Friday

April 18, 2014

April 18, 2014

Number of results: 1,934

**algebra**

Sorry, in general, a+(bc+2) ≠ 2a(b+c) However, a+(bc+2) =(a+bc)+2 =(a+2)+bc
*Monday, May 9, 2011 at 9:38am by MathMate*

**MATH**

Find AC? I assume you have a typo above? BC = BA + AC 5x - 3 = 2x + 5 + AC 3x - 8 = AC since A is the MP of BC and BA = 2x + 5 BC = 2(BA) BC = 2(2x + 5) BC = 4x + 10 BC = BC 5x - 3 = 4x + 10 x = 13
*Sunday, January 16, 2011 at 7:05pm by helper*

**Physics**

suppose that the separation between speakers A and B is 5.80 m and the speakers are vibrating in phase. They are playing identical 135 Hz tones, and the speed of sound is 343 m/s. What is the largest possible distance between speaker B and the observer at C, such that he ...
*Tuesday, May 1, 2007 at 9:05pm by Mary*

**MATH**

A is the midpoint of BC. BA=2x+5 and BC=5x-3. solve for x and find the length of BC
*Sunday, January 16, 2011 at 7:05pm by BOB*

**Algebra**

-b+bc-c^3-(c^3+bc-c^3+b)= =-b+bc-c^3-bc-b= =-2b-c^3
*Friday, March 16, 2012 at 12:08pm by Susan*

**addition of monomials**

-27 bc 85 bc -30 bc
*Monday, November 20, 2006 at 8:09pm by rose an*

**Geometry-8th gr**

or, using the angle bisector theorem, AD/DC = AB/BC so, as Reiny calculated, AB/BC = 5/7 AD+BC = 84 5x+12x=84 x=7 so, AB = 35 BC = 49
*Friday, February 1, 2013 at 12:12pm by Steve*

**chemistry**

from UCI!!!!! 1 is equal bc of equilibrium 2 is endothermic bc of absorbing heat 3 is absorb....bc it is endothermic yay all finish!
*Monday, January 25, 2010 at 11:01pm by Alex Le*

**solid mensuration**

The circle radius is 5 cm. That comes from the area. The triangle ACB is a right triangle with AB as a diameter. The length of AB is 10 cm, since it is a diameter (AC)^2 + (BC)^2 = (AB)^2 = 100 Area = (1/2)(AB)*(BC) = 11 (AC)*(BC) = 22 (BC)=22/(AC) (AC)^2 + 484/(AC)^2 = 100 ...
*Saturday, December 1, 2012 at 7:13am by drwls*

**math**

Assume the 2x2 matrix to be A= \ a b c d Do the matrix multiplication AA and equate each element to A, a=a²+bc b=b(a+d) c=c(a+d) d=bc+d² From which we conclude a+d=1 or a=1-d and bc = a-a² = d-d² Take a=4, then d=-3 bc=4-4²=-12, If b=2, c=-6 So 4 2 -6...
*Thursday, November 25, 2010 at 3:56pm by MathMate*

**algebra**

(bc^2)-^2 Do you mean, (bc^2)^-2 (bc^2)^-2 = b^-2 c^-4 = 1/(c^4 b^2)
*Saturday, February 5, 2011 at 5:46pm by helper*

**Algebra - REINY**

Hi - Do you think this is correct? BC = AD Area of Rectangle = (FB+AF).BC Area of Rectangle = 72 units squared Area = 1/2 bh Area 1 = 1/2 FB.BC Area 2 = 1/2 AF.AD 1/2 = AF.BC A1 + A2 = 36 units squared 1/2 FB.BC + 1/2 AF.BC 1/2 [FB.BC + AF.BC] 1/2 [BC (FB + AF) 1/2.72 units ...
*Thursday, March 7, 2013 at 7:19am by Anthony*

**11th grade**

Angle A=45, AB=10, and BC=8. This is an SSA configuration which could result in 0, 1 or two distinct triangles, depending on the length of the "dangling" leg BC, i.e. the side which does not touch the given angle A. To determine which case applies, we construct a triangle ...
*Thursday, June 3, 2010 at 10:08pm by MathMate*

