Friday

April 18, 2014

April 18, 2014

Number of results: 93,101

**MITx: 6.002x Circuits and Electronics**

to add capacitors in parallel Ceq = C1 + C2 because C = Q/V V the same, charges add to add capacitors in series q is the same on both in general V = C Q here V = V1 + V2 = C1 q + C2 q V/q = (C1+C2) so Ceq = q/V = 1/(C1 + C2)
*Saturday, February 8, 2014 at 11:05am by Damon*

**Physics**

Three parallel plate capacitors (C1,C2 and C3 ) are in series with a battery of 100 V. C1=2500 micro Farad; C2=2C1 , C3=3C1 . (a) What is the potential difference over each capacitor and how much charge is on each capacitor? Across C1 :V1 (in Volts) = incorrect Q1 (in C) = ...
*Wednesday, March 13, 2013 at 12:19am by P*

**physics**

This is the situation I have been given: You are given three capacitors, one with a capacitance of 0.025 micro-farads, another with a capacitance of 0.05 micro farads, and the third with a capacitance of 0.015 micro-farads. Using only these capacitors, arranged in series, ...
*Thursday, October 11, 2012 at 7:04pm by Rachel*

**physics**

lets say two capacitors C1 and C2 1uF each are connected in series with a voltage source 5v. One of the capacitors C2 has an initial voltage of 1v and the other has no charge on it initially.What is the final voltages across the capacitor C2?
*Monday, September 10, 2012 at 4:37am by Venkatarama*

**physics**

lets say two capacitors C1 and C2 1uF each are connected in series with a voltage source 5v. One of the capacitors C2 has an initial voltage of 1v and the other has no charge on it initially.What is the final voltages across the capacitor C2?
*Monday, September 10, 2012 at 8:36am by Venkatarama*

**physics**

Capacitors in series subract. Capacitors in parallel add. #2. !/c = 1/c1 + 1/c2 You know c and c2, substitute and solve for c2.
*Tuesday, October 15, 2013 at 12:44am by DrBob222*

**Physics **

Two capacitors are connected in parallel as shown above. A voltage V is applied to the pair. What is the ratio of charge stored on C1 to the charge stored on C2, when C1 = 1.5C2 ? how do you do this? ( The answer is 3/2) Thanks for helping ; ) I appreciate that
*Friday, February 4, 2011 at 2:12am by Amanda C.*

**PHYSICS**

Two capacitors are connected to a battery. The battery voltage is V = 60 V, and the capacitances are C1 = 2.00 μF and C2 = 4.00 μF. Determine the total energy stored by the two capacitors when they are wired (a) in parallel and (b) in series.
*Saturday, February 2, 2013 at 12:53pm by PLEASE HELP *

**physics**

Put the capacitors in series with the 4.5 V of batteries in series. Although no DC current will flow, the voltage drop across the two capacitors will be in inverse proportion to the capacitances. C1/C2 = V2/V1 With one known capacitance C1, you can solve for C2. You do not ...
*Saturday, February 13, 2010 at 3:47am by drwls*

**physics - capacitors**

Capacitors C1 = 5.0 µF and C2 = 2.0 µF are charged as a parallel combination across a 150 V battery. The capacitors are disconnected from the battery and from each other. They are then connected positive plate to negative plate and negative plate to positive plate. Calculate ...
*Saturday, July 10, 2010 at 11:39pm by lo*

**Physics**

A)Two identical resistors are connected in parallel across a 30-V battery, which supplies them with a total power of 7.0 W. While the battery is still connected, one of the resistors is heated so that its resistance doubles. The resistance of the other resistor remains ...
*Saturday, October 22, 2011 at 8:33pm by Kristi*

**Physics**

A)Two identical resistors are connected in parallel across a 30-V battery, which supplies them with a total power of 7.0 W. While the battery is still connected, one of the resistors is heated so that its resistance doubles. The resistance of the other resistor remains ...
*Monday, October 24, 2011 at 12:56pm by Kristi*

**physics**

Vm = Xc Im Xc = 1/ωC therefore for fixed V I2/I1 = C2 /C1 C2 = 4.2C1 + C1 = 5.2C1 (they are connected in parallel) I2 = (C2/C1)I1 = 5.2*0.22 = 1.144 A
*Tuesday, November 13, 2012 at 1:33pm by Kay*

