Wednesday

April 16, 2014

April 16, 2014

Number of results: 116,401

**Pre-Cal**

Yes I am, but I don't understand it. I don't have a teacher to teach me. I do my work online, and I just need 2nd semester of pre-cal to graduate.
*Saturday, March 17, 2012 at 9:29pm by Adrianna*

**pre cal**

eh? plug in 6 for x. What do you get? If you're taking pre-cal, this should be a no-brainer.
*Wednesday, June 19, 2013 at 3:19pm by Steve*

**Pre-cal**

start with f(z) = i as directed then f(i) = -1 +i - i = -1 check f(-1) =+1 -1 - i = -i do not check f(-i) =-1 -i - i = -1 -2i
*Saturday, January 3, 2009 at 12:09pm by Damon*

**Pre-Cal(Please check)**

i did -2/3 divided by 15, 10, -6, 0 and 14 I got 15, 0, -6 , 4 ,11.4 Is this correct?
*Saturday, March 27, 2010 at 5:38pm by Abbey*

**pre cal **

does anyone take pre-cal online ?
*Monday, April 16, 2012 at 6:44pm by Mecie *

**Pre. Cal.**

coefs of row 4 1 4 6 4 1 so a^4 + 4 a^3 b + 6 a^2 b^2 + 4 a b^3 + b^4 (3p+r^3)^4 a = 3p b = r^3 a^4 = 81 p^4 check 4 a^3 b = 4*27 or 108 p^3 r^3 check 6 a^2 b^2 = 6*9 or 54 p^2 r^6 check etc
*Thursday, May 14, 2009 at 10:43pm by Damon*

**pre cal--check**

yes
*Tuesday, March 31, 2009 at 8:27pm by Reiny*

**Pre-Cal(Please check)**

-(-2) + sqrt 4 - (-2)^2 = 2 + sqrt 4 + 4 No 2 + sqrt 4 - 4
*Tuesday, March 16, 2010 at 1:47am by Damon*

**Pre Cal Check**

focus: (0,p) vertex: if not given, then it is assumed (0,0) Directrix: k+p or k-p, i'm not sure I think these are the general equations for the focus, vertex, and directrix of a parabola, but i'm not sure. could someone please check this? thanks.
*Sunday, February 25, 2007 at 8:33pm by Marie*

**Pre-Cal(Please check)**

sqrt2 /10 Do I just leave this as sqrt2/10 or can I reduce it to sqrt1/5?
*Thursday, March 11, 2010 at 3:04pm by Abbey*

**Pre-Cal(Please check)**

1)f(x) = -x + sqrt 4 - x^2 Find f(-2) -(-2) + sqrt 4 - (-2)^2 = 2 + sqrt 4 + 4 2 + sqrt 8 = 4.828 Is this correct?
*Tuesday, March 16, 2010 at 1:47am by Hannah*

**pre-cal**

pre-cal? more like algebra I must be the review section for the x-intercept, set y=0: x=1 for the y-intercept, set x=0: y = -2
*Sunday, December 9, 2012 at 11:59am by Steve*

**Pre-Cal(Please help)**

Error
*Tuesday, March 23, 2010 at 1:05pm by Mark*

**Pre Cal**

please explain your b and a.
*Monday, July 25, 2011 at 3:04pm by Ashley*

**Pre-Cal(Please check!!!)**

are you solving for r? In an isoceleses right triangle, of angles 45-45-90, the hypontense is side*sqrt2 In your case, r=20*1.41=28.2 Your tangent of 45 degrees is wrong, it is tangent45=1
*Tuesday, March 23, 2010 at 4:09pm by bobpursley*

**Pre-Cal(Please help)**

h(x) = 1/x-3 + 1 I know the vertical and horizontal asymptotes but I just need to know the domain. Please help. I am very confused.
*Monday, March 29, 2010 at 6:18pm by Hannah*

**Pre-Cal**

What is the domain of f/g? f(x) = x / x+1 g(x) = x^3 Please explain! Thank you
*Monday, March 22, 2010 at 9:44pm by Hannah*

**Pre-Cal(Please help)**

Answered Already
*Sunday, April 4, 2010 at 3:59pm by Abbey*

**Pre-cal**

f(x)= x+1 and g(x)= square root of x-3 please help me!
*Thursday, December 13, 2012 at 5:57pm by Isis*

