Wednesday

April 16, 2014

April 16, 2014

Number of results: 567

**Precal**

Give the equation of the line that passes through point (-1, 6) and is parallel to a=<3,1>
*Thursday, January 23, 2014 at 11:42pm by PreCal*

**PreCal**

Alright thank you. Can I also put them in my calculator? I wasn't sure but I did for the first one and got the same answer.
*Sunday, April 3, 2011 at 1:59pm by PreCal*

**PreCal**

Write each expression in problems 1 to 3 in the form a + bi. 1. (8-3i)+(-6+2i) 2. 4/(2-i) 3. (3-2i)^3 I do not understand at all where to start. I tired looking on google to find a way to solve but I didn't get any real help. So please help me!
*Sunday, April 3, 2011 at 1:59pm by PreCal*

**PreCal**

Thank you so much for your help!
*Sunday, April 3, 2011 at 1:59pm by PreCal*

**PreCAL**

Write an equation in slope–intercept form of the line with the given parametric equations. x = 9t + 2 y = –6t + 9 Answer Choices (A) y=-2/3x-3/7 (B) y=-3/2x+3/31 (C) y=31/3x-2/3 (D) y=-2/3x+31/3
*Friday, January 24, 2014 at 9:55pm by PreCAL*

**calculus**

If you are weak in math, what you need is a precalculus site (or algebra/trig/functions). I would not try to get ahead of the calculus course you will be taking. Try this one: http://jwbales.home.mindspring.com/precal/
*Monday, July 28, 2008 at 9:36pm by drwls*

**precal**

Thank you!
*Sunday, May 23, 2010 at 5:56pm by anonymous*

**PreCal**

yes
*Tuesday, September 14, 2010 at 7:48pm by TutorCat*

**PreCal**

Thank YOU!!!
*Saturday, September 3, 2011 at 1:30am by Jack*

**precal**

thanks
*Friday, March 23, 2012 at 8:10pm by olivia*

**PreCal**

,l
*Wednesday, June 8, 2011 at 4:07am by Anonymous*

**precal**

thanks :)
*Friday, November 2, 2012 at 8:17am by Aly*

**PreCal**

It's 3.1
*Sunday, August 15, 2010 at 7:03pm by Hannah*

**Precal**

Isn't it x^2+x-6 = 0 (x+3)(x-2) = 0? x = -3 or x= +2?
*Saturday, June 22, 2013 at 7:08pm by Abi*

**Precal**

If x = 1 then (1 + 1 - 6)/1 = -4/1 = -4
*Saturday, June 22, 2013 at 7:08pm by Damon*

**PreCAL**

x = 9 t + 2 x - 2 = 9 t ( x - 2 ) / 9 = t t = ( x - 2 ) / 9 y = – 6 t + 9 y = - 6 * ( x - 2 ) / 9 + 9 y = - 3 * 2 * ( x - 2 ) / ( 3 * 3 ) + 9 y = - ( 2 / 3 ) ( x - 2 ) + 9
*Friday, January 24, 2014 at 9:55pm by Bosnian*

**PreCal**

ok thanks I'll work on that
*Tuesday, November 20, 2007 at 12:01pm by kelly*

**precal**

(-8)the exponent is -1/3
*Wednesday, January 7, 2009 at 10:15pm by ash*

**precal**

thank u
*Thursday, March 18, 2010 at 11:16pm by john 2020*

**precal**

But thanks alot!
*Friday, March 23, 2012 at 8:08pm by Olivia*

**precal- PLEASE HELP!**

thank you.
*Wednesday, March 28, 2012 at 9:50am by olivia*

**precal**

36.8
*Thursday, October 27, 2011 at 5:47pm by nriyah*

**Precal**

wa
*Tuesday, May 21, 2013 at 3:13am by gdfd*

**Precal**

Incomplete.
*Tuesday, May 21, 2013 at 3:13am by Henry *

**Precal**

x = 3 or x = +2 I mean
*Saturday, June 22, 2013 at 7:08pm by Damon*

**precal log**

4^(2x-5)=8^(x-3) Thanks
*Wednesday, April 9, 2008 at 12:54am by Deb*

**precal**

I get 2 for y... does that sound right
*Tuesday, April 15, 2008 at 11:24pm by Deb*

**precal**

(48)with the exponent of 1/2
*Wednesday, January 7, 2009 at 9:51pm by ash*

**precal**

What is your question?
*Saturday, September 11, 2010 at 4:50pm by Ms. Sue*

**precal**

are there solutions to x^3+27i=0 is so what are they?
*Thursday, December 30, 2010 at 10:50am by sue *

