Thursday

April 17, 2014

April 17, 2014

Number of results: 642

**English**

Are these correct? The beginning of the sentences before "the skiers" are they still considered part of the noun phrase, or are they considered a prepositional phrase, or something different? I believe they are part of the noun phrase, but not sure. The part in the [ ] is what...
*Sunday, November 16, 2008 at 8:51pm by Megan*

**pre-calc**

determine if the following lines are parallel, perpendicular or neither. Explain your reasoning. -2x+3y=3 2x+3y=3 Rewrite them in y = mx + b form to get the slopes, m. The lines are parallel of the slopes are the same. They are perpendicular if the product of the slopes is -1 ...
*Wednesday, January 10, 2007 at 7:01pm by britteny*

**Algebra**

Are the slopes the same? Did you solve for the slope? I don't think the slopes are equal.
*Wednesday, June 18, 2008 at 12:12am by DrBob222*

**physics**

Examine the slopes of the straight lines obtained from the graphs of p versus 1/V. Why are the slopes different?
*Tuesday, December 18, 2012 at 4:47pm by Anonymous*

**algebra**

true slopes of perpendicular lines are negative reciprocals of each other, or the product of their slopes = -1 (1/2)(-2) = -1
*Saturday, November 2, 2013 at 10:54pm by Reiny*

**geometry**

compute the side lengths and slopes. If the sides are all equal, and the slopes are parallel, it's a square.
*Monday, August 13, 2012 at 1:58pm by Steve*

**Math**

take the slopes of lines AB, AC, and BC. Are any of those 3 slopes opposite reciprocals of each other?
*Thursday, April 15, 2010 at 11:56pm by Reiny*

**math**

If two lines are perpendicular, then their slopes are negative reciprocals of each other, or another way of looking at it, when their slopes are multiplied the result is -1 Is (-2/3)(3/2) = -1 ???
*Saturday, July 14, 2012 at 9:35pm by Reiny*

**Statistics**

Suppose the correlation between two variables is -0.57. If each of the y-values is multiplied by -1, which of the following is true about the new scatterplot? It slopes up to the right, and the correlation is -0.57 It slopes up to the right, and the correlation is +0.57 It ...
*Thursday, November 8, 2012 at 9:35am by John*

**statistics**

Suppose the correlation between two variables is -0.57. If each of the y-values is multiplied by -1, which of the following is true about the new scatterplot? It slopes up to the right, and the correlation is -0.57 It slopes up to the right, and the correlation is +0.57 It ...
*Wednesday, November 14, 2012 at 1:02pm by joey*

**statistics**

Suppose the correlation between two variables is -0.57. If each of the y-values is multiplied by -1, which of the following is true about the new scatterplot? It slopes up to the right, and the correlation is -0.57 It slopes up to the right, and the correlation is +0.57 It ...
*Thursday, November 15, 2012 at 10:26am by joey*

**Statistics**

Suppose the correlation between two variables is -0.57. If each of the y-values is multiplied by -1, which of the following is true about the new scatterplot? It slopes up to the right, and the correlation is -0.57 It slopes up to the right, and the correlation is +0.57 It ...
*Friday, November 16, 2012 at 10:34am by John*

**Statistics**

Suppose the correlation between two variables is -0.57. If each of the y-values is multiplied by -1, which of the following is true about the new scatterplot? It slopes up to the right, and the correlation is -0.57 It slopes up to the right, and the correlation is +0.57 It ...
*Sunday, November 18, 2012 at 10:23am by John*

**Statistics**

Suppose the correlation between two variables is -0.57. If each of the y-values is multiplied by -1, which of the following is true about the new scatterplot? It slopes up to the right, and the correlation is -0.57 It slopes up to the right, and the correlation is +0.57 It ...
*Monday, December 17, 2012 at 11:14am by Jill*

**Statistics**

Suppose the correlation between two variables is -0.57. If each of the y-values is multiplied by -1, which of the following is true about the new scatterplot? It slopes up to the right, and the correlation is -0.57 It slopes up to the right, and the correlation is +0.57 It ...
*Tuesday, December 18, 2012 at 10:56am by Jill*

**algebra**

m1 = -A/B = -4/5. m2 = -A/B = -5/4. They are not parallel, because the slopes are not =. They are not perpendicular, because the slopes are not neg. reciprocals. m2 would have to be +5/4.
*Sunday, October 31, 2010 at 2:26pm by Henry*

