Tuesday
March 11, 2014

# Search: ae

Number of results: 629

Mathematics
By the way, having gotten interested, I also solved this by brute force trial and error. I assumed an exponential type solution: y = Ae^x + Bxe^x+ C then dy/dx = Ae^x + Bxe^x + Be^x plug that in Ae^x + Bxe^x + Be^x - Ae^x/x - Be^x - C/x = 1/x + 1 + Ae^x + Bxe^x+ C combine like...
Saturday, December 29, 2007 at 6:20am by Damon

Math Calculus Help
we know that p = ae^kt using the known values, √e/2 = ae^k e/2 = ae^2k divide to get (e/2) / (√e/2) = e^k √e = e^k so, k = 1/2 now, we see that √e/2 = ae^(1/2) so a = 1/2 p(t) = 1/2 e^(t/2) p(4) = 1/2 e^2
Thursday, November 15, 2012 at 2:45pm by Steve

Reaction rates
so... k=Ae^(Ea/RT) Do I set it up as ratios? I.e. 0.0000100s-1=Ae^(-Ea/R * 636) ____________________________ 0.000479s-1=Ae^(-Ea/R * 700) A cancels out ...and then solve from there?
Saturday, November 20, 2010 at 10:37pm by Confused

Gr. 9 Math (continued)
Given AE=4, EB=9, If AE≠EB, the only way that AEFG and EBHF are similar is that AE<EF<EB, which means really that AEFG is similar to FEBH to ensure the vertices correspond. If that's the case, Let EF=x, then AE/x = x/EB, or x² = AE*EB = 36 EF = x = 6 (negative ...
Sunday, December 12, 2010 at 1:58pm by MathMate

geometry!
oin AC and DE. Triangles AFE and DFC are similar. so AF/FC = AE/CD = AE/EB also AE + EB = AB ie AE +234AE =AB so AE/AB =1/235 so AF/FC = 1/235 FC = 235 AF now, AC = AF +FC = 236AF ie AC/AF = 236/1 ie AC : AF = 236 : 1
Thursday, February 28, 2013 at 12:54am by Navneet

Reaction Descriptions
abd, bf, cf, cd, ae, ae is correct
Wednesday, January 12, 2011 at 9:46pm by caitlin

Reaction Descriptions
abd, bf, cf, cd, ae, ae is correct :)
Wednesday, January 12, 2011 at 9:46pm by chemlab

geometry
Given: ABC,/ AD bisects <BAC, and /AE=/ED Prove: AE/AC = BD/BC
Monday, November 25, 2013 at 3:38am by loveofnursing

GEOMETRY
GIVEN: TRIANGLE ABC,AD bisects <BAC,and AE=ED, PROVE:AE/AC=BD/BC
Monday, September 17, 2012 at 8:41pm by HELEN

Geometry / Proofs
Given: Triangle ABC with AD bisecting angle BAC, and AE is congruent to ED (both line segments). Prove: AE/AC = BD/BC. Statements Reasons
Tuesday, August 27, 2013 at 3:24pm by Lisa

Physics
Ap/Ae = pi*(8.25r)^2/pi*r^2=68.1r^2/r^2= 68.1/1 Ap = 68.1*Ae. Ap = Area of the planet. Ae = Area of the earth.
Sunday, September 8, 2013 at 2:09pm by Henry

geometry
In the accompying diagram of circleo, diameter ad,chord AE,ans secantsCAB and CDE are drawn ; m angle BAD=40;and m arch AE=5((m arch ED) what is the measure of ACE?
Saturday, March 10, 2012 at 9:21pm by Vanna

Algebra
If m angle FGE =5x+10, Find the value of x so that line FC is perpendicular to Line AE. Line AE is a striaght line
Sunday, September 9, 2012 at 12:07am by Maria

chemistry
I agree that the explosion of gasoline is a low energy of activation as is H2 and O2 explosion with a spark. I would agree that the rusting of a nail is a higher AE than gasoline explosion but, to repeat myself, high is a relative term. And I'm not so sure that it is ...
Saturday, January 17, 2009 at 2:47pm by DrBob222

geometry
How AC is related to AE, are they equal? If yes, then you have to solve this way: AC=AE 2x-1=x^2-2, then solve for x x=1
Sunday, September 18, 2011 at 8:27pm by Anonymous

