Sunday

April 20, 2014

April 20, 2014

Number of results: 52,743

**Simplifying Rational Expressions4x-12/4x**

These are the answers i wanted corrected: 4x12/4x d+7/d^2-49 t^2-25/t^2+t-20 2x^2+6x+4/4x^2-12x-16 6-y/y^2-2y-24 You will have to use brackets to show the intended order of operation. How can we 'correct' your work if you supply neither solutions nor answers? I will be happy ...
*Sunday, March 11, 2007 at 10:20pm by mike*

**Simplifying Rational Expressions**

Can someone slove these for me 1.(4x-12)/4x 2.(d+7)/(d^2-49 ) 3.(t^2-25)/(t^2+t-20) 4.(2x^2+6x+4)/(4x^2-12x-16) 5.(6-y)/*y^2-2y-24) all you have to do is reduce like #1 4x-12 ______ 4x cross out the 4x b/c it's on the top and bottom which leaves just -12 on the top You can't ...
*Wednesday, May 16, 2007 at 9:16pm by mike*

**Simplifying Rational Expressions**

Can someone PLEASE solve these for me 1.4x-12/4x 2.d+7/d^2-49 3.t^2-25/t^2+t-20 4.2x^2+6x+4/4x^2-12x-16 5.6-y/y^2-2y-24 You need to use parentheses to clarify the menaing of those expressions. For example, if you mean (4x-12)/4x instead of 4x - (12/4x), then the answer is 4(x-...
*Wednesday, May 16, 2007 at 4:41pm by mike*

**derivative **

F(X)=2x^2(3-4x)^2 This is what I have so far. I am usually pretty good at simplifying but I am missing something here. f'(x)=2x^2(4)(3-4x)^3(-4) + (3-4x)^4(4x) Here is where I go wrong. (Answer from book) =4x(3-4x)^3(-12+3) ================================= I get F(X)=2x^2(3-...
*Saturday, June 11, 2011 at 11:31am by Damon*

**Simplifying Rational Expressions**

Can anyone help me with these 3x-9/3x x^2-25/x^2+6x+5 4x8/105x 4x+4/x^22x3 2x^2+14x+12/4x^4x8 nevermind
*Sunday, March 11, 2007 at 10:08pm by mike*

**Simplifying Rational Expressions**

1. 4x-12/4x 2. d+7/d^2-49 3.t2-25/t^2+t20 4.2x^2+6x+4/4x^212x16 5.6y/y^22y24 Can someone help me with these,please,lol,I'm brain dead Try to factor where you can, then simplify as much as you can. I'll show you the first two problems; maybe you can try the rest on your own. #1...
*Wednesday, March 7, 2007 at 6:30pm by mike*

**Simplifying Rational Expressions**

Alright I believe i got it right this tim(They should be typred out correctly).Can someone solve these for me 1.(4x-12)/4x 2.(d+7)/(d^2-49) 3.(t^2)-25/(t^2+t-20) 4.(2x^2+6x+4)/(4x^2-12x-16) 5.(6-y)/(y^2-2y-24) We do not do your work for you. Find the factors for the numerator ...
*Wednesday, May 16, 2007 at 8:58pm by mike*

**algebra**

*simplifying rational expressions a. 6x+12/4-x b. 3x^2/12-2x
*Tuesday, November 13, 2012 at 7:55pm by jaime*

**Math**

Use rational exponents to simplify the radical. If rational exponents appear after simplifying, write the answer in radical notation. 20sqrt(x^12)
*Saturday, April 17, 2010 at 6:04pm by Help please*

**derivative **

29) Find the derivative of the function. F(X)=2x^2(3-4x)^2 This is what I have so far. I am usually pretty good at simplifying but I am missing something here. f'(x)=2x^2(4)(3-4x)^3(-4) + (3-4x)^4(4x) Here is where I go wrong. (Answer from book) =4x(3-4x)^3(-12+3) Thanks for ...
*Saturday, June 11, 2011 at 11:31am by Steff*

**math**

When simplifying a rational fraction, why do you need to factor the numerator and the denominator? Include two examples! to get like terms Can you explain a little more? When you factor then you can cancel like terms Example: 12/3 (3)(4) ------- = 4/1 =4 3 i need to ask you a ...
*Tuesday, June 14, 2005 at 10:52pm by jenn*

