Wednesday

April 16, 2014

April 16, 2014

Number of results: 28,195

**Calculus**

We are doing limits in Calculus, but now we are doing trig limits too and i do not get how to do any of them. For example ones like this, how do you do them? sec (x-1) / (x sec x) x approaches 0 ((3 sin (x)) 1 - cos(x)) / (x^2) x approaches 0 (sin (2x)) / (sin (3x)) x ...
*Sunday, September 28, 2008 at 8:15pm by Michael*

**calculus**

The triangle is bounded by x-axis x=1, and y=x. The integrals can be carried out in order dx, then dy or vice-versa. However, integrating with respect to dy first makes for an easier integration (in the evaluation of I). Be very sure you understand how the limits are obtained...
*Monday, April 2, 2012 at 3:30am by MathMate*

**calculus (limits)**

Use limits to explain why f(x)= (7-3X)/(X+9) has a vertical asymptote.
*Saturday, January 21, 2012 at 11:03pm by k*

**Calculus**

we know these limits exist as h->0: (f(a+h)-f(a))/h (g(a+h)-g(a))/h sum of limits is thus (f(a+h)-f(a) + g(a+h)-g(a))/h = (f(a+h)+g(a+h) - (f(a)+g(a))/h = ((f+g)(a+h) - (f+g)(a))/h the limit is d(f+g)/dx at x=a
*Monday, October 15, 2012 at 11:37pm by Steve*

**College Calculus**

Improper integrals implicitely imply taking limits of the upper and/or lower limits of the integration.
*Thursday, February 28, 2008 at 7:59pm by Count Iblis*

**calculus**

let u=(7-4x) then du=4dx so the integration is now.. INT u^2 du/4 limits from 7 to 3 looks like u^3/12 limits 7 to 3 check that
*Thursday, October 10, 2013 at 10:10am by bobpursley*

**Calculus**

TWO examples of each of the following: two sided limits and theorem on limits (SUM, difference, product, quotient, nth root, ).
*Wednesday, August 29, 2012 at 3:12am by Anne*

**Calculus - MathMate Please help**

nope, you are wrong. I got the correct answer. area1 and area2 are not equal to each other since their limits are DIFFERENT. for area1, the limits should be (from 0 to c/2) and for area2. the limits should be (from pi/2+c to pi). by solving it i got the value for c. Thank you ...
*Monday, November 29, 2010 at 6:42pm by K*

**Math**

I'm in Calculus AP and we are learning about limits. I'm having trouble with finding limits algebraically. So here's a sample that you can use to help explain this to me. Find the limit of lim x (arrow to the right) 1 x-1/x(squared)-1. Please help!
*Monday, September 5, 2011 at 4:26pm by Michael*

**Calculus**

TWO examples of two sided limits and each theorem on limits.
*Wednesday, August 29, 2012 at 12:48am by Nicole*

**Calculus please help!!! double integral**

Combine the following two integrals into one by sketching the region, then switching the order of integration. (sketch the region) im gonna use the S for integral sign..because idk what else to use. SS6ycos(x^3-3x)dxdy+SS6ycos(x^3-3x) And the first integration limits for x are...
*Thursday, March 22, 2012 at 4:32pm by Sean*

**Calculus**

I'm having trouble interpreting your variables and limits. c,d are the limits on dy? That's odd, since I'd expect functions of y to be limits on dx. Anyway, interpreting it as ∫[0,√12]∫[y^(1/3),sqrt(16-y^2)] dx dy I get 15.8, twice your answer I tried to get ...
*Wednesday, March 21, 2012 at 4:07am by Steve*

**Maths Calculus Derivatives & Limits **

Using the definition of the derivative evaluate the following limits 1) Lim h---> 0 [ ( 8 + h )^1/3 - 2 ] / h 2) Lim x ---> pi/3 ( 2cosx - 1 ) / ( 3x - pi)
*Tuesday, October 25, 2011 at 9:19am by Yousef*