MATH
Complete Problem 34 in Section 5.2 Exercises (Ch. 5) of Essentials of Geometry for College Students. 34. Given: ABC,/ AD bisects <BAC, and /AE=/ED Prove: AE/AC = BD/BC
Monday, June 17, 2013 at 10:46pm by BJ

Integrated Math 1
CE must be 7 also, as C bisects AE.You have a right triangle AED, so AE=14 (hypotenuse), side DE 10. AD=sqrt(14^2-10^2)
Sunday, July 15, 2012 at 6:47pm by bobpursley

Math
if h(x) = ae^bx, just plug in your values: 22 = ae^2b 14.08 = ae^4b divide one by the other, and the a's cancel 14.08/22 = .64 = e^2b e^b = .8 22 = a*.64 a = 34.375 h(x) = 34.375 e^bx = 34.375 * 0.8^x
Saturday, February 16, 2013 at 3:43pm by Steve

chemistry
It would help if we knew what you were doing. #2. Theoretical yield = TE actual yield = AE = TE-1.5 %yield = (AE/TE)*100 =
Wednesday, July 18, 2012 at 6:27am by DrBob222

Geometry Proofs
Given: AD=AB AE= AD/3 AF= AB/3 Prove: AE= AF
Monday, August 13, 2007 at 10:25am by Sarah

geometrY!
Given: Let r=AE:EB Draw a diagram of the parallelogram ABCD. Insert E on AB. Extend DE to join CA at F. (The above is as given by the question). Examine the triangles FAE and DBE. Show that they are similar noting that FA is parallel to DB. Therefore the ration FE:ED = AE:EB ...
Wednesday, February 27, 2013 at 1:56am by MathMate

trigonometry
Construct the trapezoid ABCD ,where AB || CD AB = 12 and CD = 22 angle C=65 and angle D = 40 Draw AE || BC where E is on CD So now ABCE is a parallelogram, and CE = 12 which makes ED = 10 Now look at triangle AED, by corresponding angles angle AED = 65°, angle D = 40 leaving ...
Friday, February 10, 2012 at 6:18am by Reiny

Geometry
1. Ae = 360 / N = 90, 90N = 360, N = 360 / 90 = 4 Sides. 2. At = 80 + 90 + 103 + x = 360, X = 360 - 273 = 87 deg. 3. At =(N - 2)180, At = (7 - 2)180 = 900 deg. 4. Ae = 360 / N = 360 / 5 = 72 DEG. 5. 6. 7. At = (N - 2)180 = 1440, (N - 2) = 1440 / 180 = 8, N = 8 - 2 = 6 Sides. 8...
Tuesday, November 30, 2010 at 2:16pm by Henry

Electricity help needed please
I assume your wires are round, not spherical. That is, they have a circular cross-section. If A has power P, and cross-section area a, length m and resistivity r, then its resistance R = rm/a P = E^2/R E^2/(rm/a) = aE^2/rm Conductor B has power (2a)E^2/(2r*3m) = 4/6 aE^2/rm = ...
Friday, November 15, 2013 at 5:49am by Steve

Calculus
f = ax e^(bx) f' = ae^(bx) + abx e^(bx) = ae^(bx) (1+bx) f'(1/8) = 0, so b = -8 f(1/8) = 1 = a(1/8)e^(-1), so a=8e f(x) = (8e)x e^(-8x)
Wednesday, March 6, 2013 at 4:09pm by Steve

calculus
let y = 4 x dy = 4 dx so integral of e^y sin y dy try e^y cos y derivative = -e^y sin y + e^y cos y so try ae^y cos y + be^y sin y derivative = -ae^ysiny+ae^ycosy+be^ycosy+be^ysiny we need a=-b to get rid of cos terms so -b e^y cos y +b e^y sin y so be^y sin y - be^y cos y try...
Wednesday, May 5, 2010 at 2:08am by Damon

MATHS
Let segments AB and CD have common point E. Then AC<AE+EC and BD<BE+ED. AE+EC+BE+ED=AB+CD
Saturday, September 3, 2011 at 8:48am by Mgraph