**Math - explanation**

This is an example in the text book. Using vectors, demonstrate that the three points A(5, -1), B(-3,4) and C(13,-6) are collinear. Solution AB = (-8, 5) BC = (16, -10) Then BC = 2AB AB and BC have the opposite direction, so the points A, B, and C must be collinear. I don't ...
*Saturday, March 29, 2008 at 4:42pm by Anonymous*

**Geometry-7th grade**

All sides of a Rhombus are congruent. Therefore, AB = BC = CD = AD BC = x + 9 DC = 5x - 2 BC = DC x + 9 = 5x - 2 4x = 11 x = ?
*Monday, February 21, 2011 at 1:37pm by Helper*

**Physics, please help**

Distruive interference? Unless you put C in the line between A and B, this the asnwer is at infinity. Now on the line between A and B, the distance from A to C has to be an odd multiple of halfwavelength greater than C to B. Now, the distance between the speakers is two ...
*Friday, May 4, 2007 at 4:04am by Papito*

**Angle question**

Quadrilateral JKLM is a rhombus. If mangleLMK = 36, find mangleKJM In the right triangle ABC, mangleB = 90, AB = 5, and AC= 12. Find BC. Round to the nearest tenth, if necessary. Help? Is AB a side and AC a side? I can't tell from your description which are sides and which is ...
*Monday, August 21, 2006 at 8:14pm by Rachel*

**chemistry**

Well i believe it is bc H20 needs alot of energy to bc a gas bc of the molecular bonds on it, while CO2 requires less energy to become a gas so that is why it becomes a gas at room temp
*Tuesday, November 25, 2008 at 12:39am by Steven*

**math **

AB/XY = BC/YZ, 5/35 = BC/70, Multiply both sides by 70: BC = 70*5/35 = 10 cm.
*Monday, April 25, 2011 at 7:42pm by Henry*

**physics**

Pascal’s principle F1/A1=F2/A2. F(bc)={A(bc)/A(mc)}•F(pedal) = =(1.83/6.32) •49 =14.2 N This is the normal force exerted on the brake shoe. The frictional force is F(fr) =μ F(bc)=0.442•14.2 =6.3 N
*Friday, November 30, 2012 at 12:16pm by Elena*

**geometry help!!**

oops. hit wrong key. 24*AB = 7*BC but AB+BC = 124/2 = 62, so 24(62-BC) = 7BC BC = 48 AB = 14 Area = 24*14 = 7*48 = 336
*Wednesday, March 13, 2013 at 4:36pm by Steve*

**Math**

Are the sides of triangle BCE, BC, BE and EC ? In rectangle ABCD, is side BC opposite to side AD? If so, AD = BC = 3 If so, since BCE is an equilateral triangle, (all three sides equal)therefore BE = BC = EC = 3. I don't have the advantage of seeing the diagram you are, so you...
*Tuesday, January 25, 2011 at 7:51pm by helper*

**math**

<<c is the midpoint of bc,bc=12, >> Are you sure you copied that question correctly? c should be an endpoint of bc. I can see how d might be the midpoint.
*Friday, March 2, 2012 at 8:04pm by drwls*

**probability**

PROBLEM 2: SET OPERATIONS AND PROBABILITIES (3 points possible) Find the value of P(A∪(Bc∪Cc)c) for each of the following cases: The events A, B, C are disjoint events and P(A)=2/5. P(A∪(Bc∪Cc)c)= incorrect The events A and C are disjoint, and P(A)=1/2 ...
*Friday, February 7, 2014 at 4:10pm by JuanPro*

**math b**

A median is a line joining the a vertex to the mid-point of the opposite side. If the median is also an altitude to side BC, then the median should be perpendicular to BC. Let D be the mid-point of BC. The coordinates of D should be rather obvious, being the mid-point of ...
*Monday, May 25, 2009 at 1:44pm by PC*

**Please help with a trapezoid - circle problem**

Correction: AB = CD = 10. h = Diameter = 2*3 = 6=Ht. or altitude. Draw altitudes CE and BF Draw diagonal CF which bisects BCE and BFE. Therefore, CFE = 45o tan45 = h/BC = 6/BC BC = 6/tan45 = 6. = Shortest base.
*Monday, February 18, 2013 at 7:01pm by Henry*

