Number of results: 15,828
The answer to 28 is pure garbage. Evaporation of water is a physical process and not a chemical one. And if you leavae the glass of water uncovered, the water will completely evaporate and you will not maintain the balance. Water goes undergo autoioniation as follows: H2O + ...
Tuesday, May 12, 2009 at 11:30am by DrBob222
For a basic buffer you want a weak base (NH3) and a salt of the weak base (NH4Cl) since the acid being mixed is always HCl. Just reason through to see if you have a weak base and its salt. NH3 + HCl ==> HCl i. 100 mmoles (mL x M) NH3 and 100 mmoles HCl. Exactly neutral, no ...
Saturday, July 18, 2009 at 5:27pm by DrBob222
Start from the equation NaOH + HCl -> NaCl + H2O so 1 mole of HCl is needed for each mole of NaOH So mmoles of HCl are 10.0 ml x 0.75 mol l^-1 which must be equal to number fo mmoles of NaOH used X ml x 0.10 mol l^-1 solve for X
Tuesday, November 10, 2009 at 2:29am by Dr Russ
NaHCO3 + HCl -> NaCl+H2O+CO2 What is the normality of a sodium bi carbonate solution containing 5.08g NaHCO3 in 150 ml solution?
Thursday, November 12, 2009 at 4:12pm by Janice
First, a double displacement (or double replacement). HCl + NaHCO3 ==> NaCl + H2CO3. Then a decomposition because H2CO3 is not stable at room temperature and atmospheric pressure. H2CO3 ==> H2O + CO2.
Friday, November 20, 2009 at 4:39pm by DrBob222
acid + base = salt + water HBz + NaOH ==> NaBz + H2O NaBz + HCl ==> HBz + NaCl Benzoic acid is C6H5COOH and it is the right most H that is involved in the reaction. I have let Bz stand for C6H5COO. The idea behind this is that benzoic acid reacts with NaOH to produce the...
Monday, February 8, 2010 at 9:31pm by DrBob222
Which of these is true about the following reaction? NaOH + HCl ¡æ NaCl + H2O A. NaOH is the proton acceptor. B. HCl acts as the Br©ªnsted-Lowry acid. C. NaOH and HCl are the products. D. This is an example of a neutralization reaction. E. The products will be acidic. Okay so ...
Monday, March 29, 2010 at 5:11pm by Lily
Write the equation and balance it. NaOH + HCl ==> NaCl + H2O Calculate moles NaOH. Calculate moles HCl. Set up an ICE chart to see what you finish with. If the moles base and moles acid are the same, they exactly neutralize each other and the pH will be exactly neutral for ...
Wednesday, March 31, 2010 at 4:20pm by DrBob222
NaHCO3 + HCl = NaCl + H2O + CO2 The HCl in the reaction is 2 molar what i need it to figure out how much CO2 if produced when 10g of each substance is mixed. And the limmiting reagent and any information that can be produced around the ammount of CO2 prouced.
Monday, April 5, 2010 at 10:29am by Souza
In the reaction: NaOH + HCl --> NaCl + H2O how many moles of water are produced when 1 mole of HCl is neutralized by 1 mole of NaOH?
Tuesday, April 6, 2010 at 3:03pm by Anonymous
NaOH + HCl --> NaCl + H2O What is the amount of heat absorbed by water? given: mass: 102.2 grams specific heat: .9601 cal/g degrees C
Tuesday, April 6, 2010 at 4:21pm by Janae
NaOH + HCl ==> NaCl + H2O. moles NaOH = M x L. moles HCl = moles NaOH (since the reaction is 1 mole NaOH to 1 mole HCl). molarity HCl = moles/L. Post your work if you get stuck.
Sunday, April 11, 2010 at 3:40am by DrBob222
Ð—Ð°Ð¿Ð¸ÑˆÐµÐ¼ ÑƒÑ€Ð°Ð²Ð½ÐµÐ½Ð¸Ðµ Ñ€ÐµÐ°ÐºÑ†Ð¸Ð¸: NaOH + HCl = NaCl + H2O C NaOH*V NaOH = C HCl*V HCl Ð³Ð´Ðµ: C NaOH Ð¸ C HCl...
Tuesday, April 13, 2010 at 8:44am by Yevgeniy
A complicated work but do-able. NaOH + HCl ==> NaCl + H2O. I think one must decide where we are at the equivalence point. Since the M NaOH is twice that of the HCl, that means the HCl will take twice as much to neutralize the NaOH. So that 35 mL is made up of 2 mL HCl for ...
Sunday, May 2, 2010 at 11:52pm by DrBob222
First the M of HCl must be determined from the titration with NaOH. NaOH + HCl ==> NaCl + H2O Since the molar ratio or the reactants is 1:1, one may use mL x M = mL x M. Use that to determine M HCl. Then go to the Ca(OH)2 solution. 2HCl + Ba(OH)2 ==> BaCl2 + 2H2O Here ...
Monday, May 3, 2010 at 1:46pm by DrBob222
Remember this. acid + base = salt + H2O. I'll do the first one and leave the second for you. HCl + NaOH ==> NaCl + HOH. Just pull the H and OH out and what's left is the salt. HC2H3O2 + NaOH ==> On HC2H3O2, it's the FIRST H that is the acid H, the H3, for example, is ...
Tuesday, May 4, 2010 at 8:08pm by DrBob222
There are two problems here. #1. pH when adding 1.90 mL of 0.1 M NaOH to 8.00 mL of 0.1 M HCl. moles NaOH = M x L = 0.0019 x 0.1 = 0.00019 moles moles HCl = 8.00 mL x 0.1 M = 0.008 x 0.1 = 0.0008. NaOH + HCl ==> NaCl + H2O Place the moles below the reactants so you can see ...
Sunday, July 11, 2010 at 8:46pm by DrBob222
You have two questions here. #1. pH of 0.8 mL x 0.1 M NaOH + 8.00 mL of 0.1 M HCl. moles NaOH = M x L = 0.1 x 0.0008 = 0.00008 moles NaOH. moles HCl = M x L = 0.1 x 0.008 = 0.0008 moles NaOH + HCl ==> NaCl + H2O Now place the moles under the reactants so you can see what is...
Monday, July 12, 2010 at 4:33am by DrBob222
#1 NaOH + HCl --> NaCl + H2O #4. mLNaOH x M NaOH = mL HCl x M HCl Solve for the one unknown in the equation.
Wednesday, August 11, 2010 at 4:19am by DrBob222
Calculate the volume of Carbon dioxide gas generated when 40.0 g of sodium carbonate reacts with hydrocholric acid according to the following reaction. The gas is to be collected at STP Na2CO3 + HCL-----> NaCL +H2O + CO2(g)
Sunday, October 3, 2010 at 5:02pm by Patrina