Wednesday
April 23, 2014

Search: NaOH, HC2H3O2

Number of results: 4,667

chemistry
If it requires 30.0 milliliters of 1.2 molar HCl to neutralize 20.0 milliliters of NaOH, what is the concentration of the NaOH solution? Balanced equation: NaOH + HCl NaCl + H2O 0.60 M NaOH 0.80 M NaOH 1.3 M NaOH 1.8 M NaOH
Wednesday, June 22, 2011 at 12:14pm by Magan

Chem
(Na^+) = (NaOH) mols NaOH = M x L (NaOH) = (M NaOH x L NaOH/total volume) = 0.200 x 0.100/0.350) =? The others look ok to me.
Monday, October 28, 2013 at 10:14pm by DrBob222

CHEM 101
HBr + NaOH ==> NaBr + H2O mols HBr = M x L = ? Convert mols HBr to mols NaOH using the coefficients in the balanced equation. M NaOH = mols NaOH?L NaOH. You have M NaOH and mols NaOH, substitute and solve for L NaOH (and convert to mL if that is needed).
Tuesday, October 8, 2013 at 11:39am by DrBob222

biology
suppose 23mL of NaOH was required. How much Carbonic Acid was neutralized? 1L of .01 NaOH contains ____ mol NaOH? lmL of .01 NaOH contains _____mol NaOH? 23mL of .01 NaOH contains _____ mol NaOH? 2 mol of NaOH react with 1 mol H2CO3 2.3 x 10^-4 mol of NaOH react with ____mol CO2
Tuesday, October 5, 2010 at 6:03pm by Anonymous

Chemistry
Запишем уравнение реакции: NaOH + HCl = NaCl + H2O C NaOH*V NaOH = C HCl*V HCl где: C NaOH и C HCl...
Tuesday, April 13, 2010 at 8:44am by Yevgeniy

chemistry 101
If 15g of NaOh is dissolved in 285 g of water, calculate the following. Assume the density of the solution is 1.06 g/cc. a) Calculate the moles of NaOH in the solution? My answer is 15gNaOH/40g NaOH= .0375 mole NaOH b) Waht is the mass % w/w of the solution? My answer is 15g ...
Saturday, December 8, 2012 at 12:34am by Tracy

chemistry
Do mean to calculate the volume of NaOH required for the neutralization? 2NaOH + H2SO4 ==> Na2SO4 + 2H2O moles H2SO4 = grams/molar mass Use the coefficients in the balanced equation to convert moles H2SO4 to moles NaOH. 15% NaOH means 15 g/100 mL (is that 15% w/v?) So 15 g ...
Thursday, March 17, 2011 at 4:30pm by DrBob222

Chemistry
moles chloroacetic acid = M x L moles acid = moles NaOH M NaOH = moles NaOH/L NaOH. You have M NaOH and M NaOH, solve for L NaOH and convert to mL if you wish.
Thursday, January 19, 2012 at 9:25am by DrBob222

Inorganic chemistry
mol KHP = (0.7719g)(1 mol KHP/204.2g) = .0038mol Where are the moles of NaOH? I know that there are 0.02637 L of NaOH and I know M = mol/l I know there are 40g NaOH/mol NaOH There is 1 mol of NaOH in the balanced equation But I do not have grams of NaOH
Tuesday, April 14, 2009 at 1:02pm by Steve

AP Chemistry
moles acid or base = M x L = ?? Next use the coefficients in the balanced equation to convert moles acid/base to the other one. The M = moles/L. Here is an example using (a). HCl + NaOH ==> NaCl + HOH moles HCl = M x L = 0.500M x 0.021L = 0.0105. moles NaOH = 0.0105 x (1 ...
Saturday, September 24, 2011 at 9:11pm by DrBob222

AP Chemistry
H2A + NaOH ==> NaHA + H2O for the first H. NaHA + NaOH ==> Na2A + H2O for the 2nd H. mols H2SO4 = 0.018L x 0.122 M = ? mols NaOH = same for the first H. M NaOH = moles NaOH/L NaOH. Solve for L NaOH.
Saturday, March 17, 2012 at 2:08am by DrBob222

Chemistry(Please help, thank you!!)
2NaOH + H2SO4 ==> 2H2O + Na2SO4 moles H2SO4 = M x L = ? moles NaOH = 2 x moles H2SO4 from the equation. M NaOH = moles NaOH/L NaOH. You have moles NaOH and L NaOH, solve for M NaOH.
Tuesday, October 25, 2011 at 10:21pm by DrBob222

