Wednesday

April 16, 2014

April 16, 2014

Number of results: 926

**AE is this correct?**

You're doing great, Scooby! And you're welcome.
*Friday, March 6, 2009 at 6:47pm by Ms. Sue*

**Mathematics**

By the way, having gotten interested, I also solved this by brute force trial and error. I assumed an exponential type solution: y = Ae^x + Bxe^x+ C then dy/dx = Ae^x + Bxe^x + Be^x plug that in Ae^x + Bxe^x + Be^x - Ae^x/x - Be^x - C/x = 1/x + 1 + Ae^x + Bxe^x+ C combine like...
*Saturday, December 29, 2007 at 6:20am by Damon*

**AE**

Scooby, I gave you a series of sites on that topic yesterday.
*Thursday, August 21, 2008 at 3:27pm by GuruBlue*

**AE,, this right?>(revised)**

Wonderful answer, Scooby!
*Thursday, March 12, 2009 at 10:49pm by Ms. Sue*

**AE**

Scooby...now you need to find some material that supports your point of view...
*Thursday, August 21, 2008 at 3:27pm by GuruBlue*

**AE....**

Scooby -- please post the answers you've found for this question. We'll be glad to comment on it and add to it if necessary.
*Wednesday, March 11, 2009 at 9:43pm by Ms. Sue*

**AE**

Scooby, when you have done the research and have written a rough copy, we will be happy to make further suggestions and corrections. We do not do your work for you..... as you well know by now.
*Saturday, August 23, 2008 at 2:16am by GuruBlue*

**Math Calculus Help**

we know that p = ae^kt using the known values, √e/2 = ae^k e/2 = ae^2k divide to get (e/2) / (√e/2) = e^k √e = e^k so, k = 1/2 now, we see that √e/2 = ae^(1/2) so a = 1/2 p(t) = 1/2 e^(t/2) p(4) = 1/2 e^2
*Thursday, November 15, 2012 at 2:45pm by Steve*

**Scooby -- AE**

Scooby, it looks to me like you have a good handle on how you learn best... I always had the most success with the hands on techniques...Projects for building something that demonstrated a principal... like building a 3 faced representation of the Capital, White House and ...
*Friday, August 1, 2008 at 4:47pm by GuruBlue*

**AE..**

Scooby -- For this assignment, you need to show what you have learned about teaching. You can't copy from the internet, but you must present your thoughts and beliefs. What are YOUR ideals for effective classroom management? How will YOU organize your classroom? How will YOU ...
*Sunday, April 12, 2009 at 8:30pm by Ms. Sue*

**Reaction rates**

so... k=Ae^(Ea/RT) Do I set it up as ratios? I.e. 0.0000100s-1=Ae^(-Ea/R * 636) ____________________________ 0.000479s-1=Ae^(-Ea/R * 700) A cancels out ...and then solve from there?
*Saturday, November 20, 2010 at 10:37pm by Confused*

**ae**

Scooby, sometimes "setbacks" are blessings. I quit a PhD program because I was not learning anything, and was not having fun. It turned out, I started to have fun again, and was damn good at what I was doing, and I grew much more than I had in years. So blessings often jump ...
*Sunday, July 5, 2009 at 6:30pm by bobpursley*

**Gr. 9 Math (continued)**

Given AE=4, EB=9, If AE≠EB, the only way that AEFG and EBHF are similar is that AE<EF<EB, which means really that AEFG is similar to FEBH to ensure the vertices correspond. If that's the case, Let EF=x, then AE/x = x/EB, or x² = AE*EB = 36 EF = x = 6 (negative ...
*Sunday, December 12, 2010 at 1:58pm by MathMate*

**geometry!**

oin AC and DE. Triangles AFE and DFC are similar. so AF/FC = AE/CD = AE/EB also AE + EB = AB ie AE +234AE =AB so AE/AB =1/235 so AF/FC = 1/235 FC = 235 AF now, AC = AF +FC = 236AF ie AC/AF = 236/1 ie AC : AF = 236 : 1
*Thursday, February 28, 2013 at 12:54am by Navneet*

