Monday

April 21, 2014

April 21, 2014

Number of results: 1,226

**pre alg**

How do u find the GCF with exponets in a 7th gr. pre alg. class?
*Sunday, January 11, 2009 at 6:51pm by tay*

**Alg II**

So in our Alg II class we're studing variables and functions, and from the situation given we are to figure out the equation. "In a lighting storm, the time interval betwee the flash ad the bang (f) is directly proportional to the distance between you and the lighting (m)." ...
*Thursday, September 24, 2009 at 10:35pm by Rylie*

**Algebra 1 Answer Check**

Okay, assuming this is Alg I, I'm pretty sure you accidentally miscommunicated the problem wrong. The problem above is UN-FACTORABLE assuming only real numbers. However, if you insist, the answer to this problem requires some Alg II knowledge. Q: 9x^2 - x +2 A: (1/36)(-18ix...
*Monday, March 10, 2014 at 9:49pm by herp_derp*

**math**

Try this tutorial, be sure to look at both pages: http://www.themathpage.com/Alg/slope-of-a-line.htm
*Wednesday, February 3, 2010 at 8:00pm by Damon*

**Math**

That is a big subject, especially for cubics and higher order polynomials. I recommend that you start by reading this: http://tutorial.math.lamar.edu/Classes/Alg/Factoring.aspx
*Monday, February 1, 2010 at 1:06am by drwls*

**math word problem**

Nope. http://library.thinkquest.org/20991/alg/ratios.html
*Tuesday, April 17, 2012 at 8:04pm by Ms. Sue*

**math - algebra**

Use polynomial long division, or synthetic division. See http://tutorial.math.lamar.edu/Classes/Alg/DividingPolynomials.aspx for an example. The answer is x^2 -x +4
*Sunday, November 11, 2007 at 7:52pm by drwls*

**Alg 1**

The popultion of Medford High is 800 students & the population of WEstville High is 1240 students. Medfords pop. has been increasing by 30 students per year, while westville has been decreasing by 25 students per year. In how many yearas will the populations be the same. how ...
*Wednesday, March 9, 2011 at 11:19pm by Casey*

**math**

how do i solve two step equations? Do you mean two equations in two unknowns? The method of substitution is one way. There is a good tutorial here: http://www.themathpage.com/alg/simultaneous-equations.htm
*Thursday, January 18, 2007 at 10:35am by megan*

**maths**

Multiply in out using the distributive rule: http://www.themathpage.com/alg/distributive-rule.htm
*Sunday, June 5, 2011 at 5:27pm by drwls*

**math(algabra readness**

http://www.themathpage.com/alg/algebraic-expressions.htm#expressions
*Tuesday, August 31, 2010 at 7:42pm by Ms. Sue*

**math**

This is a difference of two squares. You have a special factor theorm for these. http://themathpage.com/Alg/difference-two-squares.htm
*Sunday, February 21, 2010 at 11:10pm by bobpursley*

**Math (URGENT)**

http://www.themathpage.com/alg/complete-the-square.htm#complete
*Monday, November 21, 2011 at 12:10pm by drwls*