**pre cal**

solve for x: x^(2/3)=(1/27) (2^(x)+4)/(2^x)=2 explain please
*Sunday, December 7, 2008 at 8:46pm by jason*

**Science**

A 50 gram ice cube is cooled to -10oC in the freezer. How many calories of heat are required to heat it until it becomes liquid water at 20oC? (The specific heat of ice is 0.5 cal/goC.) Answer A) 1250 cal. B) 4000 cal. C) 5000 cal. D) 5250 cal. Can someone please help me solve...
*Monday, September 26, 2011 at 1:29am by Anonymous*

**physics **

A 50 gram ice cube is cooled to -10oC in the freezer. How many calories of heat are required to heat it until it becomes liquid water at 20oC? (The specific heat of ice is 0.5 cal/goC.) Answer A) 1250 cal. B) 4000 cal. C) 5000 cal. D) 5250 cal. Can someone please help me solve...
*Monday, September 26, 2011 at 5:17pm by Allison*

**Pre-Cal(Please help)**

Nevermind I think I figured it out.
*Saturday, March 27, 2010 at 5:48pm by Abbey*

**pre-cal/trig**

if you get to cosx+sinx=1/square root of 2, well we are doing identities in my pre-cal class and cosx+sinx always equals 1, so it would be 1/square root of 2.
*Tuesday, March 4, 2008 at 7:44pm by emily*

**Pre-Cal(please check)**

From what I am reading into the diagram, you have a distance down the riverbank of 100ft, then w across the river. The angle to the end of w from the start of the 100ft length is 54deg tangent54=w/100 w= 100 tangent54.
*Tuesday, March 23, 2010 at 4:31pm by bobpursley*

**Pre-Cal(Please help)**

1/(x+3) domain everywhere on x axis except x = -3 where the denominator is zero.
*Thursday, March 25, 2010 at 10:09pm by Damon*

**pre cal**

please help dont understand this...Assume f(x) = 2x + 8 and g(x) = 5. What is the value of (f + g)(3)?
*Tuesday, September 27, 2011 at 2:58pm by random person*

**Pre-Cal(Please check!!!)**

solve for r There is a right triangle with the hypotenuse as r , the angle as 45 degrees and opposite side as 20. I am having a hard time finding this out. I had tan 45 = 1.61 20(1.61) = 32.4 but this is wrong.
*Tuesday, March 23, 2010 at 4:09pm by Abbey*

**Pre-Cal(please check)**

I have to find the width of a river which is represented by a right trianle. The opposite side is labeled w and the adjacent side is 1oo ft. Theta is 54 degrees. Would my equation be opp = adjacent/cos(54)?
*Tuesday, March 23, 2010 at 4:31pm by Hannah*

**PRE-CALC still stuck**

Pre-cal? V=kT V=kr^2 I=V(1/R)
*Sunday, October 18, 2009 at 5:55pm by bobpursley*

**pre-cal**

can you please tell me the differences and examples of the numerical,algebraic, and graphical representations?
*Saturday, March 1, 2008 at 10:14pm by Lusi*

**pre-cal**

can anyone please explain to me how to simplify this exponential expression??I got no idea...THANKS A LOT! [(-8x^6)/(y^-6)]^2/3
*Tuesday, February 5, 2008 at 7:39pm by Kelly*

**Pre Cal(please show me the work)**

wait I forgot to add that she bought the card origionally for $1
*Tuesday, March 18, 2008 at 3:42pm by Brittany*

**Pre-Cal (Please help)**

Identify any asymptotes of the graph. y = 1.08^5x I know that there is a horizontal asymptote but I do not know how to find it.
*Monday, March 22, 2010 at 4:40pm by Mark*

**pre-cal**

Find the terminal point determined by t.Please enter answer in ordered pair
*Sunday, June 5, 2011 at 3:29pm by mookie*

**Math applied/pre-cal**

(-8/5)^7/4*(-8/5)^1/4=64/25 Not sure how get this answer . Could please show me the steps.
*Wednesday, July 11, 2012 at 1:53pm by Hannah*