Calculus
Hmmm. Forget the above. We want y(0) = 1 and y(2.32) = 0.1 So, assuming y = aebx we have 1 = ae0 a = 1 so, y = ebx .1 = e2.32b ln .1 = 2.32b b = -2.3/2.3 = -1 So, y = e-x Am I still wrong here?
Sunday, October 30, 2011 at 10:03pm by Steve

geometry
I must assume that A and B are the centres of your two circles for this to make sense. Join AE, and you will have a right angles triangle AEB with AE=11, AB = 19 , and BE = x x^2 + 11^2 = 19^2 x^2 = 240 x = √240 so the area = (1/2) base x height = (1/2)(√240)(11...
Thursday, April 4, 2013 at 1:30am by Reiny

Math
This is rather crude. http://awwapp.com/s/ae/d6/63.html
Monday, August 5, 2013 at 4:06pm by Ms. Sue

geometry
Just lay out the points on the line BD contains the right half of BC and the left half of CE So, what's left is the same length: The left half of AC and the right half of CE AE = AB + BC + CD + DE but BD = BC + CD = 14 so, AE = AB + 14 + DE However, AB = BC and CD = DE so AB+...
Sunday, December 11, 2011 at 7:20pm by Steve

Anatomy & Physiology
Thank you for using the Jiskha Homework Help Forum. Try the following: http://www.accessexcellence.org/AE/AEC/CC/heart_anatomy.php Sra
Thursday, August 14, 2008 at 3:47pm by SraJMcGin

math
Tough to figure out from the "non-given" diagram. let DB, the horizontal distance be x. angle ADB = 48 degrees, 30 minutes (not inches!) = 48.5° so tan 48.5 = 40/x x = 40/tan48.5 = 35.39 m from C, draw a horizontal to meet AB at E tan 24.5 = AE/x AE = xtan24.5 = 16.13 m so ...
Sunday, June 19, 2011 at 4:05am by Reiny

Anatomy
Thank you for using the Jiskha Homework Help Forum. Try the following: http://www.accessexcellence.org/AE/AEC/CC/heart_anatomy.php
Tuesday, May 27, 2008 at 1:17pm by SraJMcGin

Geometry
Given triangle ABC, AD bisects angle BAC,and AE=ED Prove AE/AC=BD/BC Because I cant draw it I will explain. Its a triangle, A is the point at the top, B is the point at the bottom left and C is the point at the bottom right.There is a line going right down the middle, which is...
Saturday, September 29, 2012 at 8:23pm by Teisha

maths
Assume formula Population in billions at time t (counting from 1987) as P(t)=Ae^(kt) where A and k are constants. At t=0 (1987), P(0)=Ae^(0)=A=5 the formula becomes: P(t)=5e^(kt) P(1)=5*1.02=5e^(kt) [t=1] => e^(k)=1.02 [t=1] Take log both sides k=log(1.02) [natural log] So ...
Wednesday, July 18, 2012 at 1:18am by MathMate

social studies
If you look at the geography of ancient Egypt, you'll clearly see that it's in the pharoah's best interest to have the people of the upper Nile (to the south) and the lower Nile (to the north, where it flows into the Mediterranean Sea) under one rule -- for protection, for ...
Monday, September 22, 2008 at 8:03pm by Writeacher

geometry
B is the midpoint of AC, D is the midpoint of CE, and Bd=14. find AE. B is the midpoint of AC, D is the midpoint of CE and BD=7. Find AE.
Sunday, December 11, 2011 at 7:20pm by james

Geometry
draw the trap ABCD where AD=10,DC = 7, BC=17 and BA = 6 Draw AE parallel to DC, then AE=7 and BE = 7 We now have a parallelogram and a triangle. Let's find angle AEB which is also angle C , call it Ų by cosine law in triangle ABE 6^2 = 7^2 + 7^2 - 2(7)(7)cosŲ cosŲ = .632653...
Sunday, May 22, 2011 at 3:18pm by Reiny

AE
behaviorist
Sunday, April 12, 2009 at 8:05pm by scooby91320002

AE is this correct?
is the rest ok?
Thursday, August 14, 2008 at 4:48pm by scooby91320002

