i sin O ) is also written in an abbreviated form z = r cis O cos + sin = cis
Friday, November 3, 2006 at 6:38pm by kevin
115 cis 45* 3 solutions = 120* apart Are these correct? 115 cis 45* 115 cis 45 + 120 = 165* 115 cis (45 + 120 + 120) = 285*?? WHat is cis? cos + isin OH LOL!!!Wish I could help!LOL!But...PLease help me!!:(
Sunday, November 5, 2006 at 5:50pm by kevin
i^6 = (i^2)^3 = (-1)^3 = -1 The square, not the square root of -1 is 1. :) B.t.w., can you prove that -1 times -1 is 1? Hint, try to prove first that for any number X: -1 times X equals -X How do you find the square root of -1? The square of any real number is alwayspositive. ...
Wednesday, November 15, 2006 at 3:37pm by Count Iblis
You can add or subtract complex numbers by treating the i as a variable and combining like terms. I am having a lot of trouble figuring out these equations with imaginary numbers. 1. (3+2i)+(7-i)= 2.(1-6i)+(2-i)= 3. (2+i)-(3+i)= 4.(4+i)-(2-i)= Can someone please walk me ...
Tuesday, January 16, 2007 at 3:52pm by chrissy
Maths- complex numbers
Find tan(3 theta) in terms of tan theta Use the formula tan (a + b) = (tan a + tan b)/[1 - tan a tan b) in two steps. First, let a = b = theta and get a formula for tan (2 theta). tan (2 theta) = 2 tan theta/[(1 - tan theta)^2] Then write down the equation for tan (2 theta + ...
Tuesday, February 13, 2007 at 2:45am by Jake
by using the substitution w = z^3, find all the solutions to z^6 - 8z^3 +25 = 0 in complex numbers, and describe them in polar form, using @(theta) to denote the angle satisfying tan@ = 3/4 ( note simply leave @ as it is, dont calculate it). i got up to z^3 = 4+3i and 4-3i ...
Monday, March 12, 2007 at 9:25am by Anonymous
Math - Complex Numbers
Could someone show me how to get the work for: 3/4 (sqrt)-16/25 ? The answer says 3/5i. Could anybody tell me how to get there and work with complex fractions and simplify them? Thanks! 3/4 SQRT(-16/25) 3/4 SQRT( 16/25*-1) 3/4 *4/5 *SQRT( -1) but the sqrt of -1 is defined as i...
Tuesday, May 8, 2007 at 9:51pm by Danielle
let z= a+bi be a complex number. it is given that the quotient (z-i)/(z-1) is purely imaginary. show that z lies on a circle and determine the centre and radius of this circle. OK, here's my working out...( i am using "X" as my times symbol) step1: (a+bi-i)/(a+bi-1)X[(a-1)-bi...
Wednesday, March 12, 2008 at 4:09am by Anne
the complex number Z satisfies Z/(Z+4)= 3+2i Find Z. please help thx!
Thursday, March 13, 2008 at 7:11am by Anne
Complex Number Proof
Prove: If Z and W are complex numbers, then the conjugate of (Z+W) is equal to the conjugate of Z plus the conjugate of W. My thought is that this is kind of like the distributive property, but I'm not sure. It doesn't help that I haven't written a proof in over 10 years. Help...
Wednesday, June 11, 2008 at 4:38pm by Amy
the complex number Z satisfies Z+i/(1+2i)= iz Find Z. please help thx!
Tuesday, November 4, 2008 at 7:22am by Mary
the complex number Z satisfies (Z+i)/(1+2i)= iz Find Z. please help thx!
Tuesday, November 4, 2008 at 1:43pm by Mary
algebra ll-imaginary numbers
do a google search for "complex numbers"
Wednesday, March 18, 2009 at 7:50am by Reiny
Oh thank you so much i forgot that when you that the square root of a negative you get the complex #
Monday, January 31, 2011 at 9:03pm by Allie
division of complex numbers
no, use 2-3i, because (2+3i)(2-3i) = 4 - 9i^2 = 4+9 = 13 and you get rid of the complex number in the bottom
Monday, January 16, 2012 at 4:13pm by Steve
Math (Complex Numbers)
Let a,b,c be complex numbers satisfying a+b+c=abc=1 and (ab+bc+ac)/3=(1/a^2)+(1/b^2)+(1c^2) The sum of absolute values of all possible ab+bc+ac can be written as (√n)/m, where n and m are positive coprime integers. What is n+m?
Thursday, May 9, 2013 at 9:55am by Mahler
Sketch the sets of complex numbers in the complex plane that satisfy the following: a) |z-1|=2 b) |z-3i|=2 c) |z-5+2i|=2 I'm not sure, but are you supposed to rearrange the whole thing to |z|=a+bi? So, part b would be |z|=2+3i.
Wednesday, October 9, 2013 at 9:34pm by Rin-chan-san
all are circles of radius 2, with center at various numbers. |z-c| = r has center at c. |z|^2 = x^2+y^2 That's why the curves are circles.
Wednesday, October 9, 2013 at 9:34pm by Steve
If z = -3+4i, determine the following related complex numbers. a)vector z b)3(vector z) c) 1/(vector z) d) |z| e) |vector z| f) (vector z)/(|z|^2)
Friday, October 11, 2013 at 10:45am by Rinchan