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April 16, 2014

Search: The equation of the tangent line to f(x) = \sqrt{x} at x = 49 is y =

Number of results: 67,863

algebra
find an equation of the line containing the given pair of points. (-9,0) and (0,4) what is the equation of the line? y=?
Monday, November 21, 2011 at 4:45pm by amy

algebra
find an equation of the line containing the given pair of points. (-9,0) and (0,4) what is the equation of the line? y=?
Monday, November 21, 2011 at 4:46pm by amy

Math
Write an equation of the line with y-intercept 4 that is parallel to the line whose equation is y=3x+2
Wednesday, February 29, 2012 at 4:21pm by amy

Caculus f'(x)
y = ax^3 y' = 3ax^2 at x=-2, y' = 12a The line y=2x+b has slope 2, so 12a=2 a = 1/6 at x = -2, y = -8a = -4/3 so the line must go through (-2,-4/3) So, the tangent line has slope 2 and goes through (-2,-4/3) y = 2x+b -4/3 = -4 + b b = 8/3 So, now we have y = 2x - 8/3 is ...
Friday, February 14, 2014 at 7:48pm by Steve

Calculus
show lim x->3 (sqrt(x)) = (sqrt(c)) hint: 0< |sqrt(x)-sqrt(c)|= (|x-c|)/(sqrt(x)+sqrt(c))<(1/(sqrt(c))*|x-c|
Monday, October 3, 2011 at 11:47pm by Shayna

Calculus
show lim x->3 (sqrt(x)) = (sqrt(c)) hint: 0< |sqrt(x)-sqrt(c)|= (|x-c|)/(sqrt(x)+sqrt(c))<(1/(sqrt(c))*|x-c|
Tuesday, October 4, 2011 at 10:06am by DJ

Trig
sin (30/2) = +/- sqrt [(1-cos 30)/2] + in first quadrant = sqrt [ (1 - {sqrt 3}/2)/2) ] = sqrt [ (2 - sqrt 3)/4 ] = (1/2) sqrt (2 - sqrt 3)
Friday, April 13, 2012 at 3:17pm by Damon

algebra
6 x ^ 3 - 2 x = - 9 x ^ 2 Add 9 x ^ 2 to both sides 6 x ^ 3 - 2 x + 9 x ^ 2 = - 9 x ^ 2 + 9 x ^ 2 6 x ^ 3 + 9 x ^ 2 - 2 x = 0 x * ( 6 x ^ 2 + 9 x - 2 )= 0 You equation have 3 solutions: Obviously solution x = 0 Equation : 6 x ^ 2 + 9 x - 2 = 0 have two solutions : x1/2= [ - 9...
Monday, November 26, 2012 at 6:51am by Bosnian

distance formula
d^2 = 7^2 + 7^2 = 49*2 d = 7 sqrt 2 d = 9.899 etc yes
Friday, April 20, 2012 at 4:24pm by Damon

Calculus questions..really need help, please!
3) If f(x)=arcsin(x/3), then what's f'(sq5). I set f'(x) = arcsinx/arcsin3..am I on the right path? ---------------------- d/dx (sin^-1 u ) = du/dx /sqrt(1-u^2) here u = x/3 so f'(x) =(1/3) / sqrt (1 - x^2/9) now f'(sqrt 5) f'(sqrt 5) = (1/3) / sqrt (1 - 5/9) = (1/3) / sqrt (4...
Tuesday, November 4, 2008 at 7:55pm by Damon

calculus
We are given a fixed point through which the tangents pass. On the curve (parabola), the slope of the tangent is dy/dx = 2x at the point (x,x²-2). What we need here is a line that passes through a point (x,f(x)) and (1,-5) with a slope of 2x. Thus we form the equation: (...
Tuesday, March 1, 2011 at 6:18pm by MathMate

algebra
Find the equation of the line passing through the points: (-5,-5) and (6,-5) Hmmm. both y are -5. The line has to have zero slope, and the y intercept is -5 y= -5 is the equation Thank You
Saturday, March 3, 2007 at 1:41pm by jacque