**precal**

(root2-root2i)^6
*Friday, May 20, 2011 at 4:16pm by joe*

**Precal**

THAAAAAAANK YOOOOOOU.
*Thursday, August 25, 2011 at 8:15am by Jason*

**PreCal**

Thanks, I am understanding now.
*Monday, September 5, 2011 at 5:03pm by Tim*

**PreCal**

How do you simplify i38?
*Wednesday, September 7, 2011 at 3:39pm by Chandra*

**precal**

1. no is said inx 2.yes
*Saturday, February 4, 2012 at 11:35am by Loura*

**precal**

4(3.75^1/64-1)=r
*Monday, February 13, 2012 at 12:05am by dave*

**precal**

cotxsinx=cosx
*Friday, March 23, 2012 at 6:01pm by olivia*

**precal**

cosx/sinxcotx=1
*Friday, March 23, 2012 at 8:08pm by olivia*

**precal- PLEASE HELP!**

thanks alot!!!!!!!!!!!!!!
*Sunday, March 25, 2012 at 9:21pm by olivia*

**Precal**

log(base 5)((x^2+2x+1)/x^2)
*Wednesday, January 22, 2014 at 11:51pm by Me*

**Precal**

What the Fuk is this sh!t?
*Wednesday, January 22, 2014 at 11:51pm by eM*

**precal**

(x^2+11)/(3-x) x=4i
*Tuesday, August 21, 2012 at 1:03pm by katie*

**precal**

4/(x+h-3)^2 - 4/(x-3)^2 --------------------------- h -4(h+2(x-3)) ------------------------------ (x-3)^2(x+h-3)^2 Not sure where else you want to take it.
*Tuesday, November 6, 2012 at 3:12pm by Steve*

**precal**

well, that's what I did, using h for Δx.
*Tuesday, November 6, 2012 at 3:12pm by Steve*

**Precal**

for example try x = -1 y = (1 + 1 - 6)/-1 = -6/-1 = +6
*Saturday, June 22, 2013 at 7:08pm by Damon*

**Precal**

rather -6/-.001
*Saturday, June 22, 2013 at 7:08pm by Damon*

**Precal**

if x = -4 (16 -4 -6) / -4 = 6/-4 which is negative
*Saturday, June 22, 2013 at 7:08pm by Damon*

**precal**

4,850,000
*Thursday, September 2, 2010 at 6:38pm by Anonymous*

**precal**

nvm that's wrong
*Thursday, September 2, 2010 at 6:38pm by Anonymous*

**PreCal**

Solve for x. -3x^2+8=-4
*Saturday, September 14, 2013 at 6:36pm by Anonymous *

**PreCal**

-3x^2 = -12 x^2 = 4 x = ±2
*Saturday, September 14, 2013 at 6:36pm by Steve*

**PreCal**

.6931 = ln(2)
*Saturday, November 30, 2013 at 4:17pm by Steve*

**PreCal**

Great. Thanks so much
*Saturday, November 30, 2013 at 4:17pm by Terri*

**precal**

which of the following is an asymptote of f(x)= 5/x+6
*Friday, February 21, 2014 at 1:49pm by harley*

**precal (log)**

3^(log3(4x)) thank u
*Tuesday, April 8, 2008 at 1:32am by Deb*

**Precal**

How do you find the 6th root of -i?
*Thursday, December 11, 2008 at 5:42pm by Sara*

**precal**

I will be happy to check your thinking on this.
*Tuesday, February 24, 2009 at 6:48pm by bobpursley*

**precal**

yes i meant to have it with parantheses
*Sunday, January 10, 2010 at 5:24pm by joe*

**precal**

simplify: csc²x secx
*Monday, March 8, 2010 at 12:45am by john2*

**precal**

How do you solve: sin[arccos(-2/7)] ?
*Sunday, May 23, 2010 at 5:56pm by anonymous*

**precal**

Damon, yes. Military time.
*Saturday, August 28, 2010 at 2:20am by Anonymous*

**precal**

messed up the formula N = No(1 + r)^t
*Tuesday, August 31, 2010 at 5:54pm by Anonymous*

**precal**

^^ previous post. SORRY.
*Saturday, September 11, 2010 at 4:50pm by Anonymous*

**PreCal**

i have to figure out what x is
*Tuesday, September 14, 2010 at 7:48pm by Hayli*

**precal**

are you aware that cos x + i sin x = e^(i x) ?
*Friday, May 20, 2011 at 4:20pm by Damon*

**precal**

left and right are both 1
*Friday, March 23, 2012 at 8:10pm by Damon*

**precal**

Thats ok, I think I kind of understand it.
*Friday, March 23, 2012 at 8:10pm by olivia*

