Search: algebra: logs

Number of results: 62,330

Math
Logs are stacked up in apile as shown in the figure. The top row has 15 logs and the bottom row has 21 logs. How many logs are in the stack? a1= 1+14=15 an= 7+14=21 s1=(n/2)(a1+an) (n/2)(15+21) = 18 How do I figure out the n?
Tuesday, May 4, 2010 at 4:37pm by Abbey(Please help)

Algebra 2 ..
256^2 = (4^4)^2 = 4^8 so, you are correct. But, you can't be smart IF YOU SHOUT IN CAPS!! log 45^x = x log45, so you are correct again. log 12^(x+1) = (x+1) log 12/log 6, so you are right again. Don't know whether you're smart, but you seem to understand logs. ...
Friday, February 22, 2013 at 10:19pm by Steve

Logs-Algebra
How do you graph the following logs? f(x)=log5 (x-2) f(x)=log5 x-2 f(x)= log5 x f(x)=log5 (x+2)
Tuesday, October 23, 2007 at 11:11pm by Jayme

Nautical/Maths
By the way, in the old days like when I went sailboat racing, we had to use logs of trig functions to do these products by adding and subtracting logs because we did not have calculators. This was a total mess and resulted in complicated things like using half the angles so ...
Friday, January 4, 2008 at 3:49am by Damon

math - natural logs
Find the EXACT solution to e^(1-x) = 4^x You must use logs, not just a calculator.
Monday, October 31, 2011 at 10:10pm by BJ

Math: Calculus
changing the base of a log: Alg II http://www.sosmath.com/algebra/logs/log4/log43/log43.html
Monday, October 17, 2011 at 7:37pm by bobpursley

Precalculus
.5=e^(-20t) I am assuming this involves logs but we did't really learn logs. Anyone care to walk me thru with a calculator. Have the Ti-83
Thursday, March 13, 2008 at 7:08pm by Trevor

precalculus
start by collecting logs: log5 (x+3) + log5(x-1) = 1 now recall that sum of logs is log of product log5 [(x+3)(x-1)] = 1 raise 5 to the power of both sides: (x+3)(x-1) = 5 x^2 + 2x - 3 = 5 x^2 + 2x - 8 = 0 (x+4)(x-2) = 0 x = 2 or -4 Since logs of negative numbers do not exist...
Monday, January 9, 2012 at 11:07am by Steve

Math
Well I know that a product law of logs is log(a) + log(b) = log(ab) and the quotient law of logs is log(a)-log(b)=log(a/b) But how do I change those laws, or relate it to prove the law of exponents. I know what the law of exponents are, but I just need help proving it IN ...
Saturday, May 23, 2009 at 5:07pm by Jus

math
take the log base 5 of each side x-1=log5 9=log10 9 /( log10 5) http://www.sosmath.com/algebra/logs/log4/log43/log43.html
Sunday, October 5, 2008 at 5:12pm by bobpursley

College Algebra
The purpose of logs is that when multiplying, logs add. Thence the slide rule, and a mydrid of mechanical computing devices. The other use, is that many natural processes in nature are logarithimic in nature (population growth, interest, radioactiveity, in fact, anything whose...
Thursday, October 21, 2010 at 10:54am by bobpursley

another pre cal (logs)
according to your basic laws of logs your expression is log3 ((3x-6)(x^2 - 4)/81)
Monday, March 31, 2008 at 1:14am by Reiny

college algebra
log(a^b) = b log(a) log(ab) = log(a) + log(b) since 1/b = b^-1, log(a/b) = log(a) - log(b) since √a = a^(1/2), log √a = 1/2 log a log x^4y^7/4 = 4logx + 7logy - log4 so you should be able to do the other if these problems involve logs base 4, that doesn'...
Wednesday, April 17, 2013 at 4:36pm by Steve

chem
"Yule logs are simulated wood logs make of compressed paper that burn with a red and green flame.How would you produce a similar yule log?"
Wednesday, July 9, 2008 at 1:11am by jennifer

Pre Cal (logs)
I need help with these logs 1: Log underscore4 16X 2: 2 Ln ( X(sqr. root)e 3:5^[2logUnderscore5(3x)] 4:log underscore2 ^[1280-logunderscore2 5) I don't understand how to do them thanks
Sunday, March 30, 2008 at 11:25pm by Deb

math logs
solve 3^(2x+1) = 9^(2x-1) using base 3 logs
Saturday, November 12, 2011 at 9:03pm by Sejul

