Thursday

April 17, 2014

April 17, 2014

Number of results: 108,613

**Physics: Buoyancy**

When submerged, the buoyancy force equals the weight of water being lifted with the ship. Therefore the cable tension force is the hull Weight, M g = 2.25*10^5 Newtons
*Sunday, January 27, 2013 at 11:36pm by drwls*

**physics**

You cannot solve for the mass with only the information provided. You also need to know the fluid dynamic resistance (drag) and the buoyancy force. They depend upon size, velocity and volume. rope tension = M g + Ma + Drag - Buoyancy > 22 N
*Sunday, April 5, 2009 at 4:37am by drwls*

**physics-buoyancy**

Use Archimedes' law of buoyancy. - to calculate what fraction of the volume of an iceberg floating in the ocean is above the water level. -how many 20kg penguins can be supported by a 1000 cubic meter iceberg that is on the verge of being completely submerged?
*Sunday, May 8, 2011 at 11:55pm by jen*

**Physics**

(a) Get the Volume by using V = Weight/(Density)= M g/(10.17*10^3 kg/m^3) Ignore the buoyancy effect of air; it is negligible. You get V = 0.043 m^3 (b) and (c) look the same to me. The effective density in water (with buoyancy force subtracted) is 9.17*10^3 kg/m^3. Repeat (a...
*Wednesday, December 12, 2007 at 12:59am by drwls*

**physics**

a) The probably want you to use Force = Mass* aaceleration to get the net force on the balloon, and then use Net Force = Buoyancy - Weight to get the buoyancy force. Once you have that, you can get the volume of the balloon using Archimedes Principle. This approach neglects ...
*Wednesday, September 1, 2010 at 11:28pm by drwls*

**physics-buoyancy**

physics-buoyancy - bobpursley, Monday, May 9, 2011 at 6:12am you need the density of ice, and the density of sea water. abbreviate these as di, and ds weight of iceberg: di*VolumeIce*g weight of displaced seawater: ds*VolumeIce*k*g where k is a fraction Archemedes says these ...
*Sunday, May 8, 2011 at 11:55pm by bobpursley*

**physics**

first calculate the buoyancy of 80% of a physics student. Mass of student = 80 kg density of student = 1040 kg/m^3 volume of student = 80/1040 = .0769 m^3 buoyancy of 80% of student = 1000 g .8 .0769 = 61.54 g Newtons so we need a force of 80 g - 61.54 g Newtons up from the ...
*Wednesday, January 4, 2012 at 7:06am by Damon*

**physics**

300 N (if you don't take into account the buoyancy force in the air)
*Monday, May 7, 2012 at 5:57pm by Elena*

**Physics**

The buoyancy force equals the weight of the fluid displaced. That is what the principle says.
*Wednesday, November 10, 2010 at 10:17pm by drwls *

**physics help please...**

I used the difference in wood and water density to get the net buoyancy.
*Monday, December 20, 2010 at 7:05pm by Damon*

**Physics**

can you use principle of density and buoyancy to explain how a cartesian diver works?
*Sunday, May 6, 2012 at 12:09am by sachi*

**Physical Science**

http://en.wikipedia.org/wiki/Buoyancy
*Wednesday, April 15, 2009 at 8:28pm by DrBob222*

**physics**

For floating the buoyancy force F has to be equal to mg F = Mg = DVg, where D is the density of water. Then mg = DVg V=m/D=80/1000 = 0.08 m^3
*Tuesday, March 27, 2012 at 1:30pm by Elena*

**PHYSICS**

Fish achieve neutral buoyancy (so they don't have to swim constantly to stay in place) via a swim bladder. A swim bladder is a little internal sack that they can inflate/deflate with air, which changes their volume but not their total mass. To see how this allows them to ...
*Monday, October 21, 2013 at 9:36am by Saiba*

**Physics**

Let P = 5.5 N, G= 3.3 N Buoyancy force F= P - G or according to the definition F= Mg= DVg. where D is the density of water. P - G = DVg, V = (P G)/Dg =(5.5-3.3)/10009.8 =2.2410^-4 m^3
*Sunday, March 18, 2012 at 12:05pm by Elena*

