Friday

April 18, 2014

April 18, 2014

Number of results: 109,976

**physics**

A large wooden wheel of radius R and the moment of inertia I is mounted on an axle so as to rotate freely. A bullet of mass m and speed v is shot tangential to the wheel and strike its edge, lodging in the wheel’s rim. If the wheel was originally at rest, what is its rotation ...
*Saturday, December 4, 2010 at 9:10am by Gee*

**Physics Help!**

It would be nice if you posted your three ways to calculate the quantity, and the values that you obtained. Moment of inertia =Σmr² In this case, the weight is all distributed at the rim, ignoring spokes, so 1.1 kg r²=0.15 kg-m² Solve for r.
*Thursday, November 5, 2009 at 6:35pm by MathMate*

**English**

1. I don't need the money at the moment. 2. He felt refreshed at the moment. 3. Can you lend me some money at the moment? (Are all correct? What is the meaning of 'at the moment'?)
*Sunday, April 12, 2009 at 9:53pm by John*

**physics**

Angular momentum = Iω kg-m²/s. ω=angular velocity in rad./s. I=moment of inertia =(1/2)Mr² M=total mass of air in kg. r=outside radius of hurricane, in m.
*Tuesday, October 26, 2010 at 3:34pm by MathMate*

**Physics**

torque = F*r = I*alpha where F = force, r = radius, I = moment of inertia, and alpha is angular acceleration. a) For a cylinder I = 1/2*m*r^2, where m is mass b) F*r = 1/2*m*r^2*alpha Substitute values from the problem to find m c) omega = alpha*t where omega is angular velocity
*Wednesday, December 5, 2012 at 9:06pm by Jennifer*

**physics**

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 210 N applied to its edge causes the wheel to have an angular acceleration of 1.161 rad/s2. (a) What is the moment of ...
*Wednesday, November 9, 2011 at 3:56pm by Anonymous*

**physics**

A large grinding wheel in the shape of a solid cylinder of radius 0.370m is free to rotate on a frictionless, vertical axle. A constant tangential force of 470 N applied to its edge causes the wheel to have an angular acceleration of 0.800 rad/s2. (a) What is the moment of ...
*Sunday, November 11, 2012 at 5:33pm by Anonymous*

**physics**

You never said the angle turned was 2 pi. You typed 45,,a Torque is force times lever arm (in this case, wheel radius) (iii) Angular momentum after time T is (Torque)*(Time) = (Moment of inertia)*(angular velocity)
*Tuesday, July 20, 2010 at 8:53am by drwls*

**physics**

A 4.4 diameter merry-go-round is rotating freely with an angular velocity of 0.63 . Its total moment of inertia is 1800 . Four people standing on the ground, each of mass 66 , suddenly step onto the edge of the merry-go-round.
*Friday, October 29, 2010 at 8:03pm by Anonymous*

**Physics**

No problem. For my question, I know the goal is to basically subtract the inertia's of the 3 holes from the whole disk's inertia, 0.5*MR^2, but I think what I'm stuck on is how to find that value, or relate it to what we know. The final inertia needs to be 0.81(0.5*MR^2). I'm ...
*Friday, November 2, 2012 at 6:29pm by John*

**Physics**

A diver can reduce her moment of inertia by a factor of about 3.5 when changing from a straight position to a tuck position. If she makes two rotations in 1.5s when in the tuck position, what is her rotational speed (rot/s) when in the straight position?
*Tuesday, April 20, 2010 at 10:44pm by Bella*

**physics**

The decrease in potential energy equals the increase in kinetic energy, most of which is rotational KE. First compute the moment of inertia of the yo-yo, I. If it falls a distance L (which is 1.1 m in this case) then M g L = (1/2) I w^2 + (1/2) M V^2 The angular rotation rate ...
*Monday, November 29, 2010 at 2:05am by drwls*