**Reaction Descriptions**

abd, bf, cf, cd, ae, ae is correct
*Wednesday, January 12, 2011 at 9:46pm by caitlin*

**Reaction Descriptions**

abd, bf, cf, cd, ae, ae is correct :)
*Wednesday, January 12, 2011 at 9:46pm by chemlab*

**geometry**

Given: ABC,/ AD bisects <BAC, and /AE=/ED Prove: AE/AC = BD/BC
*Monday, November 25, 2013 at 3:38am by loveofnursing*

**GEOMETRY**

GIVEN: TRIANGLE ABC,AD bisects <BAC,and AE=ED, PROVE:AE/AC=BD/BC
*Monday, September 17, 2012 at 8:41pm by HELEN*

**AE**

Scooby, which of these environments do you learn best in? In what kind of atmosphere do you most enjoy learning? In what kind of atmosphere have you found teachers who are most successful in helping YOU learn? This is where I would start forming a philosophy. I discovered that...
*Thursday, July 31, 2008 at 2:07pm by GuruBlue*

**Scooby -- AE**

I just saw your reply from last night and responded to it. http://www.jiskha.com/display.cgi?id=1217527628
*Friday, August 1, 2008 at 4:47pm by Ms. Sue*

**Geometry / Proofs**

Given: Triangle ABC with AD bisecting angle BAC, and AE is congruent to ED (both line segments). Prove: AE/AC = BD/BC. Statements Reasons
*Tuesday, August 27, 2013 at 3:24pm by Lisa*

**Physics**

Ap/Ae = pi*(8.25r)^2/pi*r^2=68.1r^2/r^2= 68.1/1 Ap = 68.1*Ae. Ap = Area of the planet. Ae = Area of the earth.
*Sunday, September 8, 2013 at 2:09pm by Henry *

**geometry**

In the accompying diagram of circleo, diameter ad,chord AE,ans secantsCAB and CDE are drawn ; m angle BAD=40;and m arch AE=5((m arch ED) what is the measure of ACE?
*Saturday, March 10, 2012 at 9:21pm by Vanna*

**Algebra**

If m angle FGE =5x+10, Find the value of x so that line FC is perpendicular to Line AE. Line AE is a striaght line
*Sunday, September 9, 2012 at 12:07am by Maria*

**chemistry**

I agree that the explosion of gasoline is a low energy of activation as is H2 and O2 explosion with a spark. I would agree that the rusting of a nail is a higher AE than gasoline explosion but, to repeat myself, high is a relative term. And I'm not so sure that it is ...
*Saturday, January 17, 2009 at 2:47pm by DrBob222*

**geometry**

How AC is related to AE, are they equal? If yes, then you have to solve this way: AC=AE 2x-1=x^2-2, then solve for x x=1
*Sunday, September 18, 2011 at 8:27pm by Anonymous*

**MATH**

Complete Problem 34 in Section 5.2 Exercises (Ch. 5) of Essentials of Geometry for College Students. 34. Given: ABC,/ AD bisects <BAC, and /AE=/ED Prove: AE/AC = BD/BC
*Monday, June 17, 2013 at 10:46pm by BJ*

**Integrated Math 1**

CE must be 7 also, as C bisects AE.You have a right triangle AED, so AE=14 (hypotenuse), side DE 10. AD=sqrt(14^2-10^2)
*Sunday, July 15, 2012 at 6:47pm by bobpursley*

**AE**

Scooby... everyone has failed at something. The trick is in what did you "learn" from the failure. I always learn 'well, I won't make that mistake again." Then I go take another swat at it... The trick is to LEARN something from everything that happens in your life...both the ...
*Sunday, August 24, 2008 at 2:35am by GuruBlue*

**Math**

if h(x) = ae^bx, just plug in your values: 22 = ae^2b 14.08 = ae^4b divide one by the other, and the a's cancel 14.08/22 = .64 = e^2b e^b = .8 22 = a*.64 a = 34.375 h(x) = 34.375 e^bx = 34.375 * 0.8^x
*Saturday, February 16, 2013 at 3:43pm by Steve*

