Sunday

April 20, 2014

April 20, 2014

Number of results: 38,689

**pre alg**

(25a^-2 b^-5 c^8) / (40 a^5 c^9) 25/40 = 5/8 check a^-2/a^5 = a^-7 check b^-5 = b^-5 check c^8/c^9 = c^-1 check
*Sunday, March 1, 2009 at 4:35pm by Damon*

**Alg**

Please check for errors.
*Friday, October 29, 2010 at 3:07pm by Henry*

**Alg**

Check for errors;something is missing.
*Friday, October 29, 2010 at 3:00pm by Henry*

**alg**

sqrt(3x^2)=-18 check:
*Thursday, May 16, 2013 at 2:27pm by Jane*

**alg**

solve and check solution 12x=11x-5
*Monday, October 12, 2009 at 2:37pm by jerson*

**Alg 2 trig**

What do you think? I will be happy to check your work.
*Friday, March 9, 2012 at 11:05am by bobpursley*

**alg 2 check?**

(4x+y)^2 answer:16x^2+y^2 is this correct?
*Monday, July 15, 2013 at 3:37pm by tyneisha*

**Algebra 1 Answer Check**

Okay, assuming this is Alg I, I'm pretty sure you accidentally miscommunicated the problem wrong. The problem above is UN-FACTORABLE assuming only real numbers. However, if you insist, the answer to this problem requires some Alg II knowledge. Q: 9x^2 - x +2 A: (1/36)(-18ix...
*Monday, March 10, 2014 at 9:49pm by herp_derp*

**pre-alg Answer Check**

If this is supposed to be the equation x/2 = 9/4 , then 4x = 18 x = 4.5
*Thursday, November 14, 2013 at 10:51pm by Reiny*

**alg 2 check?**

The polynomial 15xy+3x^3y^4 is what degree? I do not understand how to solve this
*Monday, July 15, 2013 at 3:40pm by tyneisha*

**Alg 2**

check for extraneous solutions. 0, 7^4 2^4, inside the equation x^5/6 = 9x^7/12 - 14x^1/3
*Sunday, February 9, 2014 at 6:40pm by luciano*

**pre alg**

How do u find the GCF with exponets in a 7th gr. pre alg. class?
*Sunday, January 11, 2009 at 6:51pm by tay*

**Alg 2 **

Solve the equation. Check for extraneous solutions. 10 ln 100x - 3 = 117 Thank you in advanced
*Thursday, February 2, 2012 at 1:54am by Yolie*

**college alg**

the function f(x)=6x+9/3x-7 find the inverse and check answer f^-1(x)=? please show work
*Wednesday, September 5, 2012 at 6:53pm by ALLI*

**college alg**

the function f(x)=6x+9/3x-7 find the inverse and check answer f^-1(x)=? please show work
*Wednesday, September 5, 2012 at 8:23pm by MYA*

**alg 2 check?**

not quite (4x+y)(4x+y) = 16x^2 + 4xy + 4xy + y^2 = 16x^2 + 8xy + y^2 You can always check your results by evaluating with numbers. For example, if x=1 and y=2, (4+2)^2 = 36 16*4+1 = 65 a good sign your result is wrong
*Monday, July 15, 2013 at 3:37pm by Steve*

**college math intermediate alg**

4y^5*81q^7/(9q^2*16y)= do the coefficents first, then the powers 4*81/16*9= 9/4 y^(5-1)q^(7-2) 9y^4 q^5 /4 check that.
*Monday, December 13, 2010 at 9:10am by bobpursley*

**alg 1**

I've helped you with several of these questions -- although you thought you'd fool us by posting under different names. I'll be glad to check your answer.
*Wednesday, July 10, 2013 at 7:02pm by Ms. Sue*

**alg**

I've helped you with several of these questions -- although you thought you'd fool us by posting under different names. I'll be glad to check your answer.
*Wednesday, July 10, 2013 at 7:03pm by Ms. Sue*

