Wednesday

April 16, 2014

April 16, 2014

Number of results: 36,553

**English grammar**

Michael: Email me please Bobpursley@gmail.com
*Wednesday, November 21, 2007 at 6:41pm by bobpursley*

**bobpursley**

1/2=14x to solve for x, divide both sides by 14 1/28=x
*Monday, January 12, 2009 at 5:08pm by bobpursley*

**algebra**

Michael: Please email me Bobpursley@gmail.com
*Wednesday, November 21, 2007 at 9:05pm by bobpursley*

**bobpursley**

dividing by 6 is the same thing as multiplying both sides by 1/6
*Monday, January 12, 2009 at 5:08pm by bobpursley*

**bobpursley: math cont**

y=mx+b y=x+b -3=-3+b b=0 so the equation is y=x I have no idea what you did.
*Tuesday, February 23, 2010 at 4:26pm by bobpursley*

**Chemistry - bobpursley pls help **

didn't I just demonstrate it is conc HCl?
*Tuesday, September 21, 2010 at 4:47pm by bobpursley*

**to: bobpursley**

all were correct. see the post about squaring 3
*Sunday, September 8, 2013 at 8:22pm by bobpursley*

**TO BOBPURSLEY**

how come when I put into my calculator (sqrt5 - sqrt 3)^2 i get .2540333076 not 5-3 or simply 2...?????????
*Sunday, May 31, 2009 at 7:31pm by TO BOBPURSLEY*

**7th grade science bobpursley**

Go to the head of the class. All correct.
*Wednesday, January 16, 2013 at 9:12pm by bobpursley*

**Jim**

If you are interested in being a regular volunteer, please email me. Bobpursley@gmail.com
*Sunday, November 1, 2009 at 11:20am by bobpursley*

**to bobpursley**

TTT HHH THH HtH HHt tth tht htt I count eight.
*Tuesday, December 1, 2009 at 4:23pm by bobpursley*

**Chem- bobpursley**

1.67E-27kg*(.0015/9.11E-31) =2.75 so three protons.
*Tuesday, September 21, 2010 at 8:39pm by bobpursley*

**Math BOBPURSLEY HELP HELP HELP HELP**

Why did you make it so complicated? 1/2 m v^2=GMe m/re v^2= 2GMe/re take the square root of each side.
*Monday, May 2, 2011 at 11:35am by bobpursley*

**bobpursley**

Post the web address with spaces, such as this.. w w w . H o t s a u s a g e . D e f ?
*Wednesday, October 15, 2008 at 9:08pm by bobpursley*

**bobpursley**

good work, watch sig digits.
*Wednesday, October 15, 2008 at 9:55pm by bobpursley*

**TO BOBPURSLEY**

makes sense to me but is my answer also correct?
*Wednesday, May 27, 2009 at 2:59pm by TO BOBPURSLEY*

**Grammar and Compositon Bobpursley**

ok, give me a few minutes.
*Wednesday, November 4, 2009 at 11:25am by bobpursley*

**math confused for bobpursley**

BobPursley is taking a couple of days off from the Jiskha Board.
*Thursday, May 22, 2008 at 8:27pm by Ms. Sue*

**TO BOBPURSLEY**

everything made sense I just dont see why .5 m must be half a wave length
*Sunday, November 15, 2009 at 3:19pm by TO BOBPURSLEY*

**Language Arts**

Jim, email me if you are interested in being a regular volunteer here. BobPursley@gmail.com
*Saturday, October 31, 2009 at 2:05pm by bobpursley*

**ACCOUNTING/Bobpursley**

I have no idea what the items were, that was what I was pointing out to you. THe assignement said cover ....., and I can't help if those are not listed.
*Friday, April 9, 2010 at 6:00pm by bobpursley*

**math 117 for bobpursley**

ally, settle down. The answer is obviously 30. Surely you can verify that with your calculator.
*Wednesday, February 23, 2011 at 7:56pm by bobpursley*

**to bobpursley**

see my post. anytime you have a nuber being taken to a power, the law of exponsents holds.
*Sunday, September 8, 2013 at 8:30pm by bobpursley*

