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April 19, 2014

Search: comp/155

Number of results: 1,409

Comp 155
Thank you for your help.
Sunday, May 1, 2011 at 4:09pm by Tracy

Comp 155
You're welcome!
Sunday, May 1, 2011 at 4:09pm by Writeacher

Comp 155
It didn't matter.
Thursday, September 1, 2011 at 1:47pm by Her

physics
Fb=15.6kg * 9.8N/kg = 152.88N @ 0 deg.= Force of the block. Fp = Fh = 155.88sin0 = 0N = Hor comp of block. Fv = 155.88cos0 = 155.88N = Force perpendicular to plane. Applied Force: Fap = 72.2N @ 34.8deg. Fh = 72.2cos34.8 = 59.29N. = Hor comp of applied force. Fv = 72.2sin34.8...
Friday, February 25, 2011 at 5:02pm by Henry

comp 155
You're welcome. Go and do well! =)
Wednesday, June 29, 2011 at 2:19pm by Writeacher

Comp 155
What is an analysis essay?
Wednesday, August 24, 2011 at 11:16pm by Me

comp 155
What kind of HELP do you need?
Friday, November 19, 2010 at 1:21pm by Writeacher

Comp 155
separate = correct spelling!
Sunday, May 1, 2011 at 4:09pm by Writeacher

comp/155 week 4 assignment
need help
Friday, July 29, 2011 at 2:06pm by jennifer

Comp 155
List the steps to buying a home.
Monday, August 15, 2011 at 6:37pm by Camille

Comp 155
Introduction, body, conclusion.
Thursday, August 18, 2011 at 4:55pm by Ms. Sue

Comp 155
Camille -- read the linked webpage I gave you.
Monday, August 15, 2011 at 6:37pm by Writeacher

Comp 155
identify the three key parts of a paragraph.
Thursday, August 18, 2011 at 4:55pm by Camille

Comp 155
The introduction is usually the topic sentence.
Thursday, August 18, 2011 at 4:55pm by Ms. Sue

Comp 155
Explain the key differences between the types of essays.
Wednesday, August 24, 2011 at 11:16pm by Me

COMP 155
Confusion and disgust with such sloppy writing.
Sunday, November 28, 2010 at 10:59pm by Ms. Sue

comp 155
You can purchase solutions for your class at: uopaxiasolutions dot com
Saturday, September 11, 2010 at 2:45am by JimmyTree

comp/155
We'll be glad to help you. Please post your thesis statement.
Monday, July 15, 2013 at 2:08pm by Ms. Sue

comp/155
explain why using pronouns may help make your writing more effective?
Wednesday, May 11, 2011 at 9:28am by sharon

comp 155
got confused thanks for helping me this class really stresses me out.
Wednesday, June 29, 2011 at 2:19pm by glenna

comp/155
explain why using pronouns my help make your writing more effective.
Wednesday, May 11, 2011 at 9:28am by porta

comp/155
I am having problems writing a essay and not really sure how to start.
Monday, July 15, 2013 at 2:08pm by cheri

Comp/155
What strategies might a writer use to ensure pronouns are used effectively?
Friday, April 1, 2011 at 2:19am by Monica

Comp 155
The reader would be confused and believe that the author is disorganized and stupid.
Friday, August 19, 2011 at 8:05pm by Ms. Sue

Comp 155
Define sentence variety and rhythm in your own words and explain how they interact in effective writing.
Thursday, September 1, 2011 at 1:47pm by Her

Comp 155
Define repetition in writing and explain why it is important to avoid repeating words or phrases when you create an academic essay
Thursday, September 1, 2011 at 1:38pm by Her

math12
you are right, most calculators cannot go over 69! but if you break down 155!/(2!153!) by its definition: 155! = (155)(154)153! then 155!/(2!153!) = (155)(154)153! / (2!153!) = 155(154)/2 look for a key something like nCr by definition that is n!/(r!(n-r)!) nCr is just another...
Tuesday, April 14, 2009 at 10:33pm by Reiny

Comp 155
Does your instructor want YOUR own words or the words of an anonymous Jiskha tutor?
Thursday, September 1, 2011 at 1:47pm by Ms. Sue

