Wednesday

April 23, 2014

April 23, 2014

Number of results: 70,421

**Pre-calculus**

Looks like calculus not pre-calculus to me by the way. I do not see how to do it without taking the derivative.
*Tuesday, November 27, 2012 at 6:01pm by Damon*

**Pre-calculus-check answers**

1) I got a remainder of 5, check your work 2) correct
*Saturday, August 23, 2008 at 1:47pm by Reiny*

**Pre-Calculus/Calculus**

I am too embarassed to ask this Calculus (really pre-calculus) question in tutoring, because I know I should know. Is the inverse of f(x)=3x-1 actually f(x)=1/3x+1? How do I find it? What if it asks the same equation replaced with f to the -1 power (x)? I think I know how the ...
*Tuesday, July 1, 2008 at 10:38pm by Molly*

**Pre-calculus-check answer**

yes
*Saturday, August 23, 2008 at 2:36pm by Reiny*

**pre calculus**

You need to write out the question. I have no idea what "pre calculus" this could be, maybe zeroes, however, that is standard fare for an algebra course.
*Tuesday, December 10, 2013 at 6:26pm by bobpursley*

**pre calculus**

You need to write out the question. I have no idea what "pre calculus" this could be, maybe zeroes, however, that is standard fare for an algebra course.
*Tuesday, December 10, 2013 at 6:26pm by bobpursley*

**Pre Calculus**

Pre Calculus why is sin(-20)/cos 380 equal to tan (-200)
*Sunday, November 15, 2009 at 10:07pm by Pre Calculus*

**Pre-Calculus**

yeah part exams library go there Pre-Calculus exam
*Thursday, October 29, 2009 at 7:46pm by stephanie*

**PRE-CALCULUS**

THIS IS FOR ALGEBRA/PRE-CALCULUS MATH. I POSTED IT JUST AS THE TEACHER WROTE IT.
*Tuesday, September 13, 2011 at 10:41pm by aLVIN*

**Pre-Calculus-check answers**

correct.
*Saturday, October 11, 2008 at 2:10pm by bobpursley*

**Pre-calculus-check answers**

bewbs
*Saturday, August 23, 2008 at 2:15pm by Anonymous*

**Pre-calculus-check answers**

both correct
*Saturday, August 23, 2008 at 1:41pm by Reiny*

**Pre-Calculus-check answers**

then the book is wrong
*Saturday, August 30, 2008 at 8:38pm by Reiny*

**Pre-Calculus-check answers**

75*32
*Saturday, October 11, 2008 at 2:03pm by Anonymous*

**Pre-Calculus**

I am in Honors Pre-Calculus and am having a hard time understanding my teacher. I feel so stupid. Does anyone have any suggestions on a website that might give me some insight into what I am doing wrong? Thanks!
*Tuesday, October 7, 2008 at 4:23pm by Jill*

**pre-calculus-check over work**

all correct.
*Monday, April 21, 2008 at 10:21am by bobpursley*

**Pre-calculus-check answers**

I am not familiar with the notation [g x f](x) 2) is correct
*Saturday, August 23, 2008 at 1:37pm by Reiny*

**Pre Calculus 1**

make sure to check your answers, since x > 0
*Tuesday, March 29, 2011 at 7:50pm by Reiny*

**Pre-Calculus/Trig Check please and help**

correc, typo. -3x^2
*Monday, September 5, 2011 at 8:52am by bobpursley*

**pre calculus**

Pre-Calculus? I wonder what the question is. In a basic algebra course, you would be looking for zeroes, and probably get those by factoring. 2x^2+11x-21=0 (2x-3)(x+7)=0 x= 1.5, or x=-7
*Tuesday, December 10, 2013 at 12:39pm by bobpursley*

**Pre-Calculus-check answers**

Oops, forgot to mention that the answer for problem 2 is d.
*Sunday, August 10, 2008 at 12:22pm by Lucy*

**Pre-Calculus**

Pre-Calculus? That is a nasty equation. We might use Newton's Method, but that would be Calculus. I tried some "trial and erro" and got x = appr .371 using 2 decimals 4 sin .37 = 1.44646 e^.37 = 1.4477 I am curious what method was suggested that you should use.
*Friday, March 29, 2013 at 10:30pm by Reiny*

**pre-calculus**

pre-calculus and i didn't understand where the d and cos came from
*Thursday, September 29, 2011 at 10:44pm by tatiana*