**Geometry**

slopes of parallel lines are equal. slopes of perpendicular lines are negative reciprocals. What do you think?
*Saturday, July 14, 2012 at 6:39pm by Steve*

**algebra again**

Determine the slopes (m) of the lines by putting the equations in the form y = mx + b. If the product of the two slopes is -1, the lines are perpendicular.
*Sunday, May 2, 2010 at 12:13pm by drwls*

**algebra**

also you can first find y in the equation(s), and then find the slopes, and finally multiply the slopes.
*Tuesday, April 15, 2008 at 4:55pm by Jeremy*

**math**

since the slopes are not the same, not parallel since the slopes are not negative reciprocals, not perpendicular
*Friday, November 16, 2012 at 7:09pm by Steve*

**Economis**

A demand curve that is unit elastic everywhere is a. linear and slopes downward b. linear and slopes upward c. vertical d. horizontal e. nonlinear
*Tuesday, January 19, 2010 at 12:52am by Rosa*

**Algebra**

Very easy Recall that the slopes of perpendicular lines have slopes that are negative reciprocals of each other, or in other words, the product of their slopes is -1 Your first line is x + 3y = 12 So the perpendicular line must be 3x - y = c , the only thing we don't know is ...
*Monday, October 15, 2007 at 10:39pm by Reiny*

**math**

Perpendicular lines have slopes that are negative reciprocals of one another (multiply the two slopes together and their product has to be a negative 1). In y=mx+b, m is the slope.
*Monday, February 22, 2010 at 2:06pm by FiestadeNoche*

**Geometry**

Calculate the slopes of each of the lines between the pair of points. Hint: The slope of the line that is the first side is (y2-y1)/(x2-x1) =(6-3)/(11-2) = 1/3 If the product of the two slopes is -1, they are perpendicular. If not, they aren't.
*Wednesday, November 21, 2007 at 11:47pm by drwls*

**9th grade math**

find a system where the slopes are different. ANy two lines with different slopes intersect at exactly one point. Looks like (C)
*Wednesday, December 5, 2012 at 9:26pm by Steve*

**Algebra**

in y = mx + b, the slop is m for parallel lines the slopes must be the same for perpendicular lines the slopes are negative reciprocals of each other. I see the first slope as +9 and the second as -9 so which fits?
*Sunday, May 16, 2010 at 11:07pm by Reiny*

**geometry**

If the slopes of the lines are equal, the lines are parallel if the slopes are negative reciprocals of each other, the lines are perpendicular, ( e.g. 5/3 vs -3/5)
*Saturday, September 25, 2010 at 7:27am by Reiny*

**Science**

Erosion is worse on slopes because the water flows faster in heavy rains. Trees that are planted to hold the soil in place will help for a 20-100 years, but eventually they tilt and fall on steep slopes, tearing out the root ball and making erosion worse. I have been fighting ...
*Monday, March 1, 2010 at 7:10pm by drwls*

**Math - number of solution**

Transform each equation to the form y=mx+b where m=slope and b=y-intercept. If the slopes (m) are distinct (different), then there is one solution. If the slopes are identical, then check the y-intercepts. If the y-intercepts are different, there is no solution (lines are ...
*Saturday, August 28, 2010 at 4:55am by MathMate*

**math**

The slope of the given equation is 5/7 the slopes of perpendicular lines have slopes that are opposite reciprocals of each other. so the perpendicular line has slope -7/5
*Wednesday, March 17, 2010 at 7:45pm by Reiny*

**Math**

just figure their slopes. If the slopes are the same, L1║L2. If their product is -1, then L1┴L2. Otherwise, neither.
*Thursday, February 20, 2014 at 6:47pm by Steve*

**math**

for Ax + By = C the slope = - A/B parallel lines have equal slopes perpendicular lines have slopes that are opposite reciprocals of each other. let me know what you concluded.
*Wednesday, January 19, 2011 at 8:21pm by Reiny*

**Geology/Glaciers**

Why do north facing slopes on mountains support glaciers today while south facing slopes do not?
*Wednesday, November 12, 2008 at 12:19am by Charlie*

**calculus**

The slopes of the tangent lines to the graph of the function f(x) increase as x increases. At what rate do the slopes of the tangent lines increase? f(x) = x2 – 1 Thanks for the help.. really need it.
*Tuesday, September 21, 2010 at 12:32pm by john*