Chemistry
Are you titrating the ASA with NaOH? If so use the volume NaOH in the titration. Then mols = M NaOH x L NaOH
Tuesday, June 4, 2013 at 12:29pm by DrBob222

chemistry
I think 1 is right. I disagree with 2. Yes, the solution of NaOH M is too low since all of the NaOH has not dissolved but during the second titration the NaOH is stronger which means it takes less NaOH than it should and M = mmols/mL so smaller NaOH mL means a larger M. 3. The...
Tuesday, March 11, 2014 at 2:25am by DrBob222

CHemistry
im not sure how u solve these types of problems... How many moles of NaOH are contained in 200ml of a 0.1M of NaOH? How many grams of NaOH are contained in 500ml of a .5M solution of NaOH? <<How many moles of NaOH are contained in 200ml of a 0.1M of NaOH? >> A 0.1 ...
Saturday, April 21, 2007 at 10:21pm by Phil

chemistry
How many moles NaOH do you need? THat is M x L = ? M NaOH = moles NaOH/L NaOH. YOu know M NaOH (6.0M) and you know moles from the first part. Solve for L and convert to mL.
Monday, October 24, 2011 at 7:10pm by DrBob222

Chemistry105
mol NaOH = grams/molar mass= ? M = mols/L = ? mols/0.1L b) mols HCl = M x L = ? mols NaOH = mols HCl M NaOH = mols/L soln. You know M NaOH and mols NaOH, solve for L NaOH and convert to mL if you wish.
Tuesday, December 4, 2012 at 9:47pm by DrBob222

Chem 2 Lab
H3PO4 + 3NaOH ==> 3H2O + Na3PO4 mols H3PO4 = 0.4/molar mass H3PO4 = ? Convert mols H3PO4 to mols NaOH using the coefficients in the balanced equation. M NaOH = mols NaOH/L NaOH. You know M and mols NaOH, solve for L NaOH
Wednesday, April 25, 2012 at 10:30pm by DrBob222

Chemistry
#1. For H2SO4L: 2NaOH + H2SO4 --> Na2SO4 + 2H2O moles H2SO4 = M x L = ?? moles NaOH = 2x moles H2SO4 (from the equation). M NaOH = moles NaOH/L NaOH. #1. For HCl: NaOH + HCl ==> NaCl + H2O moles NaOH = M(from the first part) x L moles HCl = moles NaOH (from the equation...
Monday, October 4, 2010 at 3:03pm by DrBob222

chemisrty
HCl + NaOH ==> NaCl + H2O mols HCl = M x L = ? mols NaOH = same. (Look at the coefficients in the balanced equation.) M NaOH = mols NaOH/L NaOH. You have molos and M, solve for L.
Thursday, April 25, 2013 at 11:47am by DrBob222

chemistry
HCl is titrated with NaOH. When doing the titration, some of the NaOH splashed onto the inside surface of the Erlenmyer flask, and you forgot to rinse it into your sample. Would the systematic error be falsely high, low, or unaffected and why? Thanks. As I understand the ...
Sunday, September 17, 2006 at 4:25pm by bria

Chem
KHC8H4O4 + NaOH ==> NaKC8H4O4 mols KHC8H4O4 = grams/molar mass. mols NaOH = same (Look at the coefficients in the balanced equation.) M NaOH = mols NaOH/L NaOH
Monday, April 8, 2013 at 7:03am by DrBob222

chemistry
moles acrylic acid = grams/molar mass moles acrylic acid = moles NaOH. M NaOH = moles NaOH/L NaOH. You know M NaOH and moles NaOH, solve for L NaOH and convert to mL.
Wednesday, January 25, 2012 at 6:54pm by DrBob222

Chemistry
KHP + NaOH ==> NaKP + H2O So 1 mole KHP uses 1 mole NaOH. moles KHP = grams/molar mass. Calculate moles KHP Then moles NaOH = moles KHP M NaOH = moles NaOH/L NaOH. (mL NaOH used = final reading - initial reading, then convert to liters.)
Tuesday, October 4, 2011 at 8:50pm by DrBob222

