Friday

April 18, 2014

April 18, 2014

Number of results: 70,539

**Algebra 2**

I searched Google under the key words "permutations vs. combinations" to get these possible sources: Combinations and Permutations www.mathsisfun.com/combinatorics/combinations-permutations.htmlCombinations and Permutations. What's the Difference? In English we use the word "...
*Friday, August 10, 2012 at 12:33am by PsyDAG*

**Business Algebra**

Permutations and Combinations have many real-world applications such as determining the number of ways of being dealt a particular poker hand from a deck of cards at your weekend poker game; or creating the batting order for the baseball team that you manage. Other areas that ...
*Wednesday, June 10, 2009 at 10:18pm by Redbone*

**Math**

There are 6 ways to fill first, then 5 ways to fill second, and 4 ways to hand out third prize. So there are 6*5*4 or 120 ways, as Jordan said. Except Jordan meant to say 120 different permutations and not combinations. Permutations imply positioning, while combinations do not.
*Sunday, August 23, 2009 at 7:33pm by Reiny*

**algebra 2 (permutations & combinations)**

what is C(52,5) ?
*Wednesday, April 10, 2013 at 8:47pm by Reiny*

**Math: Permutations and Combinations**

Need a verification: Combinations of n items taken r at a time: C9n,r)= n!/(n-r)!*r! C(8,0) 8!/(8-0)!*(0)! = 8!/8!*0! = 0 or Answer is 0 or 1?
*Friday, August 28, 2009 at 3:57pm by Dee*

**MATH ELE.**

Check this helpful site. http://www.mathsisfun.com/combinatorics/combinations-permutations.html
*Tuesday, August 11, 2009 at 2:03pm by Ms. Sue*

**Math**

Find the probability that if the letters of the word "parallel" are randomly arranged that the L's will not be together. In class, I'm studying permutations and combinations. The solutions stated the no. of permutations where 3 L's are together is 6!/2!. Could you please ...
*Thursday, October 11, 2012 at 5:47am by Candice*

**Math**

http://www.mathsisfun.com/combinatorics/combinations-permutations.html
*Tuesday, November 10, 2009 at 10:44am by Ms. Sue*

**algebra ll**

permutations of 4 of ten (if the order of the 4 on the sheet matters) n!/(n-r)! = 10!/6! =10*9*8*7 = 5040 Now if all you care about is the different groups of 4 and not what order on the sheet, you want the combinations of 4 of ten n!/[r!(n-r)!] = permutations/r! =5040 /4*3*2...
*Sunday, October 26, 2008 at 8:36pm by Damon*

**Finite Math**

Please help with this problem. In a student writing contest with 25 entries, 3 essays are selected for first, second, and third place awards and 5 are selected for honorable mention. How many ways can this be done? Thanks. Ok Gen, for the first place there are 25 choices, for ...
*Tuesday, July 25, 2006 at 1:08pm by Gen*

**Math**

For the three-letter set {R, S, T}, find the two-letter combinations. I realize that this deals with combinations and not permutations. I just do not understand how they want this done.
*Saturday, May 8, 2010 at 12:02am by BWB*

**math**

If you really mean "combinations" then Dr WLS has it right. If there is no matter the order (combinations) then there is only one combination but I suspect you mean permutations.
*Sunday, November 30, 2008 at 8:06pm by Damon*

**algebra 2 (permutations & combinations)**

from a standard deck of 52 cards, how many different five-card hands can be drawn?
*Wednesday, April 10, 2013 at 8:47pm by grace*

**Algebra Grade 7**

I am trying to think how I would have done this in grade 7. I assume you have not had permutations, combinations and factorials. make a table of combinations first person shakes hands with 9 --> 9 projects second with 8 --> 8 more third with 7 --> 7 more etc 9+8+7+6+5...
*Thursday, October 18, 2012 at 3:36am by Damon*

**Math**

We are working on permutations and combinations and the problem reads as follows: A deli offers its cheese sandwich with various combinations of mayonnaise, lettuce, tomatoes, pickles, and sprouts. 5 types of cheese are available. How many different cheese sandwiches are ...
*Friday, February 12, 2010 at 7:31am by nicole*

**Math**

say we have 8 bands numbered 1 through 8 chance that band 1 is top = 1/8 then chance that band 2 is second = 1/7 then chance that band 3 is third = 1/6 etc so I claim 8! ways (big number, you compute :) Now how many permutations of 8 taken 3 at a time (permutations not ...
*Friday, July 29, 2011 at 6:32pm by Damon*