**bobpursley**

I would rather eat Tacos.
*Saturday, March 20, 2010 at 7:44pm by bobpursley*

**Technology: ms.sue, bobpursley**

excellent.
*Thursday, April 8, 2010 at 5:58pm by bobpursley*

**To bobpursley**

I had a simple answer like that, but Ms. Sue wanted me to be more specific, so thats what I wrote. Thank you so much bobpursley:-)
*Sunday, October 25, 2009 at 6:18pm by Sara*

**Physics-bobpursley please check**

You second solution makes no sense. Why would you set the KE of an object equal to its PE?
*Thursday, November 4, 2010 at 9:18pm by bobpursley*

**chem -repost for bobpursley**

on a per mole basis, you release 4 moles of new gas. At STP, it occupies 2*22.4 liters
*Sunday, April 17, 2011 at 8:53pm by bobpursley*

**bobpursley**

I dont see any unanswered. I am not a biologist....electrical engineering, physics, geek stuff mainly. I specialize in irritating Georgia Peaches.
*Tuesday, March 23, 2010 at 12:41pm by bobpursley*

**Math BOBPURSLEY HELP HELP HELP HELP**

Then set the initial KEnergy equal to the potential energy at the surface of EArth. 1/2 mv^2= GMe*m/re solve for escape velocity, v
*Monday, May 2, 2011 at 11:35am by bobpursley*

**Algebra 2 ..........BOBPURSLEY**

What graph? There is no y in the equation (x-2)^3 -2=0
*Saturday, January 26, 2013 at 7:58pm by bobpursley*

**Marth**

Please email me if you are interested in being a "regular" volunteer tutor. Bobpursley@gmail.com Your responses are very excellent, and helpful. Thanks for all you do.
*Sunday, July 5, 2009 at 4:36pm by bobpursley*

**BobPursley/journaling**

It depends on the age of the child, but nearly always includes thoughts, daily activites, or even short essays. My youngest (7) often wrote letters in the journal.
*Wednesday, August 13, 2008 at 8:15pm by bobpursley*

**chemistry-PC**

PC: email me if you are interested in becoming a regular volunteer teacher. Bobpursley@gmail.com
*Friday, May 29, 2009 at 9:02am by bobpursley*

**Science-bobpursley/Ms.Sue**

the first is correct. On the second, I have no idea what the diagram is, however, I suspect your "ancestor" is correct.
*Thursday, December 12, 2013 at 11:02am by bobpursley*

**Bobpursley plz help**

Please dont put my name in the subject box. Others here can help better than I, and I am only online a few minutes. I have another life also. Yes, on first. Yes on second.
*Monday, August 24, 2009 at 8:27pm by bobpursley*

**bobpursley**

The question is odd. You are correct. I am not certain why the author of the question worded it all this way.
*Wednesday, October 15, 2008 at 10:16pm by bobpursley*

**physics- response to bobpursley**

II is wrong, III is wrong. If I were you I would discuss it with your instructor.
*Wednesday, June 24, 2009 at 8:48pm by bobpursley*

**To bobpursley**

thanks so much bobpursley:-)
*Friday, October 9, 2009 at 10:12pm by sara*

**Chemistry--bobpursley**

correct.
*Tuesday, October 26, 2010 at 6:29pm by bobpursley*

**damon**

Professor, please email me at BobPursley@gmail.com I need to have your email address in order to enable you to post hot links. Thanks.
*Sunday, April 6, 2008 at 3:02pm by bobpursley*

**bobpursley!**

If 1/5 m= 22, then m = 22 (5). If 2/3c=5.9, then c = 5.9 (3/2) Even though I am not bobpursley, I hope this helps. thanks for asking.
*Monday, January 12, 2009 at 5:31pm by PsyDAG*

**Matt**

Matt, I need your new email address. BobPursley@gmail.com
*Friday, November 13, 2009 at 10:09pm by bobpursley*

**Univesity of Phoenix**

I believe that there are two things that motivate humans: the need to grow, and the need to avoid pain. That theory is mine, and it has served me well in application. Bobpursley
*Sunday, October 24, 2010 at 6:06pm by bobpursley*

**random**

you're pretty good at history and literature as well... i'm not sure about Reiny, and bobpursley, and damon..and GuruBlue i've noticed bobpursley answer many different type of questions; science, lit, history, ..
*Sunday, February 22, 2009 at 10:16pm by Bella*