Reaction Descriptions
5. AE
Wednesday, January 12, 2011 at 9:46pm by someone

AE
and possible some websites that can help me with this... thank you
Thursday, July 31, 2008 at 2:07pm by scooby91320002

AE
do you know any websites I ccan use
Tuesday, August 5, 2008 at 12:32am by scooby91320002

AE....
How can diversity be an asset to the classroom?
Friday, March 6, 2009 at 12:03am by scooby91320002

AE is this correct?
cool so i can turn it in.
Friday, March 6, 2009 at 6:47pm by scooby91320002

AE....
what are teachers Rights and Responsibilities
Sunday, March 29, 2009 at 4:32pm by scooby91320002

AE ( last and final one)
Yes.
Sunday, March 29, 2009 at 5:57pm by Ms. Sue

AE..
i cant seem to find the info on it
Sunday, April 12, 2009 at 8:30pm by scooby91320002

AE.. does it sound ok
Yep.
Sunday, April 12, 2009 at 9:48pm by Ms. Sue

AE.. does it sound ok
can you help me with organizing the classroom?
Sunday, April 12, 2009 at 9:48pm by scooby91320002

AE
Of course, a personal computer is o.k.
Sunday, April 26, 2009 at 1:26pm by Ms. Sue

Reaction Descriptions
Is AE correct?
Wednesday, January 12, 2011 at 9:46pm by Jay

maths
Let ABC be a triangle.Draw median AD on BC.Draw median AE of triangle ABD on BD.Take a point on side AB say F and join CF. Now from D make a line parallel to CF such that the line cuts AB at G. Note- G lies between F and B. AD intersect CF and P. AE intersect GD at H. So BD=DC...
Monday, September 2, 2013 at 7:31am by nami

AE
teacher certification/licensure requirements
Friday, June 27, 2008 at 11:46pm by scooby91320002

AE....
It does reduce group think tendencies.
Friday, March 6, 2009 at 12:03am by bobpursley

AE is this correct?
That looks right. :-)
Friday, March 6, 2009 at 6:47pm by Ms. Sue

AE is this correct?
You're doing great, Scooby! And you're welcome.
Friday, March 6, 2009 at 6:47pm by Ms. Sue

AE..
i cannot seem to undersatnd what they want me to do. and dont know where to start
Sunday, April 12, 2009 at 8:30pm by scooby91320002

AE.. does it sound ok
This is a good start.
Sunday, April 12, 2009 at 9:48pm by Ms. Sue

AE
I am with both but I have no idea where to start.
Thursday, April 30, 2009 at 4:12pm by scooby91320002

AE
can you help me with a better understand plz on what I am suppose to do.
Sunday, May 31, 2009 at 12:46pm by scooby91320002

AE(updated)
is dropouts one? i am not sure
Sunday, May 31, 2009 at 12:46pm by scooby91320002

AE
i dunno if i am even understanding the reading
Sunday, May 31, 2009 at 12:46pm by scooby91320002

AE
i dont understand what they want me to do on pages 134
Sunday, May 31, 2009 at 12:46pm by scooby91320002

math
f(t)=Ae^rt t=1, r= .085, A=9000
Thursday, October 7, 2010 at 7:59pm by bobpursley

Latin
agricola will have all first declension endings. Almost all first-declension nouns are feminine, but this is the primary exception. Because agricola is masculine, any adjective that modifies it needs to be masculine also. bonus will have second-declension endings to modify ...
Thursday, June 24, 2010 at 5:56pm by Writeacher

Math
Solution 1: Triangles ADE and BFE are similar since \overline{AD}\parallel\overline{BF}. Furthermore, the ratio of their areas is 9:1, so AE/BE = 3. Then CD = AB = AE + BE = 3BE + BE = 4BE. Triangles FEB and FDC are similar, so the area of triangle FDC is (DC/BE)^2 \cdot [FEB...
Saturday, November 23, 2013 at 9:15pm by ASDF

AE
where can i find the steps required for a multicultural classroom?
Sunday, July 6, 2008 at 3:30pm by scooby91320002