**physics**

A 4.0 kg pulley of radius 0.15 m is pivoted about an axis through its center. What constant torque is required for the pulley to reach an angular speed of 25 rad/s after rotating 6.0 revolutions, starting from rest? What moment of inertia do I use to figure our the torque?
*Sunday, December 12, 2010 at 12:28pm by erik*

**Physics**

A small circular object with mass m and radius r has a moment of inertia given by I = cmr2. The object rolls without slipping along the track shown in the figure. The track ends with a ramp of height R = 3.0 m that launches the object vertically. The object starts from a ...
*Thursday, March 29, 2012 at 10:36pm by Adam*

**Physics**

Use conservation of angular momentum. Assume the outstretched arms have a moment of inertia contribution of Iarms2 = (1/3) M(arms) L^2, where L = 1.80m m. [(Ibody + Iarms1)w1] = [(Ibody + Iarms2)w2] Solve for w2
*Wednesday, November 7, 2007 at 5:38pm by drwls*

**Physics**

A non-rotating cylindrical disk of moment of inertia I is dropped onto an identical disk rotating at angular speed w. Assuming no external torques, what is the final common angular speed of the two disks?
*Wednesday, April 21, 2010 at 9:39am by Aja *

**Physics**

A person on a rotating stool with arms stretched out rotates at an angular speed of 5.00 rad/s. On bringing in his arms, the angular speed increases to 7.50 rad/s. By what factor does the moment of inertia change?
*Monday, November 4, 2013 at 1:38pm by Mikhail*

**Physics**

Two particles with masses 3.1 kg and 6.6 kg are connected by a light rod of length 4 m. Find the moment of inertia of the system about an axis perpendicular to the rod and passing through: a) the midpoint of the rod; b) the center of mass of the system of particle:
*Monday, November 28, 2011 at 3:48pm by kole*

**physics please help**

First compute the moment of inertia about a vertical axis of symmetry. Then apply the parallel axis theorem. The answer will depend upon where the "horizontal bar" of the letter "A" is placed, and whether the 18 cm or the 12 cm is the vertical dimension.
*Monday, December 8, 2008 at 2:19am by drwls*

**physical**

Fiend moment of inertia of a circular ring about a tangent to the ring the lying in its planc
*Sunday, May 13, 2012 at 1:10pm by Md jawed*

**science**

earth and the moon are kept in their respective orbits due to the influence of ? a) inertia b) gravity c) both inertia and gravity d) neither inertia and gravity
*Sunday, November 10, 2013 at 2:34pm by victoria*

**Physics**

A constant torque of 22.9 N·m is applied to a grindstone whose moment of inertia is 0.168 kg·m2. Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 17.1 rev, assuming it started from rest. Answer in units of rev/s
*Tuesday, April 2, 2013 at 6:18pm by dallas*

**physics**

A fireman tosses his 0.863-kg hat onto a peg, where it oscillates as a physical pendulum. If the center of mass of the hat is 8.32 cm from the pivot point, and its period of oscillation is 0.762 s, what is the moment of inertia of the hat about the pivot point?
*Wednesday, November 17, 2010 at 8:54pm by Anonymous*

**Physics (Mechanics)**

A uniform plate of height H= 0.69 m is cut in the form of a parabolic section. The lower boundary of the plate is defined by: y= 1.10x^2. The plate has a mass of 5.62 kg. Find the moment of inertia of the plate about the y-axis. Alright, I've done this so far: So I figured I ...
*Friday, March 21, 2008 at 10:04pm by Kara*

**Physics 203 ( College)**

Four particles, one at each of the four corners of a square with 2.5-m-long edges, are connected by mass less rods. The masses of the particles are m1 = m3 = 2.0 kg and m2 = m4 = 7.0 kg. Find the moment of inertia of the system about the z axis.
*Monday, April 4, 2011 at 11:58am by Kayla*

**school**

Two disks are spinning freely about axes that run through their respective centres (see figure below). The larger disk (R1 = 1.42 m) has a moment of inertia of 1180 kg · m2 and an angular speed of 4.0 rad/s. The smaller disk (R2 = 0.60 m) has a moment of inertia of 906 kg · m2...
*Wednesday, October 30, 2013 at 10:35am by Aaron*