**math**

Eq1: 4x + 6y = 12. m1 = -A/B = -4/6 = -2/3. Y-int. = C/B = 12/6 = 2. Eq2: 2x + 3y = 6. m2 = -2/3. Y-int. = 6/3 = 2. Since the slopes and Y-intercepts are both equal, the Eqs represent the same line. Therefore, we have an infinite number of solutions. Multiply both sides of Eq2...
*Tuesday, April 2, 2013 at 5:31pm by Henry*

**calculus**

The slopes of the tangent lines to the graph of the function f(x) increase as x increases. At what rate do the slopes of the tangent lines increase? f(x) = x2 – 6 PLZZ help
*Tuesday, September 21, 2010 at 12:51pm by Amanda*

**Geometry**

A Trapezoid has 2 parallel sides which have equal slopes, and 2 non-parallel sides with unequal slopes. So we calculate the slope of all 4 sides and make comparisons: AB. m = (6-2) / (4-2) = 4/2 = 2. BC. m=(-3-6) / (4-4)=-9/0 = undefined. CD. m = (-1-(-3)) / (2-4) = 2/-2 = -1...
*Sunday, April 10, 2011 at 12:00pm by Henry*

**Algebra**

You must have written the second equation incorrectly. It needs a "y" term. It the productsa of the slopes, not the slopes themselves that must be -1. Picking an ordered pair is just a matter of picking x and computing y, for any x that you want. Two ordered pairs define a ...
*Wednesday, March 4, 2009 at 12:54am by drwls*

**alg.**

Determine which two equations represent perpendicular lines. a) y=2x - 6 b) y=1/2x + 6 c) y= -1/2x + 6 d) y= 1/2x - 6 I know that perpendicular lines have negative recipricals, but I'm having trouble with this problem. I think the answer is b & c because they are both 1/2 and ...
*Monday, July 30, 2007 at 8:35pm by lacy*

**math**

The slopes of the lines connecting each pair of the points is different: -1/5, -1 and -3/7 They points cannot be on the same line. The three slopes would be the same if they were on the same line.
*Wednesday, April 22, 2009 at 7:59am by drwls*

**math**

if lines are parallel, they have the same slope so, the first step is to convert each equation to the slope-intercept form: y = -1/4 x + 2/3 y = k/6 x - 5/6 If the slopes are the same, then -1/4 = k/6 k = -3/2 If the lines are perpendicular, their slopes are negative ...
*Thursday, November 17, 2011 at 6:43pm by Steve*

**algebra**

the slopes of your lines are determined by the coefficients of the x terms of your equations. They are 3 for the first one, and -1/2 for the second. Since their product is not equal to -1, they cannot be perpendicular no matter what the value of a is The 5a term has nothing to...
*Sunday, January 27, 2008 at 10:16pm by Reiny*

**math**

To be parallel to the xz plane, y must be constant. In this case, the constant is y = 3. There is more than one line parallel to the xz plane that passes through that point. If the z vs x slopes of the various possible slopes in the y=3 plane are denoted by m, z - 4 = m (x - 2)
*Wednesday, December 19, 2012 at 1:45am by drwls*

**Calculus**

The slopes of the tangent lines are equal to the derivative of the parabola at the points. y ' = 2x, so y'(a) = 2a and y'(-a) = -2a. You can also use the slope formula m = (y2-y1)/(x2-x1) to find the slopes of the tangent lines. Therefore m = (a^2+3-(-6))/(a-0)=(a^2+9)/a. ...
*Monday, June 17, 2013 at 3:45pm by Joe*

**math**

Best I can come up with is: (py - by)/(px - bx) = -1 [(px - ax) / (py - ay)] It relates the slopes of two perpendicular lines: each line's slope is the negative reciprocal of the others. The problem arises when one of the slopes is 0, because then the (negative) reciprocal is ...
*Tuesday, May 5, 2009 at 11:51pm by RickP*

**math helper plese**

2 isosceles triangles have the same height. The slopes of the sides of triangle A are double the slopes of the corresponding sides of triangle B. How do the lengths of their bases compare? A. The base of A is quadruple that of B. The base of A is double that of B. C. The base ...
*Monday, January 17, 2011 at 9:23pm by Kelly*

**math**

y = mx + b In the above Eq, m is the slope and b is the y-int. When 2 lines are perpendicular, their slopes are negative reciprocals of each other: y = (1/2)x + 7 and y = -2x + 7. Two lines are per. if their slopes are reciprocals AND their signs are opposite. These 2 Eq meet ...
*Monday, August 30, 2010 at 11:00pm by Henry*

