Saturday

April 19, 2014

April 19, 2014

Number of results: 1,409

**Comp 155**

Thank you for your help.
*Sunday, May 1, 2011 at 4:09pm by Tracy*

**Comp 155**

You're welcome!
*Sunday, May 1, 2011 at 4:09pm by Writeacher*

**Comp 155**

It didn't matter.
*Thursday, September 1, 2011 at 1:47pm by Her*

**physics**

Fb=15.6kg * 9.8N/kg = 152.88N @ 0 deg.= Force of the block. Fp = Fh = 155.88sin0 = 0N = Hor comp of block. Fv = 155.88cos0 = 155.88N = Force perpendicular to plane. Applied Force: Fap = 72.2N @ 34.8deg. Fh = 72.2cos34.8 = 59.29N. = Hor comp of applied force. Fv = 72.2sin34.8...
*Friday, February 25, 2011 at 5:02pm by Henry*

**comp 155**

You're welcome. Go and do well! =)
*Wednesday, June 29, 2011 at 2:19pm by Writeacher*

**Comp 155**

What is an analysis essay?
*Wednesday, August 24, 2011 at 11:16pm by Me*

**comp 155**

What kind of HELP do you need?
*Friday, November 19, 2010 at 1:21pm by Writeacher*

**Comp 155**

separate = correct spelling!
*Sunday, May 1, 2011 at 4:09pm by Writeacher*

**comp/155 week 4 assignment**

need help
*Friday, July 29, 2011 at 2:06pm by jennifer*

**Comp 155**

List the steps to buying a home.
*Monday, August 15, 2011 at 6:37pm by Camille*

**Comp 155**

Introduction, body, conclusion.
*Thursday, August 18, 2011 at 4:55pm by Ms. Sue*

**Comp 155**

Camille -- read the linked webpage I gave you.
*Monday, August 15, 2011 at 6:37pm by Writeacher*

**Comp 155**

identify the three key parts of a paragraph.
*Thursday, August 18, 2011 at 4:55pm by Camille*

**Comp 155**

The introduction is usually the topic sentence.
*Thursday, August 18, 2011 at 4:55pm by Ms. Sue*

**Comp 155**

Explain the key differences between the types of essays.
*Wednesday, August 24, 2011 at 11:16pm by Me*

**COMP 155**

Confusion and disgust with such sloppy writing.
*Sunday, November 28, 2010 at 10:59pm by Ms. Sue*

**comp 155**

You can purchase solutions for your class at: uopaxiasolutions dot com
*Saturday, September 11, 2010 at 2:45am by JimmyTree*

**comp/155**

We'll be glad to help you. Please post your thesis statement.
*Monday, July 15, 2013 at 2:08pm by Ms. Sue*

**comp/155**

explain why using pronouns may help make your writing more effective?
*Wednesday, May 11, 2011 at 9:28am by sharon*

**comp 155**

got confused thanks for helping me this class really stresses me out.
*Wednesday, June 29, 2011 at 2:19pm by glenna*

**comp/155**

explain why using pronouns my help make your writing more effective.
*Wednesday, May 11, 2011 at 9:28am by porta*

**comp/155**

I am having problems writing a essay and not really sure how to start.
*Monday, July 15, 2013 at 2:08pm by cheri*

**Comp/155**

What strategies might a writer use to ensure pronouns are used effectively?
*Friday, April 1, 2011 at 2:19am by Monica*

**Comp 155**

The reader would be confused and believe that the author is disorganized and stupid.
*Friday, August 19, 2011 at 8:05pm by Ms. Sue*

**Comp 155**

Define sentence variety and rhythm in your own words and explain how they interact in effective writing.
*Thursday, September 1, 2011 at 1:47pm by Her*

**Comp 155**

Define repetition in writing and explain why it is important to avoid repeating words or phrases when you create an academic essay
*Thursday, September 1, 2011 at 1:38pm by Her*

**math12**

you are right, most calculators cannot go over 69! but if you break down 155!/(2!153!) by its definition: 155! = (155)(154)153! then 155!/(2!153!) = (155)(154)153! / (2!153!) = 155(154)/2 look for a key something like nCr by definition that is n!/(r!(n-r)!) nCr is just another...
*Tuesday, April 14, 2009 at 10:33pm by Reiny*

**Comp 155**

Does your instructor want YOUR own words or the words of an anonymous Jiskha tutor?
*Thursday, September 1, 2011 at 1:47pm by Ms. Sue*

