Wednesday

April 16, 2014

April 16, 2014

Number of results: 108,717

**Physics/Nautical Mile**

Hello Bob, love your analogy about mom's apple pie recipe. Allow me to enter the NM debate at this point. Do you happen to have a good explanation re the origin of the k in knots for "nautical miles per hour"?
*Saturday, October 6, 2007 at 2:56am by Reiny*

**Calc**

Two commercial airplanes are flying at an altitude of 40,000 ft along straight-line courses that intersect at right angles. Plane A is approaching the intersection point at a speed of 427 knots (nautical miles per hour; a nautical mile is 2000 yd or 6000 ft.) Plane B is ...
*Tuesday, October 1, 2013 at 11:21am by Anonymous*

**Calc**

Two commercial airplanes are flying at an altitude of 40,000 ft along straight-line courses that intersect at right angles. Plane A is approaching the intersection point at a speed of 427 knots (nautical miles per hour; a nautical mile is 2000 yd or 6000 ft.) Plane B is ...
*Tuesday, October 1, 2013 at 11:27am by Anonymous*

**Algebra ii**

60 nautical miles = 1° of latitude the town is 90-35.2° or 54.8° from the north pole so the distance to the pole is 54.8(60) nautical miles = 3288 nautical miles = 3288(1.15) or 3781.2 statute miles
*Thursday, November 3, 2011 at 12:22pm by Reiny*

**calculus**

Two commercial airplanes are flying at an altitude of 40,000 ft along straight-line courses that intersect at right angles. Plane A is approaching the intersection point at a speed of 429 knots (nautical miles per hour; a nautical mile is 2000 yd or 6000 ft.) Plane B is ...
*Thursday, September 27, 2012 at 7:00pm by Avi*

**Algebra ll**

A lazy row in my dory is at 3 nautical miles/hour. so in t hours I go 3 t nautical miles so my distance y is modeled by the equation y = 3 t
*Saturday, March 8, 2014 at 2:01pm by Damon*

**Physics/Nautical Mile**

The difference in the two latitudes may be due to the oblateness (nonsphericity) of the earth. The plane tangent to local sea level is not perpendicular to a line to the center of the earth, except at the poles and the equator. The same oblateness is the reason for the ...
*Sunday, October 7, 2007 at 4:06am by drwls*

**Physics**

You are thinking correctly. Delta v over delta t expresses acceleration. delta v = 78kts (nautical miles/second) (convert to other units if desired. delta t = 29.8s average acceleration = (78/29.8) nautical miles/sec^2.
*Wednesday, October 3, 2007 at 1:25pm by Quidditch*

**maths**

A ship sails on a steady course bearing 106 degrees from A to B.If B is 76 nautical miles further east than A,find,to the nearest nautical mile,how far the ship has sailed?
*Friday, March 8, 2013 at 3:29am by Shane*

**Pre-Algebra**

One hundred nautical miles equals about 185 kilometers. To the nearest kilometer, how far in kilometers is 290 nautical miles?
*Thursday, December 13, 2012 at 10:27pm by Anonymous*

**maths**

A lighthouse is 9.6 nautical miles from a ship which bears 156 degrees from the lighthouse.How far is the ship east of the lighthouse?Give answer correct to one-tenth of a nautical mile.
*Sunday, March 3, 2013 at 3:13pm by Shane*

**Trigonometry**

Navigation A ship leaves port at noon and has a bearing of S 29° W. If the ship sails at 20 knots, how many nautical miles south and how many nautical miles west will the ship have traveled by 6:00 P.M.?
*Monday, February 4, 2013 at 1:36am by AwesomeGuy*

**Precalculus**

A nautical mile equals the length of arc subtended by a central angle of 1 minute on a great circle on the surface of Earth. If the radius of Earth is taken as 3960 miles, express 1 nautical mile in terms of ordinary, or statute, miles.
*Thursday, January 12, 2012 at 12:39pm by Jillian*

**Physics/Nautical Mile**

That makes sense. BTW, interesting thread.
*Saturday, October 6, 2007 at 2:56am by Reiny*