algebra essentials
Find an equation for the line that contains each pair of points. If the line is not vertical. Write the equation in slope-intercept form. X(4,5,0) and Y(0,4,5)
Saturday, February 23, 2008 at 11:12pm by Roderick

math
I have the point slope equation of a line as y-500=(-4/3)x+(188/3) how would i convert this equation into the normal form of a line?
Sunday, April 19, 2009 at 9:03pm by kelly

math
find an equation of the line containing the given pair of points. Express your answer in the form x =a,y=b or y=mx+b (-1,_1) and (9,9) what is an equation of the line?
Sunday, January 9, 2011 at 5:05pm by Norma

Algebra 1
23.what is the slope of a line parallel to a line represented by the equation x=2y-3? 19.what is the solution to the following system of equation? Y=4x-8 Y=2x 16.which graph below shows the function f(x)=-3x-1? 12.what is the solution to the following system of equations? Y=2x...
Saturday, January 21, 2012 at 12:53pm by Elyon

math
d/dx x(1+y)^(1/2) + y(1+x)^(1/2)=0. Can some1 show me the calculation because i didnt get like the answer. [ans=-1/(1+x)^2 but my calculation=-(sqrt(y+1) (2 sqrt(x+1) sqrt(y+1)+y)/(sqrt(x+1) (2 sqrt(x+1) sqrt(y+1)+x)]
Friday, July 22, 2011 at 4:12am by jess

physics
sqrt (12^2 + 5^2) = sqrt(144+25) = 13 sqrt (13^2 + 9^2) = (sqrt(169+81) = sqrt(250) = 5 sqrt(10)
Friday, August 12, 2011 at 7:03pm by Damon

algebra
sqrt (90 x^26) /sqrt (2 x) = sqrt (45 x^25) = sqrt ( 9*5*x*x^24) = 3 * x^12 * sqrt (5 * x) in other words a
Sunday, March 16, 2008 at 8:24pm by Damon

calculus
Now, the slope of the tangent line at any point (x,y) on the curve is just y'(x) = cosx At x=pi, y' = -1 and y=3 So, we want the line through (pi,3) with slope -1. y-3 = -(x-pi) = pi-x y = -x + 3+pi The slope of the normal line is -(1/-1) = 1 y-3 = (x-pi) y = x + 3-pi
Thursday, September 22, 2011 at 9:34pm by Steve

algebra
simplify: sqrt (28) a) 4 sqrt (7) b) 7 sqrt (2) c) 2 sqrt (7) d) sqrt (7) c im just making show that they are correct sorry for posting up so many
Thursday, June 24, 2010 at 7:39pm by anthony

algebra and geometry
you mean (6 sqrt 2 )/3? if so its already simplified to lowest terms if you meant 6 sqrt(2/3) then it is = sqrt(36*2/3) = sqrt 24 this is equivalent to 2 sqrt(6)
Thursday, March 21, 2013 at 5:34pm by Knights

Algebra
If you square the left side of the equation (and the right also), you get x + 3 - 2 sqrt[(x-2)(x+3)] + x-2 = 1 That is where the "FOIL" is done, but you still have more to do. Combine terms and you get 2x - 2 sqrt[(x-2)(x+3)] = 0 Divide both sides by two, move the -sqrt[(x-2)(...
Tuesday, January 27, 2009 at 7:33pm by drwls

calculus
the tangent line has slope f'(x) f'(x) = 10x f'(3) = 30 So, now we have a point and a slope. The line is thus y-41 = 30(x-3) Same for the others; just plug in different numbers.
Saturday, May 4, 2013 at 3:01pm by Steve

Please Help with calculus
What his means is that if you draw the graph of y=e^(x/9) and then draw the tangent line at x=0, if you move along that line horizontally to the left by .03 (dx), you will move vertically down by 1/300 (dy).
Wednesday, June 26, 2013 at 9:37am by Steve