Comp 155
Are you aware that we have access to NO TEXTBOOK? Therefore, we have no idea what you read in Chapter 6, Section 2 of the text. Sra
Monday, August 15, 2011 at 11:30pm by SraJMcGin

Comp 155
identify key points to keep in mind when writing a topic sentence. How might these key points help you write effectively
Friday, August 19, 2011 at 7:54pm by Me

math
0.22. 0.375. 0.530. 0.685. 0.84 0.22+0.155+0.155+0.155+0.155=0.84
Tuesday, September 4, 2012 at 11:17pm by Susan

Comp 155
Based on the readings in Ch. 6, Section 2 of the text, identify key points to keep in mind when writing a topic sentence. How might these key points help you write effectively?
Monday, August 15, 2011 at 11:30pm by Camille

comp/155 week 4 assignment
You sure do! This is not an Axia site. We have no connection with any schools. We do not know what your assignment is! If you post your assignment and tell us how you would like us to help you, we'll try to give you a hand.
Friday, July 29, 2011 at 2:06pm by Ms. Sue

comp 155
Re-think these: I know it is important, so I will defiantly be there (their) on time. I should of written (wrote) down where I last put them. I donít want to buy that. Itís to expensive. Correct I love my car. Itís interior is so comfortable. Correct An evening out can be a ...
Wednesday, June 29, 2011 at 2:19pm by Writeacher

comp 155
Write three sentence using plurals correctly and three sentences using possessives correctly on the topic of how to store personal financial information effectively and efficiently.
Friday, November 19, 2010 at 1:21pm by lorretta

comp 155
Compare and contrast your abilities as an academic writer now as opposed to when you began at Axia College. Using four comparatives and four superlatives within your responses, explain what has led to these changes and what changes you will make in the future.
Saturday, September 11, 2010 at 2:45am by Anonymous

math
155/775 First reduce that fraction to its lowest terms. I first get 31/155. That can be reduced again by dividing 155 by 31.
Monday, November 12, 2007 at 6:39pm by Ms. Sue

physics
mass = 155/1000 = 0.155 kg. V = 95mi/3600s * 1600m/mi = 42.2 m/s. Momentum=m*V = 0.155 * 42.2=6.54 kg.m/s
Sunday, January 19, 2014 at 7:18pm by Henry

Comp 155
When writing a paragraph, it is important that the topic sentence and supporting points within that paragraph be directly related. What would be the reaction of a reader if the topic sentences in an essay did not coincide with the supporting points?
Friday, August 19, 2011 at 8:05pm by Me

COMP 155
When writing a paragraph, it is important that the topic sentence and supporting points within that paragraph be directly related. What would be the reaction of a reader if the topic sentences in an essay did not coincide with the supporting points?
Sunday, November 28, 2010 at 10:59pm by Keisga

comp 155
I donít want to buy that. Itís to (too) expensive. Correct<~~delete this word I love my car. Itís ( Its) interior is so comfortable. Correct<~~delete this word ~~~~~~~~~~~~~~~~~~~~~~ And why did you change this one? Your welcome. I was happy to help. correct
Wednesday, June 29, 2011 at 2:19pm by Writeacher

Comp 155
Adjectives I see: best runaway toxic full moving unsuccessful unattended "a half-mile long" small veteran young runaway separatre toxic Adverbs I see: lately slowly "a engineer" -- are you kidding me? "decimate" -- only 1/10th of the town will be destroyed??
Sunday, May 1, 2011 at 4:09pm by Writeacher

Comp 155 Week 6
Describe your experience with credit and credit cards in a brief paragraph using at least five adverbs and five adjectives in your description. Bold the adverbs and underline the adjectives. What is the most effective way to determine whether a word is an adjective or an adverb
Tuesday, August 9, 2011 at 11:13pm by Camille

physics
what is the vert. comp. of vector with magnitude 88.5m/s and whose horiz. comp. is 75.4m/s? what is the direct. of this vector?
Sunday, January 13, 2008 at 7:16pm by Anonymous

math
Let x = length. Solve for x. (2*17.5) + 2x = 155 35 + 2x = 155 2x = 155 - 35 2x = 120 x = ?
Sunday, December 27, 2009 at 6:07pm by Ms. Sue