AE.. is this right
That's a good general answer.
Thursday, March 12, 2009 at 10:11pm by Ms. Sue

AE
Yep. Those are two of the benchmarks.
Sunday, March 15, 2009 at 2:04pm by Ms. Sue

AE.. does it sound ok
waht is another way of saying convey?
Sunday, March 15, 2009 at 4:38pm by scooby91320002

AE
How will responsibilities as a teacher influence the rights of a student?
Sunday, March 29, 2009 at 4:54pm by scooby91320002

AE
Exactly! It's a very good example to use.
Sunday, March 29, 2009 at 5:30pm by Writeacher

AE.. does it sound ok
ok so go onto the next one?
Sunday, April 12, 2009 at 9:48pm by scooby91320002

AE
I have no idea how to do the paper if I am not on the right track.
Thursday, April 30, 2009 at 4:12pm by scooby91320002

AE
Yes. Education pregnant teens Wisconsin
Sunday, May 31, 2009 at 12:46pm by Ms. Sue

geometry
find x if ac=2x-1 and ae=x2-2
Sunday, September 18, 2011 at 4:23pm by Anonymous

AE
Why is "WHY" even here at all in the first place??
Saturday, July 26, 2008 at 12:32am by LeeLoo

geometry
AB = AE BC = DE prove 1 = 2
Saturday, November 16, 2013 at 1:51pm by Anonymous

math
I will assume that D is the midpoint of AB draw the median from A to BC to meet BC at E let the intersection of these two medians be F Since you have an isosceles triangle that median will meet BC at right angles. Also the medians intersect each other in the ratio of 2:1, the ...
Sunday, March 13, 2011 at 4:45pm by Reiny

AE
what are some laws pertaining to special needs students?
Thursday, August 21, 2008 at 3:05pm by scooby91320002

AE
Scooby, I gave you a series of sites on that topic yesterday.
Thursday, August 21, 2008 at 3:27pm by GuruBlue

AE
Once again, practice your searching skills. Sra
Friday, August 22, 2008 at 11:45pm by SraJMcGin

AE
ok now i am on the right track. just time to reword it
Sunday, March 15, 2009 at 2:04pm by scooby91320002

AE
I am right there with Writeacher! So long as they want to do it my way, they can do what they want <G>
Sunday, March 29, 2009 at 4:54pm by GuruBlue

AE ( last and final one)
should i put that for the answer to that question??
Sunday, March 29, 2009 at 5:57pm by scooby91320002

AE
Which approach are you taking -- the behaviorist or the constructivist theory?
Sunday, April 12, 2009 at 8:05pm by Ms. Sue

AE
sorry i want contructivist becasue it deals with hands on activity
Sunday, April 12, 2009 at 8:05pm by scooby91320002

AE..
i just want to see some sites as an example if that helps
Sunday, April 12, 2009 at 8:30pm by scooby91320002

AE..
i just want to see some sites as an example if that helps
Sunday, April 12, 2009 at 8:30pm by scooby91320002

AE
need infor on teacher discipline strategies plz
Sunday, April 12, 2009 at 11:19pm by scooby91320002

AE
List 3-5 factors that define teaching as a professional career.
Friday, May 8, 2009 at 6:47pm by scooby91320002

AE
would teen preganncy work? what other should be?
Sunday, May 31, 2009 at 12:46pm by scooby91320002

AE .
what can i say for a seond one that happened in 2000-present?
Friday, June 19, 2009 at 8:37pm by scooby91320002

Reaction Descriptions
1. abd 2.bf 3. cf 4. cd 5. don't know 6. ae
Wednesday, January 12, 2011 at 9:46pm by anonymous

geometry
make a diagram Triangle ABC with AB=17, BC=8 and AC = 15 Did you realize that your triangle is right-angled, with angle C = 90° ? let the points of contact of the circle be D on BC, E on AC, and F on AB Two properties we can use ... 1. The centre of the incscribed circle lies ...
Tuesday, June 8, 2010 at 7:03am by Reiny

AE
This site may give you some ideas. (Broken Link Removed)
Thursday, July 24, 2008 at 11:40pm by GuruBlue

AE,, this right?>(revised)