**physics**

The weight of the block is 15 N. If the scale says 11.8 N, there must be a buoyancy force of 3.2 N, not matter what the fluid densty or fractional immersion is.
*Tuesday, January 19, 2010 at 11:25pm by drwls*

**physics**

Determine the buoyant force a balloon as a funtion of depth. At what depth does the buoyancy occur
*Monday, March 21, 2011 at 6:25pm by Rehman*

**Physics: Buoyancy**

bouyancy=MassSteel/density steel * density water tension=23000kg-bouyancyabove
*Sunday, January 27, 2013 at 11:40pm by bobpursley*

**Physics**

The buoyancy force equals the weight of 125 cm^3 of water. Multiply that mass (0.125 kg) by g.
*Tuesday, November 27, 2012 at 7:03am by drwls*

**physics**

The net buoyancy force on a 2/3 full cylinder of water will depend upon the weight of the empty cylinder, which is not specified.
*Tuesday, August 2, 2011 at 1:07am by drwls*

**physics**

Let B = the buoyancy force and M = the initial total mass. Let m be the ballast mass released M g - B = M*1.2 m/s^2 (M-m)g -B = -M*1.2 m/s^2 Solve for m. m g = M*2.4m/s^2 m/M = 2.4/g m = 0.245 M = 49 kg
*Wednesday, March 2, 2011 at 3:10pm by drwls *

**Physics**

A cubical object of sides 5 cm is immersed completely in water. What is the force of buoyancy on the object? (Assume g = 10 m/s2)
*Tuesday, November 27, 2012 at 7:03am by Mark*

**physics**

Let the length above the surface of the water is «x, a =0.120 m, ρ1/ρ2 = 0.9. Since the density of water is ρ2 = 1000 kg/m³, the density of wood is ρ1 = 900 kg/m³. mg = F(buoyancy force), ρ1Vg = ρ2V1 g ρ1a³g = ρ2a...
*Tuesday, May 1, 2012 at 10:35am by Elena*

**simple physics.....**

Steve is right if the basket is above the ocean water level. If the basket is submerged, buoyancy forces reduce the force required.
*Tuesday, March 12, 2013 at 1:58am by drwls*

**physics**

The 2.5 N reduction is due to buoyancy, which equals the paperweight volume multiplied by the weight density of water, which is 9810 N/m^3. Therefore V = 2.5/9810 = 0.00025 m^3 = 250 cm^3
*Friday, December 11, 2009 at 11:31pm by drwls*

**physics**

The buoyancy force on the 490 balloon is F = 6kN , and the air resistance is F_D = (100v)N, where is in m/s. Determine the terminal or maximum velocity of the balloon if it starts from rest. vmax = ?
*Tuesday, March 8, 2011 at 4:28am by Roshni*

**physics**

This is my lab project and i need help in how to start to solve this problem. Determine the buoyant force on a balloon(filled with air) as a function of depth. At what depth does neutral buoyancy occur.
*Friday, March 18, 2011 at 10:29am by ami*

**Physics (Buoyancy)**

A Cuboid with lenght as 6m and breadth as 3m, is floating in a lake. A man comes and sits on it and it sinks 1cm, then find the weight of the man. (Take g=10 m/s -2)
*Thursday, March 14, 2013 at 7:05am by Krishnam Kumawat*

**Physics (Buoyancy)**

weight of man=weight of water displaced = 6*3*.01* density water* g = .18m^3*1E3Kg/m^3*9,8 m/s^2 = .18*E3*9.8 Newtons
*Thursday, March 14, 2013 at 7:05am by bobpursley*

**physics**

Let that required force be F. F + M*g = (1/6) pi*D^3* 1000 kg/m^3*g The term on the right is the buoyancy force. Solve for F in Newtons. g is the acceleration of gravity, 9.8 m.s^2 M = 0.523 kg D = 0.217 m
*Monday, August 6, 2012 at 11:34pm by drwls*

**physics**

Vb = 4kg * 1m^3/4000kg = 0.001 m^3. = Vol. of the ball. Fb = mg = (V*D)*g. Fb = 0.001m^3 * 1000kig/m^3 * 10 = 10 N. = Force of Buoyancy.
*Tuesday, October 23, 2012 at 11:45am by Henry*