**Algebra**

I need help multiplying rational expressions.. x-2/x+3 x 4x+12/6 first I took the four out from 4x +12/6 so I got x-2/x+3 x 4(x+3)/6 but now I'm not sure what to do?
*Wednesday, May 25, 2011 at 8:08pm by Michelle*

**Pre-Calculus**

Simplifying Complex Fractions [(x+3)/12] / [(4x-5)/15] [(x+3)/12] x [15/(4x-5)] (x+3)5/4(3x-5) (5x+15/12x-20)<-- final answer Did I do this right. If not could you please explain how to do it correctly
*Wednesday, February 27, 2013 at 3:28am by Caroline*

**Simplifying Rational Expressions**

1.4x12 / 4x 2.d+7 / d^2-49 3.t^2-25 / t^2+t-20 4.2x^2+6x+4 / 4x^2-12x-16 5.6-y / y^2-2y-24 1. 12 [4x] cancels out. so you're left with just 12. 2. 1/d-7 factor the d^2-49 to (d+7)(d-7). cancel out the (d+7) 3. (t-5)/(t-4) factor both numerator and denominator. so then it's: (t...
*Sunday, March 11, 2007 at 11:33pm by mike*

**Math - Rational Roots**

1.) What are the possible rational roots of the function f(x) = 3x^4 - x - 2 2.) What are the rational roots of the following equation: x^3 - 4x^2 - 4x +16 = 0 Thank you for any help!
*Sunday, September 12, 2010 at 9:39pm by Julia*

**08.02 Multiplying and Dividing Rational Expression**

Can someone solve these for me?Can someone correct meif I didn't type these right 1.(m-2)/(m-5)*(m+5)/(m-2) 2.4(x+2)/5x*(6x^2)/2x 3.(25-x^2)/12*6/(5-x) 4.(a^2-9)/a^2*(a^2-3a)/(a^2+a-12) 5.(5x-5)/(16)/(x-1)/6 6.(6-3x)/(5)/(4x-8)/25 7.(x^2-9)/(4X+12)/(x-3)/6 8.(x^2+13x+12)/(x+2...
*Wednesday, May 16, 2007 at 9:06pm by mike*

**12th grade - Math**

factoring usually assumes we are dealing with rational numbers x^2 - x + 12 = 0 does not factor (there are no two numbers which multiply to get 12 and add to get -1) 2. x(4x^2 + 21x - 18) = x(4x - 3)(x + 6) 3. grouping x^2(x-1) - 1(x-1) = (x-1)(x^1 - 1( = (x-1)(x-1)(x+1) or (x...
*Wednesday, September 1, 2010 at 8:26am by Reiny*

**Math-Rational #'s**

Just trying to understand this. Please let me know if I did these right. Thanks!!! -7 as a rational # = -7/10 -3.03 as a rational # = -33/10 -2 3/12 as a rational # = -25/12 1.03 as a rational # = 13/10
*Monday, March 15, 2010 at 8:52pm by Kate*

**Algebra**

Take any number (except for 1). Square that number and then subtract one. Divide by one less than your original number. Now subtract your original number. You reached 1 for an answer, didn’t you? How does this number game work? (Hint: Redo the number game using a variable ...
*Monday, April 21, 2008 at 12:14pm by Candace*

**algebra**

Take any number (except for 1). Square that number and then subtract one. Divide by one less than your original number. Now subtract your original number. You reached 1 for an answer, didn’t you? How does this number game work? (Hint: Redo the number game using a variable ...
*Thursday, March 25, 2010 at 12:51am by Anonymous*

**Algebra Help PLEASE**

Take any number (except for 1). Square that number and then subtract one. Divide by one less than your original number. Now subtract your original number. You reached 1 for an answer, didn’t you? How does this number game work? (Hint: Redo the number game using a variable ...
*Friday, June 6, 2008 at 4:27pm by Anonymous*

**Algebra Help PLEASE**

Take any number (except for 1). Square that number and then subtract one. Divide by one less than your original number. Now subtract your original number. You reached 1 for an answer, didn’t you? How does this number game work? (Hint: Redo the number game using a variable ...
*Friday, June 6, 2008 at 4:27pm by Katina*

**Math**

Use rational exponents to simplify the radical. If rational exponents appear after simplifying, write the answer in radical notation. 3sqrt(2)/ 5sqrt(2)
*Saturday, April 17, 2010 at 6:05pm by Help please*

