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April 16, 2014

Search: Physics #43

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math helllllllllllpppp plzzzzzzzzzzzzzzzzzzzzzzz
43^0 = 1 or 01 43^1 = 43 43^2 = 1849 43^3 = 79507 43^4 = 3418801 43^5 = 147008443 43^6 = ......049 43^7 = ..... 07 43^8 = ..... 01 43^9 = ..... 43 ahhh, can you see how the end repeats ? ending: 43 49 07 01 43 repeats after 4 numbers 2082/4 = 520 and remainder of 1 and behaves...
Tuesday, May 14, 2013 at 2:16pm by Reiny

Physics
Momentum = m1V1-m2V2. Momentum = 0.241*1.53 - 0.321*2.49=-0.43 = 0.43 to the Left. m*V = 0.43. (0.241+0.321)V = 0.43 0.562V = 0.43 V = 0.765 m/s.
Monday, November 19, 2012 at 5:09pm by Henry

Physics
B. d = 0.5a*t^2 = 2.27*8.43^2 = 161.3 m. C. V = a*t = 4.53*8.43 = 38.2 m/s. D. 3.62*8.43 = 30.5 m/s.
Friday, September 20, 2013 at 1:54am by Henry

Geometry
Triangle ABC, angle A = 55 deg side b = 43 tan A = op/adj = a/b = a/43 tan 55 = a/43 a = 43 * 1.4281 a = 61.4083 cos 55 = adj/hyp = b/c = 43/c cos 55 = 43/c c = 43/0.5736 c = 74.9651 I'll let you finish (not sure what 'length of triangle' is) Length of triangle = ?
Monday, February 14, 2011 at 9:41pm by helper

Physics
V = Vo + a*t = 0 43 + a*0.28 = 0 0.28a = -43 a = -153.6 m/s^2
Friday, January 31, 2014 at 12:51pm by Henry

Physics
λ=4•10.75=43 cm=0.43 m λ=v/f f1= v/ λ =344/0.43 = 800 Hz f2=600 Hz resonance fₒ=2400 Hz
Monday, June 4, 2012 at 10:17pm by Elena

Physics(Please help)
The angle is -43°, not 43° The vector points below the x-axis, so sin is negative.
Friday, May 25, 2012 at 2:44pm by Steve

algebra
easiest way: since the two lines are parallel, they will differ only in the constant. so let the new line by x + 4y = k but (7,9) lies on it so 7 + 4(9) = k k = 43 for an equation of x + 4y = 43 change to y = mx + b form 4y = -x + 43 y = (1/4)x + 43/4
Saturday, August 29, 2009 at 12:09am by Reiny

algebra
easiest way: since the two lines are parallel, they will differ only in the constant. so let the new line by x + 4y = k but (7,9) lies on it so 7 + 4(9) = k k = 43 for an equation of x + 4y = 43 change to y = mx + b form 4y = -x + 43 y = (1/4)x + 43/4
Saturday, August 29, 2009 at 12:09am by Reiny

physics
How long does it take to fall 17.2 inches. (I assume you are working with an ancient text that uses feet and inches so in your world g = 32 ft/s^2) 17.2 inches /12 in/ft = 1.43 ft d = 1.43 = (1/2) g t^2 1.43 = 16 t^2 t = .299 seconds to fall So horizontal speed u took us 1.61 ...
Saturday, November 17, 2012 at 8:53pm by Damon

physics
How long does it take to fall 17.2 inches. (I assume you are working with an ancient text that uses feet and inches so in your world g = 32 ft/s^2) 17.2 inches /12 in/ft = 1.43 ft d = 1.43 = (1/2) g t^2 1.43 = 16 t^2 t = .299 seconds to fall So horizontal speed u took us 1.61 ...
Saturday, November 17, 2012 at 8:53pm by Damon

Physics
This ball fell during t=sqrt2h/g) =sqrt(2•0.9/9.8)=0.43 s Horizontal motion (v(x)=const) => L=v(x) •t v(x)=L/t=2.6/0.43=6.1 m/s
Tuesday, October 30, 2012 at 10:50pm by Elena

