Saturday

April 19, 2014

April 19, 2014

Number of results: 23,994

**Trig - Thanks Damon**

Thanks for the help Damon. Much appreciated. Don
*Saturday, December 17, 2011 at 5:12pm by Don*

**trig**

yes, that is what I said. Cot 45 = 1/tan 45 = 1 I also did the other trig functions of 45 because I am sure you will need them.
*Monday, May 19, 2008 at 6:32pm by Damon*

**trig - go with Damon**

dang - go with Damon again. I used a 35" radius. Note to self: read twice, type once.
*Thursday, January 23, 2014 at 5:58pm by Steve*

**Trig.**

(p-8)(p-8) = 0 p = 8 y^3/2 = 8 y^3 = 8*8 y = 2*2 = 4
*Wednesday, January 9, 2008 at 8:55pm by Damon*

**trig**

(s^2/c^2)( 1+ c^2/s^2) = ? 1/(1-s^2) s^2/c^2 + 1 = ? 1/(c^2) (s^2+c^2)/c^2 = = ? 1/(c^2) 1/c^2 = 1/c^2
*Friday, March 26, 2010 at 12:16am by Damon*

**Trig**

Thanks Damon.
*Sunday, January 8, 2012 at 7:49pm by Don*

**trig**

b/1 = b
*Thursday, January 26, 2012 at 10:14pm by Damon*

**trig**

You are welcome :)
*Thursday, February 6, 2014 at 3:18pm by Damon*

**Trig.**

(s^2/c^2)(1/s) - s^2/c^2 (s^2/c^2) [ 1/s -1 ] (s^2/c^2)(1-s)/s (s/c^2)(1-s) I do not know what more can be done.
*Sunday, January 10, 2010 at 6:17pm by Damon*

**Trig**

1 + cot^2
*Tuesday, December 20, 2011 at 9:57pm by Damon*

**Trig**

Yes, correct
*Tuesday, December 27, 2011 at 6:42pm by Damon*

**Trig**

Yes, correct
*Tuesday, December 27, 2011 at 6:39pm by Damon*

**Trig**

1/a by definition
*Friday, January 27, 2012 at 6:12pm by Damon*

**trig**

when is 3 x = 2 pi ?
*Sunday, April 22, 2012 at 5:56pm by Damon*

**Damon - trig**

Damon, when I opened the page and started to answer this question, I left it alone to watch the end of the WorldCup football game, and when I resumed I did not refresh the page, thus did not see your answer was already posted.
*Friday, July 2, 2010 at 4:12pm by Reiny*

**Trig**

tan(a-b) = [ tan a - tan b)/(1 + tan a tan b) You better learn those trig identities.
*Tuesday, December 27, 2011 at 6:42pm by Damon*

**Trig**

atta go :)
*Thursday, January 14, 2010 at 5:45pm by Damon*

**trig**

lower right
*Thursday, March 10, 2011 at 8:06pm by Damon*

**trig**

(2x+1)(9x-3)
*Sunday, September 11, 2011 at 6:52pm by Damon*

**TRIG**

tan (angle) = 5.5/6.2
*Sunday, September 11, 2011 at 7:23pm by Damon*

**Trig**

sin A = cos B
*Tuesday, December 13, 2011 at 6:45pm by Damon*

**trig**

so x = +/- 4 if 8 wide what is y ? 16 = 8 y y = 2
*Tuesday, December 20, 2011 at 8:19pm by Damon*

**Trig - Thanks Damon and Lindsey**

Thanks a bunch
*Tuesday, December 20, 2011 at 8:32pm by Don*

**trig**

No, x is half the width.
*Tuesday, December 20, 2011 at 8:19pm by Damon*

**Trig**

The answer is 1/8 Is that correct Damon ?
*Tuesday, December 27, 2011 at 6:42pm by Don*