**physics**

Three capacitors with C1=C2=C3= 10.00 uF are connected to battery with voltage V= 194 V. What is the voltage across capacitor C1
*Wednesday, November 23, 2011 at 11:50pm by JL*

**physics!!!**

Two capacitors, C1 = 27.0 µF and C2 = 35.0 µF, are connected in series, and a 21.0 V battery is connected across them. (a) Find the equivalent capacitance, and the energy contained in this equivalent capacitor. equivalent capacitance= µF total energy stored= (b) Find the ...
*Friday, January 27, 2012 at 11:08am by Help*

**probability**

By symmetry this is 1/3! P(X,Y,Z are all different) P(X,Y,Z are all different) = 1- P(X,Y,Z are not all different) X,Y,Z are not all different if and only if one or more of the three conditions are satisfied: c1: X = Y c2: X = Z c3: Y = Z Terefore: P(X,Y,Z are not all ...
*Tuesday, November 20, 2007 at 2:36am by Count Iblis*

**Physics**

Two fully charged capacitors (C1 = 2.00uF, q1=6.00uC,C2=8.00uF, q2 = 12.0 uC). The switch is closed, and the charge flowed until equilibrium is re-established, which occurs when both capacitors have the same voltage across their plates. Find the resulting voltage across either...
*Wednesday, February 17, 2010 at 8:09pm by Eric*

**PHYSICS**

Two capacitors, C1=25.0x10^-6 and C2=5.0x10^-6 are connected in parallel and charged with a 100-V power supply. a)calculate the total energy stored in the 2 capacitors b) what potential difference would be required across the same 2 capacitors connected in series in order that...
*Monday, February 4, 2008 at 2:33am by nat*

**MATHS**

two circles c1 and c2 meet at the points A and B. CD is a common tangent to these circles where C and D lie on the circumference of C1 and C2 respectively. CA is the tangent to c2 at A. When produced DB meets the circumference of C1 at p. Prove that PC is parallel to AD
*Thursday, August 18, 2011 at 6:51am by JJ*

**whoops**

in general q/C here V = V1 + V2 = q/C1 + q/C2 V/q = (1/C1+1/C2) so Ceq = q/V = 1/(1/C1 + 1/C2) = C1 C2 /(C1+C2)
*Saturday, February 8, 2014 at 11:05am by Damon*

**Calculus - Second Order Differential Equations**

Solve the initial-value problem. y'' - 2y' + y = 0 , y(2) = 0 , y'(2) = 1 r^2-2r+1=0, r1=r2=1 y(x)=c1*e^x+c2*x*e^x y(2)=c1*e^2+c2*2*e^2=0 c1=-(2*c2*exp(2))/exp(2) c1=-2*c2 y'(x)=-2*c2*e^x+c2*e^x*(x-1) y'(2)=-2*c2*e^2+c2*e^2*(2-1)=1 c2(-2e^2+e^2)=1 c2=1/(-2e^2+e^2)=1/(-e^2) c1...
*Tuesday, July 10, 2007 at 4:15am by COFFEE*

**social studies**

What is the total capacitance of capacitors connected in series, C1=444F, C2=621F
*Monday, March 25, 2013 at 5:43am by Trevor*

**Calculus-HELP!!!!**

y=c1 e^x cos(x)+ c2 e^x sin(x) y(0) = 1 , so 1 = c1 e^0 cos 0 + c2 e^0 sin 0 1 = c1 + 0 c1 = 1 y' = c1 e^x (-sin(x)) + c1 e^x cosx + c2 e^x cos(x) + c2 e^x sinx = e^x( - c1 y'(0) = -1 -1 = c1 e^0 (-sin 0) + c2 e^0 cos 0 -1 = 0 + c2 c2 = -1 y'' = c1 e^x (-cos(x)) + c2 e^x (-sin...
*Tuesday, July 2, 2013 at 9:08pm by Reiny*

**Calculus**

y = c1 e^-6x + c2 e^x Plug in your boundary conditions, and you get c1 + c2 = 0 c1/e^12 + c2/e^2 = 1 Now just solve for c1 and c2
*Sunday, March 16, 2014 at 6:39pm by Steve*

**maths**

What is the total capacitance of capacitors connected in series, C1=25F, C2=125F ? Round result to whole number.
*Tuesday, February 26, 2013 at 6:24am by mano*