Chemistry
0.01L KHP * 0.445M KHP = 0.00445 molKHP KHP and NaOH are in 1 to 1 ratio so, moles NaOH = 0.00445 so, 0.00445mol NaOH/ 0.01154L NaOH = 0.386M NaOH
Monday, October 4, 2010 at 7:30pm by Andrew

acid and base titrations
Which of the following solutions should be used when titrating a 25.00mL sample of CH3COOH that is approximately 0.1 M? a.) 0.150 M NaOH b.) 0.001 M NaOH c.) 3.00 M NaOH d.) 6.00 M NaOH
Sunday, November 21, 2010 at 5:15am by jj reddick

Chemistry
moles H2C2O4 = grams/molar mass = ?? Using the coefficients in the balanced equation, convert moles H2C2O4 to moles NaOH. That will be ??moles H2C2O4 x (2 moles NaOH/1 mole H2C2O4) = ??moles H2C2O4 x 2 = xx moles NaOH. Then M NaOH = moles NaOH/L NaOH, and round to the ...
Tuesday, June 7, 2011 at 7:06pm by DrBob222

Chemisty
How many mols MgSO4 so you have? That is moles = M x L = 0.541 x 0.148 = ? Using the cofficients in the balanced equation, convert moles MgSO4 to moles NaOH. That is ?moles MgSO4 x (2 moles NaOH/1 mol MgSO4) = ?moles MgSO4 x 2/1 = ? moles MgSO4. Then M = moles/L soln MNaOH = ...
Tuesday, February 7, 2012 at 9:39pm by DrBob222

Chemistry
I find it helpful to write each step of the procedure and see how the question affects each. 1. mols KHP = grams/molar mass 2. mols NaOH = mols KHP 3. M NaOH = mols NaOH/L NaOH So you did steps 1 and 2 right but on 3 added too much L NaOH. That's in the denominator, too big ...
Wednesday, December 5, 2012 at 3:17pm by DrBob222

AP chemistry
moles KHP = grams/molar mass Substitute and solve for mols. KHP + NaOH ==> NaHP + H2O so the reaction is 1:1 and moles KHP = moles NaOH. Then M NaOH = moles NaOH/L NaOH. To obtain L NaOH, you will need to subtract the final buret reading - initial buret reading and convert ...
Sunday, October 24, 2010 at 8:29pm by DrBob222

chemistry
The whole idea here is that you have an equation that tells you what is going on AND you have measured quantities of each; therefore, you can calculate the missing quantity of the other one. 2NaOH + H2SO4 ==> Na2SO4 + 2H2O How many moles acid did we use? That is M x L = ? ...
Friday, March 16, 2012 at 12:15am by DrBob222

chemistry
Write the equation and balance it. HCl + NaOH ==> NaCl + H2O 1. moles HCl used = M x L = ?? 2. Using the coefficients in the balanced equation, convert moles HCl to moles NaOH. Since everything is a 1:1 ratio, that means moles NaOH = moles HCl. 3. Then M NaOH = moles NaOH/L...
Wednesday, June 15, 2011 at 2:07pm by DrBob222

chem 111 lab
KHP + NaOH ==> NaKP + H2O mols KHP = grams/molar mass From the equation, mols KHP = mols NaOH. M NaOH = moles NaOH/L NaOH
Monday, February 20, 2012 at 6:22pm by DrBob222.

chemistry
We'll call benzoic acid HB. HB + NaOH ==> NaOH mols HB = grms/molar mass Look at the equation (the coefficients) 1 mol NaOH = 1 mol HB; therefore, mols HB = mols NaOH. Then M NaOH = mols NaOH/L soln.
Wednesday, May 9, 2012 at 10:58pm by DrBob222

Chemistry
moles solid NaOH = 9.4 g/molar mass NaOH = ?? moles NaOH solution = M x L = ?? Add to find the sum of the moles. This is the total NaOH dissolved (in moles). Now convert 2.37 gallons of water to mL and concn NaOH (molarity) = total moles/L.Post your work if you get stuck.
Monday, October 4, 2010 at 6:30pm by DrBob222

organic bio chemistry
H2SO4 + 2NaOH ==>Na2SO4 + 2H2O mols H2SO4 = M x L = ?? Look at the coefficients in the balanced equation. mols NaOH = 2 x mole H2SO4. Then M NaOH = moles NaOH/L NaOH You know M and you know moles, solve for L NaOH and convert to mL.
Tuesday, March 8, 2011 at 11:06pm by DrBob222

Chemistry help
NaOH is a strong base, so it will completely dissociate into OH-. pOH+pH=14, so 14-pOH=pH Solve for pOH 2.00g of NaOH*(1 mole of NaOH/39.997 g)= moles of NaOH moles of NaOH/2.00L=molarity of NaOH -log[molarity of NaOH]=pOH 14-pOH=pH
Monday, July 29, 2013 at 7:36pm by Devron