**Multiplying and Dividing Rational Expressions**

Can someone solve these for me?Can someone correct meif I didn't type these right (m-2)/(m-5)*(m+5)/(m-2) 4(x+2)/5x*(6x^2)/2x (5x-5)/(16)/(x-1)/6 (6-3x)/(5)/(4x-8)/25 (x^2-9)/(4X+12)/(x-3)/6 (x^2+13x+12)/(x+2)/(x+1) or can someone do a few for me
*Monday, May 21, 2007 at 6:52pm by mike*

**math**

•Post a response to the following: Take any number (except for 1). Square that number and then subtract one. Divide by one less than your original number. Now subtract your original number. Did you reached 1 for an answer? You should have. How does this number game ...
*Wednesday, October 1, 2008 at 2:08am by Anonymous*

**ALGEBRA**

i NEED MORE THAN JUST THE EXAMPLE i ALSO NEED TO EXPLANATION Take any number (except for 1). Square that number and then subtract one. Divide by one less than your original number. Now subtract your original number. You reached 1 for an answer, didn’t you? How does this number...
*Tuesday, March 9, 2010 at 8:05pm by SLIM*

**Simplifying Rational Expressions**

12x1
*Wednesday, May 16, 2007 at 4:41pm by mavhel*

**algebra**

Factor this polynomial: F(x)=x^3-x^2-4x+4 Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3). The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you...
*Friday, January 19, 2007 at 9:31am by bailey*

**algebra 2**

List all possible rational zeros of each function. f(x)=4x^5+4x^2-9 Find all rational roots of each function f(x)=2x^3+x^2+8x+4
*Saturday, May 5, 2012 at 8:53pm by Zac*

**Math 209**

When simplifying a rational fraction, why do you need to factor the numerator and the denominator? If there is a common factor in both the numerator and denominator, that factor will cancel, thus simplifying the fraction. e.g. 15/18 = (3*5)/3*6) =(3/3)*(5/6) =(1)*5/6 =5/6
*Tuesday, April 3, 2007 at 8:24pm by Jennifer*

**pre calculus**

all the rational possibilities are ±1,±2,±3,±4,±6,±12 That's a lot, but it's easy to check the small values. A little synthetic division shows that f(x) = (x-1)(x^3+3x^2-4x-12) = (x-1)(x-2)(x^2+5x+6) = (x-1)(x-2)(x+2)(x+3)
*Monday, April 29, 2013 at 11:10am by Steve*

**school work**

Factoring Polynomials and Simplifying Rational Expressions
*Thursday, December 11, 2008 at 2:07pm by sherri*

**Calculus**

I will assume you meant (4x^2 +6x−12)/(x^3 − 4x) = (4x^2 + 6x - 12)/( x(x+2)(x-2) ) split it into partial fractions let A/x + B/(x+2) + C/(x-2) = (4x^2 + 6x - 12)/( x(x+2)(x-2) ) multiply by x(x+2)x-2) A(x^2-4) + Bx(x-2) + Cx(x+2) = 4x^2 + 6x - 12 This must be true...
*Sunday, May 26, 2013 at 3:33am by Reiny*

**Math**

if it's an integer, it's obviously rational: 3,-10 if it's a terminating decimal, it's obviously rational 12.3978 If it's a repeating decimal, it's rational: 12.278963 = 12.27 + 8963/1000000 Otherwise it's irrational: √2 = 1.41421356...
*Friday, September 27, 2013 at 7:30pm by Steve*

**4th grade**

i used the equation: 1/2x+1/4x+3=x then add 1/2x and 1/4x: 3/4x+3=x then subtract 3/4x on both sides:3=1/4x then divide by 1/4x: 12=x -12 coins is the answer :)
*Wednesday, April 8, 2009 at 5:57pm by Courtney*

**Algebra**

Take any number (except for 1). Square that number and then subtract one. Divide by one less than your original number. Now subtract your original number. You reached 1 for an answer, didn’t you? How does this number game work? (Hint: Redo the number game using a variable ...
*Wednesday, August 25, 2010 at 1:28am by Spring*

**math**

I need help making up a number game for simplifying rational fractions
*Tuesday, May 12, 2009 at 12:57pm by shelly*

**Simplifying Rational Expressions**

1) d + 7/d^2 - 49 2)b^2 - 10b + 21/b^2 - 11b + 28 Please help me.
*Wednesday, June 3, 2009 at 11:11pm by Claire*