**Calculus - Second Order Differential Equations**

Solve the boundary-value problem. y''+5y'-6y=0, y(0)=0, y(2)=1 r^2+5r-6=0, r1=1, r2=-6 y=c1*e^x + c2*e^-6x y(x)=c1*e^x+c2*e^-6x y'(x)=c1*e^x-6*c2*e^-6x y(0)=c1+c2=0, c1=-c2 y(2)=c1*e^2+c2*e^(-12)=1 -c2*e^2-6c2*e^(-12)=1 -c2(e^2-6*e^-12)=1 c2=-1/(e^2-6e^-12) c1=1/(e^2-6e^-12) y...
*Monday, July 9, 2007 at 8:19pm by COFFEE*

**Physics**

I have a circuit with three capacitors and a battery. The battery supplies 15V. The battery is in series with C3. C3 is in series with ( C23). C3= 3*10^-6 F C2= 2 *10^-6 F C1= 1*10^-6 F (respectively C2 +C3 are is parallel withe ach other). I know the equivalent capacitance ...
*Wednesday, February 10, 2010 at 6:57pm by Sara*

**Calculus**

y = e^x (c1 + c2*x) y' = e^x (c1 + c2 + c2*x) Now plug in the initial conditions to get e^2 (c1 + 2c2) = 0 e^2 (c1 + c2 + 2c2) = 1 Now just solve for c1 and c2
*Sunday, March 16, 2014 at 6:40pm by Steve*

**Solve**

Solve 1/C=1/C1 + 1/C2 for C1 This multiple choice and the listed answers are: a.)C1= CC2/(C2-C) b.)C1= C-C2/C c.)C1= C+C2/CC2 d.)C1= C+C2/C2
*Sunday, October 12, 2008 at 11:35am by Shawn*

**physics - capacitors**

C1 acquires C1*V = 7.5*10^-4 C and C2 acquires C2*V = 3.0*10^-4 C, initially. When rewired, there is a total of 4.5*10^-4 C on the positive-plate sides and -4.5*10^-4 C on the negative-plate sides. The charges redistribute to maintain the same potential on each capacitors. (2/...
*Saturday, July 10, 2010 at 11:39pm by drwls*

**Physics**

Four capacitors are connected in series with a battery, as in the figure below, where C1 = 3.24 µF, C2 = 6.11 µF, C3 = 12.1 µF, C4 = 25.0 µF, V = 18.4 V. (a) Calculate the capacitance of the equivalent capacitor. µF (b) Compute the charge on C3. µC (c) Find the voltage drop ...
*Friday, September 17, 2010 at 12:07am by Max*

**Physics**

question 9 a: Ec1=Voltage/plate separation b: because the battery is connected the E field does not change c: when the battery is disconnected then Q1+Q2 must equal Q1'+Q2' Ec1=Q1'/(k*C1*d) and Ec2=Q2'/(C2*d) where Q1'=(Q1+Q2)/(1+(C2/K*C1) and Q2'=C2/(K*C1)*(Q1+Q2)/(1+(C2/K*C1))
*Saturday, June 15, 2013 at 4:36am by boss*

**Math another problem**

Subtract 1/C2 from each side. 1/C1 = 1/C - 1/C2 = (C2-C)/(C*C2) Now turn both fractions upside down. This is called "taking the reciprocal of both sides" C1 = C*C2/(C2 - C) = 1/[(1/C) - (1/C2)]
*Sunday, October 12, 2008 at 12:25am by drwls*

**Discrete Math**

"So the characteristic roots are 1?" Correct! For _n+1 = -8a_n – 16a_n - 1, n ≥ 1, given a₀ = 5, a₁ = 17. you have correctly solved for λ=-4, and the solution is an=C1(-4)^n+C2*n*(-4)^n which simplifies to: an=(C1+nC2)(-4)^n a0=5=(c1+0*C2)(-4)^0=C1, so...
*Tuesday, April 5, 2011 at 4:11pm by MathMate*

**Physics**

you have 8microC total charge. You have 23microF capacitance. Voltage= Qtotal/C=8/23 volts. on C1, q=C1*8/23=7micro*8/23=56/23 micro F on C2, q=16micro*8/23=128/23 microC adding q1+q2, 184/23 microF=8microF
*Tuesday, February 14, 2012 at 9:45pm by bobpursley*