**Physics**

If you suspended it from the middle, the period would be infinite because the rule would balance and their would be no torque to pull it back into a vertical position when displaced. They just hung the ruler from the 20 cm mark to make it more fun than hanging from the end. It...
*Monday, December 15, 2008 at 10:41pm by Damon*

**Physics please help!!**

The moment of inertia of a uniform rod, about a line through the center and perpendicular to the rod, is I = M L^2/12 The kinetic energy of the rotating rod is (I/2)* w^2 w = 7.27 rad/s L = 0.529 m M = 0.478 kg Calculate that kinetic energy. It equals the work required.
*Thursday, March 10, 2011 at 6:15pm by drwls*

**physics**

A typical ten-pound car wheel has a moment of inertia of about 0.35 kg*m^2. The wheel rotates about the axle at a constant angular speed making 45.0 full revolutions in a time interval of 7.00 sec . What is the rotational kinetic energy of the rotating wheel?
*Monday, October 26, 2009 at 2:55am by Anonymous*

**physics**

A typical ten-pound car wheel has a moment of inertia of about 0.35 kg*m^2. The wheel rotates about the axle at a constant angular speed making 45.0 full revolutions in a time interval of 7.00 sec . What is the rotational kinetic energy of the rotating wheel?
*Monday, October 26, 2009 at 3:09am by Anonymous*

**Physics**

Aristotle did not understand inertia at all. Galileo did. The word is of Latin origin. Greeks never used it The word inertia also fits well in your blank space
*Friday, October 2, 2009 at 9:33pm by drwls*

**Physics**

A skater spinning with angular speed of 1.5 rad/s draws in her outstretched arms thereby reducing her moment of inertia by a factor a 3. a) Find her angular speed. b)What is the ratio of her final angular momentum to her initial angular momentum? c)Did her mechanical energy ...
*Thursday, December 2, 2010 at 1:17pm by Tarren*

**Physics**

The moment of inertia of an asteroid rotating about its own axis is 5.00 ! 10 4 kg"m2. Its angular velocity is 40.0 rad/s. If a force acts on the asteroid for 0.100 s, increasing the angular velocity to 48.0 rad/s, find its magnitude
*Friday, December 9, 2011 at 8:06am by HELP*

**physics**

Three identical thin rods, each of length L and mass m, are welded perpendicular to one another as shown below. The assembly is rotated about an axis that passes through the end of one rod and is parallel to another. Determine the moment of inertia of this structure. (Answer ...
*Thursday, November 6, 2008 at 10:05pm by sara*

**Physics**

The object of a flywheel is to resist changes in angular momentum. That means you want the largest possible moment of inertia for a given mass. That means you put as much mass out at the maximum radius as you can. therefore you have a thin web, just enough for needed strength...
*Friday, June 18, 2010 at 8:26pm by Damon*

**Physics**

A dumbbell consists of two equal compact masses of 2 kg each, connected by a massless rod of length 0.8 metres. What is the moment of inertia of the dumbbell about an axis through the centre of, but perpendicular to, the rod? could someone just tell me how to get started on ...
*Thursday, July 29, 2010 at 4:58am by Tim*

**physics**

A turntable with a moment of inertia of 0.014 kg*m2 rotates feely at 2.7 rad/s. A circular disk of mass 500 g and diameter 22 cm, and initially not rotating, slips down a spindle and lands on the turntable. a) Find the new angular speed. rad/s b) what is the change in kinetic...
*Saturday, December 11, 2010 at 6:10pm by applebottom*

**physics**

pls explain this to me ? "momentum is inertia....but inertia is NOT momentum" :S confused
*Sunday, December 9, 2012 at 4:54pm by Anya *

**Physics**

You doubled moment of inertia. Angular momentum total must be the same. If you keep angular momentum the same, then angular speed must be 1/2 the original. Rotational energy is not conserved.
*Wednesday, April 21, 2010 at 9:39am by bobpursley*

