Number of results: 115,792
I am first pasting the previous response. Then, I will step through the steps. --------------- Break the problem into vertical and horizontal components. Find the initial vertical component (30.0 m/s) * sin(60) because the problem says the missile is launched 30 degress from ...
Wednesday, April 2, 2008 at 6:27pm by Quidditch
Assume the ball starts its upward flight from the top of the throwers head, 1.75m above the ground. 1--Time to maximum height above the thrower's head derives from Vf = Vo - 9.8t or 0 = 5.376 - 9.8t making t(up) = .548sec. 2--Time back to the top of the throwers head is also ....
Wednesday, April 16, 2008 at 1:10pm by tchrwill
1. A 3.25 kg steel ball strikes a wall with a speed of 10.0 m/s at an angle of 60.0° with the surface. It bounces off with the same speed and angle. If the ball is in contact with the wall for 0.195 s, what is the average force exerted on the ball by the wall? x component: N y...
Sunday, July 6, 2008 at 11:01pm by Elisa
A rollercoaster car of mass 600.0 kg is moving 2.4m/s at the top of a peak that is 25m off the ground. The car moves down slope and up the next hill. Assume that it loses 20,000J of energy by the next time it gets to the top of the next peak due to friction forces. If the ...
Saturday, May 31, 2008 at 7:06pm by sarah
The initial total(kinetic + potential) energy, with respect to ground level zero P.E., is (1/2) M V^2 + M g H = 1728 J + 147,150 J = 148,778 J. If it loses 20,000 J before reaching the next peak, and has 2.0 m/s velocity there, then 128,778 = (1/2) M V^2 + M g H' = 1200 + M g ...
Saturday, May 31, 2008 at 7:06pm by drwls
1--The study of projectile motion is made easy by breaking the initial velocity into its vertical and horizontal components. Thus, If a projectile is fired with an initial velocity of Vo at an angle "”" to the horizontal, Vv = Vvertical = (Vo)sin(”) and Vh = Vhorizontal = (Vo)...
Tuesday, June 3, 2008 at 1:40pm by tchrwill
a drinking fountain projects water at an initial angle of 50 degrees above the horizontal and the water reaches a maximum height of 0.150 m above the point of exit. assume air resistance is negligible. calculate the speed at which the water leaves the fountain. the readius of ...
Monday, June 9, 2008 at 10:29pm by shelly
From Vf = Vo - 9.8t, 5.6 = 0 - 9.8t or t = .571sec. to zero verical velocity and maximum height. From h = Vot - 4.9t^2, h = .56(.571) - 4.9(.571)^2 or h = 1.597 m upward from the 115m drop point for a total height of 116.56m. Again, from h = Vot + 4.9t^2, the time to reach the...
Saturday, July 19, 2008 at 2:14pm by tchrwill
It travels upwards until the vertical velocity component becomes zero. An easier way to calculate it it to require that the initial kinetic energy become completely potential energy there. (1/2) M Vo^2 = M g H where H is the maximum height above the thrower's hand. H = Vo^2/(2...
Monday, July 21, 2008 at 7:21pm by drwls
How would you reword the terms of this equation: (1/2)M Vo^2 = M g H Where H is the maximum height above the thrower's hand. H = VoČ/(2 g) = 11.5 m Could you substitute the letters H & M with Y, Yo, V, Vo, G, T, or use any of these four newton's equtions: V = Vo + gt Y = Yo + ...
Tuesday, July 22, 2008 at 6:29am by ruby
i have this problem, it asks: (a) With what speed must a ball be thrown vertically from ground level to rise to a maximum height of 50m? answer: 31m/s (b)How long will it be in the air?\ answer: 6.4s (c) Sketch graphs of y, v, and a vs. t for the ball. On the first two graphs...
Monday, August 25, 2008 at 2:18pm by alk
In a projectile motion, if we measure the maximum height h and horizontal range R (1) How to get launch angle θ in terms of h and R (2) A hobby rocket reaches a height of 72.3 m and lands 111 m from the launch point.What is the angle of launch? What is the launch speed?
Tuesday, September 9, 2008 at 12:27am by Jenny
An object is thrown straight up. At the same instant that the object reaches its maximum height, a second object is dropped from this maximum height. Which object hits the ground first and why? Also, a ball is thrown straight up. If the ball's initial velocity is considered ...
Saturday, September 13, 2008 at 9:45pm by meg
You can simplify the problem a bit by realizing that the pot will take the same length of time going up as going down past the window's 2 meter height. Thus it takes 0.25 s to go from top to bottom. Let H be the verticaldistance from maximum height to the top of the window. ...
Saturday, September 13, 2008 at 11:36pm by drwls
Well i think that the one that is dropped from the maximum height will hit the ground first because it doesn't have negative velocity like the one thrown from the ground has. And the second question I don't understand at all? Please help. and thank you.
Saturday, September 13, 2008 at 9:45pm by meg
An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its launch point. What is the initial (launch) speed of the object?
Monday, September 15, 2008 at 11:39pm by Eve
A ball thrown vertically upward is caught by the thrower after 2 seconds. Find the initial velocity of the ball and the maximum height the ball reaches???!!
Thursday, September 18, 2008 at 5:45pm by mb
A daredevil on a motorcycle leaves the end of a ramp with a speed of 29.0 m/s as in the figure below. If his speed is 26.7 m/s when he reaches the peak of the path, what is the maximum height that he reaches? Ignore friction and air resistance.
Saturday, October 4, 2008 at 5:52pm by Sandhya
A projectile is launched with a speed of 41 m/s at an angle of 60° above the horizontal. Use conservation of energy to find the maximum height reached by the projectile during its flight. m
Thursday, October 9, 2008 at 2:08pm by k
The answer is NOT the square root 2. It is the initial velocity Vo divided by the square root of two. Think of the law of conservation of energy and you should be able to see why. The kinetic energy is reduced by half, because it is half way to its maximum height, where the ...
Sunday, October 19, 2008 at 12:50pm by drwls