Friday
April 18, 2014

Search: Pre Cal/Logarithism

Number of results: 10,332

Pre Cal/Logarithism
given that f(x)=11^x, find x when f(x)=7 a) x=Ln(7/11) b) x=Ln7/Ln11 c) x= 7/11 d) x= ll sub 7 11
Sunday, July 24, 2011 at 9:39pm by Angela

Pre Cal/Logarithism
so you solving: 11^x = 7 take ln of both sides ln(11^x) = ln7 x(ln11) = ln7 x = ln7/ln11
Sunday, July 24, 2011 at 9:39pm by Reiny

Pre-Cal
Yes I am, but I don't understand it. I don't have a teacher to teach me. I do my work online, and I just need 2nd semester of pre-cal to graduate.
Saturday, March 17, 2012 at 9:29pm by Adrianna

pre cal
eh? plug in 6 for x. What do you get? If you're taking pre-cal, this should be a no-brainer.
Wednesday, June 19, 2013 at 3:19pm by Steve

pre cal
does anyone take pre-cal online ?
Monday, April 16, 2012 at 6:44pm by Mecie

pre-cal
pre-cal? more like algebra I must be the review section for the x-intercept, set y=0: x=1 for the y-intercept, set x=0: y = -2
Sunday, December 9, 2012 at 11:59am by Steve

pre-cal/trig
if you get to cosx+sinx=1/square root of 2, well we are doing identities in my pre-cal class and cosx+sinx always equals 1, so it would be 1/square root of 2.
Tuesday, March 4, 2008 at 7:44pm by emily

PRE-CALC still stuck
Pre-cal? V=kT V=kr^2 I=V(1/R)
Sunday, October 18, 2009 at 5:55pm by bobpursley

Integrated Physics and Chemistry
The specific heat capacity of copper is 0.09 cal/gC. How much energy is needed to flow into a 10-gram sample to change its temperature from 20C to 21C? A)0.009 cal B)0.09 cal C)0.9 cal D)9 cal
Thursday, April 21, 2011 at 10:29am by Ashley!!

math
80 cal/g x 5 g 400g/cal or 400 cal/g not sure can any one help Neither. 80 cal/g x 5g = 400 cal. The unit g cancels to leave calories. x2+2x-15
Monday, December 11, 2006 at 10:45pm by rena

chemistry
How many calories are required to heat 25.0 g of platinum from 24.5 C to 75C (specific heat of platinum = 0.139 J/gK)? 1. 47 cal 2. 42 cal 3. 48 cal 4. 20 cal 5. 80 cal Thank you.
Sunday, November 22, 2009 at 5:30pm by Danny

science
the conversion factor for calories (cal) and joules (J) is: 1 cal = 4.184 J now to convert calories to joules, we multiply 4000 cal by 4.184 J / 1 cal so that the cal unit will be canceled, and the numerator will have the unit J: 4000 cal * 4.184 J / cal = 16736 J hope this ...
Wednesday, October 26, 2011 at 3:09am by Jai

Pre-Cal
Find the standard form of the equation of the ellipse. (Remember center is midpoint between either foci or vertices) (1) 9x^2+4y^2+36x-24y+36=0 (2) Vertices: (0,5)(0,-5) Passes through the point (4,2) Centered at the origin
Sunday, April 19, 2009 at 6:33pm by Cal

Pre-Calculus
I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
Saturday, September 17, 2011 at 2:40pm by Cristina

Pre-Calculus
I'm trying to finish up my pre-cal homework and I am stuck on 2 problems... ***determine the intervals over which the function is increasing, decreasing, or constant*** 32. f(x)=x^2-4x 33. f(x)=√x^2-1 (that's square root of x^2-1) thank you so much for the help =)
Saturday, September 17, 2011 at 3:48pm by Cristina

Science
A 50 gram ice cube is cooled to -10oC in the freezer. How many calories of heat are required to heat it until it becomes liquid water at 20oC? (The specific heat of ice is 0.5 cal/goC.) Answer A) 1250 cal. B) 4000 cal. C) 5000 cal. D) 5250 cal. Can someone please help me solve...
Monday, September 26, 2011 at 1:29am by Anonymous

physics
A 50 gram ice cube is cooled to -10oC in the freezer. How many calories of heat are required to heat it until it becomes liquid water at 20oC? (The specific heat of ice is 0.5 cal/goC.) Answer A) 1250 cal. B) 4000 cal. C) 5000 cal. D) 5250 cal. Can someone please help me solve...
Monday, September 26, 2011 at 5:17pm by Allison

Chemistry
You don't need the heat of vaporization to do that calculation. It takes 10g*1Cal/C g*10C = 100 Cal heat release to reduce the temperature ot 0C, and another 80 Cal/g*10 g = 800 Cal to freeze it. The sum is 900 Cal
Saturday, April 17, 2010 at 12:35am by drwls