**physics**

A cylinder of mass M=58 kg, radius R=1.3 m and moment of inertia I=(1/2)MR2 is initially rotating around its central axis with an angular velocity ωi= 1.8 rad/s. A tangential force F of constant magnitude applied to the edge of the cylinder during 5.9 s brings it to rest...
*Sunday, March 25, 2012 at 9:48pm by katie*

**applied mechanics**

How do we calculate the "radius of gyration" of a 500g steel rod spinning at 300 RPM and having a lenght of 30cm? We need this to find the moment of Inertia... don't we?
*Thursday, May 7, 2009 at 9:48am by Henri*

**Mechanics**

An aeroplane propeller has a 100kg and radius of gyration of 0.6cm.find its moment of inertia.How large a torque is required to give it angular acceleration of 20rad/sec^2
*Thursday, February 14, 2013 at 1:25pm by Precious*

**Mechanics**

An aeroplane propeller has a 100kg and radius of gyration of 0.6cm.find its moment of inertia.How large a torque is required to give it angular acceleration of 20rad/sec^2
*Thursday, February 14, 2013 at 1:25pm by Precious*

**Mechanics**

An aeroplane propeller has a 100kg and radius of gyration of 0.6cm.find its moment of inertia.How large a torque is required to give it angular acceleration of 20rad/sec^2
*Thursday, February 14, 2013 at 1:27pm by Precious*

**Mechanics**

An areoplane propeller has a 100kg and radius of gyration of 0.6cm.find its moment of inertia.how large a torque is required to give it angular acceleration of 20rad/sec^2
*Thursday, February 14, 2013 at 1:34pm by Precious*

**Physics**

21 rpm = 2.20 rad/s Angular deceleration rate required = alpha = 2.2/6.0 = 0.367 rad/s^2 Torque required = I*alpha where I is the moment of inertia. I will leave you to calculate that. First you need to locate the center of mass and the distances of the masses from that center.
*Monday, January 31, 2011 at 11:23pm by drwls*

**Physics**

zero interia is inertia. Have you ever tried yanking a tablecloth from beneath the table setting without moving the setting? The law of inertia applied (hopefully).
*Sunday, September 21, 2008 at 7:35pm by bobpursley*

**Physics**

In the manufacture of a cam, a uniform solid cylinder of radius R is first machined. Then an off-center hole of radius R/2 is drilled, parallel to the axis of the cylinder, and centered at a point a distance R/2 from the center of the cylinder. Then cam, of mass M, is then ...
*Wednesday, May 16, 2007 at 3:15am by Lancelot*

**physics**

A wheel rotates without friction about a stationary horizontal axis at the center of the wheel. A constant tangential force equal to 83.N is applied to the rim of the wheel. The wheel has radius 0.110m . Starting from rest, the wheel has an angular speed of 14.6rev/s after 3....
*Friday, May 3, 2013 at 8:47pm by amy*

**physics**

What's inertia? Inertia is the tendency of an object at rest to remain at rest; or the tendency of an object to continue moving if it is moving. In plain language, it's the tendency of an object to want to continue doing whatever it's doing. I had a definition years ago given ...
*Thursday, February 8, 2007 at 12:58pm by Jacob*

**Physics HELP!!!**

A ball (radius 0.2 m) is rolling on level ground toward an incline. If its velocity is 3 m/s, to what maximum height above the ground does it roll up the incline? The ball is a hollow sphere with a moment of inertia I=(2/3)mr2 (m is the mass of the ball, r its radius).
*Wednesday, October 27, 2010 at 8:51pm by Alex*

**Physics**

Ignore the pulley's moment of inertia (since they don't tell you its radius and mass). Let T be the unknown tension on both sides. With two equations, the variable T can be eliminated to solve for the acceleration, which is the same for both masses. We are eager to critique ...
*Wednesday, March 24, 2010 at 10:52am by drwls*