Math
The line passing through a point Pt(xt,yt) is (y-yt) = m(x-xt) where m is the slope. For the given function f(x) = (x - 2)^5 (x + 1)^2 We first validate that f(3) = 16, the tangent point. f(3) = (3 - 2)^5 (3 + 1)^2 =16 ..... OK The only unknown is the slope m, which we should ...
Friday, June 26, 2009 at 3:19pm by MathMate

Math
At what point on the curve y = 6 + 2e^x − 3x is the tangent line parallel to the line 3x − y = 1?
Saturday, October 13, 2012 at 5:06pm by Anonymous

Algebra
Write the equation of the line L satisfying the given geometric conditions. L has y-intercept (0,-3) and is parallel to the line with equation y=2/3x+1 I will be happy to critique your work on this. y=(2/3)x-3?
Sunday, May 20, 2007 at 4:59pm by Linda

algebra
The slope of the first line, which can be most easily seen when rewritten as y = (2/5) x -12/5, is m = 2/5 The y-intercept of the second equation is what you get when x = 0. That number is y = -6 Therefore the equation of the line you want is y = (2/5)x -6
Wednesday, March 12, 2008 at 11:25pm by drwls

math
Find the equation of the line that is parallel to the line formed by the equation 3x + 2y = -20 and passes through the point (-24, 12).
Tuesday, December 14, 2010 at 9:23am by Anonymous

math
Find an equation of a line that is parrellel to the line of each equation: y=2x-7 y=-4x+5 y=x-3
Friday, April 25, 2008 at 6:16pm by Marianna

Algebra - equation
What equation represents a line parallel to the line given by y-3x=6?
Monday, May 18, 2009 at 5:14pm by randi

geometry
What is an equation of the line that passes through (-3,6)and is parallel to the line with the given equation: y=-x-5
Thursday, October 28, 2010 at 8:49pm by noah

Calculus
(A) Find the equations of the tangent lines to the circle x^2 +y^2=25 at the points where x=4. (B) Find the equations of the normal lines to this circle at the same points. (The normal line is perpendicular to the tangent line at that point.) (C) At what point do the two ...
Friday, November 7, 2008 at 12:43am by George

Algebra
First the slope. Perpendicular to a slope of -3 means a line slope of 1/3 y= 1/3 x + b. Now put in the x,y point and solve for b. write the equation of a line that has a y intercept (0,5) and is perpendicular to the line with equation y=-3x+1
Sunday, March 11, 2007 at 10:59pm by bobpursley

math
what you missed is maybe sqrt (1/3) = 1/sqrt 3 multiply top and bottom by sqrt 3 to clear denominator of radical 1/sqrt 3 = (1/3)sqrt 3
Saturday, February 14, 2009 at 5:24pm by Damon

Algebra 2
suspect you mean a^2 -2 a sqrt 3 = -2 half of 2 sqrt 3 squared is 3 so add 3 to both sides a^2 -2 a sqrt 3 + 3 = 1 (a-sqrt 3)^2 = 1 a = sqrt 3 +/-1
Wednesday, December 7, 2011 at 1:33am by Damon

calculus
So one wants the line equation in the form of y= dy/dx * x + b from the original equation.. e^y + xe^y y' + y' e^x + y e^x=0 y' (xe^y+e^y)+ y e^x + e^y=0 check that. I would put in (0,4) and solve for y' at this point. Then go into the line equation y=y' x + b and solve for b ...
Tuesday, February 10, 2009 at 1:46am by bobpursley

pre cal
find the standard form of the equation of the ellipse with center (0,0) and foci at (+- 4square root 3, 0) and verticies (+-8,0) x^2/a^2 + =y^2/b^2 = 1 a = 8 b = sqrt(8^2 - (4sqrt3)^2) ..= sqrt(64 - 48) = sqrt(16) = 4 Thus, x^2/64 + y^2/16 = 1
Friday, May 25, 2007 at 4:28pm by jessica

calculus 1
If f(x) = 9x2 − x3, find f'(2) and use it to find an equation of the tangent line to the curve y = 9x2 − x3 at the point (2, 28).
Thursday, January 31, 2013 at 5:25pm by monic

