Tuesday
March 11, 2014

# Search: Scooby -- AE

Number of results: 922

AE is this correct?
You're doing great, Scooby! And you're welcome.
Friday, March 6, 2009 at 6:47pm by Ms. Sue

Mathematics
By the way, having gotten interested, I also solved this by brute force trial and error. I assumed an exponential type solution: y = Ae^x + Bxe^x+ C then dy/dx = Ae^x + Bxe^x + Be^x plug that in Ae^x + Bxe^x + Be^x - Ae^x/x - Be^x - C/x = 1/x + 1 + Ae^x + Bxe^x+ C combine like...
Saturday, December 29, 2007 at 6:20am by Damon

AE
Scooby, I gave you a series of sites on that topic yesterday.
Thursday, August 21, 2008 at 3:27pm by GuruBlue

AE,, this right?>(revised)
Thursday, March 12, 2009 at 10:49pm by Ms. Sue

AE
Scooby...now you need to find some material that supports your point of view...
Thursday, August 21, 2008 at 3:27pm by GuruBlue

AE....
Scooby -- please post the answers you've found for this question. We'll be glad to comment on it and add to it if necessary.
Wednesday, March 11, 2009 at 9:43pm by Ms. Sue

AE
Scooby, when you have done the research and have written a rough copy, we will be happy to make further suggestions and corrections. We do not do your work for you..... as you well know by now.
Saturday, August 23, 2008 at 2:16am by GuruBlue

Math Calculus Help
we know that p = ae^kt using the known values, √e/2 = ae^k e/2 = ae^2k divide to get (e/2) / (√e/2) = e^k √e = e^k so, k = 1/2 now, we see that √e/2 = ae^(1/2) so a = 1/2 p(t) = 1/2 e^(t/2) p(4) = 1/2 e^2
Thursday, November 15, 2012 at 2:45pm by Steve

Scooby -- AE
Scooby, it looks to me like you have a good handle on how you learn best... I always had the most success with the hands on techniques...Projects for building something that demonstrated a principal... like building a 3 faced representation of the Capital, White House and ...
Friday, August 1, 2008 at 4:47pm by GuruBlue

AE..
Scooby -- For this assignment, you need to show what you have learned about teaching. You can't copy from the internet, but you must present your thoughts and beliefs. What are YOUR ideals for effective classroom management? How will YOU organize your classroom? How will YOU ...
Sunday, April 12, 2009 at 8:30pm by Ms. Sue

Reaction rates
so... k=Ae^(Ea/RT) Do I set it up as ratios? I.e. 0.0000100s-1=Ae^(-Ea/R * 636) ____________________________ 0.000479s-1=Ae^(-Ea/R * 700) A cancels out ...and then solve from there?
Saturday, November 20, 2010 at 10:37pm by Confused

ae
Scooby, sometimes "setbacks" are blessings. I quit a PhD program because I was not learning anything, and was not having fun. It turned out, I started to have fun again, and was damn good at what I was doing, and I grew much more than I had in years. So blessings often jump ...
Sunday, July 5, 2009 at 6:30pm by bobpursley

Gr. 9 Math (continued)
Given AE=4, EB=9, If AE≠EB, the only way that AEFG and EBHF are similar is that AE<EF<EB, which means really that AEFG is similar to FEBH to ensure the vertices correspond. If that's the case, Let EF=x, then AE/x = x/EB, or x² = AE*EB = 36 EF = x = 6 (negative ...
Sunday, December 12, 2010 at 1:58pm by MathMate

geometry!
oin AC and DE. Triangles AFE and DFC are similar. so AF/FC = AE/CD = AE/EB also AE + EB = AB ie AE +234AE =AB so AE/AB =1/235 so AF/FC = 1/235 FC = 235 AF now, AC = AF +FC = 236AF ie AC/AF = 236/1 ie AC : AF = 236 : 1
Thursday, February 28, 2013 at 12:54am by Navneet