**math**

Are you doing pre-calculus or calculus? In calculus, the maximum is obtained by setting f'(t)=derivative with respect to t = 0 and solving for t. In pre-calculus, you can transform the expression by completing the squares. Ax² + Bx + C =A(x²+ (B/A)x + C/A) =A((x + (B...
*Tuesday, September 8, 2009 at 10:22pm by MathMate*

**Pre-Calculus-check answers**

correct, except for the missing PI in the frequency term.
*Saturday, August 30, 2008 at 6:31pm by bobpursley*

**Pre-Calculus-check answers**

I am not surprised as I have found many errors thus far. Thanks for helping
*Saturday, August 30, 2008 at 8:38pm by Lucy*

**Pre-Calculus**

h/225= tangent 49.5deg If I understand the picture correctly, check me. solve for h.
*Wednesday, March 24, 2010 at 8:42pm by bobpursley*

**pre-calculus**

I did this already, but left a few steps for you to finish. Check the previous post of the same question
*Friday, March 7, 2008 at 7:47am by drwls*

**Pre-Calculus-check answers**

I double checked my typing on the first problem and everything was entered correctly.
*Saturday, August 30, 2008 at 8:38pm by Lucy*

**Pre-Calculus-check answers**

Write the equation of the circle that passes through the point (3,4) and has its center at (1,2). Answer: (x-1)^2 +(y-2)^2 = 8 Thanks for the help.
*Saturday, October 11, 2008 at 2:10pm by Lucy*

**Pre-Calculus**

Go back and check your volleyball question. I just saw it and you missed the angle of launch in your equations.
*Monday, March 3, 2014 at 6:15pm by Damon*

**Pre-Calculus-check answers**

I agree about the sign change but your answer d makes the graph shorter, not taller. I think b)
*Sunday, August 10, 2008 at 12:26pm by Damon*

**Pre-Calculus-check answers**

Oops---left the "x" off of 12 Should read: f(x)=6+x^4+2x^2-5x^3-12x Sorry
*Sunday, August 31, 2008 at 11:47am by Lucy*

**Pre-calculus-check answers**

which of the following results is the graph of f(x)=x^2 being expanded vertically by factor of 3 and reflected over the x-axis
*Saturday, August 23, 2008 at 1:47pm by Anonymous*

**Pre-Calculus**

b^2 = a^2 + c^2 - 2ac cos 54 = 1485 b = 38.5 Check your numbers again. I get sinA = a*sinB/b = .1366 A = 7.85 degrees
*Monday, December 7, 2009 at 12:47am by drwls*

**Pre-Calculus**

Of course you are right, silly of me not to even check for the obvious. I was too concerned about the two obtuse angles. c so.... No such triangle is possible.
*Sunday, April 7, 2013 at 11:25am by Reiny*

**Math: Pre-calculus**

P=2(W+L) A=WL, so L = 180/W so, P = 2(W+180/W) This is pre-cal, so you don't have calculus at your disposal. But, you do know that a square has maximum area for a given perimeter. So, W = L = √180 = 6√5
*Sunday, October 6, 2013 at 5:35pm by Steve*

**Pre-Calculus-check answer**

Solve: x^2+y^2=10 and xy=3 Answer: (+/-3, +/-1) or (+/-1, +/-3)
*Sunday, October 12, 2008 at 10:05pm by Lucy*

**pre calc**

A pre-calculus answer is -0.64 + kπ radians, where k∈ℤ.
*Monday, January 25, 2010 at 8:11pm by MathMate*

**Pre-Calculus-Please check**

Please check: 1.Find polar equation of x^2 + y^2 = 10y subbed r^2 for x^2 + y^2 and sin(theta sin for y =r^2=10sin(theta) 2. y=5 r=5/sin 3. x^2+y^2 =x^2 + y^2 =2x+3y
*Wednesday, October 5, 2011 at 6:56pm by Tonya*

**Pre-Calculus-check answers**

Use a sum or difference identity to find the exact value of sin 255 degrees Answer: sqrt6-sqrt2/4 Thanks
*Saturday, August 30, 2008 at 10:10pm by Lucy*

**Pre-Calculus-check answer**

Yes, all of those answers work. You can prove that by substitution. You can also derive it by substituting 3/x for y in the first equation. x^2 + 9/x^2 = 10 x^4 - 10x^2 +9 = 0 (x^2-9)(x^2 - 1) = 0 (x+3)(x-3)(x+1)(x-1) = 0
*Sunday, October 12, 2008 at 10:05pm by drwls*

