# an equation of the line tangent to y+x^3

40,539 results

**Calculus [finding slope of tangent line]**

Find the slope of the tangent line to the curve 0x^2−2xy+2y^3=10 at point (-4,1) Help please? Thanks in advance

**geomery**

Triangle ABC, inscribed in a circle, has AB = 15 and BC = 25. A tangent to the circle is drawn at B, and a line through A parallel to this tangent intersects line BC at D. Find DC.

**calculus I**

Find the tangent line approximation to 1/x when x=1 How do i find tangent line approximations??? my prof hasn't gone over this and i don't understand how to do it.

**math**

1. two circles. x^2+y^2-16x-8y+35=0 and x^2+y^2=5 are given. a. write the equations in the standard form. b.prove that the circles touch each other. c.hence calculate the equation of their common tangent 2. find the equation of a. circle. with centre c(2;3) and which I is the ...

**Calc**

A line tangent to y=(x^2)+1 at x=a, a>0, intersects the x-axis at point P. a) Write an expression for the area of the triangle formed by the tangent line, the x-axis, and the line x=a. b) For what value of 'a' is the area of the triangle a minimum? Justify your answer. Show...

**Calculus 2nd Post please help**

Find an equation of the tangent line to the graph of the function f defined by the following equation at the indicated point. (x - y - 1)3 = x; (1, -1)

**Calculus**

Consider the function g(x) = sinxcosx. a. Find an equation of the tangent line to the graph of g at (pi/3, sqrt3/4). b. Find the critical number(s) of g on the interval [0, 2pi]. Does the function have a relative minimum, relative maximum, or neither at each critical number. ...

**Calculus**

Use the given equation to answer the following questions. (Enter your answers from smallest to largest.) r = 8cos(¦È) 0 ¡Ü ¦È < ¦Ð (a) Find the points on the given curve where the tangent line is horizontal. theta= theta= (b) Find the points on the given curve where...

**Calculus (Tangent Line Approximation)**

Use tangent line approximation to derive an estimate for (1 + x)n , when x is near 0, and n is any real number.

**Calculus**

Suppose that y=f(x) = sqrt(2x), x>=0 Find a c > 0 such that the tangent line to the curve y = f(x) at x = c has the same slope as the tangent line to the curve y = f^–1(x) at x = c. You get: c = 1/8 c = 1/2 c = (1/8)^(1/3) c = (1/3)^(2/3) c = (1/2)^(1/3)

**Calculus**

Given that y=x^(5/2)- x^(-1/2) . a) Find the coordinates where the tangent line is parallel to the line y-4x-4=0. b) Find the coordinates where the tangent line is perpendicular to the line 2y-3x-12=0.

**Math**

Use linear approximation, i.e. the tangent line, to approximate cube root of 27.05 as follows. Let f(x) = cube root of x and find the equation of the tangent line to f(x) at x = 27 in the form y = mx+b. Note: The values of m and b are rational numbers which can be computed by ...

**calculus**

for what value of r=4sinè have vertical tangent? In polar coordinates? Theta=90 deg is vertical. I do not know if you know how to differentiate polar coordinate equations so I changed your equation from polar to rectangular form, I don't know if that is the way you do it. ...

**calculus**

Find a function f(x) = a + b sqrt(x) that is tangent to the line 2y - 3x = 5 at the point (1,4) AND Find a function of the form f(x)=c+dcoskx that is tangent to the line y=1 at the point (0,1) and tangent to the line y=x+(3/2) - (pi/4) at the point ([pi/4], [3/2)

**Pre-Calculus**

Im having trouble with this. Find an equation of the tangent line to the parabola at the given point and find the x-intercept of the line. x^2=2y (4,8)

**Pre-Cal**

Find an equation of the tangent line to the parabola at the given point, and find the x-intercept of the line. 17) x^2=2y , (-3,9/2) 18) y=-2x^2 , (-1,-2)

**Calculus: for mathmate**

Find the slope of the tangent line to the graph of the given function at any point: 1. f(x)= 13 I understand that you said the tangent to the line is the coefficient of x, but what would be the slope of this problem. For problems like this are there specific steps to take?