**physics**

Did you get the torque correct in part (1) ? It equals the angular acceleration divided by the moment of inertia, including that due to the children. The force required at the edge equals the required torque divicded by the radius, 3.0 m. You need to say what your units of ...
*Thursday, June 21, 2012 at 12:47am by drwls*

**biomechanics**

If a kicker produces a torque of 8Nm with her muscles and the resulting angular acceleration of her leg is 20rad/m2, what is the moment of inertia of her leg?
*Tuesday, April 6, 2010 at 7:28pm by Jane*

**Oh my - sign !**

The inner radius I assume means that the axle does not spin. Therefore your moment of inertia has a negative, not positive sign I = 8*(0.5^2 - 0.3^2)/2) I =.64 kgm^2
*Sunday, February 26, 2012 at 4:35pm by Damon*

**Physics**

The moment of inertia of a solid uniform sphere of mass M and radius R is given by the equation I=(2/5)MR2 . Such a sphere is released from rest at the top of an inclined plane of height h, length L, and incline angle è. If the sphere rolls down the plane, find its speed at ...
*Thursday, April 7, 2011 at 2:44pm by Anonymous*

**Physics**

The density of the Earth, at any distance r from its center, is approximately (14.2-11.6(r/R)*10^3) Kg/m^3, where R is the radius of the Earth. Show that this density leads to a moment of inertia I = 0.330MR2 about an axis through the center, where M is the mass of the Earth. ...
*Sunday, November 18, 2012 at 2:23pm by Avery*

**physics**

I still don't get it.Moment of inertia of the yo-yo is 1/2 mr^2: 1/2(.053kg)(.0365^2) + 1/2(.0052kg)(.006^2) which equals to 3.54*10^-5 so i plugged that into = square root of (2*9.8*1.1)/ (1 + (3.54*10^-5/(mr^2)) and i got something like 4.6 which is not a correct answer. Can...
*Monday, November 29, 2010 at 2:05am by Sasha*

**Physics- Angular Momentum**

The moment of inertia of the rod rotating about its center is M*L^2/12 When the idential masses m are at radius R, the moment of intertia due to their masses is 2*m*R^2 The total angular momentum remains unchanged. Let w1 be the initial angular velocity. A) When the masses ...
*Tuesday, December 28, 2010 at 3:22pm by drwls*

**Physics**

A helicopter has two blades (see figure), each of which has a mass of 220 kg and can be approximated as a thin rod of length 6.7 m. The blades are rotating at an angular speed of 45 rad/s. (a) What is the total moment of inertia of the two blades about the axis of rotation? (a...
*Wednesday, October 27, 2010 at 1:48pm by Claire*

**physics**

A helicopter has two blades (see figure), each of which has a mass of 270 kg and can be approximated as a thin rod of length 6.7 m. The blades are rotating at an angular speed of 52 rad/s. (a) What is the total moment of inertia of the two blades about the axis of rotation? (a...
*Tuesday, July 16, 2013 at 3:37pm by samon*

**physics**

Angular momentum is L = I•ω, where I = m•R² is the moment of inertia of the material point. L = I•ω = m•R²• ω = =0.2 (kg)•(1.45)² (m²) •13 (rad/s) = =5.47 kg•m²/s.
*Sunday, May 6, 2012 at 3:44pm by Elena*

**Physics**

A uniform lamina consists of a disc with radius R with a disc of radius r cut off from its centre, with r < R. The total mass of the object is M. Find the moment of inertia when the lamina rotates about an axis perpendicular to the lamina, thought its centre.
*Friday, March 18, 2011 at 7:56am by Kagiso Setuke*

**math**

Find the volume of the region obtained by revolving the area below about the line x=3. y = x3, x=2, y=0 Find the moment of inertia of this solid of revolution.
*Thursday, March 13, 2014 at 11:51pm by Anonymous*

