Wednesday

April 16, 2014

April 16, 2014

Number of results: 70,005

**Precalculus/Trig 6**

Find the exact value of the following trigonometric functions: sin(13pi), cos(14pi), tan(15pi)
*Monday, October 8, 2012 at 9:05am by Greg*

**Precalculus/Trig 6**

follow the steps that I showed you in previous post
*Monday, October 8, 2012 at 9:05am by Reiny*

**Precalculus/Trig 5**

Find the exact value of thet following trigonometric functions: tan(5pi/6) tan(7pi/6) tan(11pi/6)
*Monday, October 8, 2012 at 9:03am by Greg*

**Precalculus/Trig 5**

You should be able to make a quick sketch of the following right-angled triangles 30° - 60° - 90° ---> π/6rad - π/3rad - π/2 ---> 1 -- √3 -- 2 and 45° - 45° - 90° --> π/4 - π/4 - π/2 ---> 1 - 1 - √2 You should also know the...
*Monday, October 8, 2012 at 9:03am by Reiny*

**MATH**

Let x be the number. You multiply that number by 7 SO FAR WE HAVE: 7x You add 15 to that number SO FAR WE HAVE: 7x+15 You subtract 3^2 (which is 9) from that number SO FAR WE HAVE: 7x+15-9 When you do all of that to the number, you get 48 THE FINAL EQUATION IS: 7x+15-9=48 TO ...
*Thursday, November 13, 2008 at 10:27pm by Trig*

**Anonymous**

Give the exact intersection point for the equations f(x)=4sin^2x+7sinx+6 and g(x)=2cos^2x-4sinx+11 Ok, my result is that there is no intersection point because if you put f(x)=g(x) and try to solve for x or the intersection point, the LS f(x) is not possible, so there is none...
*Friday, May 8, 2009 at 2:54pm by trig*

**TRIG**

please help two questions h t t p : / / w w w . j i s k h a . c o m / d i s p l a y . c g i ? i d = 1 2 5 2 9 6 7 1 5 7 also A surveillance satellite circles Earht at a height of h miles above the surface. Suppose that d is the distance, in miles, on the sruface of Earth that ...
*Monday, September 14, 2009 at 7:08pm by TRIG*

**#3 of 6**

We have this: (3) Simplify: -5(cot^2theta-csc^2theta) A)5 B)-5 C)-5csc^2 theta D)5csc^2 theta I chose A You said B, right? Let's see if that's true. I will use x in place of theta to avoid having to write the word theta through and through. So, x = theta. cot^2 (x) = cos^2 (x...
*Thursday, February 14, 2008 at 3:28pm by Guido*

**JOe**

How do I find the equation of the wave h t t p : / / w w w . j i s k h a . c o m / d i s p l a y . c g i ? i d = 1 2 5 9 8 9 5 8 9 3
*Thursday, December 3, 2009 at 11:09pm by PreCalculus*

**6**

what is the resonance structure for O3?
*Thursday, September 15, 2011 at 10:23pm by Anonymous*

**6**

First of all, please identify the School Subject with one of the ones on the list on the upper left-hand side. Then try some of the following links for information: http://www.google.com/search?q=what+is+the+resonance+structure+for+O3&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-...
*Thursday, September 15, 2011 at 10:23pm by SraJMcGin*

**6**

The best physical activity is one that is ________. A. Enjoyable enough to bring along a snack B. Enjoyable enough to be lulled to sleep C. Enjoyable enough to do regularly D. All of the above c
*Sunday, March 4, 2012 at 4:26pm by desha*

**6**

Yes.
*Sunday, March 4, 2012 at 4:26pm by Ms. Sue*

**precalculus**

I will assume f(x) = 6/(1-x) f(g(x)) = f(1 - 6/x) = 6/(1 - (1 - 6/x) = 6/(1-1+6/x) = 6/(6/x) = 6(x/6) = x
*Sunday, January 15, 2012 at 4:25pm by Reiny*

**PRECALCULUS**

3x^2+5x^4+6
*Wednesday, April 20, 2011 at 10:29pm by Anonymous*

**Precalculus**

No it isn't. The correct answer is x = 0 6 ^ ( x + 3 ) = 6 ^ ( 0 + 3 ) = 6 ^ 3 = 216 6 ^ x = 6 ^ 0 = 1 216 - 1 = 215
*Sunday, January 29, 2012 at 1:55am by Bosnian*