Algebra 2
logs?
Thursday, June 4, 2009 at 8:50am by Kay

algebra: logs
Log3x=4
Monday, December 10, 2012 at 11:26am by Ruth

algebra
solve e^x / 3 = 5^x using logs.
Saturday, December 3, 2011 at 6:12pm by Anil

Maths (Logs)
1.Write the following equation without logs log y = mx+ c This would be y = 10^(mx+c) right? 2. Explain why this fits the exponential model (in other words, it can be written in the form y = a x b^x where a and b are real numbers).
Monday, April 7, 2008 at 10:23pm by BP

misplaced modifier
Were you hunting behind a pile of logs? -- or Was the fire extinguisher behind a pile of logs? We can't tell from this sentence.
Saturday, September 24, 2011 at 4:32pm by Ms. Sue

college algebra
You are going to use 3 man rules of logs 1. log(A/B) = logA - logB 2. Log(AB) = logA + logB 3. log A^n = nlogA log 3√x + log x^4 - log x^3 = log 3 + log x^(1/2) + 4logx - 3logx = log3 + (1/2)logs + logx = log3 + (3/2)logx 2. 4 log (x+3) - 5 log (x^2+4) + 1/3 log y = ...
Wednesday, April 17, 2013 at 8:57am by Reiny

Algebra
domain is your choice of x's that you can use in your equation For logs, one of the main properties is that I can only take the log of a positive number so for y = 4 + lnx , the domain is x > 0 however, the result of taking such logs results in any real number, so ...
Sunday, April 7, 2013 at 10:17pm by Reiny

Alegbra (logs)
if logs are the same, the arguments are the same, so x-16 = 9x x = -2 But, log(x) is not defined for x<0, regardless of the base if you mean the entire exponents is 1+ln(7), then e^(1+ln(7)) = e^1 * e^ln(7) = 7e by definition, e^ln(n) = n
Monday, April 22, 2013 at 3:39pm by Steve

Algebra
express log (3x^5y^3/z^3) as the sum and difference of logs with no exponents.
Wednesday, December 8, 2010 at 6:23pm by peggy

precalculus
for the first you don't even need logs 3^(x^3)=9^x 3^(x^3)=(3^2)^x 3^(x^3) = 3^(2x) so x^3 = 2x x^3 - 2x = 0 x(x^2 - 2) = 0 x = 0 or x = ±√2 for second, take logs of both sides log(2^x) = log 10 xlog2 = 1 x = 1/log2 for the last 4^x = 2^x 2^(2x) = 2^x 2x...
Monday, December 1, 2008 at 3:50pm by Reiny

math
the base doesn't really matter. All logs follow the same rules. (a) log(x^2-9) - 9log(x) but your parentheses are not balanced, so that's a guess. Could also be 3(log(x^2-9) - 3log(x)) (b) log(5) + 4log(a) Now, it helps to know that we're using logs base a, since ...
Monday, April 8, 2013 at 12:25am by Steve

algebra
solve 2 = 1(1.079)^n you will have to know how to use logs. take the log of both sides.
Saturday, May 22, 2010 at 7:24pm by Reiny

Logarithums?
I don't see why you have to convert it; they are indeed the same thing. I want to draw a graph for this, but I can't :-) In general, you can use the rule that ln(1/x) = -ln(x), so you can simply declare that and be done. I'll try to show an equivalence so it might ...
Sunday, September 20, 2009 at 4:59am by jim

physics
The fraction (1/6) that remains after 70 years satisfies the relation: 1/6 = 2^(-t/T), where T is the half life and t = 70 years. Take logs of both sides to solve for T. I'll use logs to base e but it doesn't matter -1.7918 = -70/T ln 2 = -48.52/T T = 27.1 years
Wednesday, May 21, 2008 at 5:51am by drwls

Math
You will have to know the basic rules of logs log(A/B) = logA - logB comes into play here log6 7 - log6 x = 4 log6 (7/x) = 4 by definition of logs 6^4 = 7/x 1296 = 7/x x = 7/1296
Sunday, December 6, 2009 at 11:11am by Reiny

math
Mr Logan can saw 8 logs in 3 hours. How many logs can Mr Logan saw in one hour?
Wednesday, August 15, 2012 at 1:15pm by Andrea

College Algebra... HELP
we can take logs of only positive numbers, so - domain: x>0 - range: y is any real number - no asymptotes
Sunday, January 1, 2012 at 9:17pm by Reiny

algebra 2
find the points of intersection of the following algebraically y=2^x + 4^x y=2^x+1 - 4^x+1 I set them equal to each other but not sure if you use logs or what to solve it
Tuesday, August 10, 2010 at 10:10pm by jonathan