Reaction Descriptions
abd, bf, cf, cd, ae, ae is correct
Wednesday, January 12, 2011 at 9:46pm by caitlin

Reaction Descriptions
abd, bf, cf, cd, ae, ae is correct :)
Wednesday, January 12, 2011 at 9:46pm by chemlab

geometry
Given: ABC,/ AD bisects <BAC, and /AE=/ED Prove: AE/AC = BD/BC
Monday, November 25, 2013 at 3:38am by loveofnursing

GEOMETRY
GIVEN: TRIANGLE ABC,AD bisects <BAC,and AE=ED, PROVE:AE/AC=BD/BC
Monday, September 17, 2012 at 8:41pm by HELEN

AE
Scooby, which of these environments do you learn best in? In what kind of atmosphere do you most enjoy learning? In what kind of atmosphere have you found teachers who are most successful in helping YOU learn? This is where I would start forming a philosophy. I discovered that...
Thursday, July 31, 2008 at 2:07pm by GuruBlue

Scooby -- AE
I just saw your reply from last night and responded to it. http://www.jiskha.com/display.cgi?id=1217527628
Friday, August 1, 2008 at 4:47pm by Ms. Sue

Geometry / Proofs
Given: Triangle ABC with AD bisecting angle BAC, and AE is congruent to ED (both line segments). Prove: AE/AC = BD/BC. Statements Reasons
Tuesday, August 27, 2013 at 3:24pm by Lisa

Physics
Ap/Ae = pi*(8.25r)^2/pi*r^2=68.1r^2/r^2= 68.1/1 Ap = 68.1*Ae. Ap = Area of the planet. Ae = Area of the earth.
Sunday, September 8, 2013 at 2:09pm by Henry

geometry
In the accompying diagram of circleo, diameter ad,chord AE,ans secantsCAB and CDE are drawn ; m angle BAD=40;and m arch AE=5((m arch ED) what is the measure of ACE?
Saturday, March 10, 2012 at 9:21pm by Vanna

Algebra
If m angle FGE =5x+10, Find the value of x so that line FC is perpendicular to Line AE. Line AE is a striaght line
Sunday, September 9, 2012 at 12:07am by Maria

chemistry
I agree that the explosion of gasoline is a low energy of activation as is H2 and O2 explosion with a spark. I would agree that the rusting of a nail is a higher AE than gasoline explosion but, to repeat myself, high is a relative term. And I'm not so sure that it is ...
Saturday, January 17, 2009 at 2:47pm by DrBob222

geometry
How AC is related to AE, are they equal? If yes, then you have to solve this way: AC=AE 2x-1=x^2-2, then solve for x x=1
Sunday, September 18, 2011 at 8:27pm by Anonymous

MATH
Complete Problem 34 in Section 5.2 Exercises (Ch. 5) of Essentials of Geometry for College Students. 34. Given: ABC,/ AD bisects <BAC, and /AE=/ED Prove: AE/AC = BD/BC
Monday, June 17, 2013 at 10:46pm by BJ

Integrated Math 1
CE must be 7 also, as C bisects AE.You have a right triangle AED, so AE=14 (hypotenuse), side DE 10. AD=sqrt(14^2-10^2)
Sunday, July 15, 2012 at 6:47pm by bobpursley

AE
Scooby... everyone has failed at something. The trick is in what did you "learn" from the failure. I always learn 'well, I won't make that mistake again." Then I go take another swat at it... The trick is to LEARN something from everything that happens in your life...both the ...
Sunday, August 24, 2008 at 2:35am by GuruBlue