MaTh
4x + x 155 5x = 155 x = 31
Monday, August 19, 2013 at 10:22pm by Ms. Sue

math
consider the amount of $1 at the end of 2 years at 6.2% simple ---- 1 + (1)(.062)(2) = $1.124 at 6.1 comp. annually ---- (1.061)^2 = $1.1257 at 5.58% com. semi --- (1.0279)^4 = $1.11636 at 5.75% comp. quarterly -- (1.014375)^8 = 1.12096 so what do you think?
Monday, April 25, 2011 at 4:50pm by Reiny

Statistics
Between z = -2 and z = 0.4. (Points: 5) 0.655 0.977 0.477 0.155 0.633 my answer was o.155 is this correct
Sunday, June 20, 2010 at 11:11am by John

math
time = 8 years , 155 days = 8 + 155/365 = 8.42466 x e^(8.4266(.0895)) = 225500 x = $106092.70
Saturday, November 16, 2013 at 9:45am by Reiny

Chemistry
I got A) Exo B) Exo C) Endo D) Endo But its wrong :/ i have no idea what i am doing wrong. A) 942+3(432)-6(386)=-78 B)494-522=-28 C)4(459)-2(432)+494=478 D)2(155)-155=155
Sunday, January 22, 2012 at 10:53pm by Kristen

word problem money
1 quarter=25 1 dime=10 13x10=130 or 1.30+25=155 or 1.55 25x3=75 or .75+80=155 or 1.55 25x5=125 or 1.25+30=155 or 1.55 Correct :)
Monday, April 2, 2012 at 9:00pm by Rezu

Physics - Inelastic Collision ( check + help)
A billiard ball of mass 0.55kg moves with a velocity of 12.5m/s towards a stationary billiard ball of the identical mass and strikes it with a glancing blow. The first billiard ball moves of at an angle of 29.7deg clockwise from its original direction, with a velocity of 9.56m...
Sunday, September 26, 2010 at 2:52pm by Shaila

stats
Here's the rest of the data 155 160 150 145 200 155 190 140 170 175 142 168
Tuesday, March 12, 2013 at 1:49pm by kelly

math
x=number of 2 legged birds y=number of 4 legged mammals 2x+4y=550 if there are a total of 155 animals and you know the number of 2 legged birds, you could subtract the two and find the number of 4 legged mammals therefore, let y=155-x substitution: 2x+4(155-x)=550 solve for x...
Monday, August 9, 2010 at 6:56pm by Anonymous

Comp 155
http://www.wikihow.com/Buy-a-House
Monday, August 15, 2011 at 6:37pm by Writeacher

geometry
I found out the first part of which is x for the figure which was 115 degrees.They do give you the other measures of the angles which are 115,155,155,155.135,135,115.The second part of the problem say yo find the sum of the measures of the exterior angles,one at each vertex,...
Saturday, July 23, 2011 at 4:59pm by Lauren

chemistry
155.0 grams of N2 (nitrogen gas) are put in a 4.50L container at 35C. What is the pressure? PV=nRT n=155/molmassN2 Convert temps to K.
Tuesday, January 9, 2007 at 6:54pm by TIFFANY

Comp/155
Surely this has been covered in your text or other course materials. You can also use this: http://grammar.ccc.commnet.edu/grammar/index2.htm Read and study all the sections on pronouns; there are five.
Friday, April 1, 2011 at 2:19am by Writeacher

Math
let the bill before taxes and tips be $x then (1.15)(1.08)x = 193 x = 193/((1.15)(1.08)) = 155.39 After tax, bill was 155.39(1.08) = 167.83 now 15% of that is 25.17 so the tip was 25.17 check: [155.39 + .08(155.39)])1.15) = 193
Saturday, February 13, 2010 at 10:04pm by Reiny

math
$56,950 * (0.118) * (155/365) = $2853.74 This assumes simple interest, with no payments and principal reduction during the 155 day interval.
Tuesday, June 14, 2011 at 12:25am by drwls

trig
150 at 155į = 63.4i -135.9j 25 at 160į = 8.6i - 23.5j sum = 72.0i - 159.4j = 175.0 at 155.7į
Friday, November 16, 2012 at 6:17am by Steve

comp 155
No one can write this but you. Notice all the "you" and "your" in the assignment? Are you clear on what comparatives and superlatives are? If not, here's a good explanation with examples: http://grammar.ccc.commnet.edu/grammar/adjectives.htm#comparative
Saturday, September 11, 2010 at 2:45am by Writeacher

math
Pt = Po(1+r)^n, r APR / 4 = 4% / 4 = 1% = 0.01 = QPR = Ouarterly percentage rate. n=4 comp/yr * 6yrs = 24 comp. periods. Pt = 1300(1.01)^24 = $1650.66.
Sunday, July 3, 2011 at 8:31am by Henry

