Wednesday

April 23, 2014

April 23, 2014

Number of results: 3,170

**physics**

tension= weight held up= weight chain below+ weight bolder tension= (790+600)g That is the tension at the top, and of course, the tension at the bottom is 790g, so tension varies on the length. If it breaks, it is at the top. Here, tension cannot be greater than 3*600*g. Is it?
*Wednesday, February 8, 2012 at 2:06pm by bobpursley*

**physics**

a)What is the tension T in the string? in this case, tension = mass2 X gravity so, tension = 1.10 kg X 9.8 m/s^2 tension = 10.78 For letter b, I am afraid I have no clue :( c)What is the speed of the puck? F = (m(v^2))/r the tension is the force in this case, so: tension = (m1...
*Tuesday, November 30, 2010 at 2:13pm by Brianna*

**Physics**

isnt v=sqrt(tension) but f*lambda= v= sqrt(tension). So leaving the lambda constant, then f is proportional to sqrt tension 230/220= sqrt (tension/orgtension) square both sides, solve for tension, then find the percent increase.
*Monday, November 15, 2010 at 6:26pm by bobpursley*

**Physics**

In a vertical circle, max tension is at the bottom. Tension=mg+mv^2/r solve for v In a hoizontal circle, tension is more complicated. Tension=m * sqrt((v^2/r)^2+g^2)
*Wednesday, May 30, 2012 at 1:32pm by bobpursley*

**Physics( Explain and choose right answer)**

The tension is smallest at the top, if the speed is in fact enough to make the top without the tension going to zero. At top: Tension + m g = m v^2/R tension = m (v^2/R - g) if the centripetal acceleration is not greater than g, the rope goes slack.
*Monday, March 24, 2014 at 6:40pm by Damon*

**Physics**

The force on the rope is tension, which is equal to mg-ma But this same tension is spinning the wheel: angularacceleration=Tension/I a/R=Tension/I aI=R(mg-ma) solve for a, then you have it. check my thinking.
*Sunday, May 11, 2008 at 11:26am by bobpursley*

**Physics**

frequency*wavelength=speed=sqrt(tension/mass/length) 200*1=sqrt(tension/.0003) square both sides solve for tension 40000*.0003=tension=hangingmass*g
*Tuesday, April 16, 2013 at 6:07pm by bobpursley*

**Physics**

a rock suspended from a string moves downwards at constant a=g. Which of the following is true concerning the tension in the string? a) the tension is zero b)the tension is equal to the weight of the rock c)the tension is less to the weight of the rock d)the tension is greater...
*Wednesday, November 14, 2007 at 2:54pm by Andrea*

**Physics**

You can use the law of cosines here, but it is much more complicated. Two sides a,b are the vectors (head to tail), and c is the unknown side. The angle between the vectors is 180-60=120 draw a triangle to prove that. c^2=a^2+b^2-2ab*cos120 = 2*tension^2( 1-cos120) =2 tension^...
*Sunday, April 3, 2011 at 1:36pm by bobpursley*

**Physics URGENT!!!**

The rope is doing two things: lifting up, reducing the normal weight (and friction), and pulling the sled horizontally. consider horizontal: tension*CosTheta*distance=work=friction*distance tension*CosTheta=friction=mu*(mg-tension*sinTheta) solve for tension. work=tension*...
*Friday, October 5, 2012 at 10:00pm by bobpursley*

**Physics **

1. due to symettry, assume each half is supporting 25N So you are looking for tension. SinTheta=1m/5m based on lengths SinTheta=25N/tension based of forces 25/Tension=1/5 tension= 125N check that.
*Wednesday, October 6, 2010 at 7:37pm by bobpursley*

**Physics( Explain and choose right answer) **

A ball on the end of a rope is moving in a vertical circle near the surface of the earth. Point A F T is at the top of the circle; C is at the bottom. Points B and D are exactly halfway between A and C. Which one of the following statements concerning the tension in the rope ...
*Monday, March 24, 2014 at 6:40pm by Dan*