ALGEBRA
you know, you post problems involving logs and so on, so I cannot believe you can't solve the equation above. What is the difficulty? Show us what you have and where you get stuck.
Monday, April 16, 2012 at 10:43am by Steve

Math
The log button provides the logarithm (base 10) of any number punched into the calculator. (There is also an ln button on most calculators that provides the logarithm (base e) of any number punched into the calculator. There is probably a way of solving that equation without ...
Saturday, November 29, 2008 at 3:51pm by DrBob222

more pre cal logs
sorry I am so lost I missed the class that talked about logs since my sister was in the hospital giving birth to a still born baby.... now I am all lost... Expand the log Ln 3sqrootx^2y/x+3 (the 3 is part of the sqroot not infront like the 3rd power) I hope that makes since
Monday, March 31, 2008 at 1:52am by Deb

math
Take logs of both sides. I'll use logs to base 10, but it doesn't matter what base is used as long as it is consistent. log 14 = n log 1.4 n = log 14/log 1.4 = 1.14613/.14613 = 7.843
Tuesday, February 26, 2008 at 2:01am by drwls

algebra 2 logs and trig
no, of course not. did you mean this? 2log2 cscx= log4 cscx That is correct.
Friday, August 13, 2010 at 11:07am by bobpursley

algebra
remember we can only take logs of positive numbers, so ... 5x+1 > 0 x > -1/5
Monday, April 7, 2008 at 10:46am by Reiny

college algebra
i = .035/12 = .002916667 solve for n 8800 = 3100(1.002916667)^n use logs
Monday, July 25, 2011 at 6:42pm by Reiny

Algebra II
16 is supposed to be next to Log(16) but lower. This is for both the Logs in the equation.
Tuesday, May 18, 2010 at 4:05pm by Anonymous

algebra-Needed Quick
by definition, we can only take logs of positive numbers, so x-9 > 0 x > 9
Thursday, February 19, 2009 at 8:45am by Reiny

Math
n/2(26) = 18 26n = 36 n = 36/26 something very wrong with your equation, since n has to a whole number where does the 18 come from? you seem to be using the formula S(n) = n/2(first + last) so 18 would be the sum of the logs ???? that makes no sense, since the bottom row alone...
Tuesday, May 4, 2010 at 4:37pm by Reiny

Algebra 2
log2 + log(x^2) = log(2x^2) use whatever base of logs you choose; the laws remain the same.
Thursday, April 11, 2013 at 12:19am by Steve

Algebra
Add the logs of every term in the product. For the x^3 term, you get 3logx. You do the rest. Let us know if you want your answer checked
Tuesday, July 28, 2009 at 12:20am by drwls

math logs
3^(2x+1) = 3^2(2x-1) easy way 2x+1 = 4x-2 2z=3 x= 3/2 using logs base 3 2x+1 = (2x-1)log3(9) 2x+1 = (2x-1)log3(3^2) 2x+1 = (2x-1)(2) log3(3) 2x+1 = 2(2x-1) same as above
Saturday, November 12, 2011 at 9:03pm by Damon

math
Hmmm... it may require some knowledge of how some functions work. Take 1/x. You can plug any value into x and it will be defined unless x is 0. You cannot divide something by 0. 0 no matter how many times will not be equal to 1. Another common one is sqrt(x). It's no ...
Wednesday, April 2, 2008 at 8:19pm by Anonymous

Alg 2 (HS)
take logs of both sides (x+2) log 4 = log 160 x+2 = log160/log4 x = log160/log4 - 2 that is also log4160 - 2 but most calculators don't do logs to various bases, but do have log
Saturday, September 22, 2012 at 1:15am by Steve

college algebra
lots of folks just write log_2(x-2) the numbers are subscripts, not lower-case. 1. since we're dealing with logs base 2, just say log: 2log(x-2) + log2 = 3 log(x-2)^2 + log2 = 3 log(2(x-2)^2) = 3 2(x-2)^2 = 8 (x-2)^2 = 4 x = 0 or 4 I assumed that log(lower2)^2 meant log(...
Friday, November 30, 2012 at 2:57pm by Steve

more pre cal logs
In your text or in your notes you should find 3 main rules for logs. 1. log(AB) = logA + logB 2. log (A/B) = logA - logB 3. log (A^n) = nlogA use them in this question. You did not use brackets to establish the correct order of operations here, so I will let you finish it. You...
Monday, March 31, 2008 at 1:52am by Reiny

