Tuesday

December 1, 2015
Number of results: 35,573

**Calculus**

write the equation of line tangent to f(x)=(1/3x^3)-x^2+x-1 when x=1
*May 9, 2014 by Kim*

**Calculus**

The equation of the tangent line to f(x) = \sqrt{x} at x = 64 is y =
*October 31, 2014 by Alessandra Romano*

**slope of tangent line**

the sl0pe of the tangent line to the graph of the exponential function y=2^x at the point (0,1) is lim(x->0)(2^x-1)/x. estimate the slope of three decimal places. f'(x)=2^x. what do i do. we have to solve this without using derivative. i keep getting zero.
*September 23, 2007 by Anonymous*

**Calculus Help Please!!!**

Find the equation in slope intercept form of the tangent line and the normal line to the curve x^2+4xy+y^2=13 at the point.(2,1). show steps please!!! thank you!
*April 8, 2014 by Tanya *

**CALC (TANGENT LINE)**

1-show that 1-x/2 is the tangent line approximation to 1/ sqrt of 1+x near x=0 2-what is the local linearization of e^x^2 near x=1 3-find the tnagent line approximation of 1/x near x=1
*April 1, 2010 by MILEY*

**calc**

for the parametric curve defined by x=3-2t^2 and y=5-2t ...sketch the curve using the parametric equation to plot of the point. use an arrow to indicate the direction of the curve for o<t<1. Find an equation for the line tangent to the curve at the point where t=-1. x=3...
*April 17, 2007 by kelly*

**Calculus**

Find the equation of the tangent line to the curve 2e^(xy) = x + y at (0,2)
*May 14, 2009 by Matt*

**Calculus**

If the equation of the tangent line to the curve: xy^3+xy=6, (3,1) find m and b
*June 11, 2009 by gnozahs*

**Calculus**

find the equation of the tangent line to the curve when x=7. f(x)= 6-x^2
*August 9, 2009 by Stacy*

**Calculus**

find the equation of the tangent line to the curve when x=7. f(x)= 6-x^2
*August 9, 2009 by Stacy*

**Claculus**

find the equation of the tangent line to y^3-xy=-6 at the point (7,2)
*June 21, 2010 by Trace*

**calculus**

Find the equation of the tangent line to the graph of f(x)=4x^3-1x^2+1 at x=-2.
*October 12, 2010 by jo*

**Calculus **

find the equation of a tangent line of x^(1/4) + y^(1/4) = 4 at the point (16,16)
*November 14, 2010 by kevin *

**calculus**

equation of the tangent line to the curve y = 2x²-x+10 at the point (-1,13)
*February 21, 2011 by Anonymous*

**Calculus Please Help**

Let f(x) = x^3 - x^2 + x - 1. Find an equation for tangent line to f at x = 2.
*March 23, 2011 by Abi*

**Calculus Please Help**

Let f(x) = x^3 - x^2 + x - 1. Find an equation for tangent line to f at x = 2.
*March 23, 2011 by Cecille*

**calculus**

find equation of a tangent line to y=x^3-5x+6 at the point where x=2
*June 19, 2011 by Yetty*

**Calculus**

find f(3) and f'(3), assuming that the tangent line to y=f(x) at a=3 has the equation y=5x+2.
*September 7, 2011 by Hannah*

**Calculus**

find an equation for the line tangent to y=2-6x^2 at (-5,-148)
*September 7, 2011 by Hina*

**math**

Find f(3) and f'(3), assuming that the tangent line to y=f(x) at a=3 has the equation y=5x+2
*September 22, 2011 by Anonymous*

**calculus**

find an equation of the tangent line to the curve at y=2x^3+5x, (-1, 3)
*September 24, 2011 by vicki *

**Calculus**

equation of tangent line of the function sqrt (3x+5) where x=10
*October 14, 2011 by Jack*