**Nautical/Maths**

If the dimensions are nautical miles, or miles, then the triangle covers a large fraction of the curved earth, and different equations of spherical trigonometry must be used. If that is the case, ignore my previous answer. The radius of the earth must be used to solve the ...
*Friday, January 4, 2008 at 3:49am by drwls*

**Math!**

At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 25 knots and ship B is sailing north at 16 knots. How fast (in knots) is the distance between the ships changing at 6 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Thursday, June 4, 2009 at 10:44pm by <3*

**calculus**

At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 17 knots and ship B is sailing north at 20 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Thursday, September 24, 2009 at 11:55pm by Parker*

**calculus**

At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 17 knots and ship B is sailing north at 20 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Thursday, September 24, 2009 at 11:55pm by Parker*

**Maths**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 16 knots and ship B is sailing north at 22 knots. How fast (in knots) is the distance between the ships changing at 7 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Thursday, October 15, 2009 at 7:56pm by Salman*

**Math**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 16 knots and ship B is sailing north at 22 knots. How fast (in knots) is the distance between the ships changing at 7 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Friday, October 16, 2009 at 7:25am by Salman*

**calculus**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 25 knots and ship B is sailing north at 16 knots. How fast (in knots) is the distance between the ships changing at 7 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Tuesday, October 20, 2009 at 4:38pm by Georgia*

**math**

At noon, ship A is 40 nautical miles due west of ship B. Ship A is sailing west at 18 knots and ship B is sailing north at 23 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Saturday, November 7, 2009 at 4:31am by adrienne*

**Calculus**

At noon, ship A is 20 nautical miles due west of ship B. Ship A is sailing west at 23 knots and ship B is sailing north at 17 knots. How fast (in knots) is the distance between the ships changing at 5 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Monday, March 1, 2010 at 9:27pm by Samuel*

**calculus 1**

At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 16 knots and ship B is sailing north at 17 knots. How fast (in knots) is the distance between the ships changing at 5 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Thursday, March 25, 2010 at 3:37pm by Anonymous*

**calculus 1**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 18 knots and ship B is sailing north at 19 knots. How fast (in knots) is the distance between the ships changing at 3 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Thursday, March 25, 2010 at 11:22pm by mona*

**calculus 1**

At noon, ship A is 20 nautical miles due west of ship B. Ship A is sailing west at 21 knots and ship B is sailing north at 18 knots. How fast (in knots) is the distance between the ships changing at 5 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Thursday, March 25, 2010 at 11:24pm by mona*

**Calculus**

At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 19 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour
*Saturday, April 3, 2010 at 8:21am by Anonymous*

**Calculus**

At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 18 knots and ship B is sailing north at 22 knots. How fast (in knots) is the distance between the ships changing at 6 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Tuesday, October 26, 2010 at 2:46pm by Sam*

**Calc**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 16 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 7 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Thursday, October 28, 2010 at 11:35pm by Pierre*

**Calculus**

At noon, ship A is 20 nautical miles due west of ship B. Ship A is sailing west at 22 knots and ship B is sailing north at 18 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Sunday, October 31, 2010 at 8:39pm by Anonymous*

**CAL**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 21 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Sunday, July 10, 2011 at 4:26am by LAURA*

**CALCULUS**

At noon, ship A is 40 nautical miles due west of ship B. Ship A is sailing west at 23 knots and ship B is sailing north at 19 knots. How fast (in knots) is the distance between the ships changing at 5 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Monday, October 24, 2011 at 10:07am by CRYSTAL*

**Calc**

At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 15 knots and ship B is sailing north at 18 knots. How fast (in knots) is the distance between the ships changing at 6 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Sunday, February 19, 2012 at 3:33pm by Heather*

**calculus**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 15 knots and ship B is sailing north at 21 knots. How fast (in knots) is the distance between the ships changing at 3 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Thursday, September 24, 2009 at 11:55pm by Cesar*

**PLEASE HELP Math**

At noon, ship A is 40 nautical miles due west of ship B. Ship A is sailing west at 24 knots and ship B is sailing north at 22 knots. How fast (in knots) is the distance between the ships changing at 6 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Sunday, March 15, 2009 at 10:16pm by Randall*