**ae**

Scooby, Bobpursley is right. Go for the career that makes you excited about getting up in the morning. It doesn't have to be the "popular" career of the moment. It doesn't have to be the career that will make you an instant fortune. It doesn't have to be the job your parents ...
*Sunday, July 5, 2009 at 6:30pm by GuruBlue*

**chemistry**

It would help if we knew what you were doing. #2. Theoretical yield = TE actual yield = AE = TE-1.5 %yield = (AE/TE)*100 =
*Wednesday, July 18, 2012 at 6:27am by DrBob222*

**Geometry Proofs**

Given: AD=AB AE= AD/3 AF= AB/3 Prove: AE= AF
*Monday, August 13, 2007 at 10:25am by Sarah*

**geometrY!**

Given: Let r=AE:EB Draw a diagram of the parallelogram ABCD. Insert E on AB. Extend DE to join CA at F. (The above is as given by the question). Examine the triangles FAE and DBE. Show that they are similar noting that FA is parallel to DB. Therefore the ration FE:ED = AE:EB ...
*Wednesday, February 27, 2013 at 1:56am by MathMate*

**trigonometry**

Construct the trapezoid ABCD ,where AB || CD AB = 12 and CD = 22 angle C=65 and angle D = 40 Draw AE || BC where E is on CD So now ABCE is a parallelogram, and CE = 12 which makes ED = 10 Now look at triangle AED, by corresponding angles angle AED = 65°, angle D = 40 leaving ...
*Friday, February 10, 2012 at 6:18am by Reiny*

**Geometry**

1. Ae = 360 / N = 90, 90N = 360, N = 360 / 90 = 4 Sides. 2. At = 80 + 90 + 103 + x = 360, X = 360 - 273 = 87 deg. 3. At =(N - 2)180, At = (7 - 2)180 = 900 deg. 4. Ae = 360 / N = 360 / 5 = 72 DEG. 5. 6. 7. At = (N - 2)180 = 1440, (N - 2) = 1440 / 180 = 8, N = 8 - 2 = 6 Sides. 8...
*Tuesday, November 30, 2010 at 2:16pm by Henry*

**Electricity help needed please**

I assume your wires are round, not spherical. That is, they have a circular cross-section. If A has power P, and cross-section area a, length m and resistivity r, then its resistance R = rm/a P = E^2/R E^2/(rm/a) = aE^2/rm Conductor B has power (2a)E^2/(2r*3m) = 4/6 aE^2/rm = ...
*Friday, November 15, 2013 at 5:49am by Steve*

**Calculus**

f = ax e^(bx) f' = ae^(bx) + abx e^(bx) = ae^(bx) (1+bx) f'(1/8) = 0, so b = -8 f(1/8) = 1 = a(1/8)e^(-1), so a=8e f(x) = (8e)x e^(-8x)
*Wednesday, March 6, 2013 at 4:09pm by Steve*

**calculus**

let y = 4 x dy = 4 dx so integral of e^y sin y dy try e^y cos y derivative = -e^y sin y + e^y cos y so try ae^y cos y + be^y sin y derivative = -ae^ysiny+ae^ycosy+be^ycosy+be^ysiny we need a=-b to get rid of cos terms so -b e^y cos y +b e^y sin y so be^y sin y - be^y cos y try...
*Wednesday, May 5, 2010 at 2:08am by Damon*

**MATHS**

Let segments AB and CD have common point E. Then AC<AE+EC and BD<BE+ED. AE+EC+BE+ED=AB+CD
*Saturday, September 3, 2011 at 8:48am by Mgraph*

**Calculus**

Hmmm. Forget the above. We want y(0) = 1 and y(2.32) = 0.1 So, assuming y = aebx we have 1 = ae0 a = 1 so, y = ebx .1 = e2.32b ln .1 = 2.32b b = -2.3/2.3 = -1 So, y = e-x Am I still wrong here?
*Sunday, October 30, 2011 at 10:03pm by Steve*

**geometry**

I must assume that A and B are the centres of your two circles for this to make sense. Join AE, and you will have a right angles triangle AEB with AE=11, AB = 19 , and BE = x x^2 + 11^2 = 19^2 x^2 = 240 x = √240 so the area = (1/2) base x height = (1/2)(√240)(11...
*Thursday, April 4, 2013 at 1:30am by Reiny*