College Algebra
All you have to do is compute the logs to base 10 of 4.63x10^-9 and 9.32x10^-4 , and add a minus sign. For seawater, the answer is 8.33, which is 9.00 - log 4.63
Monday, December 8, 2008 at 1:54am by drwls

CALC
Now on this one I am not sure what you mean. log base 2 (x) or log (2x) I will assume base 2 then log x + log (4-x) = 0 where logs are base 2 adding logs is multiplying log (x(4-x)) = 0 x(4-x) = 2^0 which is one 4x - x^2 = 1 x^2 -4x +1 = 0 solve for x
Wednesday, July 22, 2009 at 4:59pm by Damon

Algebra
Solve the equation. 2log3 y = log3 4+ log3 (y+8) Here's what ive got take out the logs and say y^2= 4+ y +8 which simplifies to (y^2)-y=12 how do i simplfy the y?
Saturday, April 30, 2011 at 11:08pm by Kenya

chemistry
help required in calculating the pH value of a .84 mols per litre solution of sulfuric acid. I understand that pH = -log 10 (2x 0.84), I am not very experienced with logs and need assistance as to which keys to press on the scientific calculator in relation to the logs. thank ...
Tuesday, March 6, 2007 at 5:45am by ruby

College algebra
Use the properties of logs to write the expression as one log: 8log(base 5)4th square root of x minus 4log(base 5) x
Sunday, May 12, 2013 at 4:18pm by Taylor

MATH 1111
College Algebra help with logarithms! Ln (x-4) - Ln (x+1) = 16 How do I take natural logs?? it's a study guide question for our final exams
Thursday, April 30, 2009 at 4:48pm by Sammy

advanced algebra
when you add logs of the same base, you are multiplying like log A + log B = log (A*B) so we have really 3^log9(8) -------------------------- ONE WAY --If you know log rules logb(M) = logc(M)/logc(b) so log9(8) = log3(8)/log3(9) but log3 (9) = log3 (3)^2 = 2*1 = 2 so log9(8...
Sunday, February 24, 2008 at 6:04pm by Damon

Science
Which of the following materials will burn the fastest in open air? A. a log, two feet in diameter B. two logs, each one foot in diameter C. a pile of small splinters made from a two-foot diameter log D. Both logs and the splinters will burn at the same rate.
Monday, March 12, 2012 at 4:47pm by Samantha

Calculus
I see y = (2x+1)(x-2)^.5 / [(x-3)^(2/3)] There are many ways to do this to find dy/dx one is to use the quotient rule and just slug it out. If you know logs, there is a nice way: using the rules of logs we get ln y = (1/2)ln(x-2) + ln(2x+1) - (2/3)ln(x-3) then (dy/dx) / y = 1...
Thursday, November 8, 2007 at 6:33pm by Reiny

algebra
ln x - ln 5 = 7 ln(x/5) = 7 , by rules of logs x/5 = e^7 , by definition of ln x = 5e^7 = appr 5483.2 I can't make out the second one
Sunday, October 28, 2012 at 3:48pm by Reiny

Pre calculus
Usually you take logs to the base of the number having exponents. In your example, you have e^(3x-7), so take logs base e. If you had written 2^(x+3) * 2^(x-7) = 32 then you'd take logs base 2. As for graphing, just recall the all exponent/log graphs look the same, except ...
Tuesday, November 20, 2012 at 10:48am by Steve

algebra
(1/2)^(T/2.52*10^5) = 0.988 T is the time, in years, since it was 100% U-234. Solve for T. Use of logs is recommended. T = 4390 years That rounds off to 4000 years.
Wednesday, July 27, 2011 at 10:13am by drwls

Algebra 1
2. log3(x - 1) = log3(4). If two numbers have equal logs, they are equal: x-1 = 4, x = 4 + 1 = 5.
Tuesday, February 8, 2011 at 12:38pm by Henry

LOGARITHMS
HI THE QUESTION STATES THAT ONE SHOULD CALCULATE THE LOGS WITHOUT THE USE OF A CALCULATOR...OKAY MY PROBLEM IS THIS... 2 3 2log 8 + 2log 8 what should i do? i had come to the piont of... 4 5 log 8 + log 8 But what's to do now i dont know..Think u can help?... cheers ...
Wednesday, October 25, 2006 at 8:15am by TIGGER

algebra
I will do B), you do the others the same way ... b) (g of f)(x) to me means g(f(x)) = g(lnx) = e^(3lnx) since we can only take logs of positive numbers, domain: x > 0 range: I hope you are familiar with the basic exponential function, so y>0
Wednesday, September 5, 2012 at 10:39pm by Reiny

