Sunday

April 20, 2014

April 20, 2014

Number of results: 12,056

**Pre-Cal**

Use the law of cosines to find the angle of Q between the given vectors. v=3i + j w=2i - j
*Sunday, March 28, 2010 at 5:08pm by Hannah*

**Pre Cal**

Find the manitude of each vetcor, and write each vector as the sum of the unit vectors. Choose either one (2,6) or (4,-5) Thank you
*Saturday, January 9, 2010 at 9:13pm by amy*

**pre-Cal(Please help)**

Use the law of cosines to find the angle Q between the given vectors. v = 3i + j w = 2i - j
*Wednesday, March 31, 2010 at 5:34pm by Hannah*

**Pre-Cal**

Yes I am, but I don't understand it. I don't have a teacher to teach me. I do my work online, and I just need 2nd semester of pre-cal to graduate.
*Saturday, March 17, 2012 at 9:29pm by Adrianna*

**Pre Cal/Vectors**

Can someone show the steps involved in figuring out this type of problem? Given the magnitudes of vectors u and v and the angle Ό between them, find the magnitude of the sum u + v to the nearest tenth and the angle that the sum vector makes with u to the nearest degree. /...
*Sunday, July 24, 2011 at 8:06pm by Joe*

**pre cal**

eh? plug in 6 for x. What do you get? If you're taking pre-cal, this should be a no-brainer.
*Wednesday, June 19, 2013 at 3:19pm by Steve*

**pre cal **

does anyone take pre-cal online ?
*Monday, April 16, 2012 at 6:44pm by Mecie *

**pre-cal**

pre-cal? more like algebra I must be the review section for the x-intercept, set y=0: x=1 for the y-intercept, set x=0: y = -2
*Sunday, December 9, 2012 at 11:59am by Steve*

**Pre Cal**

The magnitude of each vector is found by taking the square root of the square of each component. ||(2,6)|| = sqrt(2^2 + 6^2) It is usually written as double bars. The vector can also be expressed as the sum of scalar components multiplied by unit vectors. With i = (1, 0) and j...
*Saturday, January 9, 2010 at 9:13pm by Marth*

**Pre Cal/Vectors**

Follow the same method and steps as I showed you in http://www.jiskha.com/display.cgi?id=1311551145 except this one is easier since it forms a right-angled triangle, and your parallogram is a rectangle. If the resultant is R, then R^2 = 20^2 + 86^2 = 7796 R = √7796 = 88....
*Sunday, July 24, 2011 at 8:06pm by Reiny*

**Pre Cal/Vectors**

X = 20. Y = 86. tanA = Y/X = 86/20 = 4.3, A = 76.9 deg. R = X / cosA = 20 / cos76.9 = 88.24 OR R = Y / sinA = 86 / sin76.9 = 88.3 .
*Sunday, July 24, 2011 at 8:06pm by Henry*

**pre-cal/trig**

if you get to cosx+sinx=1/square root of 2, well we are doing identities in my pre-cal class and cosx+sinx always equals 1, so it would be 1/square root of 2.
*Tuesday, March 4, 2008 at 7:44pm by emily*

**math**

given that vectors(p+2q) and (5p-4q) are orthogonal,if vectors p and q are the unit vectors,find the dot product of vectors p and q?
*Wednesday, January 2, 2013 at 1:04am by bhawani*

**math**

given that vectors(p+2q) and (5p-4q) are orthogonal,if vectors p and q are the unit vectors,find the product of vectors p and q?
*Tuesday, January 1, 2013 at 6:21am by bhawani*

**PRE-CALC still stuck**

Pre-cal? V=kT V=kr^2 I=V(1/R)
*Sunday, October 18, 2009 at 5:55pm by bobpursley*

**pre-calc**

Use pairs of points to find two different direction vectors in the plane. eg. (1,4,-5) and (4,2,-3) Now take the cross product of those two vectors. You should have learned an algorithm to do that.
*Wednesday, February 17, 2010 at 8:24pm by Reiny*

**Integrated Physics and Chemistry**

The specific heat capacity of copper is 0.09 cal/g°C. How much energy is needed to flow into a 10-gram sample to change its temperature from 20°C to 21°C? A)0.009 cal B)0.09 cal C)0.9 cal D)9 cal
*Thursday, April 21, 2011 at 10:29am by Ashley!!*