**physics**

a ball of mass of 4kg,of density 4000kg/m3 is completely immersed in water of density 1000kg/m3.find the force of buoyancy.[g=10m/s2]
*Tuesday, October 23, 2012 at 11:45am by keerthiga*

**physics**

density of Al = 2.7*10^3 kg/m^3 weight = m g = 89 N so m = 89 N /9.8 m/s^2 = 9.08 kg mass = density*volume so volume = mass/(2.7 *10^3) so volume = 9.08 /(2.7*10^3) = 3.36*10^-3 m^3 density of water = 10^3 kg/m^3 buoyancy = volume * density of water * g = 3.36*10^-3*10^3 * 9.8...
*Wednesday, November 25, 2009 at 7:42pm by Damon*

**Physics - Buoyancy**

well, it has .3N of bouyancy. that is equivalent to what volume of water? .3=densitywater*g*volume solve for volume then density= weight/volume=20.3/volume and specfic gravity= denstiy/denstiywater.
*Thursday, November 11, 2010 at 12:09pm by bobpursley*

**physics**

It is the question if you say it is. Partially submerging the copper object will reduce the tension in the steel wire. There will be a buoyancy force equal to half the volume of the copper object multiplied by the density of water. Let V be the volume of the copper and g be ...
*Wednesday, February 16, 2011 at 11:42pm by drwls*

**2nd grade**

What is importance of AIR in buoyancy?
*Friday, January 8, 2010 at 1:12am by manahil*

**science**

3. (Use buoyancy to help raise the empty tank.)
*Wednesday, May 12, 2010 at 1:36am by drwls*

**asap science**

Buoyancy pushes an object upward.
*Thursday, February 6, 2014 at 5:08pm by DrBob222*

**Physics: Buoyancy**

A crane lifts the 23000 kg steel hull of a ship out of the water. Determine the following. (a) the tension in the crane's cable when the hull is submerged in the water
*Sunday, January 27, 2013 at 11:36pm by Seth*

**Physics: Buoyancy**

A crane lifts the 23000 kg steel hull of a ship out of the water. Determine the following. (a) the tension in the crane's cable when the hull is submerged in the water
*Sunday, January 27, 2013 at 11:40pm by Seth*

**asap science**

what direction does buoyancy act in? all directions, up? etc.
*Thursday, February 6, 2014 at 5:08pm by :)*

**science**

Try some of the following links for information: http://search.yahoo.com/search?fr=mcafee&p=How+did+Archimedias+prove+mathematically+that+salt+water+and+diving+were+related+to+buoyancy%3F+ Sra
*Thursday, November 3, 2011 at 8:04pm by SraJMcGin*

**PHYSICS URGENT DUE IN 15 MINUTES**

Something doesn't make sense to me here. With a density of 1.24 g/cm^3, the weight of the sphere is greater than the buoyancy force. It should sink to the bottom of the tank. What good is a string at the bottom of the tank? Your equations are correct.
*Thursday, March 24, 2011 at 11:06pm by drwls*

**science**

How did Archimedias prove mathematically that salt water and diving were related to buoyancy?
*Thursday, November 3, 2011 at 8:04pm by Justin*

**Physics**

The force consists of two parts (with buoyancy neglected) (1) The weight, (4/3)*pi*R^3*(density) (2) The drag force, (0.95 kg/s)*V Look up the density of copper and use SI units for R and V. Add the two components for the answer in Newtons.
*Saturday, July 10, 2010 at 10:32am by drwls*

**physics**

A wooden cube with a specific gravity of 0.90 and side length 0.120 m is placed into a bucket of water and floats upright with its sides in a horizontal or vertical orientation. What is the mass of the cube, what is the buoyancy force acting on the cube and how much of the ...
*Tuesday, May 1, 2012 at 10:35am by Anonymous*

**Physics**

Let the unknown required force be F. F + M*g = buoyant force = (volume)*(water density)*g Volume = (pi/6)*D^3 = 26.52 cm^3 M = Mass = 2.23 g That is an extremely light ball. More like a balloon. The buoyancy force is much larger than the weight. Solve for F
*Thursday, October 27, 2011 at 9:12pm by drwls*