**calculus**

find the equation of the tangent line for (xy)^2+(xy)-x=11 at the point (-11,0)
*October 28, 2011 by Anonymous*

**calculus**

Find an equation of the tangent line to the curve at (8,0). y=ln(x^2 -8x +1)
*November 9, 2011 by Alexa*

**calculus**

Find an equation of the tangent line to the graph y=(x^3 + 2)^5 at x= -1
*December 10, 2011 by Maha*

**Math**

Find an equation of the tangent line to the graph of y = f(x) at x = a, a = 1. f(x) = x + 3/x^2 + 1
*April 13, 2012 by Sandra Gibson*

**calculus**

f(x)=(x^2+1)(1-x-x^3).Determine the equation of the line tangent to f(x) at the point (1,-2).
*September 30, 2012 by jump*

**Calculus**

(x) = x ^3 - 12 x + 11, write the equation of the line tangent to the curve at x = 1
*October 18, 2012 by Kerry*

**calculus**

find the equation of the line tangent to the graph y=3e^x at x=1
*January 30, 2013 by Anonymous*

**calculus**

find the equation of the line tangent to the graph y=3e^x at x=1
*January 30, 2013 by Anonymous*

**calculus**

find equation of tangent line for x^(1/3) + y^(1/2)=2 at point (1,1)
*June 16, 2013 by jack*

**math**

Find the equation of the line tangent to f(x)=3x^2-2x-1 at the point where x=2
*August 1, 2013 by gerald*

**Calculus 1**

Given f(x)= 3e^(1-x^2)*ln(x), find the equation of the tangent line at x = 1.
*October 26, 2014 by Ben*

**Calculus**

If f(1)=4 and f'(1)=2, find an equation of the tangent line at x=1 A. y=2x+2 B. y=2x-2 C. y=4x-7 D. y=4x-2 E. None of these
*November 30, 2014 by Anonymous *

**Calculus**

Find the equation of the tangent line when x=2 for the functin f(x)=5^(x/2)
*March 29, 2015 by Anonymous*

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...
*October 18, 2010 by james*

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...
*October 18, 2010 by james*

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...
*October 18, 2010 by james*

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...
*October 18, 2010 by james*

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...
*October 18, 2010 by james*

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...
*October 18, 2010 by james*

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...
*October 18, 2010 by james*

**math**

A(-3,-2) B(8,4)are the ends of the diameter of a circle. the tangent of the circle at point B is -11x+6y+64=0 the line L passes through A and the origin. line L has a gradient of 2/3 what is the coordinates that the line L and tangent at point B cross?? (this question had 4 ...
*October 18, 2010 by james*

**Calculus**

What are the coordinates of the point on the graph of f(x)=(x+1)(x+2) at which the tangent is parallel to the line with equation 3x-y-1=0? a)(-3,2) b)(-1,0) c)(0,2) d)(1,6) To answer this, I put f(x)=(x+1)(x+2) into the form f(x)=x^2+3x+2 and found the derivative which is f'(x...
*April 30, 2015 by Sara*

**Calculus**

Given the function y=(x^2-5/x+3), answer the following questions. a) Find dy/dx. Simplify your answer b) Find the coordinates of any points on the graph of y where the tangent line is horizontal. Show your work. c) Are there any points on the graph of y where the tangent line ...
*December 5, 2012 by Rudy*

**calculus **

1. Which of the following expressions is the definition of the derivative of f(x) = cos(x) at the point (2, cos(2))? 2. Find the derivative of f(x) = |x + 2| at the point (1, 3) 3. Find f '(x) for f(x) = -2x3 + 3x2 - x + 15. 4. Find all values of x on the graph of f(x) = -2x3...
*January 15, 2015 by mock*

**Math - point on the graph (check +help)**

Determine the coordinates of the point on the graph of f(x)=sqrt(2x+1) where the tangent line is perpendicular to the line 3x+y+4=0 I do not seem to get the answer... I find the first derivative of f(x0 and equate it to the value of the slope from the tangent line. the answer ...
*October 23, 2010 by Anonymous*