**math**

At noon, ship A is 40 nautical miles due west of ship B. Ship A is sailing west at 16 knots and ship B is sailing north at 17 knots. How fast (in knots) is the distance between the ships changing at 5 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Friday, March 26, 2010 at 7:21pm by bob dylan*

**Cal 1**

(1 pt) At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 20 knots and ship B is sailing north at 23 knots. How fast (in knots) is the distance between the ships changing at 5 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Wednesday, November 3, 2010 at 7:05pm by TJ*

**Calculus**

1 pt) At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 19 knots and ship B is sailing north at 21 knots. How fast (in knots) is the distance between the ships changing at 6 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Saturday, May 5, 2007 at 9:27pm by Anonymous*

**Calculus **

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 23 knots and ship B is sailing north at 17 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.) Please help!
*Sunday, July 28, 2013 at 6:21pm by Anonymous*

**Calculus Please help!**

At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 18 knots and ship B is sailing north at 23 knots. How fast (in knots) is the distance between the ships changing at 3 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Friday, February 28, 2014 at 3:02pm by ALI*

**calculus**

(1 pt) At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 15 knots and ship B is sailing north at 21 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Tuesday, March 10, 2009 at 4:18pm by bill nye*

**math**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 21 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.) this is a cal ...
*Saturday, July 9, 2011 at 9:08pm by lisa*

**math**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 21 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.) this is a cal ...
*Saturday, July 9, 2011 at 10:26pm by lisa*

**calculus**

let t hours be some time after noon (so 4:00 pm is t=4) so you have a right angled triangle with a vertical of 21t nautical miles and a horizontal of (15t + 50) nautical miles let the distance between them, or the hypotenuse, be s nautical miles s^2 = (21t)^2 + (15t+50)^2 2s(...
*Tuesday, March 10, 2009 at 4:18pm by Reiny*

**calculus**

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 25 knots and ship B is sailing north at 25 knots. How fast (in knots) is the distance between the ships changing at 6 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Monday, May 14, 2012 at 12:28am by remy*

**calculus**

At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 15 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 3 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Sunday, November 4, 2012 at 8:25pm by Anonymous*

**calculus**

At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 15 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 3 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Sunday, November 4, 2012 at 8:30pm by Anonymous*

**calculus**

At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 15 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 3 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
*Sunday, November 4, 2012 at 11:26pm by Anonymous*

**Nautical/Maths**

Thank you drwls, The accepted format for determining nautical miles is a capital M. I put NM just in case someone was confused. Sorry for the additional confusion. Now to the problem. Again the PZX triangle is to do with celestial navigation and I understand spherical ...
*Friday, January 4, 2008 at 3:49am by Mike*

**physics**

Math books drive me crazy with their misuse of navigational language. You travel on a heading as used in the second sentence. A bearing is what direction you look to see something. (The enemy is on a bearing of 185 degrees true.) Anyway start at (x,y) = (0,0) It is heading 25 ...
*Friday, April 12, 2013 at 12:43pm by Damon*

**Physics/Nautical Mile**

If you want to explore this in some depth, there are many good introductory books on geophysics, you might call your local library.
*Friday, October 5, 2007 at 8:16am by bobpursley*

**algebra**

Two ships make the same voyage of 3000 nautical miles. The faster ship travels 10 knots faster than the slower one (a knot is 1 nautical mile per hour). The faster ship makes the voyage in 50 hr less time than the slower one. Find the speeds of the two ships.
*Tuesday, February 21, 2012 at 11:04pm by Krystal*

**Physics/Nautical Mile**

It couln't be done until we knew the shape of the Earth with some precision, in particular the semimajor and semiminor axis. WGS 84 is the system that defined these lengths with some precision. With that, the point of curvature could be determined, and thence the distance ...
*Saturday, October 6, 2007 at 2:56am by bobpursley*

**Precalculus**

Around the earth is 360*60 = 21600 minutes of arc or nautical miles. 2 pi (3960) = 24881 landlubber miles around the earth 24881/(360*60) = 1.152 landlubber miles/ nautical mile
*Thursday, January 12, 2012 at 12:39pm by Damon*