Pre-Calculus
Determine the derivative at the point (2,−43) on the curve given by f(x)=7−7x−9x^2. I know that the answer is -43, but I was wondering if it was just a coincidence that the derivative at the point (2,−43) is -43, or is there a reason why -43 is the same...
Saturday, October 19, 2013 at 10:37pm by Ann

algebra
the width of a rectangle is 3 less than twice the length of x. if area of rectangle is 43 in sq ft. which equation can be used to find length in feet a. 2x(x-3)=43 b.2x+2(2x-3)=43 c.x(3-2x)=43 d.x(2x-3)=43
Friday, March 29, 2013 at 6:50pm by Anonymous

physics
You forgot to include the directions of the speeds. The correct equation is: 1000*11 x-hat +2400*19 y-hat=3400*v3 v3 = 110/43 x-hat +24*19/43 y-hat The magnitude of v3 is thus: sqrt[(110/43 )^2 + (24*19/43 )^2]
Thursday, December 13, 2007 at 5:54pm by Count Iblis

physics
Wb = mg = 4.4kg + 9.8N/kg = 43.12N. Work = F*h = 43.12 * 1.3 = 56.1J.
Wednesday, November 9, 2011 at 3:20pm by Henry

math
Ahhh, great question!!!! We know two of the prices, the high and the low, which is a total of $43. So the average price of the remaining 19 books must be > $18 and < $25 (375-43)/19 = 17.5 no good (530-43)/19 = 25.6 no good (175-43)/19 = 6.9 no good (445-43)/19 = 21.1 ...
Monday, February 18, 2008 at 9:33pm by Reiny

physics
If the two wires are at the same angle to the horizontal (43 degrees), they have equal tension, T. Balance the vertical forces with 2 T sin 43 = M g Solve for T
Saturday, February 19, 2011 at 11:36am by drwls

math
5 3/8 = 43/8 (43/8) / 2 (43/8) * (1/2) = 43/16 = 2 11/16
Wednesday, September 12, 2012 at 8:38pm by Ms. Sue

Math
these questions have been 'fudged' so that they can be done mentally by using basic factoring techniques. for the first 7.7^2-2.3^2 , I see the difference of squares = (7.7 + 2.3)(7.7-2.3) = 10 (5.4) = 54 the last one uses 'common factoring' 43*56 + 43*44 = 43(56+44) = 43*100...
Sunday, March 7, 2010 at 2:35pm by Reiny

physics
12 + 32 = 43 ft/s^2 177 * (43/32) = 238 pounds
Monday, February 24, 2014 at 9:29pm by Damon

physics
I am not going to do all these for you. They are all basically the same. a = (V2-V1)/t = (25.6-0)/.59 = 43.4 m/s^2 F = m a = 879 * 43.4 = 38,140 Newtons
Friday, November 26, 2010 at 1:40am by Damon

Physics
t^2=2x3.14x0.47/a Or, a=6.28x0.47/1.43^2=0.43 m/sec^2
Saturday, November 3, 2012 at 2:25pm by mahesh

physics
This is a matter of resolving a vector into components. Basic stuff. a) 576 cos 43 b) 576 sin (-43) assuming the +x axis is up.
Sunday, January 30, 2011 at 8:04pm by drwls

Algebra
Use Quadratic Formula: X = (-0.8 +- sqrt(0.64+2.96))/-0.04 = -27.43, and 67.43 X = 67.43 m.
Friday, April 4, 2014 at 12:41pm by Henry

Pre algebra
-3(4x+3)+4(6X+1)=43 -12x - 9 + 24x + 4 = 43 12x = 43 - 4 + 9 I'm sure you can take it from there.
Sunday, January 23, 2011 at 7:02pm by Ms. Sue

calculus
Find where the graphs intersect. That will give you the limits of integration. 4x^2 = 7x^2 at x=0 4x^2 = 3-4x at x = 0.5 7x^2 = 3-4x at .43 4x^2 < 7x^2, so we need to integrate 7x^2 - 4x^2 from 0 to 0.43 3-4x - 4x^2 from 0.43 to 0.5 Int(3x^2) = x^3 [0,0.43] = 0.08 Int(3-4x-...
Monday, October 24, 2011 at 11:42am by Steve