**Physics-(correction)**

I meant C3 is in series with C2 and C1 which means that C2 and C1 are in parallel
*Wednesday, February 10, 2010 at 6:57pm by Sara*

**PHYSICS**

Two capacitors C1 = 7.00 µF and C2 = 11.0 µF are connected in series to a 9.00 V battery. (a) Find the equivalent capacitance of the combination. µF (b) Find the potential difference across each capacitor. (c) Find the charge on each capacitor.
*Monday, October 14, 2013 at 1:47pm by HELP!!!*

**Math**

Two circles C1 and C2 touch externally at A. The tangent to C1 drawn at a point B on the circumference of C1 meets C2 in P and Q so that P is between B and Q. QA is produced and meets C1 at X. Prove that angle XAB = angle PAB.
*Wednesday, September 19, 2012 at 7:48am by Jun*

**Science ; Micro-organisms**

i have to finished this cross word , and i need help on the last two . So thank you if you can solve it :) A substance that micro organisms can be grown on . its a 4 letter word. A group Of Micro Organisms , its a 6 letter word.
*Thursday, April 16, 2009 at 1:55pm by Saffron.*

**Physics**

Ceq(c1,c2):3uF. This combination is in series with the 3uF capacitor and both are connected to the 15v battery. The voltage will get divided equally since they are both of the same value(7.5v). Hence energy would be. Both c1 and c2 have 7.5v across them since they are in ...
*Wednesday, February 10, 2010 at 6:57pm by Venkatarama*

**physics**

What is the force exerted on 40 micro coulombs by 20 micro coulombs? (charges are separated by 80cm)
*Wednesday, May 2, 2012 at 6:16pm by paul*

**physics**

Calculate the magnitude and direction of the Coulomb force on each of the three charges connected in series: 1st - 6 micro Coulombs (positive charge) 2nd - 1.5 micro Coulombs (positive charge) 3dr - 2 micro Coulombs (negative charge) Distance between 1st and 2nd - 3cm Distance...
*Wednesday, May 16, 2012 at 11:19pm by andrew*

**physics**

Calculate the magnitude and direction of the Coulomb force on each of the three charges connected in series: 1st - 6 micro Coulombs (positive charge) 2nd - 1.5 micro Coulombs (positive charge) 3dr - 2 micro Coulombs (negative charge) Distance between 1st and 2nd - 3cm Distance...
*Monday, May 21, 2012 at 7:35am by andrew *

**physics**

A C1= 2.50uF capacitor is charged to 862 V and a C2= 6.80uF capacitor is charged to 660 V . These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to each other. What will be the ...
*Friday, March 8, 2013 at 6:32pm by Steve*

**physics**

An infinite sheet with a surface charge density of -2.1 micro-coulombs/m2 runs parallel to the x axis. Another infinite sheet a surface charge density of +2.1 micro-coulombs/m2 runs parallel to the y axis. A charge of -4.1 micro-coulombs moves at a 45 degree angle towards the ...
*Friday, February 10, 2012 at 8:33am by Mandaleigh*

**Physics**

The drawing shows two fully charged capacitors (C1 = 7 µF, q1 = 4 µC; C2 = 16 µF, q2 = 4 µC). The switch is closed, and charge flows until equilibrium is reestablished (i.e., until both capacitors have the same voltage across their plates). Find the resulting voltage across ...
*Tuesday, February 14, 2012 at 9:45pm by Laura*

**Math**

two charges of +2.6 micro c and -5.4 micro C experience an attractive force of 6.5 mN.what is separation between the charges?
*Sunday, February 12, 2012 at 10:43am by sheldan*

**business-economics**

Suppose that there is a common resource of size y in a two period society. Each of two citizens, one and two, can withdraw a nonnegative amount c1 or c2 for consumption in period one, provided that c1+c2 <=y . In the event that they attempt to consume in excess of what is ...
*Wednesday, September 14, 2011 at 3:11pm by quynh*

**Physics **

Capacitors in parallel have the same voltage V applied to each. The stored charge on each is CV. Since V is the same the ratio of charges is the ratio of capacitances, C. Q1/Q2 = C1/C2 = 1.5
*Friday, February 4, 2011 at 2:12am by drwls*

**Math**

Two small conducting spheres are identical except that sphere x has a charge of -10 micro coulombs and sphere y has a charge of + 6 micro coulombs . After the spheres are brought in contact and then separated,what is the charge on each sphere ,in micro coulombs ?
*Thursday, August 18, 2011 at 5:21pm by Troy*