CHEMISTRY
mols HCl = M x L = ? mols NaOH = mols HCl (look at the coefficients in the balanced chemical equation). M NaOH = mols NaOH/L NaOH You know mols and L, solve for M. L for NaOH is 0.075 since you want M of the diluted solution.
Friday, October 18, 2013 at 1:38pm by DrBob222

Chemisty
Vol NaoH titration Ml Naoh (1L/1000 mL) (.270 M (NAOH)= mol NaOH
Monday, January 14, 2013 at 5:11pm by Bellam

chemistry
You need to learn to place an arrow; otherwise, we don't know the difference between the reactants and the products. In this case, how many mole HCl did you use? mole HCl = M x L = ?? Now convert, using the coefficients in the balanced equation, to moles NaOH. The equation is ...
Wednesday, June 22, 2011 at 6:43pm by DrBob222

chemistry
It still makes no sense to me. Here is the problem as I see it. I don't understand what the 15% has to do with the problem. What is the mass of NaOH (notice I use caps since naoh means absolutely nothing) required to neutralize 176 g H2SO4. 2NaOH + H2SO4 ==> 2H2O + Na2SO4 ...
Saturday, March 19, 2011 at 10:40am by DrBob222

Chemistry
I've been working on this problem for hours and cant figure it out. I know it should be simple, but I'm stuck... The question is... Describe how to prepare 1.00L of a 1.0% (w/v) NaOH from a 2.0 M NaOH. *I need to figure out how many ml of the stock solution is needed. So far I...
Thursday, January 10, 2013 at 6:08pm by James

chem
KHC2O4 + NaOH ==> NaKC2O4 + H2O mols KHC2O4 = grams/molar mass = ? mols NaOH = mols KHC2O4(see the coefficients in the balanced equation). Then M NaOH = mols NaOH/L NaOH and solve for M
Wednesday, November 21, 2012 at 2:52pm by DrBob222

AP Chemistry
HCl + NaOH ==> NaCl + H2O mols HCl = M x L = ? mols NaOH = mols HCl M NaOH = mols NaOH/L NaOH I believe that works out to be about 4.2M but check my work.
Wednesday, September 11, 2013 at 6:18pm by DrBob222

Chemistry-Is this correct?
The concentration of NaOH is normally in the range of 3-6 M when they peel potatoes and soak them in a solution of NaOH , remove them and spray them off. If I have 45.7 mL of 0.500M of H2SO4 required to react completely with a 20.0 mL sample of NaOh. What is the molar ...
Thursday, May 20, 2010 at 4:20pm by Sara

Chemistry
One commercial method used to peel potatoes is to soak them in a solution of NaOH for a short time, remove them from the NaOH, and spray off the peel. The concentration of NaOH is normally in the range of 3 to 6 M. The NaOH is analyzed periodically. In one such analysis, 45.7 ...
Wednesday, January 12, 2011 at 1:06am by Chin

chemistry
NaOH + KHP ==> NaKP + H2O mols KHP = grams/molar mass mols NaOH = mols KHP (look at the coefficients in the balanced equation.) M NaOH = mols NaOH/L NaOH
Tuesday, December 11, 2012 at 3:57pm by DrBob222

chemistry
H3PO4 + 3NaOH ==> 3H2O + Na3PO4 mols H3PO4 = M x L = ? Using the coefficients in the balanced equation, convert mols H3PO4 to mols NaOH. That is mols H3PO4 x 3 = mols NaOH. Now M NaOH = mols NaOH/L NaOH. YOu know M and mols, solve for L NaOH and convert to mL.
Monday, December 10, 2012 at 8:06pm by DrBob222

chemistry- thank you
Write the equation. 2NaOH + H2SO4 ==> H2O + Na2SO4. moles H2SO4 = M x L = ?? moles NaOH needed = twice that (from the equation). Then M NaOH = moles NaOH/L NaOH. Solve for L NaOH.
Sunday, October 31, 2010 at 9:49pm by DrBob222

Chemistry
So far so good; however, you didn't include the volume of NaOH required in the titration. M(NaOH) x mL(NaOH) = M(vinegar) x mL(vinegar). 0.1250 x mL(NaOH) = M(vinegar) x 4.00 mL Plug in the mL NaOH, whatever it is, and you will have just one unknown which is the molarity of ...
Wednesday, July 23, 2008 at 10:44pm by DrBob222