**precalculus**

Find the nth term of a sequence whose first several terms are given. 6, 8, 6, 8, 6, 8, . . .
*Thursday, November 22, 2012 at 12:22am by Ama*

**precalculus**

6 posibilities for red x 6 possibilities for green = 36 total
*Sunday, September 9, 2007 at 11:25pm by drwls*

**PRECALCULUS**

find the cube roots of the complex number. 27((cos(11pi/6)) + i(sin(11pi/6))
*Wednesday, April 20, 2011 at 10:29pm by YOSHI*

**precalculus**

first x^2+12x+36 = (x+6)(x+6) so ln of (x-7)(x+6) ===================== (x+6)(x+6)(x+7)(x-7) ln of 1 ===================== (x+6)(x+1) = ln 1 - ln(x^2 +7x + 6) but ln 1 = 0 so - ln (x^2 + 7 x + 6)
*Wednesday, January 11, 2012 at 7:28pm by Damon*

**Precalculus**

-9 is incorrect, sorry. The answer is also not 6 or -6
*Sunday, March 2, 2014 at 2:09pm by John*

**Precalculus**

let y = 6^x then our equation becomes 6^3(6^x) - 6^x = 215 216y - y = 215 215y = 215 y = 215/215 = 1 so 6^x = 1 x = 0
*Sunday, January 29, 2012 at 1:55am by Reiny*

**precalculus**

solve for x: logx (6+4x-x2) = 2
*Friday, May 8, 2009 at 5:00pm by Kathy*

**Precalculus**

Bosnian's answer is correct. I'll just show how to get 0. 6^(x+3) - 6^x = 215 recall that when multiplying exponents of the same base, we add their exponents. for example, x^2 * x^4 = x^(2+4) = x^6 now we do the opposite to 6^(x+3). we'll separate this into, 6(x+3) = 6^x * 6^3...
*Sunday, January 29, 2012 at 1:55am by Jai*

**Precalculus**

use the half-angle formula, using x = pi/6
*Sunday, November 24, 2013 at 9:38pm by Steve*

**Math-help!!!**

Elly writes the following expression on the blackboard. (13+24)+0+7 Use three properties of addition to simplify the expression. Include the names of the properties you use. what properties of addition are there cause im not sure!!!!
*Monday, April 7, 2008 at 7:49pm by Busy 6*

**math**

a) d=(25-4)/3 b) do the rest itll be easy
*Monday, April 7, 2008 at 7:45pm by Busy 6*

**math**

a)n=(7+1)/2 b)it is easy now
*Monday, April 7, 2008 at 7:58pm by Busy 6*

**math**

stupid question
*Saturday, April 5, 2008 at 6:44pm by Busy 6*

**Math-help!!!**

thanx a lot!!!
*Monday, April 7, 2008 at 7:49pm by Busy 6*

**math**

ok,this is wat u do u make both denominators equal by finding the LCM(least common multiple) that is 8 what do u have to do if u want to make both fractions have the same denominator? u do this 2 1/4=2 2/8 u reduce 2 2/8 to get 2 1/4, rite? then 7/8 cannot go into 2 2/8, rite ...
*Tuesday, April 8, 2008 at 7:08pm by Busy 6*

**Math**

wat is the slow to go hiccups???
*Tuesday, April 8, 2008 at 5:24pm by Busy 6*

**math**

How can you find the percent one number is of another? For example, what percent or 35 is 7? (I think 20%)
*Tuesday, November 3, 2009 at 7:43pm by 6 math*

**math**

Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).
*Thursday, July 7, 2011 at 1:11pm by katie 6*

**math**

The equation of the line through point (-5, 0) and parallel to the y-axis is what?
*Thursday, July 7, 2011 at 9:43pm by katie 6*

**geometry**

Indicate the equation of the line through (2, -4) and having slope of 3/5.
*Friday, July 8, 2011 at 5:49pm by katie 6*

**geometry**

If a translation maps point (3, 2) to (4, 5); or T: (3, 2) (4, 5), then what is the image of the point (0, 0)?
*Sunday, July 17, 2011 at 8:56pm by katie 6*

**math**

The point (5, -2) is rotated 90° about the origin. Its image is
*Monday, July 18, 2011 at 5:18pm by katie 6*