Algebra
(a) The equation is in the form ax^2 + bx + c Use those values for b^2 - 4ac. (-16)^2 - 4*4*25 = 256 - 400 = -144 The determinant is negative, so there will be two imaginary solutions. (b) The quadratic equation is x = (-b +/- sqrt(determinant))/(2a) Using the values of a, b, ...
Tuesday, July 7, 2009 at 7:02pm by Marth

maths
1. Prove using mathematical induction that 1+2+3+...+n=[ n(n+1)]/2 2. Find the derivative of 2^x^2+log2(2x^2-1) 3. Use DeMeoivre's theorem to simplify the following expressions [(Cos pie/3 + isin pie/3)^5 (cos 2pie/3- isin 2pie/3)^4]/ (cos pie/6 - isin pie/6)^2 4.Find the ...
Tuesday, February 19, 2013 at 6:20am by muselitata

maths
1. Prove using mathematical induction that 1+2+3+...+n=[ n(n+1)]/2 2. Find the derivative of 2^x^2+log2(2x^2-1) 3. Use DeMeoivre's theorem to simplify the following expressions [(Cos pie/3 + isin pie/3)^5 (cos 2pie/3- isin 2pie/3)^4]/ (cos pie/6 - isin pie/6)^2 4.Find the ...
Tuesday, February 19, 2013 at 6:21am by muselitata

calc
Are you sure it is not a typo? Anyway if it is for real, solve with quadratic x = [ 8 +/- sqrt (64 -12) ]/2 = [8 + sqrt(52) ]/2 = [ 8 +/- 2 sqrt(13) ]/2 = 4 + sqrt 13 or = 4 - sqrt 13 so [ x - (4+sqrt 13)] [ x - (4-sqrt 13) ]
Monday, January 9, 2012 at 7:59pm by Damon

Algebra 2
multiply top and bottom by (sqrt(5) + 2 ) .3 [sqrt(5)+2]/ {[ sqrt (5) -2][sqrt(5) +2] } = (.3 sqrt(5) +.6)/ (5-4) = .3 sqrt(5) + .6
Sunday, February 15, 2009 at 6:40pm by Damon

physics
String mass per unit length is w = 0.00717/2.49 = 2.88*10^-4 kg/m With five antinodes, the wavelength is L = 2/5 * 2.49 = 0.996 m The frequency is f = 455 Hz The wave speed is C = L*f = 453.2 m/s The tension T must provide that wave speed. sqrt(T/w) = 453.2 m/s Solve for T, in...
Saturday, March 3, 2012 at 8:21am by drwls

Algebra
You did the hardest part correctly. Once you have the corner coordinates, square the length of any side to get the area. The length of the diagonal of your square is sqrt[7^2 + 7^2] = 7 sqrt 2, so the length of sides should be 7. The area must be 49
Tuesday, December 2, 2008 at 3:57pm by drwls

math,correction
can someone correct this for me plz.... Write the equation of the line L satisfying the given geometric conditions. (#1)L has y-intercept (0, -3) and is parallel to the line with equation y = (2)/(3)x + 1. My answer:
Monday, January 22, 2007 at 4:45am by jasmine

alegbra
Find an equation of the line containing the give pair of points. (-2, -1), and (-7, -4). The equation of the line in slope - intercept form is y= I 've tried this problem and can not seem to get could please help me.
Monday, March 16, 2009 at 8:46pm by Johnnie

alegbra
Find an equation of the line having slope and containing the given point. M=4/5, (3, -7) The equation of the line is Y= I have tried to work this problem and could not get the answer. Please help me.
Thursday, March 19, 2009 at 4:57pm by Johnnie