**emily**

What is the potential halfway between two point charges spaced 1 mm apart if q1=10 micro culumbs and q2= -5 micro culumbs
*Wednesday, February 15, 2012 at 8:28pm by physics*

**Calculus Antiderivative Problem**

v = 1/3 (t+2)^2 + c1 x = 1/6 (t+2) + c1*t + c2 now plug in the given conditions when t=0 to find c1 and c2
*Friday, November 8, 2013 at 7:29pm by Steve*

**physics HELP MEEE SO CONFUSED**

What is the potential halfway between two point charges spaced 1 mm apart if q1=10 micro culumbs and q2= -5 micro culumbs
*Wednesday, February 15, 2012 at 9:03pm by bel *

**Physics**

The capacitor with the dielectric (#2) will have 4.2 times the C-value of the air-gap capacitor (#1). Let's call the capacitances C1 and C2 = 4.2 C1. Since the energies (E) are equal, E1 = (1/2) C1 V^2 = E2 = (1/2) C2 V2^2 C1 * 18^2 = (4.2 C1) * V2^2 V2^2 = (1/4.2) * 324 Solve...
*Monday, September 3, 2007 at 11:02am by drwls*

**Math/Calculus**

A series circuit contains a resistor with R = 24 ohms, an inductor with L = 2 H, a capacitor with C = 0.005 F, and a generator producing a voltage of E(t) = 12 sin(10t). The initial charge is Q = 0.001 C and the initial current is 0. (a) Find the charge at time t. 2Q"+24Q'+...
*Thursday, July 12, 2007 at 12:49am by COFFEE*

**Physics**

a. C = C1*C2/(C1+C2) = 30 uF 33.6*C2/(33.6+C2) = 30 33.6C2 = 1008+30C2 33.6C2-30C2 = 1008 3.6C2 = 1008 C2 = 280 uF In series. b. C1 + C2 = 30 uF 29.3 + C2 = 30 C2 = 30 - 29.3 = 0.7 uF in parallel.
*Tuesday, October 15, 2013 at 11:33pm by Henry *

**micro**

What media? Micro what? This sounds like a question from a lab experiment you were supposed to perform. We need the details
*Tuesday, February 19, 2008 at 11:28am by drwls*

**Physics**

m1=2 kg, c1= 0.107 cal/(g*K)= 448 J/kg•K, T1=273+70=343.15 K, m2=1kg, c2=4185 J/kg•K, T2=273+15=288.15 K Q1 =m1•c1(T1-Tₒ) = m1•c1•T1- m1•c1•Tₒ Q2 = m2•c2• ( Tₒ-T2) = m2•c2•Tₒ- m2•c2•T2 Q1=Q2 m1•c1•T1- m1•c1•Tₒ= m2•c2•Tₒ- m2•c2•T2 m1•c1•T1+ ...
*Sunday, July 1, 2012 at 10:06pm by Elena*

**Calculus-HELP!!!**

The solution will be c1 e^k1x + c2 e^k2x where k1 and k2 are the roots of 2x^2+x-4=0. x = (-1±√33)/4 So, y = c1 e(-1+√33)/4 x + c2 e(-1-√33)/4 x y(0) = 0, so c1+c2=0 y'(0) = 1 so (-1+√33) c1 + (-1-√33) c2 = 1 c1 = 1/(2√33) c2 = -1/(2√33)
*Saturday, July 20, 2013 at 9:10pm by Steve*

**potential**

What is the potential halfway between two point charges spaced 1 mm apart if q1=10 micro coulumbs and q2= -5 micro coulumbs?
*Thursday, February 16, 2012 at 11:38am by anne*

**Physic**

Capacitors in parallel: Give as clear as explanation as possible as to why it is physically reasonable to expect that two identical parallel plate capacitors are placed in parallel ought to have twice the capacitance as one capacitor.
*Sunday, March 30, 2014 at 7:04pm by ikine4*

**PHYSICS**

Determine the equivalent capacitance between A and B for the group of capacitors in the drawing. Let C1 = 12 µF and C2 = 4.0 µF.
*Friday, March 4, 2011 at 10:37pm by YANA*

**Calculus II**

There IS an antiderivative (integral) of 1/x. It is the natural log-base-e (ln) function. In your case f'(x) = -1/x + C1 f"(x) = - ln x + C1 x + C2 where C1 and C2 are arbitrary constants
*Saturday, January 24, 2009 at 11:07pm by drwls*