**Comp 155**

Are you aware that we have access to NO TEXTBOOK? Therefore, we have no idea what you read in Chapter 6, Section 2 of the text. Sra
*Monday, August 15, 2011 at 11:30pm by SraJMcGin*

**Comp 155**

identify key points to keep in mind when writing a topic sentence. How might these key points help you write effectively
*Friday, August 19, 2011 at 7:54pm by Me*

**math**

0.22. 0.375. 0.530. 0.685. 0.84 0.22+0.155+0.155+0.155+0.155=0.84
*Tuesday, September 4, 2012 at 11:17pm by Susan*

**Comp 155**

Based on the readings in Ch. 6, Section 2 of the text, identify key points to keep in mind when writing a topic sentence. How might these key points help you write effectively?
*Monday, August 15, 2011 at 11:30pm by Camille*

**comp/155 week 4 assignment**

You sure do! This is not an Axia site. We have no connection with any schools. We do not know what your assignment is! If you post your assignment and tell us how you would like us to help you, we'll try to give you a hand.
*Friday, July 29, 2011 at 2:06pm by Ms. Sue*

**comp 155**

Re-think these: I know it is important, so I will defiantly be there (their) on time. I should of written (wrote) down where I last put them. I don’t want to buy that. It’s to expensive. Correct I love my car. It’s interior is so comfortable. Correct An evening out can be a ...
*Wednesday, June 29, 2011 at 2:19pm by Writeacher*

**comp 155**

Write three sentence using plurals correctly and three sentences using possessives correctly on the topic of how to store personal financial information effectively and efficiently.
*Friday, November 19, 2010 at 1:21pm by lorretta*

**comp 155**

Compare and contrast your abilities as an academic writer now as opposed to when you began at Axia College. Using four comparatives and four superlatives within your responses, explain what has led to these changes and what changes you will make in the future.
*Saturday, September 11, 2010 at 2:45am by Anonymous*

**math**

155/775 First reduce that fraction to its lowest terms. I first get 31/155. That can be reduced again by dividing 155 by 31.
*Monday, November 12, 2007 at 6:39pm by Ms. Sue*

**physics**

mass = 155/1000 = 0.155 kg. V = 95mi/3600s * 1600m/mi = 42.2 m/s. Momentum=m*V = 0.155 * 42.2=6.54 kg.m/s
*Sunday, January 19, 2014 at 7:18pm by Henry *

**Comp 155**

When writing a paragraph, it is important that the topic sentence and supporting points within that paragraph be directly related. What would be the reaction of a reader if the topic sentences in an essay did not coincide with the supporting points?
*Friday, August 19, 2011 at 8:05pm by Me*

**COMP 155**

When writing a paragraph, it is important that the topic sentence and supporting points within that paragraph be directly related. What would be the reaction of a reader if the topic sentences in an essay did not coincide with the supporting points?
*Sunday, November 28, 2010 at 10:59pm by Keisga *

**comp 155**

I don’t want to buy that. It’s to (too) expensive. Correct<~~delete this word I love my car. It’s ( Its) interior is so comfortable. Correct<~~delete this word ~~~~~~~~~~~~~~~~~~~~~~ And why did you change this one? Your welcome. I was happy to help. correct
*Wednesday, June 29, 2011 at 2:19pm by Writeacher*

**Comp 155**

Adjectives I see: best runaway toxic full moving unsuccessful unattended "a half-mile long" small veteran young runaway separatre toxic Adverbs I see: lately slowly "a engineer" -- are you kidding me? "decimate" -- only 1/10th of the town will be destroyed??
*Sunday, May 1, 2011 at 4:09pm by Writeacher*

**Comp 155 Week 6**

Describe your experience with credit and credit cards in a brief paragraph using at least five adverbs and five adjectives in your description. Bold the adverbs and underline the adjectives. What is the most effective way to determine whether a word is an adjective or an adverb
*Tuesday, August 9, 2011 at 11:13pm by Camille*

**physics**

what is the vert. comp. of vector with magnitude 88.5m/s and whose horiz. comp. is 75.4m/s? what is the direct. of this vector?
*Sunday, January 13, 2008 at 7:16pm by Anonymous*

**math**

Let x = length. Solve for x. (2*17.5) + 2x = 155 35 + 2x = 155 2x = 155 - 35 2x = 120 x = ?
*Sunday, December 27, 2009 at 6:07pm by Ms. Sue*