**math**

-•-+-+-+-0-+-+-+-+-5-+-+-+-+-•-+-+-+ The interval notation uses square brackets [] to enclose the lower and upper limits when the limits are included in the interval. Parentheses () are used if the limits are excluded. In this case, the limits of -4 and 10 are ...
*Wednesday, November 25, 2009 at 8:56pm by MathMate*

**calculus, limits, l'hopital**

You're very welcome. Keep up the good work. Calculus is best learned with lots of practice.
*Sunday, February 13, 2011 at 3:08pm by MathMate*

**Calculus**

The limits are 0,3
*Friday, April 12, 2013 at 10:39am by Tiffany*

**Calculus**

In most introductory Calculus courses, the study of limits precedes the concept of the derivative, since limits are used to develop the derivative by First Principles, so ... using your idea of conjugates, ..... Lim ( √(4u+1) - 3)/(u-2) , u--->2 = Lim ( √(4u+1...
*Monday, September 16, 2013 at 1:32pm by Reiny*

**Calculus, Limits**

Thank you! That was a huge help!
*Monday, January 20, 2014 at 7:04pm by DeeDee*

**Calculus**

using the limits formula....
*Thursday, July 10, 2008 at 1:23pm by Vanessa*

**Calculus**

This question is related to limits.
*Saturday, February 21, 2009 at 4:39pm by Alex*

**Calculus**

Whatever you did using limits is wrong.
*Saturday, October 31, 2009 at 11:45pm by drwls*

**Calculus (Limits)**

I want to say that you are correct.
*Saturday, October 22, 2011 at 7:29pm by Damon*

**Math - Calculus**

how to solve limits?
*Monday, July 9, 2012 at 5:27pm by John*

**Calculus 3**

wow thank you! How did you find the limits for x and y?
*Friday, April 5, 2013 at 11:02am by Heather*

**Calculus- limits**

never mind it was 12
*Tuesday, April 15, 2008 at 2:39pm by Ethan*

**Calculus**

Yeah. Thanks. I found out that the limits are from 0 to 2 and 2 to 3.
*Wednesday, January 27, 2010 at 6:36pm by <3*

**calculus - limits**

limit approaches 6 x+6/x^2-36
*Tuesday, October 4, 2011 at 8:39pm by Michelle*

**calculus (limits)**

Graph the function and you will see it
*Saturday, January 21, 2012 at 11:03pm by yuuka*

**calculus**

Evaluate the Integral ∫1, 0 x^3(1+x^4)^6dx where 1=b 0=a for the limits
*Saturday, April 30, 2011 at 9:27pm by noell*

**Calculus**

Show, using limits, that f(x) = x2 x + 3, is continuous at x = 2.
*Wednesday, March 12, 2014 at 2:15am by Anonymous*

**CALC-LIMITS**

F(X)= x-2/(x^2-4) is continuous at x=1 and why as limits approach from 1+ and 1-
*Wednesday, December 19, 2012 at 4:28pm by daryl*

**Calculus - Limits**

lim x--> 3 (3 - x)/ (x^2 - 9) I know the answer is -1/6, but I can't figure out how to get there.
*Wednesday, September 19, 2007 at 12:18am by Jimmy*

**calculus**

[1 + 2/k + 1/k^2]/[1 - 3/k + 2/k^2] Numerator is A(k) = 1 + 2/k + 1/k^2 Denominator is: B(k) = 1 - 3/k + 2/k^2 What are the limits of A(k) and B(k) for k ---> infinity?
*Thursday, February 21, 2008 at 6:47pm by Count Iblis*

**Calculus: Limits**

2) converges, the other answers are correct
*Sunday, April 6, 2008 at 7:30pm by Count Iblis*

**calculus - limits**

limit as x approaches infinity; tan^(-1) (x^2 - x^4) any help is appreciated =D
*Sunday, October 18, 2009 at 9:48am by Reen*

**calculus (limits)**

factor (x+h)^.5 ? I do not know how Somehow you have to know that sqrt(1+h) ---> 1 + .5 h +.....
*Saturday, January 22, 2011 at 2:09pm by Damon*