**phys**

m1 = 10.9•10^-3 kg, v =400 m/s, t(o) = 20oC, m2 = 0.4 kg,. specific heat of the iron and wood, respectively, c1 = 444 J/kg, and c2 = 1700 J/kg. (a) m1•v^2/2 = 10.9•10^-3•(400)^2/ 2 =872 J = QQ/ Q = m1•c1•Δt, Δt = Q/ m1•c1 = 872/10.8•10^-3•444 = 180oC. t(new) = 20oC...
*Thursday, April 26, 2012 at 1:12am by Elena*

**Calculus**

Great! I understand now that C0=f(a) c1=f'(a) c2=f"(a)/2 Now, If I am to find the parabolization of the equation x^2-x at x=2, then c0=x^2-x=2^2-2=2 c1=2x-1=2(2)-1=3 c2=2/2=1 So, the equation (taken from c0+c1(x-a)+c2(x-a)^2) is >> 2+3(x-2)+1(x-2)^2?? Is this correct? ...
*Monday, November 13, 2006 at 8:17pm by Matt*

**science**

You can count the number of (micro) craters on the surface of the rock. Knowing the age of te rock, you then know the flux of micro meteorites. Using this information you can deduduce how old a surface is by counting the number of (micro) craters per unit area
*Wednesday, March 12, 2008 at 5:50pm by Count Iblis*

**Physics please help **

What is the potential halfway between two point charges spaced 1 mm apart if q1=10 micro coulombs and q2= -5 micro coulombs? Attempt at solution: no idea but need to get this right our homework is graded
*Wednesday, February 15, 2012 at 9:30pm by bel *

**physics**

The potential diffrence across a series combination of 4(micro)F and 12(micro)F capacitor is 240V. What is the potential diffrence across 4(micro)F capacitor?
*Wednesday, January 11, 2012 at 11:33am by Nuwaya*

**Physics**

Ct = C1*C2/(C1+C2) = 8.3*2.9/(8.3+2.9) = 2.15 uF Qt = Ct*E = 2.15 * 24 = 51.6 uC.=Q1=Q2. Energy=0.5C*E^2 = 0.5*2.15*24^2 =619.2 Joules Parallel Combination: Ct = C1 + C2 = 8.3 + 2.9 = 11.2 uF. Energy = 0.5*Ct*E^2 = 619.2 Joules 0.5*11.2*E^2 = 619.2 5.6E^2 = 619.2 E^2 = 110.6 E...
*Wednesday, October 16, 2013 at 2:01pm by Henry *

**Discrete Math**

Solve the recurrence relation: an+1 = 7an – 10an-1, where n ≥ 2, and given a₁ = 10, a₂ = 29. You have done the first step to give: λ1=2, λ2=5. So the function is defined by the powers of λ1 and λ2, with the associated constants C1 ...
*Tuesday, April 5, 2011 at 4:11pm by MathMate*

**electronics technician**

There is no way I will answer all of these. If you try yourself someone might help. The first one is just common sense. Capacitance is charge per unit voltage. With two capacitors in parallel they are both at the same voltage, so each has charge corresponding to that voltage, ...
*Tuesday, June 18, 2013 at 9:52am by Damon*

**physics**

A point charge of +10 micro-coulombs lies at x = -0.39 m, y = 0 m, a point charge of -5.7 micro-coulombs lies at x = +0.39 m, y = 0 m, and a point charge of +14.9 micro-coulombs lies at x = 0 m, y = -0.3 m. A point charge of +10 micro-coulombs is moves from x = 0 m, y = +0.11 ...
*Friday, February 10, 2012 at 8:32am by Mandaleigh*

**Electrons circuits**

Hi everyone! I'm new in here. Recently I bought a movement monitor which detects micro movement. If the sensor does not detect a movement in 20 seconds, the build-in speaker will beep until the sensor detects a movement. I'm using it for my project and I have a question about ...
*Friday, April 4, 2008 at 11:26pm by Jacky*