**MaTh**

4x + x 155 5x = 155 x = 31
*Monday, August 19, 2013 at 10:22pm by Ms. Sue*

**math**

consider the amount of $1 at the end of 2 years at 6.2% simple ---- 1 + (1)(.062)(2) = $1.124 at 6.1 comp. annually ---- (1.061)^2 = $1.1257 at 5.58% com. semi --- (1.0279)^4 = $1.11636 at 5.75% comp. quarterly -- (1.014375)^8 = 1.12096 so what do you think?
*Monday, April 25, 2011 at 4:50pm by Reiny*

**Statistics**

Between z = -2 and z = 0.4. (Points: 5) 0.655 0.977 0.477 0.155 0.633 my answer was o.155 is this correct
*Sunday, June 20, 2010 at 11:11am by John*

**math**

time = 8 years , 155 days = 8 + 155/365 = 8.42466 x e^(8.4266(.0895)) = 225500 x = $106092.70
*Saturday, November 16, 2013 at 9:45am by Reiny*

**Chemistry**

I got A) Exo B) Exo C) Endo D) Endo But its wrong :/ i have no idea what i am doing wrong. A) 942+3(432)-6(386)=-78 B)494-522=-28 C)4(459)-2(432)+494=478 D)2(155)-155=155
*Sunday, January 22, 2012 at 10:53pm by Kristen*

**word problem money**

1 quarter=25 1 dime=10 13x10=130 or 1.30+25=155 or 1.55 25x3=75 or .75+80=155 or 1.55 25x5=125 or 1.25+30=155 or 1.55 Correct :)
*Monday, April 2, 2012 at 9:00pm by Rezu*

**Physics - Inelastic Collision ( check + help)**

A billiard ball of mass 0.55kg moves with a velocity of 12.5m/s towards a stationary billiard ball of the identical mass and strikes it with a glancing blow. The first billiard ball moves of at an angle of 29.7deg clockwise from its original direction, with a velocity of 9.56m...
*Sunday, September 26, 2010 at 2:52pm by Shaila*

**stats**

Here's the rest of the data 155 160 150 145 200 155 190 140 170 175 142 168
*Tuesday, March 12, 2013 at 1:49pm by kelly*

**math**

x=number of 2 legged birds y=number of 4 legged mammals 2x+4y=550 if there are a total of 155 animals and you know the number of 2 legged birds, you could subtract the two and find the number of 4 legged mammals therefore, let y=155-x substitution: 2x+4(155-x)=550 solve for x...
*Monday, August 9, 2010 at 6:56pm by Anonymous*

**Comp 155**

http://www.wikihow.com/Buy-a-House
*Monday, August 15, 2011 at 6:37pm by Writeacher*

**geometry**

I found out the first part of which is x for the figure which was 115 degrees.They do give you the other measures of the angles which are 115,155,155,155.135,135,115.The second part of the problem say yo find the sum of the measures of the exterior angles,one at each vertex,...
*Saturday, July 23, 2011 at 4:59pm by Lauren*

**chemistry**

155.0 grams of N2 (nitrogen gas) are put in a 4.50L container at 35C. What is the pressure? PV=nRT n=155/molmassN2 Convert temps to K.
*Tuesday, January 9, 2007 at 6:54pm by TIFFANY*

**Comp/155**

Surely this has been covered in your text or other course materials. You can also use this: http://grammar.ccc.commnet.edu/grammar/index2.htm Read and study all the sections on pronouns; there are five.
*Friday, April 1, 2011 at 2:19am by Writeacher*

**Math**

let the bill before taxes and tips be $x then (1.15)(1.08)x = 193 x = 193/((1.15)(1.08)) = 155.39 After tax, bill was 155.39(1.08) = 167.83 now 15% of that is 25.17 so the tip was 25.17 check: [155.39 + .08(155.39)])1.15) = 193
*Saturday, February 13, 2010 at 10:04pm by Reiny*

**math**

$56,950 * (0.118) * (155/365) = $2853.74 This assumes simple interest, with no payments and principal reduction during the 155 day interval.
*Tuesday, June 14, 2011 at 12:25am by drwls*

**trig**

150 at 155° = 63.4i -135.9j 25 at 160° = 8.6i - 23.5j sum = 72.0i - 159.4j = 175.0 at 155.7°
*Friday, November 16, 2012 at 6:17am by Steve*