**math**

4-4x > 16 Since 4 does not contain the variable to solve for, move it to the right-hand side of the inequality by subtracting 4 from both sides. -4x>-4+16 Add 16 to -4 to get 12. -4x>12 Divide each term in the inequality by -4. - 4x/-4<12/-4 Simplify the left-hand ...
*Sunday, June 13, 2010 at 8:00pm by Abby Clark*

**algebra**

Use the rational zero theorem to list all possible rational zeros for the given function f(x)=x^3-4x^2-19x-14
*Saturday, June 8, 2013 at 10:29pm by Sharday*

**Calculus**

Yoiu understand correctly what you need to do, but you should write: "g(x)= x^3+4x-16=0" Instead, you can say that if x = g(14), then x satisfies the equation: x^3+4x-16 = 0 Use the rational roots theorem. Since 16 has many divisors, you can try to shift x, e.g. put x = t + 1...
*Tuesday, March 31, 2009 at 5:57pm by Count Iblis*

**math**

When simplifying a rational fraction, why do you need to factor the numerator and the denominator? Include two examples
*Tuesday, June 14, 2005 at 10:52pm by shirley*

**Algebra**

x^2 - 4x + 17 = 29 x^2 - 4x - 12 = 0 1. by factoring: (x-6)(x+2) = 0 x = 6 or x = -2 2. by completing the square: x^2 - 4x + ___ = 12 + ____ x^2 - 4x + 4 = 12 + 4 (x-2)^2 = 16 x-2 = ± 4 x = 2 ± 4 = 6 or -2 3. by formula x = (4 ± √(16-4(1)(-12))/2 = (4 ± √64)/2 = (4...
*Sunday, April 26, 2009 at 2:05pm by Reiny*

**please help solve algebra problem**

For this question to make sense, I will assume you meant: 4x/(x^2-18x+72) + 4/(x-6) the first denominator factors to (x-6)(x-12), so it becomes your lowest common denominator then 4x/(x^2-18x+72) + 4/(x-6) = 4x/[(x-6)(x-12)] + 4/(x-6) =[4x(x-6) + 4] / [(x-6)(x-12)] = [4x^2 - ...
*Friday, October 19, 2007 at 9:23pm by Reiny*

**MATH...somewhat urgent**

first one is correct second one: in 4x-12+12=3(0)-12 you added 12 on one side, but subtracted on the other. should have been 4x-12+12=3(0)+12 4x = 12 x = 3, so x-intercept is (3,0) last one: change x+4y=8 to 4y = -x + 8 y = (-1/4)x + 2 comparing it to y = mx + b we can see the...
*Sunday, November 22, 2009 at 5:36pm by Reiny*

**Math- Algebra II**

x^2-4x+12=0 Complete the square to solve for x. Okay I know how to do up to here: (-4/2)^2 -12=x^2-4x(-4/2)^2 2-12= x^2-4x+2 -10= DO I FACTOR IT?
*Wednesday, January 5, 2011 at 10:07pm by Christina*

**Algebra 2**

(3-x)/-4 = (x+6)/3 subtract the terms on the right over to the left (everything) [(3-x)/-4]-[(x+6)/3]=0 find a common denominator for 4 and 3 which is 12 [-3(3-x)/12]-[4(x+6)/12]=0 multiply over (-9+3x)/12 - (4x+24)/12= 0 [(-9+3x)-(4x+24)]/12 = 0 dont forget the negative (-3+...
*Friday, August 24, 2007 at 1:20pm by ~christina~*

**algebra**

use the rational root theorem to list the possible rational roots for each of the following equations f(x)=x^2+2x+1 f(x)=x^2-2x+5 f(x)=x^2+4x-5
*Wednesday, June 1, 2011 at 7:28pm by Anonymous*

**Algebra**

Use the Rational Theorem to list the possible rational roots. f(x)=x^2+2x+1 f(x)=x^2-2x+5 f(x)=x^2+4x-5
*Sunday, March 21, 2010 at 12:15pm by Paula*

**Mica**

you could sketch it and see appr. where it crosses the x-axis. let f(x) = x^3 - 2x^2 - 4x - 8 If there are any rational factors, then test for f(x) = 0 using x = ±1, ±2,±4, and ±8 none work, so there are no rational factors.
*Thursday, April 8, 2010 at 10:44am by Reiny*

**Math**

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function. -2x^4+4x^3+3x^2+18
*Tuesday, February 18, 2014 at 8:16pm by John*