**math**

easiest way: list the points in a column, repeat the one you started with 2 3 -2 -4 3 4 2 3 area = (1/2)[ sum of downproducts - sum of up-products] = (1/2)[-8 -8 + 9 - (-6 -12 +8) ] = (1/2)( -7 + 10] = 3/2 or label the points A(2,3) , B(3,4) and C(-2,-4) BC = √(25 + 64...
*Saturday, October 13, 2012 at 11:27am by Reiny*

**math**

given that a/b = c/d then ad = bc now divide both sides by cd to get a/c = b/d as required or if we cross - multiply the first we had ad = bc if we cross-multiply a/c = b/d we also get ad = bc so it it true.
*Tuesday, May 26, 2009 at 1:01pm by Reiny*

**Geometry**

Did you make a sketch? On my diagram length(BC) = length(AC) - length(AB) = 12x-2 - (5x+2) = 7x-4 but B is the mipoint, so AB = BC 7x-4 = 5x+2 2x = 6 x = 3 then BC = 7(3)-4 = 17 check: AB = 17 AC = 12(3)-2 = 34 BC = 17 , YUP!!
*Thursday, July 1, 2010 at 11:11pm by Reiny*

**Trig-Medians and law of cosines and sines**

In triangle ABC, we have AB=3 and AC=4. Side BC and the median from A to BC have the same length. What is BC? Not making sense to me, I think the answer must be simple, but I don't know how to solve I applied the law of sines but to no avail. Help is appreciated, thanks.
*Wednesday, November 20, 2013 at 11:53am by Sam*

**math**

ive been working on my sat's and i cant seem to figure out how to answer the following question. a right angle is given. the length of ba is 20. what is the approx length of bc? sin= .643 cos= .766 tan= .839 the answer is 12.9 but i dont know how that is. I assume bc is the ...
*Saturday, July 14, 2007 at 5:23pm by bart*

**geometry**

since B is the midpoint of line AC, that means AB=BC set AB=BC 12x-5=4x+15 find x. plug x into 4x+15 to find BC.
*Monday, September 13, 2010 at 3:48pm by Anonymous*

**math**

c is the midpoint of bc,bc=12, and cd 4x-8 what is the value of x
*Friday, March 2, 2012 at 8:04pm by Anonymous*

**Geometry**

BC has endpoints B(5,9) and C(-4,-3). Find the coordinates of the midpoint of BC.
*Tuesday, November 6, 2012 at 4:16pm by Mark*

**foundations of geometry**

find y and bc if b is between a and c ab=6y, bc=12y
*Wednesday, October 20, 2010 at 1:44pm by benjimn*

**geometry**

If b is between A and C, find the value of "x" and BC. AB=3(x+7),BC=2(x-3),and AC=50
*Monday, September 22, 2008 at 11:22pm by taz manian*

**math**

multipy all terms by abc bc+ac=ab bc=a(b-c) solve for a
*Monday, May 24, 2010 at 9:55pm by bobpursley*

**geometry**

if b is between a and c find the value of x and the measure of bc (ab=3x,bc=5x,ac=8)
*Friday, November 19, 2010 at 5:25pm by B*

**geometry**

If B is between A and C, AB=3x-1, BC=2x+4 and AC=38, what is the value of BC?
*Friday, January 28, 2011 at 2:58pm by octavia*

**Gemotry**

A(2,4) , B(3,1), C(15,7). The altitude is perpendicular to BC. Therefore, it's slope is the negative reciprocal of BC. m = (7-1) / (15-3) = 6/12 = 1/2=slope of BC. m2 = -2/1 = -2 = Slope of altitude.
*Sunday, July 24, 2011 at 2:43pm by Henry*

**geometry**

ab=3x, bc=5x, ac=8 what is x and bc?
*Friday, September 10, 2010 at 10:10pm by C*

**Algebra**

Simplify...Show work...-b+bc-c^3-(c^3+bc-c^3+b)
*Friday, March 16, 2012 at 12:08pm by sherry*

**trignometry**

Since you posted this twice, I think you realized that the symbols did not come out like you intended. I think you meant this: AB = 8, angle A = 60° then you are given sin60° = .866 cos60° = .5 tan60° = 1.73 the problem is that we don't know where the 90° angle is, could be at...
*Wednesday, April 24, 2013 at 11:57pm by Reiny*