**comp 155**

No one can write this but you. Notice all the "you" and "your" in the assignment? Are you clear on what comparatives and superlatives are? If not, here's a good explanation with examples: http://grammar.ccc.commnet.edu/grammar/adjectives.htm#comparative
*Saturday, September 11, 2010 at 2:45am by Writeacher*

**math**

Pt = Po(1+r)^n, r APR / 4 = 4% / 4 = 1% = 0.01 = QPR = Ouarterly percentage rate. n=4 comp/yr * 6yrs = 24 comp. periods. Pt = 1300(1.01)^24 = $1650.66.
*Sunday, July 3, 2011 at 8:31am by Henry*

**Physics**

Vector: 14.7km @ (-35)deg = 325deg CCW, 4th QUAD. X = hor = 14.7*cos(325)=12.04km = East Comp. Y = ver = 14.7*sin(325) = -8.43km = South Comp.
*Wednesday, January 19, 2011 at 6:31pm by Henry*

**Math**

One way to reduce fractions is to start with a small number. I know that 155 and 70 is divisible by 5 because they end in 0 or 5. 70/155 = 14/31
*Tuesday, November 1, 2011 at 2:45pm by Ms. Sue*

**physics**

The vertical problem is dropping a mass from a height of 155 meters. The horizontal speed has nothing to do with the vertical problem. The vertical component of velocity is zero at the beginning. So how long to drop: y = Xo + Vi t + (1/2) a t^2 here x = -155 (or 155 down) Xo...
*Wednesday, December 15, 2010 at 5:38pm by Damon*

**math**

Pt = Po(1+r)^n. r = (1.7%/360) / 100% = 0.0000472 = Daily % rate expressed as a decimal. n = 1 comp./day * 180 days = 180 comp. periods. Pt = 4800(1.0000472)^180 = $4840.41.
*Thursday, December 8, 2011 at 4:43pm by Henry*

**Comp 155**

http://owl.english.purdue.edu/owl/resource/685/01/
*Wednesday, August 24, 2011 at 11:16pm by Ms. Sue*

**Chemistry**

I assume that is 155 kJ and not 155 kJ/mol. 40.7 kJ/mol x (?mol) = 155 kJ.
*Friday, April 22, 2011 at 9:03am by DrBob222*

**Math**

I'm assuming you mean the rate changes to 9 % after 3 years. Pt = Po(1+r)^n. r = (10%/4) / 100% = 0.025 = Quarterly % rate exprssed as a decimal. n = 3 yrs * 4 comp / yr. = 12 Comp. periods. Pt = $9000(1.025)^12 = $12,104 After 3 years. r = (9%/2) / 100% = 0.045 = Semi-annual...
*Wednesday, January 11, 2012 at 5:14pm by Henry*

**Physics**

Vo = 27m/s @ 20 Deg. Xo = 27*cos20 = 25.4 m/s = Hor. comp. Yo = 27*sin20 = 9.2 m/s. = Ver. comp. A. h = (Y^2-Yo^2)/ 2g. h = (0-(9.2)^2 / -19.6 = 4.35 m. B. V = 0 @ max. ht. C. R = Vo^2*sin(2A)/g. R = (27)^2*sin40 / 9.8 = 47.8 m.
*Wednesday, June 20, 2012 at 11:34pm by Henry*

**physics**

A man pushs a cart wt a force of 36N directd@ an angle 25dgree belw the horizontal. The horizntal comp oe the force is 32.6N.The vrticl comp of force is 15.6N.Fnd work dne on the cart as the prsn moves50m
*Monday, August 15, 2011 at 2:36am by Luc*

**physical**

how do i get a 45 year old inactive male who weighs 280lb and has a body comp of 55% lean mass and 45% fat mass.down to his goal! his goal is to alter his body comp to 80%-20% and lower his weight to 200lbs
*Sunday, February 1, 2009 at 5:09pm by Leah*

**math**

To convert a percentage to a decimal number, divide by 100. For example, 155% = 155/100 = 1.55 You can convert the percentages to the scale factors the same way.
*Thursday, November 26, 2009 at 8:06pm by MathMate*

**math**

You must have been given a table or chart with the conversion factors between your different units. Some of these I don't know. e.g. what is pm and nm ? the first is done this way: 1 km = 1000m so 155 km = 1000(155) m = 155000 m
*Friday, October 9, 2009 at 8:10am by Reiny*