**Physics/Nautical Mile**

My previous posts have dramatically improved my understanding of how a NM is derived but other questions have been raised: In most books entitled "Pass your Day Skipper" or "Yachtmaster" or similar nautical/navigational publications Latitude is described and illustrated as the...
*Saturday, October 6, 2007 at 2:56am by Mike*

**Physics/Nautical Mile**

Goodness. Gestational? It was meant to be gravitational (field strength). I type in the dark, and am losing vision in my left eye. Sorry.
*Friday, October 5, 2007 at 8:16am by bobpursley*

**Nautical/Maths**

I don't see why you have both M and (NM) following the length numbers. Are the dimensions meters, nanometers, miles of nautical miles? Your call. After deciding what units you are talking about, let side PZ of the triangle be a and side PX be b. The length of side ZX (c) can ...
*Friday, January 4, 2008 at 3:49am by drwls*

**Geomatics**

Briefly, you will need access to the Nautical Almanac, published jointly by UK and US yearly. Some free versions are available on the web for past years. The nautical almanac gives the position of the sun (and many other celestial bodies) in longitude and latitude at any hour ...
*Monday, April 11, 2011 at 1:36am by MathMate*

**Physics/English/Nautical Mile**

In my previous posts about the NM I think part of my problem is I do not understand the meaning of the word "SUBTENDED". Explanation please. Mike
*Friday, October 5, 2007 at 2:21pm by Mike*

**Nautical/Maths**

hi
*Friday, January 4, 2008 at 3:49am by Anonymous*

**Physics**

The Nautical Mile is internationally recognised as 1852m which is an approximation of 1' of latitude subtended to the earths surface. However it is an average and the geographical length on the earths surface of 1' of lat subtended will vary according to the radius of the ...
*Friday, October 5, 2007 at 4:45am by Mike*

**Whoops**

A MINUTE of latitude is a nautical mile.
*Thursday, January 15, 2009 at 8:17pm by Damon*

**math**

Arithmetic: Clipper's lead = 8 knots * (1/2) hour = 4 nautical miles For each hour, the Rover catches up by (10-8)=2 nautical miles. Time required to catch up = 4/2 hours (after 9:30) Time the Rover will catch up = 11:30 Algebra: Let t=time (as of 9:30) to catch up 10*t - 8*t...
*Sunday, October 4, 2009 at 5:24pm by MathMate*

**math**

Let the time past noon be t hours Distance, since noon, travelled by the westbound ship is 16t nautical miles, and ship B is 17t nautical miles. Let D be the distance between them D^2 = (16t)^2 + (17t)^2 D^2= 545t^2 D = (√545)t dD/dt = √545 notice that dD/dt is a ...
*Friday, March 26, 2010 at 7:21pm by Reiny*

**trigonometry**

You do not need to compute in nautical miles to get the correct answer.
*Thursday, January 15, 2009 at 8:17pm by drwls*

**Math Analysis**

Ok, let's make a diagram showing the sideview. Let A be the origianl position of the ship, let B be the position after 20 minutes, Let P be the top of the hill, and Q be on AB extended so that BQ and PQ form a right angle. Summarizing: angle Q = 90º, angle QBP = 1.4º, angle ...
*Tuesday, March 2, 2010 at 10:22pm by Reiny*

**Maths/Law of sines**

I have a spherical triangle and I know 1 angle 31.3 degrees and all 3 sides which are 1624, 2118.4 and 1078.85 nautical miles. In order to find the other 2 angles I know I must use the law of sines: sin A over a = sin B over b = sin C over c If angle A is 31.3 degrees and side...
*Sunday, January 13, 2008 at 1:18pm by Mike*

**Physics/Nautical Mile**

Hello again Bob, Thanks for your reply. The point that has grabbed my attention now is you refer to the "NEW" definition of the minute of latitude. Things are slowly falling into place at this end. Do you happen to know when the "NEW" definition of latitude was introduced? Mike
*Saturday, October 6, 2007 at 2:56am by Mike*

**math**

Cross multiply and solve for x. 17/60 = x/12 60x = 204 x = 3.4 nautical miles
*Saturday, November 10, 2012 at 5:36pm by Ms. Sue*