**algebra**

a) Find the slope of the average cost (0.16). Transform the equation for the price to y=0.14x-0.95 from which the slope can be found. If the slopes are different, the two lines will intersect. If the product of the two slopes is -1, the two lines are perpendicular. b) see a) ...
*Sunday, August 29, 2010 at 11:37pm by MathMate*

**geometry**

easy, after making sketch, show that the slopes of opposite sides are equal. Then draw the diagonals and find their slopes show that the slope of one diagonal is the opposite reciprocal of the slope of the other. Be careful in your slope calculations with the subtraction of ...
*Thursday, December 8, 2011 at 11:57am by Reiny*

**algebra 1**

Slope between two points P1(x1,y1), P2(x2,y2) is given by: m=(y2-y1)/(x2-x1) So the sum of the slopes would be the sum of the slopes LM, MN, and NL. For LM, m=(0-0)/(10-4)=0 I am sure you can complete the rest.
*Friday, December 10, 2010 at 6:12pm by MathMate*

**Algebra 1 ( bobpursley)**

#1 ok you can avoid solving for b by using the point-slope form: y-0 = 2/5 (x-5) #2 how could you get #1 and not get #2? m = -6/7 point-slope form: y-0 = -6/7 (x-0) y = -6x/7 all this means is that b=0 #3 1st has slope -2 the others all have slope 2 #4 only the 1st two. The ...
*Tuesday, December 3, 2013 at 11:24am by Steve*

**Algebra**

Ok, so you know that parallel lines have a special trick with their slopes. When you multiply the two slopes of the lines together, you should get -1. So what number could you multiply 3 by to get a -1? -1/3! So far, your line equation should be y=-1/3 x + b. How do you get b ...
*Tuesday, February 19, 2008 at 10:17pm by Rhonda*

**Math**

consistent if their slopes are different x+y=5 2x-3y=6 dependent if one equation is a multiple of the other. 2x+3y=9 4x+6y=18 inconsistent if the slopes are the same, but one equation is not a multiple of the other. 3x-y=8 9x-3y=5
*Thursday, November 15, 2012 at 3:51pm by Steve*

**algebra**

Change into the standard equation for a straight line of y = mx + b 2x+5y=7 and 5y = -2x+7 then divide by 5 to obtain y=(-2/5)x + 7/5 Second equation is 5x-2y=8 -2y=-5x+8 multiply by -1 2y=5x-8 y=(5/2)x-4 Lines are parallel if the slopes are equal. Lines are perpendicular if ...
*Tuesday, June 3, 2008 at 10:54am by DrBob222*

**Algebra**

you need to get it into slope intercept form--y=mx+b (m being the slope) to figure out whether they are parallel (having equal slopes) or perpendicular (slopes are negative reciprocals) 2y-x=2 2y=x+2 y=1/2x+1 slope=1/2 y+2x=4 y=-2x+4 slope=-2 -2 and 1/2 are negative ...
*Tuesday, February 8, 2011 at 7:46pm by hw*

**math**

Best I can come up with is: (py - by)/(px - bx) = -1 [(px - ax) / (py - ay)] It relates the slopes of two perpendicular lines: each line's slope is the negative reciprocal of the others. The problem arises when one of the slopes is 0, because then the (negative) reciprocal is ...
*Tuesday, May 5, 2009 at 11:51pm by RickP*

**CALCULUS**

y = 0.5x + 6 makes an angle arctan 0.5 = 26.57 degrees with the x axis. It slopes upward. y = -.75x -1 makes and angle arctan -0.75 = -36.87 degrees with the x axis (It slopes downward) The sum of those two angles is the acute angle between them. 63.44 degrees. Round it to 63 ...
*Tuesday, May 10, 2011 at 11:37am by drwls*

**MaTH**

First you have to put your line into y = mx + b format. 9x - 6y = -3 -6y = -9x -3 y = 9/6 x - 3 y = 3/2 x - 3 Parallel lines have the same slope. m represents you slope. Perpendicular lines have slopes that are negative reciprocals of each. flip the fraction and include the ...
*Monday, February 18, 2013 at 5:20pm by JJ*

**Geometry HELP**

If two lines are parallel then their slopes are equal If two lines are perpendicular, their slopes are negative reciprocals of each other (opposite in sign and the fraction is flipped) for the first one, find slope(AB) and slope(CD), and decide second is very easy slope of ...
*Tuesday, June 8, 2010 at 11:05pm by Reiny*

**math**

i am not going to solve the problem for you but i will tell you how to first you have to convert both equations to y=mx+b form. You can do it by isolating the y variable to one side. If Y has a coeffienct then divide it by the coefficent and do the same thing on the other side...
*Thursday, April 16, 2009 at 5:32pm by math pro*