**Calculus grade 12 exam review PLEASE HELP ASAP !!**

THANK U! to be honest i really hate calculus and i didnt really pay attention in the course. im going into kin (of arts) so its a pre-req but i wont be taking any math or calc courses in university, i dont know why its a pre req then. but thanks u so much
*Thursday, June 21, 2012 at 3:52pm by Sarah Berkley Adamson*

**Pre-Calculus check answers**

How does statistics relate to algebra and specifically to linear equations and linear programming?
*Sunday, August 31, 2008 at 11:46am by boisetta Jacobs*

**Pre-Calculus/Trig Check please and help**

First find (x-3i)(x+3i)=x^2+9 and then (x-3)(x^2+9)=x^3-3x^2+9x-27
*Monday, September 5, 2011 at 8:52am by Mgraph*

**Pre-Calculus-check answers**

I suspected as much :) Your first function appears to have two zeros, but both are for positive X (approx. 0.5 and 5.0). The second one appears to have a couple of zeros somewhere around -1.4 and +1.4: would you like to check that out? (That's just from a quick sketch of the ...
*Sunday, August 31, 2008 at 11:47am by David Q*

**Pre-calculus-check answers**

your first one would be (x+3i)(x-3i)(x-i)(x+i) which is what you had, but then =(x^2 - 9i^2)(x^2 - i^2) remember i^2 = -1 = (x^2 + 9)(x^2 + 1) = .... you can finish that your second question is correct
*Saturday, August 23, 2008 at 1:32pm by Reiny*

**Pre-calculus-check answer please**

Write the standard form of the equation of the circle that is tangent to the line x=3 and has center at (-2,-7). Answer: (x+2)^2+(y+7)^2=49 Is this correct?
*Monday, October 13, 2008 at 11:48am by Lucy*

**pre calculus**

determine the order of magnitude for the following: 1. a $1 bill and a dime 2. two products scored a PH level of 6.1 and 4.o I can't figure out #1… but I did get #2 to be 10^2.1 Please help with #1 and check to see I did #2 right?
*Monday, February 3, 2014 at 4:25pm by Anonymous*

**Pre-Calculus-check answers**

Find the degree measure of the central angle whose intercepted arc measures 8cm in a circle of radius 15cm. Answer: -401.07 degrees
*Saturday, October 11, 2008 at 5:09pm by Lucy*

**Pre-Calculus-check answers**

Which of the following results in the graph of f(x)=x^2 being expanded vertically by a factor of 3 and reflected over the x-axis? a) f(x)= (1/3)x^2 b) f(x)= -3x^2 c) f(x)= (-1/x^2)+3 d) f(x)=(-1/3)x^2 Answer: d Thanks for checking my answers
*Sunday, August 10, 2008 at 12:26pm by Lucy*

**Pre-Calculus**

Sorry to be a pest but I never got an answer and I'm really stuck Can you please check this equation. Find polar equation of x^2 + y^2 = 10y x^2 + y^2 = r^2 r^2 = 10sin(theta)
*Friday, October 7, 2011 at 9:58am by Tonya*

**Pre-Calculus**

*I mean you get all the factors of x = +/- p/q. In the problem, x = +/- 20, and its factors are written there above. The factors are the ones you have to check by substituting them to the expression. :)
*Monday, December 16, 2013 at 1:11am by Jai*

**pre calculus**

all the rational possibilities are ±1,±2,±3,±4,±6,±12 That's a lot, but it's easy to check the small values. A little synthetic division shows that f(x) = (x-1)(x^3+3x^2-4x-12) = (x-1)(x-2)(x^2+5x+6) = (x-1)(x-2)(x+2)(x+3)
*Monday, April 29, 2013 at 11:10am by Steve*

**Pre-Calculus-check answers**

Write an equation of the tangent function with period 3pi/8, phase shift -pi/5, and vertical shift -2. Answer: y=tan(8x/3 - 8pi/15)-2 Thanks
*Saturday, August 30, 2008 at 6:31pm by Lucy*

**Pre-Calculus**

the easy way to check is to see if the points are common y1-y2=0 (are the y's the same?) Put this in your google search window: 2(3.41)-(3.41-1)^2-1= then try the other root.
*Monday, September 20, 2010 at 12:21pm by bobpursley*

**Pre-calculus-check answer**

If cot theta =0.85, find tan theta. Answer: 1.176
*Saturday, August 23, 2008 at 2:36pm by Lucy*