**Math**

Hello, I have two more rational exponent question that I wanted to verify please: 4x^3y^-2 _________ 2x^-1y^4 = 2x^4y^6 is this correct? 2nd question: [w^1 / w^-3] my answer: = [w^(1)(-4)/ w ^ (-3)(-4)] = w^-4 / w^12 = w^12 / w^4 = w^3 / w Is this right?
*Thursday, November 18, 2010 at 2:21pm by Dania*

**Math**

f(x) = (x-1)(4x^2+4x+5) the quadratic has no real roots, so the only rational root is x=1.
*Monday, December 17, 2012 at 3:11pm by Steve*

**Solving Rational Equations**

not much of a problem here. Since 5-x = -(x-5), 4x/(x-5) = -8/(x-5) 4x = -8 x = -2
*Wednesday, February 27, 2013 at 11:30pm by Steve*

**Algebra 2**

If there is a rational root, it would be +or- 1,2,3,4,6,8 or 12. x = -2 works, so x+2 is a factor. So, after one factoring step, and a bit of polynomial long division, you have (x+2)(x^3 -x^2 -6x +18) = 0 Next, use the rational root theorm on the cubic factor. You will find ...
*Friday, February 18, 2011 at 8:38pm by drwls*

**calculus**

pleaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaasw help can you pleaaaaase help me find the area between y=cos(4x) and y=1-cos(4x) 0<=x<=pi/4 i tried to solve it, and i got like : 2*sqrt3+ pi/12 is it right? if not please tell me how can i solve it...i'm really confused i found ...
*Sunday, May 2, 2010 at 6:37pm by aymal*

**math**

List all possible rational zeros of... h(x)= 2x to the (4th power) - 5x (to the third power) + 3x (to the 2nd power) + 4x - 6 Use the Rational Roots Theorem. Any root of the form p/q with p and q relatively prime must be such that p divides 6 and q divides 2. You then find the...
*Monday, May 21, 2007 at 6:22pm by Kate*

**Polynomial Fucntion Problem**

Could you help me with the following problem, I dont understand how to do it. Am I suppose to use the linear factorization theorem? Find an nth degree polynomial function with real coefficients satisfying the given conditions. 1. n=3; 3 and i are zeros; f(2)=20 my answer ...
*Tuesday, October 9, 2007 at 7:58pm by Jen*

**precalc/trig**

Write the partial fraction decomposition of the rational expression. 4x^2–19x+31/ (x+2)(x^2–4x+5)
*Saturday, December 3, 2011 at 11:19am by Robert*

**algebra**

Simplifying Rational Expressions: a^3-2a^2/2a^2-4a
*Thursday, May 19, 2011 at 3:59pm by layla*

**Derivatives**

how can you possibly get a polynomial as the derivative of a rational function? apparently f(x) = ln(x^2+1) f'(x) = 2x/(x^2+1) f"(x) = 2(1-x^2)/(x^2+1)^2 since if f =u/v f' = (u'v-uv')/v^2 so, the derivative of f' is ((2)(x^2+1) - (2x)(2x))/(x^2+1)^2 = (2x^2+2 - 4x^2)/(x^2+1)^...
*Monday, May 6, 2013 at 11:42am by Steve*

**10th grade math**

4x - 5y = 0 (#1) 4x + 6y = 12 (#2 x 2) -11y = -12 I subtracted them y = 12/11 back in #1 4x = 5(12)/11 x = 15/11
*Monday, October 20, 2008 at 9:27pm by Reiny*

**math**

When simplifying a rational fraction, why do you need to factor the numerator and the denominator? Include two examples! I will be happy to critique your thinking on this. I wouldn't ask if I knew how to guess
*Tuesday, June 14, 2005 at 11:07pm by jenn*

**AED **

Explain why this statement is true: when simplifying rational expressions, we must cancel factors only, and not terms. Give an example using just numbers.
*Saturday, July 10, 2010 at 12:35am by Lori*

**Math**

Explain why this statement is true: when simplifying rational expressions, we must cancel factors only, and not terms. Give an example using just numbers.
*Wednesday, July 14, 2010 at 9:31pm by Lori*

**calculus**

i did all that, i found Pi/12 then , i took the integral from 0 to pi/12, and from pi/12 to pi/4 and i got: integr from 0 to pi/12 cos(4x)-(1-cos(4x) + integ from pi/12 to pi/4 1-cos(4x)-cos(4x) but i'm not sure if it was right or not...can u check with me please?
*Saturday, May 1, 2010 at 3:51pm by aymal*