Chemistry help
There are numerous ways to do this but the shortest way is to use the dilution formula that you have in the last sentence of your post. I even take a short cut with that. 0.01M NaOH x (2.0 mL/8 mL) = ? M. Note: It isn't needed, but you really do have the mass. moles NaOH = M x...
Thursday, March 15, 2012 at 5:05pm by DrBob222

chemistry
For the KHP question. Convert 0.51 g KHP to mols. mols = g/molar mass. You don't ask a question but I assume you want to know the molarity of the NaOH. Mols KHP = mols NaOH. mols NaOH = L x M. YOu have mols NaOH and L NaOH. Calculate molarity NaOH. Post yuor work if you get ...
Sunday, October 14, 2007 at 9:28pm by DrBob222

Chemisty
H2Ox + 2NaOH ==> Na2Ox + 2H2O mols Ox = grams/molar mass mols NaOH required = 2 x mols Ox (from th equation). M NaOH = mols NaOH/L NaOH/ Then to prepare 2.5L of solution you will need how many mols total? That is M x L = ? grams NaOH = mols NaOH/molar mass NaOH. You know ...
Wednesday, May 9, 2012 at 9:42am by DrBob222

Chemistry
I will assume that this is a titration problem. You know the mass of the KHC8H4O4 (potssium hydrogen phthalate) and you titrated that mass with NaOH. mols phthalate = grams/molar mass. Since the equation is 1:1 (1 mol phthalate to 1 mol NaOH) the mols NaOH = mols phthalate ...
Sunday, October 7, 2012 at 12:21am by DrBob222

Chemistry
NaOH + KHP ==> NaKP + H2O moles KHP = M x L = ?? moles NaOH = same (from the equation) M NaOH = moles NaOH/L NaOH
Monday, October 4, 2010 at 7:30pm by DrBob222

chemistry
KHP is a monoprotic acid with a molar mass of 204.22 g/mol. The titration data are as following. The average concentration of NaOH solution is M. 1 2 3 mass of KHP (g) 2.789 2.543 2.612 vol NaOH used (mL) 27.77 23.22 27.12 You didn't ask a question but I assume you are to ...
Wednesday, May 16, 2007 at 1:41am by jared

Chem 100L
I worked this for someone last night. mols oxalic acid = grams/molar mass. Use the coefficients in the balanced equation to convert mols H2C2O4 to mols NaOH. M NaOH = mols NaOH/L NaOH
Sunday, December 2, 2012 at 3:40pm by DrBob222

chemistry
A volume of 100mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M NaOH to the reaction flask. Classify the following conditions based on whether they are before the equivalence point, at the equivalence point, or after...
Monday, August 6, 2012 at 8:00pm by Anon

Chemistry(Please help, thank you!!)
Hannah, I can't believe you can't follow instructins but here is the problem worked IN DETAIL. H2SO4 + NaOH ==> Na2SO4 moles H2SO4 in the problem = M x L = 1.00M x 0.01000 L = 0.01000 moles (10.00 mL = 0.01 moles).My instructions were moles H2SO4 = M x L. Now we convert ...
Tuesday, October 25, 2011 at 10:21pm by DrBob222

chemistry
KHP + NaOH ==> NaHP + H2O moles KHP = grams/molar mass Solve for moles. Look at the equation; it is 1:1 so moles KHP = moles NaOH.] The M NaOH = moles NaOH/L NaOH.
Saturday, October 16, 2010 at 12:26am by DrBob222

chemistry
mols H2SO4 = M x L = ? mols NaOH = twice that (from the coefficients) M NaOH = mols NaOH/L NaOH. You know M and mols; solve for L and convert to mL. Click post answer
Wednesday, March 20, 2013 at 9:55pm by DrBob222

Chemistry
H2Ox + 2NaOH ==> 2H2O + Na2Ox moles H2Ox = grams/molar mass Convert moles H2Ox to moles NaOH using the coefficients in th balanced equation. That will give you moles NaOH = 2 x moles H2Ox. Then M NaOH = moles NaOH/L NaOH.
Saturday, March 26, 2011 at 11:39pm by DrBob222

organic chemistry
First, this doesn't look like an organic chem question to me. I don't know any organic chemistry but this one I can work. moles NaOH = Molarity NaOH x liters NaOH = ? Convert moles NaOH to moles H2SO4 this way. ?mols NaOH x (1 mole H2SO4/2 moles NaOH = ?moles NaOH x 1/2 = x ...
Tuesday, January 31, 2012 at 10:01pm by DrBob222