Math
The line L has equation of 4x + 3y = 7. Find the equation of the line perpendicular to L which passes through the point of intersection of L and the y-axis. Give answer in ax + by + c = 0.
Sunday, December 9, 2012 at 2:26pm by Angie

algebra
Which choice could be the equation of a line perpendicular to the line represented by this equation? y = 5 for this question, i put this: y = -1/5x but, it says i am wrong. how is that? 5 is 5/1, and so the negative reciprocal of 5/1 would be -1/5, right?
Sunday, November 10, 2013 at 10:11pm by caduceus

precalculus
Find (a) the equation of a line that is parallel to the given line and includes the given point, and (b) the equation of a line that is perpendicular to the given line through the given point. Write both answers in slope-intercept form. (c) Graph both of these lines on the ...
Friday, November 11, 2011 at 1:38pm by tinathomas

Algebra
x^2 - 6 x + 4 = 0 x = [ 6 +/- sqrt (36 -16) ] / 2 x = 3 +/- 2 sqrt (9 - 4) x = 3 +/-2 sqrt (5) ======================== t^2 + 4 t - 2 = 0 t = [ -4 +/- sqrt (16 + 8) ] / 2 t = [-4 +/- 2 sqrt (4+2) ] / 2 t = -2 +/- sqrt (6) ==================== 3 x^2 + 10 x + 5 = 0 x = [ -10...
Wednesday, April 23, 2008 at 8:05pm by Damon

Geometry
There is a right triangle with an altitude of 12. The line of the altitude splits the base into two segments, x and x+7. One leg of the right triangle is y, which is closest to the segment x. The other leg is z, which is closest to segment x+7. We have to figure out what the ...
Tuesday, January 8, 2008 at 8:50pm by tchrwill

calculus please help me
Let f(x)=9sinx/2sinx+4cosx. Then 'f(x)= ((2sinx+4cosx)(9cosx)-(9sinx)(2cosx-4sinx))/(2sinx+4cosx)^2. The equation of the tangent line to y=f(x) at a=2 can be written in the form y=mx+b where m= 9and b= ______.?????
Wednesday, May 7, 2008 at 5:22pm by Leslie

math
I need help with "write in equation in slope-intercept form for the line that is parallel to to the given line line and and that passes through the given point. y=1/2x=5;(4,-3) How do you find a line that is perpendicular. Please and thank you! :)
Saturday, February 8, 2014 at 7:30pm by Kerri

math
sqrt(75)=sqrt(25)sqrt(3) which simplifies to 5 times sqrt(3) so 6x5xsqrt(3)= 30 sqrt(3)
Monday, November 28, 2011 at 7:00pm by Kelsey

Froude number
Fr = v/sqrt(Lg) v = n R or (1/2) n D (1/2) n D / sqrt (D g) <----- = (1/2) n sqrt D/sqrt g = (1/2) n sqrt (D/g) What's the explanation of replacing L with D there?
Thursday, February 20, 2014 at 4:06pm by Hydro

Calc problem
Consider the function y=(kx)/(x-k) a. Show that y is symmetric with respect to the line y=x. b. Write the equations of the horizontal and vertical asymptotes of y. c. Find the point(s) of intersection of y with the line x-y=-2k, and find the slope of the tangent line at the ...
Saturday, February 23, 2008 at 5:43pm by Holly

geometry
x = length of one side of a square x - 7 = length of one side of an equilateral triangle Equation: 4x + 3(x - 7) = 49 Solving for x: 4x + 3x - 21 = 49 7x - 21 = 49 7x = 70 x = 10 Now you should be able to determine the perimeter of each figure. I hope this helps.
Tuesday, October 16, 2012 at 7:22pm by MathGuru

physics
The runner wants to go the remaining 1100 m in 3 minutes. That will require an average speed of 6.11 m/s. His speed for the first 2700 minutes was 8900m/(27*60 s) = 5.49 m/s. If he accelerates for time T (seconds) and then maintains constant speed for 180-T seconds, Final ...
Thursday, June 10, 2010 at 10:48am by drwls

algebra
Simplify: ( sqrt (2) + sqrt (3) ) ( sqrt (2) - sqrt (3) )? a) 2 - 2 sqrt (6) - 3 b) -1 c) 2 + 2 sqrt (6) - 3 d) 5 i just need to know if my answer or right or wrong. i think the answer is b thanks
Friday, June 18, 2010 at 5:26pm by anthony

math
d/dx x(1+y)^(1/2) + y(1+x)^(1/2)=0. Can some1 show me the calculation because i didnt get like the answer. [ans=-1/(1+x)^2 but my calculation=-(sqrt(y+1) (2 sqrt(x+1) sqrt(y+1)+y)/(sqrt(x+1) (2 sqrt(x+1) sqrt(y+1)+x)]
Friday, July 22, 2011 at 7:09pm by will