**physics**

A circular blade on a radial arm saw is turning at 257 rad/s at the instant the motor is turned off. In 17.0 s the speed of the blade is reduced to 90 rad/s. Assume the blade to be a uniform solid disk of radius 0.170 m and mass 0.400 kg. Find the net torque applied to the ...
*Monday, June 4, 2007 at 12:51pm by Jeannine*

**Physics. PLEASE HELP!!**

A 1.2 m diameter wagon wheel consists of a thin rim having a mass of 11 kg and six spokes, each with a mass of 1.1 kg. Find the moment of inertia of the wagon wheel for rotation about its axis. Answer in units of kg · m2
*Friday, April 20, 2012 at 12:35pm by Amber*

**physics**

A 350-g air track cart on a horizontal air track is attached to a string that goes over a pulley with a moment of inertia of 6.00 × 10-6 kg·m2 and a radius of 1.35 cm. The string is pulled vertically downward by a force of 2.50 N. What is the acceleration of the cart?
*Thursday, April 11, 2013 at 11:11am by Anonymous*

**physics**

acceleration = v^2/R side force = m v^2/R overturning moment = m v^2 h/R righting moment = m g d/2 so m g d/2 = m v^2 h/R v^2 = g d R /(2h) v = sqrt [ g d R / (2 h) ]
*Thursday, November 20, 2008 at 12:57am by Damon*

**physics**

Hi, can someone please help with this question. A thin, uniform rod is bent into a square of side length a. If the total mass is M, find the moment of inertia about an axis through the center and perpendicular to the plane of the square. Use the parallel-axis theorem. Express ...
*Saturday, October 18, 2008 at 10:49am by Mary*

**physics please help**

The initial kinetic energy of the bar, which is (1/2) I wo^2 = (1/2)*M (L^2/3)*(vo/L)^2 = (1/6)*M vo^2 Must equal the increase in potential energy in the upside-down position, which is M g L since the center of mass raises by an amount L. I is the moment of inertia of the rod ...
*Saturday, November 27, 2010 at 6:14pm by drwls*

**Physics**

Convert 1800 rpm to radians per second and call it w. (It texts, it's usually a Greek lower case omega) The angular momentum is I w, where I is the moment of inertia. Use units of kg m^2/s For a solid cylinder of mass M and radius R, I = (1/2) M R^2. The torque L required to ...
*Thursday, December 10, 2009 at 9:29pm by drwls*

**physics**

The total kinetic energy is the sum of Translational KE = (1/2)MV^2 = 39.5 V^2, and Rotational KE = 2*(1/2)*I*w^2 = I*V^2/R^2 = 0.978 V^2 I is the moment of inertia of a single wheel. The fraction of the energy that is rotational is 0.978V^2/(0.978+39.5)V^2 = 0.0243 Note that ...
*Tuesday, July 10, 2012 at 5:23pm by drwls*

**physics**

A 650g ball on the end of a light rod is rotated in a horizontal circle of 1.2m radius.Calculate the torque needed to keep the ball rotating if the air resistance exerts a force of .02N on the ball. Ignore the moment of inertia and the air resistance of the rod.
*Sunday, March 27, 2011 at 4:45pm by Mark*

**physics**

A 44.8- child is standing on the outer edge of a merry-go-round that has moment of inertia 981 and radius 2.40 . The entire system is initially rotating at 0.180 . Find the angular velocity if the child moves to a final position 1.10 from the center of the merry-go-round.
*Sunday, September 30, 2012 at 6:55pm by Anonymous*

**Physics**

In the device a 50g mass is hung from a pulley and released. A disk is placed on the platform. The platform has a radius of 5cm. The disk and platform go from rest to an angular velocity of 8.5rad/s in 2.5 seconds. What is the moment of inertia of the disk? What is its mass? ...
*Sunday, April 6, 2014 at 4:56pm by Joe*

**Physics**

A pair of constant forces of magnitude F = 11.1 N is applied to opposite sides of the axle of a top, as shown in the figure. The diameter of the axle is d = 8.67 mm. The angle è, which has a value of 36.1°, describes the steepness of the top's sloping sides. The moment of ...
*Tuesday, December 10, 2013 at 5:50pm by Physics*