**geometry**

If b is between A and C, find the value of "x" and BC. AB=3x,BC=5x,and AC=8
*Monday, September 22, 2008 at 11:21pm by taz manian*

**geometry**

B is the midpoint of line AC. If AB = 12x-5 and BC = 4x + 15. Find x and BC.
*Monday, September 13, 2010 at 3:48pm by Anonymous*

**geometry**

IF AB = 15 and AC =23,find the length of BC (BC has a line over it)
*Wednesday, September 14, 2011 at 6:15pm by Diane*

**geometry**

what is the value of the variable and bc if b is between a and c if AB=17, BC=3m, AC=32
*Thursday, October 31, 2013 at 6:46pm by Anonymous*

**geometry**

It should be easy to see that AB = AC = AD let each one be x in triangle ADC 2x + 7 = 51 2x= 44 x = 22 in triangle ABC 2x + BC = 59 44 + BC = 59 BC = 15
*Monday, April 15, 2013 at 4:19am by Reiny*

**Math**

Foil Left side gives you: = a^2c^2 + a^2d^2 + b^2c^2 + b^2d^2 = (ac)^2 + (ad)^2 + (bc)^2 + (bd)^2 Foil Right side (ac+bd)^2 = ac x ac + ac x bd + ac x bd + bd x bc = (ac)^2 + 1acbd + 1acbd + (bd)^2 Foil (ad-bc)^2 = ad x ad - bc x ad - bc x ad + bc x bc = (ad)^2 - 1acbd - 1acbd...
*Friday, January 11, 2013 at 11:05am by Math Teach*

**math**

If you were finding slope, then you have it upside down. slope AB = (-2 + 1)/(4+2) = -1/6 slope of BC = (3+1)/(4+2) = 4/6 = 2/3 equation of BC y-3 = (2/3)(x-4) 3y - 9 = 2x - 8 2x - 3y + 1 = 0 distance from A(4,-2) to BC = |2(4) - 3(-2) + 1|√(2^2 + (-3)^2) = 15/√13
*Wednesday, November 23, 2011 at 2:09pm by Reiny*

**math**

did you mean A vavies with BC or A varies directly with BC, if so, then a. A = kBC so, 6 = k(4)(9) k = 6 then A = 6BC b. A = 6(3)(10) = 180 c. 20 = (6)(15)C C = ......
*Monday, September 1, 2008 at 5:19pm by Reiny*

**trig**

ABC is an isoscele triangle in which [AB]=[AC]=5cm and [BC]=6cm. Calculate [AM], where M is the mid-point of BC.
*Saturday, March 26, 2011 at 7:22pm by ezendu*

**maths**

Locate points on the ocean: Let the point at 30 degrees be A Let the point at 60 degrees be B Let the base of the lighthouse be point C Let the height of the lighthouse be h h/BC = tan 60 = √3 h/AC = tan 30 = 1/√3 √3 BC = 1/√3 AC 3BC = AC That means AC...
*Tuesday, November 8, 2011 at 4:14am by Steve*

**Math**

In triangle ABC, D and E are midpoints of AB and AC, DE=4x and BC=2x+48. Find BC. Thanks So Much!!
*Saturday, May 21, 2011 at 10:28pm by Alana*

**maths**

so, we want to show that ab+bc+ca <= (a^2+b^2+c^2) since all squares are positive, 0 <= (a-b)^2 + (a-c)^2 + (b-c)^2 0 <= a^2-2ab+b^2 + a^2-2ac+c^2 + b^2-2bc+c^2 0 <= 2(a^2+b^2+c^2) - 2(ab+ac+bc) ab+ac+bc <= a^2+b^2+c^2 This is in fact true for any three real ...
*Thursday, February 14, 2013 at 12:43pm by Steve*

**math**

ahh, that's better make a sketch of a line and label point A, B, C, and D using CD : AB = 5:2 label AB = 2x and CD = 5x , giving you the 5:2 ratio From AC = 25 you can now label BC as 25-2x From BD = 46 you can label BC as 46-5x so obviously 25-2x = 46-5x x = 7 sub back in ...
*Wednesday, October 6, 2010 at 11:57am by Reiny*