**physics**

Thank you for giving both speed and radius this time: Ac = v^2/r at the top force on seat = m (v^2/r - g) = 92 (155^2/596 -9.8) = 2806 N at the bottom m (v^2/r + g) =92 (155^2/596 +9.8) = 4610 N
*Saturday, October 25, 2008 at 6:25pm by Damon*

**math**

$155.5 how I found it: I tried to find what an amount for which to total amount of tax cost $9.33 so, I chose random numbers to test this, 155.5x.06=9.33
*Tuesday, February 25, 2014 at 9:28pm by Ashley*

**Physics**

h1=a*t^2 = 28.3*5.5^2=856.1 m Above gnd. V1 = a*t = 28.3 * 5.5 = 155.7 m/s. V = V1 + g*t = 0 155.7 - 9.8t = 0 -9.8t = -155.7 t = 15.9 s. To reach max ht. h2 = V1*t + 0.5g*t^2 h2 = 155.7*15.9 - 4.9*15.9^2 = 1236 m Above h1. h = h1 + h2 = 856 + 1236 = 2092 m. Above gnd.
*Tuesday, September 17, 2013 at 10:45pm by Henry *

**COM 155**

What do you hope to accomplish COM 155?
*Tuesday, February 28, 2012 at 3:59pm by Destiny*

**Physics**

Do a vertical frce balance. The "normal force" is the force upward exerted by the ground on the suitcase. 155 N + X sin 25 = M g (the weight) X is the force applied to the handle and M = 23 kg. Solve for X 0.4226 X = 225.6 - 155 = 70.6 N
*Thursday, January 14, 2010 at 2:45pm by drwls*

**physics**

i dont understand how to do this question, its a phys 11: "A skier is acc. down a 30.0 degree hill at 3.80m/s^2" a) What is the horiz. comp. of the acc.? b) What is the vert. comp. of the acc.? c) Assuming she starts from rest and acc. uniformly down hill, how long will it ...
*Sunday, January 13, 2008 at 6:54pm by Anonymous*

**physics**

Vo = 48.6m/s @ 37deg. Vo(h)=48.6cos37 = 38.8m/s = hor. comp. Vo(v)=48.6sin37 = 29.2m/s = ver comp. Rectangular Form: Vo = 38.8 + j29.2 m/s. The "j" means there is a 90 degree phase difference between the 2 vectors.
*Friday, June 24, 2011 at 4:59pm by Henry*

**Finance**

Pt = Po(1+r)^n, r = 4.40%/yr * 0.75yr = 3.3% = 0.033 = rate per compounding period expressed as a decimal. n = 15yrs / 0.75yr/comp.Period = 20 Comp. periods. Pt = 1000(1.033)^20 = $1914.28.
*Tuesday, October 4, 2011 at 8:03am by Henry*

**maths**

we know that 2+(n-1)d = 29, so d = 27/(n-1) sum of first n terms is n/2 (4+(n-1)d) n/2 (4+(n-1)*27/(n-1)) = 155 n = 10 check: d = 27/9 = 3 10th term is 2+9(3) = 29 S10 = 5(4+9(3)) = 155
*Monday, April 22, 2013 at 3:44pm by Steve*

**Math**

Pt = Po(1+r)^n. a. r = (8.01%/12) / 100% = 0.006675 = Monthly % rate expressed as a decimal. n = 12 comp./yr * 15 yrs. = 180 comp. periods. Pt = 2631(1.006675)^180 = $8713.48. b. Pt = Po(1+r)^n. r = (8.01%/360) / 100% = 0.0002225 = daily % rate expresed as a decimal. n = 360 ...
*Sunday, December 11, 2011 at 6:22am by Henry00*

**physics **

m1v1v+m2v2=(m1+m2)V 2500*-14i+1500*23j=(3800)V then X-comp is 2500*-14/3800 Y-comp is 1500*23/3800 P=(m1+m2)V find the value of V from the square root of the previous .... 0553053359
*Wednesday, September 1, 2010 at 6:07am by Qais *

**algebra**

Pt = Po(1 + r)n. r = 5%/yr * 0.5yr = 2.5% = 0.025 = semi-annual rate expressed as a decimal. n=2 comp/yr * 6yrs = 12 comp. periods. Pt = 20000(1.025)^12, Pt = 20000 * 1.3449 = $26,897.78
*Friday, March 4, 2011 at 1:23am by Henry*