**calculus**

Find an equation of the line tangent to 2x^2-x-ln(x-4)-y^2=9 at (5,6)

**calculus**

Write an equation of the line tangent to y=(9-x^2)^2/3 at x=1

**calculus**

find the equation of the tangent line to y=4^((x^2)-6x+3) at x=4

**Calculus**

write the equation of line tangent to f(x)=(1/3x^3)-x^2+x-1 when x=1

**Calculus**

The equation of the tangent line to f(x) = \sqrt{x} at x = 64 is y =

**cal**

find the equation for the tangent line g(x)=x-1/2x+4 at x=-1

**slope of tangent line**

the sl0pe of the tangent line to the graph of the exponential function y=2^x at the point (0,1) is lim(x->0)(2^x-1)/x. estimate the slope of three decimal places. f'(x)=2^x. what do i do. we have to solve this without using derivative. i keep getting zero.

**calculas**

The point P(7, −4) lies on the curve y = 4/(6 − x). (a) If Q is the point (x, 4/(6 − x)), use your calculator to find the slope mPQ of the secant line PQ (correct to six decimal places) for the following values of x. (i) 6.9 mPQ = (ii) 6.99 mPQ = (iii) 6.999 mPQ = (iv) 6...

**CALC (TANGENT LINE)**

1-show that 1-x/2 is the tangent line approximation to 1/ sqrt of 1+x near x=0 2-what is the local linearization of e^x^2 near x=1 3-find the tnagent line approximation of 1/x near x=1

**Calculus Help Please!!!**

Find the equation in slope intercept form of the tangent line and the normal line to the curve x^2+4xy+y^2=13 at the point.(2,1). show steps please!!! thank you!

**calc**

for the parametric curve defined by x=3-2t^2 and y=5-2t ...sketch the curve using the parametric equation to plot of the point. use an arrow to indicate the direction of the curve for o<t<1. Find an equation for the line tangent to the curve at the point where t=-1. x=3...

**Math**

Find an equation for the tangent line to the curve at (π/2 , 2). y = 4 + cot(x) - 2csc(x) I am confused how to take the derivative of this problem. When I tried to solve it I ended up with -csc^2 (x) + (2csc(x) * cot(x)). From there I can't seem to simplify it. Also, can ...

**Calculus**

Find the equation of the tangent line to the curve 2e^(xy) = x + y at (0,2)

**Calculus**

If the equation of the tangent line to the curve: xy^3+xy=6, (3,1) find m and b

**Calculus**

find the equation of the tangent line to the curve when x=7. f(x)= 6-x^2

**Calculus**

find the equation of the tangent line to the curve when x=7. f(x)= 6-x^2

**Claculus**

find the equation of the tangent line to y^3-xy=-6 at the point (7,2)

**calculus**

Find the equation of the tangent line to the graph of f(x)=4x^3-1x^2+1 at x=-2.

**Calculus**

find the equation of a tangent line of x^(1/4) + y^(1/4) = 4 at the point (16,16)

**Calculus Please Help**

Let f(x) = x^3 - x^2 + x - 1. Find an equation for tangent line to f at x = 2.

**Calculus Please Help**

Let f(x) = x^3 - x^2 + x - 1. Find an equation for tangent line to f at x = 2.

**calculus**

find equation of a tangent line to y=x^3-5x+6 at the point where x=2

**Calculus**

find f(3) and f'(3), assuming that the tangent line to y=f(x) at a=3 has the equation y=5x+2.