**alg**

I've helped you with several of these questions -- although you thought you'd fool us by posting under different names. I'll be glad to check your answer.
*Wednesday, July 10, 2013 at 7:08pm by Ms. Sue*

**Alg 2**

but if you plug in all 3 answers back to check for extraneous solutions, are any extraneous?
*Sunday, February 9, 2014 at 12:49am by luciano*

**Alg 2 **

Solve the equation. Check for extraneous solutions. ln x + ln(x-2) = 1
*Thursday, February 2, 2012 at 2:56am by Yolie*

**alg 2 check?**

1.)solve for n:-7n-21=-63 my answer: n=3 is this correct? please explain 2.)identify the x and y int for te equation 3x-4y=12.
*Monday, July 15, 2013 at 4:44pm by tyneisha*

**Alg 2**

1. check your typing 2. why do you have an absolute number symbol around a positive number like |18| ?
*Monday, July 30, 2012 at 9:10pm by Reiny*

**college alg**

the function f(x)=6x+9/3x-7 is one to one. find its inverse and check your answer. f^-1(x)=? please show work
*Wednesday, September 5, 2012 at 8:55pm by MYA*

**pre-alg Answer Check**

Use the proportion to find the missing length in the following similar figures. x/2 9/4 4.5 18 (My Answer) 8 2.25
*Thursday, November 14, 2013 at 10:51pm by Pretty Reckless*

**ALG 2! plz help urgent!!**

1) 4n = n + 78 3n = 78 n = 78/3 n = 26 I'll be glad to check your answers for the other problems.
*Tuesday, December 18, 2012 at 12:27pm by Ms. Sue*

**alg**

i need help solving this one (x + 4)^2/3= 9 a) 13 b) 23;-31 c) 5 d) 31;-31 also sove check for extraneous solutions (6x-5)^1/2 = (7+ 4x)^1/2 a) 1/6 b) -9 c) 6 or d) 1/5
*Saturday, March 15, 2008 at 9:58pm by John*

**alg**

i need help solving this one (x + 4)^2/3= 9 a) 13 b) 23;-31 c) 5 d) 31;-31 also sove check for extraneous solutions (6x-5)^1/2 = (7+ 4x)^1/2 a) 1/6 b) -9 c) 6 or d) 1/5
*Sunday, March 16, 2008 at 1:53pm by john*

**Alg 2**

(x-4)^3/2 = -6 Chris, you can do what you said but it would be wrong. what you said: (x-4)^3 = 36 x-4 = 3.3 x = 7.3 HOWEVER go back and check 3.3^3/2 = +6 NOT -6 In other words, when you squared both sides you threw the problem out with the bath water.
*Monday, February 2, 2009 at 10:26pm by Damon*

**ALG 2**

Just check the 4th row of Pascal's triangle: 1 4 6 4 1 attach the descending powers of x and ascending powers of y, so that the powers always add up to 4: x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4
*Saturday, January 21, 2012 at 6:40pm by Steve*

**alg 2 check?**

the degree of a polynomial is the largest sum of powers of the variables in each term. In this case, the terms have degree 15xy: 1+1 = 2 3x^3y^4: 3+4 = 7 so, the polynomial is of degree 7.
*Monday, July 15, 2013 at 3:40pm by Steve*

**Alg 2**

Ok heres another factoring that I need someone to check Problem: -x^3 + 27 -(x^3 - 3^3) So I moved the positive and found out what cubed would make 27 Using the forum_search_20140419la: (a-b)(a^2+ab+b^2) -(x-3) (x^2 + 3x + 9) Right? Or did I make a mistake?
*Wednesday, January 7, 2009 at 11:00pm by Chopsticks*

**Alg/Trig**

well, you know that h/x = tan 39.8° h/(x+51.7) = tan 19.7° Now eliminate x and solve for h: h/tan39.8° = h/tan19.7° - 51.7 1.2h = 2.8h - 51.7 h = 32.3 check my math, but that's the method to my madness.
*Wednesday, February 26, 2014 at 11:17am by Steve*