**calculus **

1. Which of the following expressions is the definition of the derivative of f(x) = cos(x) at the point (2, cos(2))? 2. Find the derivative of f(x) = |x + 2| at the point (1, 3) 3. Find f '(x) for f(x) = -2x3 + 3x2 - x + 15. 4. Find all values of x on the graph of f(x) = -2x3...
*January 15, 2015 by gerald*

**trigonometry**

Find the equation of a line passing through the origin so that the tangent of the angle between the line in quadrantI and the positive x-axis is sqrt3/3. A. y=sqrt3/3x B. y=sqrt3x C.y=x D.y=sqrt2/2x thnks alot:)
*January 16, 2009 by y912f*

**Calculus-derivatives**

Verify these answers~ 1. For what value(s) of x does f(x)=(x^2-16)^5 have a horizontal tangent? a) x=-4,4 b) x=-4,0,4 c) x=0 d) x=0,4 Answer is B, x=-4,0,4 --------------------------------------- 2. What is the derivative of f(x)=(3x^2+7)^3? a) f'(x)=3(3x^2+7)^2 b) f'(x)=18(3x...
*February 18, 2012 by Jake*

**Math**

Write the equation of the circle with center (-2,-3) and tangent to the line 2x+5y=10.
*January 25, 2009 by Hannah*

**calculus **

Determine the equation of the line that is tangent to y=8^x at the point on the curve where x=1/2
*April 19, 2010 by Anonymous*

**calculus**

Find the equation of tangent line to the curve Y=2/x^2+x At the point where x=1
*November 30, 2010 by pinki*

**calculus**

find,if any, an equation for a common tangent line to these 2 curves:5x^2;and 5x^2-x+6
*October 12, 2010 by lam*

**calculus**

y=3⋅2^x Find the equation of the line tangent to the graph of y at x=1.5.
*October 14, 2010 by jordyn*

**Calculus**

Find the equation of the tangent line to the graph of f(x) = −6x ln(x + 10) at x = 0.
*October 20, 2010 by Erika*

**Calculus**

which of the following is an equation of the line tangent to the graph of y = (x^3)-x at the point where x =2: a) y - 6 = 4(x-2) b) y - 6 = 5(x-2) c) y - 6 = 6(x-2) d) y - 6 = 11(x-2) e) y - 6 = 12(x-2) thanks!
*December 14, 2010 by Marc*

**calculus**

which of the following is an equation of the line tangent to the graph of y = (x^3)-x at the point where x =2: a) y - 6 = 4(x-2) b) y - 6 = 5(x-2) c) y - 6 = 6(x-2) d) y - 6 = 11(x-2) e) y - 6 = 12(x-2) thanks!
*December 14, 2010 by Marc*

**calculus**

what is the equation of the tangent line to the curve x^3 + 2y^2 + 3xy = 6 at the point (1,1)?
*December 15, 2010 by Sasha*

**Calculus**

Find the equation of the line tangent to the graph of f at (1,1) where f is given by f(x)=2x^3-2x^2+1
*February 8, 2011 by Grace*

**Ap Calculus**

Find the equation of the tangent line to the graph of f(x)=cos3xlnx^4 at (1,0)
*February 10, 2011 by Dinorah*

**algebra 2**

how to find equation of horizontal tangent line of 2y^3+6x^2y-12x^2+6y=1
*April 4, 2011 by Anonymous*

**Calculus**

Find an equation of the tangent line to the curve f(x)=-1/x+2 at the points (2, -1/4).
*May 9, 2011 by Anonymous*

**Calculus**

Find the equation of a circle with center C(1,6) and tangent line x-y-1=0.
*July 29, 2011 by Cad*

**Calculus**

If the slope is 3, find an equation of the tangent line to the curve at P(8, -3).
*October 8, 2011 by Cat*