Algebra 2
Can someone please explain to me how to solve logarithmic equations? Some examples are: -5=log2X 3^5x+1= 40 and log6X+(log6)7=(log6)35 I hope that makes sense because logs are hard to type.
Friday, April 18, 2008 at 1:11pm by JaneLee

College Algebra
adding logs follows this rule (log ab)=loga + logb you have log (50x*x-1)=2 take the antilog of each side. 50x(x-1)=100 solve for x
Monday, March 7, 2011 at 8:00pm by bobpursley

algebra
e^x / 3 = 5^x take logs to base e: x-log(3) = xlog(5) group terms to get x(log(5)-1)=-log(3) x = -log(3)/(log(5)-1)
Saturday, December 3, 2011 at 6:12pm by MathMate

Math+Growth/Decay
By the way, at the vertical asymptote where x = -1/3, the value for y gets infinitely negative as you get closer and closer to that line (since the values in the parenthesis are getting smaller and smaller as you approach the minimum value for x, -1/3). Remember that it's ...
Wednesday, March 11, 2009 at 9:57pm by Toothpicks

Algebra
What is 2 to the fifth power? That will tell you the answer. You could also use logs. x log 2 = log 32 x = log 32/log2 = ?
Tuesday, August 4, 2009 at 12:19am by drwls

Algebra-please check my answers
4^(x + 4) = 5^(2x + 5) Take logs to base e of both sides (x+4) ln4 = (2x+5)ln 5 (x+4)/(2x+5) = (ln5)/(ln4)= 1.161 Solve for x
Friday, October 26, 2007 at 10:20pm by drwls

algebra
y = 4+e^-x/3 y-4 = e^-x/3 ln(y-4) = -x/3 x = -3ln(y-4) so, f inverse = -3ln(x-4) for domain, recall that ln(u) is defined only for u>0 domain for exponentials and range for logs is all reals
Tuesday, August 28, 2012 at 6:32pm by Steve

algebra
rules of logs b^log b(x) = x like 10^log(-3) = -3 there is no power of the base that will give you a negative result. Therefore there is no such thing as the log of a negative number. If you try it with a calculator it will say ERROR
Tuesday, January 29, 2008 at 9:43pm by Damon

misplaced nodifier
Modifiers (adjectives and adjective phrases mostly) need to be placed as close as possible to whatever they're describing/modifying. Which one, do you think, is the corrected version of what you posted? ~~> We had been hunting for the fire extinguisher behind a pile...
Saturday, September 24, 2011 at 4:32pm by Writeacher

Algebra
No. You have to add the logs of each term. Remember that log (abc) = log a + log b + log c etc. Your answer should be log (a x^3 y^2 z) = log a + 3 log x + 2 log y + log z
Tuesday, July 28, 2009 at 12:20am by drwls

algebra 2 logs and trig
Think about log2 and log4. If N is a number, log2(N)=1/2 log4(N) I am uncertain if the second term is csc^2 x or csc 2x. But my hint above should lead you to the solution.
Friday, August 13, 2010 at 11:07am by bobpursley

d
change logs to numbers. 1E6(1+-.02) now, go to logs. remember that log(ab)=log a+logb Intensity=6 +log.98 to 6 +log(1.02) The error is the difference, so error=log1.02-log.98= .009+.009=.018 You can work it more accurately. Now differentials: Error=highentensity-lowintensity ...
Wednesday, November 7, 2012 at 5:24pm by bobpursley

algebra 2 logs and trig
log(base 2)cotx - 2log(base 4)csc2x = log(base 2)cosx the answer should be x = pi/3, 5pi/3 not sure how to work it out though, any help? I tried canceling the bases but that led to a dead end.
Friday, August 13, 2010 at 11:07am by Teddy

Please help me!!!! maths
I am not sure if the 5 , 8 , and 6 are bases of the logs or just multipliers. Let's hope they are just multipliers, or else it would be a terrible terrible mess by the laws of logs log5(x-2)+log8(x-4) = log6(x-1) log [40(x-2)(x-4)] = log 6(x-1) anti-log it 40(x^2 - 6x + 8...
Wednesday, April 3, 2013 at 5:33am by Reiny