**Pre Alg (Check my work?)**

#1 QII #2 Assuming a typo and A=(8,-10), then A'=(-8,-10) #3 (x,y)->(x+1,y+3) (-2,-5)->(-1,-2) Looks like you have some reviewing to do. There are lots of web sites out there which discuss the topic and provide examples.
*Monday, November 11, 2013 at 4:54pm by Steve*

**Alg 2 Please can Someone Check this???**

1) 8^2y = 52^4y+3 2) 2^3(2y) = 2^26(4y+3) 3) 6y = 104y+78 4) -98y = 78 5) y= -0.796
*Wednesday, May 26, 2010 at 7:55pm by Anonymous*

**Alg 2**

well, 0 obviously works (2^4)^5/6 = 2^10/3 = 2^3*2^1/3 = 8*2^1/3 9(2^4)^7/12 = 9*2^7/3 = 36*2^1/3 14(2^4)^1/3 = 14*2^4/3 = 28*2^1/3 8=36-28 looks good to me You can check 7^4 in a similar manner.
*Sunday, February 9, 2014 at 6:40pm by Steve*

**Alg 2 Check Please!!!**

1) 8^2y = 52^4y+3 2) 2^3(2y) = 2^26(4y+3) 3) 6y = 104y+78 4) -98y = 78 5) y= -0.796
*Wednesday, May 26, 2010 at 6:46pm by Anonymous*

**Alg II**

So in our Alg II class we're studing variables and functions, and from the situation given we are to figure out the equation. "In a lighting storm, the time interval betwee the flash ad the bang (f) is directly proportional to the distance between you and the lighting (m)." ...
*Thursday, September 24, 2009 at 10:35pm by Rylie*

**math**

Try this tutorial, be sure to look at both pages: http://www.themathpage.com/Alg/slope-of-a-line.htm
*Wednesday, February 3, 2010 at 8:00pm by Damon*

**alg**

yes, it is a because you factor... x^2-81= x-9(x+9) x^2+18x-81= (x+9)(x+9) check: 9x+9x= 18x x*x= x^2 -9*9= -81 ((x-9)(x+9))/((x+9)(x+9))-> cross out x+9 ANS:(x-9)/(x+9)
*Tuesday, June 29, 2010 at 3:28pm by Nancy*

**alg**

-3 / (x^2 - 2x) + 1 /[2x (x^2 - 5x + 4)] -3/[x(x-2)] + 1/[2x(x-4)(x-1)] I think maybe a typo perhaps should be -3 / (x^2 - 4x) + 1 /[2x (x^2 - 5x + 4)] -3/[x(x-4)] + 1/[2x(x-4)(x-1)] multiply top and bottom of first by 2(x-1) -6(x-1)/[2x(x-4)(x-1)] + 1/[2x(x-4)(x-1)] [-6x+7]/[...
*Wednesday, June 30, 2010 at 5:13pm by Damon*

**Pre-Alg**

(Check my work?) 1.) Use arrow notation to write a rule that describes the translation of a point from (5,6) to (6,11) A.(x,y) -> (x + 1, y + 5) B.(x,y) -> (x - 1, y - 5) C.(x,y) -> (x - 1, y + 5) D.(X,y) -> (x + 1, y - 5) 2.) Point A(6,-2) is reflected over the x-...
*Friday, November 8, 2013 at 12:24am by AudioslavedCobain182*

**Math**

That is a big subject, especially for cubics and higher order polynomials. I recommend that you start by reading this: http://tutorial.math.lamar.edu/Classes/Alg/Factoring.aspx
*Monday, February 1, 2010 at 1:06am by drwls*

**math word problem**

Nope. http://library.thinkquest.org/20991/alg/ratios.html
*Tuesday, April 17, 2012 at 8:04pm by Ms. Sue*

**Math (alg 2)**

a/b = 3/2 so a is bigger a^2 - b^2 = 20 well b = 2a/3 so a^2 - 4a^2/9 = 20 9 a^2 - 4 a^2 = 180 a^2 = 36 a = 6 or -6 try a = 6 then b = 4 36 - 16 = 20 sure enough then also check a = -6 then b = -4 36 - 16 = 20 so that works too
*Sunday, September 7, 2008 at 5:31pm by Damon*