**Science-bobpursley**

Thanks for helping me with al those parts bobpursley. If you have time, can you also check my questions please. Thank you very, very much in return. My post is on the second page.
*Tuesday, April 6, 2010 at 9:49pm by Sara*

**bobpursley**

work is ok, for the net forces add the two forces, the 365 and the 374N forces. Watch significant digits.
*Wednesday, October 15, 2008 at 9:29pm by bobpursley*

**physics repost bobpursley**

This is a simple math problem . c=300/300 * 4.18* 10/50 = .8 j/gC about. Now if you do specific heat in calories, you get .2. Numbers without units are meaningless.
*Monday, June 22, 2009 at 10:48pm by bobpursley*

**7th grade science bobpursley**

please dont put a particular teacher's name in the subject box. What happens often, if that teacher is not online, other teachers don't look at it, and you MISS OUT on help. Thanks.
*Wednesday, January 16, 2013 at 9:12pm by bobpursley*

**Physics-bobpursley can u check this again please**

dang. I forgot about PEnergy gain. F(net)*d=1/2 kx^2+ 1/2 mv^2+mgx sorry, It has been a long day for me (since three am). check my thinking.
*Thursday, October 28, 2010 at 10:54pm by bobpursley*

**Chemistry**

I think bobpursley meant that: pOH = -log[OH-] and pH = 14 - pOH Use these relationships to get the pH after finding the molarity of KOH = [OH-] as bobpursley suggested.
*Wednesday, August 5, 2009 at 1:35am by GK*

**s.s**

i dont have a clue about what you are on about-i bet bobpursley agree's with that too. Well I totally agree with bobpursley. Thanks. P.S; what does S.S mean for the subject??!!
*Monday, October 29, 2007 at 8:08am by Danielle*

**Go with bobpursley - math**

Never mind my solution, go with bobpursley Found my "silly error" , just noticed I had my fractions upside - down. e.g. speed for shorter trip = x/4 , etc. Can I blame it on the heat affecting my brain ?
*Friday, July 22, 2011 at 9:38am by Reiny*

**Please bobpursley help.algebra 2**

The first is a function of x as there is one y value for all x. At any x, y=3. The second is not a function because there is no value of y defined for any x. At x=3, y can be any value, and at other x values, y is undefined.
*Monday, August 27, 2007 at 8:46pm by bobpursley*

**sra McGuin**

Scan and attach to an email to me Bobpursley@gmail.com and I will get it to Sra McGuin
*Thursday, January 1, 2009 at 9:31pm by bobpursley*

**ATTN bobpursley**

Thanks.
*Saturday, October 4, 2008 at 2:04pm by bobpursley*

**Bobpursley+Chemistry**

done.
*Wednesday, January 14, 2009 at 6:26pm by bobpursley*

**go with bobpursley - algebra**

ARRGGGHHHH!!!! looks like I messed up in my 45-49 could be done with 1 quarter, 2 dimes, and 4 pennies. Nowhere else do we actually need 2 nickels so as bobpursley said 3 quarters, 2 dimes 1 nickel 4 pennies for a total of 10 coins
*Monday, May 7, 2012 at 6:40pm by Reiny*

**bobpursley please help**

Hmmmm, It appears to me you did too much rounding. I do not understand all the conversions . wf^2=Wi^2+2ad 0=16.1^2+2(-1.93)d d= 16.1^1/3.86 radians distance= angdisplacement*r = 16.1^2/3.86 * .0330/2=1.11 m check that.
*Sunday, November 28, 2010 at 4:55pm by bobpursley*

**Physics(thank you for the help)**

Physics(thank you for the help) - bobpursley, Sunday, May 27, 2012 at 4:53pm I am uncertain what part b is. I am uncertain what F is in the ratio F/Fa If F is the total force, then F/Fa=k by definition. So frankly, I have no idea what the question is asking.
*Sunday, May 27, 2012 at 4:45pm by bobpursley*

**Chemistry Bobpursley**

on b, think what a buffer does. on c, if a very large stsron acid, it is most likely to make the solution more acid, decreasing, I agree with that. THe issue is what is a very large amount.
*Wednesday, November 7, 2012 at 10:08pm by bobpursley*

