Wednesday

April 16, 2014

April 16, 2014

Number of results: 86,725

**college algebra... LOG**

log4(little 4) 8 how do i write this in y=?
*Friday, November 18, 2011 at 9:18am by brianna*

**college algebra... LOG**

Use the laws of logarithms, log ab = log a+log b logaa = 1, and loga sqrt(b)=(1/2)loga b log 8 = log44*2 =log44+log42 =1+loga2 =1+(1/2)log42 =1+(1/2)(1) =3/2
*Friday, November 18, 2011 at 9:18am by MathMate*

**College Algebra..LOG**

log4(little four) (40 - 3x) = 0 now i need to solve for x...
*Sunday, November 20, 2011 at 8:50pm by Brianna *

**College Algebra..LOG**

log4(little four) (40 - 3x) = 0 now i need to solve for x...
*Sunday, November 20, 2011 at 10:06pm by Brianna *

**College Algebra..LOG**

log 1 = 0 to any base so, 40-3x = 1 x = 13
*Sunday, November 20, 2011 at 8:50pm by Steve*

**college algebra**

2 log x- log 9=log 441
*Tuesday, July 24, 2012 at 10:21am by faylinn*

**college algebra**

2 log x- log 9=log 441
*Tuesday, July 24, 2012 at 10:32am by faylinn*

**Log Algebra**

Find the inverse of the function y=log8 x
*Sunday, May 1, 2011 at 10:58am by Marta*

**Log Algebra**

See: http://www.jiskha.com/display.cgi?id=1304264746
*Sunday, May 1, 2011 at 10:58am by MathMate*

**College Algebra**

log(x+10)=1+log(4x-3)
*Friday, April 20, 2012 at 8:06pm by Brian*

**College Algebra**

log(xy^12)
*Saturday, December 1, 2012 at 1:06am by Jason*

**algebra**

(y-3)(y-6)=0
*Thursday, July 28, 2011 at 9:23pm by college math*

**ALGEBRA**

Why is it impossible to combine the expression radical 3x + 3^ radical 3x into a single term? Explain. (I'm having a real tough time with this one, can anyone here explain this to me? Thank you!)
*Monday, November 4, 2013 at 6:26pm by College Student*

**college algebra, Please help!!**

log(1.9)= log(a^6) log(1.9) = 6*log(a) log(a) = (log(1.9))/6
*Tuesday, November 27, 2012 at 10:29pm by Jennifer*

**Calculus**

Determine the area of the region enclosed by the limaçon r=5+2sin(theta)
*Saturday, March 21, 2009 at 8:17pm by Log*

**log**

please help given that 4^(2x+1) X 7^(x-1) = 8^x X 14^2x evaluate 14^x this is what i did, but i got stuck anyways. 2^(4x+2) X 7^(x-1) = 2^3x X 14^2x 2^(x+2) = 2^2x X 7^(x+1) sorry this might be a bit confusing, but the big letter X is 'multiply'
*Thursday, July 2, 2009 at 7:49am by log*

**math!!!!!!! help 3**

You first need to find out how many gallons would be drank after 6 days, so you multiply 3/5 * 6 to get 18/5. Then you subtract 18/5 from the original 5 gallons so 5 - 18/5. You have to make equivalent fractions so you put the 5 over one, and multiply the numerator and ...
*Wednesday, October 27, 2010 at 9:56pm by Log*

**math!!!!!!! help 3**

You first need to find out how many gallons would be drank after 6 days, so you multiply 3/5 * 6 to get 18/5. Then you subtract 18/5 from the original 5 gallons so 5 - 18/5. You have to make equivalent fractions so you put the 5 over one, and multiply the numerator and ...
*Wednesday, October 27, 2010 at 9:56pm by Log*

**College Algebra**

solve the following: Log(50x)+log(x-1)=2
*Monday, March 7, 2011 at 8:00pm by bob*

**Math algebra **

the length of a rectangular photograph is 8in. more than the width. if the area is 560 in^2 what are the dimensions of the photograph? the width is____ in. and the length is ____ in.
*Friday, February 15, 2013 at 3:31pm by college student*

**math algebra **

the length of a rectangular photograph is 11 in. more than the width. if the area is 80in^2 what are the dimensions of the photograph ? the width is___ in. and the length is___ in.
*Friday, February 15, 2013 at 3:51pm by college student*