**physics**

TRIAL 1 A. ) Bag A + 6 stones Mass (kg) - 0.037 kg Mass of weight hanger + slotted weights - 210 g/ 0.21kg Tension 1 (N) - ?? Acceleration (m/s2) - ?? B. ) Bag B + 4 stones Mass (kg) - 0.08 Mass of weight hanger + slotted weights - 210 g/ 0.21kg Tension 1 (N) - ?? Acceleration...
*Wednesday, May 4, 2011 at 4:07pm by nik*

**CHemistry...Please help**

Rank these liquids by their expected surface tension. Rank from greatest to least surface tension. 1.CH3CH2OCH3 2.CH3CH2CH2-OH 3.CH3CHOHCH2-OH 4.HO-CH2CHOHCH2-OH So as Dr. Bob mentioned to me before surface tension is how the surface molecules stick together. Does that mean 1 ...
*Monday, January 19, 2009 at 2:45pm by Saira*

**Waves & Tension**

A 5.9 m wire with a mass of 79 g is attached to the mast of a sailboat. If the wire is given a "thunk" at one end, it takes 0.087 s for the resulting wave to reach the other end. 1. What is the tension in the wire? 2. Calculate the tension for a 89-g wire. --- I don't know how...
*Sunday, December 2, 2012 at 1:17am by Brienne*

**Physics (please help!!)**

well, if you are pulling at an angle of 32.6 deg... for constant velocity, the horizontal force =friction force friction force=(mg-upwardforce)mu = (450-tension*sin32.4)mu that has to equal horizontal force, or horizontalforce= tension*cos32.4 set them equal tension*cos32.4=...
*Friday, February 18, 2011 at 4:38pm by bobpursley*

**physics**

assuming each side holds half the weight.. I see a triangle where sinTheta=(1/2weight)/Tension sinTheta=(4.2N)/Tension solve for Tension.
*Monday, February 14, 2011 at 1:53pm by bobpursley*

**Physics**

assume the weight of the hanging down mass to be M2, with the other mass is horizonal movement, and mass M1 net force=m2*g=totalmass*a m2*g=(M1+M3)a now tension between them. the tension is pulling mass1 tension=m1*a or, tension is holding back M2 and m2g-tension=M2a either ...
*Monday, March 24, 2014 at 11:18am by bobpursley*

**Physics**

The angles matter. SinTheta=1/2 mg /Tension solve for tension: tension= mg/2sintheta
*Sunday, February 20, 2011 at 5:47pm by bobpursley*

**Physics**

find the moment of inertia for the two disks (each has half the mass). tension*radius= momentinertia*angular acceleartion and tension= mg-ma=mg-m*angacceleration*r so you have two equations, two unknowns, solve for tension, and angular acceleartion. on the way up, tension*...
*Saturday, March 17, 2012 at 5:22pm by bobpursley*

**physics**

well, mg is downward, so tension must be sin30=mg/tension solve for tension.
*Thursday, November 18, 2010 at 9:41pm by bobpursley*

**Physics**

Well, downward forces are W, and upward forces are his Pull, and tension. So his pull + Tension=W on the tire side. On the other side, tension=Pulling force so Pull+tension=W Pull+ Pull=W do the math.
*Saturday, January 9, 2010 at 8:27pm by bobpursley*

**physics**

The sum of the horizontal tension components is zeo and the sum of the vertical tension components equals the weight. The two tension forces are also equal in magnitude, due to symmetry.
*Monday, November 19, 2012 at 1:03am by drwls*

**Physics**

look at each string tension ... tensionin1=31.5 cos51 tensionvertical1=31.5sin51 but the tension vertical in the lower string must be equal to the upper vertical tension.. tensionvertica2=Tensionlower*cos55 31.5sin51=Tensionlower*cos55 solve for tension in the lower string. ...
*Monday, September 30, 2013 at 9:21pm by bobpursley*

**Physics**

well, look at the net accelerating force. Net accelerating force=totalmass*a 1kg*9.8-.2*2.5*9.8=(3.5kg)a solve for acceleration. Tension? Look at the tension pulling the cart: Tension= ma+friction=2.5*a+.2*2.5*9.8 check all that against your force diagram. If you wish, compare...
*Friday, January 21, 2011 at 7:55pm by bobpursley*

**physics**

at the lowest point, tension=mg+mv^2/r at the top, tension=mv^2/r-mg for it to go slack, tension would be zero.
*Friday, December 18, 2009 at 9:53pm by bobpursley*