**english grammer**

Teambuilding consensus when team decisions have to be making it is very important that every member of the team at least can live with it. Everybody must have had the opportunity to mention his arguments and everybody must have the feeling that his opinion is taken into ...
*Tuesday, December 20, 2011 at 12:29pm by natty 6*

**Math check**

The middle 69% of a normally distributed population lies between what two standard scores? (Give your answers correct to two decimal places.) 0.69 and 0.31
*Wednesday, June 12, 2013 at 10:56pm by Sue 6*

**Math help**

We have no ideal on how to start this problem, we have look for it on the charts, did not see. Please help Consider the following. (Give your answers correct to two decimal places.) (a) Find the standard score (z) such that the area above the mean and below z under the normal ...
*Wednesday, June 12, 2013 at 11:58pm by Sue 6*

**Math help**

We have no ideal on how to start this problem, we have look for it on the charts, did not see. Please help Consider the following. (Give your answers correct to two decimal places.) (a) Find the standard score (z) such that the area above the mean and below z under the normal ...
*Wednesday, June 12, 2013 at 11:58pm by Sue 6*

**Math help**

I have looked at that page and really do not understand how to use it, it ask for mean, sd, below, above etc. Would you please just once show me how to plug the information into this graph and I also get mixed up on which one to use. It looks like it may help me if I just knew...
*Wednesday, June 12, 2013 at 11:58pm by Sue 6*

**Math help**

Can someone give me a heads up on how to even start this problem.. Consider the following. (Give your answers correct to two decimal places.) (a) Find the standard score (z) such that the area above the mean and below z under the normal curve is 0.3989. (b) Find the standard ...
*Friday, June 14, 2013 at 4:54pm by Tom 6*

**Math**

A brewery's filling machine is adjusted to fill bottles with a mean of 31.5 oz. of ale and a variance of 0.003. Periodically, a bottle is checked and the amount of ale noted. (a) Assuming the amount of fill is normally distributed, what is the probability that the next ...
*Friday, June 14, 2013 at 6:52pm by Tom 6*

**Math**

There is a few of us working on these together so if you see different names that means none of us can figure it out. Again thank you
*Friday, June 14, 2013 at 6:52pm by Tom 6*

**Math help**

I put the information in as you said and I got for the second answer 0.66 and the last one 0.47 and they were wrong. What did I do wrong, I followed your instructions...
*Friday, June 14, 2013 at 4:54pm by Tom 6*

**Math Help and check**

The weights of ripe watermelons grown at Mr. Smith's farm are normally distributed with a standard deviation of 2 lb. Find the mean weight of Mr. Smith's ripe watermelons if only 5% weigh less than 18 lb. (Give your answer correct to one decimal place.) Incorrect: Your answer ...
*Saturday, June 15, 2013 at 4:50pm by Tom 6*

**Math check**

The middle 69% of a normally distributed population lies between what two standard scores? (Give your answers correct to two decimal places.)0.31 and 1.69 was my answers and they are wrong????. .
*Saturday, June 15, 2013 at 4:52pm by Tom 6*

**Precalculus**

Perform the indicated operation and the write the result in standard form (6+ sq root -5)(6 + sq root -7)=
*Friday, October 19, 2007 at 6:56pm by George*

**Precalculus**

6*6 + 6isqrt7 +5i*sqrt5+ i*sqrt35 I dont see how you can get less than four terms.
*Friday, October 19, 2007 at 6:56pm by bobpursley*

**Precalculus**

6*6 + 6isqrt7 +5i*sqrt5+ i*sqrt35 I dont see how you can get less than four terms.
*Friday, October 19, 2007 at 6:56pm by bobpursley*

**Precalculus**

Solve for x: 6^(x+3) - 6^x = 215. I got answer as 1, is it correct?
*Sunday, January 29, 2012 at 1:55am by Jake*

**Precalculus**

6(2x + 1)^3(3x -5) + 6(3x - 5)^2(2x + 1)^2 6(2x+1)^2(2x+1)(3x-5) +6(2x+1)^2 (3x-5)(3x-5) 6(2x+1)^2(3x-5) [ 2x+1 + 3x-5 ] 6(2x+1)^2(3x-5)(5x-4) So I do not see how to get that answer either.
*Tuesday, January 5, 2010 at 9:00pm by Damon*