**physics-bobpursley/drwls please check**

bobpursley/ drwls please help me with my post on Sunday, April 15 at 10:16pm and 10:19pm. Thanks!
*Monday, April 16, 2007 at 7:24am by Mary*

**TO BOBPURSLEY**

acceleartiononmoon= GMassmoon/radius^2 =G 7.35E22/(1.74E6)^2= G 2.43E10= = 6.67E-11*2.43E10= 1.62 m/s^2 or as a gravitational field constant= 1.62 N/kg I have no idea why you used the mass of Earth. were did you get a = r^-2 Gm from i thought that the equation was net force = ...
*Saturday, September 12, 2009 at 5:03pm by TO BOBPURSLEY*

**TO BOBPURSLEY**

you dont get it. Divide the force of gravity by the mass of the object which is being accelerated. F/massyou = your acceleration of course, forces come in couplets, so F/massmoon= moons acceleration toward you. where F is the force of gravity, it operates on you and the moon, ...
*Saturday, September 12, 2009 at 5:03pm by bobpursley*

**BobPursley, HELP! Please!!!!**

I am soooo confused!!
*Wednesday, March 25, 2009 at 7:53pm by BobPursley, HELP! Please!!!!*

**chem -repost for bobpursley**

2. Yes, it is acidic because it is a salt made from a salt of a strong acid and a weak base. 3. Catalysts speed a reaction by providing an alternate reaction pathway, since they speed it, the rate constant is greatly changed. Good thinking.
*Saturday, April 9, 2011 at 2:34pm by bobpursley*

**Thanking MS Sue**

Thank you Ms Sue for all you do here. We appreciate it. You have helped students all your life, and I am certain many of them haven't forgotten you. Thank you from all of us. BobPursley
*Sunday, September 11, 2011 at 10:02pm by bobpursley*

**AE**

Be sure you're paying attention to what Bobpursley has written. The NCLB regulations are not the only laws that the feds have passed that affect education, even though education is not in the Constitution or Amendments. Bobpursley has listed other federal laws that affect ...
*Tuesday, August 5, 2008 at 12:32am by Writeacher*

**Grammar and Compositon Bobpursley**

I think I would work on his personal characteristics, rich just is just wealth. Is he kind, charitable, sociable, community oriented? What is his legacy? Rich is awfully shallow for a legacy, as is poor. Humans are worth more than their bank account.
*Wednesday, November 4, 2009 at 11:25am by bobpursley*

**math**

You didn't read bobpursley's original answer very well. math - bobpursley, Tuesday, January 26, 2010 at 8:35pm I wonder how tall and wide the door is. If the door is wide and tall enough, the tallest cabinet is 8 feet.
*Tuesday, January 26, 2010 at 9:12pm by Ms. Sue*

**Algebra - for bobpursley**

Now any UTex student worth his salt knows -2(4-3k)=-8+6k Must have been Aggie thinking here. with that change, it becomes 14-8k-16 = -8+6k subtracting 6k from each side -2-14k=-8 adding two to each side -14k=-6 k=6/14 or 3/7
*Thursday, September 26, 2013 at 6:16pm by bobpursley*

**math**

math - bobpursley, Tuesday, May 14, 2013 at 7:41pm 125=M*e^(.045*40) M=125K/6.04== 20.66236 K 125=M(1+.05)^40 log 125=logM + 40log1.05 M= = 17.75571 thousand
*Tuesday, May 14, 2013 at 7:22pm by bobpursley*

**Math CONTINUATION OF QUESTION FROM bobpursley**

Thank you for answering the question before bobpursley, I understand how you did the deriv of inside, outside, but how do I now do the second derivative since you have the extra -18x^2 in the numerator?? Thank you very much! (I suppose I have to brush up on my derivatives) ...
*Thursday, March 10, 2011 at 9:05pm by KIKSY*

**Physics**

ysics - bobpursley, Tuesday, April 2, 2013 at 3:42pm deltaLength=1000ft*coeffexpansion*33 look up the coefficent of linear expansion for STEEL (railroad tracks are steel, not iron), figure delta length, add that to the original 1000ft It scares me to think of a train running ...
*Tuesday, April 2, 2013 at 3:35pm by bobpursley*

** Anonymous and bobpursley**

can you please Anonymous and bobpursley explain this to me. Please and thank you
*Thursday, November 4, 2010 at 9:26pm by anna*