**alg 2**

y = 4^(x+1) - 1 ??
*Tuesday, February 12, 2008 at 3:30pm by Reiny*

**alg 2**

thanks
*Wednesday, March 12, 2008 at 10:30am by Abby*

**alg 2.**

okay thanks
*Thursday, May 8, 2008 at 8:08pm by Miley*

**alg 2.**

thanks!
*Monday, May 19, 2008 at 7:33pm by Miley*

**alg 2.**

yes.
*Tuesday, June 3, 2008 at 9:38pm by bobpursley*

**Alg**

x=0
*Saturday, February 14, 2009 at 9:47pm by Mishi Couture*

**alg**

= 1 + 1
*Sunday, July 5, 2009 at 7:43pm by drwls*

**alg**

thanks
*Friday, June 25, 2010 at 7:02pm by anthony*

**alg**

thanks
*Monday, June 28, 2010 at 3:40pm by sean *

**alg**

You're welcome
*Monday, June 28, 2010 at 3:44pm by Jen*

**alg**

thanks
*Tuesday, June 29, 2010 at 3:23pm by sean*

**alg**

THANKS
*Monday, July 12, 2010 at 11:47am by kid*

**alg**

thanks
*Monday, July 12, 2010 at 11:48am by kid*

**alg**

You're welcome.
*Monday, July 12, 2010 at 11:48am by Ms. Sue*

**Alg**

4(q+p)
*Friday, September 9, 2011 at 6:49pm by David*

**ALG help**

x^2 - 5^2 = (x-5).(x+5)
*Friday, March 2, 2012 at 3:33am by Libuse*

**Alg 2**

so, (C)
*Monday, July 30, 2012 at 9:10pm by Steve*

**Alg 1**

yes
*Saturday, April 13, 2013 at 7:55pm by Anonymous*

**Alg 1**

8
*Sunday, April 14, 2013 at 5:02pm by Allison*

**Alg 1**

2+2
*Saturday, April 13, 2013 at 11:27am by Noah*

**digital electronics**

http://www.dspguru.com/comp.dsp/tricks/alg/grayconv.htm
*Tuesday, August 12, 2008 at 11:14pm by bobpursley*

**math-alg**

b?
*Wednesday, September 26, 2007 at 1:00am by none*

**alg 2.**

Why is ln(e^-2) = -2. Why doesn't it = e^-2??
*Thursday, May 8, 2008 at 8:08pm by Miley*

**alg 2.**

thanks damon!!!!!!
*Thursday, May 8, 2008 at 8:08pm by Miley*

**alg 2.**

ohh okay thanks
*Thursday, May 8, 2008 at 8:32pm by Miley*

**alg 2.**

huh??
*Thursday, May 8, 2008 at 8:32pm by Miley*

**alg 2.**

ahhhaaa....thanks:)
*Monday, May 19, 2008 at 7:32pm by Miley*

**alg 2.**

in general a^-b = 1/a^b
*Monday, May 19, 2008 at 7:34pm by Damon*

**alg**

no i dont
*Monday, June 9, 2008 at 8:43pm by jerson*

**alg 2**

what is the PRODUCT?
*Monday, June 16, 2008 at 8:33pm by MILEY!:)7*

**alg 2**

log2 (x+2) = 2 2^(x+2) = x+2 = 2^2 = 4 x = 2
*Monday, June 16, 2008 at 8:40pm by Damon*

**alg**

thanks drwls
*Monday, July 5, 2010 at 12:20pm by sean*

**Alg 2**

Yes. No Mistake.
*Wednesday, January 7, 2009 at 11:00pm by Sushi*

**alg**

2(-3^8-9)x9
*Friday, January 16, 2009 at 2:37pm by tony walker*

**alg 1**

Correct!
*Monday, March 30, 2009 at 7:34pm by PsyDAG*

**alg**

how do you simplify 7[-4+8(-5+3)]
*Tuesday, December 15, 2009 at 1:17pm by jerson*

**alg**

Solve: 2 / x - 1 - 3/4 = 5 / x - 1 a) -2 b) 2 c) 3 d) -3
*Thursday, July 1, 2010 at 9:39am by sean*

**alg**

right
*Friday, June 25, 2010 at 7:02pm by Reiny*

**alg**

correct
*Monday, June 28, 2010 at 2:17pm by bobpursley*

**alg**

Thanks bobpursley
*Monday, June 28, 2010 at 2:17pm by sean *

**alg**

Correct
*Monday, June 28, 2010 at 3:44pm by Anonymous*

**alg**

Correct
*Monday, June 28, 2010 at 3:44pm by Jen*

**alg**

Right.
*Monday, June 28, 2010 at 3:40pm by Jen*

**alg**

correct.
*Tuesday, June 29, 2010 at 3:25pm by bobpursley*

**alg**

thanks Nancy
*Tuesday, June 29, 2010 at 3:28pm by sean*

**alg**

thanks jessie
*Tuesday, June 29, 2010 at 3:19pm by sean*

**alg**

thanks henry
*Tuesday, June 29, 2010 at 3:03pm by sean*

**alg**

correct
*Wednesday, June 30, 2010 at 8:22am by Reiny*

**alg**

THANKS REINY
*Wednesday, June 30, 2010 at 8:22am by anth*

**alg**

a is thanks bobpursley
*Wednesday, June 30, 2010 at 3:52pm by sean*

**alg**

thanks psydag
*Thursday, July 1, 2010 at 9:31am by sean*

**alg**

solve: 1 / x + 2 + 1 / x - 2= 1 / x^2 - 4 a)-2 b) 2 c)-1/2 d) 1/2
*Friday, July 2, 2010 at 6:30pm by sean*