**Integrated Physics and Chemistry**

The specific heat capacity of copper is 0.09 cal/g°C. How much energy is needed to flow into a 10-gram sample to change its temperature from 20°C to 21°C? A)0.009 cal B)0.09 cal C)0.9 cal D)9 cal
*Thursday, April 21, 2011 at 10:29am by Ashley!!*

**Pre-Cal(Please check)**

I don't know what the original question is. If the answer given is sqrt(2/10), most teachers expect the answer to be rationalized, namely, no square-root sign in the denominator. So sqrt(2/10) =sqrt(1/5) =1/sqrt(5) =sqrt(5)/sqrt(5)² =sqrt(5)/5
*Thursday, March 11, 2010 at 3:04pm by MathMate*

**pre cal--check**

Name all the values of x that are not in the domain of f(x) = (2–x^2)/ (x+ 5) I got only x= -5 because that's the only value that would make the denominator zero.
*Tuesday, March 31, 2009 at 8:27pm by Jason*

**Pre Cal(please show me the work)**

then as I said replace a with 1 in t/9 = log(32/a) to get t = 9log32 = 13.55 years
*Tuesday, March 18, 2008 at 3:42pm by Reiny*

**pre-Cal(Please help)**

Use the law of cosines to find the angle Q between the given vectors. v = 3i + j w = 2i - j
*Wednesday, March 31, 2010 at 5:34pm by Hannah*

**math**

80 cal/g x 5 g 400g/cal or 400 cal/g not sure can any one help Neither. 80 cal/g x 5g = 400 cal. The unit g cancels to leave calories. x2+2x-15
*Monday, December 11, 2006 at 10:45pm by rena*

**chemistry**

How many calories are required to heat 25.0 g of platinum from 24.5 °C to 75°C (specific heat of platinum = 0.139 J/gK)? 1. 47 cal 2. 42 cal 3. 48 cal 4. 20 cal 5. 80 cal Thank you.
*Sunday, November 22, 2009 at 5:30pm by Danny*

**science**

the conversion factor for calories (cal) and joules (J) is: 1 cal = 4.184 J now to convert calories to joules, we multiply 4000 cal by 4.184 J / 1 cal so that the cal unit will be canceled, and the numerator will have the unit J: 4000 cal * 4.184 J / cal = 16736 J hope this ...
*Wednesday, October 26, 2011 at 3:09am by Jai*

**pre cal**

Find f of g of h and state the exact domain. f(x) = sqrt x g(x)= e^x - 13e^x/2 + 42 h(x) = 2x I need help on this one bad! Please help!
*Wednesday, October 5, 2011 at 8:51pm by Anonymous*

**Lauren**

memorize the conversion units. 1000J=1kJ 1 cal= 4.1868 J 1k=1000 units so as an example, then on the second 2970kcal(4.1868J/cal) Then immediately check the units, to make certain the units cancel out to leave what you want. In this case... kcal*J/(cal) leaves kJ do the math.
*Thursday, December 5, 2013 at 3:07pm by bobpursley*

**Chem**

I wish teachers would get away from Calories vs calories. A Calorie (with a capital C, sometimes called a "big calorie" actually is a kilocalorie and should be addressed as such. So 1 Cal = 1000 calories. There are 4.184 joules in 1 calorie. You can convert from anything to ...
*Sunday, October 16, 2011 at 8:13pm by DrBob222*

**pre-cal/trig**

PlEASE hlep me with this!! I need it as soon as possible....... cos(x-(pi/4))+sin(x-(pi/4))=1 Find the answer from 0 to 2pi. When I slove this, I got cosx+sinx=(1/ square root of 2). then I don't know what to do the rest. Please help me.
*Tuesday, March 4, 2008 at 7:44pm by aa*

**Physics**

Fp=440 - 15/5 = 437Hz = Freq. of piano. Brent, check your 3-28-11, 11:57am post for solution to your Pre-cal prob.
*Wednesday, March 30, 2011 at 1:02pm by Henry*

**pre-cal/trig**

Can Anybody answer this question for me???? Please??? PlEASE hlep me with this!! I need it as soon as possible....... cos(x-(pi/4))+sin(x-(pi/4))=1 Find the answer from 0 to 2pi
*Tuesday, March 4, 2008 at 7:44pm by ^quen^*

**pre-cal-please help**

the midpoint is the average of the x's and the average of the y's let me know what you got.
*Saturday, October 13, 2012 at 11:22am by Reiny*