Pre. Cal.
yes
Thursday, May 14, 2009 at 10:43pm by Reiny

Pre cal
OK. Thanks. =]
Saturday, August 29, 2009 at 6:12pm by Anonymous

Pre-Cal
Thank You
Saturday, March 27, 2010 at 5:38pm by Abbey

Pre-Cal
Thank You!!
Sunday, March 28, 2010 at 12:54pm by Hannah

Pre-Cal
Thank You
Sunday, April 4, 2010 at 5:30pm by Abbey

Pre Cal
b)
Monday, July 25, 2011 at 3:04pm by Anonymous

Pre Cal
why and how do you know
Monday, July 25, 2011 at 3:04pm by Ashley

Pre Cal
Thank you!!!
Monday, February 13, 2012 at 11:06pm by Anonymous

Pre-Cal
thanks
Saturday, March 17, 2012 at 9:29pm by Adrianna

Pre-cal
thank you
Wednesday, April 18, 2012 at 10:10am by sandra

Pre-cal
to do what?
Thursday, December 13, 2012 at 5:57pm by Steve

college maths
Mathematically, you can set up the problem as follow: 232 Cal/1.5 Cup = x Cal/1 cup 1x = 232/1.5 x = 154.7 Cal Another way, this is a no brainer question given the choices below. With 1.5 cup, you know it has 232 Cal, so with only 1 cup, you know the answer should be less than...
Wednesday, December 15, 2010 at 2:16pm by Terry

Chemistry
1.24E7 J x (1 cal/4.184J) = 2.98E6 cal. 12 oz x 2.98E6 cal/80,000 cal = ?oz Gatorade.
Saturday, April 20, 2013 at 7:55pm by DrBob222

Pre-Cal
What are bearings??
Tuesday, February 5, 2008 at 12:34pm by Daisy M.

Pre Cal
thanks so much!
Tuesday, February 19, 2008 at 1:01pm by Kindell

another pre cal (logs)
Thank you
Monday, March 31, 2008 at 1:14am by Deb

Pre-Cal
xy=2 {{x^2=3+y^2}}
Tuesday, October 21, 2008 at 6:16pm by Ash

Pre Cal.
correct.
Tuesday, March 31, 2009 at 9:28am by bobpursley

pre cal--check
yes
Tuesday, March 31, 2009 at 8:27pm by Reiny

Pre Cal.
is theta.
Tuesday, April 21, 2009 at 3:12pm by Jamie

Pre Cal.
correct!
Tuesday, April 21, 2009 at 3:12pm by Reiny

Pre-Cal
(-2,1) and (2,1) are the vertices.
Saturday, May 2, 2009 at 7:37pm by Hal

Pre Cal
Solve for x 2^x=8^x-3
Tuesday, December 22, 2009 at 2:53am by Raina

Pre-Cal
Everywhere BUT 0
Thursday, March 25, 2010 at 10:22pm by Damon

Pre-Cal :)
You're very welcome!
Saturday, March 27, 2010 at 5:38pm by MathMate

Pre-cal
I agree
Saturday, May 8, 2010 at 12:23am by Reiny

Pre Cal
What is the inverse of g(x)= 1/2(x-1)^3-4
Monday, October 25, 2010 at 1:17am by Katie

Pre Cal
40
Saturday, January 9, 2010 at 5:50pm by Anonymous

Pre Cal
this is wrong
Sunday, July 24, 2011 at 8:20pm by Dalidah

pre-cal
no "t" in formula
Monday, January 16, 2012 at 8:07pm by Steve

Translation
It is pre-cal
Friday, March 23, 2012 at 4:25pm by Sebastian

Pre-cal
123694587
Thursday, May 6, 2010 at 7:21pm by Anonymous

Pre-Cal
#3 = B 95
Saturday, March 17, 2012 at 10:21pm by Ryan

pre cal
what is the question?
Wednesday, February 13, 2013 at 5:08pm by bobpursley

Pre cal
second
Thursday, January 30, 2014 at 8:42pm by shelly

Pre cal
how do you find A?
Thursday, January 30, 2014 at 8:42pm by shelly

pre cal
mmmhhh? (0+3)^2 = 3^2 = 9
Thursday, January 30, 2014 at 8:53pm by Reiny

pre cal
zero
Thursday, March 6, 2014 at 9:43am by Damon

pre cal
s400
Sunday, September 4, 2011 at 11:14pm by Halib

Chemistry
Do you know the conversion factor? 1 cal = 4.184 joules and I get 4565 cal. Is that a capital C for cal. In nutrition, especially in the old days, there was a big calorie (actually a kilocalorie or Calorie) and a small calorie (a calorie). If we round the 5 to the even number...
Friday, October 30, 2009 at 7:22pm by DrBob222

Pre-Cal (again)
If: f(x)= 3/x^2-1 g(x)= x+1 What is the domain of f, g, and f o g?
Saturday, September 20, 2008 at 9:19pm by Crystal

Trig/Pre-Cal
1 - - x > 0 x
Sunday, September 7, 2008 at 11:18pm by Brooke

pre cal
What would cos2theta=-1/2 be???
Saturday, November 15, 2008 at 2:45pm by becca

pre cal
what is the sum of e or 1n
Sunday, January 11, 2009 at 6:07pm by ash

Pre-Cal
Find f X g 3 sqrt of x+1 X x^3+1
Thursday, February 26, 2009 at 11:32pm by Dan