**College Algebra**

amount = 1(1/2)^(t/5700) .34 = .5^(t/5700) log .34 = (t/5700)log .5 t = 5700(log .34)/log .5 = 8871 years
*Monday, November 22, 2010 at 10:47am by Reiny*

**college algebra**

You are going to use 3 man rules of logs 1. log(A/B) = logA - logB 2. Log(AB) = logA + logB 3. log A^n = nlogA log 3√x + log x^4 - log x^3 = log 3 + log x^(1/2) + 4logx - 3logx = log3 + (1/2)logs + logx = log3 + (3/2)logx 2. 4 log (x+3) - 5 log (x^2+4) + 1/3 log y = log...
*Wednesday, April 17, 2013 at 8:57am by Reiny*

**college algebra**

log(a^b) = b log(a) log(ab) = log(a) + log(b) since 1/b = b^-1, log(a/b) = log(a) - log(b) since √a = a^(1/2), log √a = 1/2 log a log x^4y^7/4 = 4logx + 7logy - log4 so you should be able to do the other if these problems involve logs base 4, that doesn't matter. ...
*Wednesday, April 17, 2013 at 4:36pm by Steve*

**College Algebra**

.29*5=2-log(100-x) log(100-x)=.55 100-x=3.55 x=96.4
*Tuesday, December 9, 2008 at 7:23am by bobpursley*

**College Algebra**

.1 = .5^(t/5700) t/5700 = log .1/log .5 t = 18935
*Wednesday, December 8, 2010 at 9:17pm by Reiny*

**college algebra**

log = natural logarithm log ( a ^ n ) = n * log ( a ) If your expression mean : e ^ ( 0.05 t ) = 1600 then : 0.05 t * log ( e ) = log ( 1600 ) Remark : The natural logarithm of e = 1 0.05 t = log ( 1600 ) Divide both sides by 0.05 t = log ( 1600 ) / 0.05 Remark : 1 / 0.05 = 20...
*Tuesday, January 31, 2012 at 1:00am by Bosnian*

**College Algebra**

Log(x+10) = 1 + Log(4x-3). Log(x+10)-Log(4x-3) = 1. Log(x+10)/Log(4x-3) = 1. Cross multiply: Log(x+10) = Log(4x-3). If 2 numbers have equal Logs, the numbers are equal: x+10 = 4x-3. 4x-x = 10+3. 3x = 13. X = 13/3.
*Friday, April 20, 2012 at 8:06pm by Henry*

**college algebra**

solve the following logarithm equation log (4x+7)=1+log(x-6) x=? please show work
*Wednesday, September 5, 2012 at 6:42pm by ALLI*

**College Algebra**

How do you solve 3 log(base 2)*(x-1)+ log(base 2)4=5
*Monday, November 12, 2012 at 12:15pm by Hope*

**College Algebra**

Write the expression as a single logarithm whose coeffecient is 1. Log x + 12 log y
*Saturday, December 1, 2012 at 1:06am by Billie*

**college algebra**

ln y = log 9 e^(ln y) = e^(log 9) y = e^(0.9542) y = 2.5967
*Monday, November 4, 2013 at 8:18pm by Jai*

**college algebra**

log x^2 - log9 = log 441 log (x^2 /9) = log 441 "antilog" it x^2/9 = 441 x^2 = 3969 x = ±63 , but we cannot take log of a negative, so x = 63
*Tuesday, July 24, 2012 at 10:32am by Reiny*

**college algebra**

log10(7^x) = log10(8) Using log rules (log(a^b) = b*log(a)) x*log10(7) = log10(8) x*.845 = .903 = log(8)/log(7) x = 1.068 to 3 decimals
*Tuesday, November 27, 2012 at 11:21pm by Jennifer*

**College Algebra**

Give the real solution set for each of the following: 42) log(6)(x^2+11) + log(6)x = 1 + log (6)(x^2+1)
*Tuesday, November 16, 2010 at 8:23pm by Y0gi*

**College Algebra**

1.45=2-log(100-x) -.55=-log(100-x) .55=log(100-x) take the antilog of each side 3.458133892=100-x You are taking the LOG of both sides. You want the antilog.
*Tuesday, December 9, 2008 at 7:23am by bobpursley*