**Pre-Cal**

Find the standard form of the equation of the ellipse. (Remember center is midpoint between either foci or vertices) (1) 9x^2+4y^2+36x-24y+36=0 (2) Vertices: (0,5)(0,-5) Passes through the point (4,2) Centered at the origin
*Sunday, April 19, 2009 at 6:33pm by Cal*

**Pre-Cal(Please help!!)**

Consider the function y=arcsin x. a) Use a grapging utility to complete the table. x = -1 -0.8 -0.6 -0.4 -0.2 y = ? ? ? ? ? I am not sure what to plug into the calculator to get the answer.
*Monday, February 15, 2010 at 4:41pm by Hannah*

**Pre-cal (Please Check)**

1) Evaluate (if possible) the sine, cosine, and tangent of the angles without a calculator. a) 10pi/3 Sin = -sqrt 3/2 Cos = -1/2 Tan = sqrt 3 Are these correct ? I do not understand when to make them negative. b) 17pi/3 Sin = -sqrt 3/2 Cos = 1/2 Tan = - sqrt 3 Are these ...
*Wednesday, February 10, 2010 at 4:40pm by Hannah*

**Pre CAL!! Please HELP**

find the solutions of the equation that are in the interval [0,2pi) (a) sin2t+sint=0 (b)cost-sin2t=0
*Thursday, November 4, 2010 at 8:52pm by Hayli*

**Pre CAL!! Please HELP**

find the solutions of the equation that are in the interval [0,2pi) (a) sin2t+sint=0 (b)cost-sin2t=0
*Thursday, November 4, 2010 at 8:56pm by Hayli*

**Pre-Cal(Please help)**

Approximate the equation's soultions in the interval (o, 2pi). If possible find the exact solutions. sin 2x sinx = cosx I do not know where to start.
*Saturday, March 6, 2010 at 6:12pm by Abby*

**Pre-Cal(Please help)**

Determine the domains of (a)f and (b) f X g f(x) = 1/x g(x)= x + 3 For the domain of f I had x > 0 and for f X g I had all real numbers but this was wrong.
*Thursday, March 25, 2010 at 10:09pm by Hannah*

**Pre-Cal**

Perform the operation and write the result in standard form. (2-3i)(5i) over 2+3i Please help!! I do not understand this.
*Wednesday, March 25, 2009 at 2:29pm by Kim*

**Pre cal**

)a function f is defined as f(x) = 3*2^x describe the end behavior of f, please describe in detail how you got the answer and explain your abbreviations.
*Monday, July 25, 2011 at 9:25pm by Ashley*

**Pre Cal**

what does it mean when it says describe the end behavior of f and whats that for f(x)=(x^2+x+3)/(x-1) and f(x)= 3*2^x, please explain everything, and if you use --> tell me what that means, cuz i have no clue
*Monday, July 25, 2011 at 7:49pm by Ashley*

**Pre-Cal**

the centre is clearly (0,1), the midpoint of these two vertices. and a = 2 so x^2/4 - (y-1)^2/b^2 = 1 but it passes through the point (5,4), so 25/4 - 9/b^2 = 1 -9/b^2= 1-24/4 -9/b^2 = -20/4 b^2/9 = 4/20 = 1/5 b^2 = 9/5 so the hyperbola is x^2/25 - 5(y-1)^2/9 = 1 (check my ...
*Saturday, May 2, 2009 at 7:37pm by Reiny*

**Pre-Cal(Please help)**

Use synthetic division to show that x is a solution of the third-degree polynomial equation, and use the result to factor the polynomial completely. List all the real zeros of the function. x^3 - 28x - 48 = 0 Value of x = -4 Please help!!Thank you
*Saturday, March 27, 2010 at 5:48pm by Abbey*

**Pre-Cal**

What is the domain, range, zeros, symmetry, and is it even/odd of these functions? (how can you tell, i don't remember how you get all these, refresher please) y= 1/x y=[x] y=sq rt. of x^2 -4 y=sin x y=cos x y=tan x
*Monday, August 23, 2010 at 6:21pm by Amanda*

**Pre-Cal(Please help)**

Give the domain of the function and identify any vertical or horizontal asymptotes. h(x) = 1 / x - 3 + 1 I had x = 0 and y = 3. Would the domain be all numbers except 1?
*Friday, March 26, 2010 at 12:17am by Hannah*