**college**

it has to do with choosing, and combinations/permutations though.
*Tuesday, September 21, 2010 at 8:12pm by finite*

**math**

if order matters, it's permutations if not, then it's combinations
*Tuesday, September 18, 2012 at 10:53am by Steve*

**Math**

Use either permutations or combinations
*Sunday, April 7, 2013 at 5:24pm by Shaniqua*

**math**

use permutations and combinations on these types of problems.
*Friday, February 24, 2012 at 6:57pm by L.Bianchessi*

**Combinations and Permutations, Steve and Ms. Sue☺**

i mean 8 not a
*Wednesday, April 10, 2013 at 5:44pm by steven*

**Combinations and Permutations, Steve and Ms. Sue☺**

1. C 2. B 3. D 4. B 5. D 6. B 7. B 8. B
*Wednesday, April 10, 2013 at 5:44pm by Slim Shady*

**math**

http://www.google.com/search?client=safari&rls=en&q=Combinations+permutations&ie=UTF-8&oe=UTF-8
*Thursday, May 17, 2012 at 2:57pm by PsyDAG*

**math ,correction**

Is this correct? consider determining how many possible phone numbers are in an area code (repeated numbers allowed) Is this a combination, a permutation, or neither? I think it would be a combination wouldn't it? Since there are ten number possibilities in each of the three ...
*Friday, July 13, 2007 at 7:47pm by student*

**Combinations and Permutations, Steve and Ms. Sue☺**

Are they right? Please help
*Wednesday, April 10, 2013 at 5:44pm by Jman*

**Math: Permutations and Combinations**

The formula is correct, noting the parentheses, i.e. C(n,r) = n!/((n-r)!r!) Since 0!=1, the expression 8!/((8-0)!*(0)!) = 1
*Friday, August 28, 2009 at 3:57pm by MathMate*

**Combinations and Permutations, Steve and Ms. Sue☺**

#8. the answer is 6,840 yourwelcome.
*Wednesday, April 10, 2013 at 5:44pm by Sam*

**Combinations and Permutations, Steve and Ms. Sue☺**

#8. the answer is 6,840 yourwelcome.
*Wednesday, April 10, 2013 at 5:44pm by Sam*

**Combinations and Permutations, Steve and Ms. Sue☺**

the answer for number 2- is b and a b 1140
*Wednesday, April 10, 2013 at 5:44pm by steven*

**Algebra II-Please help!!**

permutations: That means all the arrangements of three made from the 12 when order is important. For example ABC and ACB and BAC and BCA aand CAB and CBA are all different. The formula for that is n!/[n-r]! here n = 12 and r = 3 so we have 12!/9! which is 12*11*10 = 132 That ...
*Monday, April 4, 2011 at 5:29pm by Damon*

**algebra**

start with no flavour (which does not apply here), each time we add a flavour, we double the number of flavours. So there are 2^7 flavour combinations for 7 flavours, including the no flavour at all "combination". So there are 2^7-1 flavour combinations in total. For example: ...
*Sunday, May 22, 2011 at 2:21pm by MathMate*

**college math**

Explain permutations and combinations and the differences between the two. Use examples to illustrate.
*Friday, December 7, 2007 at 8:48pm by Rose*

**math**

Misty - AEB is the same combination as ABE Combinations pay no attention to order, permutations do.
*Monday, January 21, 2008 at 5:41pm by Damon*

**Math**

Just different heights? Or are orders of stacking important? We do not have a clear indication of what "this stack of boxes" is. Review your information on combinations and permutations.
*Tuesday, December 8, 2009 at 10:53am by PsyDAG*

**college math**

6 ways to put an entry in space 1 times 5 ways to put an entry in space 2 times 4 ways to put an entry in space 3 times 3 4 2 5 1 6 looks like 6! = 720 How many permutations of 6 taken 3 at a time? (They are permutations not combinations, because the order in the group of ...
*Wednesday, December 12, 2007 at 9:24pm by Damon*

**permutations and combinations**

Four men and four women are to be seated alternatively at a round table. In how many ways can this be done?
*Monday, January 2, 2006 at 6:28am by bb*

**Permutations/Combinations**

In how many ways can 5 men and 5 women be seated at a round table if two men must not sit together?
*Sunday, February 27, 2011 at 7:50am by Newbie*

**math**

By the way the permutations of n items taken r at a time is n!/(n-r)! and if it does not matter how the r items are arranged in each sub group, then it is the number of "combinations" n! / [ r! (n-r)! ]
*Saturday, August 25, 2012 at 7:53pm by Damon*