**Physics - Buoyancy**

What is the volume , in L occupied by 50.0 kg ethanol at 20 degree centimeter ? the density of ethanol at 20 degree centimeter is 0.789 g/ml ?
*Thursday, November 11, 2010 at 12:09pm by Anonymous*

**College Physics**

Someone will gladly critique your work. Nonconservative work done is the product of the water resistance force and the distance it has fallen. They have not mentioned the density of the rock. There will be a buoyancy force on the rock that should be considered, so some of the ...
*Wednesday, March 3, 2010 at 9:49pm by drwls*

**PHYSICS**

mass = W/g = 9.08 kg (a) For the volume, divide the above mass by the density of aluminum, which you should look up. (b) Apparent weight = Actual weight - buoyancy = 89 N - (Volume)*(water density)*(g)
*Tuesday, July 20, 2010 at 7:42pm by drwls*

**physics-Please HELP!**

What percent error is introduced by weighing a Styrofoam block in air, which exerts an upward buoyancy force, rather than in vacuum? The density of air is 1.2 kg/m^3. (The density of Styrofoam is 160 kg/m^3)
*Monday, January 16, 2012 at 5:32pm by Ashley*

**physics**

The object will sink, since the buoyancy force is less than its weight. The net downward force is (4.55-3.20)g = 12.25 N Use Fnet = M*a for the acceleration, a. a = 12.25/4.55 = 2.69 m/s^2
*Saturday, December 1, 2012 at 1:28am by drwls*

**8th grade**

What is the buoyancy force on a 15 g object which displaces 60 ml of water?
*Monday, August 16, 2010 at 6:29pm by fernando*

**physics**

You need to know how much mass was dropped, compared to the mass of the balloon. The buoyancy force will be the same, but the acceleration will increase in proportion to the reduction of mass. Knowing the speed of the balloon when the mass was dropped does not provide the ...
*Tuesday, August 31, 2010 at 12:25am by drwls*

**physics**

a) How far does it have to fall? Assume one meter. Don't forget there is a buoyancy effect. Net downward force is [1.05*density)*V - (density)*V]*g = M*a = (1.05)*density*a "density" is ambient density a = (0.05/1.05) g = 0.47 m/s^2 (1/2) a t^2 = 1 m when t^2 = (1 m)*(4.25 s^2...
*Sunday, May 8, 2011 at 11:28pm by drwls*

**Physics**

If they expect you to neglect hydrodynamic friction (drag), use a = F/m to get the acceleration a, where F is the weight minus the buoyancy force. The accleration is up in both cases. In the real world, drag will be important in reducing a and will depend upon the diameter and...
*Monday, November 7, 2011 at 3:36am by drwls*

**Physics**

A large piece of wood, of mass 56 kg, falls over a waterfall and into the drop pool below. It enters the pool travelling at 12 ms-1 and is then subject to an upwards acceleration of 5.8 ms-2 due to its buoyancy. How long does it take before it bobs to the surface of the pool?
*Thursday, September 30, 2010 at 8:28pm by Rebecca*

**physics**

Your answer is correct Weight = gravity buoyancy force. W=mg - ρ(w)Vg, V=(mg-W)/ ρ(w)g =(59.8-39.3)/10009.8=9.910^-4 m³. ρ=m/V=5/9.910^-4 =5051.5 kg/m³
*Wednesday, June 27, 2012 at 9:23pm by Elena*

**science**

look..i'm not really good in english..but i really2 need help here..why jellyfish must be in buoyancy of water group???
*Saturday, October 10, 2009 at 9:20am by =)*

**Physics - Buoyancy**

A scale reads 20.3 N when an object is not submerged in water and 20.0 N when the object is (completely) submerged in water. What is the specific gravity of the object?
*Thursday, November 11, 2010 at 12:09pm by Phil*

**physics**

I'm kind of confused about this question... so to figure out the accleration you would do F= Fb -w where Fb is the buoyancy force and F is the net force. THen you would you F=ma to find the accleration...but after that I'm kind of lost...helpp pleaseee..
*Thursday, December 3, 2009 at 7:59pm by Anonymous*

**2nd grade**

Please look here: http://www.google.com/search?q=importance+of+air+in+buoyancy&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a Sra
*Friday, January 8, 2010 at 1:12am by SraJMcGin*