**AP PHYSICS..so lost**

Tension= mg +- ma where a is the acceleration. + when the elevator is going up (it adds to tension), and - going down, it reduces tension when falling. a= change velocity/time (rest means zero velocity)
*Monday, October 15, 2007 at 11:57pm by bobpursley*

**physics**

A string is hanging from the rearview mirror of you car and a ball is at the end of this string. Suppose that your drive around a circular track at fixed speed. Which list below gives all the forces that act on the ball? A) tension and the force of gravity b) tension force of ...
*Saturday, November 21, 2009 at 6:26pm by jon*

**physics**

A 5.9 m wire with a mass of 79 g is attached to the mast of a sailboat. If the wire is given a "thunk" at one end, it takes 0.087 s for the resulting wave to reach the other end. 1. What is the tension in the wire? 2. Calculate the tension for a 89-g wire. --- I don't know how...
*Sunday, December 2, 2012 at 8:43am by Brienne*

**physics**

For a mass m attached to a string of length L and swings horizontally with a tangential speed of v, the horizontal component of the tension of the string is given by: T=mv²/r If it swings in a vertical, this tension has to be adjusted for the weight of the mass due to ...
*Saturday, November 21, 2009 at 7:15pm by MathMate*

**physics 11**

tension on cable=3*103*g work=tension*distance powerrate=work/time=tension*height/time
*Friday, November 2, 2012 at 5:26am by bobpursley*

**Physics help please**

Tension force in the direction of motion = 125 cos 30 = 108 N Work done by rope tension = Tension force in the direction of motion times distance moved = 108*5 = 541 Joules Since the velocity is constant, the horizontal tension force, 108 N is equal and opposite to the ...
*Thursday, December 5, 2013 at 5:41pm by Damon*

**Physics**

mg is the downward force, mv^2/r is the centripetal force, tension is the string force at the angle. Tan theta= tension/mg solve for tension.
*Sunday, November 18, 2007 at 6:45pm by bobpursley*

**physics**

wavespeed= constant*sqrt(tension/constant1) freq*wavelength=constant*sqr(tension) so if freq is doubled, wavelength same, tension must have went up by 4? check my thinking.
*Monday, January 26, 2009 at 9:58pm by bobpursley*

**physics**

WEll, he has to counter the horizontal force on the ball. draw the force diagram mg down,horizontal, and tension costheta=mg/Tension figure the cosine of 18 degrees, solve for tension.
*Sunday, April 10, 2011 at 1:39pm by bobpursley*

**physics**

Look at the tension: tension=mg/sinTheta Now, the horizontal component of tension is tension*costheta, or mg/tantheta That must equal centripetal force, mv*2/radius. the radius must be 1.50*sinTheta so finally, mv^2/1.5*sintheta =mg/tantheta solve for v check my thinking.
*Wednesday, October 10, 2007 at 7:17pm by bobpursley*

**physics**

The string closest to the axis of rotation would have the maximum tension. Draw the free body diagram and it will be clear that the tension in the closest string balances not only the centrifugal force on the attached ball but also the tension in the string next in the chain.
*Sunday, August 5, 2012 at 2:49am by Ajayb*

**Physics**

The tension is mg+ma The work done by tension is tension*13 work done by weigh? mg*13 worktension=changePE+KEchange solve for KE change, then velocity from that.
*Wednesday, October 29, 2008 at 1:41pm by bobpursley*

**physics help- tension**

Is the time measured from the time the weights are released? If so, you know that the acceleration rate is .35/0.7 = 0.5 m/s^2. For which rope do you want to know the tension? They will be different. Writing the free body F = ma equation for both weights will let go solve for ...
*Sunday, December 6, 2009 at 10:01pm by drwls*

**Vectors/Tension**

The problem is much simpler than you are doing. Due to symettry, each side is supporting half the weight (1/2 mg= 2.5g) Now, using your angles SinTheta=2.5g/Tension Now substitute for sintheta, 2/sqrt(104) and solve for tension
*Wednesday, August 29, 2007 at 8:47pm by Bobpursley*