Physics
Vector: 14.7km @ (-35)deg = 325deg CCW, 4th QUAD. X = hor = 14.7*cos(325)=12.04km = East Comp. Y = ver = 14.7*sin(325) = -8.43km = South Comp.
Wednesday, January 19, 2011 at 6:31pm by Henry

Math
One way to reduce fractions is to start with a small number. I know that 155 and 70 is divisible by 5 because they end in 0 or 5. 70/155 = 14/31
Tuesday, November 1, 2011 at 2:45pm by Ms. Sue

physics
The vertical problem is dropping a mass from a height of 155 meters. The horizontal speed has nothing to do with the vertical problem. The vertical component of velocity is zero at the beginning. So how long to drop: y = Xo + Vi t + (1/2) a t^2 here x = -155 (or 155 down) Xo...
Wednesday, December 15, 2010 at 5:38pm by Damon

math
Pt = Po(1+r)^n. r = (1.7%/360) / 100% = 0.0000472 = Daily % rate expressed as a decimal. n = 1 comp./day * 180 days = 180 comp. periods. Pt = 4800(1.0000472)^180 = $4840.41.
Thursday, December 8, 2011 at 4:43pm by Henry

Comp 155
http://owl.english.purdue.edu/owl/resource/685/01/
Wednesday, August 24, 2011 at 11:16pm by Ms. Sue

Chemistry
I assume that is 155 kJ and not 155 kJ/mol. 40.7 kJ/mol x (?mol) = 155 kJ.
Friday, April 22, 2011 at 9:03am by DrBob222

Math
I'm assuming you mean the rate changes to 9 % after 3 years. Pt = Po(1+r)^n. r = (10%/4) / 100% = 0.025 = Quarterly % rate exprssed as a decimal. n = 3 yrs * 4 comp / yr. = 12 Comp. periods. Pt = $9000(1.025)^12 = $12,104 After 3 years. r = (9%/2) / 100% = 0.045 = Semi-annual...
Wednesday, January 11, 2012 at 5:14pm by Henry

Physics
Vo = 27m/s @ 20 Deg. Xo = 27*cos20 = 25.4 m/s = Hor. comp. Yo = 27*sin20 = 9.2 m/s. = Ver. comp. A. h = (Y^2-Yo^2)/ 2g. h = (0-(9.2)^2 / -19.6 = 4.35 m. B. V = 0 @ max. ht. C. R = Vo^2*sin(2A)/g. R = (27)^2*sin40 / 9.8 = 47.8 m.
Wednesday, June 20, 2012 at 11:34pm by Henry

physics
A man pushs a cart wt a force of 36N directd@ an angle 25dgree belw the horizontal. The horizntal comp oe the force is 32.6N.The vrticl comp of force is 15.6N.Fnd work dne on the cart as the prsn moves50m
Monday, August 15, 2011 at 2:36am by Luc

physical
how do i get a 45 year old inactive male who weighs 280lb and has a body comp of 55% lean mass and 45% fat mass.down to his goal! his goal is to alter his body comp to 80%-20% and lower his weight to 200lbs
Sunday, February 1, 2009 at 5:09pm by Leah

math
To convert a percentage to a decimal number, divide by 100. For example, 155% = 155/100 = 1.55 You can convert the percentages to the scale factors the same way.
Thursday, November 26, 2009 at 8:06pm by MathMate

math
You must have been given a table or chart with the conversion factors between your different units. Some of these I don't know. e.g. what is pm and nm ? the first is done this way: 1 km = 1000m so 155 km = 1000(155) m = 155000 m
Friday, October 9, 2009 at 8:10am by Reiny

physics
Thank you for giving both speed and radius this time: Ac = v^2/r at the top force on seat = m (v^2/r - g) = 92 (155^2/596 -9.8) = 2806 N at the bottom m (v^2/r + g) =92 (155^2/596 +9.8) = 4610 N
Saturday, October 25, 2008 at 6:25pm by Damon

math
$155.5 how I found it: I tried to find what an amount for which to total amount of tax cost $9.33 so, I chose random numbers to test this, 155.5x.06=9.33
Tuesday, February 25, 2014 at 9:28pm by Ashley