**trig**

yes I get 171.346
*Sunday, March 11, 2012 at 7:09pm by Damon*

**trig**

see above
*Sunday, March 11, 2012 at 7:07pm by Damon*

**trig**

see above
*Sunday, March 11, 2012 at 7:09pm by Damon*

**Trig**

6 + sin k x 6 feet
*Thursday, June 21, 2012 at 5:15pm by Damon*

**trig**

whoops, sorry
*Wednesday, November 7, 2012 at 10:51am by Damon*

**Trig - Thanks Damon**

You are welcome :)
*Saturday, December 17, 2011 at 5:12pm by Damon*

**Trig.**

The one with the typo was hard.
*Wednesday, January 9, 2008 at 8:55pm by Damon*

**trig**

sin (theta + pi/2)
*Thursday, April 17, 2008 at 5:50pm by Damon*

**trig**

cos (theta - pi/2)
*Thursday, April 17, 2008 at 5:50pm by Damon*

**trig**

very similar to the last one
*Thursday, April 17, 2008 at 5:56pm by Damon*

**Trig**

decibels sound level
*Saturday, April 24, 2010 at 6:32pm by Damon*

**trig**

yes. Sqrt 2 is approximately 1.41
*Sunday, January 30, 2011 at 12:49am by Damon*

**Trig **

Huh? tan theta = 8/5 !!!
*Thursday, March 10, 2011 at 8:36pm by Damon*

**alg2/trig**

I bet you mean a/(a-b) + b/(b-a) a/(a-b) - b/(a-b) (a-b)/(a-b) 1
*Thursday, October 13, 2011 at 8:36pm by Damon*

**trig**

a) 2 and 4 b) cos+ in 1 and 4 but csc + in 1 so must be in 4
*Thursday, January 26, 2012 at 9:42pm by Damon*

**trig**

tan 31 = h/580
*Wednesday, February 26, 2014 at 8:17am by Damon*

**Trig.**

OH, that is a different problem ! let p = y^1.5 then p^2 -16 p + 64 = 0
*Wednesday, January 9, 2008 at 8:55pm by Damon*

**Algebra2/trig**

Whoops, sorry, forgot the 3^8
*Thursday, March 19, 2009 at 8:40pm by Damon*

**math -trig**

Hey, that is really cool !
*Tuesday, June 9, 2009 at 8:19pm by Damon*

**Trig**

I am not going to do them all for you. Let's see you try.
*Sunday, November 28, 2010 at 5:46pm by Damon*

**trig**

try both x and y are 45 degrees.
*Thursday, November 17, 2011 at 1:32pm by Damon*

**trig/precalculus**

M = sin x/cos c = tan x
*Tuesday, December 13, 2011 at 10:49am by Damon*

**trig**

15/7 That is it, now you try some.
*Thursday, January 26, 2012 at 12:28am by Damon*

**Trig TYPO**

then in quadrant 1 sin T = y/1 so + cos T = x/1 so + tan T = y/x so +
*Friday, February 15, 2008 at 5:53pm by Damon*

**Algebra II/Trig**

How did that 4 get up top though?
*Thursday, August 7, 2008 at 6:52pm by Damon*

**trig**

humm, looks like we agree in the end :)
*Friday, July 2, 2010 at 4:12pm by Damon*

**trig**

x = 180 + 45 in degrees = (1 1/4) pi in radians
*Sunday, January 30, 2011 at 12:49am by Damon*

**Math- Trig**

tan 30 = 12/AB
*Thursday, December 8, 2011 at 3:02pm by Damon*

**trig**

y^2 + 7^2 = 25^2 y^2 = 625 - 49 = 576 y = 24
*Wednesday, January 25, 2012 at 10:37pm by Damon*

**trig**

Much more fun to do it the hard way
*Monday, March 26, 2012 at 11:20am by Damon*

**trig**

Just did one like this. Now you try.
*Monday, March 26, 2012 at 11:10am by Damon*

**trig**

You can convert those degrees to radians I trust.
*Thursday, July 4, 2013 at 4:12pm by Damon*

**Trig**

Found my mistake .... All is good now Thanks for the help earlier Damon Don
*Tuesday, December 27, 2011 at 8:53pm by Don*

**Trig**

I do not think so. That would be a very unusual thing for "them" to say :)
*Sunday, January 8, 2012 at 7:38pm by Damon*

**Precalculus**

sin^2 x + cos^2 x = 1 VERY IMPORTANT trig identity
*Thursday, January 26, 2012 at 10:37pm by Damon*

**trig question**

sorry 1 = EO, the side along the x axis
*Saturday, April 28, 2012 at 2:57pm by Damon*