**Calculus**

If 2x^3 + 2xy - y^2 = 6, then approximate the equation of the tangent line at point x = 1.44
*February 10, 2012 by Scooby10*

**calculus**

An equation of the line tangent to the graph of f(x) = (4x2 - 8x + 3)4 at the point where x = 1 is:
*February 16, 2012 by Anonymous*

**Calculus**

Find the equation of the tangent line to the graph of √(xy)=x-2y at (4,1)
*April 17, 2012 by Alan*

**calculis**

Find the equation of the tangent line to the curve y=e^2x + 4x at the point (0,1)
*April 23, 2012 by John*

**Calculus**

Find the slope of the tangent line to the graph of the equation: y = (2x^2+3)(x-1) at x=2. a = 11 b = 08 c = 19 d = 16
*April 26, 2012 by What's the Difference?*

**CALCULUS**

An equation of the line tangent to the graph of (5x - 1)/(3x + 1) at the point where x = 1 is? Any ideas?
*June 5, 2012 by ANONYMOUS*

**Calculus**

Determine the equation of the tangent line to the curve y = 2x²-1 at the point where x = -2
*June 15, 2012 by Sarah*

**calculus**

Find the equation of the tangent line to the curve x^3 + xy^2 =5 at the point (1,2).
*September 30, 2012 by jump*

**calculus**

Find the equation of the tangent line to the graph of the function f(x)=x-3/3x-5 at x=1
*October 22, 2012 by Derik*

**math**

find an equation of the tangent line to the graph of y=e^(2x-3) at point (3/2,1) thanks!
*October 31, 2012 by matthias*

**maths**

Find the equation of the tangent to circle x² + y² - 6x + 4y - 12 = 0 which is parallel to line 4x +3y +5
*January 4, 2013 by nanuna*

**Calculus**

Let f(x)= 6x+(4/x^2). Then the equation of the tangent line to the graph f(x) at the point (2,13) is give by y=mx+b What is m? What is b?
*January 30, 2013 by Anonymous*

**Calculus**

Let f(x)= 6x+(4/x^2). then the equation of the tangent line to the graph of f(x) at the point (2,13) is given by y=mx+b. What is m and what is b?
*January 31, 2013 by Anonymous*

**math**

43. What is an equation of the circle that has its center at the origin and is tangent to the line y=3x 7?
*February 27, 2013 by Shelyn Yang*

**Calculus**

find the equation of the tangent line to the graph of y= f(x) = ln (x)/x at the point (1,0)
*May 1, 2013 by Emma*

**Calculus**

Find an equation of the tangent line to the graph of y = e-x2 at the point (2, 1/e4).
*July 11, 2013 by Anonymous*

**Calculus **

Let f(x) = x ^3. The equation of the tangent line to f(x) at x = 5 is y=75x - 250 What is the approximation for 4.6 ^3?
*August 5, 2013 by Anonymous*

**Math**

Find an equation of the tangent line to the circle x^2+y^2=25 at the point (4,-3)
*August 20, 2013 by Sarah*

**AP CALC**

find an equation of the tangent line to the graph of x^4-2y^2=1 at the point (2,4)
*December 17, 2013 by Anon*

**calculus**

Find the equation of the tangent line to the ellipse x 2 + 4y 2 = 25 when x = 3 and y < 0. Answer 3x - 8y = 7 3x - 8y = 25 3x + 8y = 7 3x + 8y = 25
*February 23, 2014 by shira*

**Urgent Calculus Help 2**

Find the equation of the tangent line to the graph of f(x) = 6x ln(x + 4) at x = 2.
*July 9, 2014 by Anonymous*

**Calculus**

Find the equation of the tangent line to f(x)=sec x - 2 cos x at (pi/3, 1).
*August 30, 2015 by Anonymous*

**Calculus 1**

Find the equation of the tangent line to the curve y = (9 ln x)/x at the points (1, 0) and (e, 9/e).
*October 2, 2015 by TayB*