**Math**

A rational function g has the lines x=2 and x=-2 as vertical asymptotes, the line y=4 as a horizontal asymptote, and numbers 3 and 1 as zeros. Find a formula for g(x). So I got g(x)=(4x^2-16x+12)/(x^2-4) Is this correct
*Monday, September 6, 2010 at 9:10pm by Leanna*

**algebra**

4x^2 - 7x + 3. Use the AC Method: A * C = 4 * 3 = 12 = -3 * -4, 4X^2 + (-3X + -4X) +3, Group the 4 terms into 2 factorable pairs: 4x^2 -4x) + (-3x + 3), Factor 4x from the 1st pair & -3 from the 2nd pair: 4x(x - 1) + -3(x - 1), Factor (x - 1) from each term: (x - 1) (4x - 3).
*Tuesday, November 2, 2010 at 2:38pm by Henry*

**Partial Decompostion Fractions**

Can you please help me with the following questions please, I dont understand them. I know the general rule about them. Write the partial fraction decomposition of the rational expression. (x^2+4x-1)/(x^2+3)^2 (4x^3+4x^2)/(x^2+5)^2
*Saturday, November 17, 2007 at 9:34pm by Soly*

**Algebra-Partial Fractions**

Can you please help me with the following questions please, I dont understand them. I know the general rule about them. Write the partial fraction decomposition of the rational expression. (x^2+4x-1)/(x^2+3)^2 (4x^3+4x^2)/(x^2+5)^2
*Monday, November 19, 2007 at 7:32pm by Soly*

**algebra**

When you tried it, you incorrectly added 4x + 12 = 16x. ________ The x intercept is a point on the x axis. In other words, the y value at that point(s) is 0. So, given your equation 4y - 12 = 4x, set y equal to 0 and solve for x. 4(0) - 12 = 4x x = ?
*Sunday, August 16, 2009 at 7:20pm by Marth*

**math**

You have two different equations. Where does B come from? 4x - 2 = 10 4x = 12 x = 3 4x^2 - 2 = 10 4x^2 = 12 x^2 = 3 x = √3 = 1.7321
*Monday, August 23, 2010 at 11:41am by PsyDAG*

**Analytic Geometry**

Your description defines an ellipse. does the question expect you to find that equation by using that definition? if so, then let such a point on that locus be P(x,y) √[(x-2)^2 + y^2] + √[(x+2)^2 + y^2] = 8 √[(x-2)^2 + y^2] = 8 - √[(x+2)^2 + y^2] square...
*Friday, January 14, 2011 at 8:11am by Reiny*

**math**

remember , volume = lwh x(12x-15)(12x-21) = 945 simplifying a bit x(3)(4x - 5)(3)(4x-7) = 945 x(4x-5)(4x-7) = 105 16x^3 -48x^2 +35x - 105=0 by grouping ... 16x^2(x - 3) + 35(x-3) = 0 (x-3)(16x^2 + 35) = 0 x = 3 or x^2 = -35/16 , which is not real so the only real solution is x...
*Wednesday, October 9, 2013 at 8:30pm by Reiny*

**calculus quick question**

write it as g(x) = (1 - 4x^2)^(1/2) g ' (x) = (1/2)(1 - 4x^2)^(-1/2) (-8x) = -4x(1 - 4x^2)^(-1/2) now by the product rule g '' (x) = (-4x)(-1/2)(1-4x^2)^(-3/2) (-8x)- 4(1 - 4x^2)^(-1/2) = (-16x^2)(1-4x^2)^(-3/2) - 4(1 - 4x^2)^(-1/2) = -4(1 - 4x^2)^(-3/2) [ 4x^2 - (1-4x^2...
*Sunday, December 2, 2012 at 12:08pm by Reiny*

**precalc!!!!!**

f(x) =3x-4x^2 f(f(x))=3(3x-4x^2)-4(3x-4x^2)^2 factor out (3x-4x^2) =(3x-4x^2)(3-4(3x-4x^2) =(3x-4x^2)(3-12x+16x^2) f(f(f(x))=3(3x-4x^2)(3-12x+16x^2)-4(3x-4x^2)(3-12x+16x^2)^2 factor out (3x-4x^2)(3-12x+16x^2) f(f(f(x))=(3x-4x^2)(3-12x+16x^2)(3-4(3x-4x^2)(3-12x+16x^2)) =(3x-4x^...
*Monday, March 5, 2012 at 5:11am by Susan*