**Physics**

In an Atwood machine, one block has a mass of M1 = 520 g and the other has a mass of M2 = 320 g. The frictionless pulley has a radius of 4.6 cm. When released from rest, the heavier block moves down 51 cm in 1.00 s (no slippage). What is the tension T1? Find the pulley's ...
*Saturday, November 5, 2011 at 3:23pm by Morgan*

**Physics **

In an Atwood machine, one block has a mass of M1 = 520 g and the other has a mass of M2 = 320 g. The frictionless pulley has a radius of 4.6 cm. When released from rest, the heavier block moves down 51 cm in 1.00 s (no slippage). What is the tension T1? Find the pulley's ...
*Saturday, November 5, 2011 at 11:10pm by Spencer*

**Science**

A torque of 60 N*m acts on a wheel of moment of inertia 30 kg*m^2 for 5 s and then is removed. a) What is the angular acceleration of the wheel? b) How many revolutions does it make in 15 s if it starts at rest?
*Wednesday, November 30, 2011 at 5:44pm by John*

**science**

You probably mean to ask: "Find the moment of inertia of the system about an axis passing through the center.." Each mass is R = sqrt2 meters from the center. I = (1 + 2 + 3 + 4)*R^2 = 20 kg*m^2
*Friday, August 17, 2012 at 3:55am by drwls*

**mechanics**

a fly wheel of mass 66kg and 2m radius makes 55rpm.assuming mass is concentrated at the rim.calculate the angular velocity and moment of inertia
*Sunday, October 7, 2012 at 12:11pm by Anonymous*

**calculusiii**

Let S be the part of the sphere x^2 + y^2 + z^2 = 25 that lies above the plane z = 4. Let S have constant density k. (a) Find the center of mass. (b) Find the moment of inertia about the z-axis.
*Sunday, April 28, 2013 at 9:43pm by Anonymous*

**physics**

Moment of inertia of the board respectively the pivot point is Io = m(L^2 + W^2)/12 = 9.4(4.5^2+0.3^2)/12 = 15.93 kg•m^2, Moment of inertia of the system (board+2 point mass-ñhildren) respectively the pivot point is I = Io + 2mR^2 = 15.93 + 2•11•(4.5/2)^2 = 127.305 kg•m^2 An ...
*Friday, March 16, 2012 at 10:33pm by Elena*

**physics**

A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is 4.6 kg m^2. A second student tosses a 1.5 kg mass with a speed of 2.9 m/s to the student on the stool, who catches it at a distance of 0.40 s from the...
*Thursday, March 17, 2011 at 6:03pm by nikki*

**physics**

A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is 4.6 kg m^2. A second student tosses a 1.5 kg mass with a speed of 2.9 m/s to the student on the stool, who catches it at a distance of 0.40 s from the...
*Friday, March 18, 2011 at 4:45pm by nikki*

**Physics**

(a) Calculate the kinetic energy that the earth has because of its rotation about its own axis. Assume that the earth is a uniform sphere and that its path around the sun is circular. For comparison, the total energy used in the United States in one year is about 9.33e9 Joules...
*Sunday, November 2, 2008 at 10:53am by Kyle*

**Inertia**

The moment of Inertia about the center of a thin rod of length L is .. I=1/12 M L^2 Here the length is a/4, mass is M/4 I=1/12 (M/4)(a^2/16) or you can calculate that. Now, the Parallel axis theorm, the displacement is 1/2 a side, or a/8 The new I is I=Icm + Mass*d^2 = above I...
*Monday, November 3, 2008 at 1:40pm by bobpursley*

**Physics**

I w where I is moment of inertia and w is radians/second = 2 pi/period period = 1 minute = 60 seconds I = (1/3) M L^2 = (1/3)(.020 Kg)(.25 m)^2 = 4.17*10^-4 4.17 *10^-4 * 2 * pi / 60 = 4.36 * 10^-5
*Wednesday, June 29, 2011 at 6:21pm by Damon*