**Physics**

No, the weight PLUS the acceleration determines the force pullng. pulling force= 10g massbeingaccelerated( 10+3.50)kg retarding force: 3.5gSin40 10g-3.5gSin40=(10+3.5)acceleration solve for acceleration. Now tension pulling: two ways. Tension holding the 10kg weight.. 10g-10*...
*Wednesday, October 19, 2011 at 7:34pm by bobpursley*

**physics**

A string is hanging from the rearview mirror of you car and a ball is at the end of this string. Suppose that you drive around a circular track at fixed speed. Which list below gives all the forces that act on the ball? A) tension and the force of gravity b) tension force of ...
*Monday, November 23, 2009 at 5:57pm by julia*

**Physics**

Remember that tension is just a force. Therefore, it helps to draw a free body diagram. There are two forces on the yo-yo: the force of weight, and the tension of the string. Because the object is rotating, the tension results in a centripetal force (always directed inwards to...
*Sunday, December 13, 2009 at 8:55pm by Marth*

**Physics**

What is surface tension and what does tension in surface mean. Definition of tension?
*Wednesday, April 28, 2010 at 2:20pm by Akashdeep Singh*

**physics**

A picture hangs on the wall suspended by two strings, with è = 61°. The tension in string 1 is 1.8 N. è is connected to string 1, and 32° is connected to string 2. (a) Is the tension in string 1 greater than, less than, or equal to the tension in string 2? greater than less ...
*Thursday, September 30, 2010 at 11:03pm by jack*

**physics**

A 0.21 kg ball on a string is whirled on a vertical circle at a constant speed. When the ball is at the three o'clock position, the tension is 18 N. (c) Is the tension in the string greater when the ball is at the twelve o'clock position or when it is at the six o'clock ...
*Friday, April 4, 2008 at 7:58pm by Johnathan*

**physic**

you start by breaking up the tension in the rope into a vertical part (which reduces force normal and friction), and a horizontal part. Forcenormal=mg-vertical component of tension Friction=forcenormal*mu so to move, the horizontal component of tension must at least equal ...
*Saturday, October 24, 2009 at 2:30am by bobpursley*

**Physics**

at the lowest point, tension= mg+v^2/r solve for velocity At the top, tension= v^2/r-mg when tension is zero, the rope is slack, solve for velocity.
*Saturday, December 5, 2009 at 6:55pm by bobpursley*

**physics**

For the fundamental frequency to change by an octave, the tension T in the string must vary by a factor of 4. (Wave speed and fundamental frequency vary with the square root of the tension). Consider how large an amplitude the pendulum must swing to have the tension vary by a ...
*Wednesday, August 6, 2008 at 12:12am by drwls*

**Physics**

You pull downward with a force of 27 N on a rope that passes over a disk-shaped pulley of mass 1.3 kg and radius 0.075 m. The other end of the rope is attached to a 0.61 kg mass. Find the tension in the rope on both sides of the pulley. I found that the tension on the side you...
*Sunday, March 21, 2010 at 11:51pm by Mary*

**physics**

A window washer is standing on a scaffold supported by a vertical rope at each end. The scaffold weighs 192 N and is 3.4 m long. What is the tension in each rope when the 708-N worker stands 2.40 m from one end? Smaller tension: ___N Larger tension: ___N
*Thursday, April 4, 2013 at 2:58pm by Dan*

**Physics**

tension in the string = m*V^2/r max tension is 70N so Vmax = sqrt(70*r/m)
*Friday, June 29, 2012 at 1:18pm by ajayb*

**Physics**

Wouldn't tension be 1/2 mg/Tension? the 1/2 is used because each side of the wire carries 1/2 the weight.
*Thursday, November 12, 2009 at 6:09pm by bobpursley*

**Physics**

An elevator cable can withstand a maximum tension of 1.89×104N before breaking. The elevator has a mass of 480kg and a maximum acceleration of 2.25m/s^2 . Engineering safety standards require that the cable tension never exceed two-thirds of the breaking tension.
*Wednesday, November 18, 2009 at 12:34pm by Anonymous*

**physics**

A 5 000-N weight is held suspended in equilibrium by two cables. Cable 1 applies a horizontal force to the right of the object and has a tension, T1. Cable 2 applies a force upward and to the left at an angle of 37.0° to the negative x axis and has a tension, T2. What is the ...
*Sunday, September 18, 2011 at 11:04am by Susan*