**Accounting**

A check returned by a bank because the issuer's cash account balance could not cover the check is called a(n): a. Cancelled check b. Certified check c. Outstanding check d. NSF check
*Thursday, October 18, 2012 at 7:14pm by Anton*

**math - algebra**

Use polynomial long division, or synthetic division. See http://tutorial.math.lamar.edu/Classes/Alg/DividingPolynomials.aspx for an example. The answer is x^2 -x +4
*Sunday, November 11, 2007 at 7:52pm by drwls*

**Alg 1**

The popultion of Medford High is 800 students & the population of WEstville High is 1240 students. Medfords pop. has been increasing by 30 students per year, while westville has been decreasing by 25 students per year. In how many yearas will the populations be the same. how ...
*Wednesday, March 9, 2011 at 11:19pm by Casey*

**math ALG 2!**

4x=x+78 4(20)=20+78 80=98 no i did guess and check 4(26)=26+78 104=104
*Tuesday, March 19, 2013 at 5:39pm by Aparna*

**math ALG 2!**

RED BIK= 300/2=150+14=164 BLU DIK= 150-14=136 CHECK YOUR ANSWERS= 164+136=$300
*Thursday, December 13, 2012 at 8:12pm by khan*

**math**

how do i solve two step equations? Do you mean two equations in two unknowns? The method of substitution is one way. There is a good tutorial here: http://www.themathpage.com/alg/simultaneous-equations.htm
*Thursday, January 18, 2007 at 10:35am by megan*

**maths**

Multiply in out using the distributive rule: http://www.themathpage.com/alg/distributive-rule.htm
*Sunday, June 5, 2011 at 5:27pm by drwls*

**alg math 116**

y = 39 + 5x 9x + 3y = -51 Substitute 39 + 5x for y in the second equation and solve for x. Put that value in the first equation to solve for y. Check by putting both values in the second equation. I hope this helps.
*Monday, February 1, 2010 at 11:08pm by PsyDAG*

**math(algabra readness**

http://www.themathpage.com/alg/algebraic-expressions.htm#expressions
*Tuesday, August 31, 2010 at 7:42pm by Ms. Sue*

**Alg 1**

so it lands at y=0 0=-.005x^2+.45x-6.5 multiply all by 200 x^2-90x+1300=0 using the quadratic equation.. x= (90+-sqrt(8100-5200)/2=45+-1/2 sqrt(2800)=45+-sqrt(2700)=45+-51.96 we reject the negative solution x=96.96 feet check my math,I did it in my head.
*Tuesday, April 16, 2013 at 4:36pm by bobpursley*

**math**

This is a difference of two squares. You have a special factor theorm for these. http://themathpage.com/Alg/difference-two-squares.htm
*Sunday, February 21, 2010 at 11:10pm by bobpursley*

**Math (URGENT)**

http://www.themathpage.com/alg/complete-the-square.htm#complete
*Monday, November 21, 2011 at 12:10pm by drwls*