Physics
conservation of momentum, first collary. the center of gravity does not change if it was still before. CG= (0*83+13*43 )/(83+43) and it does not move. That is where they will meet.
Monday, November 1, 2010 at 6:11pm by bobpursley

math
13/43 * 30/43* 30/43 Unless I am wrong. This may be more complicated than I think.
Sunday, November 24, 2013 at 9:57pm by Sam

math8
5(3c-c)+3=43 15c - 5c + 3 = 43 10c = 43 - 3 10c = 40 c = 4
Thursday, January 31, 2013 at 5:50pm by Ms. Sue

Math
43 heads = 43 animals ( I hope!!) C = number of chickens G = number of goats C + G = 43 2C + 4G = 108 solve simultaneously to find C and G if you are right, C = 32 G = 11
Tuesday, January 18, 2011 at 10:43pm by helper

algebra
Are you sure that (x1 + 43) after the capital-sigma sum sign is not xi + 43 ? It makes no sense otherwise. If the general term is xi +43, add up the xi values from x1 to x15 and add 15*43 to that sum.
Tuesday, March 22, 2011 at 4:17am by drwls

Physics
m*g = 5.36k * 9.8N/kg = 52.53 N. = Wt. of object. a. KE = 0 J. = Initial KE V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*1 = 19.6 V = 4.43 m/s. KE = 0.5m*V^2 = 2.68*4.43^2 = 52.59 J. b. V^2 = Vo^2 + 2g*h V^2 = 4.43^2 + 19.6*1 = 39.22 V = 6.26 m/s. KEo = 2.68*4.43^2 = 52.59 J. KE = 2.68*6....
Saturday, March 8, 2014 at 3:16pm by Henry

physics
what is the initial velocity of this equation. .92m= 3.10 times .43 + 1/2 times 9.8 m/s times .43 squared
Friday, May 16, 2008 at 10:49am by lisa

physics 1
1/2 (.386)t^2 + 1/2 (.359)t^2 = 88.7 .745t^2 = 177.4 t = 15.43 seconds to impact so, George rode .5(.386)(15.43^2) = 45.95 m
Tuesday, January 28, 2014 at 11:48am by Anonymous

Physics
F = 125 N mass = (125+305)/10 = 43 kg a = F/m = 125/43 = 2.9 m/s^2
Tuesday, January 17, 2012 at 8:10pm by Damon

heeeeeeeeeeelp math
Solve using a probability tree. First calculate the outcomes with distinct rolls for a sum of P(x)=30/36. For simplicity, the probability is multiplied by 36 to use integers. sum=x 36*P(x) x*36*P(x) 3 2 6 4 2 8 5 4 20 6 4 24 7 6 42 8 4 32 9 4 36 10 2 20 11 2 22 Sums of 2 and ...
Friday, July 5, 2013 at 8:30am by MathMate

physics
2.1 * 9.81 * .61 = 12.57 Newtons maximum friction force so no 15 - 12.56 = 2.43 Newton net force a = F/m = 2.43 / 2.1 = 1.16 m/s^2
Tuesday, January 21, 2014 at 5:46pm by Damon

physics
v = Vi -7.1 t 0 = 43 - 7.1 t t = 43/7.1 = 6.06 s average speed during stop = 7.1 /2 =3.55 m/s d = 3.55 * 6.06 = 21.5 m
Thursday, March 27, 2014 at 2:29am by Damon

Physics
The oscillation period is 23/25 = 0.920 seconds. 0.6 seconds is 0.65217 periods after the maximum displacement, so the phase angle is x = 4.0977 radiansafter maximum downward displacement. Displacement @ t=0.6 s (with + being down) = 76 mm*(cos x) = 76 mm*(-0.57668) = -43.8 mm...
Sunday, December 30, 2012 at 4:36pm by drwls

Physics
30days * 24h/day = 720 Hours kW * h = (60/1000)kW * 720h = 43.2 kWh Cost = 43.2kWh * 0.10/kWh = $4.32
Thursday, March 20, 2014 at 2:45pm by Henry

Algebra
since you give no idea on the available space, that's hard to say. However, a border of 2.43 inches around a 5x7 photo will occupy an area of (5+2*2.43)(7+2*2.43) = 116.94 in^2, which is more than twice as big as the photo.
Friday, March 21, 2014 at 9:45pm by Steve