**complex zeros**

X^4 + 16 equals 0
*Tuesday, April 3, 2012 at 1:36am by precal*

**precal**

Find the Difference quotient: 4/(x-3)^2
*Tuesday, November 6, 2012 at 3:12pm by katie*

**PreCal**

x^2+y^2-4x-12y+31=0
*Saturday, September 3, 2011 at 12:19am by Katie*

**Math precal**

well, (a+b)^2 = a^2+2ab+b^2 that should help
*Thursday, January 10, 2013 at 11:45pm by Steve*

**Math Analysis (PreCal)**

y = 2sin(4(x-2/3))
*Thursday, March 7, 2013 at 11:12pm by Steve*

**Precal**

LOL try -3/-.001
*Saturday, June 22, 2013 at 7:08pm by Damon*

**Precal**

I have not used a calculator.
*Saturday, June 22, 2013 at 7:08pm by Damon*

**Precal**

but if replace x with -4 i get a positive answer too!
*Saturday, June 22, 2013 at 7:08pm by Abi*

**PreCal**

So does that mean x=3? (so 3x3x3=27)
*Friday, November 29, 2013 at 10:04am by Terri*

**PreCal**

I'm so confused. How did you figure it out.
*Saturday, November 30, 2013 at 4:17pm by Terri*

**PreCal**

Oops 21e^-0.2 I mean
*Saturday, November 30, 2013 at 4:33pm by Terri*

**PreCal - repost**

e^-.2 = 1/e^.2 = 1/1.2214= .8187
*Saturday, November 30, 2013 at 4:40pm by Damon*

**PreCal**

^No, I'm sorry don't mind my post ^^;
*Sunday, December 1, 2013 at 12:10pm by Jai*

**Precal**

<-1+3t,6+t> or y-6 = 1/3 (x+1)
*Thursday, January 23, 2014 at 11:42pm by Steve*

**PreCAL**

y = - ( 2 / 3 ) ( x - 2 ) + 9 y = - ( 2 / 3 ) x - ( 2 / 3 ) * ( - 2 ) + 9 y = - ( 2 / 3 ) x + 4 / 3 + 9 y = - ( 2 / 3 ) x + 4 / 3 + 27 / 3 y = - ( 2 / 3 ) x + 31 / 3 Answer D
*Friday, January 24, 2014 at 9:55pm by Bosnian*

**precal **

find the domain and inverse for (f)= 2 + 1/(e^(x/3-5)
*Thursday, February 20, 2014 at 11:57pm by hamal*

**precal**

I hope one of the choices was y=5
*Friday, February 21, 2014 at 1:49pm by Steve*

**Precal**

how to express 3+4i in polar form
*Wednesday, February 7, 2007 at 6:48pm by Icon44*

**precal**

i honestly dont know what to do or how to start anyways
*Tuesday, February 24, 2009 at 6:48pm by trista*

**precal**

verify: tanx secx = -2tanx
*Monday, March 8, 2010 at 8:29am by john2*

**precal**

can u simplify the answer any more?????
*Thursday, March 18, 2010 at 11:16pm by john 2020*

**precal**

find all the roots of x^4-8x^2+5.
*Wednesday, August 18, 2010 at 10:38pm by john2*

**precal**

If lim 1/5^n exists, what is its value? It's either 0.2 or 0
*Saturday, September 4, 2010 at 8:06pm by Anonymous*

**precal**

hint: cos(A+B) = cosAcosB - sinAsinB
*Monday, December 27, 2010 at 4:20pm by Reiny*

**PreCal**

That's fine if you don't have to show your work.
*Sunday, April 3, 2011 at 1:59pm by Henry*

**precal**

identify the trigonometric form of -6+6i
*Friday, May 20, 2011 at 4:18pm by joe*

**precal**

Joe, we are not going to do your work for you. Sorry.
*Friday, May 20, 2011 at 4:20pm by bobpursley*

**precal 2**

solve the equation 4cos^2x-1=0
*Sunday, July 24, 2011 at 9:01pm by denise *

**PreCal**

i38 = 38 @ 90 deg.
*Wednesday, September 7, 2011 at 3:39pm by Henry*

**precal**

Find the components and so that fog =H . H(x)=log_3e^x
*Wednesday, November 9, 2011 at 9:37pm by tina*

**precal**

I apologize 4 the typo, that's how the work was given to me.
*Friday, March 23, 2012 at 8:08pm by Olivia*

**Precal**

just about -6 / -.001 which is positive
*Saturday, June 22, 2013 at 7:08pm by Damon*

**PreCal**

go to wolfram alpha and plug it in
*Sunday, November 10, 2013 at 5:25pm by james*

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