**PHYSICS**

tension= force repulsion= kQ1*Q2/distance^2 when cut, then T=ma or a= tension/mass
*Wednesday, February 24, 2010 at 9:06pm by bobpursley*

**physics**

maximum tension in the string of an oscillating pendulum is double of the minimum tension. Then angular amplitude is
*Tuesday, December 21, 2010 at 3:47am by Anonymous*

**Physics**

sketch the figure. considering tension, cosTheta=mg/tension period=2PIsqrt(length/g)
*Sunday, February 26, 2012 at 8:31pm by bobpursley*

**physics**

can some one help me with coming with a better way to word theses annswers. As the angle increases, what happens to the tension in the string? *the the tension in the string will get tighter or larger for t1 What would you have to do to the angle to make the tension in the ...
*Wednesday, October 20, 2010 at 10:48am by Derek*

**physics**

can some one help me with coming with a better way to word theses annswers. As the angle increases, what happens to the tension in the string? *the the tension in the string will get tighter or larger for t1 What would you have to do to the angle to make the tension in the ...
*Wednesday, October 20, 2010 at 11:36am by derek*

**physics**

an 6lb object is hanging from a 10lb object which in turn is hanging from a ceiling. need to find tension(T1) of rope from ceiling to 10lb object and tension(T2) from the 10lb object to the 6lb object. please, need assitance in trying to set up the problem. thanks Tension is a...
*Monday, September 25, 2006 at 10:48pm by greg*

**Physics**

Sum moments around the beam end at the wall. mg*L/2-Tension*sin30=0 solve for tension.
*Tuesday, November 16, 2010 at 4:51pm by bobpursley*

**college physics**

If the initial tension in the string is (2.10+/- 0.02)N, what is the tension that would double the wave speed?
*Wednesday, March 20, 2013 at 1:28am by Anonymous*

**Physics help!**

F= ma= Tension-Weight ma+Weight=Tension (4125kg)(0.0300 * 9.8)+ (4125kg)(9.81)=Tension Calculate and this will give you the answer for maximum force. For part (2) You have to subtract them (ma-weight)
*Monday, September 26, 2011 at 6:59pm by J*

**physics**

An elevator with a wieght of 27.8 kN is given an upward acceleration of 1.22 m/s^2 by a cable. a) what is the tension in the cable. b) what is the tension when the elevator is declerating at the rate of 1.22m/s^2 but is still moving upwards? what exactly is a kN? to find the ...
*Monday, November 13, 2006 at 9:50pm by Chris*

**Physics**

The tension will decrease but I just don't know how to explain it.. I took an example of 1.0m with 35 degree and I found tension 0.303 N.
*Thursday, July 28, 2011 at 6:26am by Anonymous*

**physics**

Since the circle is vertical, maximum tension is experienced when the ball is at the bottom of the loop. Tension must support both weight and centripetal force. Require that M*V^2/R + M*g = (maximum tension) Tmax = 50.0 N Then solve for V. M*V^2/R = 50 - 7.35 = 42.65 N V = ...
*Saturday, March 23, 2013 at 11:33pm by drwls*

**physics**

each half of the closline supports 2kg draw the triangle: sin10=2g/tension tension=about 20/sin10=20/(10/57) using the small angle approximation tension=114/10= about 10 N
*Saturday, November 3, 2012 at 7:57pm by bobpursley*

**physics**

if the cables are at the center of the sign, assume each one carries 100N due to symettry. Sin45=100/Tension solve for tension.
*Wednesday, October 6, 2010 at 7:25pm by bobpursley*

**Physics**

The difference in power required from the motor. 1.1*10^4 W, is the towing work, which equals rope tension times velocity. Solve for the tension.
*Friday, October 8, 2010 at 12:06am by drwls*

**Physics**

To solve this problem, you'll need the tension formula which is T=Ma. T is tension, mass M is weight Mg and tension or in other words the mass that is on the surface, & a is acceleration. M=3kg a=2.5m/s2 T=? Just plug it into the formula... T=(3kg)(2.5m/s2) T=7.5N
*Saturday, November 30, 2013 at 5:32pm by Lily*