**College Algebra**

Solve the logarithmic equation for x. log(base 3)(x+6) - log(base 3)(x+1)=1 urgent! help!
*Tuesday, December 4, 2012 at 9:38pm by Patrick:)*

**college algebra**

Solve the logarithmic equation. Log x +log2x = 4 Wouldn't this be no solution because log x is undefined?
*Wednesday, April 24, 2013 at 3:49pm by Deb*

**college algebra**

Write expression as one logarithm and simplify if appropriate. log 3√x + log x^4 - log x^3 4 log (x+3) - 5 log (x^2+4) + 1/3 log y I have these who problems but I don't know where to start. HELP Please.
*Wednesday, April 17, 2013 at 8:57am by Deb*

**algebra-LOG - correction**

Use the laws of logarithms, log ab = log a+log b logaa = 1, and loga sqrt(b)=(1/2)loga b log 8 = log44*2 =log44+log42 =1+log42 =1+(1/2)log44 =1+(1/2)(1) =3/2
*Friday, November 18, 2011 at 9:18am by MathMate*

**algebra solving log equations**

n sqrt(x-8)= 5 I would like help to solve this what i did was to take away the square root i squared both sides coming up with (ln sqrt(x-8))^2= (5)^2 ln(x-8)=25 am i alowed to do this with ln in the equation? then i subtract 8 from both sides ln x = 17 e^(ln x)= e^17 e ...
*Wednesday, October 30, 2013 at 9:50pm by Marcos*

**algebra solving log equations**

Ln sqrt(x-8) = 5 Exponential form: e^5 = sqrt(x-8) Square both sides: e^10 = x-8 X = 8 + e^10 exponential form:
*Wednesday, October 30, 2013 at 9:50pm by Henry *

**College Algebra**

recall that n*log(a) = log(a^n) so, using base 2, we have 3log(x-1)+log(4) = 5 log(x-1)^3 + 2 = 5 log(x-1)^3 = 3 (x-1)^3 = 2^3 x-1 = 2 x = 3 check: 3log2 + log4 = 5 3+2 = 5
*Monday, November 12, 2012 at 12:15pm by Steve*

**college algebra**

logx + log 2x = 4 log (x(2x)) = 4 , using the rule log AB = logA + logB log (2x^2) = 4 so 2x^2 = 10^4 2x^2 = 10000 x^2= 5000 x = ± √ 5000 but x > 0 for log x to be defined so x = √5000
*Wednesday, April 24, 2013 at 3:49pm by Reiny*

**college algebra**

assuming 52 weeks per year i = .078/52 = .0015 5000(1.0015)^n= 8000 1.0015^n = 1.6 log (1.0015^n) = log 1.6 nlog1.0015 = log 1.6 n = log1.6/log1.0015 = 316.57 monts = 6.03 years it would take 6 years
*Saturday, October 15, 2011 at 10:10pm by Reiny*

**College Algebra**

Let T be the age in years. 0.27 = (0.5)^(T/5700) Take logs of both sides to solve. T/5700 = log(0.27)/log(0.5) = 1.889 T = ___ years
*Wednesday, December 1, 2010 at 1:07am by drwls*

**college algebra**

Irf you mean log base 2 2^log2(x) = x = 2^y
*Friday, April 23, 2010 at 3:04pm by Damon*

**College Algebra**

Write each of the following as a single logarithm: 8) ((5-log x)/4) + 4log y =
*Tuesday, November 16, 2010 at 8:20pm by Y0gi*

**College Algebra**

Write each of the following as a single logarithm (log (x+3))/(3) = 1
*Tuesday, November 16, 2010 at 8:22pm by Y0gi*

**college Algebra**

Ln y = Log 9 = 0.95424 Exponential form: e^(0.95424) = y Y = 2.5967
*Monday, November 4, 2013 at 5:40pm by Henry *

**college algebra**

lots of folks just write log_2(x-2) the numbers are subscripts, not lower-case. 1. since we're dealing with logs base 2, just say log: 2log(x-2) + log2 = 3 log(x-2)^2 + log2 = 3 log(2(x-2)^2) = 3 2(x-2)^2 = 8 (x-2)^2 = 4 x = 0 or 4 I assumed that log(lower2)^2 meant log(lower2...
*Friday, November 30, 2012 at 2:57pm by Steve*