**Calculus**

Find the indicated limits. Lim x-> 1- sqrt 1 - 1/ x-1
*Monday, June 6, 2011 at 3:00pm by Robo*

**calculus - limits**

Does the limit lim 2011t/3-(squareroot)t+9 exist ? t-0
*Tuesday, October 4, 2011 at 8:39pm by Whitney*

**Calculus**

Find the Limits. lim [t^3 + 3t^2]/[t^3 - 4t^2] t->0
*Saturday, October 8, 2011 at 7:36pm by Nemo*

**Calculus**

Evaluate the following limits (x^2 + 2x - 8)/x-2 Lim x->2
*Monday, April 29, 2013 at 7:28pm by Drew*

**Calculus - Limits. Check my answer, please! :)**

looks good.
*Sunday, October 6, 2013 at 11:44am by Steve*

**Calculus (Limits)**

Let f be defined as follows, where a does not = 0, f(x) = {(x^2 - 2a + a^2) / (x-a), if x does not = a 5, if x = a Which of the following are true about f? I. lim f(x) exists as x approaches a II. f(a) exists III. f(x) is continuous at x = a. A. None B. I, II, and III C. I ...
*Saturday, October 22, 2011 at 7:30pm by Mishaka*

**calculus**

find the derevative (hint try to use limits) (x^2010 - 1 )\(x -1 )
*Sunday, February 21, 2010 at 12:49pm by Anonymous*

**calculus, limits, l'hopital**

Thank you so much! I didn't think to remove the 6x. So helpful, thank you!!
*Wednesday, February 9, 2011 at 10:11pm by Kate*

**calculus**

The answer is 2 a = 0 (start of the spring) b = 1 integrate 4x then plug in the limits (0 and 1)
*Thursday, December 1, 2011 at 6:08pm by Chris*

**Calculus**

integral of 4-sqrt(x) = 4x - 2/3 x^(3/2) now just plug in your limits for x
*Wednesday, April 17, 2013 at 11:02pm by Steve*

**Calculus (Limits)**

f(x) is a function differentiable at x=1 and f′(1)=1/13. What is the limit of (x^3 - 1)/f(x) - f(1) as x approaches 1?
*Sunday, July 21, 2013 at 3:17am by Drake*

**Calculus**

area=int y dx over limits area=int(1/3 x^4 -4) dx area= 1/15 x^5 -4x over limits area=1/15-4-(-1/15+4)=2/15-8 reduce that. Area negative means below the x axis. area= 7 13/15= 7.866 And here is a neat numerical integration applet to demonstrate it. enter xo=-1, x1=1, 10 steps...
*Thursday, December 8, 2011 at 11:55pm by bobpursley*

**Math - Compound**

Quarterly componding of interest after one year at 6% annual rate gives you an annual yield of (1 + 0.06/4)^4 - 1 = 6.136% Continuous compounding requires you to consider limits. The answer is Limit (as n approaches infinity) of 1 + 0.06/n)^n - 1 Calculus shows that this ...
*Saturday, January 24, 2009 at 4:48pm by drwls*

**calculus - limits**

can someone help me determine that limit for the following function, as x --> -2? 2 - abs(x) / 2 + x
*Sunday, October 4, 2009 at 3:39pm by thomas*

**calculus**

find the derevative (hint try to use limits) (x^2010 - 1 )\(x -1 )as x approaches1
*Sunday, February 21, 2010 at 12:53pm by Anonymous 2*

**calculus**

It makes no sense. volume= 2PI INT y^2 dx over the x limits.
*Friday, August 13, 2010 at 6:18am by bobpursley*

**Calculus (Limits)**

using L'Hospital's Rule, lim = (3x^2-1)/(f'(1)-0) = 3/(1/13) = 39
*Sunday, July 21, 2013 at 3:17am by Steve*