Math
if h(x) = ae^bx, just plug in your values: 22 = ae^2b 14.08 = ae^4b divide one by the other, and the a's cancel 14.08/22 = .64 = e^2b e^b = .8 22 = a*.64 a = 34.375 h(x) = 34.375 e^bx = 34.375 * 0.8^x
Saturday, February 16, 2013 at 3:43pm by Steve

ae
Scooby, Bobpursley is right. Go for the career that makes you excited about getting up in the morning. It doesn't have to be the "popular" career of the moment. It doesn't have to be the career that will make you an instant fortune. It doesn't have to be the job your parents ...
Sunday, July 5, 2009 at 6:30pm by GuruBlue

chemistry
It would help if we knew what you were doing. #2. Theoretical yield = TE actual yield = AE = TE-1.5 %yield = (AE/TE)*100 =
Wednesday, July 18, 2012 at 6:27am by DrBob222

Geometry Proofs
Monday, August 13, 2007 at 10:25am by Sarah

geometrY!
Given: Let r=AE:EB Draw a diagram of the parallelogram ABCD. Insert E on AB. Extend DE to join CA at F. (The above is as given by the question). Examine the triangles FAE and DBE. Show that they are similar noting that FA is parallel to DB. Therefore the ration FE:ED = AE:EB ...
Wednesday, February 27, 2013 at 1:56am by MathMate

trigonometry
Construct the trapezoid ABCD ,where AB || CD AB = 12 and CD = 22 angle C=65 and angle D = 40 Draw AE || BC where E is on CD So now ABCE is a parallelogram, and CE = 12 which makes ED = 10 Now look at triangle AED, by corresponding angles angle AED = 65°, angle D = 40 leaving ...
Friday, February 10, 2012 at 6:18am by Reiny

Geometry
1. Ae = 360 / N = 90, 90N = 360, N = 360 / 90 = 4 Sides. 2. At = 80 + 90 + 103 + x = 360, X = 360 - 273 = 87 deg. 3. At =(N - 2)180, At = (7 - 2)180 = 900 deg. 4. Ae = 360 / N = 360 / 5 = 72 DEG. 5. 6. 7. At = (N - 2)180 = 1440, (N - 2) = 1440 / 180 = 8, N = 8 - 2 = 6 Sides. 8...
Tuesday, November 30, 2010 at 2:16pm by Henry

I assume your wires are round, not spherical. That is, they have a circular cross-section. If A has power P, and cross-section area a, length m and resistivity r, then its resistance R = rm/a P = E^2/R E^2/(rm/a) = aE^2/rm Conductor B has power (2a)E^2/(2r*3m) = 4/6 aE^2/rm = ...
Friday, November 15, 2013 at 5:49am by Steve

Calculus
f = ax e^(bx) f' = ae^(bx) + abx e^(bx) = ae^(bx) (1+bx) f'(1/8) = 0, so b = -8 f(1/8) = 1 = a(1/8)e^(-1), so a=8e f(x) = (8e)x e^(-8x)
Wednesday, March 6, 2013 at 4:09pm by Steve

calculus
let y = 4 x dy = 4 dx so integral of e^y sin y dy try e^y cos y derivative = -e^y sin y + e^y cos y so try ae^y cos y + be^y sin y derivative = -ae^ysiny+ae^ycosy+be^ycosy+be^ysiny we need a=-b to get rid of cos terms so -b e^y cos y +b e^y sin y so be^y sin y - be^y cos y try...
Wednesday, May 5, 2010 at 2:08am by Damon

MATHS
Let segments AB and CD have common point E. Then AC<AE+EC and BD<BE+ED. AE+EC+BE+ED=AB+CD
Saturday, September 3, 2011 at 8:48am by Mgraph

Calculus
Hmmm. Forget the above. We want y(0) = 1 and y(2.32) = 0.1 So, assuming y = aebx we have 1 = ae0 a = 1 so, y = ebx .1 = e2.32b ln .1 = 2.32b b = -2.3/2.3 = -1 So, y = e-x Am I still wrong here?
Sunday, October 30, 2011 at 10:03pm by Steve

geometry
I must assume that A and B are the centres of your two circles for this to make sense. Join AE, and you will have a right angles triangle AEB with AE=11, AB = 19 , and BE = x x^2 + 11^2 = 19^2 x^2 = 240 x = √240 so the area = (1/2) base x height = (1/2)(√240)(11...
Thursday, April 4, 2013 at 1:30am by Reiny