**Math/Calculus**

Solve the initial-value problem. Am I using the wrong value for beta here, 2sqrt(2) or am I making a mistake somewhere else? Thanks. y''+4y'+6y=0, y(0)=2, y'(0)=4 r^2+4r+6=0, r=(-4 +/- sqrt(16-4(1)(6))/2 r=-2 +/- sqrt(2)*i , alpha = -2, beta = 2(sqrt(2)) y=e^-2x*(c1*cos(sqrt(2...
*Thursday, July 12, 2007 at 12:15am by COFFEE*

**Calculus**

Please look at my work below: Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/- Sqrt(4^2-4(1)(6)))/2(1) r=(16 +/- Sqrt(-8)) r=8 +/- Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2 y'(0)=4, c2=4 y(x)=e^(...
*Tuesday, July 10, 2007 at 2:08pm by COFFEE*

**Math**

2 circles C1 and C2 meet at the points A and B. Points C and Dare points on the circumferences of C1 and C2 respectively such that angle CAB = angle DAB. CD cuts C1 and C2 at the points Y and X respectively. if Z is the foot of the perpendicular from X to BY, prove that angle ...
*Wednesday, September 19, 2012 at 7:30am by Jun*

**physics**

1) 2 spheres of equal diameters have 15 micro coulomb charge and -10 micro coulomb charge respectively. if they are placed 5cm apart what will be the force of attraction between them? 2) a charge of .5 micro coulomb is placed in an electric field whose intensity is 4x10^5n/c...
*Sunday, October 10, 2010 at 2:13pm by Deyo*

**economics**

Do you think lotteries have both micro and macro economic effects or only micro? How do lotteries change what and for whom goods and services are produced?
*Sunday, September 18, 2011 at 5:20pm by Emily*

**Discrete Math**

For 9:05 pm an=(C1+nC2)1^n=C1+nC2 a0=40 => C1=40 a1=31 => 31=(40+1*C2) => C2=-9 Maybe you should show your work how you got C2=-3
*Tuesday, April 5, 2011 at 4:11pm by MathMate*

**MATH**

Differential equations, initial value problem. The general equation of motion is: mx"+Bx'+kx=f(t), where the independent variable is t, and the displacement x is the dependent variable. In this case, external force f(t)=0, so mx"+Bx'+kx=0 substitute m=0.25, k=4, B=1 we have a ...
*Wednesday, March 16, 2011 at 1:54pm by Anonymous*

**Solve**

Okay I understand it now I have to make them have the same denominators so I multiply 1/C by the numerator and denominator by C2 so it would be C2/(C2*C) and the other part is 1/C2 times C which would be C/(C2*C) which would make the problem 1/C1= C2-C/(C2*C) what do I do next?
*Sunday, October 12, 2008 at 11:35am by Shawn*

**physics2**

A charge of -6.5 micro-Coulombs is placed at the origin of a coordinate system. Another charge of -7.6 micro-Coulombs is placed at x = +0.29 m, y = +0.17 m. A third charge of +14 micro-Coulombs is placed at x = -0.29 m, y = 0 m. What is the magnitude of the total electric ...
*Saturday, January 29, 2011 at 12:06pm by kelly*

**Physics**

Two charges are arranged on the x axis so that there is a positive charge of 3.6 micro C at the orgin and a negative charge of -2.5 micro C located 2 centimeters to its right. to the nearest centimeter, where on the x axis should a positive charge be placed so that the net ...
*Friday, March 21, 2008 at 12:44pm by Maria Lewis*

**Physics**

Two charges are arranged on the x axis so that there is a positive charge of 3.6 micro C at the orgin and a negative charge of .2.5 micro C located 2.5 centimeters to its right. to the nearest cetimeter, where on the x axis should a positive charge be placed so that the net ...
*Friday, March 21, 2008 at 1:04pm by Maria Lewis*

**Calculus**

Find f'(x) and see if there is a zero (root) on the interval. If not, the extrema are the two limits of the interval. Check the sign of f'(x) on the interval. If there is no zero on the interval, the sign should not change (+ OR -). If f'(x) is + on the interval, it is ...
*Thursday, November 4, 2010 at 7:00am by MathMate*

**medicine**

It is understood to be mass/volume for ease of dosage calculations. Therefore whether it is 0.9% saline or simply water, the proportions are the same. You can do the calculations as follows: Suppose we need v ml of c1% concentrated dextrose diluted with 1000 ml of liquid to ...
*Saturday, September 18, 2010 at 4:38pm by MathMate*