**Physics**

tension in the cord is made up of weight mg, and centripetalforce directed outward. Add those as vectors to get tension. Period=2PIsqrt(l/g)
*Wednesday, November 4, 2009 at 12:35pm by bobpursley*

**physics**

Fnet = M a = M V^2/R Tension - M g = M V^2/R "tension" is the net centripetal force actng upon the monkey by the arm he is swinging with. That is what you want to calculate. T = M (g + V^2/R) = 9.5 kg*[9.8 m/s^2 + (3.4^2 m^2/s^2)/0.7 m)] The answer will be in Newtons.
*Monday, July 19, 2010 at 1:07am by drwls*

**physics**

three identical blocks are pulled on a horizontal frictionless surface. if the tension in the rope held by the habd is 30N what is the tension in the other ropes?
*Wednesday, February 2, 2011 at 6:26pm by joy*

**s**

F=ma so the tension in a coupling depends on the mass behind the coupling In the case of the just last car, tension=masscar*a now between the 30and 31 car, there are 20 cars behind tension=20(masscar)a
*Saturday, September 22, 2012 at 8:08pm by bobpursley*

**Physics**

you have a tension on the rope, twirling a cylinder. THe tension produces torque, which moves the cylinder.and , it is the cylinder which retards the bucket mass. bucketweight*radius=MomentInertia*angularacceeration. moment of inertia for a cylinder. Look it up. so folve for ...
*Sunday, March 25, 2012 at 2:18am by bobpursley*

**physics**

A rock is suspended by a light string. When the rock is in air, the tension in the string is 43.8 . When the rock is totally immersed in water, the tension is 26.2 . When the rock is totally immersed in an unknown liquid, the tension is 18.8 .
*Friday, May 31, 2013 at 8:00pm by lungani*

**AP Physics**

The force pulling downwards is 4mg but you must take into account Tension. so Torque = I*angular acceleration which in turn ='s rF. where F = Tension(T).
*Monday, February 18, 2008 at 12:41am by Ryan*

**Physics**

the possible frequencies are 440+-1.5 hz Use the law of tensions,,, frequency is proportinal to the square root of tension, or tension is prop to freq squared.
*Saturday, March 29, 2008 at 8:16pm by bobpursley*

**physics **

Two blocks are connected by strings and hung from the ceiling as shown. Tension T1 is 187 N and tension T2 is 78 N. Find the mass of each block.
*Thursday, November 1, 2012 at 11:55am by tomas*

**Physics**

OK, break the problem into two parts, the rope tension into vertical and horizontal parts. Since the wall and block both support the vertical equally, the vertical down force on the blockB is 1/2 weightA. So forcefrictionB= mu*forcenormal =mu(massB*g+1/2 massA*g) now, that ...
*Thursday, November 18, 2010 at 8:25pm by bobpursley*

**physics**

The person weighs m=60 kg, so it takes 60 kg weight (mg) to keep her suspended. If there is no motion, the tension on the rope is therefore 60g. The next step is to establish if there is motion. If the pulley is frictionless, then the tension on each side of the pulley is the ...
*Sunday, June 13, 2010 at 10:01am by MathMate*

**Physics**

In the figure below the left hand calbe has a tension T1 and makes an angle of 42 with the horizontal. the right hand calbe as a tension T3 and makes an angle of 47 with the horizontal. The horizontal cable connecting the two masses has a tension of 37 N. Determine the mass M2.
*Wednesday, September 15, 2010 at 6:09am by Josh*

**physic**

Vertical T = force of burgular Find inclined tension using Ay = A*sin(theta) Find horizontal tension using Pythag: A^2 = Ay^2 + Ax^2 Ax is the horizontal tension
*Monday, October 12, 2009 at 2:08am by Deb*

**physics **

The figure shows two 1.00kg blocks connected by a rope. A second rope hangs beneath the lower block. Both ropes have a mass of 250g . The entire assembly is accelerated upward at 3.00m/s2 by force F. What is F? What is the tension at the top end of rope 1? What is the tension ...
*Monday, November 4, 2013 at 11:06pm by Anonymous*

