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April 23, 2014

Search: NARAYANA JUNIOR COLLEGE .PHYSICS

Number of results: 4

NARAYANA
r = sqrt(x^2+y^2) = 2 m E =kq/r^2 =910^9810^-9/2^2 =18 V/m (directed to the charge)
Saturday, March 31, 2012 at 11:49am by Elena

NARAYANA
a point charge q=-8.0nC is located at origin . find electric field vector at point x=1.2m,y=-1.6m
Saturday, March 31, 2012 at 11:49am by B.Y.SARAT

narayana junior college,physics
a point charge q=-8.0nC is located at origin . find electric field vector at point x=1.2m,y=-1.6m
Saturday, March 31, 2012 at 10:01am by B.Y.SARAT

NARAYANA JUNIOR COLLEGE .PHYSICS
2 PARTICLES [FREE TO MOVE] WITH CHARGES +q and +4q are a distance L APART. A 3RD CHARGE IS PLACED SO THAT THE ENTIRE SYSTEM IS IN EQ2UILIBRIUM.FIND THE LOCATION,MAGNITUDE AND SIGN OF THE 3RD CHARGE
Saturday, March 31, 2012 at 9:03am by B.Y.SARAT

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