**Calculus**

Following 2 questions are from a book at a point where LHopitals Rule, Squeeze Theorem etc. have not been discussed and limits (A) and (B) as given below are to be evaluated by simple methods like algebraic simplification etc. 1. Int. of (xlogx)dx from 0 to 1. Indefinite Int...
*Wednesday, March 12, 2014 at 6:13am by MS*

**Calculus**

Following 2 questions are from a book at a point where LHopitals Rule, Squeeze Theorem etc. have not been discussed and limits (A) and (B) as given below are to be evaluated by simple methods like algebraic simplification etc. 1. Int. of (xlogx)dx from 0 to 1. Indefinite Int...
*Thursday, March 13, 2014 at 2:45am by MS*

**calculus**

Given the function: y = 2 - x - x^3 use limits to find the slope (and then the equation) of the tangent line at x =2.
*Thursday, September 25, 2008 at 10:46pm by Alex*

**calculus**

Given the function y = 2 - x - x^3 Use limits to find the slope (and then the equation) of the tangent line at x = 2
*Monday, September 29, 2008 at 11:11pm by Erika*

**calculus**

Given the function y = 2 - x - x^3 Use limits to find the slope (and then the equation) of the tangent line at x = 2
*Tuesday, September 30, 2008 at 12:41am by Erika*

**calculus-limits**

For f(x) = e^x sinx , what can be said about lim x -> negative infinty? Explain.
*Wednesday, June 16, 2010 at 8:46pm by John*

**Calculus (Limits)**

No, its not a typo, it is supposed to be x^2 - 2a + a^2. Thank you for the reassurance, I figured that this was the most logical choice!
*Saturday, October 22, 2011 at 7:30pm by Mishaka*

**calculus**

int (4t^2-sinT) dt 4/3 t^3 +cosT over limits x to 1 4/3 * 1+cos1-4/3 x^3-cosx
*Sunday, February 5, 2012 at 3:07pm by bobpursley*

**Calculus 2**

i know that the ratio test is used to figure it out. you first find the limits right?
*Monday, November 5, 2012 at 12:50am by James*

**Calculus, Limits**

Find the limit. lim t → ∞ (sqrt t + t^2)/(6t − t^2)
*Monday, January 20, 2014 at 7:04pm by DeeDee*

**calculus - limits**

mass is unbounded, it increases. Since this cannot happen, velocity cannot equal the speed of light.
*Thursday, October 1, 2009 at 2:50pm by bobpursley*

**Calculus**

Use the definition of continuity and properties of limits to show that the function is continues at given a. f(x)=x^2+sqrt(7-x) a=4
*Monday, September 12, 2011 at 9:55pm by Kevin*

**Maths Calculus Derivatives & Limits **

Drag out L'Hospital's Rule 1) 1/3 (8+h)^(-2/3) / 1 = 1/3 * 1/4 = 1/12 2) -2sinx/3 = -√3/3
*Tuesday, October 25, 2011 at 9:19am by Steve*

**math/calculus**

Yes, rules of continuity. Has to have same limits from left and right, and has to be differentiable at that point.
*Thursday, July 5, 2012 at 2:06pm by bobpursley*

**Physics**

No on the first. If you are in calculus, work= INT fdx=INT kxdx= 1/2 k x^2 eval at the limits .2 to .25 Same thing on the second. If you are not in calculus, the energy stored in a spring is 1/2 kx^2. You have to evaluate the stored energy at each point, and take the difference.
*Wednesday, October 17, 2007 at 5:07pm by bobpursley*

**Statistics**

Multiple Choice Which of the following statements is true about the 95% confidence interval of the average of a sample? A) 95 of 100 avgs of samples will be within the limits of the confidence interval. B) There is a 95% chance the avg of the population to be within the limits...
*Friday, July 26, 2013 at 6:00am by Andrew*

**Calculus**

We did this for x in [1,3] Just change the limits of integration and follow the same steps. How is this one more difficult? Where do you get stuck?
*Monday, December 16, 2013 at 6:13pm by Steve*