Pre-Cal
if 2^x=3 whats does 4^-x equal
Thursday, February 26, 2009 at 11:32pm by Dominique

Pre-Cal.
Graph it on your calculator.
Thursday, March 26, 2009 at 9:16am by bobpursley

Pre Cal.
all 3 are correct.
Monday, June 15, 2009 at 6:29pm by Reiny

Pre Cal.
All correct!
Thursday, August 13, 2009 at 12:45am by MathMate

Pre Cal.
Both correct!
Thursday, August 13, 2009 at 12:49am by MathMate

Pre Cal.
none of them are correct.
Saturday, August 15, 2009 at 4:31pm by bobpursley

Pre-Cal
Simplify e^3ln2-1
Saturday, January 9, 2010 at 11:02pm by jamie

Pre-Cal
1/sec = cos
Friday, March 5, 2010 at 5:42pm by bobpursley

Pre-Cal
yes, to your second part
Wednesday, March 10, 2010 at 11:12pm by Reiny

Pre-Cal(Please help)
Error
Tuesday, March 23, 2010 at 1:05pm by Mark

Pre-Cal(urgent)
Nevermind.
Wednesday, March 31, 2010 at 11:06pm by Hannah

Pre-cal
both are right.
Sunday, May 9, 2010 at 7:59pm by bobpursley

pre-cal
(576^1/2+512^1/3)^1/3
Monday, May 31, 2010 at 7:53pm by Soto

pre-cal
16
Thursday, September 2, 2010 at 6:06pm by Ms. Sue

L Pre-Cal
yes that was a typo, my bad!
Wednesday, January 26, 2011 at 7:43pm by Norah

Pre Cal
please explain your b and a.
Monday, July 25, 2011 at 3:04pm by Ashley

Pre cal
Thank you sooooo much !!!
Sunday, October 23, 2011 at 8:28pm by Basim

Pre Cal
cos^2+tan^2=1
Sunday, March 25, 2012 at 7:56pm by Trevion

pre-cal
thank you very much
Wednesday, April 18, 2012 at 10:52am by sandra

Pre-Cal
YOU SHOULD KNOW HOW TO DO THIS!
Wednesday, March 25, 2009 at 2:29pm by YOU'RE BAD AT MATH

pre cal
7tan^2(pheta)-2=3
Thursday, June 28, 2012 at 10:48pm by Maria

pre cal
(y^2)^-4y^8 simplify
Thursday, August 30, 2012 at 11:20pm by jennifer

pre-cal
That's what I thought but was not for sure. thanks!!
Saturday, October 13, 2012 at 5:21pm by ladybug

pre cal
by definition, tan(t) = b/a
Sunday, February 17, 2013 at 2:18pm by Reiny

Pre cal
ix^2-2x+i=0
Sunday, March 17, 2013 at 6:21pm by Anonymous

Pre-Cal
tan-1=43\9.3
Wednesday, May 1, 2013 at 8:01pm by Anonymous

pre cal
19500(1.039)^5 = ?
Tuesday, May 28, 2013 at 11:49am by Steve

pre cal
x^2(4x^2+1)^7(76x^2+3)
Sunday, June 30, 2013 at 3:44pm by Tony

pre cal
how did you solve this??? I am so los.
Sunday, June 30, 2013 at 3:44pm by jovahnna

pre cal
C = 5.69 + .0848x
Wednesday, January 15, 2014 at 3:16am by Steve

pre cal
how did you get the nine after the A?
Thursday, January 30, 2014 at 8:53pm by shelly

Math Pre-Cal
how would i do that
Thursday, January 30, 2014 at 9:16pm by Holly

pre cal
I agree. What about it?
Wednesday, February 12, 2014 at 10:25pm by Reiny

chemistry
334 J/g x (1 cal/4.184 J) = ? cal/g. Note how i knew that the factor is 1 ca/4.184 J and not 4.184 J/1 cal. The unit we don't want cancels(J); the unit we want to keep stays(cal).
Thursday, June 20, 2013 at 6:04pm by DrBob222

physics
In cooling down to liquid at 0 C, the steam will lose Q = 540 cal/g*15g + 1.0cal/gC*100C*15g = 8100 + 1500 = 9600 calories. That amount of heat, transferred to the ice, can melt 9600 cal/80 cal/g = 120 g of ice. The 540 cal/g and 80 cal/g numbers that I used are the heats of ...
Tuesday, April 3, 2012 at 9:25pm by drwls

Chemistry
How much heat is released when 10 g of steam at 100C is cooled to 10 g of liquid water at 100C? I am working on a practice test and the answer is not in the back of the book. Can some one help me. 1. 10 cal 2. 5400 cal 3. 800 cal 4. 6200 cal
Thursday, November 10, 2011 at 2:40am by nan

pre - cal
12-5y^2 what's the question?
Monday, August 20, 2007 at 10:32pm by Anonymous

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