Algebra 2
3 b sqrt ( 3*9 a a^4 b) + 2a sqrt (3 a a^2 b b^2) 3 b 3 a^2 sqrt(3 a b) + 2 a a b sqrt(3 a b) 9 a^2 b sqrt (3 a b) + 2 a^2 b sqrt (3 a b) 11 a^2 b sqrt (3 a b)
Sunday, February 15, 2009 at 6:40pm by Damon

math
B=1.69 (sqrt (s)+4.45)-3.49 solve for s
Thursday, February 16, 2012 at 10:08pm by Melissa

Algebra 2 Help
7 + 24i r = sqrt (49 + 576) = 25
Friday, February 28, 2014 at 11:31am by Damon

MATH
1/(X^-2Y)-1(XY^-2)=____ XY (square root of 84 - square root of 5.25) I don't understand the first equation. sqrt(84)=sqrt(4*21)=sqrt(16*5.25)=4sqrt(5.25) so sqrt(84)-sqrt(5.25)= 4sqrt(5.25)-sqrt(5.25)=3sqrt(5.25)
Friday, April 13, 2007 at 5:39pm by JORDAN

algebra 1
First, put the equation in slope-intercept form. 6x-7y=4 -7y=-6x+4 -y=-6/7x+4/7 y=6/7x-4/7 So the slope of the parallel line will also be 6/7. Now use the point slope formula to find the equation of the line. y-y1=m(x-x1) y-(-2)=6/7(x-5) y+2=6/7(x-5) y+2=6/7x-30/7 y=6/7x-44/7 ...
Sunday, July 10, 2011 at 8:19pm by Max

math
y = √2 cosx I usually check if the given point is actually on the line LS = 1 RS = √2 cos(pi/4) = √2(1/√2) = 1 = LS dy/dx = -√2(sinx) at (pi/4,1) dy/dx = -√2(1/√2) = -1 So the slope of the tangent is -1 and the slope of the normal is +...
Thursday, October 15, 2009 at 7:45pm by Reiny

Calculus
First find the slope of the tangent line = y' y' = 5/2 * x^(3/2) + 1/2 * x^(-3/2) The line in question has slope m=4 So, you want y'=4 5/2 * x^(3/2) + 1/2 * x^(-3/2) = 4 let u = x^(3/2) We can rewrite that as 5u/2 + 1/2u = 4 Multiply by 2u 5u^2 + 1 = 8u 5u^2 - 8u + 1 = 0 u = 1...
Monday, October 17, 2011 at 7:23am by Steve

math
Y = 2x^2 - 7x + 1. V(h , k), h = Xv = -b / 2a, = 7 / 4 = 1 3/4. Substitute 7/4 for x in the given Eq: k = Yv = 2(7/4)^2 - 7(7/4) +1, = 98/16 - 49/4 +1, = 49/8 - 49/4 + 8/8, = 49/8 - 98/8 + 8/8, = - 41/8 = -5 1/8. V(1 3/4 , - 5 1/8). Axis of Sym. = h = Xv = 1 3/4.
Monday, November 1, 2010 at 2:53pm by Henry

Math
These questions that I have completed are on a test review for my exam and I would just like to know if they are correct. These are only a few of the questions, I have more that are just not complete yet. Thank You! 1) List the intercepts for the graph of the following ...
Wednesday, October 6, 2010 at 3:53pm by Hannah