**Math**

This is rather crude. http://awwapp.com/s/ae/d6/63.html
*Monday, August 5, 2013 at 4:06pm by Ms. Sue*

**geometry**

Just lay out the points on the line BD contains the right half of BC and the left half of CE So, what's left is the same length: The left half of AC and the right half of CE AE = AB + BC + CD + DE but BD = BC + CD = 14 so, AE = AB + 14 + DE However, AB = BC and CD = DE so AB+...
*Sunday, December 11, 2011 at 7:20pm by Steve*

**PSYCHOLOGY **

thanks
*Friday, December 4, 2009 at 7:36pm by scooby*

**PSYCHOLOGY **

thanks
*Sunday, December 6, 2009 at 8:42pm by scooby*

**religion**

o ok thank you
*Saturday, March 20, 2010 at 2:03pm by scooby*

**child development**

Thank you!!!
*Saturday, January 16, 2010 at 8:30pm by scooby*

**diversity in classroom**

is anyone on?
*Saturday, May 22, 2010 at 1:43am by scooby*

**math**

.42
*Wednesday, May 23, 2012 at 7:19pm by scooby*

**Anatomy & Physiology**

Thank you for using the Jiskha Homework Help Forum. Try the following: http://www.accessexcellence.org/AE/AEC/CC/heart_anatomy.php Sra
*Thursday, August 14, 2008 at 3:47pm by SraJMcGin*

**math**

Tough to figure out from the "non-given" diagram. let DB, the horizontal distance be x. angle ADB = 48 degrees, 30 minutes (not inches!) = 48.5° so tan 48.5 = 40/x x = 40/tan48.5 = 35.39 m from C, draw a horizontal to meet AB at E tan 24.5 = AE/x AE = xtan24.5 = 16.13 m so ...
*Sunday, June 19, 2011 at 4:05am by Reiny*

**education**

Scooby, what is your question?
*Sunday, March 15, 2009 at 2:53pm by GuruBlue*

**algebra updatte**

no idea
*Wednesday, November 4, 2009 at 8:48pm by scooby*

**classroom instruction**

oh ok ty
*Sunday, March 28, 2010 at 9:35pm by scooby*

**classroom management**

ok ty
*Friday, May 14, 2010 at 9:59pm by scooby*

**science**

i found it thanks it was the erlenmeyer
*Wednesday, September 1, 2010 at 8:55pm by scooby*

**English**

wehhehewewhe
*Thursday, September 21, 2006 at 3:53pm by scooby dooo*

**Anatomy**

Thank you for using the Jiskha Homework Help Forum. Try the following: http://www.accessexcellence.org/AE/AEC/CC/heart_anatomy.php
*Tuesday, May 27, 2008 at 1:17pm by SraJMcGin*

**Geometry**

Given triangle ABC, AD bisects angle BAC,and AE=ED Prove AE/AC=BD/BC Because I cant draw it I will explain. Its a triangle, A is the point at the top, B is the point at the bottom left and C is the point at the bottom right.There is a line going right down the middle, which is...
*Saturday, September 29, 2012 at 8:23pm by Teisha*

**math**

Scooby, what is a composite number?
*Wednesday, July 15, 2009 at 7:55pm by DrBob222*

**plagiarism am i correct? plz help**

r u sure on these?
*Tuesday, January 12, 2010 at 7:22pm by scooby*

**child development does it sound ok**

is it suppose to be an*
*Friday, January 15, 2010 at 8:22pm by scooby*

**psychology**

How psychological disorders are classified:
*Monday, January 18, 2010 at 7:33pm by scooby*

**classroom management**

thank you ms sue
*Saturday, June 5, 2010 at 2:45pm by scooby*

**classroom management**

You're welcome, Scooby.
*Saturday, June 5, 2010 at 2:45pm by Ms. Sue*

**math**

i am usre there is more can you help me plz
*Wednesday, September 1, 2010 at 9:13pm by scooby*