**Math**

t noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 16 knots and ship B is sailing north at 22 knots. How fast (in knots) is the distance between the ships changing at 7 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.) Note: Draw ...
*Thursday, October 15, 2009 at 4:53pm by Salman*

**Calculus**

At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 20 knots and ship B is sailing north at 16 knots. How fast (in knots) is the distance between the ships changing at 6 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.) Note: Draw ...
*Sunday, November 22, 2009 at 4:10pm by Bobby*

**8th Grade Math (Algebra1)**

I actually have a few different problems that are giving me trouble. The first: We have to use the motion problem formula: d=rt and make a table containing the elements: rate: * time: = distance ------------------------------ label #1 label #2 The Directions for this problem's...
*Tuesday, February 3, 2009 at 9:21pm by Nicole C.*

**Maths/Law of sines**

You must use the fact that one degree around the earth is 60 nautical miles to get distances as angles.
*Sunday, January 13, 2008 at 1:18pm by Damon*

**trigonometry**

Sorry I can only do this problem in nautical miles :) (where one degree of latitude is one mile)
*Thursday, January 15, 2009 at 8:17pm by Damon*

**Calc**

If t is measured in hours and f '(t) is measured in knots, then integral from 0 to 2 of f '(t)dt = ? (Note: 1 knot = 1 nautical mile/hour)
*Sunday, January 2, 2011 at 4:27pm by Erica*

**Nautical Studies/Tides**

New moons & Full moons are responsible for Spring Tides. Moon's & Sun's gravity in line. 1st quarter & last quarter are responsible for Neap Tides. Moon's gravity 90 degrees to Sun's gravity. This is generally accepted & understood. However if you look in a tide table or ...
*Wednesday, October 10, 2007 at 2:09am by Mike*

**calculus**

A ship is running at 14 3/4 knots (nautical miles per hour) for 7 1/2 hours. How far does the ship travel?
*Sunday, January 24, 2010 at 4:51pm by Jammie*

**calculus**

A ship is running at 14 3/4 knots (nautical miles per hour) for 7 1/2 hours. How far does the ship travel?
*Sunday, January 24, 2010 at 4:51pm by Jammie*

**chemistry**

By international agreement, the nautical mile is now defined as exactly 1852 meters. By what percentage does this current definition differ from the original definition?
*Friday, January 7, 2011 at 3:28pm by Anonymous*

**Nautical studies**

Thanks Bob, Got it sorted. 2.08 x Sq root of the height gives horizon in NM. Answer in my question is 29.5M Mike
*Thursday, November 8, 2007 at 3:41am by Mike*

**Math story problem**

The Airbus A380-800, the largest in the Airbus fleet has a range of 8,200 nautical miles. Please write this number in scientific notation.
*Thursday, October 6, 2011 at 1:28pm by Katie A*

**Algebtra**

from 630 feet at the top of the horizon. Due to the curvature of the earth how far away is the city. using d=sqrt[3h/2] where d is the distance in nautical miles and h is the height in feet.
*Sunday, September 11, 2011 at 7:14pm by Dianne*

**Spherical Trigonometery**

I am trying to apply the formula cos c = cos a x cos b + sin a x sin b x cos C to find the length of c in my spherical triangle. I am working with 2 examples in a book in which the answers are given. In the first example all the sines & cosines calculated are positive and I ...
*Tuesday, January 15, 2008 at 4:21am by Mike*

**Physics/Nautical Mile**

Still studying! I have The Macmillan & Silk Cut Nautical Almanac from 1981 which pre-dates WGS84 and they make reference to the NM being 6046 feet at the equator and 6108 feet at the poles. Conversions to metres = 1842.82m and 1861.71m. Remarkably similar to WGS84 derived ...
*Sunday, October 7, 2007 at 4:06am by Mike*

**Nautical**

With a steady wind blowing at 15Kn blowing over the sea is it possible to determine the speed the waves are travelling? Thanks Mike
*Friday, November 23, 2007 at 3:34am by Mike*