**bobpursley**

The steps? YOu have to have a physician with admitting priviledges, admit you. It can occur in his office, at your home, in the emergency room. If the physician admits you, you are admitted. This can occur in a wide variety of circumstances. The process of the admitting ...
*Thursday, April 1, 2010 at 9:29am by bobpursley*

**To Bobpursley**

Ok I finally understand your work and it makes sense to me but I guess it's wrong and I don't see were I followed your work and got the same answer as you positive one... the only thing is I put the problem into my calculator and get negative one and the back of the book gives...
*Sunday, November 15, 2009 at 8:31pm by To Bobpursley (Wrong answer???)*

**Math 9th**

I got it. bobpursley was REALLY close for b. the only difference is that there's no decimal. also, c=225. just use the substitution method and you should be fine. If you're tired Kat, especially since you've been staring at it a while, i suggest forgetting about it now and ...
*Friday, January 23, 2009 at 9:13pm by nattily*

**chem??????????????????**

YEs, it is the correct balanced equation bobpursley A 2.80 mol/L solution of iron (II) dichromate is combined with 5.00L of a 2.25 mol/L acidic solution of tin (II) bromide. Calculate the volume of iron (II) dichromate required. FeCr2O7 + SnBr2 --> SnCr2O7 + FeBr2 Is this ...
*Wednesday, May 16, 2007 at 6:32pm by bobpursley*

**algebra 2**

How is this problem done? IF f(x)=2x^2-8x-3 FIND f(-2) algebra 2 - bobpursley, Saturday, January 16, 2010 at 1:42pm Put in for x the value -2, and compute f(-2) algebra 2 - hellogoodbie, Saturday, January 16, 2010 at 1:47pm so is the answer f=21/2? if that is right, thank you ...
*Saturday, January 16, 2010 at 2:04pm by hellogoodbie*

**algebra 2**

How is this problem done? IF f(x)=2x^2-8x-3 FIND f(-2) algebra 2 - bobpursley, Saturday, January 16, 2010 at 1:42pm Put in for x the value -2, and compute f(-2) algebra 2 - hellogoodbie, Saturday, January 16, 2010 at 1:47pm so is the answer f=21/2? if that is right, thank you ...
*Saturday, January 16, 2010 at 2:59pm by hellogoodbie*

**TO BOBPURSLEY**

Goodness. forcegravity= GMassmoon*massyou/r^2 forcegravity/massyou = GMassmoon/r^2 "g"= G*Massmoon/r^2
*Saturday, September 12, 2009 at 5:03pm by bobpursley*

**Chemistry!! - bobpursley please**

Calculate the maximum wavelength of light capable of removing an electron for a hydrogen atom from the energy state characterized by the following when n=4 =__________nm Responses Chemistry!! - bobpursley, Wednesday, October 22, 2008 at 4:05am So the two energy states are n=4 ...
*Wednesday, October 22, 2008 at 6:40pm by Giznelbell*

**Grammar and Composition Bobpursley**

On the last, your thesis did not say anything about businessman,you said he was rich. So we disagree on that. On the first, you are right, I numbered the paragraphs on my printout,and the spaces separating the paragraphs did not print. I see now. The third point, in paragraph ...
*Wednesday, November 4, 2009 at 5:21pm by bobpursley*

**Physics**

A vertical spring with a spring constant of 450 N/m is mounted on the floor. From directly above the spring, which is unstrained, a 0.30 kg block is dropped from rest. It collides with and sticks to the spring, which is compressed by 3.0 cm in bringing the block to a momentary...
*Friday, April 6, 2007 at 8:42pm by Mary*

**Algebra 1 Please bobpursley**

Hi Mary, I understand from your post that you are the mother of the student. I really can't tell at what grade level this is supposed to be, but I agree with Bobpursley's earlier comment when you first posted this question. I also cannot make any sense of this problem. I have ...
*Saturday, September 12, 2009 at 2:53pm by Reiny*

**bobpursly,.math**

Ok, assume it equals zero. 2x + 3y -6=0 subtract 3y from each side. add six to each side. divide both sides by two. its how its in the book i'm suppost to solve for x. but how? How do I solve for the following: Directions solve each literal equation for the individual variable...
*Tuesday, December 19, 2006 at 9:29am by bobpursley*