**CALCULUS**

I will answer #1. repost for #2 and #3 if necessary. A vertical asymptote is typically caused by the denominator becoming zero. The function is undefined at this point. The limits of the function from left and right may or may not be the same, and are usually ±&infin. A...
*Thursday, September 30, 2010 at 11:15pm by MathMate*

**Calculus**

As I noted in my original answer, there is an inconsistency in the specified limits of integration or "boundaries" of your enclosed area. The spiral curve r = 2 theta starts at theta = 0 and ends at theta = 1.5 pi. The straight line theta = pi is the -x axis. It is not clear ...
*Saturday, February 6, 2010 at 4:17am by drwls*

**Calculus**

Your question does not make sense because you are using "?" for domain limits and in place of what should probably be a < sign in the last line.
*Saturday, September 15, 2007 at 5:56pm by drwls*

**calculus**

position is the integral p(t)=Defintegral (v(t) dt) if the limits are 0 to t then p(t)=-cost-sint -(-cos0-sin0)) check all that, I did it in my head.
*Thursday, December 2, 2010 at 12:44pm by bobpursley*

**calculus **

How do you integrate a ratio? (Why is a : there?) Why is there no dx in your integral? What are the limits of integration? Why is there a comma at the end? Please use standard notation
*Friday, February 4, 2011 at 11:04pm by drwls*

**calculus**

Evaluate the limits without using a calculator. Justify all steps in the solutions. lim x-->0 x^7cos(3/x)
*Saturday, February 12, 2011 at 10:47pm by Janet*

**calculus, limits, l'hopital**

Find the limit as x->0 of (2-2cos(x))/(sin(5x)) Mathematically I got 2/5, but on the graph it appears to be 0.
*Sunday, February 13, 2011 at 3:08pm by Kate*

**calculus**

Evaluate the limits without using a calculator. Justify all steps in the solutions. lim x-->0 x^7cos(3/x)
*Sunday, February 13, 2011 at 9:48pm by Janet*

**calculus**

This makes no sense. too many "=" signs. Post again, be a little clearer on the function, the limits on x. Anyway, integral sqrt(x) = 2/3 x^3/2
*Friday, December 2, 2011 at 2:47am by Steve*

**college calculus**

I don't know how to solve this indefinite integral with both limits as variables: ^x^3 (z^4+1)dz ⌄ln(x) If you could explain I'd appreciate it.
*Saturday, November 30, 2013 at 10:36pm by tatiana*

**Statistical Quality Control /UCL's & LCL's**

Lower limits = mean - 3(sd/√n) Upper limits = mean + 3(sd/√n) mean = np sd = √npq n = 500 p = .05 q = 1 - p Calculate the lower and upper limits using the mean, standard devation, and sample size. I hope this helps.
*Saturday, February 4, 2012 at 7:03am by MathGuru*

**physics**

Work is conservative, so do the x first, then the y. work=INT f.dx + int f.dy = INTkq1q2/x^2 dx+ int kq1q2/y^2 dy = kq1q1 (1/x)over limits + kq1q2 (1/y)over limits limits x .140 to .230 ; y 0 to .290
*Wednesday, February 22, 2012 at 8:43am by bobpursley*

**Math >> limits**

The limit is of the form: Lim x--> 0 f(x)/g(x) where f(0) = g(0) = 0. So we can't take the limits for f and g separately and divide them. Rewrite the limit as: Lim x--> 0 [f(x) - 0]/[g(x) - 0] = Lim x--> 0 [f(x)-f(0)]/[g(x)-g(0)] Lim x-->0{[f(x)-f(0)]/x}/{[g(x)-g(0...
*Wednesday, September 5, 2007 at 6:57am by Count Iblis*

**calculus**

Tell your teacher to just go ahead and teach you how to do "limits" (rolls eyes and shakes head in utter frustration !!!)
*Thursday, October 22, 2009 at 10:36pm by Reiny*

**Calculus**

Evaluate the triple integral _E (xy)dV where E is a solid tetrahedron with vertices (0,0,0), (4,0,0), (0,1,0), (0,0,4) I just can't seem to find the limits, of x,y and z
*Monday, April 26, 2010 at 6:29am by Salman*