Algebra
Yes, you can solve the exponential equation without using logs if you are using a calculator. EQUATION:L=2.43*W^0.3326=2.43*24^0.3326=2.43*2.8778=6.99=7.0 In this example, L was the unknown and W was 24lbs.The calculator was used to solve expo. If W was the unknown and L was 7...
Wednesday, June 23, 2010 at 5:08pm by Henry

math
larger ---- x smaller ---- y x+y = 60 x-y = 26 add them 2x = 86 x=43 43+y = 60 y = 17 difference between their squares = 43^2 - 17^2 = 1560
Monday, September 10, 2012 at 7:43pm by Reiny

math
3 minutes = 180 seconds; 3 min and 43 seconds = 180 + 43 = ?? Average speed in relation to what? You already know miles per hour: 3 43/60 mph.
Friday, April 24, 2009 at 5:58pm by Writeacher

physics
A. Work = F*cosA * d = 43 J. 60*cosA * 2.0 = 43 120*cosA = 43 cosA = 0.35833 A = 69o B. a = (V^2-Vo^2)/2d a = (2.7^2-0)/4 = 1.82 m/s^2. F*cos69 = m*a 60*cos69 = m*1.82 m = 60*cos69/1.82 = 11.80 kg.
Tuesday, February 25, 2014 at 1:09pm by Henry

Physics
Let V be the recoil velocity. Since the total momentum must remain zero after throwing the ball, 0.0546*44.8 + 43.4*V = 0 V = -2.45/43.4 = -0.805 m/s The minus sign means it moves in the opposite direction as the ball.
Sunday, December 2, 2012 at 1:53am by drwls

algebra
when d is positive, where is 7 d >-43 well whenever d >-43/7 when d is negative, when is |d|>-43 well whenever d < -43/7 in other words for all real d IN FACT: the absolute value of any old number is positive. It is greater than ANY negative number
Monday, December 29, 2008 at 1:14pm by Damon

Physics A
I assume the bookshelf is being pulled up a 37 degree slope and that a 43 N force does the pulling in the same direction, up the slope. In that case the work done is 43*5 = 215 Joules.
Wednesday, November 21, 2012 at 12:09am by drwls

Algebra 2
term(1) = 43 term(2) = 47 a = 43 , d = 4 term(17) = a + 16d = 43 + 16(4) = 107
Monday, November 26, 2012 at 12:19pm by Reiny

Physics
Fap-Ff = m*a. 43-Ff = 3.3*0 = 0 Ff = 43 N. = Force of friction.
Sunday, February 10, 2013 at 1:25pm by Henry

physics
mg = 43 N. m = 43/g = 43 / 9.8 = 4.39 kg = Mass of ball. a = Fap / m = -51 / 4.39 = -11.62 m/s^2 Vf = Vo + at = 0. t = (Vf-Vo)/a. t = (0-4.9) / -11.62 = 0.422 s. NOTE: Fap = Force applied. Vf = Final velocity. Vo = Initial velocity.
Friday, February 24, 2012 at 12:50am by Henry

math
2b^2+s^2 = 59 2s^2+b^2 = 43 b^2 = 43-2s^2, so 2(43-2s^2)+s^2 = 59 3s^2 = 27 s=ħ3 so, b=ħ5 Only positive values are "feasible", so s=3,b=5 (2.98*3 + 4.58*5)*1.06 = 33.75
Monday, December 10, 2012 at 9:53am by Steve

Physics
No more than 120/35 = 3.43 A could flow if the resistors were in series. Theretore I mus assume that they are in parallel and that 11-3.43 = 7.57 A flows through the unknown resistor. Use that fact and the 120 V applied voltage to get its resistance, R = V/I = 15.85 ohms
Sunday, April 10, 2011 at 4:46pm by drwls

College Physics
Yes, it is a Compton shift problem. The "theta" that you use is 160 degrees, which is the angle that the X-ray photon is scattered. (The electron is scattered at a different angle). Your 0.00243 constant is actually h/(mc), where h is Planck's constant and m is the electron ...
Tuesday, April 13, 2010 at 11:48pm by drwls

algebra
3x+43 = 8x+8 8x - 3x = 43-8 5x = 35 X = 7. A = 3*7 + 43 = 64 Deg.
Sunday, May 13, 2012 at 6:45pm by Henry