**math-calculus**

btw this is actually pre-calculus publisher is absolute value publications
*Tuesday, January 17, 2012 at 11:28pm by Shreya*

**Pre-Calculus-check answers**

1) I agree 2) Your answer is OK, but these are not geometric means. They are three numbers in a geometric progression. Another possible answer would be -2, -2 sqrt2, -4.
*Saturday, September 13, 2008 at 4:12pm by drwls*

**Pre-Calculus**

Find the values of x for which the line y=2x intersects the parabola y=(x-1)^2+1. So I set the equations equal to eachother, and solved for x using the quadratic formula. The solution I got was: x=3.41 and x=0.59. Could someone please check my work.
*Monday, September 20, 2010 at 12:21pm by Jon*

**pre calculus**

Multiply 1.2 rev/s by 2 pi radians/revolution. The radius does not matter. Learn to spell calculus
*Thursday, December 3, 2009 at 11:50am by drwls*

**Pre-calculus-check answer please**

did you make a quick sketch? should it not be obvious from your sketch, that the radius would be 5 ? so the equation should have been: (x+2)^2 + (y+7)^2 = 25
*Monday, October 13, 2008 at 11:48am by Reiny*

**Pre-calculus-check answers**

Choose the statement that is true for the graph f(x) =x^3-12x. Answer: f(x) decreases for x >-2 2) Which type of critical point, if any, is present in the graph of f(x)=(x-4)^5+1 Answer: none
*Saturday, August 23, 2008 at 2:15pm by Lucy*

**pre-calculus**

The best way to check is to substitute your answer back into the equation. SQRT(2x+1)-5=8 SQRT( (2*84)+1)-5=8 SQRT(168+1)-5=8 SQRT(169)-5=8 13 - 5 = 8 8 = 8 You are correct!
*Tuesday, September 20, 2011 at 4:27pm by Quidditch*

**pre-ap pre calculus **

To solve an equation by finding x-intercepts, Cynthia graphed the function y=x^3-5x+|2x-3| Give several possibilities for the original equation. How do I do it and what's the answer? Thanks
*Tuesday, September 8, 2009 at 2:14pm by Anonymous*

**Pre-Calculus**

I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
*Saturday, September 17, 2011 at 2:40pm by Cristina*

**Pre-Calculus**

I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
*Saturday, September 17, 2011 at 3:48pm by Cristina*

**Pre-Calculus**

Please check: 1.Find polar equation of x^2 + y^2 = 10y r^2 for x^2 + y^2 and sin(theta sin for y =r^2=10sin(theta) 2. y=5 r=5/sin 3. x^2+y^2 =x^2 + y^2 =2x+3y
*Wednesday, October 5, 2011 at 11:06pm by Tonya*

**Pre-Calculus**

if sintheta=-1/sqrt10, then costheta= (10-1)/sqrt10= sqrt (9/10) check those. Then sin2theta= sintheta*costheta=-2/sqrt10*sqrt9/10 = sqrt9 /5=3/5=.6 cos2Theta=1-2sin^2 theta=1-2(1/10)=.8 check all that. I have no idea what you did.
*Wednesday, July 13, 2011 at 4:03pm by bobpursley*

**Pre-Calculus-check answers**

not quite if x+iy = r e^iT = r (cos T i sin T) then r = sqrt (x^2+y^2) not sqrt [x^2 + (iy)^2] so r = sqrt (29), not 21
*Saturday, September 13, 2008 at 4:09pm by Damon*

**Pre. Cal.**

coefs of row 4 1 4 6 4 1 so a^4 + 4 a^3 b + 6 a^2 b^2 + 4 a b^3 + b^4 (3p+r^3)^4 a = 3p b = r^3 a^4 = 81 p^4 check 4 a^3 b = 4*27 or 108 p^3 r^3 check 6 a^2 b^2 = 6*9 or 54 p^2 r^6 check etc
*Thursday, May 14, 2009 at 10:43pm by Damon*

**Pre-calculus-check answers**

If f(x)=4x^2 and g(x)=2/x, find [g x f](x). Answer: -1/2x^2 2) Are f(x)=1/2x+5 and g(x)=2x-5 inverses of each other? Answer: no
*Saturday, August 23, 2008 at 1:37pm by Lucy*

**pre alg**

(25a^-2 b^-5 c^8) / (40 a^5 c^9) 25/40 = 5/8 check a^-2/a^5 = a^-7 check b^-5 = b^-5 check c^8/c^9 = c^-1 check
*Sunday, March 1, 2009 at 4:35pm by Damon*