**Physics/Nautical Mile**

There is a geometric center of the Earth, as is there a gravitational center. They are different because of the uneven distribution of the Matter in Earth (Earth does wobble). The center of curvature is indeed different from the center of the Earth, and in fact, for each ...
*Friday, October 5, 2007 at 8:16am by bobpursley*

**Physics/Nautical Mile**

Those drawings are simplified. The only reason that the "new" definition of the minute of latitude being arc disance subtended by one minute from the center of curvature is that satellite mapping has made it possible to accurately map the real Earth Surface. For surface ...
*Saturday, October 6, 2007 at 2:56am by bobpursley*

**Physics/Nautical Mile**

http://mathforum.org/kb/message.jspa?messageID=1470195&tstart=0 This is as I learned it many years ago as a seaman.
*Saturday, October 6, 2007 at 2:56am by bobpursley*

**maths**

Lighthouse = 9.6nmi@156o. X = 9.6*cos156 = -8.8 n. miles = 8.8 n. miles West of ship. Ship = 8.8 Nautical miles East of light- h0use.
*Sunday, March 3, 2013 at 3:13pm by Henry*

**Nautical Studies**

I am trying to find an up to date position for the Magnetic North Pole. All searches I have made state positions that are several years out of date. Can anyone help Thanks Mike
*Sunday, October 28, 2007 at 3:52am by Mike*

**Nautical**

Yes, by using a combination of gps (for ship velocity) and laser velocimeter (for wave relative velocity), and vector addition. However, the wave speeds will not all be the same, and will not equal the wind speed.
*Friday, November 23, 2007 at 3:34am by drwls*

**Nautical/Maths**

Should I multiply .836 by .643 ? Then multiply .549 by .766 by .766 ? Then add the 2 answers together ? ---------------------------------- Yes, yes, you have it. I used a TI-83 calculator that has sin and cos functions
*Friday, January 4, 2008 at 3:49am by Damon*

**chem**

since time = distance/speed, and the times are equal, Assuming nautical miles, so knots make sense, 70/(20+s) = 45/(20-s) s = 100/23 = 4.35 knots
*Monday, July 22, 2013 at 5:05pm by Steve*

**Calculus - Optimization **

The cost of fuel for a boat is one half the cube of the speed on knots plus 216/hour. Find the most economical speed for the boat if it goes on a 500 nautical mile trip.
*Wednesday, March 20, 2013 at 6:17pm by Sam*

**Nautical Studies**

Three bells (I am Aground) rapid bells for five seconds Three bells (I am arground) That is what I remember. I couldn't find it online, and most of my references have been boxed away.
*Tuesday, October 9, 2007 at 2:41am by bobpursley*

**Nautical/Maths**

The haversines are because of that log problem I mentioned. Forget it. We do not have to multiply and divide by adding and subtracting logs any more. Use a calculator. same old law of sines sin A/sin a = sin B/sin b = sin C/sin c
*Friday, January 4, 2008 at 3:49am by Damon*

**Nautical/Maths**

Please can someone solve this PZX triangle for me and give your workings. Angle ZPX 040 degrees Distance PZ 3000M (NM) Distance PX 2000M (NM) Thanks a million. Mike
*Friday, January 4, 2008 at 3:49am by Mike*

**math- precalculus**

Landlubber mathematicians have never been to sea :( The direction a ship is heading is called "heading" The direction the ship is from you is called its "bearing". That aside: from origin go 15 nautical miles at 90 + 10 degrees clockwise from North, or 10 degrees South of East...
*Saturday, March 21, 2009 at 5:19pm by Damon*

**trig**

arc length s = rθ 300 = 4000θ 3/40 = θ that is in radians In degrees, that's 180/pi * 3/40 = 4.3° Check: a nautical mile is 1' of latitude, = 1.15 miles. 4.3° * 60'/° * 1.15mi/' =~ 300 mi
*Tuesday, January 24, 2012 at 9:30pm by Steve*

**Physics/Nautical Mile**

The NM by definition is something used at sea. In my previous post I established there is a difference in the length of the earths radius at the equator compared to the poles, although it is not clear whether the radius is a measurement of land mass or sea level? Additionally ...
*Friday, October 5, 2007 at 8:16am by Mike*

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