Physics
h1=a*t^2 = 28.3*5.5^2=856.1 m Above gnd. V1 = a*t = 28.3 * 5.5 = 155.7 m/s. V = V1 + g*t = 0 155.7 - 9.8t = 0 -9.8t = -155.7 t = 15.9 s. To reach max ht. h2 = V1*t + 0.5g*t^2 h2 = 155.7*15.9 - 4.9*15.9^2 = 1236 m Above h1. h = h1 + h2 = 856 + 1236 = 2092 m. Above gnd.
Tuesday, September 17, 2013 at 10:45pm by Henry

COM 155
What do you hope to accomplish COM 155?
Tuesday, February 28, 2012 at 3:59pm by Destiny

Physics
Do a vertical frce balance. The "normal force" is the force upward exerted by the ground on the suitcase. 155 N + X sin 25 = M g (the weight) X is the force applied to the handle and M = 23 kg. Solve for X 0.4226 X = 225.6 - 155 = 70.6 N
Thursday, January 14, 2010 at 2:45pm by drwls

physics
i dont understand how to do this question, its a phys 11: "A skier is acc. down a 30.0 degree hill at 3.80m/s^2" a) What is the horiz. comp. of the acc.? b) What is the vert. comp. of the acc.? c) Assuming she starts from rest and acc. uniformly down hill, how long will it ...
Sunday, January 13, 2008 at 6:54pm by Anonymous

physics
Vo = 48.6m/s @ 37deg. Vo(h)=48.6cos37 = 38.8m/s = hor. comp. Vo(v)=48.6sin37 = 29.2m/s = ver comp. Rectangular Form: Vo = 38.8 + j29.2 m/s. The "j" means there is a 90 degree phase difference between the 2 vectors.
Friday, June 24, 2011 at 4:59pm by Henry

Finance
Pt = Po(1+r)^n, r = 4.40%/yr * 0.75yr = 3.3% = 0.033 = rate per compounding period expressed as a decimal. n = 15yrs / 0.75yr/comp.Period = 20 Comp. periods. Pt = 1000(1.033)^20 = $1914.28.
Tuesday, October 4, 2011 at 8:03am by Henry

maths
we know that 2+(n-1)d = 29, so d = 27/(n-1) sum of first n terms is n/2 (4+(n-1)d) n/2 (4+(n-1)*27/(n-1)) = 155 n = 10 check: d = 27/9 = 3 10th term is 2+9(3) = 29 S10 = 5(4+9(3)) = 155
Monday, April 22, 2013 at 3:44pm by Steve

Math
Pt = Po(1+r)^n. a. r = (8.01%/12) / 100% = 0.006675 = Monthly % rate expressed as a decimal. n = 12 comp./yr * 15 yrs. = 180 comp. periods. Pt = 2631(1.006675)^180 = $8713.48. b. Pt = Po(1+r)^n. r = (8.01%/360) / 100% = 0.0002225 = daily % rate expresed as a decimal. n = 360 ...
Sunday, December 11, 2011 at 6:22am by Henry00

physics
m1v1v+m2v2=(m1+m2)V 2500*-14i+1500*23j=(3800)V then X-comp is 2500*-14/3800 Y-comp is 1500*23/3800 P=(m1+m2)V find the value of V from the square root of the previous .... 0553053359
Wednesday, September 1, 2010 at 6:07am by Qais

algebra
Pt = Po(1 + r)n. r = 5%/yr * 0.5yr = 2.5% = 0.025 = semi-annual rate expressed as a decimal. n=2 comp/yr * 6yrs = 12 comp. periods. Pt = 20000(1.025)^12, Pt = 20000 * 1.3449 = $26,897.78
Friday, March 4, 2011 at 1:23am by Henry