**physics**

Buoyancy force = Volume*(air density - helium density)- (balloon fabric mass) = desired mass reduction = 20 kg Solve for the volume. You will have to assume a gas pressure and temperature. You should also take into account the mass of the material of the ballon, but they ...
*Friday, March 26, 2010 at 7:22pm by drwls*

**Physics**

The volume of the block is .1^3 meters^3 weightinAir=density*volume*g Now, in oil, buoyancy subtracts.. weight=weight in air-weight of oil displaced. figure the weight of oil displaced the same way as above
*Friday, November 13, 2009 at 8:43pm by bobpursley*

**science**

I am doing a science project on density and buoyancy. What would be a good hypothesis for this topic?
*Saturday, January 19, 2008 at 1:02pm by shay*

**PHYSICS**

Actually, in the Millikan experiment, there can be one or several charges per drop. What was observed was that the charges were a small multiple of e. In your case, go along with the assumption that the charge is +e and equate the electric force e V/d to the particle's weight...
*Saturday, March 6, 2010 at 9:59pm by drwls*

**physics**

T=F(buoyancy) mg = = ρ(water)Vg - ρ(balsa)Vg= =Vg[ρ(water) - ρ(balsa)] = =0.25³9.8(1000 160)=129 N
*Monday, July 29, 2013 at 11:11pm by Elena*

**Science**

Saltwater has a higher density. It therefore has a larger buoyancy force acting upon it when floating in saltwater at any given depth.
*Thursday, October 18, 2012 at 11:06pm by drwls*

**Physics**

The buoyancy force is 0.838 - 0.705 = 0.133 N Let D be the density and V be the volume D*V*g = 0.838 newtons (1000 kg/m^3)*V*g = 0.133 newtons (That came from Archimedes principle) D = 6300 kg/m^3 (or 6.3 g/cm^3) V = 0.838/(6300 g) = 1.357*10^-5 m^3 = 13.57 cm^3
*Friday, January 27, 2012 at 10:05pm by drwls*

**physics**

The volume of the mass is V = 200/0.8 = 250 cm^3 = 250*10^-6 m^3 and the buoyancy force (up) is Fb = V*200 kg/m^2*g = 0.49 N. The weight force (down) is 0.2 kg*g = 1.96 N. To keep it floating, an upward force of at least 1.96 - 0.49 N = 1.47 N is needed
*Saturday, February 11, 2012 at 10:08am by drwls*

**Intro to Physics**

The buoyancy force in water is 1.15 N. 1.15 N = V*g*1000 kg/m^3 5.15 N = V*g*(density) Combine the two above equations to get density/1000 = 5.15/1.15 = 4.48 density = 4480 kg/m^3 = 4.48 g/cm^3
*Wednesday, November 7, 2012 at 9:51pm by drwls*

**Biology 1010**

Which of following is NOT characteristics of all fish? a.gills as respiratory organs b.two-chambered heart c.swim bladder for buoyancy organ d.skin with scales e.presence of jaws
*Wednesday, April 18, 2012 at 9:47pm by Whitney *

**physics**

Use Stokes' drag equation for the terminal velocity. Stoke's equation says, for a sphere in a viscous fluid, F=6(pi)RnVc, where F is the force, R is the radius of the sphere, n is the viscosity, and V is the velocity through the fluid. For the force F, use the weight minus the...
*Wednesday, November 2, 2011 at 11:16pm by drwls*

**Physics Archimedes buoyancy lab**

In calculating the density of a heavy solid. The string holding the heavy solid will cause error. specific gravity= (mass object in air)/ (mass object in air- mass object in water) = density When does it lead to an experimental density that is too high? Too low? not sure...
*Wednesday, December 12, 2007 at 12:27am by ~christina~*

**physics**

The average density of the rock is 2.00*10^3 kg/m^3, which is twice that of water. That is because the buoyancy force in water equals half the weight in air. The solid part (with mass 5.0 kg/m^3) needs to occupy only 40% of the volume in order for the rock to have a total mass...
*Tuesday, December 6, 2011 at 5:35am by drwls*