**Calculus**

A rational function g has the lines x=2 and x=-2 as vertical asymptotes, the line y=4 as a horizontal asymptote, and numbers 3 and 1 as zeros. Find a formula for g(x). So I got g(x)=(4x^2-16x+12)/(x^2-4) Is this correct Math Mate?
*Monday, September 6, 2010 at 6:55pm by Leanna*

**Calculus (Reiny or MathMate)**

A rational function g has the lines x=2 and x=-2 as vertical asymptotes, the line y=4 as a horizontal asymptote, and numbers 3 and 1 as zeros. Find a formula for g(x). So I got g(x)=(4x^2-16x+12)/(x^2-4) Is this correct
*Monday, September 6, 2010 at 8:49pm by Leanna*

**algebra2**

Solve each of the following quadratic equations. can some explain how to do these kinds of problems 4x^2=13x+12 i believe if i am understanding this i am supose to add to where i get =0 4x^2-13x+12=0 now what do i need to do I am thinking factoring but I am not sure how to do ...
*Wednesday, May 9, 2007 at 2:11pm by Tina*

**algebra**

First combine like terms. 4x^2-8x-12+6x = 4x^2 -2x -12 = (4x+6)(x-2)
*Wednesday, November 28, 2012 at 1:27pm by PsyDAG*

**Algebra**

Can someone please explain how to do these problems. 1)write a polynomial function of least degree with intregal coefficients whose zeros include 4 and 2i. 2)list all of the possible rational zeros of f(x)= 3x^3-2x^2+7x+6. 3)Find all of the rational zeros of f(x)= 4x^3-3x^2-...
*Friday, August 10, 2007 at 10:30pm by Marissa*

**maths**

after expanding your expression and simplifying it, I got x^4 - 8x^3 + 15x^2 + 4x - 20 trying a few values, I found x = 2 to be a root. that left me with (x-2)(x^3 - 6x^2 + 3x + 10) after a synthetic division, and what do you know, x = 2 works here too, so we have (x-2)(x-2)(x...
*Wednesday, August 3, 2011 at 11:41am by Reiny*

**ALGEBRA**

y=-4x+3 y=-4x-9 y=-4x+12 y=-4x-45 y=-4x-5 are all parallel lines
*Monday, September 14, 2009 at 10:18pm by Reiny*

**Algebra 2**

Find all numbers that must be excluded from the domain of the given rational expression. 1) x^2+4x/x^2-16 2) 6x^3y-6xy/x^3+5x^2+4x 3) 4-x^2/x^2+x-6
*Tuesday, October 25, 2011 at 11:56pm by Anonymous*

**Algebra 2**

Find all numbers that must be excluded from the domain of the given rational expression. 1) x^2+4x/x^2-16 2) 6x^3y-6xy/x^3+5x^2+4x 3) 4-x^2/x^2+x-6
*Wednesday, March 14, 2012 at 9:19pm by Gabby*

**math**

Select the expression that is equivalent to -4(x-3) a) -4x-3 b) -4x+3 c) -4x-12 d) -4x+12
*Tuesday, February 12, 2013 at 1:25pm by monet*

**Algebra**

Please check my answers. Thanks! Solve the polynomial equation. In order to obtain the first root, use synthetic division to test the possible rational roots. 5.2x^3-13x^2+22x-8=0 -My answer:{1/2,2,4} 6.x^3-8x^2-x+8=0 -My answer: {1,-1,8} Find the rational zero of the ...
*Tuesday, October 9, 2007 at 9:13pm by Jes*

**Algebra- is my answer right**

Use the rational zeros theorem to list all possible rational zeros of the following. -2x^3-x^2-4x-5 I got +-1,+-5+-,5/2,+-1/2 Be sure that no value in your list appears more than once.
*Tuesday, February 1, 2011 at 5:06am by Jen*

**algebra**

5x^3+4x^2-10x-8 Note that the coefficients are 5,4, -10,-8 with 5,4 as a common factor =5,4, -2(5,4) So we can factorize by grouping. 5x^3+4x^2-10x-8 =x^2(5x+4) -2(5x+4) Taking (5x+4) as the common factor =(x^2-2)(5x+4) would be the answer for rational factors. Further ...
*Sunday, July 24, 2011 at 1:37am by MathMate*