**pre-calculus**

well i didn't want to post the answers because someone could easily choose an answer choice. i just wanted to compare reiny's answer to the answer i'd already gotten. i wanted to double check from a credible source.
*Friday, October 3, 2008 at 9:28pm by aelisha*

**pre-calculus**

for the first one, why not graph the parabola ? hint: it has x-intercepts of (0,) and (4,0) now check in your textbook or notebook what it says about even and odd functions in relation to their graphs. for the second, I suggest you make a table of values, graph it, and draw ...
*Friday, October 3, 2008 at 10:51pm by Reiny*

**Pre-Calculus**

Can you show me how to find the rectangular equation: r=2cos(theta) + 3 sin (theta) All I need is an example to work off I was absent today from Pre-Calc and I have homework to do and no explanation with them-Please help with this one Thank you
*Monday, October 3, 2011 at 7:49pm by Leah*

**pre calc**

This is a long, long way from pre-calculus. 2,4 is in quadrant I when on any axis, it is not in a quadrant. In the case of 0,3 it is on the border between quadrants I,and II.
*Thursday, September 10, 2009 at 5:40pm by bobpursley*

**pre calculus**

90 = 1/2 (2h-5) h h = (5+√1465)/4 b = 2h-5 = 1/2 (√1465 - 5) odd answer, so better check my math
*Tuesday, November 27, 2012 at 1:38am by Steve*

**Pre-calculus**

I want to make sure this is right. the inverse of f(x)=(-3x+2)/(2x-1) I got f^-1(x)=(x-2)/(2x-3). if its right how do i check the answer to see if it is right. also would the domain of f be D=all real numbers except 1/2. And I do not know how to get the range for f^-1
*Sunday, December 4, 2011 at 6:25pm by nessa*

**Pre-calculus-check answers**

Write the slope-intercept form of the equation of the line that passes through the point (-5,4)and has a slope of -1. Answer: y=-x-1 2)Solve the system of equations algebraically: 1/3x+1/3y=1 and 2x+2y=9 Answer: no solution
*Saturday, August 23, 2008 at 1:41pm by Lucy*

**Pre Calculus**

T4 = T3*r, so r = 36/24 = 3/2 T3 = ar^2, so 24 = a(9/4), so a=32/3 S10 = 32/3 * (1-(3/2)^10)/(1 - 3/2) = 58025/48 seems clumsy, so better check my math.
*Sunday, November 25, 2012 at 5:29pm by Steve*

**Pre-cal**

start with f(z) = i as directed then f(i) = -1 +i - i = -1 check f(-1) =+1 -1 - i = -i do not check f(-i) =-1 -i - i = -1 -2i
*Saturday, January 3, 2009 at 12:09pm by Damon*

**Pre-calc**

Pre calculus? This is stock Algebra II. put the equations in the form of ax^2+bx+c=0 then factor. for instance, c is already in that form. 2x^2+x-6=0 (2x-3)(x+2)=0 x= 3/2 x=-2 do the others the same method.
*Monday, January 25, 2010 at 5:18pm by bobpursley*

**pre-algebra**

Check the answers to your last two posts. The websites shows exactly how to do it. We'll be glad to check your answer.
*Thursday, January 13, 2011 at 9:27pm by Ms. Sue*

**Pre-calculus-check answers**

1) df/dx = 3x^2 -12 = 2(x+2)(x-2) There are critical points (where the derivative is zero) at x = +2 and -2. x=2 is a relative minimum. f(x) increases (when x increases) for x > +2 and decreases for -2 < x < 2 2) That equation has an absolute minimum at x = 4.
*Saturday, August 23, 2008 at 2:15pm by drwls*

**Pre-Calculus-check answers**

Find the sixth term in the geometric sequence: sqrt3y^3, -3y^5, 3sqrt3y^7 Answer: -27y^13 2) Find three geometric means between -sqrt2 and -4sqrt2. Answer: -2, 2sqrt2, -4 Thanks
*Saturday, September 13, 2008 at 4:12pm by Lucy*

**Pre-Calculus**

Could someone check my answers? 27. (16/9)^2/3 = 64/27 28. (49/25)^3/2 = 343/125 31. (-64)^2/3 = 8 32. (-8)^-4/3 = 1/16 or -1/16
*Monday, April 22, 2013 at 10:55pm by Caroline*

**Pre-Calculus-Please check**

1. r² = 10r sin θ r = 10 sin θ 2. looks good 3. r² = 2rcosθ + 3rsinθ r = 2cosθ + 3sinθ
*Wednesday, October 5, 2011 at 6:56pm by Steve*