**Chemistry**

See my note at your original post about the number of significant figures. Also, in this post note the typo on the first problem. moles = 0.155/46.0 and not 0.155 x 46.0
*Tuesday, June 14, 2011 at 4:00pm by DrBob222*

**univ/com/155**

write a paragraph of instructions on the writing process for future com/155 students.include the steps in the writing process.
*Thursday, April 26, 2012 at 8:00pm by sonya*

**exp of math**

Pt = Po(1+r)^n, r = APR/2 = 8% / 2 = 4% = .04. n = 2 comp/yr * 3yrs = 6 comp. periods. Pt = 2195(1.04)^6 = $2777.38. Int. = 2777.38 - 2195 = $552.38.
*Sunday, July 3, 2011 at 8:14am by Henry*

**algebra**

Conventional algebra: x=number of small cups y=number of large cups form the system of equations x+y=155 2x+3y=335 Solve the system for x and y. Quick way by substituting directly: Let 155-x=number of large cups 2x+3(155-x)=335 Solve the linear equation for x. Faster way by ...
*Tuesday, May 7, 2013 at 6:09pm by MathMate*

**Math**

Pt = Po(r + 1)^n. r = 16% / 4 = 4% = 0.04 = Quarterly int. rate. n = 4 yrs * 4 comp / yr 16 comp. Pt = 4700 (1.04)^16, Pt = 4700 * 1.8730 = 8803.01 = Amt. due after 4 yrs.
*Tuesday, November 30, 2010 at 4:33pm by Henry*

**math**

The slope m of a line passing through two points (x1, y1), (x2, y2) is given by m = (y2-y1)/(x2-x1) m = (-5/6 - -5/4) / (-3-2/3) = (5/12) / (-11/3) = -15/132 = -5/44 The equation for a straight line is of the form y = m*x + b where m is the slope and b is the y-intercept. So ...
*Tuesday, November 27, 2012 at 10:59pm by Jennifer*

**Physics**

V = 155mi/h @ 225o + 45mi/h @ 0o. X = 155*cos225 + 45 = -64.6 Mi/h. Y = 155*sin225 = -109.6 Mi/h. V^2 = X^2 + Y^2. V^2 = (-64.6)^2 + (-109.6)^2 = 16,185.66 V = 127.2 Mi/h.
*Thursday, January 24, 2013 at 4:45pm by Henry*

**Physics**

2T=(2*pi*massproton)/(chargeproton*B) So a) B=(pi*1.67*10^-27)/(1.6*10^-19*155*10^-9) b) Doubling the kinetic energy changes the velocity. Period T does not depend on velocity so the answer is 155 ns.
*Wednesday, November 17, 2010 at 11:04pm by ME*

**math**

1. Investment: $15,000 @ 8% for 9mo,compounded quarterly. Pt = Po(1+r)^n. r = (8%/4) / 100% = 0.02 = Quarterly percentage rate expressed as a decimal. n = 4 comp./yr * 0.75yr = 3 comp. periods. Pt = 15,000(1.02)^3 = 15,918.12. Int. = 15918.12 - 15000 = $918.12. 2. Investment...
*Friday, May 20, 2011 at 12:31pm by Henry*

**math**

Number(P or C) = number(P) + number(C) - number(P and C) = 140 + 75 - 60 = 155 number (NOT(PorC)) = 200-155 = 45 OR Make a Venn diagram of 2 intersecting circles inside a rectangle, labeling them P and C for phone and car place 60 inside the intersection of the two circles ...
*Wednesday, August 15, 2012 at 10:09pm by Reiny*

**Math**

465 y = 155 x - 35 y = (155/465) x - 35/465 y = (1/3) x - 7/93 when x = 0 y = -7/93 no matter what you do starting with -7/93 going up with a slope of 1/3 it will be hard to get an integer y
*Friday, February 7, 2014 at 6:46pm by Damon*

**Physics**

This is a The Russell traction apparatus problem and I solved the weight to be 76N. The second part of the problem asks what the angle is if the traction force is 19.4N horizontally. My initial thought was to use half of the weight as the y-comp and 19.4 for as the x-comp to ...
*Sunday, November 11, 2007 at 4:22pm by Lou-Anne*

**Physics**

Im doing a problem on The Russell traction apparatus and I solved the weight to be 76N. The second part of the problem asks what the angle is if the traction force is 19.4N horizontally. My initial thought was to use half of the weight as the y-comp and 19.4 for as the x-comp ...
*Sunday, November 11, 2007 at 6:00pm by Lou-Anne*

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