**Calculus - Damon**

Find the line which passes through the point (0, 1/4) and is tangent to the curve y=x^3 at some point. So I found the derivative which is 3x^2. Let (a, a3) be the point of tangency. 3x^2 = (a3 - 1/4)/(a-0) I'm not sure how to solve for a. Yes, the point is (0,1/4) but it's not...
*November 5, 2008 by Samantha*

**calculus**

Find all points on the curve x^2y^2+xy=2 where the slope of tangent line is -1. This is what I got. x^2y^2+xy=2 x^2*2ydy/dx + 2x*y^2 + x*dy/dx + y =0 dy/dx(2yx^2+x)= -2xy^2-y dy/dx = (-2xy^2-y)/(x+2yx^2) how do I finish from here? I need to know where the slop of the tangent ...
*April 2, 2009 by Riley*

**calculus**

Find the tangent line to the curve xy3+2y−2x=1 through the point (x,y)=(1,1). (Enter ∗ for multiplication: type 2*x for 2x. Enter / for division: type 1/2 for 12.) Tangent Line y=
*August 12, 2015 by JuanPro*

**calc**

standard equations of circles that have centers on line 5x-2y=-21 and are tangent to both axis. Any ideas?? First express the line as in point slope form y=(5/2)x - 21/2 The center must be on the line, so it is a point expressed as (x,(5/2)x - 21/2) In order for the circle to ...
*September 26, 2006 by Melba*

**Vectors**

3 planes; $: x+2y-2z-6=0 %: 2x-y+z+8=0 £: 2x-y+2z+3=0 (a)(i)Find the cartesian equation for the plane @ parallel to $ and containing the point (1,1,2) (ii)Calculate the distance between $ and @ (b)(i)Find the parametric equations for the line of intersection of the planes $ ...
*April 25, 2010 by Anonymous*

**vectors**

3 planes; $: x+2y-2z-6=0 %: 2x-y+z+8=0 £: 2x-y+2z+3=0 (a)(i)Find the cartesian equation for the plane @ parallel to $ and containing the point (1,1,2) (ii)Calculate the distance between $ and @ (b)(i)Find the parametric equations for the line of intersection of the planes $ ...
*April 25, 2010 by Anonymous*

**Calculus - Functions?**

#1. A cubic polynomial function f is defined by f(x) = 4x^3 +ax^2 + bx + k where a, b and k are constants. The function f has a local minimum at x = -1, and the graph of f has a point of inflection at x= -2 a.) Find the values of a and b #2. Let h be a function defined for all...
*February 21, 2011 by Amy*

**calculus**

Consider the function y=x/(x+1) a) Find dy/dx b) Find the equation of the line tangent to the curve at x=-2 c) Find the equation of the line normal to the curve at x=1
*October 15, 2011 by Eric*

**Calculus 1**

The curve with the equation y^2=5x^4-x^2 is called a kampyle of Eudoxus. Find an equation of the tangent line to this curve at the point (-1,2).
*September 29, 2015 by TayB*

**Math**

Help please... some diff equation prbolems... 1.) Transform 2xdy - y(x+1)dx + 6y^3dx = 0 into a Bernoulli Equation. 2.) The equation of the tangent line of the one-family of curve x^2 + y^2 = 25 at P(4, 3) is_______ 3.) The complete solution of 2x^3 dy = y (y^2 + 3x^2) ...
*December 14, 2009 by Therese*

**Calculus**

Use linear approximation, i.e. the tangent line, to approximate (the 3 is inside the v part if you know what I mean, it's not 3 times sqrt) 3√125.2 as follows: Let f(x) = 3√x. The equation of the tangent line to f(x) at x=125 can be written in the form y=mx+b where...
*September 28, 2009 by Z32*

**calculus**

Find an equation of the tangent line to the curve at the given point. y = 3x^2 - x^3, (1,2)
*October 14, 2008 by Frank*