**algebra**

Assuming order matters, i.e. A,B,C,D is counted differently as B,A,C,D. There are 9 choices for the first place, 8 places for the second, 7 places for the third, and 6 places for the fourth. Applying the multiplication rule, there are 9*8*7*6 ways, or P(9,4) [permutations] =9...
*Friday, June 22, 2012 at 2:20pm by MathMate*

**college math**

since order does not matter here, we are dealing with combinations rather than permutations. No. of outfits C(3,1)xC(6,1)xC(14,7) = 3x6x3432 = 61776
*Saturday, February 21, 2009 at 10:46pm by Reiny*

**data management**

I am not doing the problem for you but perhaps I can give you an idea. Let's see. I have to work with M M M A A L S If all letters were different the answer would be 7!, but they are not. Let me try a simpler example Say A A B B A B A B A B B A B A A B B B A A B A B A Hmm six ...
*Saturday, January 19, 2008 at 10:59pm by Damon*

**statistics permutations and combinations**

Selecting a committee: There are 7 women and 5 men in a department. How many ways can a committee of 4 be selected if there must be at least 2 women?
*Tuesday, November 15, 2011 at 4:52pm by Celee *

**math**

There are 2^3 = 8 possibilities (permutations) if the order of appearance is important. HHH HHT HTH HTT TTT THT TTH TTT There are 4 combinations (0,1,2 or 3 tails) The probability of TTT is 1/8
*Sunday, January 15, 2012 at 11:31am by drwls*

**Math: unting and permutations**

oops, meant "counting" and permutations
*Saturday, October 25, 2008 at 1:02pm by courtney's dad*

**math permutations**

how many distinguishable permutations are there of the letters in the word effective
*Monday, January 28, 2013 at 10:52pm by mary*

**MATH PLEASEEEEE**

U N U S U A L This would be permutations of 7 objects except that we have three identical Us. so permutations of 7 objects = 7! but we have embedded in there the permutations of three objects 3! so I get 7!/3! = 7*6*5*4
*Sunday, January 18, 2009 at 6:03pm by Damon*

**alg2/trig**

Permutations: 5! Permutations with beginning consonants: 3*4!
*Wednesday, April 1, 2009 at 7:58pm by bobpursley*

**Maths**

Wow, this goes back quite some time. by definition C(n,r) = n!/(r!(n-r)!) , so C(7,3) = 7!/(3!4!) = 35 , and C(7,4) = 7!/(4!3!) Most scientific calculators contain the functions C(n,r) and P(n,r) they are probably written as nCr and nPr Here is a page that explains the ...
*Thursday, August 27, 2009 at 6:34am by Reiny*

**Statistics**

Perhaps something here will help you? http://www.google.com/search?hl=en&client=firefox-a&rls=org.mozilla:en-US:official&hs=qy7&ei=T0VOSvDIFYnENrLQge4D&sa=X&oi=spell&resnum=0&ct=result&cd=1&q=counting+combinations/permutations&spell=1 Sra
*Friday, July 3, 2009 at 1:12pm by SraJMcGin*

**Math**

Create two different situations: one in which you use combinations and one in which you use permutations. Include specific details and an explanation about what makes each situation either a combination or permutation.
*Tuesday, April 16, 2013 at 3:32pm by Katie*

**Pre-Algebra [Combinations]**

Nevermind I got all the answers: 1. 35 groups 2. 364 combinations 3. 319,600 choices -MC
*Thursday, June 25, 2009 at 6:05pm by mysterychicken*

**Statistics**

Have you learned the difference between permutations and combinations? in combinations the order does not matter. (if I hold 5 cards in my hand, the order in which they were dealt to me does not matter) C(13,5) means .. how many groups of 5 can I form from 13 It is short form ...
*Tuesday, April 6, 2010 at 10:02pm by Reiny*

**MATH probability **

Combination of 5 = 1,4 - 4,1 - 3,2 or 2,3 Less than seven includes combinations that = 1, 2, 3, 4, 5 or 6. Calculate the latter combinations and divide the number of those combinations into the former.
*Tuesday, March 1, 2011 at 5:11pm by PsyDAG*

**math**

Combinations of how many numbers? Don't you mean permutations? If 1,2,3,4 and 5 are your only five numbers and you must pick five, and if the order does not matter, then there is only one combination.
*Sunday, November 30, 2008 at 8:06pm by drwls*