Math
I had an assignment containing 45 problems, and I am unsure of 4, can you check and see if the answers are correct? 1. Write an equation of the line containing the given point and parallel line (5,-1), 3x-7y=9 My answer was: y=3/7x-22/7 2. Find the equation of the line having ...
Sunday, December 6, 2009 at 5:46pm by S

calculus
To find the slope of the tangent line you have to take the first derivative of f(x). So f'(x)=-5. Or you can also see that from the formula y=mx+b, where m is slope and b is your y intercept, that -5 is the slope. Because the original function is a line, the slope is the same ...
Friday, February 11, 2011 at 11:02pm by Allison

Algebra 1
(7^2)x - 9 = 6 49x = 15 x = 15/49 the number is 15/49 check: 7^2 = 49 the product of 49 and 15/49 = 15 15 less 9 = 6
Saturday, August 3, 2013 at 10:22am by Reiny

physics
Neglecting air friction, the time it will take the rock to hit the water is sqrt(2H/g) = 2.857 seconds. That means the sound of the splash takes 3 - 2.857 = 0.143 seconds to be heard, after hitting water. Sound travelled 49.05 m in that time. Since the cliff is 40 m high, the ...
Thursday, February 28, 2013 at 1:45am by drwls

Math
Line L has equation of 4x + 3y = 7. Find equation of the line that is perpendicular to L which passes through the point of intersection of L and the y-axis. Give answer in the form ax + by +c = 0.
Thursday, February 4, 2010 at 10:04pm by Angie

Math
The graph of the equation y=4-x consists of all the points in the coordinate plane that satisfy the equation. List 5 points that satisfy y= 4-x. Also, what do you think is the minimum number of points you need to plot in order to draw the graph of y=4-x. Please explain Set y=0...
Tuesday, November 21, 2006 at 6:40pm by victoria

Geometry/Trigonometry
Circles with centers (2,1) and (8,9) have radii 1 and 9, respectively. The equation of a common external tangent to the circles can be written in the form y=mx+b with m < 0. What is b? I drew the diagram and the tangents but to no avail. I cannot seem to find the points ...
Wednesday, December 4, 2013 at 12:18pm by Sam

calc
eliminate parameter t when x= ln(sqrt(1+t^2)+t) and y = sqrt(t^2+1 so to produce an equation y=f(x).
Friday, December 3, 2010 at 8:08pm by Ang

calc
eliminate parameter t when x= ln(sqrt(1+t^2)+t) and y = sqrt(t^2+1 so to produce an equation y=f(x).
Friday, December 3, 2010 at 8:13pm by Ang

algebra 2
That is the equation of a hyperbola. (x/6)^2 - (y/4)^2 = 1 = (x/a)^2 - (y/b)^2 where a = 6 and b = 4. The foci are at (-c, 0) and (c,0), where c = sqrt (a^2 + b^2) = sqrt 52 = 7.21
Thursday, March 3, 2011 at 7:08pm by drwls

college
since it's not factorable, we use quadratic formula: x = [-b +- sqrt(b^2 -4ac)]/(2a) where a=3, b=1, and c=1 substituting: x = [-1 +- sqrt(1^2 - 4*3*1)]/(2*3) x = [-1 +- sqrt(-11)]/6 thus x = [-1 + i*sqrt(11)]/6 ; and x = [-1 - i*sqrt(-11)]/6 *note: i = sqrt(-1) hope this helps~
Thursday, October 28, 2010 at 11:30am by jai

Physics
Your teacher is pretty easy. vertical component: solve for time in air. hf=ho+vyi*t- 4.9t^2 vyi=49, hf=ho=0 distance traveled: distance= 61*timeinair Initial speed= sqrt(49^2+61^1)
Sunday, January 8, 2012 at 5:12pm by bobpursley

ALG 2!!!
Write an equation of a line with an undefined slope and passing through the point (-2,4). Hint: To answer this question, consider the type of line that has an undefined slope. Then write an equation of that line using the values in the ordered pair.
Thursday, November 22, 2012 at 4:33pm by tyneisha

PreCalc
What is the real solutions of this equation? sqrt(2x+3)-sqrt(x+2)=2
Saturday, August 16, 2008 at 7:19am by Jonathan