**Calculus**

Notice that the derivative of the power cos^2 (4x) shows up as multiple, so we can just reverse the chain rule I know that it must be something like (cos 4x)^3.... so from y ' = sin 4x (cos 4x)^2 we get y = sin 4x (cos 4x)^3 (1/3) (-1/sin 4x) (1/4) = (-1/12) cos^3 (4x) ) which...
*Saturday, November 19, 2011 at 1:24pm by Reiny*

**math**

Multiplying and Dividing Rational Expressions: 2) x^2-8x+7/x^2+6x-7 = (x-7)/(x+7) 3) x^2-5x+6/x+4 times 3x+12/x-2 =3(x-3) 4)2x-3/5x+1 divided by 6x^2-13x+6/15x^2-7x-2=1 5) x^3-9x/x^2+11x+24 times x^2+7x-8/x^2-4x+3= x(x-3)(x-1)/(x+3)(x+8) 6) 4x-8/x^2-x-6 divided by x^3 +x^2-6x/...
*Tuesday, August 3, 2010 at 1:42pm by Jetta*

**math**

Multiplying and Dividing Rational Expressions: 2) x^2-8x+7/x^2+6x-7 = (x-7)/(x+7) 3) x^2-5x+6/x+4 times 3x+12/x-2 =3(x-3) 4)2x-3/5x+1 divided by 6x^2-13x+6/15x^2-7x-2=1 5) x^3-9x/x^2+11x+24 times x^2+7x-8/x^2-4x+3= x(x-3)(x-1)/(x+3)(x+8) 6) 4x-8/x^2-x-6 divided by x^3 +x^2-6x/...
*Wednesday, August 4, 2010 at 9:46am by Jetta*

**College Algebra**

#1. assuming base 8, just for ease of readability, 2logx = log(4x+12) log(x^2) = log(4x+12) so, if the logs are equal, so are the numbers: x^2 = 4x+12 x^2-4x-12=0 (x-6)(x+2)=0 x=6 only, since log(-2) is not real. #2. so far, so good. Recall that adding/subtracting logs means ...
*Wednesday, December 4, 2013 at 1:17pm by Steve*

**math**

Take any number (except for 1). Square that number and then subtract one. Divide by one less than your original number. Now subtract your original number. Did you reach 1 for an answer? You should have. How does this number game work? Hint: Redo the number game using a ...
*Tuesday, November 2, 2010 at 5:33pm by Paula*

**pre calc need help**

4x +2/3-3/4 =1/2 or, when you combine 2/3 and -3/4, 4x-1/12=1/2 It's saying that you get 1/2 if you multiply a certain number by 4, then subtract 1/12 from it. You want to find the number itself, so peel away all of the operations you performed on it: ADD BACK THE 1/12: 4x=7/...
*Wednesday, April 29, 2009 at 10:51pm by blue*

**algebra**

y=2x-6 4x-2(2x-6)= 12 4x-4x+12=12 12=12 infinite number of solutions
*Sunday, September 12, 2010 at 8:49pm by Joshua*

**Trig**

if the inverse is y = 5/(x+4) , then the inverse of the inverse (the original) is x = 5/(y+4) xy + 4x = 5 y = (5-4x)/x so we have f(x) = (5-4x)/x and g(x) = 4(x-2) g(5) = 4(5-2) = 12 f(g(5)) = f(12) = (5-48)/12 = -43/12
*Friday, October 12, 2012 at 1:44am by Reiny*

**7th grade math**

x + 4 (x + 3) This is not a FOIL situation. You must first clear the parentheses. 4 times x = 4x 4 times 3 = 12 We now have: x + 4x + 12 Combine like terms is our next step. x + 4x = 5x Final answer: 5x + 12 Done!
*Tuesday, February 19, 2008 at 4:41pm by Guido*

**math**

sums and differences of rational algebraic expression please answer the following 9ab/cd^2 - 7ab/cd^2 another 3/x-1 - 2/x-1 another is 4x/4x-y - 2x/4x-y another is 3x/2y - 3x-2y/3x+2y another is 8/3x - 3/4x + 4/12x another is x-3/3x+1 + x+5/3x+1
*Friday, October 8, 2010 at 8:30am by jazmin*

**Math**

4x + 4y = -36 -4x -4x 4y = -4x-36 /4 /4 /4 y = -x-9 Now you substitute this equation into the second one. 4x + 4(-x-9)= 12 Distribute the 4 4x-4x = -36 0x = -36 0 is not equal to -36, so that means this has no solution.
*Wednesday, February 16, 2011 at 10:36am by Anonymous*

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