Math
This is rather crude. http://awwapp.com/s/ae/d6/63.html
Monday, August 5, 2013 at 4:06pm by Ms. Sue

geometry
Just lay out the points on the line BD contains the right half of BC and the left half of CE So, what's left is the same length: The left half of AC and the right half of CE AE = AB + BC + CD + DE but BD = BC + CD = 14 so, AE = AB + 14 + DE However, AB = BC and CD = DE so AB+...
Sunday, December 11, 2011 at 7:20pm by Steve

PSYCHOLOGY
thanks
Friday, December 4, 2009 at 7:36pm by scooby

PSYCHOLOGY
thanks
Sunday, December 6, 2009 at 8:42pm by scooby

religion
o ok thank you
Saturday, March 20, 2010 at 2:03pm by scooby

child development
Thank you!!!
Saturday, January 16, 2010 at 8:30pm by scooby

diversity in classroom
is anyone on?
Saturday, May 22, 2010 at 1:43am by scooby

math
.42
Wednesday, May 23, 2012 at 7:19pm by scooby

Anatomy & Physiology
Thank you for using the Jiskha Homework Help Forum. Try the following: http://www.accessexcellence.org/AE/AEC/CC/heart_anatomy.php Sra
Thursday, August 14, 2008 at 3:47pm by SraJMcGin

math
Tough to figure out from the "non-given" diagram. let DB, the horizontal distance be x. angle ADB = 48 degrees, 30 minutes (not inches!) = 48.5° so tan 48.5 = 40/x x = 40/tan48.5 = 35.39 m from C, draw a horizontal to meet AB at E tan 24.5 = AE/x AE = xtan24.5 = 16.13 m so ...
Sunday, June 19, 2011 at 4:05am by Reiny

Anatomy
Thank you for using the Jiskha Homework Help Forum. Try the following: http://www.accessexcellence.org/AE/AEC/CC/heart_anatomy.php
Tuesday, May 27, 2008 at 1:17pm by SraJMcGin

education
Sunday, March 15, 2009 at 2:53pm by GuruBlue

algebra updatte
no idea
Wednesday, November 4, 2009 at 8:48pm by scooby

classroom instruction
oh ok ty
Sunday, March 28, 2010 at 9:35pm by scooby

classroom management
ok ty
Friday, May 14, 2010 at 9:59pm by scooby

science
i found it thanks it was the erlenmeyer
Wednesday, September 1, 2010 at 8:55pm by scooby

English
wehhehewewhe
Thursday, September 21, 2006 at 3:53pm by scooby dooo

Geometry
Given triangle ABC, AD bisects angle BAC,and AE=ED Prove AE/AC=BD/BC Because I cant draw it I will explain. Its a triangle, A is the point at the top, B is the point at the bottom left and C is the point at the bottom right.There is a line going right down the middle, which is...
Saturday, September 29, 2012 at 8:23pm by Teisha

math
Scooby, what is a composite number?
Wednesday, July 15, 2009 at 7:55pm by DrBob222

plagiarism am i correct? plz help
r u sure on these?
Tuesday, January 12, 2010 at 7:22pm by scooby

child development does it sound ok
is it suppose to be an*
Friday, January 15, 2010 at 8:22pm by scooby

psychology
How psychological disorders are classified:
Monday, January 18, 2010 at 7:33pm by scooby

classroom management
thank you ms sue
Saturday, June 5, 2010 at 2:45pm by scooby

classroom management
You're welcome, Scooby.
Saturday, June 5, 2010 at 2:45pm by Ms. Sue