Chemistry
How many mols acetic acid did you use? That's M x L = ? Now use the equation coefficients to convert mols acetic acid to mols NaOH. That's a 1:1 ratio; therefore, mols NaOH = same as mols acetic acid. Then M NaOH = mols NaOH/L NaOH. You have mols and M NaOH, solve for L NaOH ...
Monday, May 13, 2013 at 5:11pm by DrBob222

Chemistry
mols NaOH = grams NaOH/molar mass NaOH. Sorry I didn't spell that out.
Thursday, January 10, 2013 at 6:08pm by DrBob222

chemistry
Calculate the pH of the following solutions. (A) 0.95 NaOH (B) 9.9x10^-10 M NaOH (C) 6.7 M NaOH
Saturday, May 4, 2013 at 2:02pm by wes

Chemistry
How to solve titration problem for HC2H3O2 + NaOH= NaC2H3O2 + H2O The M of NaOH= 0.427 The volume of NaOH= 17.30mL 10.00mL of acid The second titration calculation is: The M of NaOH= 0.427 The volume of NaOH=34.60mL 20.00mL of acid
Thursday, September 27, 2012 at 8:16pm by John

chemistry
How to solve titration problem for HC2H3O2 + NaOH= NaC2H3O2 + H2O The M of NaOH= 0.427 The volume of NaOH= 17.30mL 10.00mL of acid The second titration calculation is: The M of NaOH= 0.427 The volume of NaOH=34.60mL 20.00mL of acid
Saturday, September 29, 2012 at 2:47pm by Anonymous

Chemistry
Kate's (a) and (b) are correct, but (c) is incorrect. 6.00 M NaOH = (0.325 mol NaOH) / (mL NaOH) mL NaOH = (0.325 mol NaOH) / (6.00 M NaOH) With correct significant figures, the answer to (c) is 54.2 mL.
Monday, October 31, 2011 at 1:12am by M

chemistry
I think the easiest way to work these "too small, too large, neither" problems is to go through the formula used to calculate the end result. I have summarized them here for problem #1. My comments are included with each in bold face. KHP standardization with NaOH. mols KHP = ...
Sunday, March 23, 2014 at 3:05pm by DrBob222

chemistry
My first response was in error where I said mols H2SO4 =same as mols NaOH. That isn't correct. Here are the correct instructions. H2SO4 + 2NaOH ==> 2H2O x Na2SO4 volume NaOH = final reading - initial reading. mols NaOH = M NaOH (M not listed in the post) x x L NaOH. Convert...
Wednesday, October 17, 2012 at 1:33pm by DrBob222

Chemistry
moles H2X present = 0.1873/85.00 = ?? moles NaOH = 2 x that number. MNaOH = moles NaOH/L NaOH Solve for L NaOH and convert to mL. 41.89 mL is the correct answer.
Wednesday, May 11, 2011 at 9:06pm by DrBob222

Chemistry II
HNO3 + NaOH ==> NaNO3 + HOH Notice ratio acid/base = 1:1 pH 3.78 = (H^+) = (HNO3) = 1.7E-4 (approximate--you should do it more accurately.) 1.7E-4 moles/L x 1.6E4L = about 3 moles = moles HNO3 = moles NaOH needed. M NaOH = moles NaOH/L NaOH. You have M and moles, solve for L.
Monday, October 3, 2011 at 9:37pm by DrBob222

chemistry
Thank you.. I get 5.58g NaOH / 40g NaOH / 0.25L = 0.558 NaOH solution
Thursday, March 28, 2013 at 7:16pm by Kishwa

Chemistry
You made a typo in the equation. It should be Na3C6H5O7(aq) on the right. moles citric acid = grams/molar mass Convert moles citric acid to moles NaOH. From the equation you can see that 3 moles NaOH = 1 mol citric acid; therefore, mols NaOH = 3 x moles citric acid. Then M ...
Wednesday, March 7, 2012 at 3:56pm by DrBob222

chem
HCl + NaOH ==> NaCl + HOH moles HCl = M x L = ?? Using the coefficients in the balanced equation, convert moles HCl to moles NaOH. Then M NaOH = moles NaOH/L NaOH and solve for L, then convert to mL.
Monday, June 13, 2011 at 5:02pm by DrBob222