**physics**

A runner of mass m = 48 kg and running at 3.7 m/s runs as shown and jumps on the rim of a playground merry-go-round which has a moment of inertia of 378 kg·m2 and a radius of 2 meters. Assuming the merry-go-round is initially at rest, what is its final angular velocity to ...
*Tuesday, December 10, 2013 at 3:33pm by Anonymous*

**PHYSICS**

This entirely depends on your definition of inertial. If by inertia you mean mass, the answer is obvious. Most in science mean mass when inertia is used, but sometimes the meaning is different.
*Sunday, December 19, 2010 at 6:41pm by bobpursley*

**physics**

Compute the moment of inertia of each disc using the formula I = (1/2) M R^2 For example, for the initially rotating disc, I1 = (1/2)(1.6)(0.63)^2 = 0.318 kg m^2 I2 = (1/2)(0.46)(0.38)^2 = ____? Then apply the law of conservation of angular momentum in this form: I1*w1 = (I1...
*Wednesday, June 9, 2010 at 4:26am by drwls*

**Physics ang. momentum**

A diver can reduce her moment of inertia by a factor of about 3.5 when changing from the straight position to the tuck position. If she makes 2.0 rotations in 1.5s when in the tuck position, what is the percent change in her kinetic energy as she changes to the straight ...
*Monday, December 7, 2009 at 12:29am by Taylor*

**Physics (please help!!!!)**

A thin uniform rod (length = 1.3 m, mass = 4.1 kg) is pivoted about a horizontal frictionless pin through one of its ends. The moment of inertia of the rod through this axis is 1/3 m L2. The rod is released when it is 55° below the horizontal. What is the angular acceleration ...
*Friday, March 25, 2011 at 7:36pm by HELP!!!!*

**Physics**

A thin uniform rod (length = 1.3 m, mass = 3.2 kg) is pivoted about a horizontal frictionless pin through one of its ends. The moment of inertia of the rod through this axis is (1/3)mL2. The rod is released when it is 50° below the horizontal. What is the angular acceleration ...
*Tuesday, June 19, 2012 at 10:57am by Tim*

**physics**

a wheel radius 0.25 m is mounted on a frictionless horizontal axle. the moment of inertia of the wheel about the axis is 0.040. a light cord wrapped around the wheel supports the 0.50 kg of box. the wheel is released from the rest. what is the magnitude of acceleration of the ...
*Sunday, April 28, 2013 at 10:22pm by sam*

**physics**

Two objects of equal mass are on a turning wheel. Mass 1 is located at the rim of the wheel while mass 2 is located halfway between the rim and the axis of rotation. The wheel is rotating with a non-zero angular acceleration. For each of the following statements select the ...
*Tuesday, March 20, 2012 at 9:26pm by Miriam*

**Physics**

Two objects of equal mass are on a turning wheel. Mass 1 is located at the rim of the wheel while mass 2 is located halfway between the rim and the axis of rotation. The wheel is rotating with a non-zero angular acceleration. For each of the following statements select the ...
*Wednesday, March 21, 2012 at 7:35pm by Miriam*

**Physics**

acceleration depends on force, and the amount of inertia. On the rock with twice the force, it also has twice the inertia. a=F/m
*Wednesday, July 13, 2011 at 1:25am by bobpursley*

**rotational motion physics**

A 3.7 m diameter merry-go-round is rotating freely with an angular velocity of 0.63 rad/s. Its total moment of inertia is 1600 kg\cdot m^2. Four people standing on the ground, each of mass 70 kg, suddenly step onto the edge of the merry-go-round.
*Saturday, November 19, 2011 at 12:20am by David colon*

**science**

it is the first law of motion because inertia is acting on the toy truck is experiencing inertia. Newton's first law is called the law of inertia.
*Wednesday, June 3, 2009 at 4:19pm by brittany c*

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