**Math**

Teng is designing a house and in each room he can choose from tiles, floorboards, or carpet for the floor. a. How many combinations of flooring materials are possible if her designs a 2 room studio? b. How many combinations are possible for a 3 room apartment? c. How many ...
*Sunday, December 8, 2013 at 5:48pm by Michelle *

**Algebra 2**

Solve using linear combinations. x - 5y = 6 3x + 4y = 18 What are linear combinations?
*Monday, October 3, 2011 at 12:30am by Peter*

**Combinations and Permutations, Steve and Ms. Sue☺**

#4. I would consider choosing 5 players from the team to go to a fundraiser a combination. #6 --- 4 books can be arranged in 4x3x2x1 or 24 ways #8 ---- choosing 3 from 20 is C(20,3) = 1140 (you did not answer that one) the rest are correct
*Wednesday, April 10, 2013 at 5:44pm by Reiny*

**Statistics**

3 students will represent your school at a conference at the state capital. A drawing will be held to select the 3 representatives from a group of 5 finalsts. If you and your friend are both finalists, what are the chances that both of your names will be drawn? Is it 2 out of ...
*Wednesday, March 28, 2007 at 10:23am by Tony*

**Chemistry**

Sorry for posting this again, I dont know if the question was skipped or not, but I was just wondering if I could get some help on this... thanks. There are 3 known isotopes of Hydrogen and 3 stable isotopes of oxygen. How many types of water molecules would these produce? ...
*Saturday, April 21, 2007 at 5:06pm by Jessica*

**Data Management**

In that case, for PLANETS, the possible four-letter combinations (in any order) are 5 x 4 = 20. For each combination, there are 4! = 24 ways (permutations) for arranging the letters. That makes 20x24 = 480 possible "words". Most will not be in the dctionary. Try your own ...
*Friday, January 18, 2008 at 9:47pm by drwls*

**math**

First lets look at the number of combinations (order won't matter) to go the 10 steps Behind it I will then do the number of permutations 2 2 2 2 2 ---- 1 2 2 2 2 1 1 --- 6!/(4!2!) = 15 2 2 2 1 1 1 1 --- 7!/(3!4!) = 35 2 2 1 1 1 1 1 1 --- 8!/(2!6!) = 28 2 1 1 1 1 1 1 1 1 --- 9...
*Monday, June 7, 2010 at 8:40pm by Reiny*

**college math**

Permutations We designate the permutations of n things taken n at a time as nPn and the permutations of n things taken r at a time as nPr where P stands for permutations, n stands for the number of things involved, and r is less than n. To find the number of permutations of n ...
*Friday, December 7, 2007 at 8:48pm by tchrwill*

**Algebra**

Here is a popular web site about combinations and permutations. I suggest you review it, and use it for question 4) http://mathforum.org/dr.math/faq/faq.comb.perm.html
*Thursday, February 7, 2008 at 2:01am by drwls*

**Math**

In a mathematics olympiad there are 20 finalists. In how many ways can three equal prizes be awarded, assuming that two prizes cannot be given to one finalist? In how many ways can a first, second and a third place be awarded? (I understand that Permutations and Combinations ...
*Monday, January 17, 2011 at 7:41am by Jen*

**Data Management**

List all permutations of the elements of the set {+, -, *) List all subsets (combinations) of the elements of the set {+, -, *)
*Wednesday, December 20, 2006 at 8:21pm by Raj*

**Math**

3-letter permutations: = 2x26x26 = 1352 4-letter permutations: = 2x26x26x26 = 35152 total = 36504 If not repetition allowed 3-calls = 2x25x24 = 4 letters = 2x25x24x23 = total = ..
*Friday, March 29, 2013 at 5:10pm by Reiny*

**math**

Compute: The number of combinations of 8 elements taken 3 at a time. The number of permutations of 8 elements taken 3 at at time.
*Thursday, May 17, 2012 at 2:57pm by Hannah*

**Math**

If you count the dice as unique, there are 6^3 = 216 possible outcomes There are 42 where the sum is at most 6. p(sum <= 6) = 42/216 = 7/36 1 1 1 1 1 2 1 1 3 1 1 4 and permutations: 24 1 2 2 1 2 3 and permutations: 12 2 2 2 and permutations: 6 If the dice are ...
*Tuesday, September 11, 2012 at 11:44pm by Steve*