**Physics**

draw the figure. now divide it in two, right an left. The left side tension is t, holding half the weight 1/2 *1500*g let the angle from the horizontal to the wire be theta (the angle of depression at the poles). SinTheta=750g/tension but cosTheta=.3/30 solve for theta from ...
*Saturday, March 9, 2013 at 1:50pm by bobpursley*

**physics**

Since the string tension supports the 1.48 kg mass that dangles from it, in equilibrium, T = M g = 14.50 N You don't need the information on the air puck on the table to compute the tension, but you could use the tension to compute the required speed of the air puck. Kind of a...
*Saturday, December 17, 2011 at 1:40am by drwls*

**physics**

25 gram mass is given an upward acceleration of 30 m/s^2 by a rope. need help finding tension in the rope? not sure how to set up the problem?? Tension is the reaction force. Clearly you have two forces in opposite directions. Let T be the tension in the rope. The net force ...
*Monday, September 25, 2006 at 12:11am by greg*

**Physics**

A 0.20-kg ball on a string is whirled on a vertical circle at a constant speed. When the ball is at the three o'clock position, the string tension is 16 N. Find the tensions in the string when the ball is at twelve o'clock and at the six o'clock positions. * Physics - ...
*Tuesday, October 6, 2009 at 5:26pm by Sanjna*

**Calc-Based Physics**

Look at the triangle formed with the wire and the horizontal, and the bird vertical. At the bird, the force down is 1/2 mg (we are doing only one side, due to symettry). The other force is tension, along the wire. Looks like sinSag=1/2 mg/tension and... tanSag= .2/50 use the ...
*Friday, October 26, 2007 at 4:25pm by bobpursley*

**physics**

An object of mass m is hanging by a string from the roof of an elevator. We want to compare the tension in the string due to the weight of the object under various conditions. Which statements are true? Choices: True, False. A. If the elevator is moving upwards, and speeding ...
*Wednesday, December 10, 2008 at 5:52am by Sandhya*

**Physics**

A guitar string has a tension of 100 N and is supposed to have a frequency of 110 Hz. When a standard tone of that value is sounded while the string is plucked, a beat frequency of 2 Hz is heard. The peg holding the string is loosened (decreasing the tension) and the beat ...
*Sunday, February 3, 2013 at 3:31pm by Ryan*

**Physics**

A particular steel guitar string has mass per unit length of 1.79 g/m. and tension of 61.9 N. For the wave speed to be increased by 1.9%, how much should the tension be changed? I tried increasing the wave speed (186 m/s) by 1.9%, plug that into v=sqrt(T/linear mass density), ...
*Tuesday, July 17, 2012 at 3:47pm by Bruce*

**Physics**

tensionbottom=mg+mv^2/r solve for v. force on set must equal tension... b.total acceleration is a vector of g downward, and mv^2/r along the radial. but tension alone, along the radial, tension=mgcosTheta+mv^2/r but tension and gravity force=net force net force=mass*...
*Saturday, November 23, 2013 at 8:59am by bobpursley*

**PHYSICS**

Tension= friction+ma-gravity down the ramp tension= mu*mg*cos30+ma-mgsinTheta
*Thursday, September 30, 2010 at 8:18pm by bobpursley*

**Physics**

The clothesline is under tension when you hang from it. Why is the tension greater when the clothesline is strung horizontally than whe is hangs vertically?
*Thursday, November 4, 2010 at 9:45pm by Kelsea*

**physics help please**

the tension on the string has to be equal to the weight hanging down. force on the puck equals tension. force=m v^2/r solve for v
*Sunday, November 27, 2011 at 4:50pm by bobpursley*

**Physics**

Each cable holds one half the weight. verticalforceleft=verticalforceright=24g/2*cosTheta*tension but CosTheta=2/3.5 solve for tension
*Monday, March 26, 2012 at 5:00pm by bobpursley*

**Physics-Please Help Me!!**

5.Assuming the surface tension of water is .073 N/m, what is the force required to overcome the surface tension?
*Monday, November 15, 2010 at 9:53pm by Amber*

**physics**

The wave speed on a string is 148.9 m/s when the tension is 73.4 N. What tension will give a speed 184.9 m/s?
*Friday, November 21, 2008 at 7:43pm by Anonymous*

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