**Pre-Cal**

For the given f(x), you will need to use synthetic to find the quotient q(x) and the remainder, r. Since you already figured out how to do synthetic division, you should have no problem tackling this one. Post your answer for a check if you wish.
*Saturday, March 27, 2010 at 5:38pm by MathMate*

**pre-Cal(Please help)**

v•w = |v| |w|cos Ø v•w = 6 - 1 = 5 5 = √10√5cosØ cosØ = 5/√50 Ø = 45°
*Wednesday, March 31, 2010 at 5:34pm by Reiny*

**Pre-Calculus**

I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
*Saturday, September 17, 2011 at 2:40pm by Cristina*

**Pre-Calculus**

I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
*Saturday, September 17, 2011 at 3:48pm by Cristina*

**Pre-Cal(Please help)**

Find two functions f and g such that (f X g)(x) = h(x). (There are many correct answers.) h(x) = 4 / (5x + 2)^2 = My answers were: f(x) = 4 / 5x, and g(x) = 5x + 2 Please explain. These answers were wrong and I do not know how to fix them!!
*Thursday, March 25, 2010 at 4:07pm by Hannah*

**pre-cal**

Can someone please show me how to find an equation for the line with the given properties. Parellel to the lines 3x-y= -3; containing the point (0,0) y= (then type your answer in slope intercept form)
*Saturday, October 13, 2012 at 11:45am by ladybug*

**Pre-Cal(Please help)**

1) Use the half-angle formulas to determine the exact values of the sine, cosine, and tangent of the angle. 67 degrees 30'
*Monday, March 8, 2010 at 5:13pm by Abbey*

**Chemistry**

Calculate S (measure of total entropy) for the following reaction at 25C and 1atm, and tell whether the entropy is increasing or decreasing. C3H8(g)+5O2(g)-> 3CO2(g)+4H2O(g) S of C3H8=64.5 cal/(mol*K) S of O2= 49 cal/(mol*K) S of CO2= 51.1 cal/(mol*K) S of H2O= 45.1 cal/(...
*Monday, November 16, 2009 at 8:45am by Christina*

**Chemistry Help!!!!**

Calculate S (measure of total entropy) for the following reaction at 25C and 1atm, and tell whether the entropy is increasing or decreasing. C3H8(g)+5O2(g)-> 3CO2(g)+4H2O(g) S of C3H8=64.5 cal/(mol*K) S of O2= 49 cal/(mol*K) S of CO2= 51.1 cal/(mol*K) S of H2O= 45.1 cal/(...
*Monday, November 16, 2009 at 1:43pm by Christina*

**Chemistry**

Calculate S (measure of total entropy) for the following reaction at 25C and 1atm, and tell whether the entropy is increasing or decreasing. C3H8(g)+5O2(g)-> 3CO2(g)+4H2O(g) S of C3H8=64.5 cal/(mol*K) S of O2= 49 cal/(mol*K) S of CO2= 51.1 cal/(mol*K) S of H2O= 45.1 cal/(...
*Monday, November 16, 2009 at 9:03pm by Christina*

**Chemistry**

You don't need the heat of vaporization to do that calculation. It takes 10g*1Cal/C g*10C = 100 Cal heat release to reduce the temperature ot 0C, and another 80 Cal/g*10 g = 800 Cal to freeze it. The sum is 900 Cal
*Saturday, April 17, 2010 at 12:35am by drwls*

**pre-cal**

A "super ball" dropped from a height of x feet bounces to a height y that is 80% of x. Can anyone please teach me how to find its numerical, algebraic, and graphical representations? Thanks a lot!!!
*Saturday, March 1, 2008 at 10:14pm by Lusi*

**Pre-Cal(Please check)**

1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = -sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I have to divide by 2 but that is where I an not ...
*Thursday, February 18, 2010 at 1:12pm by Hannah*

**Pre-Cal(Please check)**

1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = -sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I have to divide by 2 but that is where I an not ...
*Thursday, February 18, 2010 at 2:59pm by Hannah*

**Pre-Cal**

1) use the half-angle formulas to determine the exact values of the sine, cosine, and tangent of the angle. 67 degrees and 30' Please explain!! I do not know how to start.
*Monday, March 1, 2010 at 3:56pm by Janet*