Chemistry
See my note at your original post about the number of significant figures. Also, in this post note the typo on the first problem. moles = 0.155/46.0 and not 0.155 x 46.0
Tuesday, June 14, 2011 at 4:00pm by DrBob222

univ/com/155
write a paragraph of instructions on the writing process for future com/155 students.include the steps in the writing process.
Thursday, April 26, 2012 at 8:00pm by sonya

exp of math
Pt = Po(1+r)^n, r = APR/2 = 8% / 2 = 4% = .04. n = 2 comp/yr * 3yrs = 6 comp. periods. Pt = 2195(1.04)^6 = $2777.38. Int. = 2777.38 - 2195 = $552.38.
Sunday, July 3, 2011 at 8:14am by Henry

algebra
Conventional algebra: x=number of small cups y=number of large cups form the system of equations x+y=155 2x+3y=335 Solve the system for x and y. Quick way by substituting directly: Let 155-x=number of large cups 2x+3(155-x)=335 Solve the linear equation for x. Faster way by ...
Tuesday, May 7, 2013 at 6:09pm by MathMate

Math
Pt = Po(r + 1)^n. r = 16% / 4 = 4% = 0.04 = Quarterly int. rate. n = 4 yrs * 4 comp / yr 16 comp. Pt = 4700 (1.04)^16, Pt = 4700 * 1.8730 = 8803.01 = Amt. due after 4 yrs.
Tuesday, November 30, 2010 at 4:33pm by Henry

math
The slope m of a line passing through two points (x1, y1), (x2, y2) is given by m = (y2-y1)/(x2-x1) m = (-5/6 - -5/4) / (-3-2/3) = (5/12) / (-11/3) = -15/132 = -5/44 The equation for a straight line is of the form y = m*x + b where m is the slope and b is the y-intercept. So ...
Tuesday, November 27, 2012 at 10:59pm by Jennifer

Physics
V = 155mi/h @ 225o + 45mi/h @ 0o. X = 155*cos225 + 45 = -64.6 Mi/h. Y = 155*sin225 = -109.6 Mi/h. V^2 = X^2 + Y^2. V^2 = (-64.6)^2 + (-109.6)^2 = 16,185.66 V = 127.2 Mi/h.
Thursday, January 24, 2013 at 4:45pm by Henry

Physics
2T=(2*pi*massproton)/(chargeproton*B) So a) B=(pi*1.67*10^-27)/(1.6*10^-19*155*10^-9) b) Doubling the kinetic energy changes the velocity. Period T does not depend on velocity so the answer is 155 ns.
Wednesday, November 17, 2010 at 11:04pm by ME

math
1. Investment: $15,000 @ 8% for 9mo,compounded quarterly. Pt = Po(1+r)^n. r = (8%/4) / 100% = 0.02 = Quarterly percentage rate expressed as a decimal. n = 4 comp./yr * 0.75yr = 3 comp. periods. Pt = 15,000(1.02)^3 = 15,918.12. Int. = 15918.12 - 15000 = $918.12. 2. Investment...
Friday, May 20, 2011 at 12:31pm by Henry

math
Number(P or C) = number(P) + number(C) - number(P and C) = 140 + 75 - 60 = 155 number (NOT(PorC)) = 200-155 = 45 OR Make a Venn diagram of 2 intersecting circles inside a rectangle, labeling them P and C for phone and car place 60 inside the intersection of the two circles ...
Wednesday, August 15, 2012 at 10:09pm by Reiny

Math
465 y = 155 x - 35 y = (155/465) x - 35/465 y = (1/3) x - 7/93 when x = 0 y = -7/93 no matter what you do starting with -7/93 going up with a slope of 1/3 it will be hard to get an integer y
Friday, February 7, 2014 at 6:46pm by Damon

Physics
This is a The Russell traction apparatus problem and I solved the weight to be 76N. The second part of the problem asks what the angle is if the traction force is 19.4N horizontally. My initial thought was to use half of the weight as the y-comp and 19.4 for as the x-comp to ...
Sunday, November 11, 2007 at 4:22pm by Lou-Anne

Physics
Im doing a problem on The Russell traction apparatus and I solved the weight to be 76N. The second part of the problem asks what the angle is if the traction force is 19.4N horizontally. My initial thought was to use half of the weight as the y-comp and 19.4 for as the x-comp ...
Sunday, November 11, 2007 at 6:00pm by Lou-Anne

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