**physics**

(a) The buoyancy force on the box is V*(water density)*g = 294 Newtons The box's mass is M g = 980 N Force required to lift = 686 N (b) same approach, but the box weighs 686 N Force required to lift = 686 - 294
*Tuesday, November 27, 2012 at 1:43pm by drwls*

**science**

2000 mL = 2000 cm^3. Mass = 2000cm^3 * 0.001kg/cm^3 = 2kg. Buoyancy = mg = 2 * 9.8 = 19.6 N.
*Tuesday, May 1, 2012 at 3:42pm by Henry*

**physics**

"Airship" is this case something like a blimp. The weight within the airship is filled with helium, which has only 4/29 the density of air. That is why the airship is "lighter than air" when you average over the entire volume. Hot air balloons work because the hotter air ...
*Friday, April 10, 2009 at 7:46pm by drwls*

**science**

Metal foils such as aluminum have a higher density than water. By "wadding it up" you prevent there being any empty volumes inside to give it buoyancy. The denser material (the foil) sinks to the bottom.
*Saturday, July 7, 2012 at 5:51pm by drwls*

**FLUID MECHANICS**

What about the weight of the plate? Is the fluid moving? Does the plate have thickness (and therefore buoyancy)? A better description of the situation is needed.
*Friday, November 18, 2011 at 7:00pm by drwls*

**physics**

The increased displacement of water, nultiplied by the weight of that water, equals the buoyancy force. The increased displacement volume is 6.2*7.1*0.0602 = 2.65 m^3 The weight of that amount of displaced water is (density)*(water volume)*g = 1000*2.65*9.8 = 25,970 N That ...
*Wednesday, December 19, 2012 at 11:53pm by drwls*

**physics**

density of water = 1000 kg/m^3 if .0325 m = additional depth immersed buoyancy volume added = 3.33*5.64*.0325 mass of water displaced = 3.33*5.64*32.5 kg weigh of water displaced = m g = 3.33*5.64*32.5*9.8 Newtons = 5981 N =5.981 kN
*Friday, June 17, 2011 at 10:22am by Damon*

**physics**

In this case the displaced fluid weighs 1.03 - 0.730 = 0.300 N (the buoyancy force). The displaced fluid mass is 0.300/g = 0.0306 kg. Divide that by the cylinder's volume for the mass density (demsity) = 0.0306/3.9*10^-5 = 784 kg/m^3 Divide that by ths density of water (1000 ...
*Sunday, December 13, 2009 at 8:46am by drwls*

**science**

Ice floats because it is less dense than the liquid. When 92% of the ice cube is below the water surface, there is enough buoyancy force to support the weight, so it floats.
*Sunday, January 22, 2012 at 4:29am by drwls*

**Physics**

The actual mass of the cylinder is (density)*(volume) = 2700 kg/m^3*3.8*10^-5 m^3 = 0.1026 kg and its weight is M g = 1.007 N The reduction in weight when immersed, 0.426 N, equals the buoyancy, which is the displaced fluid weight. The density of the fluid is given by (density...
*Tuesday, November 23, 2010 at 3:10am by drwls*

**Physics**

If you understnd buoyancy at all, you should realize that the correct answer is d. Before you ask us multiple-chice questions like this, use your own judegment and tell us what you think. a. Objects denser than the fluid to not float b. Why should the densities be the same? ...
*Friday, February 20, 2009 at 5:28pm by drwls*

**pre ap physics**

There is pressure all around the ball, pushing down on the top and up on the bottom and left on the right and right on the left. However the problem asks for just one force, the vector resultant of all these forces. That is the buoyant force up on the ball (Archimedes ...
*Tuesday, January 4, 2011 at 2:45am by Damon*

**Physics (please help!!!!)**

density of water = 1000 volume of man = 80 kg / 970kg/m^3 = .0825m^3 .31*.0825 = .0256 m^3 buoyant force up on man = .0256*1000*9.81 = 251 Newtons weight of man = 80*9.81 = 785 Newtons weight - buoyancy = 785 -251 = 534 N
*Saturday, April 16, 2011 at 3:09pm by Damon*