**College algebra**

I assume you are doing pre-calculus. The inverse of f(x) = f-1(x) can be found by the following simple steps: 1. rewrite the function y=f(x) by interchanging x and y. 2. solve the resulting equation for y in terms of x. The resulting expression on the right hand side is f-1(x...
*Sunday, November 29, 2009 at 1:02pm by MathMate*

**Pre-Calculus**

ok, I would now work on the z's you have -40z and +150z the LCM of 40 and 150 is 600, so multiply your -126x-40z=470 by 15 and 272x+150z=-760 by 4 You would then add to eliminate the z's I did not check your arithmetic, so good luck
*Wednesday, September 23, 2009 at 9:28pm by Reiny*

**Pre-calculus-check answers**

Name all the values of x that are not in the domain of f(x)=2-x^2/x+5. Answer: x= -5 2)Find the minimum value of f(x,y)=2x-y+2 for the polygonal convex set determined by this system of inequalities: x >/= 1, x </= 3, y</=0, 1/2x+y</=5 Answer: -0.5
*Saturday, August 23, 2008 at 1:57pm by Lucy*

**Pre-Calculus-check answers**

Name all the values of x that are not in the domain of f(x)=2-x^2/x+5. Answer: x= -5 2)Find the minimum value of f(x,y)=2x-y+2 for the polygonal convex set determined by this system of inequalities: x >/= 1, x </= 3, y</=0, 1/2x+y</=5 Answer: -0.5
*Saturday, August 30, 2008 at 11:19am by Lucy*

**pre-calculus**

step1 test for n=1 LS = (1)(2) = 2 RS = (1)(2)(3)/3 = 2, check! step2 assume it is true for n=k, that is ... (1)(2) + (2)(3) + ... k(k+1) = k(k+1)(k+2)/3 step3 show that it must be true for n= k+1 that is ... show (1)(2) + (2)(3) + ... k(k+1) + (k+1)(k+2) = (k+1)(k+2)(k+3)/3 ...
*Thursday, June 10, 2010 at 12:33am by Reiny*

**Pre-Calculus**

well, shoot. Then just subtract 8 from both sides to get 3x^2 = -12 x^2 = -4 there is no real solution, since x^2 is never negative for real x. If you allow complex solutions, then x = 2i or -2i. I believe this is from Algebra I, and should not be posing a difficulty for ...
*Wednesday, September 11, 2013 at 4:58pm by Steve*

**Pre Calculus 12**

Im going over my pre calculus 12 exam, and I need help with one question from the chapter Transformations of graphs and stuff. Combining Transformations 2y = f(5x-10)+8 The original points are (4,6) and the new points I got by translating it and stuff are : (14/5,20) But in ...
*Tuesday, January 22, 2013 at 8:18pm by Shreya*

**Pre-Calculus**

I'm afraid I don't recognise the equations in C, D and E you've written down - but I've just sketched out the problem on a piece of graph paper. If it helps you to check your working, the centre of the circle ought to be at (3, -2) and the radius is sqrt(50). That would make ...
*Monday, September 1, 2008 at 2:50pm by David Q*

**pre calculus**

.72 = 1 (e^-.000124t -.000124t ln e = ln .72 but lne =1 t = ln .72 /-.000124 = appr 2649 years check my arithmetic
*Saturday, February 8, 2014 at 11:06pm by Reiny*

**Pre-Calculus/Trig Check please and help**

Could someone please check the first one and help me with the second one. I'm stuck-Thank you 1.What are theroots of the following polynomial equation? (x+2i)(x-5)(x-2i)(x+8) = 0 I think the roots are -2i,5,2i,-8-you take out the roots as opposites of what are in the equaion ...
*Monday, September 5, 2011 at 8:52am by Tabitha*

**Pre-Calculus**

An easy way to check is to note that the $2.20 is half of the $4.40 being depreciated, so it took half of the depreciation period of 4.4 years: 2.2 years. Odd that the asset life is the same as the amount being depreciated. Bad example, imho.
*Saturday, September 28, 2013 at 2:48pm by Steve*

**pre algebra**

Mr Chee deposited $80 into his checking account. Then, after writing a $23 check for gas and a $90 check for his child's day care, the balance in his account was $67. How much was in his account before he made the deposit? How would you solve and check the answer?
*Tuesday, February 1, 2011 at 8:55am by Amber shall*

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