**Pre-cal/Trig**

(tan/(1+sec)) + ((1+sec)/tan) = 2csc (Show all work please.)
*Monday, February 21, 2011 at 9:44pm by Katherine*

**Pre. Cal.**

yes
*Thursday, May 14, 2009 at 10:43pm by Reiny*

**Pre cal**

OK. Thanks. =]
*Saturday, August 29, 2009 at 6:12pm by Anonymous*

**Pre-Cal**

Thank You
*Saturday, March 27, 2010 at 5:38pm by Abbey*

**Pre-Cal**

Thank You!!
*Sunday, March 28, 2010 at 12:54pm by Hannah*

**Pre-Cal**

Thank You
*Sunday, April 4, 2010 at 5:30pm by Abbey*

**Pre Cal**

b)
*Monday, July 25, 2011 at 3:04pm by Anonymous*

**Pre Cal**

why and how do you know
*Monday, July 25, 2011 at 3:04pm by Ashley*

**Pre Cal**

Thank you!!!
*Monday, February 13, 2012 at 11:06pm by Anonymous*

**Pre-Cal**

thanks
*Saturday, March 17, 2012 at 9:29pm by Adrianna*

**Pre-cal**

thank you
*Wednesday, April 18, 2012 at 10:10am by sandra*

**Pre-cal**

to do what?
*Thursday, December 13, 2012 at 5:57pm by Steve*

**Pre-Cal**

y-2=3^x take the log base 3 of each side. log3(y-2)=x x= log3(y-2) y= log3(x-2) is the inverse. check: f(inverse)= 3^(log3(x-2)) + 2 = (x-2)+ 2 = x
*Friday, March 19, 2010 at 3:22pm by bobpursley*

**Pre-Cal(Please help)**

Find (a) f X g , (b) g X f, and (c) f X f f(x) = 3sqrt x-1 g(x) = x^3 + 1 For the f(x) the 3 is little above the sqrt sign. my answers were: (a) = 3sqrt x^4 -1 (b) = x^4 -1 (c) = 6sqrt x+1 These answers are wrong but I do not know how to do this.
*Thursday, March 25, 2010 at 3:58pm by Hannah*

**pre-cal-please help**

find the mid point of the line segment joining the points P1 and P2. P1 = (3,5) P2 = (-4,7)
*Saturday, October 13, 2012 at 11:22am by ladybug*

**college maths**

Mathematically, you can set up the problem as follow: 232 Cal/1.5 Cup = x Cal/1 cup 1x = 232/1.5 x = 154.7 Cal Another way, this is a no brainer question given the choices below. With 1.5 cup, you know it has 232 Cal, so with only 1 cup, you know the answer should be less than...
*Wednesday, December 15, 2010 at 2:16pm by Terry*

**Chemistry**

1.24E7 J x (1 cal/4.184J) = 2.98E6 cal. 12 oz x 2.98E6 cal/80,000 cal = ?oz Gatorade.
*Saturday, April 20, 2013 at 7:55pm by DrBob222*

**Pre-Cal**

Find f X g , g X f , and f X f f(x) = 3sqrt x-1 g(x) = x^3 + 1 For f(x) the 3 is little above the sqrt sign. My answers were: f(g(x)) = 3sqrt x^3 + 1 -1 g(f(x)) = 3sqrt (x-1)^3 -1 f(f) = 3sqrt x-1-1 My teacher said these were wrong. Please help. I do not know how to correct ...
*Monday, March 29, 2010 at 4:18pm by Hannah*

**Pre-Cal**

Find f X g , g X f , and f X f f(x) = 3sqrt x-1 g(x) = x^3 + 1 For f(x) the 3 is little above the sqrt sign. My answers were: f(g(x)) = 3sqrt x^3 + 1 -1 g(f(x)) = 3sqrt (x-1)^3 -1 f(f) = 3sqrt x-1-1 My teacher said these were wrong. Please help. I do not know how to correct ...
*Monday, March 29, 2010 at 11:06pm by Hannah*

**pre-cal**

Please state your question more clearly. What do you mean by "t values" and "primary cycle"? I have never heard of inflection points referred to as "key points", or vice versa.
*Monday, March 5, 2012 at 11:22pm by drwls*

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