**math**

80 cal/g x 5 g 400g/cal or 400 cal/g not sure can any one help Neither. 80 cal/g x 5g = 400 cal. The unit g cancels to leave calories. x2+2x-15
*Monday, December 11, 2006 at 10:45pm by rena*

**chemistry**

How many calories are required to heat 25.0 g of platinum from 24.5 °C to 75°C (specific heat of platinum = 0.139 J/gK)? 1. 47 cal 2. 42 cal 3. 48 cal 4. 20 cal 5. 80 cal Thank you.
*Sunday, November 22, 2009 at 5:30pm by Danny*

**science**

the conversion factor for calories (cal) and joules (J) is: 1 cal = 4.184 J now to convert calories to joules, we multiply 4000 cal by 4.184 J / 1 cal so that the cal unit will be canceled, and the numerator will have the unit J: 4000 cal * 4.184 J / cal = 16736 J hope this ...
*Wednesday, October 26, 2011 at 3:09am by Jai*

**physics**

Can you help me with this one also? I know how to do it with 3 vectors but I can't seem to draw it with 4 vectors. The magnitudes of the four displacement vectors shown in the drawing are A=16.0 m, B=11.0 m, C=12.0 m, and D=26.0 m. Determine the (1) magnitude and (2) ...
*Sunday, January 23, 2011 at 9:02pm by Brittany*

**Pre-Calculus**

I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
*Saturday, September 17, 2011 at 2:40pm by Cristina*

**Pre-Calculus**

I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
*Saturday, September 17, 2011 at 3:48pm by Cristina*

**math**

two vectors are defined as a=2i+xj and b=i-4j. find value of x if a) the vectors are parallel b) the vectors are perpendicular
*Sunday, November 21, 2010 at 8:12pm by karla*

**math**

two vectors are defined as a=2i+xj and b=i-4j. find value of x if a) the vectors are parallel b) the vectors are perpendicular
*Sunday, November 21, 2010 at 8:50pm by karla*

**Math - Algebraic Vectors**

Given the vectors: u = [3, 0] v = [-1, 2] a) Express the vector w = [2, 8] as a linear combination of vectors u and v. How do I do this?
*Wednesday, February 13, 2008 at 2:38pm by Anonymous*

**Science**

A 50 gram ice cube is cooled to -10oC in the freezer. How many calories of heat are required to heat it until it becomes liquid water at 20oC? (The specific heat of ice is 0.5 cal/goC.) Answer A) 1250 cal. B) 4000 cal. C) 5000 cal. D) 5250 cal. Can someone please help me solve...
*Monday, September 26, 2011 at 1:29am by Anonymous*

**physics **

A 50 gram ice cube is cooled to -10oC in the freezer. How many calories of heat are required to heat it until it becomes liquid water at 20oC? (The specific heat of ice is 0.5 cal/goC.) Answer A) 1250 cal. B) 4000 cal. C) 5000 cal. D) 5250 cal. Can someone please help me solve...
*Monday, September 26, 2011 at 5:17pm by Allison*

**Chemistry**

You don't need the heat of vaporization to do that calculation. It takes 10g*1Cal/C g*10C = 100 Cal heat release to reduce the temperature ot 0C, and another 80 Cal/g*10 g = 800 Cal to freeze it. The sum is 900 Cal
*Saturday, April 17, 2010 at 12:35am by drwls*

**math**

if vectors a+b+c=0 and modulus of the vectors a, b and c are 3 ,5 and 7 respectively. find the angle between the vectors a and b.
*Saturday, January 5, 2013 at 4:04am by raja*

**Calculus and Vectors**

THE VECTORS a - 5b AND a-b ARE PERPENDICULAR. IF a AND b ARE UNIT VECTORS, THEN DETERMINE a dot b
*Saturday, May 11, 2013 at 3:53pm by Johnny*

**physics**

You add the vectors. I recommend break each of the distances into N and E vectors, so adding the four vectors can be done in components. I will be happy to critique your thinking or work.
*Monday, January 14, 2008 at 3:11am by bobpursley*

**Calculus**

Name two sets of vectors that could be used to span a set in R^3. Show how the vectors (-1,2,0) and (3,4,0) could each be written as a linear combination of the vectors you have chosen.
*Wednesday, April 28, 2010 at 4:56pm by Jackiee*