**College Algebra**

No, it can't, it is sloppy math. you cant say log8(1000)=log1000=3 log8(x) is not logx unless you know the log is base 8. for instance, if x is 64 log8(x)=2 log (64)=1.806
*Thursday, October 21, 2010 at 10:54am by bobpursley*

**College Algebra**

adding logs follows this rule (log ab)=loga + logb you have log (50x*x-1)=2 take the antilog of each side. 50x(x-1)=100 solve for x
*Monday, March 7, 2011 at 8:00pm by bobpursley*

**College Algebra**

Solve the logarithmic equation. Express your solutions in exact form only. Please show all of your work. log base 6 (64x^3+1)-log base 6 (4x+1)=1
*Wednesday, January 18, 2012 at 3:00am by Jo *

**College Algebra**

another way would be 3log(x-1)+log(4) = 5 3log(x-1) + 2 = 5 3log(x-1) = 3 log(x-1) = 1 x-1 = 2^1 = 2 x = 3
*Monday, November 12, 2012 at 12:15pm by Steve*

**college algebra**

use the properties of logarithms to find the exact value of the expression loglower 3^18 - log lower3^6 **how do I make the three lower in the log equation?
*Tuesday, November 27, 2012 at 11:41pm by confused*

**college algebra**

I need to expand the expression without exponents. We haven't covered this yet so I am confused on how to do both of them Log x4y7/4 4 log x^8/√yz^5 4 Thanks, for your help.
*Wednesday, April 17, 2013 at 4:36pm by Deb*

**college algebra**

4^(x-3) = 3^(2x) (x-3)*Log4 = 2x*Log 3 Divide both sides by Log 4: x-3 = 2x * 0.79248 = 1.5850x x - 1.5850x = 3 -0.5850x = 3 X = -5.1282
*Monday, November 18, 2013 at 7:41pm by Henry *

**College Algebra**

Solve for x: 3^(2x)=14 We've gotten: 2x=log(subscript 3)14=2.4 Is this two answers, or what?
*Wednesday, August 5, 2009 at 6:45pm by Angela*

**College Algebra**

Express as an equivalent expression, using the individual logarithms of w,x,y and z. log a (xy^2z-3)
*Tuesday, February 9, 2010 at 6:36pm by Ashley*

**college algebra**

2Logx - Log9 = Log441. Logx^2 = Log441 + Log9 Logx^2 = Log(441*9) Logx^2 = Log3969 x^2 = 3969 X = 63
*Tuesday, July 24, 2012 at 10:21am by Henry*

**college algebra**

solve the following logarithmic equation. 1. 2log(lower2) (x-2) + log(lower2)^2=3 I do not know how to make the 2 by the g on my computer. 2. log(lower729^x) + log(lower27^x) + log(lower3^x) =9 again I do not know how to make the numbers lower case please show work, and if you...
*Friday, November 30, 2012 at 2:57pm by confused--two questions please help*

**college algebra**

not sure how to find the t, tried using the log approach but can't get the right answer.
*Sunday, November 17, 2013 at 4:10pm by Dee*

**College Algebra**

=/ I still do not understand. This is my setup. 5=[2-log(100-x)]/.29 1.45 = 2-log(100-x) -.55 = -log(100-x) .55= log(100-x) Now I am frozen there... If i take the log of both sides I do have 100-x on the right but obtain -.2596 for the left. The problem would equal 100.2596 ...
*Tuesday, December 9, 2008 at 7:23am by Marlon*

**college**

This question is algebra
*Friday, September 4, 2009 at 7:39pm by Dana*

**College Algebra**

and your question? If it is to solve for x, take the log base 3 of each side. 2x=log3 14=2.40
*Wednesday, August 5, 2009 at 6:34pm by bobpursley*

**college algebra**

isn't that 2^3=2^5x * 2^2x^2 ? take the log base 2 of each side 3=5x+2x^2 solve for x
*Sunday, May 2, 2010 at 8:21am by bobpursley*

**College Algebra**

Give the rational number that is the exact value for each of the following: 14) Log(9)((∛(3)/(ï¿½Ã£(27))=
*Tuesday, November 16, 2010 at 8:19pm by Y0gi*

**College Algebra**

2^(x+1) = 5^2x. Take log of both sides: (x+1)log2 = 2xlog5, 0.301X + 0.301 = 1.398X, 0.301X - 1.398X = -0.301, -1.097X = -0.301, X = 0.2744.
*Thursday, April 28, 2011 at 5:45pm by Henry*