**Precalculus**

Make block matrix 6 by 6 for total of 36 possible outcomes. Then count how many satisfy your criteria. 1. I get 20/36 = 5/9 2. agree 3. 2/36 = 1/18 4. 1/6 * 1/6 = 1/36 5. 1/6 + 1/6 = 1/3
*Saturday, February 8, 2014 at 5:06pm by Damon*

**Precalculus**

let z = e^x then z^2 - z - 30 = 0 (z-6)(z+5) = 0 so z = 6 or -5 if z = e^x = 6 x = ln 6 look it up if z = -5 x = ln -5 impossible so only ln 6 is solution
*Monday, July 5, 2010 at 12:56pm by Damon*

**precalculus**

In an isosceles triangle the altitude right-bisects the base, so we get a right-angled triangle let the base angle be Ø cosØ=4.5/6 = .75 Ø = 41.4° so the angle between the 2 equal sides is 97.2° or use the cosine law 9^2 = 6^2 + 6^2 - 2(6)(6)cosA cosA = -9/72 = -.125 A = 97.2°
*Thursday, April 28, 2011 at 9:35pm by Reiny*

**precalculus**

Determine the x-intercepts of the polynomial function y=-6(x+7)^4 + 5. Round to two decimal places, if necessary. y=-6(x+7)^4 + 5 0=-6(x+7)^4 + 5 -5=6(x+7)^4 -5/6 =(x+7)^4 There are no x-intercepts??
*Friday, December 9, 2011 at 1:23am by Melinda*

**Precalculus**

(sqrt2+3)^2 - (sqrt2+3) let a = sqrt 2 so a^2 = 2 (a+3)^2 - (a+3) a^2 + 6 a + 9 - a - 3 a^2 + 5 a + 6 2 + 5 sqrt 2 + 6 8 + 5 sqrt 2
*Tuesday, February 11, 2014 at 5:38pm by Damon*

**Precalculus**

Test it. if x=-6 the distance is 7. abs(x+7)=abs (-6+7)= abs (1)=1 You are correct
*Wednesday, August 29, 2007 at 7:41pm by Bobpursley*

**Precalculus**

Well that isnt one of my answers the question is multiple choice another choice is (36 - sq rt 35) + (6 sqrt 7 + 6 sqrt 5)i
*Friday, October 19, 2007 at 6:56pm by George*

**precalculus**

you should have come across the formula arc length = r(theta), where theta is the central angle 6 = 27theta theta = 6/27 radians = 2/9 rad
*Sunday, February 28, 2010 at 3:24pm by Reiny*

**PRECALCULUS**

1. x^2 + y^2 = r^2 = 16*3+16*3 = 16*6 so r = +/- 4 sqrt 6 theta = 3 pi/4 or -pi/4
*Sunday, April 24, 2011 at 3:47pm by Damon*

**precalculus**

log7 [(x-8)/(x-2)] = 1 [(x-8)/(x-2)] = 7*1 = 7 x - 8 = 7 x - 14 6 x = 6 x = 1
*Wednesday, January 11, 2012 at 7:30pm by Damon*

**precalculus**

verify the functions are inverses of each other by showing that f(g(x)) =x show work. f(x)=6/1-x g(x)= 1- 6/x
*Sunday, January 15, 2012 at 4:25pm by Sara*

**precalculus**

do a little multiplying, and we have 25*5^x + 5*5^x = 5 30*5^x = 5 5^x = 1/6 x = -log(6)/log(5)
*Saturday, February 15, 2014 at 8:51pm by Steve*

**precalculus**

find the additive inverse of the number 6- pi and -7
*Wednesday, September 9, 2009 at 5:58pm by timmy*

**Precalculus**

how do you put the polar equation r^2(sin2u)=6 into rectangular form?
*Sunday, February 13, 2011 at 7:24am by Kristen*

**precalculus**

Since it's a parabola opening downward, and is shifted up 5 units, you know that it will have two x-intercepts. So, what went wrong? You lost a "-" sign after the 2nd line. -5 = -6(x+7)^4 5/6 = (x+7)^4 ±(5/6)^(1/4) = x+7 x = -7 ±(5/6)^(1/4) = -7 ± .955
*Friday, December 9, 2011 at 1:23am by Steve*