**Pre. Cal.**

yes
*Thursday, May 14, 2009 at 10:43pm by Reiny*

**Pre cal**

OK. Thanks. =]
*Saturday, August 29, 2009 at 6:12pm by Anonymous*

**Pre-Cal**

Thank You
*Saturday, March 27, 2010 at 5:38pm by Abbey*

**Pre-Cal**

Thank You!!
*Sunday, March 28, 2010 at 12:54pm by Hannah*

**Pre-Cal**

Thank You
*Sunday, April 4, 2010 at 5:30pm by Abbey*

**Pre Cal**

b)
*Monday, July 25, 2011 at 3:04pm by Anonymous*

**Pre Cal**

why and how do you know
*Monday, July 25, 2011 at 3:04pm by Ashley*

**Pre Cal**

Thank you!!!
*Monday, February 13, 2012 at 11:06pm by Anonymous*

**Pre-Cal**

thanks
*Saturday, March 17, 2012 at 9:29pm by Adrianna*

**Pre-cal**

thank you
*Wednesday, April 18, 2012 at 10:10am by sandra*

**Pre-cal**

to do what?
*Thursday, December 13, 2012 at 5:57pm by Steve*

**Calulas and VECTORS**

THE VECTORS a - 5b AND a-b ARE PERPENDICULAR. IF a AND b ARE UNIT VECTORS, THEN DETERMINE a * b
*Wednesday, May 19, 2010 at 7:34pm by z...........................*

**college maths**

Mathematically, you can set up the problem as follow: 232 Cal/1.5 Cup = x Cal/1 cup 1x = 232/1.5 x = 154.7 Cal Another way, this is a no brainer question given the choices below. With 1.5 cup, you know it has 232 Cal, so with only 1 cup, you know the answer should be less than...
*Wednesday, December 15, 2010 at 2:16pm by Terry*

**Physics**

Break each of the vectors into N, E components. For instance: vectorC is -C*Cos35 E and C*sin35N do that for all three vectors, then the sum of all three E vectors will be zero, and the sum of all three N vectors will be zero. Solve B, C (B,C is a magnitude of vectors b, C
*Monday, January 19, 2009 at 8:59pm by bobpursley*

**Pre-Cal**

What are bearings??
*Tuesday, February 5, 2008 at 12:34pm by Daisy M.*

**Pre Cal**

thanks so much!
*Tuesday, February 19, 2008 at 1:01pm by Kindell*

**another pre cal (logs)**

Thank you
*Monday, March 31, 2008 at 1:14am by Deb*

**Pre-Cal**

xy=2 {{x^2=3+y^2}}
*Tuesday, October 21, 2008 at 6:16pm by Ash*

**Pre Cal.**

correct.
*Tuesday, March 31, 2009 at 9:28am by bobpursley*

**pre cal--check**

yes
*Tuesday, March 31, 2009 at 8:27pm by Reiny*

**Pre Cal.**

è is theta.
*Tuesday, April 21, 2009 at 3:12pm by Jamie*

**Pre Cal.**

correct!
*Tuesday, April 21, 2009 at 3:12pm by Reiny*

**Pre-Cal**

(-2,1) and (2,1) are the vertices.
*Saturday, May 2, 2009 at 7:37pm by Hal*

**Pre Cal**

Solve for x 2^x=8^x-3
*Tuesday, December 22, 2009 at 2:53am by Raina*

**Pre-Cal**

Everywhere BUT 0
*Thursday, March 25, 2010 at 10:22pm by Damon*

**Pre-Cal :)**

You're very welcome!
*Saturday, March 27, 2010 at 5:38pm by MathMate*

**Pre-cal**

I agree
*Saturday, May 8, 2010 at 12:23am by Reiny*

**pre-cal**

16
*Thursday, September 2, 2010 at 6:06pm by Ms. Sue*

**Pre Cal**

What is the inverse of g(x)= 1/2(x-1)^3-4
*Monday, October 25, 2010 at 1:17am by Katie*

**Pre Cal**

40
*Saturday, January 9, 2010 at 5:50pm by Anonymous*

**Pre Cal**

this is wrong
*Sunday, July 24, 2011 at 8:20pm by Dalidah*

**pre-cal**

no "t" in formula
*Monday, January 16, 2012 at 8:07pm by Steve*

**Translation**

It is pre-cal
*Friday, March 23, 2012 at 4:25pm by Sebastian*

**Pre-Cal**

YOU SHOULD KNOW HOW TO DO THIS!
*Wednesday, March 25, 2009 at 2:29pm by YOU'RE BAD AT MATH*