Chemistry
a. mol KHP = 0.4885g/molar mass = ? M = mols/0.1 L = approximately 0.024 but you need to do it more accurately. At the equivalence point the pH is determined by the hydrolysis of the P^2- ion. .........P^2- + HOH ==> HP^- + OH^- I.......0.024M...........0.......0 C...
Thursday, November 29, 2012 at 8:36pm by DrBob222

chemistry
Your post isn't complete without a molarity of the NaOH AND small letters (lower case) hcl don't mean anything. HCl + NaOH ==> NaCl + H2O moles NaOH = M x L = ?? Convert moles NaOH to moles HCl using the coefficients in the balanced equation. They are one so moles HCl = ...
Monday, May 23, 2011 at 6:44pm by DrBob222

Chemistry
Use the dilution relationship (Mi x Vi = Mf x Vf) to calculate the volume of 0.500 M NaOH needed to prepare 500 mL of .250 M NaOH. This is my work ? L Solution = 500mL x (1L/1000mL) = .500L ? mol NaOH = .500 L Solution x (0.250 M NaOH/1 L Solution) = .125 mol NaOH ? L solution...
Saturday, February 28, 2009 at 9:35pm by Bob

Chen=mistry
2Na + 2H2O ==> H2 + 2NaOH mols Na = 3/23 = estimated 0.13 mols NaOH formed = 0.13mols Na x (2 mols NaOH/2 mol Na) = 0.13 x 2/2 = 0.13 mols NaOH. M NaOH = mols NaOH/L H2O Substitute and solve for M.
Wednesday, May 1, 2013 at 8:44am by DrBob222

Chemistry!!!!!! Please help immediately!!!
Please show me step by step. Thank you. One commercial method used to peel potatoes is to soak them in a solution of NaOH for a short time, remove them from the NaOH, and spray off the peel. The concentration of NaOH is normally in the range of 3 to 6 M. The NaOH is analyzed ...
Sunday, March 24, 2013 at 6:21pm by Lilyyyyyyyyyyyy!!!!

Chemistry
HCl + NaOH ==> NaCl + H2O mols HCl = M x L = ? Use the coefficients to convert mols HCl to mols NaOH. Then M NaOH = mols NaOH/L NaOH.
Monday, April 23, 2012 at 2:02pm by DrBob222

Chemistry
19% w/w NaOH means 19 g NaOH/100 g soln or 19g NaOH/(19g NaOH + 81 g H2O) moles NaOH = grams/molar mass moles H2O = grams/molar mass XNaOH = moles NaOH/total mols. m = moles NaOH/kg solvent. moles NaOH from above. kg solvent from above.
Tuesday, February 21, 2012 at 1:54am by DrBob222

Chemistry (again)
Write the equation. Fe^+2 + 2OH^- ==> Fe(OH)2 moles Fe^+2 = M x L moles NaOH must be 2 x moles Fe^+2. moles OH is same as moles NaOH. g NaOH = moles NaOH x molar mass NaOH.
Tuesday, September 28, 2010 at 7:20pm by DrBob222

chemistry
If 58g of NaOH are dissolved in water to make a final volume of exactly 400mL, what is the molar concentration of NaOH? (The FM of NaOH = 40.0) How do I set this up?
Monday, October 31, 2011 at 2:20pm by Katie

chemistry
How many moles do you need? That is M x L = 3.0M x 0.250 L= ?? Now M NaOH = moles NaOH/L NaOH and solve for L NaOH, then convert to mL. An easier way is to use the dilution formula c1v1 = c2v2 6*x = 3.0*250 solve for x
Thursday, January 5, 2012 at 2:29pm by DrBob222

chemistry
2NaOH + H2C2O4 ==> Na2C2O4 + 2H2O mols H2C2O4 = M x L = ? mols NaOH = 1/2 that (look at the coefficients in the balanced equation.) M NaOH = mols NaOH/L NaOH.
Thursday, July 18, 2013 at 12:48am by DrBob222

chemistry
H2C2O4 + 2NaOH ==> Na2C2O4 + 2H2O eqn 1. moles H2C2O4 = grams/molar mass eqn 2. moles NaOH = 2 x moles H2C2O4 eqn 3. M NaOH = moles NaOH/L NaOH eqn 1 doesn't change. eqn 2 doesn't change. eqn 3 changes. If L NaOH is too high, then M NaOH is too low.
Saturday, April 2, 2011 at 12:04pm by DrBob222