**College algebra**

Use the properties of logs to write the expression as one log: 8log(base 5)4th square root of x minus 4log(base 5) x
*Sunday, May 12, 2013 at 4:18pm by Taylor*

**college Algebra**

Use a calculator to find y to four decimal places, if possible. (If an answer is undefined, enter UNDEFINED.) ln y = log 9
*Monday, November 4, 2013 at 5:40pm by Dee*

**college algebra**

Use a calculator to find y to four decimal places, if possible. (If an answer is undefined, enter UNDEFINED.) ln y = log 9
*Monday, November 4, 2013 at 8:18pm by Dee*

**College Algebra**

#1. assuming base 8, just for ease of readability, 2logx = log(4x+12) log(x^2) = log(4x+12) so, if the logs are equal, so are the numbers: x^2 = 4x+12 x^2-4x-12=0 (x-6)(x+2)=0 x=6 only, since log(-2) is not real. #2. so far, so good. Recall that adding/subtracting logs means ...
*Wednesday, December 4, 2013 at 1:17pm by Steve*

**college algebra**

Is that log to base 5 or log [5(2x+1)] ? Assuming that you mean base 5, 5^g = 2x +1 x = [5^g -1]/2 which can be written, g^-1(x) = [5^g -1]/2 where g^-1(x) is the inverse function of g(x)
*Friday, December 7, 2007 at 12:51pm by drwls*

**College Algebra**

log 6[ (64x^3+1)/(4x+1) ] = 1 (64x^3+1)/(4x+1) = 6^1 (4x+1)(16x^2 - 4x + 1)/(4x+1) = 6 16x^2 - 4x - 5 = 0 x= (4 ± √336)/32 = (4 ± 4√21)/32 = (1 ± 21)/8 We have to reject the negative answer or else the log would be undefined so x = (1 + √21)/8
*Wednesday, January 18, 2012 at 3:00am by Reiny*

**college algebra**

using rules of logs, your equation becomes log8 ((x+8)/(x+7)) = 2 (x+8)(x+7) = 8^2 = 64 x^2 + 15x + 56 - 64 = 0 x^2 + 15x - 8 = 0 x = (-15 ± √257)/2 but x > -7 or else the log part would be undefined so x = (-15 + √257)/2
*Saturday, December 1, 2012 at 11:08am by Reiny*

**log**

2.4^(3x+1)=9
*Monday, February 18, 2008 at 8:10pm by yaz*

**log**

log [2.4^(3x+1)] = log 9 (3x+1)log(2.4) = log9 I will let you finish it.
*Monday, February 18, 2008 at 8:10pm by Reiny*

**log**

How do you solve 6log2x = 13 I got log2x^5 = 13 but I don't know what to do next. Would it be 2x^5 = 13^2 HELP. Thanks.
*Wednesday, March 4, 2009 at 1:55am by Chopsticks*

**log**

6log2x=13 log2x=13/6 2x=10^13/6 x=73.39
*Wednesday, March 4, 2009 at 1:55am by Dr Russ*

**log**

thanks Dr. Russ!
*Wednesday, March 4, 2009 at 1:55am by Chopsticks*

**Log**

Expand Log5(5squareroot x/7) the first 5 is a base how would you expand that?
*Thursday, March 12, 2009 at 12:39am by Chopsticks*

**Log**

log(base5) of 5 sqrtx/7) = log (base5) 5 + log(base5)x^1/2 - log(base5) 7 = 1 + (1/2) log(base5) x - 1.20906 = (1/2) log(base5)x - 0.20906 I assumed that your square root was of x, not of x/7
*Thursday, March 12, 2009 at 12:39am by drwls*

**log**

what happens to the shape of the graph of f(x)=b^x when b=1? what happens to the shape of its inverse? explain why this happens
*Sunday, May 3, 2009 at 5:36pm by Anonymous*

