Wednesday

April 16, 2014

April 16, 2014

Number of results: 26

**statstics**

Are you doing the Berkeleyx course???
*Thursday, February 28, 2013 at 7:49am by Ilir*

**statstics**

150
*Saturday, March 2, 2013 at 1:34pm by Anonymous*

**statstics**

.804
*Thursday, March 14, 2013 at 4:31am by Anonymous*

**statstics**

26.46
*Wednesday, March 13, 2013 at 12:59pm by Anonymous*

**statstics**

it is not working , can u plz do it for me
*Wednesday, March 13, 2013 at 12:59pm by ellas*

**statstics**

You have been busted!
*Thursday, March 14, 2013 at 4:31am by Anonymous*

**statstics**

The upper quartile is the 75th percentile.
*Saturday, March 2, 2013 at 1:34pm by PsyDAG*

**Statstics**

Use the same method indicated in the previous post.
*Sunday, March 28, 2010 at 8:50am by PsyDAG*

**statstics**

Check the links below. I answered this one last night.
*Thursday, March 14, 2013 at 4:31am by Dr. Jane*

**Statstics**

I know that I am supposed to use harmonic mean. Just not sure how to set up formula.
*Tuesday, May 3, 2011 at 3:12pm by Robo*

**statstics**

i did't get it even i got the wright answer , how do u calculated upper quartile ?? on hit and trial basis??
*Saturday, March 2, 2013 at 1:34pm by ellas*

**statstics**

90% = mean ± 1.645 SEm SEm = SD/√n
*Sunday, April 14, 2013 at 12:20pm by PsyDAG*

**statstics**

With your limited data, I assume that these are the prices of all the houses. $834,000 - $819,000 = ?
*Thursday, February 28, 2013 at 7:49am by PsyDAG*

**statstics**

If weights are symmetric about the median then is you have 90 lbs at the lower quartile, you should have 150 at the upper quartile. Subtract the two numbers to get the interquartile range.
*Saturday, March 2, 2013 at 1:34pm by Dr. Jane*

**statstics**

a population of score has u=50 and standard devidation =10 if every score in the population is multipied by 2 the new mean and standard would be
*Monday, September 26, 2011 at 9:24pm by mary*

**statstics**

Considering that a researcher can test at the <p = .05 (95%), p = .01 (99%), or p = .001 (99.9%) level for statistical significance, how do you use these three levels in relationship to evaluate risk to patients in implementing the decisions based on research findings?
*Wednesday, August 17, 2011 at 9:44pm by Anonymous*

**statstics**

construct a 90 confidence interval for the population mean ÃŽÂ¼. assume the population has a normal distribution. A sample if 15 randomly selected math majors has a grade point average of 2.86 with a standard deviation od 0.78. Round to the nearest hundredth
*Sunday, April 14, 2013 at 12:20pm by Anonymous*

**Statstics**

A loaf of bread is normally distributed with a mean of 22 ounces and a standard deviation of .5 ounces. What is the probability that a loaf of bread is <21 ounces?
*Sunday, March 28, 2010 at 8:50am by Anonymous*

**statstics**

A distribution of weights is symmetric about its median. The lower quartile of the weights is 90 pounds and the median is 120 pounds. Find the interquartile range of the distribution.
*Saturday, March 2, 2013 at 1:34pm by ellas*

**Statstics**

Cities A, B, C and D are equidistant. That is, B is d miles from A, C is d miles from B, and D is d miles from C. Suppose you travel 55 mph from A to B, 40 mph from B to C, and 50 Mph from C to D. What single, constant speed could you have traveled from A to B to C to D that ...
*Tuesday, May 3, 2011 at 3:12pm by Robo*

**statstics**

A real estate company is selling 32 houses. One of the houses costs $834,000, but in order to attract more buyers, the price is dropped to $819,000. By how much does this change the average price of the 32 houses?
*Thursday, February 28, 2013 at 7:49am by ellas*

**Statstics**

. You have proposed that males will outscore females on a standardized test of math skills. You now are looking at your results from an SPSS t-test which is analyzing for significance at the á = .05 level with a two-tailed test. You see the following output: t = 4.10 sig. = ....
*Tuesday, December 6, 2011 at 8:33pm by Linda*

**statstics**

The lengths of the eggs of a species of bird are roughly normally distributed, with a mean of 32 mm and an SD of 1.2 mm. 1.Approximately what is the 99th percentile of the lengths? Give your answer in mm but please do not enter the units. 2.Approximately 50% of the eggs have ...
*Wednesday, March 13, 2013 at 12:59pm by ellas*

**statstics**

The lengths of the eggs of a species of bird are roughly normally distributed, with a mean of 32 mm and an SD of 1.2 mm. 1.Approximately what is the 99th percentile of the lengths? Give your answer in mm but please do not enter the units. 2.Approximately 50% of the eggs have ...
*Thursday, March 14, 2013 at 4:31am by ellas*

**statstics**

z = (x - 32)/1.2 For 1: you have to use a z-table to find the value where 99% of the values are less than that number meaning that there is 1% in the upper tail. Z-tables to differ from book to book, be sure to read it carefully. Once you have that z- value, substitute it into...
*Wednesday, March 13, 2013 at 12:59pm by Dr. Jane*

**Statstics**

Let x be a random variable representing dividend yield of Australian bank stocks. We may assume that x has a normal distribution with \alpha =2.3% A random sample of 18 Australian bank stocks has a sample mean of x bar = 6.1%. For the entire Australian stock market, the mean ...
*Sunday, August 7, 2011 at 9:21pm by Justina*

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