**Calculus**

find an equation for the line tangent to y=2-6x^2 at (-5,-148)

**math**

Find f(3) and f'(3), assuming that the tangent line to y=f(x) at a=3 has the equation y=5x+2

**calculus**

find an equation of the tangent line to the curve at y=2x^3+5x, (-1, 3)

**Calculus**

equation of tangent line of the function sqrt (3x+5) where x=10

**calculus**

find the equation of the tangent line for (xy)^2+(xy)-x=11 at the point (-11,0)

**calculus**

Find an equation of the tangent line to the curve at (8,0). y=ln(x^2 -8x +1)

**calculus**

Find an equation of the tangent line to the graph y=(x^3 + 2)^5 at x= -1

**Math**

Find an equation of the tangent line to the graph of y = f(x) at x = a, a = 1. f(x) = x + 3/x^2 + 1

**calculus**

f(x)=(x^2+1)(1-x-x^3).Determine the equation of the line tangent to f(x) at the point (1,-2).

**Calculus**

(x) = x ^3 - 12 x + 11, write the equation of the line tangent to the curve at x = 1

**calculus**

find the equation of the line tangent to the graph y=3e^x at x=1

**calculus**

find the equation of the line tangent to the graph y=3e^x at x=1

**calculus**

find equation of tangent line for x^(1/3) + y^(1/2)=2 at point (1,1)

**math**

Find the equation of the line tangent to f(x)=3x^2-2x-1 at the point where x=2

**Calculus 1**

Given f(x)= 3e^(1-x^2)*ln(x), find the equation of the tangent line at x = 1.

**Calculus**

If f(1)=4 and f'(1)=2, find an equation of the tangent line at x=1 A. y=2x+2 B. y=2x-2 C. y=4x-7 D. y=4x-2 E. None of these

**Calculus**

Find the equation of the tangent line when x=2 for the functin f(x)=5^(x/2)

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...

**Calculus**

What are the coordinates of the point on the graph of f(x)=(x+1)(x+2) at which the tangent is parallel to the line with equation 3x-y-1=0? a)(-3,2) b)(-1,0) c)(0,2) d)(1,6) To answer this, I put f(x)=(x+1)(x+2) into the form f(x)=x^2+3x+2 and found the derivative which is f'(x...

**Calculus**

Given the function y=(x^2-5/x+3), answer the following questions. a) Find dy/dx. Simplify your answer b) Find the coordinates of any points on the graph of y where the tangent line is horizontal. Show your work. c) Are there any points on the graph of y where the tangent line ...

**calculus**

1. Which of the following expressions is the definition of the derivative of f(x) = cos(x) at the point (2, cos(2))? 2. Find the derivative of f(x) = |x + 2| at the point (1, 3) 3. Find f '(x) for f(x) = -2x3 + 3x2 - x + 15. 4. Find all values of x on the graph of f(x) = -2x3...

**Calculus**

The graph of the equation is x^2+xy+y^2=9 a) What is the equation of the right most vertical tangent? b) That tangent touches the ellipse where y= what? I've calculated the derivative to y'=(-y-2x)/(2y+x) and I found the horizontal tangents. How do I do this part?

**Math - point on the graph (check +help)**

Determine the coordinates of the point on the graph of f(x)=sqrt(2x+1) where the tangent line is perpendicular to the line 3x+y+4=0 I do not seem to get the answer... I find the first derivative of f(x0 and equate it to the value of the slope from the tangent line. the answer ...

**calculus**

1. Which of the following expressions is the definition of the derivative of f(x) = cos(x) at the point (2, cos(2))? 2. Find the derivative of f(x) = |x + 2| at the point (1, 3) 3. Find f '(x) for f(x) = -2x3 + 3x2 - x + 15. 4. Find all values of x on the graph of f(x) = -2x3...