Physics
The movement of the suitcase is afected only by the hor. component of the force exerted by Rachel: X = hor. = 43*cosA = 27, cosA = 27/43 = 0.6279, A = 51.1 Deg.
Monday, October 25, 2010 at 11:00pm by Henry

Physics
Forces 2 and 4 cancel each other. Forces 1 and 3 combined are the same as 20 N at 270 degrees. First calculate the resultant. The equilibrant will be the opposite of that. So, add 20 N at 270 and 50 N at 60. North direction component = 50sin60 = 43.3 East direction component...
Saturday, December 8, 2012 at 6:37pm by drwls

math 012 double check me please
Your first two steps are fine. On the third, in which you go from 12x - 12 = 10x - 43 to -12 = -2x - 43 I think you mean to say you're subtracting 12x from each side. Adding 43 to each side leaves 31 = -2x. Divide each side by -2 to get x = (-31)/2. So, it looks like you were ...
Sunday, February 1, 2009 at 5:50pm by Noether

maths
Since the son's age is between 13 and 19, the father must be 43, so that if the son's age is x, 4300 + x – (43 – x) = 4289, so 2x = 32 and x = 16. So the sum of their ages is 43 + 16 = 59.
Tuesday, October 5, 2010 at 8:09pm by Evie

math
two sides are 43 + 43 = 86 the other two are (120 - 86) /2 = 17 each. So to be more than 120, sides must be 43,43,18,18
Tuesday, February 19, 2013 at 2:44am by A

Physics
PEmax=mg*hmax = 28*9.8 * 159=43,630 J. = KEmax @ bottom of hill with no friction. KE = 14*31.3^2 = 13,716 J. Energy lost = 43,630 - 13,716=29,914 J.
Friday, March 14, 2014 at 11:23am by Henry

physics - HELP
Assuming the top of the garbage can is 43 m below the roof. Acceleration due to gravity, a = -g = -9.8 m/s/s Distance, S = -43 m initial velocity, u = 0 m/s final velocity, v v²-u²=2aS v=sqrt(2aS+u²) =sqrt(2*(-9.8)*(-43)) =29.03 m/s For impact with garbage can, ...
Saturday, September 19, 2009 at 9:10pm by MathMate

Physics help
Ac = w^2 r = v^2/r w = 33*2pi radians in 60 seconds = 3.46 radians/s w^2 = 11.9 Ac w^2 r = 11.9 * .12 = 1.43 m/s^2 Fc = m Ac = .002 * 1.43 = .00286 N yes yes yes no
Saturday, November 3, 2012 at 6:21pm by Damon

chemistry
N2 + O2 --> 2 NO change in heat (delta H)= 43.2 kcal based on the reaction, which statement is true? a) 43.2 kcal are consumed when 1.00g of O2 reacts b) 43.2 kcal are consumed when 1.00g of N2 reacts c) 43.2 kcal are consumed when 1.00g of NO is produced d) 43.2 kcal are ...
Monday, November 2, 2009 at 11:07am by Katie Y.

Algebra
No. He must make 63 calls total in three weeks. 21 * 3 = 63 18 + 25 = 43 -- He's already made 43 calls in two weeks. 63 - 43 = 20
Friday, October 2, 2009 at 10:24pm by Ms. Sue

Calculus, AntiDerivatives
I need help with this problem: A car traveling at 43 ft/sec decelerates at a constant 5 ft per second squared. How many feet does the car travel before coming to a complete stop? I'm not sure where to start, i know how to find antiDerivatives, but i dont even know the equation...
Thursday, November 23, 2006 at 6:51pm by Mike

physics
Fn = 45N @ 90 Deg. + 60N @ 225 Deg. X = 45*cos90 + 60*cos225 = -42.43 N. Y = 45*sin90 + 60*sin225 = 2.57 N. tanAr = Y/X = 2.57 / -42.43 = -0.06066. Ar = -3.47 Deg. A = -3.47 + 180 = 176.5 Deg. Fn = X/cosA = -42.43 / cos176.5 = 42'51 N. @ 176.5 Deg.,CCW.
Tuesday, April 3, 2012 at 11:55pm by Henry

math
Solve for x. 14 + 18.75 + x + 4 = 43 36.75 + x = 43 x = 43 - 36.75 x = ?
Friday, October 21, 2011 at 5:47pm by Ms. Sue