**Algebra 2**

arrange the equations into the form ax + by = c 1. -14x = -632 - 26y ---> 14x - 26y = 632 slope = 14/26 = 7/13 y = (7/13)x - 316/13 ---> 7x - 13y = 316 slope = -7/-13 = 7/13 since the slopes are equal, they must be parallel. To be perpendicular, their slopes must be ...
*Tuesday, March 17, 2009 at 10:10pm by Reiny*

**algebra**

The solution to a system of linear Eqs is the point where they intesect. If the lines are parallel, they cannot intersect and, therefore, have no solution. If we solve the Eqs of two parallel lines, the answer will not make sense. For example, we could get -15 = 30 which is ...
*Wednesday, March 21, 2012 at 12:27pm by Henry*

**Math**

Perpendicular lines have slopes that are negative reciprocals. You have to find the slope of the given line by putting the equation in y = mx + b form 4x + 5y = 4 5y = -4x + 4 y = (-4/5)x + 4/5 m = -4/5 so the slope of the line perpendicular to this line is 5/4 (Note the two ...
*Sunday, March 10, 2013 at 7:15pm by Dr. Jane*

**Math - PreCalc (12th Grade)**

Which statement is true for any linear system of two equations in two variables? A) The system is independent if the slopes of the two lines are equal. B) The system is inconsistent if the y-intercepts of the two lines are equal. C) The system is independent if the graphs of ...
*Thursday, March 20, 2014 at 12:24pm by Shawna*

**MATH**

For the floor plans given in exercise27, determine whether the side through the points (2, 3) and (11, 6) is perpendicular to the side through the points (2, 3) and (-3, 18). Compute the slopes of the two lines. If the product of the slopes is -1, then te lines are ...
*Wednesday, February 14, 2007 at 8:58pm by stacy*

**Geometry**

Can someone show me how to solve this? Someone tried to explain it to me-I didn't get it.A line contains the points (3, -4) and (5, 2). Another line graphed in the same coordinate plane contains the points (0, 5) and (-2, -1). Based on the slopes of these lines are they ...
*Tuesday, July 24, 2007 at 12:38pm by Jim*

**MaThS**

A. Y = -2x+1, and Y = -2x+3. m1 = m2 = -2. The lines are parallel, because their slopes are equal. B. x+y/3+5 = 0, and 2y+6x = 1 x+y/3=-5, and 6x+2y = 1. 3x+y = -15, and 6x+2y = 1 m1 = -A/B = -3/1 = -3 m2 = -6/2 = -3 The slopes are equal; therefore, the lines are parallel.
*Sunday, August 11, 2013 at 12:23pm by Henry *

**Math**

compare slopes
*Tuesday, September 4, 2007 at 1:38pm by manny*

**math**

how do i make slopes?
*Wednesday, December 10, 2008 at 5:58pm by khadidrah*

**rate of change / slopes**

(5,5) (5,6) (5,7) 0
*Friday, May 27, 2011 at 8:44am by Henry*

**math116**

The question of how many solutions, if any,usually comes up when solving 2 equations simutaneously. First, we need to define solution: The solution is the point where the two lines inter- sect. I F they do not INTERSECT, there is no solution. Parallel lines do not INTERSECT ...
*Thursday, August 5, 2010 at 12:04pm by Henry*

**math b**

A median is a line joining the a vertex to the mid-point of the opposite side. If the median is also an altitude to side BC, then the median should be perpendicular to BC. Let D be the mid-point of BC. The coordinates of D should be rather obvious, being the mid-point of ...
*Monday, May 25, 2009 at 1:44pm by PC*

**precalc**

what are the slopes of the asymptotes of the hyperbola: (x^2)/9 - (y^2)/4 = 1
*Sunday, February 24, 2008 at 9:46pm by Kristen*

**geometry**

The product of the two slopes is -1.
*Tuesday, March 8, 2011 at 8:04pm by MathMate*

**mathematics**

the slopes of the lines are 1 and -1, so they are perpendicular.
*Tuesday, August 6, 2013 at 12:12pm by Steve*

**Physics**

I have a few questions to answer and I don't know how to start answering them. 1. On a position time graph, compare the instantaneous velocities of an object when the tangent to the curve slopes upward to the right, when the tangent slopes downward to the right, and when the ...
*Thursday, February 3, 2011 at 10:33pm by Sups*