**log**

4^(2x+1) * 7^(x-1) = 8^x * 14^2x 4^2x * 4 * 7^x /7 = (4*2)^x * (7^x)^2 (4/7)*(4^x)^2 = 4^x * 2^x * 7^x (4/7)* 4^x = 2^x * 7^x (4/7)* (2*2)^x = 2^x * 7^x = (14^x) (4/7)*2^x = 14^x = (2*7)^x (4/7) = 7^x x log 7 = log (4/7) = -.559616 x = -.28758 14^x = 0.46816 Check my thinking...
*Thursday, July 2, 2009 at 7:49am by drwls*

**log**

Use the properties of log to find the exact value of each expression. Do not use calculator 8 log 8^5
*Saturday, April 6, 2013 at 9:43am by Alley*

**log**

how long will it take $40,000 invested at 9% compounded continuously to double A=Pe^rt
*Wednesday, March 5, 2014 at 8:34am by montricia*

**log**

2 = e^.09 t ln 2 = .09 t = .6931 t = 7.7 years
*Wednesday, March 5, 2014 at 8:34am by Damon*

**College Algebra**

If a fraction is taken to a power, the value decreases. (1/2)^2 is 1/4 pH=-log(H+) where (H+) is the hydrogen ion concetnration in moles/liter. Search on google pH vinegar
*Saturday, November 3, 2007 at 10:03am by bobpursley*

**College Algebra**

All you have to do is compute the logs to base 10 of 4.63x10^-9 and 9.32x10^-4 , and add a minus sign. For seawater, the answer is 8.33, which is 9.00 - log 4.63
*Monday, December 8, 2008 at 1:54am by drwls*

**College Algebra**

For the exponential function e^x and logarithmic function log x, graphically show the effect if x is halved. Include a table of values for all four functions. Could someone please explain to me what occurs when things are halved.
*Thursday, May 14, 2009 at 9:14pm by Carmen*

**college**

3log2+2log8- 1/2 log4 = log (2^3) + log(8^2) - log(4^(1/2)) = log 8 + log 64 - log 2 = log(8*64/2) = log 256
*Thursday, December 9, 2010 at 10:54am by Reiny*

**College Algebra**

The purpose of e and ln. It turns out, in natural processes, which are continual in nature, have a form of expontential (ie log) growth to a base e (2.71828....). So it is a handy base. Humans leared to count to number bases which were whole numbers (based on 10, or 8, or 4, ...
*Thursday, October 21, 2010 at 10:54am by bobpursley*

**college**

log(782)=log782 / log12
*Saturday, December 5, 2009 at 2:28pm by bobpursley*

**College Algebra**

f(g(x)) = 2/(g(x)-3) = 2/(7/x)-3) = 2x/(7-3x) domain would be all reals except x = 7/3, but we have to recall that g(x) is not defined for x=0. So the domain of fog is all reals except 0, 7/3 2^(1-9x) = e^2x take log of both sides, recalling that ln(a^b) = b*lna: (1-9x)ln2 = ...
*Tuesday, August 14, 2012 at 1:45pm by Steve*

**College Algebra**

Using the relation ln(ex = x For e5x = 2 Take natural log on both sides, ln(e5x) = ln(2) 5x = ln(2) x = ln(2) / 5 Now make your pick for the answer.
*Wednesday, August 26, 2009 at 1:47pm by MathMate*

**College Algebra**

You're right so far, which was the hard bit. Me, I'd just pull out the calculator at this point. I did, and got 67.2972 = 67.30 to 2 d.p. You can do it by = 29 * sqrt(sqrt(29)) or by log tables. I can't think of an especially clever way.
*Saturday, October 24, 2009 at 5:29pm by jim*

**college algebra**

That would be ln5 - ln3. Use log tables, a pocket calculator or Google to calculate the value. http://www.google.com/#sclient=psy&hl=en&q=ln(5%2F3)&aq=&aqi=&aql=&oq=&gs_rfai=&pbx=1&psj=1&fp=567204dc07534ddc
*Tuesday, November 23, 2010 at 7:13pm by drwls*

**College Algebra**

If you mean e^x * e^(4x+4) = 1 just take log of both sides: x + (4x+4) = 0 5x = -4 x = -4/5 check e^(-4/5) * e^(-16/5 + 20/5) = e^(-4/5) * e^(4/5) = e^(-4/5 + 4/5) = e^0 = 1
*Sunday, November 20, 2011 at 12:24pm by Steve*

**college algebra**

Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by S(t) = 68 - 20 log (t+1), t > 0
*Tuesday, January 31, 2012 at 1:53am by Betty*

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