**precalculus**

log_5 [(x-3)(x-6)/(x+1) = 2 , we know x > 6 (x-3)(x-6)/(x+1) = 5^2 x^2 - 9x + 18 = 25x + 25 x^2 - 34x - 7 = 0 x = (34 ± √1184)/2 = (34 ± 4√74)/2 = 17 ± 2√74 , but x > 6 x = 17 + 2√74
*Sunday, January 15, 2012 at 1:22pm by Reiny*

**Precalculus**

If the base was 2 then it would be cuberoot 2^6?
*Sunday, January 29, 2012 at 11:39pm by Jake*

**precalculus**

arcsin(0) = 0 sin < 0 in QIV, so -pi/3 ditto, so -pi/6
*Tuesday, April 2, 2013 at 10:29pm by Anonymous*

**precalculus**

sin theta = 50/d if d = 300 sin theta = 50/300 = 1/6 theta = 9.6 degrees
*Sunday, April 14, 2013 at 3:39pm by Damon*

**precalculus**

f(2x) = (2x)^2 - 3 (2x) = 4 x^2 - 6 x
*Monday, January 20, 2014 at 7:07pm by Damon*

**Precalculus**

Other than a small typo, bobpursley is right He meant to say: 6*6 + 6isqrt7 +5i*sqrt5+ i^2*sqrt35 = 36 + 6i√7 + 5i√5 - √35 George, trust us, we are right according to the way you typed the question!
*Friday, October 19, 2007 at 6:56pm by Reiny*

**PreCalculus**

Problem: Identify the conic from the equation 13x^2-6(sq.rt.6)xy+7y^2-16=0 I have to choose from the following four answers: hyperbola (angle of rotation 45) hyperbla (angle of rotation 60) ellipse (angle of rotation 90) ellipse (angle of rotation 30) I used the discriminant...
*Monday, March 30, 2009 at 7:08pm by Joanie*

**precalculus**

Find the angle between the two sides of length 6 in an isosceles triangle that has one side of length 9 and two sides of length 6. Find using the inverse.
*Thursday, April 28, 2011 at 9:34pm by Victoria*

**precalculus**

Find the angle between the two sides of length 6 in an isosceles triangle that has one side of length 9 and two sides of length 6. Find using the inverse.
*Thursday, April 28, 2011 at 9:35pm by Victoria*

**precalculus**

I will assume you meant x/(4x+1) < 5x/6 times 6(4x+1) 6x < 20x^2 + 5x 20x^2 - x > 0 x(20x - 1) > 0 critical values: x = 0, x = 1/20 and of course x ≠ -1/4 try values in the intervals 1. x < -1/4, say x = -1 is -1/-3 < -5/6 ? , is 1/3 < -5/6 ? NO 2. ...
*Sunday, January 15, 2012 at 1:27pm by Reiny*

**Precalculus**

If x is the distance from the lamp, and s is the length of her shadow, then using similar triangles, 13/(x+s) = 6/s s = 6/7 x
*Wednesday, February 15, 2012 at 9:01pm by Steve*

**Precalculus**

just recall that x=rcosθ y=rsinθ you have r=3, θ=4π/3 x = 6cos4π/3 = 6*(-1/2) = -3 y = 6sin4π/3 = 6*(-√3/2) = -3√3
*Thursday, March 29, 2012 at 7:08pm by Steve*

**precalculus**

an = ( - 1 ) ^ n + 7 For odd numbers 1 , 3 , 5 ... ( - 1 ) ^ n = - 1 and ( - 1 ) ^ n + 7 = - 1 + 7 = 6 For even numbers 2 , 4 , 6 ... ( - 1 ) ^ n = 1 and ( - 1 ) ^ n + 7 = 1 + 7 = 8
*Thursday, November 22, 2012 at 12:22am by Bosnian*

**Precalculus**

5tan((1/3)x + π/2) = 5tan [(1/3)(x + 3π/2)] period = 2π/(1/3) = 6π
*Monday, June 6, 2011 at 2:23pm by Reiny*

**precalculus**

solve logarithmic equation in exact form only. show work. log_5(x-3)+ log_5(x-6)-log_5(x+1)=2
*Sunday, January 15, 2012 at 1:22pm by Sara*