**alg**

solve: 2 / x - 1 - 3/4 = 5 / x - 1 a) -3 b) 3 c) 2 d) -2
*Friday, July 2, 2010 at 6:36pm by sean*

**alg**

thanks reiny
*Friday, July 2, 2010 at 6:30pm by sean*

**alg**

i got c
*Friday, July 2, 2010 at 6:36pm by sean*

**alg**

thanks bobpursley
*Friday, July 2, 2010 at 6:42pm by sean*

**alg**

thanks drwls
*Tuesday, July 6, 2010 at 7:17am by sean*

**alg**

4.00
*Monday, July 12, 2010 at 11:47am by kid*

**alg**

$3.79
*Monday, July 12, 2010 at 11:47am by jay*

**alg 2 **

(2x-3)(x-3) ?
*Monday, November 29, 2010 at 9:09pm by bobpursley*

**alg 2**

its not finding the x!
*Wednesday, December 8, 2010 at 5:47pm by katelyn*

**alg 2**

simplify (x^3/4)^3
*Thursday, January 20, 2011 at 12:03am by katie*

**alg 2**

x^3/4 * x^3/4 * x^3/4 = x^9/64
*Thursday, January 20, 2011 at 12:03am by helper*

**pre Alg**

3(g-3)=6
*Wednesday, January 4, 2012 at 7:37pm by Riley*

**alg 2**

how about -5 -4 -3 -2 - 1 +0 +1 +2 +3 +5+4 +5 ?
*Tuesday, May 15, 2012 at 4:21pm by Reiny*

**Alg/Trig**

(x-2)^2 + (y-3)^2 = 4.5^2
*Friday, July 6, 2012 at 1:13pm by David*

**Alg**

solve: x + 8 = 2(x-2) - x
*Friday, August 31, 2012 at 2:30am by Mitch*

**ALG 2!!!**

y = 3x + 4
*Sunday, October 7, 2012 at 4:55pm by Reiny*

**simple alg 2!!!**

|-2+3| = |1| = 1
*Friday, October 19, 2012 at 10:06pm by Reiny*

**ALG 2!!!**

m=[-5-(-5)]/(3-9) m=0 the equation is y=-5
*Thursday, November 22, 2012 at 4:33pm by MNHS*

**Alg 1**

Correct.
*Tuesday, April 16, 2013 at 8:23pm by rbowh*

**pre alg**

thank u
*Thursday, May 9, 2013 at 10:26pm by john*

**pre alg**

You're welcome.
*Thursday, May 9, 2013 at 10:26pm by Ms. Sue*

**Alg 1**

also i^2=-1
*Monday, April 15, 2013 at 12:12pm by Chris*

**Alg 1**

also i^2=-1
*Monday, April 15, 2013 at 12:12pm by Chris*

**alg**

y = 3x
*Friday, December 20, 2013 at 2:49pm by Steve*

**alg**

(7 − i)(2 + i)
*Friday, April 18, 2014 at 4:42pm by alg*

**math**

http://tutorial.math.lamar.edu/Classes/Alg/FunctionDefn.aspx
*Monday, August 1, 2011 at 10:46am by Ms. Sue*

**Algebra word problems**

The area of a rectangle is found by multiplying the length by the width: A=lw. A certain rectangle has an area os x^2+7x +12. Factor the trinomial to find the length ad width of the rectagle. Please read at this site: http://www.themathpage.com/alg/factoring-trinomials.htm ...
*Tuesday, January 23, 2007 at 3:25pm by deborah*

**pre alg**

oh!!! i get it now, thank you!!
*Monday, December 10, 2007 at 8:30pm by john paul*

**alg. 2**

got it, thanks damon!
*Tuesday, March 18, 2008 at 9:34pm by Miley*

**alg 2.**

Not really wrong.
*Thursday, May 8, 2008 at 8:15pm by Damon*

**alg 2.**

much easier... thanks!!
*Thursday, May 8, 2008 at 8:30pm by Miley*

**alg 2.**

I have to condense it... thanks for your help
*Thursday, May 8, 2008 at 8:32pm by Miley*

**alg 2.**

what happen to the base 4?
*Thursday, May 8, 2008 at 8:32pm by Miley*

**Alg**

Isnt that the same as (5/2)squared?
*Tuesday, June 3, 2008 at 9:32pm by bobpursley*

**alg**

still dont get it
*Monday, June 9, 2008 at 6:30pm by jerson*

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