**math check if right plz**

thank you
*Sunday, September 8, 2013 at 4:57pm by scooby*

**math check answer plz**

thank you
*Sunday, September 8, 2013 at 5:31pm by scooby*

**math algebra**

4/5(2x-1)>12
*Friday, October 30, 2009 at 2:37pm by scooby*

**math algebra**

would that be 11:30 am?
*Friday, November 6, 2009 at 1:27pm by scooby*

**geography**

how do you do a high pressure weather report?
*Sunday, January 10, 2010 at 12:35pm by scooby*

**plagiarism am i correct? plz help**

You're welcome, Scooby.
*Tuesday, January 12, 2010 at 7:22pm by Ms. Sue*

**ms sue**

can you tell me if i am correct plz?
*Thursday, January 14, 2010 at 10:31pm by scooby*

**child development**

but is that developmentally, and list ofcharacteristics
*Friday, January 15, 2010 at 6:39pm by scooby*

**child development**

what info r they talking about
*Monday, January 18, 2010 at 5:28pm by scooby*

**aed**

i am not understanding this assignment for some reason
*Wednesday, February 10, 2010 at 9:31pm by scooby*

**aed**

ok i think i am getting it some what lol
*Wednesday, February 10, 2010 at 9:31pm by scooby*

**instruction(am i right track)**

You're welcome, Scooby! :-)
*Friday, February 26, 2010 at 9:28pm by Ms. Sue*

**classroom instruction**

i have no idea lol
*Wednesday, March 10, 2010 at 9:40pm by scooby*

**classroom instruction**

did i answer all the questions then?
*Sunday, March 28, 2010 at 9:35pm by scooby*

** DIVERSITY IN THE CLASSROOM update**

good thinking. thank you
*Friday, April 16, 2010 at 9:32pm by scooby*

**math last one sorry**

p+1.6 divided by (-0.4)=-12
*Sunday, September 8, 2013 at 6:04pm by scooby*

**Math.. check answer please ( thanks)**

You're welcome, Scooby.
*Tuesday, November 4, 2008 at 9:34pm by Ms. Sue*

**Human Resource Management**

Great, Scooby! You can do it!! :-)
*Thursday, September 10, 2009 at 4:48pm by Ms. Sue*

**human resource managment**

ok thank you i am doing it on an elementary school teacher
*Saturday, November 7, 2009 at 8:42pm by scooby*

**child development (answer included)**

thank you very much
*Thursday, December 3, 2009 at 9:26pm by scooby*

**child development**

i tried that i am having trouble rewording it
*Sunday, December 6, 2009 at 5:05pm by scooby*

**geography**

what is high pressure in terms a child can understand
*Sunday, January 10, 2010 at 12:48pm by scooby*

**plagiarism am i correct? plz help**

i try my best ill be done in may i hope
*Tuesday, January 12, 2010 at 7:22pm by scooby*

**academic honesty (answers included)**

thank you ms sue
*Wednesday, January 13, 2010 at 4:29pm by scooby*

**child development**

is that like infant early childhood etc.? if so then what do i do
*Monday, January 18, 2010 at 5:28pm by scooby*

**child development**

never mind i found it sorry
*Tuesday, January 19, 2010 at 10:20pm by scooby*

**classroom instruction**

do u have a site for example? i can look at
*Wednesday, March 10, 2010 at 10:58pm by scooby*

** DIVERSITY IN THE CLASSROOM **

thank you i hope i can figure this assignment out
*Friday, April 16, 2010 at 9:04pm by scooby*

**science**

what are the beakers called that are shaped like pears?
*Wednesday, September 1, 2010 at 8:55pm by scooby*

**math**

what different combinations can you make with the letters BLSV.
*Wednesday, September 1, 2010 at 9:13pm by scooby*

**math questions**

is there a site i could use to help me with compund inequalities?
*Sunday, November 13, 2011 at 4:49pm by scooby*

**math**

Scooby -- Divide 21 by 50. What do you get?
*Wednesday, May 23, 2012 at 7:19pm by Ms. Sue*

**math**

so u divide the top from the bottom and thats ur asnwer
*Wednesday, May 23, 2012 at 7:19pm by scooby*

Pages: **1** | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | Next>>