Math-Algebra
[SQRT(x + 3)] - [SQRT(x - 2)] =1 Can someone help me solve this equation.
Tuesday, January 20, 2009 at 11:28am by Mike

MATH
I had an assignment containing 45 problems, and I am unsure of 4, can you check and see if the answers are correct? 1. Write an equation of the line containing the given point and parallel line (5,-1), 3x-7y=9 My answer was: y=3/7x-22/7 2. Find the equation of the line having ...
Sunday, December 6, 2009 at 5:06pm by sarah

Advanced math
sqrt(2x+1) = (x-7) square both sides 2x+1 = x^2 - 14 x + 49 x^2 - 16 x + 48 = 0 (x-4)(x-12) = 0 x = 4 or x = 12 MAYBE because when you square both sides you introduce an ambiguity since -a^2 = a^2 . Therefore check both answers in the original problem. try x = 4 4 - sqrt (9...
Friday, April 18, 2008 at 5:15pm by Damon

AP Physics
I do not know if it is 7.5 nautical miles or what, so I will call the distance from the center r. convert 33 1/3 rev/mi to radians/s w = 33 1/3 rev/min *1 min/60 s *2 pi rad/rev = 3.49 rad/s a = w^2 r = 12.2 r in units of length you are using/s^2 since I do not know your ...
Sunday, January 27, 2008 at 1:16pm by Damon

Homework Help Calculus
f' = -pi/6 sin(pi/6 x) f'(1) = -pi/6 (1/2) = -pi/12 f(1) = √3/2 So, the tangent line is y-√3/2 = -pi/12 (x-1) 13pi/72 = pi/6 (13/12) So, plug in x=13/12 into the equation of the line. Note that 13/12 is close to 1, so the approximation should be close to cos(13pi/...
Wednesday, October 16, 2013 at 4:19pm by Steve

alg.
I don't know what you are asking either. The point (2,-5) is not on the line whose equation is 2x+3y=30 You may have left out an earlier part of the question. Are are asking you for the equation of a line that goes through (2,-5) AND is parallel or perpendicular to the line 2x...
Tuesday, November 11, 2008 at 8:58pm by drwls

calc ii
eliminate parameter t when x= ln(sqrt(1+t^2)+t) and y = sqrt(t^2+1 so to produce an equation y=f(x).
Friday, December 3, 2010 at 7:24pm by Ang

8th Grade Algebra: Answer Check
1,2,3,4,5,6,7 are ok. 8. sqrt (3x^2) = x*sqrt(3) Check that. 9,10,11 ok. 12. sqrt(3)*sqrt(27) = sqrt 3*sqrt(3*9) 9*sqrt(9) = 9*3= 27. Check that. check 15. I think you just wrote it wrong. I get 1/5*sqrt(10). Check that. The others look ok.
Tuesday, January 20, 2009 at 10:42pm by DrBob222

Vectors
A = i - 2 j so |A| = sqrt 5 B = -3 i + j so |B| = sqrt 10 The magnitude of the cross product A x B is |A| |B| sin T where T is the angle between the vectors. i j k 1 -2 0 -3 1 0 --> -5 k so the magnitude of the cross product is 5 so sqrt 5 * sqrt 10 * sin T = 5 5 sqrt 2 * ...
Sunday, November 2, 2008 at 2:39pm by Damon

Math
Do i have to make a tangent line?
Saturday, December 3, 2011 at 8:27pm by Jay

calc
If f (3) = 9 and f (3) = 4, find the tangent line to the graph of f when x = 3.
Wednesday, December 28, 2011 at 1:25pm by TIFFANY

math
the slope of the tangent line is the derivative of y=(x+e^-x)^2 at x=0 y' = 2(x + e^-x)(1 - e^-x) y'(0) = 2(0+1)(1-1) = 0
Tuesday, January 24, 2012 at 3:38pm by Steve

Calculus
Find the slope of the tangent line to f(x)=x/x^2+1 at (2,f(2)).
Friday, December 7, 2012 at 9:16pm by Dimitri

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