**Functions/Logarithims**

Replace C2 by 2C1 E = 1.4 log 2C1/C1 = 1.4 log 2 If C1<C2 then C1/C2 < 1 and the log is < 0 I assume negative energy needed means energy is released.
*Thursday, March 8, 2012 at 8:35pm by Steve*

**physics**

what is the electric field at the position 20 cm from Q2 and 60 cm from Q1? Q2=40 micro coulombs Q1=20 micro coulombs Q2 and Q1 are separated by 80 cm
*Wednesday, May 2, 2012 at 7:20pm by quinton*

**Physics 2**

2 spheres of equal diameters have a positive 15 micro column and negative 10 micro column charge if they are place 5 cm apart what would be the force of attraction between them.
*Tuesday, January 28, 2014 at 6:40am by schenncyl*

**physics**

c1•m1 •(310-25.4) =c2•m2•(25.4-20.2) m1= { c2•m2•(25.4-20.2)}/ c1•(310-25.4) = ={4180•1.1•5.2}/385•284.6 = 0.218 kg
*Thursday, August 9, 2012 at 10:38pm by Elena*

**Physics**

Calculate the coulomb force on q. They are all in a straight line q1, q2,q3. Q1:1.05 micro coulombs Q2:5.51 micro coulombs Q3:-2.15 micro coulombs The distance, r1, between q1 and q2 is 20.1cm. The distance, r2, between q2 and q3 is 15.3 cm. Also, calculate e coulomb force on q2
*Tuesday, July 9, 2013 at 9:21am by Amalia*

**calculus**

take integrals across the equation 2ff' - 2gg' = 0 ∫2f df - ∫2g dg = 0 (f^2 + c1) - (g^2 + c2) = 0 f^2 - g^2 = -(c1+c2) = c
*Sunday, October 21, 2012 at 2:13pm by Steve*

**physics 2**

A charge of -6.8 micro-Coulombs is placed at x = 0, y = 0. A charge of -18.5 micro-Coulombs is placed at x = 0, y = +37 cm. Another charge of -12.9 micro-Coulombs is placed at x = +17 cm, y = 0 cm. What is the angle the total electric force on the charge at x = +17 cm, y = 0 ...
*Friday, January 18, 2013 at 2:18pm by Jessica *

**Discrete Math**

What method are you expected to use to solve the recurrence relation? Have you covered characteristic polynomials or generating functions? You seem to give me the hint that you have done characteristic polynomials, so I will solve this by characteristic polynomials. The key is...
*Tuesday, April 5, 2011 at 4:11pm by MathMate*

**Diff eqn- IVP**

Differential equations, initial value problem. The general equation of motion is: mx"+Bx'+kx=f(t), where the independent variable is t, and the displacement x is the dependent variable. In this case, external force f(t)=0, so mx"+Bx'+kx=0 substitute m=0.25, k=4, B=1 we have a ...
*Thursday, March 10, 2011 at 9:45pm by MathMate*

**Physics**

I assume in ax=bt, x is a subscript and not a variable. 'a' will be used from here on. Since initial conditions are all known, the function X(t) can be found by integrations. b=3.0 m/s³ a(t) = bt V(t) = ∫a(t) + C1 = (b/2)t² + C1 since V(0)=Vo=0, C1=0, therefore V...
*Thursday, October 8, 2009 at 7:34am by MathMate*

**Economics**

Here goes... 1. Consider a model in which an individual lives two periods: this period (time one) and next period (time two). This period his budget constraint requires that his consumption, c1; plus his saving, s; equals his income, y1: c1 + s = y1: Next period his budget ...
*Sunday, September 30, 2012 at 9:25pm by Wesley*

**Physics**

What is the electric field at a point midway between a -7.34 micro coulombs and a +4.49 micro coulombs charge apart 31.5m apart?
*Tuesday, July 9, 2013 at 9:17am by Amalia*

**physics**

what is the electric field at the center of the square? q1 and q2 = -10 micro coulombs q3 and q4= 5 micro coulombs each side is 0.10 m. How do i set this up?
*Thursday, July 7, 2011 at 6:18pm by Sarah (C)*

** - Physic college**

The equation for the change of position of a train starting at x = 0 is given by x=1/2at^2 + bt3 . Find the dimensions of a and b. If y = C1 sin (C2 t) where y is a distance and t is the time. What are the dimensions of C1 and C2 ?.
*Friday, October 1, 2010 at 7:03am by meera*

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