**alg 2**

y = 4^(x+1) - 1 ??
*Tuesday, February 12, 2008 at 3:30pm by Reiny*

**alg 2**

thanks
*Wednesday, March 12, 2008 at 10:30am by Abby*

**alg 2.**

okay thanks
*Thursday, May 8, 2008 at 8:08pm by Miley*

**alg 2.**

thanks!
*Monday, May 19, 2008 at 7:33pm by Miley*

**alg 2.**

yes.
*Tuesday, June 3, 2008 at 9:38pm by bobpursley*

**Alg**

x=0
*Saturday, February 14, 2009 at 9:47pm by Mishi Couture*

**alg**

= 1 + 1
*Sunday, July 5, 2009 at 7:43pm by drwls*

**alg**

thanks
*Friday, June 25, 2010 at 7:02pm by anthony*

**alg**

thanks
*Monday, June 28, 2010 at 3:40pm by sean *

**alg**

You're welcome
*Monday, June 28, 2010 at 3:44pm by Jen*

**alg**

thanks
*Tuesday, June 29, 2010 at 3:23pm by sean*

**alg**

THANKS
*Monday, July 12, 2010 at 11:47am by kid*

**alg**

thanks
*Monday, July 12, 2010 at 11:48am by kid*

**alg**

You're welcome.
*Monday, July 12, 2010 at 11:48am by Ms. Sue*

**Alg**

4(q+p)
*Friday, September 9, 2011 at 6:49pm by David*

**ALG help**

x^2 - 5^2 = (x-5).(x+5)
*Friday, March 2, 2012 at 3:33am by Libuse*

**Alg 2**

so, (C)
*Monday, July 30, 2012 at 9:10pm by Steve*

**Alg 1**

yes
*Saturday, April 13, 2013 at 7:55pm by Anonymous*

**Alg 1**

8
*Sunday, April 14, 2013 at 5:02pm by Allison*

**Alg 1**

2+2
*Saturday, April 13, 2013 at 11:27am by Noah*

**digital electronics**

http://www.dspguru.com/comp.dsp/tricks/alg/grayconv.htm
*Tuesday, August 12, 2008 at 11:14pm by bobpursley*

**math ALG 2!**

1. x - 32 = -58 Solve for x. 2. 14n = -28 3. r = b + 14 r + b = 300 Substitute b+14 for e in second equation and solve for b. If you want, insert that value into the first equation and solve for r. Check by inserting both values into the second equation. 4-6. Use similar ...
*Tuesday, March 19, 2013 at 4:29pm by PsyDAG*

**math-alg**

b?
*Wednesday, September 26, 2007 at 1:00am by none*

**alg 2.**

Why is ln(e^-2) = -2. Why doesn't it = e^-2??
*Thursday, May 8, 2008 at 8:08pm by Miley*

**alg 2.**

thanks damon!!!!!!
*Thursday, May 8, 2008 at 8:08pm by Miley*

**alg 2.**

ohh okay thanks
*Thursday, May 8, 2008 at 8:32pm by Miley*

**alg 2.**

huh??
*Thursday, May 8, 2008 at 8:32pm by Miley*

**alg 2.**

ahhhaaa....thanks:)
*Monday, May 19, 2008 at 7:32pm by Miley*

**alg 2.**

in general a^-b = 1/a^b
*Monday, May 19, 2008 at 7:34pm by Damon*

**alg**

no i dont
*Monday, June 9, 2008 at 8:43pm by jerson*

**alg 2**

what is the PRODUCT?
*Monday, June 16, 2008 at 8:33pm by MILEY!:)7*

**alg 2**

log2 (x+2) = 2 2^(x+2) = x+2 = 2^2 = 4 x = 2
*Monday, June 16, 2008 at 8:40pm by Damon*

**alg**

thanks drwls
*Monday, July 5, 2010 at 12:20pm by sean*

**Alg 2**

Yes. No Mistake.
*Wednesday, January 7, 2009 at 11:00pm by Sushi*

**alg**

2(-3^8-9)x9
*Friday, January 16, 2009 at 2:37pm by tony walker*

**alg 1**

Correct!
*Monday, March 30, 2009 at 7:34pm by PsyDAG*

**alg**

how do you simplify 7[-4+8(-5+3)]
*Tuesday, December 15, 2009 at 1:17pm by jerson*

**alg**

Solve: 2 / x - 1 - 3/4 = 5 / x - 1 a) -2 b) 2 c) 3 d) -3
*Thursday, July 1, 2010 at 9:39am by sean*

**alg**

right
*Friday, June 25, 2010 at 7:02pm by Reiny*

**alg**

correct
*Monday, June 28, 2010 at 2:17pm by bobpursley*

**alg**

Thanks bobpursley
*Monday, June 28, 2010 at 2:17pm by sean *

**alg**

Correct
*Monday, June 28, 2010 at 3:44pm by Anonymous*

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