**Maths Calculus Derivatives & Limits **

Oops. Using definition of derivative. Check back later. Lots of messy algebra.
*Tuesday, October 25, 2011 at 9:19am by Steve*

**Calculus. Limits. Check my answers, please! :)**

#4 surely you know that tan π/3 = √3 #5 ok #6[[x]] represents the greatest integer function How could you choose 4.5? #7 ok
*Sunday, October 6, 2013 at 11:56am by Steve*

**Calculus**

Find f'(x) and see if there is a zero (root) on the interval. If not, the extrema are the two limits of the interval. Check the sign of f'(x) on the interval. If there is no zero on the interval, the sign should not change (+ OR -). If f'(x) is + on the interval, it is ...
*Thursday, November 4, 2010 at 7:00am by MathMate*

**Calculus**

You need to review your calculus. pdw ydy is the operand of the integral. INT pdw ydy= pdw int ydy= pdwy^2/2 evaluated over the limits.
*Saturday, October 24, 2009 at 11:12pm by bobpursley*

**calculus**

The bounded region is x =0 to x = 1, so those are your limits of integration. The integral is of pi*(x^2 - sqrt x)^2 dx. Visualize it as a stack of washers with holes in the middle.
*Saturday, April 23, 2011 at 4:41pm by drwls*

**Calculus**

since x^2-1=0 at x = 1, f is not continuous. For any other values, f(x) = 1/(x-1) when x > -1 f(x) = -1/(x-1) for x < -1 evaluate the left and right limits near 1 and -1 to determine the nature of the discontinuities.
*Monday, August 5, 2013 at 2:42pm by Steve*

**double integrals**

Combine the following two integrals into one by sketching the region, then switching the order of integration. (sketch the region) im gonna use the S for integral sign..lol SS6ycos(x^3-3x)dxdy+SS6ycos(x^3-3x) And the first integration limits for x are between -1 and y, for y ...
*Wednesday, March 21, 2012 at 10:50pm by Mary*

**Calculus I - Limits**

How do I find lim x-> infinity √(x^2 + x) - √(x^2 - x)
*Sunday, June 13, 2010 at 8:47pm by John*

**calculus II SURFACE AREA Integration**

Except for the limits of integration :-)
*Monday, October 31, 2011 at 4:28pm by Steve*

**Math Limits **

(x^n-1)/((x-1) )=(x-α^1 )(1-α^2 )ׅ..(x-α^((n-1)) ) How do we prove that n = the multiplication of the second term using limits and l'hopital's rule.
*Thursday, February 28, 2013 at 11:31pm by Blah*

**Calculus**

Using the first of these limits, find f'(3) if f(x)=4x^2+4x-2
*Thursday, September 3, 2009 at 9:58pm by Z32*

**Calculus**

for k=2 lim x->0 sin(sin(x))/x^2= error so undefined So do I have to do sided limits? how?
*Saturday, September 24, 2011 at 2:45pm by Sybil*

**Calculus**

I'm not sure how to calculate limits from graphs. I've tried many times but I can't figure it out. Are there any sites or tips you can give me? Thank you very much, I really appreciate it.
*Sunday, September 16, 2007 at 5:34pm by Jacob*

**calculus**

From x=-4 to x=4, the y=[(25-(x^2))^(1/2)] curve is above y > 3. From x = -5 to -4 and 4 to 5, y <3 It is not clear what the x limits of integration are, nor how the two different regions, outside and inside y=3, are to be treated.
*Friday, May 7, 2010 at 8:21pm by drwls*

**calculus **

First graph the two functions to make sure that the required region is positive within the limits of integration. Let y1(x)=x y2(x)=8-x y1(2)=2, y1(3)=3 y2(2)=6, y2(3)=5. Thus the region is always positive (the two function do not cross within the interval [2,3]). The ...
*Tuesday, January 26, 2010 at 7:09pm by MathMate*

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