**maths**

Triangle ABC has an obtuse angle at B, base BC has length equal to 30 and height equal to 24. (This height is taken with respect to base BC). D is a point on the line segment BC and E is a point on AC such that DE∥AB. F is a point on AB such that FD∥AC. As D varies...
*Saturday, June 8, 2013 at 4:15am by keshav*

**geometry**

Please use this for the portfolio. You will need graph paper. 1. Start with Triangle ABC with vertices: A(0,2), B(2,5), C(3,0) 2. Find slope of side AB and BC 3. Now TRANSLATE the Triangle 4 units left, and 2 units up (x-4,y+2) and give the new vertices to find A', B', C' 4. ...
*Monday, April 7, 2014 at 4:44pm by brit*

**Math - vector equation of a parallelogram**

Sure, we can find the vector equations of those lines, but I hesitated since you called it a parallelogram, which it isn't. let's find vector equation for line BC direction vector of BC is [4,-4] or simplified to [1,-1) a point on there is {3,6) equation for BC: [x,y] = (3,6...
*Sunday, September 5, 2010 at 11:23pm by Reiny*

**Trigonometry**

sin 75 = .5 BC/15 BC = 30 sin 75 and sorry used trig (have no idea how to do it without trig) to get exact .5 BC/15 = cos 15 so BC = 30 cos 15 cos 15 = sqrt ( [1+cos 30]/2 ) but cos 30 = .5 sqrt 3 so BC = 30 sqrt ( [ 1 + .5 sqrt 3]/2 )
*Saturday, December 1, 2012 at 8:39pm by Damon*

**geometry**

ABC is a triangle with AC=139 and BC=178. Points D and E are the midpoints of BC and ACrespectively. Given that AD and BE are perpendicular to each other, what is the length of AB?
*Monday, June 24, 2013 at 1:08pm by stranger*

**Math**

Consider a line segment with endpoints A and C with B a point on segement AC. The measure of AB = x^2, the measure of BC = 9x, and the measure of AC = 36. Then AB + BC = AC x^2 + 9x = 36 x^2 + 9x -36 = 0 (x + 12)(x - 3) = 0 x + 12 = 0 or x - 3 = 0 x = -12 x = 3 Don't use x = -...
*Tuesday, November 4, 2008 at 12:26pm by Margie*

**maths**

If ABC is a triangle with AB=20,BC=22 and CA=24. Let D lie on BC such that AD is the angle bisector of ∠BAC. What is AD2?
*Sunday, June 23, 2013 at 8:18am by Anonymous*

**geometry**

Just lay out the points on the line BD contains the right half of BC and the left half of CE So, what's left is the same length: The left half of AC and the right half of CE AE = AB + BC + CD + DE but BD = BC + CD = 14 so, AE = AB + 14 + DE However, AB = BC and CD = DE so AB+...
*Sunday, December 11, 2011 at 7:20pm by Steve*

**math help mepls**

Triangle ABC has an obtuse angle at B, base BC has length equal to 30 and height equal to 24. (This height is taken with respect to base BC). D is a point on the line segment BC and E is a point on AC such that DE∥AB. F is a point on AB such that FD∥AC. As D varies...
*Friday, June 7, 2013 at 5:47am by clavin*

**geometry**

Since CD is BOTH the median and altitude, the triangle is isosceles and AB is the short side. The 2 long sides(AB and BC) are equal. AB = BC, 2X + 8 = 3X + 5, 2X - 3X = 5 - 8, -X = -3, X = 3. P = AB + AC + BC, P = (5X + 3) + (2X + 8) + (3X + 5), P = (5*3 + 3) + (2*3 + 8) + (3*...
*Monday, October 4, 2010 at 5:16pm by Henry*

**Geometry Check**

To be collinear, line segments have to be parallel, and a point must be common for your choice slopeAB=1/3, slope BC=1/2 so they are not parallel b) slopeAB = 3/(1/2) = 6 , slope BC = 2/(1/2) = 4 not parallel c) slopeAB = -2/4 = -1/2 , slope BC = -1/2 so the correct choice is c)
*Saturday, June 12, 2010 at 12:02am by Reiny*