chemistry
H3PO4 + 3NaOH ==> Na3PO4 + 3H2O mols H3PO4 = M x L = ? mols NaOH = 3x that (from the coefficients in the balanced equation). M NaOH = mols NaOH/L NaOH. You know M and mols, solve for L and change to mL.
Monday, July 22, 2013 at 11:01am by DrBob222

chem-acid base titrations
HCl + NaOH ==> NaCl + H2O mols HCl used = L x M = 0.0200 L x 0.2019 M = ?? mols NaOH (from the equation it is a 1:1 ratio of HCl to NaOH; therefore, mols NaOH must be the same as that for HCl). mols NaOH = L x M You have L (0.03963 mL) and you have mols (from HCl), ...
Monday, April 7, 2008 at 8:12pm by DrBob222

science
what is the concentration of hydrogen ion in a 0.1M solution of sodium hydroxide(NaOH)? NaOH dissolves and completely dissociates in H2O to form the ions. NaOH ==> Na^+ + OH^- Therefore, starting with 0.1 M NaOH will give you 0.1 M in Na^+ and 0.1 M in OH^-. You know Kw=(H...
Sunday, December 31, 2006 at 9:13pm by michelle

Math
1. Write the balanced chemical equation for the reaction NaOH + HCI --> NaCI + H20 2. Extract the relevant information from the qustion: NaOH v= 30mL, M=0.10 HCI v= 25.0 mL, M=? 3. Convert to Liters NaOH v= 0.03 L, M= 0.10M HCI v=0.025L, M=? 4. Calculate moles NaOh: n(NaOH...
Monday, March 8, 2010 at 11:11am by Maria

chem
You need to know the molarity of the NaOH. The 204.2 sounds like you standardized the NaOH by using 0.4321 g of pure potassium hydrogen phthalate. moles KHP = 0.4321/204.22 = ? moles NaOH = moles KHP M NaOH = moles NaOH/0.02435 You can work out the M NaOH. Now all we need to ...
Monday, February 13, 2012 at 10:06am by DrBob222

chemisty
mols HCl = M x L = ? mols NaOH = mols HCl(look at the coefficients in the balanced equation. M NaOH = mols NaOH/L NaOH. You know L and you know mols, solve for M NaOH.
Wednesday, December 5, 2012 at 1:06am by DrBob222

Chemistry
Is that 10 mL of the 0.2M H3PO4 added to 250 mL H2O to make 260 mL solution? If you titrate the entire solution, which seems unlikely, then you will have H3PO4 ==> NaH2PO4 + H2O mols H3PO4 = 0.010L x 0.2M = 0.002 mols NaOH required = 0.002 since 1 mol H3PO4 = 1 mol NaOH. ...
Saturday, February 8, 2014 at 2:03pm by DrBob222

Chemistry
mool KHP = grams/molar mass mols NaOH = mols KHP (from the coefficients in the balanced equation.) M NaOH = mols NaOH/L NaOH
Thursday, October 17, 2013 at 5:13pm by DrBob222

AP CHEMISTRY
mL NaOH x M NaOH = mL acid x M acid. mL NaOH x 0.125M = 25.0 x 0.175 Solve for mL NaOH. The 20% ionization is extraneous information.
Friday, March 29, 2013 at 1:20am by DrBob222

chemistry
1). Adding NaOH to the buret after rinsing the buret with distilled water (essentially saying that you don't rinse the buret with NaOH)means that the NaOH is more dilute so it will take more NaOH from the buret to reach the equivalence point. So more mL means mL x M = a ...
Thursday, October 1, 2009 at 7:48pm by DrBob222

Chemistry
Write the equation and balance it. Convert 1.8 g KHP to moles. moles = grams/molar mass Convert moles KHP to moles NaOH using the coefficients in the balanced equation. Finally, M NaOH = moles NaOH/L NaOH. Solve for L NaOH and convert to mL.
Sunday, October 9, 2011 at 10:24pm by DrBob222

chemistry
2NaOH + H2SO4 ==> 2H2O + Na2SO4 moles NaOH = M x L = ? Convert moles NaOH to moles H2SO4 by using the coefficients in the balanced equation. That will be ?moles NaOH x (1 mole H2SO4/2 moles NaOH) = ?moles NaoH x (1/2) = x moles H2SO4. Then M H2SO4 = mols H2SO4/L H2SO4.
Saturday, November 19, 2011 at 9:01pm by DrBob222

Pages: 1

Search
Members