**trig**

2U-7U must be a TYPO maybe 2 U - 7V ? or 2V - 7 U ???
*Thursday, May 17, 2012 at 5:02pm by Damon*

**math trig**

a^2 + 100 = 225 a^2 =125 = 25 * 5 a = 5 sqrt 5
*Wednesday, March 19, 2014 at 7:03pm by Damon*

**Trig.**

I tried to answer down below I think no real y is a solution
*Wednesday, January 9, 2008 at 8:55pm by Damon*

**trig**

If you are supposed to give exact answer, the only one is sqrt 3
*Thursday, April 17, 2008 at 6:42pm by Damon*

**trig**

7x-10 = x^2 + 4 x - 50 x^2 -3x -40 = 0 (x-8)(x+5) = 0 x = 8 or x = -5 (-5,-45) (8,46)
*Sunday, April 4, 2010 at 8:27pm by Damon*

**math**

The period is 2 pi in radians for any old trig periodic function.
*Thursday, April 8, 2010 at 4:20am by Damon*

**trig**

I am simply not going to do these. They are all virtually the same as the ones I already did for you.
*Friday, January 27, 2012 at 6:37pm by Damon*

**Alg2/Trig**

Sketch a graph. see that vertex is at (3.-1) so form is (y+1) = k(x-3)^2 substitute in (2,0) to find k 1 = k (-1)^2 k = 1 so y = (x-3)^2 or y = x^2 - 6 x + 9
*Thursday, March 5, 2009 at 8:09pm by Damon*

**Trig**

Jennifer, graph it starting at x = 0 and go to x = pi/3 see where it crosses the axis
*Thursday, January 14, 2010 at 5:45pm by Damon*

**trig**

Do it the way Dr WLS did it, much simpler and more likely correct.
*Sunday, January 29, 2012 at 9:31am by Damon*

**Maths - Trig**

Usually my first step in proving any trig identity is taking an arbitrary angle to see if it makes it true, say 45 degrees. Picking up from Damon's first line, your equation is tanx + cotx = 2/sinx for x = 45 degrees LS = 1+1 = 2 RS = 2/.707 which is not LS so the equation is ...
*Thursday, February 19, 2009 at 1:21am by Reiny*

**Algebra2/Trig**

Horizontal axis means of form: (y-k)^2 = 4p(x-h) if the vertex is at the origin (h,k) = (0,0) y^2 = 4 p x 36 = 4 p (4) p = (9/4) so y^2 = 9 x
*Tuesday, February 3, 2009 at 9:41am by Damon*

**Physics Classical Mechanics**

You are welcome. I took trig in the early 1950s but have done a little since :)
*Friday, January 10, 2014 at 4:30pm by Damon*

**Trig-Please check**

Thank you Damon-I reworked it on the calculator to make sure I knew what I was doing-thank you again for helping
*Friday, January 13, 2012 at 11:20am by Angela P.*

**trig**

2 U = 10 i + 22 j 7 V = 14 i - 21 j ----------------- subtract for 2 U - 7 V = -4 i + 1 j but I have no idea if that is what you want. Please repair typo.
*Thursday, May 17, 2012 at 5:02pm by Damon*

**no, trig**

No, trig :) Draw a sketch, h is height of balloon over bridge tan 71 h/270 so h = 270 tan 71 = 784 then tan 54 = h/x where x is hor dist to other end from balloon x = h/tan 54 = 570 so total length = 270 + 570 = 840 meters
*Thursday, January 26, 2012 at 1:50pm by Damon*

**trig**

hypotenuse = 10 10 cos 28 = horizontal leg
*Sunday, January 23, 2011 at 11:28pm by Damon*

**trig**

(2x+1)(9x-3) one more step (2x+1)(3)(3x-1)
*Sunday, September 11, 2011 at 6:52pm by Damon*

**Trig**

sin 29 1/2 deg = h/36 36 is hypotenuse of right triangle
*Sunday, November 28, 2010 at 5:43pm by Damon*

**trig**

if the sec is -2 then the cos is -1/2 that would be 180- 60 or pi - pi/3 = 2pi/3
*Monday, September 5, 2011 at 7:27pm by Damon*