PHYSICS
V = Vo + g*Tr = 0 14 - 9.8Tr = 0 9.8Tr = 14 Tr = 1.43 s. = Rise time. h = ho + Vo*Tr + 0.5g*Tr^2 hmax = 70 + (14*1.43 -4.9*1.43^2)=80 m. Above gnd. hmax = 0.5g*t^2 = 80 4.9t^2 = 80 t^2 = 16.33 Tf = 4.04 s = Fall time. Tr+Tf = 1.43 + 4.04 = 5.47 s. = Time to strike gnd. V=Vo + ...
Thursday, April 3, 2014 at 7:25pm by Henry

physics
Add the following two vectors: 300 i (the air speed of the plane); 100 cos26 i + 100 sin26 j (wind speed relative to ground) The sum is 389.0 i + 43.8 j That a means 389 mph velocity component in the east direction and 43.8 mph in the north direction. Take the square root of ...
Monday, June 2, 2008 at 9:05am by drwls

physics
1/do +1/di =1/f f= - 0.6 m (for diverging lens), do= 1.5 m 1/di=-1/do+1/f=-(1/1.5+1/0.6)=2.33 di= - 0.43 m (‘-‘ as the image is in front of the lens) Magnification M= - di/do=0.43/1.5=0.287 h=M•H=0.287•10=2.87 cm
Monday, January 28, 2013 at 3:00pm by Elena

physics
a. d = Vo*t + 0.5g*t^2 = 98 m. 0 + 4.9t^2 = 98 t^2 = 20 Tf = 4.47 = Fall time. V = Vo + g*t = 0 + 9.8*4.47 = 43.8 m/s.= Velocity @ 98 m. b. d = Vo*t + 0.5g*t^2 = 98 m. 43.8*t + 4.9t^2 = 98 4.9t^2 + 43.8t - 98 = 0 Tf = 1.85 s.
Thursday, September 12, 2013 at 6:56pm by Henry

MATH
What do you think? Remember that 0.43 is 43 hundredths.
Friday, August 27, 2010 at 4:15pm by Ms. Sue

trigonomety
A = 43 20/60 = 43.33 Deg.
Wednesday, February 8, 2012 at 1:15pm by Henry

math
(43/8) / (1/6) (43/8) * (6/1) = 258/8 = 32.25
Friday, May 4, 2012 at 11:32am by Ms. Sue

Algebra 8
What property is shown in the equation below? -43 ÷ (-1) = 43
Monday, September 22, 2008 at 8:56pm by Gabe

Algebra
the options where... 87, -28,-43, -43/5
Wednesday, May 19, 2010 at 8:13pm by Cody

Math
6 1/7 =43/7 Multiplicative inverse = 7/43
Monday, April 7, 2014 at 4:49pm by Ms. Sue

physics
First balance ...150................M.........200...... ...................^..................... ....10.........50.....x..........75...... second balance ...200................M.........150...... ..............^........................... ....10....43..........x..........75...
Friday, June 25, 2010 at 10:33pm by MathMate

math
8.60/0.2 = 43 minutes Add 0.43 to 3:30 to find when her call ended.
Tuesday, May 10, 2011 at 7:43pm by Ms. Sue

physical science
v = g t 10 = (1/2) g t^2 t^2 = 20/9.8 t = 1.43 seconds to fall so v = 9.8 *1.43 = 14 meters/ second
Monday, June 20, 2011 at 6:57pm by Damon

Stats
P(27chose 2) (43 choose 2) 27/43 * 26/42 = 702/1806 = .3887
Monday, October 21, 2013 at 12:19am by Kuai

Physical Science
(60 W•24hours •30 days)/1000=43.2 kW•h 43.2•0.1$=4.32$
Thursday, March 20, 2014 at 2:40pm by Elena

Math
I need help I'm suppose to pick a bird of my choice convert the weight into pounds and then find the wingspan. I'm not sure what the steps of the process are. An average bluejay weights .154 pounds, using the exponent equation L = 2.43*W^0.3326 What I have so far is L = 2.43*W...
Friday, November 30, 2007 at 9:40am by Alicia