**physics**

R = outer radius r = inner radius (of spherical cavity) Sphere weight = buoyancy force (4/3) pi (R^3 - r^3)*(density of Al)*g = (4/3) pi R^3 * (density of water)*g (4/3) pi R^3 * (density of water) = 1.22 kg (Use the second equation to solve for R) The (4/3) pi g cancels out ...
*Tuesday, October 5, 2010 at 12:44am by drwls*

**physics**

Fb = 6.9 - 4.3 = 2.6 N. =Buoyancy force = Wt. of water displaced. m*g = 2.6 N. m = 2.6/g = 2.6/9.8 = 0.2653 kg. = Mass of water displaced. A. Vp = Vw = mass/Dw=0.2653/1000kg/m^3= 2.653*10^-4 m^3 = Vol. of paperweight = Vol. of water. B. m*g = 6.9 N. m = 6.9/g = 6.9/9.8 = 0....
*Sunday, November 4, 2012 at 4:38pm by Henry*

**science**

A 20 N object displaces 2,000 mL of water. What is the buoyancy? Hint: 1 mL of water = 1 cm3 of water = 1 g of water (Remember to convert g to kg) Will it float? (yes/no)
*Tuesday, May 1, 2012 at 3:42pm by Morgan*

**physics**

What do you mean by " 800 k/gm^3 than it does in air " ? The external fluid does not affect the density. Did you mean to write: "What is the volume of a metal which weighs 28g less in kerosene does in air, if the density of kerosene is 800 kg/m^3? That question can be answered...
*Thursday, March 1, 2012 at 1:53am by drwls*

**Physics**

mg = ρV g = =(2.072.555) 10^-627029.8 = 0.699 N buoyancy force Mg mg - Mg = =ρV g ρ1Vg = (ρ ρ1) Vg = =(2702 817) (2.072.555) 10^-69.8 = 0.48 N.
*Tuesday, April 10, 2012 at 5:54pm by Elena*

**science**

Because the hot air inside is less dense than the colder air inside. This causes the air to exert an upward buoyancy force on the balloon. It is the same reason things that are lighter than water will float.
*Friday, January 8, 2010 at 11:42am by drwls*

**physics**

A submerged submarine alters its buoyancy so that it initially accelerates upward at 0.325 m/s^2. What is the submarine's average density at this time? (Hint: the density of sea water is 1.025*10^3 kg/m^3). The difference of densities will give you the net bouyant force on the...
*Wednesday, May 9, 2007 at 3:32am by Anonymous*

**physics**

6) A sub has a volume of 20 m3 and a density of 1500 kg/m3. It sinks to a depth of 40 meters. The density of sea water is 1025 kg/m3. a. What is the pressure on the sub at this depth? b. The sub has a window with a diameter of 30 cm. What is the net force on the window of the ...
*Sunday, January 22, 2012 at 12:00pm by Kat*

**Physics**

The weight of the oak equals the weight of a 15 x 15 x 10.5 cm block filled with water (since that is the buoyancy force). That is the displaced volume of water. The density of the block is (water density)x(15 x 15 x 10.5)/(15 x 15 x 15) = 1 x 10.5/15 = 0.70 gm/cm^3
*Wednesday, January 6, 2010 at 10:50pm by drwls*

**physics**

1.1 a). They say it is rising at constant velocity before the bag drops. That information contains your answer. 1.1 b) You need to provide more information, preferably the mass of the sandbag and the rest of the balloon. The acceleration of the balloon at any time is Fnet/M. ...
*Wednesday, March 17, 2010 at 2:20pm by DrWLS*

**Physics**

volume = (4/3) pi r^3 = (4/3) pi (1.5)^3 = 14.1 m^3 buoyant force = rho g V = 1.03*10^3 * 9.8 * 14.1 = 142,700 N weight down = 1.2*10^4*9.8 = 117,600 N net positive buoyancy = 142700-117600 = 25,100 N Force down - 25,100 N = 1,100 N Force down = 26,200 N mass = 26,200/9.8 = ...
*Sunday, November 21, 2010 at 7:41pm by Damon*

**Fluid Mechanics**

Instead of doing the integral of pressure over the lower surface, try Archimedes. Imagine a vertical shaft, elliptical in cross section, in the water ending at your angled disc. The total force up on it will be the buoyancy or weight (mg) of water displaced.
*Tuesday, September 11, 2012 at 2:35am by Damon*

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