Pre Calculus
Major Error ! How did you mathemagically change 5^x to 20^4x ? Did you do something like (5^x)(4^4) = 20^4x ?? If so then something like this should work : (3^5)(4^2) = 12^10 which is certainly false You can only do this type of question if you know logs. take the log of both ...
Sunday, July 26, 2009 at 11:22am by Reiny

math
Require that X*(1.025)^16 = 15,000. X is the initial amount that you will need to invest. The 1.025 is the factor by which balance increases by every 3 months. It does this 16 times in 4 years. You can use logs to get the answer. I will use base 10 logs. (The base does not ...
Sunday, November 15, 2009 at 12:56pm by drwls

Algebra II
take logs to get rid of the exponents 2x ln9 = (3x-2)ln11 x(2 ln9 - 3 ln11) = -2 ln11 x = -2 ln11/(2 ln9 - 3 ln11) x = -4.79/-2.8 x = 1.71
Tuesday, November 8, 2011 at 8:51am by Steve

College Algebra
Let T be the age in years. 0.27 = (0.5)^(T/5700) Take logs of both sides to solve. T/5700 = log(0.27)/log(0.5) = 1.889 T = ___ years
Wednesday, December 1, 2010 at 1:07am by drwls

basic algebra
9400/4800 = (1.015)^4y = 1.9583 where y is the number of tears. Solve for y. I recommend using logs 4y = log1.9583/log1.015 y = 11.3 years
Friday, November 4, 2011 at 1:25pm by drwls

algebra
Since this is not my area of expertise, I searched Google under the key words "exponent rules" to get these possible sources: http://www.purplemath.com/modules/exponent.htm http://www.sosmath.com/algebra/logs/log3/log3.html http://www.mathwords.com/e/exponent_rules....
Tuesday, April 15, 2008 at 2:38pm by PsyDAG

algebra
you will have to use logs take log of both sides log(3.4^(2x-1)) = log 5 2x-1 = log 5/log 3.4 2x-1 = 1.31514 x = 1.1576
Saturday, December 13, 2008 at 12:22pm by Reiny

Algebra 1
1. log3(x - 1) = 4. x - 1 = 3^4, x = 3^4 + 1 = 81 + 1 = 82. 2. log3(x - 1) = log34. log3(x - 1) = 1.5315, x - 1 = 3^1.5315, x = 3^1.5315 + 1 = 5.379 + 1 = 6.379. Each problem required the use and understanding 0f logs. So they were basically the same.
Tuesday, February 8, 2011 at 12:38pm by Henry

Science
3. Which of the following conditions would likely cause the activation energy to be high? A.atoms are close together B.the temperature is hot C.atoms are not close together * D.a catalyst is present 4. Which of the following materials will burn the fastest in open air? A.a log...
Sunday, March 3, 2013 at 12:30am by Cassie

Math
Could you check these pleas? Firewood usually sold by a measure known as a cord. A full cord may be a stack 8x4x4ft or a stack 8x8x2ft 10. what is the volume of a full cord? 8*4*4=(128ft) 11. A short cord or a face cord of wood is 8x4xThe lenght of the logs. What is the volume...
Tuesday, September 7, 2010 at 8:19pm by TiffanyJ

Math
just as powers of products add (6^2 * 6^3 = 6^5) and subtract (6^8 / 6^3 = 6^5) log of a product is the sum of the logs, and log of a quotient is difference of logs. That's because of the definition of log: log6N is the power of 6 needed to get N. Even though it looks ...
Thursday, March 1, 2012 at 4:00am by Steve

Re: Algebra II
How to solve Log (9x+5) - Log ((x^2)-1) = 1/2 16 16 (The 16 is from the logarithmic function : b) (y=log x) b Could anyone post the answer to this? 16 is supposed to be next to Log(16) but lower. This is for both the Logs in the equation.
Tuesday, May 18, 2010 at 5:21pm by Anonymous

math30
by definition of logs: a^c = x+b x = a^c - b
Monday, May 13, 2013 at 5:39am by Reiny

logs
How do you solve: log (1/3) 1 ?
Monday, November 1, 2010 at 10:27am by Ali

Math-LOGS
duplicate
Monday, December 21, 2009 at 4:32pm by Anonymous

Math - logs
yep
Saturday, January 24, 2009 at 5:49pm by Damon

natural logs
mckendrick?
Friday, December 19, 2008 at 4:13pm by Anonymous

another pre cal (logs)
Thank you
Monday, March 31, 2008 at 1:14am by Deb

Maths-Logs
log13
Friday, November 23, 2007 at 2:53am by Anonymous

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