Algebra (please help!)
n rows (n-16) seats/row n * (n-16) = 1161 n^2 - 16 n - 1161 = 0 well, I want factors of 1161 that differ by 16. I know sqrt 1161 = 34.07... so I geuss that around 27 would be a good guess and 27+16 = 43 and sure enough 43*27 = 1161 so (n-43)(n+27) = 0 n = 43 and the number of ...
Monday, May 18, 2009 at 3:58pm by Damon

Physics(Please help)
1) A force vector has a magnitude of 579 newtons and points at an angle 43o of below the positive x axis. Find the x scalar component and the y scalar component of the vector? For the x component I did 579cos(43) = 423.45 N. Is this correct? For the y component I did 579sin(43...
Friday, May 25, 2012 at 2:44pm by Hannah

Physics
At takeoff, his velocity is zero, so there is no centripetal acceleration in the vine direction. The acceleration will be initially in the direction perpendicular to the vine, along his trajectory. The component of his weight in that direction (M g sin 43) will equal M a, so a...
Thursday, May 27, 2010 at 11:57am by drwls

algebra
with V voters, poll returns .43 as an answer. So, using R as the real value, |R-.43| <= 0.04R
Wednesday, September 28, 2011 at 11:57pm by Steve

math
Jonah wants to add 43+19. He added 43+20. What step should he take next?
Wednesday, October 19, 2011 at 8:09pm by sandra

math
M - 1 = 43 M = 43 + 1 M = 44
Monday, September 12, 2011 at 8:14pm by Ms. Sue

algebra
12/43 - y = 1 y = -31/43
Monday, October 3, 2011 at 6:16pm by Steve

math/alegbra
Well for one thing, we know f(x) is equal to y. It is the original function. For f(x)=3x^2 -5 We want to find the y value when x=-4 So just plug in -4 for all the x's and get the y value. f(-4)=3(-4)^2-5 f(-4)=3(16)-5 f(-4)=48-5 f(-4)=43 f(-4)=43=the y value at x=-4 So for the...
Friday, October 26, 2007 at 9:21pm by Corin

Algebra
let the number of rows be x let the number of seats in each row be x-16 x(x-16) = 1161 x^2 - 16x - 1161 = 0 (x-43)(x+27) = 0 x = 43 or x = -27 but x > 0 x = 43 there are 43 rows with 27 seats in each
Sunday, May 9, 2010 at 10:23pm by Reiny

maths
in place value systems-eg: 2,43,500 - is it 2 lakh or 2 lakhs 43 thousand/thousands???? Are both acceptable?
Monday, June 23, 2008 at 7:55am by sims

Division
7 is "few than 8." 43/7 = 6 bags with one marble left over. Since 43 is a prime number, it cannot be done exactly.
Thursday, December 13, 2012 at 9:05pm by PsyDAG

stats
Are you studying Markov's chains? let's set up a transition matrix 33/87 6/87 43/87 5/87 let's multiply [0 1] by this matrix to get [ 43/87 5/87] (first number represents ontime-Upstate) so how about 43/87 or .4943 ? Not absolutely sure about this.
Wednesday, July 14, 2010 at 11:05pm by Reiny

Physics
b. To solve this problem, I'll assume the resistance of the bulb is linear and remains constant when 1.5 volts is applied. R = V/I = 2.4/0.7 = 3.43 Ohms = Resistance of each bulb. When 3 are connected in parallel, Req = 3.43/3 = 1.14 Ohms. I = V/Req = 1.5/1.14 = 1.31 Amps.
Thursday, May 3, 2012 at 10:40am by Henry

algebra
N = -2x^2 + 76x + 430 = 0. Solve, using the Quad. Formula and get: x = 43, and -5. Select + value of x: x = 43,000 cases.
Monday, July 11, 2011 at 11:01am by Henry

physics
Two positive charges of 5.43 µC each are 508 cm apart. Find the electric field midway between them. What is the magnitude of the electric field if one charge is positive and the other negative, both of magnitude 5.43 µC?
Thursday, March 3, 2011 at 8:30pm by Anonymous

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