**trigonometry**

Find the equation of a line passing through the origin so that the tangent of the angle between the line in quadrantI and the positive x-axis is sqrt3/3. A. y=sqrt3/3x B. y=sqrt3x C.y=x D.y=sqrt2/2x thnks alot:)

**Calculus-derivatives**

Verify these answers~ 1. For what value(s) of x does f(x)=(x^2-16)^5 have a horizontal tangent? a) x=-4,4 b) x=-4,0,4 c) x=0 d) x=0,4 Answer is B, x=-4,0,4 --------------------------------------- 2. What is the derivative of f(x)=(3x^2+7)^3? a) f'(x)=3(3x^2+7)^2 b) f'(x)=18(3x...

**Math**

Write the equation of the circle with center (-2,-3) and tangent to the line 2x+5y=10.

**calculus**

Determine the equation of the line that is tangent to y=8^x at the point on the curve where x=1/2

**calculus**

Find the equation of tangent line to the curve Y=2/x^2+x At the point where x=1

**calculus**

find,if any, an equation for a common tangent line to these 2 curves:5x^2;and 5x^2-x+6

**calculus**

y=3⋅2^x Find the equation of the line tangent to the graph of y at x=1.5.

**Calculus**

Find the equation of the tangent line to the graph of f(x) = −6x ln(x + 10) at x = 0.

**Calculus**

which of the following is an equation of the line tangent to the graph of y = (x^3)-x at the point where x =2: a) y - 6 = 4(x-2) b) y - 6 = 5(x-2) c) y - 6 = 6(x-2) d) y - 6 = 11(x-2) e) y - 6 = 12(x-2) thanks!

**calculus**

which of the following is an equation of the line tangent to the graph of y = (x^3)-x at the point where x =2: a) y - 6 = 4(x-2) b) y - 6 = 5(x-2) c) y - 6 = 6(x-2) d) y - 6 = 11(x-2) e) y - 6 = 12(x-2) thanks!

**calculus**

what is the equation of the tangent line to the curve x^3 + 2y^2 + 3xy = 6 at the point (1,1)?

**Calculus**

Find the equation of the line tangent to the graph of f at (1,1) where f is given by f(x)=2x^3-2x^2+1

**Ap Calculus**

Find the equation of the tangent line to the graph of f(x)=cos3xlnx^4 at (1,0)

**calculus**

equation of the tangent line to the curve y = 2x²-x+10 at the point (-1,13)

**algebra 2**

how to find equation of horizontal tangent line of 2y^3+6x^2y-12x^2+6y=1

**Calculus**

Find an equation of the tangent line to the curve f(x)=-1/x+2 at the points (2, -1/4).

**Calculus**

Find the equation of a circle with center C(1,6) and tangent line x-y-1=0.

**Calculus**

If the slope is 3, find an equation of the tangent line to the curve at P(8, -3).

**Calculus**

If 2x^3 + 2xy - y^2 = 6, then approximate the equation of the tangent line at point x = 1.44

**calculus**

An equation of the line tangent to the graph of f(x) = (4x2 - 8x + 3)4 at the point where x = 1 is:

**Calculus**

Find the equation of the tangent line to the graph of √(xy)=x-2y at (4,1)

**calculis**

Find the equation of the tangent line to the curve y=e^2x + 4x at the point (0,1)

**Calculus**

Find the slope of the tangent line to the graph of the equation: y = (2x^2+3)(x-1) at x=2. a = 11 b = 08 c = 19 d = 16

**CALCULUS**

An equation of the line tangent to the graph of (5x - 1)/(3x + 1) at the point where x = 1 is? Any ideas?

**calculus**

Find the equation of the tangent line to the curve x^3 + xy^2 =5 at the point (1,2).

**calculus**

Find the equation of the tangent line to the graph of the function f(x)=x-3/3x-5 at x=1

**math**

find an equation of the tangent line to the graph of y=e^(2x-3) at point (3/2,1) thanks!

**maths**

Find the equation of the tangent to circle x² + y² - 6x + 4y - 12 = 0 which is parallel to line 4x +3y +5

**Calculus**

Let f(x)= 6x+(4/x^2). Then the equation of the tangent line to the graph f(x) at the point (2,13) is give by y=mx+b What is m? What is b?