**Pre-cal**

123694587
*Thursday, May 6, 2010 at 7:21pm by Anonymous*

**Pre-Cal**

#3 = B 95
*Saturday, March 17, 2012 at 10:21pm by Ryan*

**pre cal**

what is the question?
*Wednesday, February 13, 2013 at 5:08pm by bobpursley*

**Pre cal**

second
*Thursday, January 30, 2014 at 8:42pm by shelly *

**Pre cal**

how do you find A?
*Thursday, January 30, 2014 at 8:42pm by shelly *

**pre cal**

mmmhhh? (0+3)^2 = 3^2 = 9
*Thursday, January 30, 2014 at 8:53pm by Reiny*

**pre cal**

zero
*Thursday, March 6, 2014 at 9:43am by Damon*

**pre cal**

s400
*Sunday, September 4, 2011 at 11:14pm by Halib*

**Pre-Calculus Vectors**

nvm got it
*Monday, April 18, 2011 at 7:34pm by PETER*

**physics**

if the * is the degrees, then you need to draw the vectors according to their direction. you can use a graph paper and make your own scale: say one unit cube is 10km/hr. then use the protractor to draw the vectors taking an horizontal line as zero degrees. then draw the ...
*Thursday, June 6, 2013 at 3:57am by bonjo*

**Chemistry**

Do you know the conversion factor? 1 cal = 4.184 joules and I get 4565 cal. Is that a capital C for cal. In nutrition, especially in the old days, there was a big calorie (actually a kilocalorie or Calorie) and a small calorie (a calorie). If we round the 5 to the even number...
*Friday, October 30, 2009 at 7:22pm by DrBob222*

**Pre-Cal**

:-D Pleasure. Stu.
*Tuesday, January 29, 2008 at 5:16pm by Creating a formula from 2 variables*

**Pre-Cal (again)**

If: f(x)= 3/x^2-1 g(x)= x+1 What is the domain of f, g, and f o g?
*Saturday, September 20, 2008 at 9:19pm by Crystal*

**Trig/Pre-Cal**

1 - - x > 0 x
*Sunday, September 7, 2008 at 11:18pm by Brooke*

**pre cal**

What would cos2theta=-1/2 be???
*Saturday, November 15, 2008 at 2:45pm by becca*

**pre cal**

what is the sum of e or 1n
*Sunday, January 11, 2009 at 6:07pm by ash*

**Pre-Cal**

Find f X g 3 sqrt of x+1 X x^3+1
*Thursday, February 26, 2009 at 11:32pm by Dan*

**Pre-Cal**

if 2^x=3 whats does 4^-x equal
*Thursday, February 26, 2009 at 11:32pm by Dominique*

**Pre-Cal.**

Graph it on your calculator.
*Thursday, March 26, 2009 at 9:16am by bobpursley*

**Pre Cal.**

all 3 are correct.
*Monday, June 15, 2009 at 6:29pm by Reiny*

**Pre Cal.**

All correct!
*Thursday, August 13, 2009 at 12:45am by MathMate*

**Pre Cal.**

Both correct!
*Thursday, August 13, 2009 at 12:49am by MathMate*

**Pre Cal.**

none of them are correct.
*Saturday, August 15, 2009 at 4:31pm by bobpursley*

**Pre-Cal**

Simplify e^3ln2-1
*Saturday, January 9, 2010 at 11:02pm by jamie*

**Pre-Cal**

1/sec = cos
*Friday, March 5, 2010 at 5:42pm by bobpursley*

**Pre-Cal**

yes, to your second part
*Wednesday, March 10, 2010 at 11:12pm by Reiny*

**Pre-Cal(Please help)**

Error
*Tuesday, March 23, 2010 at 1:05pm by Mark*

**Pre-Cal(urgent)**

Nevermind.
*Wednesday, March 31, 2010 at 11:06pm by Hannah*

**Pre-cal**

both are right.
*Sunday, May 9, 2010 at 7:59pm by bobpursley*

**pre-cal**

(576^1/2+512^1/3)^1/3
*Monday, May 31, 2010 at 7:53pm by Soto*

**L Pre-Cal**

yes that was a typo, my bad!
*Wednesday, January 26, 2011 at 7:43pm by Norah*

**Pre Cal**

please explain your b and a.
*Monday, July 25, 2011 at 3:04pm by Ashley*

**Pre cal**

Thank you sooooo much !!!
*Sunday, October 23, 2011 at 8:28pm by Basim*

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