**precalculus**

x/4x+1 < 5x/6 solve the inequality answer in interval notation and show work - thanks
*Sunday, January 15, 2012 at 1:27pm by Sara*

**PreCalculus**

Given that alpha=30 degrees, a=6, and b=12. What is the number of triangles possible under these conditions?
*Monday, May 13, 2013 at 1:44am by Anonymous*

**Precalculus**

Given f(x)=(2x+3)/(3x^2+7x-6) find the equations of any vertical, horizontal, or oblique asymptotes.
*Wednesday, June 5, 2013 at 4:19pm by Jay*

**Precalculus**

let 5^x = y , then we have y^2 - 4y - 12 = 0 (y-6)(x+2) = 0 y = 6 or y = -2 5^x = 6 xlog5 = log6 x = log6/log5 = appr. 1.1133 or 5^x = -2 xlog5 = log (-2), but we cannot take logs of negatives, so no solution for that case x = log6/log5 or 1.1133
*Monday, January 30, 2012 at 11:39pm by Reiny*

**Precalculus**

1. a) and b) are correct c) the normal is perpendicular to the tangent So if the slope of the tangent at (3,9) is 6 then the slope of the normal is -1/6 y = (-1/6)x + b, plug in the point (3,9) 9 = (-1/6)(3) + b b = 19/2 y = (-1/6)x + 19/2 or y = (-1/6)x + 9.5 2. a) good! g) ...
*Monday, April 14, 2014 at 11:37pm by Reiny*

**precalculus**

50/(x+4) < 4x-1 50 < (x+4)(4x-1) 4x^2 + 15x - 4 > 50 4x^2 + 15x - 54 > 0 (x+6)(4x-9) > 0 critical values are x = -6 , x = 9/4 A quick test for values in each of the 3 domains shows x < -6 OR x > 9/4 I will let you translate the above into the interval ...
*Saturday, November 12, 2011 at 9:43pm by Reiny*

**PreCalculus**

Using Theta = 0.5 arccot((a-c)/2/b) Theta= 1/2 arccot((6/2)/6sqrt6 =1/2 arccot(1/2sqrt6) I get slightly less than 40 deg
*Monday, March 30, 2009 at 7:08pm by bobpursley*

**Precalculus**

Isn't x= rcosTheta=costheta (sqrt 6/sin2U)) I suspect you can get sin2U into a form that will reduce the equation. y= rsinTheta
*Sunday, February 13, 2011 at 7:24am by bobpursley*

**Precalculus**

add 3 cos x to each side 2=5 + 6 cos x 6cosx=-3 cosx=-1/2 x=arccos (-.5)and you can figure it from there
*Saturday, August 6, 2011 at 6:01pm by bobpursley*

**Precalculus**

x^(3/2) = 6/4 = 3/2 Take the 2/3 power of each side. x = (3/2)^(2/3) x = 1.3104.. You are correct
*Monday, August 22, 2011 at 7:08pm by drwls*

**precalculus**

f(-2) = (-2)^6 + 2(-2)^5 + 3(-2)^2 -2(-2) - 16 = 64 -64 + 12 + 4 -16 = 0 so what do you think?
*Sunday, September 25, 2011 at 4:21pm by Reiny*

**precalculus**

I believe its between (10,6) and (12,6) because we know that the starting point is at 6.. I don't know after that
*Saturday, December 3, 2011 at 11:50am by Melinda*

**precalculus**

write the expression below as a single logarithm show work. ln(x-7/x^2+12x+36)-ln(x^2-49/x+6)
*Wednesday, January 11, 2012 at 7:28pm by Sara*

**precalculus**

when it hits the ground, h = 0 -16t^2 + 36 = 0 t^2 = 36/16 t = 6/4 = 3/2 = 1.5 It will take 1.5 seconds
*Wednesday, November 28, 2012 at 10:06pm by Reiny*

**Precalculus**

new speed = √(6^2+4^2) = √52 ft/s If he rows for the opposite bank, his crossing takes the same time, regardless of the currents' speed.
*Tuesday, February 5, 2013 at 2:32am by Steve*

**precalculus**

Solve 8sin(pi/4x) = 6 for the four smallest positive solutions Give your answers accurate to at least two decimal places, as a list separated by commas.
*Sunday, April 7, 2013 at 12:03am by Anonymous*

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