**Geometry**

You are dealing with the intersection of the three altitudes, which is the orthocentre. The third altitude, from B to the x-axis will definitely hit the midpoint of AC. The others will only hit the midpoint of AB and BC if the triangle is equilateral. for that to happen AB = ...
*Sunday, November 30, 2008 at 1:39pm by Reiny*

**Math**

B is between A and C. If AB=x squared, BC=9x and AC=36, find the value(s) of x, AB, and BC.
*Tuesday, November 4, 2008 at 12:26pm by Abbey*

**geometry**

ab+bc=ac 3x+5x=8 8x=8 x=? bc=5x Put what you got for x in and solve.
*Friday, September 10, 2010 at 10:10pm by Jen*

**geometry **

The perimeter is 68. Find x,an,BC,AC.if ab is 2x+7,bc is 3x+5, and ac is 5x-4
*Wednesday, October 6, 2010 at 9:43pm by chance*

**AD or BC?**

BCE means Before the Common Era. It's the same as BC (before Christ).
*Thursday, December 13, 2012 at 9:20pm by Ms. Sue*

**St francis**

Abcd is a quadrilateral such that AB = bc, ad= 1/4am. If bc 12 what is the perimeter of abcd
*Wednesday, February 6, 2013 at 12:39am by MAggie*

**geometry**

Trapezoid ABCD has height 4, BC=5, and AD and BC are perpendicular. Find the area of the trapezoid.
*Sunday, February 13, 2011 at 10:12pm by sally*

**geometry**

Trapezoid ABCD has height 4, BC=5, and AD and BC are perpendicular. Find the area of the trapezoid.
*Sunday, February 13, 2011 at 10:13pm by sally*

**Geomatry**

What is the value of the variable and BC if B is between A and C. AB=4x BC=5x AB=16
*Tuesday, September 13, 2011 at 7:36pm by Chase*

**geometry **

What is the value of the variable and bc if b is between a and c. Ab=4x,bc=5x;ab=16
*Saturday, October 1, 2011 at 12:59pm by kelvyn*

**Math**

ABCD is a parallelogram. E is a point on DC extended, such that D and E are on opposite sides of BC. Let AE intersect BC and BD at F and G, respectively. If AG=180 and FG=108, what is EF?
*Monday, May 20, 2013 at 3:00am by John*

**maths**

ABCD is a parallelogram. E is a point on DC extended, such that D and E are on opposite sides of BC. Let AE intersect BC and BD at F and G, respectively. If AG=180 and FG=108, what is EF?
*Wednesday, May 22, 2013 at 8:00am by hemant*

**Math**

figure side lengths, then use the law of cosines. AB^2 = 25 BC^2 = 40 AC^2 = 85 AC^2 = AB^2 + BC^2 - 2*AB*BC*cosABC 85 = 25+40-2√1000 * cosABC <ABC =~ 109°
*Friday, August 31, 2012 at 1:49am by Steve*

**Music**

c cc c bc cbc be bc cccccbcd ee ee eeff f (repeat)
*Friday, March 27, 2009 at 5:18pm by bobpursley*

**geometry**

AB + BC = AC (2x-1)+(4x+2)=25 x=4 AB = 2(4)-1 = 7 BC = 4(4)+2 = 18
*Sunday, October 2, 2011 at 2:50pm by Kyle*

**maths**

tan30=6/BC OR,BC=6/TAN30 =6/1/ROOT3 =6X1.732 =10.392
*Monday, January 14, 2013 at 10:30am by karuna*

**Trigonometry**

Make a sketch. I have a triangle ABC, where BC is the ground, AC is the tower. Angle B = 60°, angle C = 84.5°, making angle A = 35.5° by Sine Law: BC/sin 35.5° = 179/sin 60° I get BC = 120.026 So the shadow of the tower is 120 ft long
*Tuesday, August 30, 2011 at 10:55pm by Reiny*

**math b**

the vertices of triangle ABC are A(-2,3), B(0,-3), and C(4,1). prove, by means of coordinate geometry, that the median to side BC is also the altitude to side BC.
*Monday, May 25, 2009 at 1:44pm by jojo*

**math**

Let ABC be a triangle such that angle ACB = 135 degrees. Prove that AB^2 = AC^2 + BC^2 + ¡Ì2 x AC x BC.
*Saturday, August 7, 2010 at 1:37am by mathsen*