**trig**

22/5 = 4 2/5 so twice around and then 2 pi/5 in quadrant 1 100 degrees is not in quadrant 1
*Thursday, January 26, 2012 at 9:47pm by Damon*

**Trig**

Do you mean where does the function cross the x axis first after x = 0? If so it is when 3x-pi/2 = 0 or x = pi/6
*Thursday, January 14, 2010 at 5:45pm by Damon*

**a bit challenging for me**

Trig tables sin a + sin b = 2 ......
*Sunday, February 10, 2008 at 3:39pm by Damon*

**trig**

f(x) =sin ( x + (4t+3/7) ) ???? the phase shift is that (4t+3/7)
*Thursday, April 17, 2008 at 8:59pm by Damon*

**trig**

y = (3sinx/2) + 4 If you mean y = 3 sin (x/2) + 4 the amplitude is 3 It goes up from 4 to 7 when the sine is +1 and down from 4 to 1 when the sine function is -1
*Monday, April 21, 2008 at 8:54pm by Damon*

**Calculus 1**

Using trig get: Xn+1 = Xn - Yn/Y'n where Y = x^3 + x + 2 Y' = 3x^2 + 1 for x = -1 Y = -1-1+2 = 0 well how embarrassing, we guessed it exactly Y' = 4 irrelevant
*Monday, October 31, 2011 at 7:53pm by Damon*

**TRIG**

2 x = pi +/- pi/3 radians you take it from there
*Friday, November 26, 2010 at 4:37pm by Damon*

**Trig**

= sin (a+b) = sin 70 Is that right Damon ?
*Tuesday, December 27, 2011 at 6:39pm by Don*

**trig**

do you mean sin (8x) or sin^8 (x) ?
*Thursday, December 29, 2011 at 5:40am by Damon*

**Trig 30**

x/2 = 2pi/3 yields a unique solution of x = 4pi/3 Does this answer come from some trig equation? Your subject title suggests that. In that case find the period of the trig function, then add k(period) to 4pi/3, k an integer.
*Friday, March 19, 2010 at 7:59pm by Reiny*

**trig**

cos(x)[2sin(x)+1]=0 so zero when cos x = 0 or when sin x = -1/2 note this is just like factoring a quadratic x^2 - 4x + 3 = 0 (x-3) (x-1) = 0 satisfied when x-3 = 0 , so x = 3 and when x-1 = 0 so x = 1
*Sunday, March 23, 2008 at 4:52pm by Damon*

**ALG/TRIG**

T = k D^(3/2) let x = 93,000,000 miles for earth 1 year = k x^(3/2) k = 1/x^(3/2) for Neptune T = [1/x^3/2) (30x)^(3/2) T = 30^(3/2) = 164 years
*Tuesday, March 6, 2012 at 2:22am by Damon*

**trig**

Period of pendulum = 1 second what is its length ? 1^2 = (2pi)^2 L/9.8 L = 9.8/(2pi)^2 L = .248 meters or 24.8 cm, about 10 inches
*Wednesday, July 6, 2011 at 11:21pm by Damon*

**trig**

f(x) = sin ( 2 pi x/L - 2) = sin (2 x/3 - 2)
*Thursday, April 17, 2008 at 5:53pm by Damon*

**trig**

x = 0, 360, 720 ....... n(360)
*Monday, April 19, 2010 at 9:27pm by Damon*

**Trig**

log b (4) = 2 b^log b( 4) = 4 so b^logb(4) = b^2 so b^2 = 4 b = 2
*Monday, January 14, 2013 at 8:42pm by Damon*

**trig**

let z = cos x then z^2 + 2 z + 1 = 0 (z+1)(z+1) = 0 z = -1 so cos x = -1 that is at x = 180
*Thursday, July 4, 2013 at 4:12pm by Damon*

**trig**

amplitude = 1 period is when 5 x = 2 pi so when x = (2/5) pi phase shift is 3.14 radians or about pi
*Sunday, April 1, 2012 at 7:29pm by Damon*

**Trig #1**

Well, look up: Surveyor Architect Naval Architect Civil Engineer Landscape Architect Astronomer
*Wednesday, May 28, 2008 at 1:08am by Damon*

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