math
i am usre there is more can you help me plz
Wednesday, September 1, 2010 at 9:13pm by scooby

math check if right plz
thank you
Sunday, September 8, 2013 at 4:57pm by scooby

thank you
Sunday, September 8, 2013 at 5:31pm by scooby

math algebra
4/5(2x-1)>12
Friday, October 30, 2009 at 2:37pm by scooby

math algebra
would that be 11:30 am?
Friday, November 6, 2009 at 1:27pm by scooby

geography
how do you do a high pressure weather report?
Sunday, January 10, 2010 at 12:35pm by scooby

plagiarism am i correct? plz help
You're welcome, Scooby.
Tuesday, January 12, 2010 at 7:22pm by Ms. Sue

ms sue
can you tell me if i am correct plz?
Thursday, January 14, 2010 at 10:31pm by scooby

child development
but is that developmentally, and list ofcharacteristics
Friday, January 15, 2010 at 6:39pm by scooby

child development
what info r they talking about
Monday, January 18, 2010 at 5:28pm by scooby

aed
i am not understanding this assignment for some reason
Wednesday, February 10, 2010 at 9:31pm by scooby

aed
ok i think i am getting it some what lol
Wednesday, February 10, 2010 at 9:31pm by scooby

instruction(am i right track)
You're welcome, Scooby! :-)
Friday, February 26, 2010 at 9:28pm by Ms. Sue

classroom instruction
i have no idea lol
Wednesday, March 10, 2010 at 9:40pm by scooby

classroom instruction
did i answer all the questions then?
Sunday, March 28, 2010 at 9:35pm by scooby

DIVERSITY IN THE CLASSROOM update
good thinking. thank you
Friday, April 16, 2010 at 9:32pm by scooby

math last one sorry
p+1.6 divided by (-0.4)=-12
Sunday, September 8, 2013 at 6:04pm by scooby

You're welcome, Scooby.
Tuesday, November 4, 2008 at 9:34pm by Ms. Sue

Human Resource Management
Great, Scooby! You can do it!! :-)
Thursday, September 10, 2009 at 4:48pm by Ms. Sue

human resource managment
ok thank you i am doing it on an elementary school teacher
Saturday, November 7, 2009 at 8:42pm by scooby

thank you very much
Thursday, December 3, 2009 at 9:26pm by scooby

child development
i tried that i am having trouble rewording it
Sunday, December 6, 2009 at 5:05pm by scooby

geography
what is high pressure in terms a child can understand
Sunday, January 10, 2010 at 12:48pm by scooby

plagiarism am i correct? plz help
i try my best ill be done in may i hope
Tuesday, January 12, 2010 at 7:22pm by scooby

thank you ms sue
Wednesday, January 13, 2010 at 4:29pm by scooby

child development
is that like infant early childhood etc.? if so then what do i do
Monday, January 18, 2010 at 5:28pm by scooby

child development
never mind i found it sorry
Tuesday, January 19, 2010 at 10:20pm by scooby

classroom instruction
do u have a site for example? i can look at
Wednesday, March 10, 2010 at 10:58pm by scooby

DIVERSITY IN THE CLASSROOM
thank you i hope i can figure this assignment out
Friday, April 16, 2010 at 9:04pm by scooby

science
what are the beakers called that are shaped like pears?
Wednesday, September 1, 2010 at 8:55pm by scooby

math
what different combinations can you make with the letters BLSV.
Wednesday, September 1, 2010 at 9:13pm by scooby

math questions
is there a site i could use to help me with compund inequalities?
Sunday, November 13, 2011 at 4:49pm by scooby

math
Scooby -- Divide 21 by 50. What do you get?
Wednesday, May 23, 2012 at 7:19pm by Ms. Sue

math
so u divide the top from the bottom and thats ur asnwer
Wednesday, May 23, 2012 at 7:19pm by scooby

Pages: 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | Next>>

Search
Members