**geometry**

In triangle ABC, if line BC is one inch longer than line AB, line AC is 10 inches shorter than the sum of line BC and line AB , and the perimeter of triangle ABC is 72 inches, find the length of line BC?
*Wednesday, November 3, 2010 at 10:14pm by meghan*

**maths --plse help me..**

without using set square or protacter construct 1. triangle A BC WITH AB = 5.5 CM , BC = 3.2 CM CA = 4.8 CM 2. DRAW LOCUS OF A POINT WHICH MOVES SO THAT IT IS ALWAYS A DISTANCE OF 2.5 CM FROM B. 3. DRAW LOCUS OF POINT SO THAT IT IS EQUIDISTANT FROM BC & CA . 4. MARK POINT OF ...
*Friday, December 28, 2012 at 11:43am by Anonymous*

**Physics. Please help!!**

Distruive interference? Unless you put C in the line between A and B, this the asnwer is at infinity. Now on the line between A and B, the distance from A to C has to be an odd multiple of halfwavelength greater than C to B. Now, the distance between the speakers is two ...
*Friday, May 4, 2007 at 3:14pm by papito*

**Math**

Trigonometry problem: The sides AB and AC of triangle ABC are of lengths 4 and 7 respectively. M is the midpoint of BC. AM is of length 3.5, Find the length of BC.
*Saturday, July 23, 2011 at 3:59am by Kalia*

**maths**

let A = (h,k). Then B=(h+2(3-h),k+2(5-k))=(6-h,10-k) C=(h+2(-3-h),k+2(-3,k))=(-6-h,-6-k) BC^2 = 12^2+16^2 = 340 BC=√340
*Thursday, January 3, 2013 at 8:59am by Steve*

**Mathsssssssssssss**

Middle of BC is ( (1+5)/2 , (-3+7)/2) ) or (3,2) is point M so line through (-3,1) and (3,2) I bet you can find that line. Then line through M perpendicular to BC slope of BC = 10/-4 = -5/2 so slope we want = 2/5 so line with m = 2/5 that goes through (3,2) I bet you can do ...
*Monday, October 4, 2010 at 1:03pm by Damon*

**math**

AC*AD = 80, so AC = 20 AD=CE=4 CE*BC/2 = 30, so BC=15 AB+BC=20, so AB=5
*Sunday, January 12, 2014 at 4:35pm by Steve*

**Math - Geometry**

If more than one plane contains three points A,B, and C, what must be true? A)AB is perpendicular to BC B)A,B, and C are noncollinear C)A,B, and C are collinear D)AB=BC
*Wednesday, December 23, 2009 at 2:29pm by Thamara*

**precal**

draw a horizontal line from B to where it intersects the building wall. Call that point C. Label the top of the building A, and the bottom D. The height of the building is thus AD = AC + CD AC/BC = tan 43° CD/BC = tan 7° Now, you see that without knowing the distance BC, there...
*Sunday, July 15, 2012 at 9:47pm by Steve*

**MATH**

1. Let triangle ABC be a triangle such that angle ACB is 135 degrees. Prove that AB^2 = AC^2 + BC^2 - (Root 2) x AC x BC There is probably an error in the sign, because the result is obtained directly by application of the cosine law, and substituting cos(135°)=-√2 ...
*Saturday, August 21, 2010 at 12:27pm by MathMate*

**geometry**

line BC in one side of a regular n-gon. the sides next to line BC are extended to meet at point W. Find the measure of angle W in terms of n.
*Monday, October 10, 2011 at 10:44pm by Anonymous*

**maths**

ABCD is a rectangle with AB=26, BC=11. X, Y and Z are points on AB, BC and CD, respectively, such that AX=BY=CZ=6. What is the area of triangle XYZ?
*Wednesday, May 8, 2013 at 7:02am by hemant*

**math**

If ABC is a triangle with AB=20,BC=22 and CA=24. Let D lie on BC such that AD is the angle bisector of ∠BAC. What is AD^2?
*Monday, June 17, 2013 at 2:53pm by jack *

**math**

ABC is a triangle with AC=139 and BC=178. Points D and E are the midpoints of BC and AC respectively. Given that AD and BE are perpendicular to each other, what is the length of AB?
*Tuesday, June 25, 2013 at 5:22am by anonymous*

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