**permutations with identical items.**

There are 7 letters, so there are 7! ways to arrange them. But, the two t's and 3 a's are indistinguishable. Since there are 2! ways to arrange the 2 t's, we divide by 2! to get the number of unique permutations. Similarly for the 3 a's. So, the final count is 7!/(2!3!) = 120 ...
*Thursday, January 23, 2014 at 11:56am by Steve*

**Pre-Algebra [Permutations]**

1. correct. 2. 6*5*4*3*2*1=6!=you do it.
*Thursday, June 25, 2009 at 3:05pm by bobpursley*

**Pre-Algebra [Permutations]**

123
*Thursday, June 25, 2009 at 3:05pm by Anonymous*

**Pre-Algebra [Permutations]**

Thought so, thanks! -MC
*Thursday, June 25, 2009 at 3:05pm by mysterychicken*

**ALGEBRA**

how many permutations are there of the following word. mathematics
*Wednesday, November 16, 2011 at 10:42pm by MONICA*

**Algebra**

It's been so long since I've donw combinations, and now I have a question about them in my algebra homework packet. Question is....Marcie has a collection of 9 DVDS. She will choose 4 of them to take in the car to watch during a long trip. How many combinations of 3 DVDS can ...
*Friday, June 12, 2009 at 10:30pm by Tiff*

**algebra**

Permutations of 9 objects taken 5 at a time = 9!/(9-5)! where 4! = 4x3x2x1 and 9! = 9x8x7x6x5x4x3x2x1
*Wednesday, March 10, 2010 at 6:31pm by FredR*

**College Math**

I would start with the number of ways of selecting three people with no restrictions, which is 13!/(3!*10!)= 286 and subtract the number of possible combinations that do not meet the requirements. For example, the number of combinations with no blacks (with only 5 nonblacks to...
*Tuesday, February 24, 2009 at 7:08pm by drwls*

**college**

Your asking for how many combinations and not the probability so ignore the answer above. First find the number of combinations if all letters and numbers can be repeated (26*26*10*10*10*10)=6760000 Then find the number of combinations if none were repeated (26*25*10*9*8*7)=...
*Friday, July 30, 2010 at 9:35pm by Ashlee*

**math**

First of all, C(14,4) is not 1001. The only combinations possibilties are: PPP (3 pencils) PPF (2 pencils and 1 felt-tip) PPB (2 pencils and 1 ballpoint, etc) BBB BBP BBF FFP FFB (the least likely result) PBF Different permutations of the same group of three don't count as ...
*Sunday, February 22, 2009 at 1:21am by drwls*

**algebra**

A pack of Jillybeans contains seven different flavors: Apricot, Banana, Coconut, Date, Eggplant, Fig and Grape. You can make each flavor indivdually or come up with some crazy combinations. How many flavor combinations are possible with these seven flavors alone or mixed?
*Sunday, May 22, 2011 at 2:21pm by Matt *

**Math (please help me Steve)**

Here's a lower bound solution. You may want to investigate other possibilities. The number 7 can be partitioned into 3 ascending non-negative integers in 8 ways, namely: 007# 016 025 034 115# 124 133# 233# There are 3 permutations of partitions (indicated #) with non-distinct ...
*Monday, July 8, 2013 at 6:58pm by MathMate*

**alg2/trig**

I got this question wrong on my test, and I have to correct it :/ How many permutations are there of all the letters in the word "TEXAS" ? The answer to this part is 120, but I have no idea on how to solve the second part without having to write it all down. *How many of these...
*Wednesday, April 1, 2009 at 7:58pm by Chris*

**science**

There are 64 possible codon permutations since there are three nucleotides of 4 four possible values (4^3 = 64). That includes duplicates (codons that code for the same amino acid) and unused codons as well. There are fewer effective codon permutations.
*Wednesday, March 18, 2009 at 12:38am by Sean*

**Geometry**

We put all possible combinations of p and q true and false in the table - there are 4 combinations. p q ~p^q 0 0 0 1 1 0 1 1
*Wednesday, January 27, 2010 at 11:41pm by Jamie*

**math**

There are 36 possible combinations for two dice. These are the combinations that total 5: 1,4 4,1 2,3 3,2 Take if from here.
*Thursday, July 7, 2011 at 6:34pm by PsyDAG*

**math**

How many different combinations of coins can total exactly $0.40? I got 31 possible combinations
*Monday, November 15, 2010 at 9:42pm by Jamie*

**Math**

We would like to test 3 different treatments on a particular type of plant. A worker at the local greenhouse will allow us to use 3 amoung 10 plants. *Note: Each treatment will be used on one and only one plant.* a) In how many different ways can we assign the plants to the ...
*Wednesday, September 27, 2006 at 12:02am by Lindz*