**algebra 2**

Posted by hellogoodbie on Saturday, January 16, 2010 at 3:24pm. Posted by hellogoodbie on Saturday, January 16, 2010 at 2:59pm. How is this problem done? IF f(x)=2x^2-8x-3 FIND f(-2) algebra 2 - bobpursley, Saturday, January 16, 2010 at 1:42pm Put in for x the value -2, and ...
*Saturday, January 16, 2010 at 4:03pm by hellogoodbie*

**AlgebrAlgebra-Mathmate or BobPursley or Reiny**

I read it as the logarithm of x. If you read it that way also, it is a logarithmic equation. Very few mathematicians get overly concerned with notation, however, I have known many high school teachers make a big deal of Log(x) and other notation. I still remember when one ...
*Tuesday, December 14, 2010 at 3:15pm by bobpursley*

**Math CONTINUATION OF QUESTION FROM bobpursley**

I don't think bobpursley is on line, so permit me to continue ... from Bob, y' = -18x^2(1+2x^3)-2 so using the product rule and chain rule combination y'' = -18x^2)(-2)(1+2x^3)^-3(6x^2) + (1+2x^2)^-2(-36x) = 216x^4(1+2x^3)^-3 - 36x(1+2x^3)^-2 = 36x(1+2x^3)^-3 [ 6x^3 - (1+2x^3...
*Thursday, March 10, 2011 at 9:05pm by Reiny*

**Algebra 1 Please bobpursley**

Mary, and Mary's mom: One of our other math teachers wrote this to me in an email: "I cannot make much sense out of the problem, even after reading it a few times. It sounds to me students are supposed to make the "identical" creatures with scissors and paper and use the ...
*Saturday, September 12, 2009 at 2:53pm by bobpursley*

**physics repost bobpursley**

The energy given off by 300 grams of an alloy as it cools through 50°C raises the temperature of 300 grams of water from 30°C to 40°C. The specific heat of the alloy (in cal/g C ) is: i know Q=CpM(delta T) but what is what? Responses * physics - bobpursley, Monday, June 22, ...
*Monday, June 22, 2009 at 10:48pm by jane*

**Reiny or Damon or Bobpursley **

Express the series 11 + 18 + 27 +...+ 171 using sigma notation. Usually you would take 27-18 and thats the step between numbers, right? (I think its the k-value?) But 27-18=9 and 18-11=7. Are we stepping by k+2 here? Like k, k+2 k+4, k+6...? Please help me. I'm not confident ...
*Friday, April 27, 2012 at 6:09pm by Tabby*

**acceleration estimate(bobpursley)**

Well, bobpursley explained this to me. I didn't understand this well. Since there was an error in the data, I am posting it again t(sec) v(ft/sec) 1 12.2 1.5 13 2 13.4 2.5 13.7 velocity of an object moving along a line at various times. How do I estimate the object's ...
*Monday, December 11, 2006 at 10:31pm by Jen*

**Calculus, bobpursley! **

http://www.jiskha.com/display.cgi?id=1285109460
*Tuesday, September 21, 2010 at 8:01pm by bobpursley*

**"STEVE", and anonomous responder**

your response shows care and insight to this question: http://www.jiskha.com/display.cgi?id=1324045462 Steve, several of your replies have been very good. If you are interested in joining our Volunteer Jiska staff, please email me at Bobpursley@gmail.com Bob
*Friday, December 16, 2011 at 1:27pm by bobpursley*

**Physics-bobpursley please check**

First, you have so many math errors it hurts. If 1/2 mv^2=.9J then v^2=2*.9/.035 v=7.17m/s I have no idea where you got 2.215m/s You have told me several things about the initial PE a) it was a height of .5m (PE= .035*9.8*.5 = .17J ( you indicated in your solution mass was ....
*Thursday, November 4, 2010 at 9:18pm by bobpursley*

**TO BOBPURSLEY**

as I did.
*Sunday, September 13, 2009 at 9:38pm by bobpursley*

**BobPursley**

done.
*Friday, July 23, 2010 at 8:54pm by bobpursley*

**For bobpursley**

ok, thanks.
*Saturday, February 12, 2011 at 8:34pm by bobpursley*

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