**I NEED HELP AND FAST!**

can anyone help me on finding slopes of a line?
*Wednesday, February 11, 2009 at 7:44pm by anonymous*

**english**

The slopes of the mountain are covered with trees.
*Thursday, November 11, 2010 at 11:20am by neshia*

**algebra**

yes, the slopes are negative reciprocals of each other
*Thursday, September 29, 2011 at 9:51pm by Reiny*

**MaThS**

the lines have slopes -1 and 1. So, they are perpendicular.
*Wednesday, August 7, 2013 at 4:29pm by Steve*

**Geometry**

slopes AB: 3/2 CD: -2/3 so, perpendicular
*Wednesday, September 4, 2013 at 3:52pm by Steve*

**math**

this problem seems with too many numbers that i don't know where to start. or even how.I have to answer the problem on top not the one that says number 27. The problem: Geometry. For the floor plans given in exercise 27, determine whether the side through the points (2,3) and...
*Friday, December 22, 2006 at 8:40pm by jasmine20*

**Math - Slopes **

slope=deltaheight/deltadepth=10/8
*Sunday, November 1, 2009 at 11:09am by bobpursley*

**algebra1**

y = -x+8 and x+y=7 OR y = -x +7 Line are parallel, both with slopes = -1 y = -x+8 y = -x+7 There is no solution
*Thursday, May 17, 2012 at 7:28pm by Rezu*

**Math**

Parallel lines have equal slopes.
*Wednesday, November 20, 2013 at 6:27pm by Henry *

**Math**

Parallel lines have equal slopes.
*Wednesday, November 20, 2013 at 6:29pm by Henry *

**Math**

Parallel lines have equal slopes.
*Wednesday, November 20, 2013 at 6:30pm by Henry *

**math, slope**

strange question! depends what you mean by "all of these". If you just want the slopes of the 6 consecutive line segments, it wouldn't be so bad take slope between (0.0) and (20,.166) then the slope between (20,.166) and (40,.181) etc. add up the 6 slopes, then divide by 6 If ...
*Monday, October 5, 2009 at 1:01pm by Reiny*

**science**

Nope. Check this page. You'll find the answer fairly quickly. http://www.google.com/search?source=ig&hl=en&rlz=1G1GGLQ_ENUS314&q=Gentle+slopes+and+rounded+mountains+&aq=f
*Tuesday, February 17, 2009 at 1:27pm by Ms. Sue*

**Algebra**

I think I got it! Are the slopes of the given and parallel lines = ?
*Wednesday, June 17, 2009 at 1:42pm by Beth*

**Algerbra1**

One. You can tell without calculating because the slopes are different.
*Tuesday, October 20, 2009 at 3:12pm by jim*

**math-slopes**

Put x,y in each and find out which equations are equal.
*Monday, February 1, 2010 at 10:42am by bobpursley*

**geometry**

how do you find the perpendicular lines if on the graph are undefied and 0 slopes?
*Wednesday, February 2, 2011 at 9:03pm by Jezebell*

**algebra**

slopes are different, so the lines must intersect: consistent
*Wednesday, January 2, 2013 at 10:57am by Steve*

**algebra**

Y = (1/4)x + 2 Y = (1/4)x m1 = m2 = 1/4 The lines are parallel, because their slopes are equal.
*Friday, January 17, 2014 at 7:13pm by Henry *

**Gr 10 math - finding slopes in shapes**

Thank you, Steve.
*Sunday, March 23, 2014 at 8:38pm by iza*

**calculus**

The curves intersect where a/(x-8) = (x-8)^2 a = (x-8)^3 x = 8 + cbrt(a) Now, we need to find a such that the curves are perpendicular. slope of x^2 - 16x + 64 = 2x - 16 slope of a/(x-8) = -a/(x-8)^2 perpendicular slope = (x-8)^2/a So, when x = 8 + cbrt(a), and the slopes are ...
*Friday, October 28, 2011 at 2:41pm by Steve*

**physics**

You and your friend are sledding on two sides of a triangle-shaped hill. On your side, the hill slopes up at 30.0° from the horizontal; on your friend's side, it slopes down at the same angle. You do not want to climb up the hill, so you tell your friend to thread a rope ...
*Thursday, September 15, 2011 at 9:51pm by Anonymous*

**economic**

Why do the production possibility frontier curve slopes downward and why it could be a line?
*Friday, January 11, 2008 at 3:58am by Dorin*

**math**

perpendicular lines have slopes that are the negative reciprocal of each other.
*Tuesday, April 7, 2009 at 7:51pm by bobpursley*

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