**Statistics**

A raffle is being conducted with 50 tickets to be sold - one per customer. There are three prizes to be awarded. If the four organizers of the raffle each buy one ticket, what is the probability that the four organizers win: a) all of the prizes? b) exactly two of the prizes c...
*Friday, July 3, 2009 at 1:12pm by Sean*

**math**

4 C 2 = combination of 4, taken 2 at a time C(4,2) = (4!/(4 - 2)!)/2! = 4!/(2!2!) C(4,2) = (4x3x2x1)/(2x1x2x1)= 24/4 = 6 total of 6 combinations 1 out of 6 possible combinations I am not a tutor
*Monday, January 17, 2011 at 2:48pm by helper*

**algebra 1**

h(3) = -9.8(9) + 30(3) + 1.5 = 3.3 I don't have the foggiest clue how you came up with -195.8 I tried different permutations of the arithmetic, but no luck.
*Friday, February 15, 2013 at 10:44am by Reiny*

**math213**

If the order does matter than the number of permutations is 12*11*10*9*8*7*6= P(12,7) = 3991680 if the order does not matter (combinations) it would be 12!/(7!5!) = C(12,7) = 792 both P(n,r) and C(n,r) can be found on a standard scientific calculator usually they are labeled ...
*Thursday, October 29, 2009 at 8:27pm by Reiny*

**statistics permutations and combinations**

3 cases : 2 women, 2 men ---> C(7,2)xC(5,2) = 21(10) = 210 3 women, 1 man ---> C(7,3)xC(5,1) = 35(5) = 175 4 women, 0 men ---> C(7,4) = 35 add up the 4 cases to get 420 or, exclude the case of no women, and one woman C(12,4) - C(7,1)xC(5,3) - C(7,0)x(C5,4) = 495 - 70...
*Tuesday, November 15, 2011 at 4:52pm by Reiny*

**Permutations/Combinations**

http://www.jiskha.com/display.cgi?id=1298802306
*Sunday, February 27, 2011 at 7:50am by Damon*

**Algebra**

I am doing the amount of permutations in the word trigonometry. For the expression, I wrote 12!/2!2!2!. I got 968003200. Is this correct? If not, should I use parenthesese? Thanks
*Friday, January 30, 2009 at 8:22pm by Caleb*

**math**

The standard answer is 2*3*8=48 different combinations,assuming that customers always take one cheese and one topping, and of course, one crust. The practical answer to the question would, however, take into account that customer can take 0 to 3 cheeses, 0 to 8 toppings, but ...
*Tuesday, May 17, 2011 at 1:50pm by MathMate*

**math2**

Mary is moving and wants photos to remember her six friends. If pictures are taken so there is a shot of every possible pair of friends- including Mary, how many pictures will be take? Would one roll of 24 exposures be enough? 27 Mary is moving and wants photos to remember her...
*Wednesday, January 24, 2007 at 6:42pm by Preston*

**Algebra Please help**

A pack of Jellybeans contains 7 different flavors: Apricot, Banana, Coconut, Date, Eggplant, Fig, and Grape. You can Eat each flavor individually or come up with some crazy combinations. How many flavor combinations are possible with these 7 flavors alone or mixed? You can use...
*Wednesday, November 9, 2011 at 7:28pm by Linda*

**algebra**

i need explanation how they solved this one the answer is provided: finding the number o fdistinguishable permutations. (15!)/(4!3!612!) = 6, 306,300
*Monday, August 11, 2008 at 5:40pm by student*

**math question**

I have the equation 3f+2.50h=240 and I want to make a table of values with at least five possible combinations. How do I determine which combinations I should use?
*Sunday, June 1, 2008 at 4:46pm by Calie*

**Algebra word problem**

A pack of Jellybeans contains 7 different flavors: Apricot, Banana, Coconut, Date, Eggplant, Fig, and Grape. You can Eat each flavor individually or come up with some crazy combinations. How many flavor combinations are possible with these 7 flavors alone or mixed? You can use...
*Tuesday, November 8, 2011 at 7:28pm by Linda*

**Algebra word problem**

A pack of Jellybeans contains 7 different flavors: Apricot, Banana, Coconut, Date, Eggplant, Fig, and Grape. You can Eat each flavor individually or come up with some crazy combinations. How many flavor combinations are possible with these 7 flavors alone or mixed? You can use...
*Tuesday, December 6, 2011 at 3:07pm by Linda*

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